PLS HELP ASAP! (Sorry for bad pic!

Answer:

length = 25ft, width = 20ft

Step-by-step explanation:

Let x= width, so length = x+5

Area = l x w  so A = x(x+5)

Since the area is given as 500 sqft, your equation is x(x+5)=500.

Although the numbers are easy  enough to factor in your head, mathematically the equation can be solved as a quadratic, as follows:

x^2 + 5x -500 = 0

Using either factoring or quadratic formula, x = 20 (the other value is negative).  Therefore the width is 20ft and the length is 25ft.

The factory must produce 6,400 parts  so that there is 1 ton of scrap aluminum for recycling.

It is given that For every part produced by a factory there are 5 ounces of scrap aluminum that can be recycled there are 16 ounces in 1 pound and 2,000 in 1 ton we need to find how many parts must the factory produce so that there is 1 ton of scrap aluminum for recycling

What is a Ratio?

A quantitative relation between two amounts showing the number of times one value contains in another

1 part produced  ⇒ 5 ounces scrap aluminium recycled.

So, the ratio of parts produced : Scrap of aluminium = 1   : 5  .... (a)

Let us assume for m parts produced ,  1 ton of scrap is recycled.

Also, 1 ton = 2, 000 pounds

and 1 pound = 16 ounces

⇒ 1 ton = 2000 x (16 ounces)  = 32,000 ounces

So, for m parts made in the  factory, 32,000 ounces scrap is recycled.

So, the ratio of parts produced : Scrap of aluminium =  m   : 32,000  .... (b)

From both the given ratio, we get

1   : 5  = m   : 32,000

m=32000/5

m=6400

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Answer:

yollo

Step-by-step explanation:

Answer:

8/15 +5/15 = 12/15 = 4/5

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

0.57

Step-by-step explanation:

57 / 100 = 0.57

You need to divide the percent by 100

Answer:

5x+3

Hope this helps!

Answer:

Use the trend line to predict the number of Umbrellas sold in a month, if there were 10 rainy days. Draw the vertical line from 10 on the horizontal axis to the trend line. Then, draw horizontal line to the vertical axis from the trend line as shown below. Number of Umbrellas sold in the month is about 9, if there were 10 rainy days.

164449 avatar

I searched your answer and this came up, I'd answer but it wont let me sadly, but hopefully this will help??

Step-by-step explanation:

I must earn at least $625 (or more) per week before tax to pay my bills.

Given,

To make $500 per week after tax in order to pay all my bills.

and, The income tax is 20%

To find the  smallest pre-tax weekly .

Now, According to the question:

Let x be the amount to earn pre - tax.

The income tax is 20% = 20/100 = 0.2

Set up an inequality:

x - 0.2x > = 500

0.8 > = 500

x >= 500/0.8

x >= 625

Hence, I must earn at least $625 (or more) per week before tax to pay my bills.

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The probability that each bill is a $1 bill is given as follows:

1/16.

A probability is calculated as the division of the desired number of outcomes by the total number of outcomes.

The bills are replaced, hence we consider that for each trial, there is a 1/4 probability of selecting a $1 bill, as one out of the four bills are of $1.

Hence the probability that each bill is a $1 bill is obtained as follows:

p = 1/4 x 1/4

p = 1/16.

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Answer:

9/2

Step-by-step explanation:

4.5 = 4 1/2 = 9/2

The expression is

See

Its distributive property which states that

Option A

Step-by-step explanation:

yes, the step is correct.

a² = cx | multiply by c

ca² = c²x

I am just not sure how that simplified the equation.

what do you want to achieve ? what's the goal here ?

to solve the equation for x it would be to divide both sides by c, which gives

a²/c = x

Answer:

C

Step-by-step explanation:

Since the graph was obtained by transforming the graph of the square root function, an equation for the function the graph represent is: \(g(x) = -\sqrt{9(x - 1)} + 2\)

In Mathematics and Geometry, a square root function is a type of function that typically has this form f(x) = √x, which basically represent the parent square root function i.e f(x) = √x.

In Mathematics and Geometry, a horizontal translation to the right is modeled by this mathematical equation g(x) = f(x - N) while a vertical translation to the positive y-direction (upward) is modeled by this mathematical equation g(x) = f(x) + N.

Where:

In this context, the required square root function can be obtained by applying a set of transformations to the parent square root function as follows;

f(x) = √x

g(x) = -√9(x - 1) + 2

\(g(x) = -\sqrt{9(x - 1)} + 2\)

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Answer: 9 1/4 - 6/23 = 2 7/12

Answer:

It would take 10 years

Step-by-step explanation:

A.  The payback period is 7.2 years. The net present value of the proposed investment is 3720.55.

B. No, the project does not meet the company's cash payback criteria.

C.  Yes, the project does meet the net present value criteria for acceptance.

A. The truck costs $55,440 and generates annual cost savings of $7,700. So the payback period is the cost of the truck divided the expected amount the truck will generate.

                $55,440 / $7,700 = 7.2 years

To solve for the net present value, we say

Net Present Value = ∑ [(Cash inflow in period t) / (1 + \(r^{t}\)] - Initial Investment.

NPV = (($7,700 / (1 + 0.08)¹) = 7 129.63

+ ($7,700 / (1 + 0.08)²) = 6601.51

+ .($7,700 / (1 + 0.08)³ = 6112.51

+ ($7,700 / (1 + 0.08)⁴) = 5659.73

+ ($7,700 / (1 + 0.08)⁵) = 5240.49

+ ($7,700 / (1 + 0.08)⁶) = 4 852.31

+ ($7,700 / (1 + 0.08)⁷) = 4492.88

+($7,700 / (1 + 0.08)⁸)  = 4160.07

+ ($27,600 / (1 + 0.08)⁸)) = 14911.42

- $55,440

We add all these values together and subtract by  $55,440

7 129.63 + 6601.51 + 6112.51 + 5659.73 + 5240.49 +4 852.31 + 4492.88 + 4160.07 + 14911.42 - $55,440

59160.55 - 55,440

NPV = 3720.55

B. The cash payback period of the project is 7.2 years. The company's cash payback criteria state that a project should not be accepted unless it has a payback period that is less than 50% of the asset's estimated useful life, which would be 4 years which is 50% of 8 years. Since 7.2 years is greater than 4 years, the project does not meet the company's cash payback criteria.

C. The positive NPV of $3,720.55 shows that embarking on the prooject will be valuable to the company. This means the project meets the NPV criteria for acceptance.

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Answer:

(1) x=-19

Step-by-step explanation:

Let's solve your equation step-by-step.

−4(x+1)−3=−3(x−4)

From the circle the value of angle x is 90 degrees

We have to find the value of x

The radius of the circle is 18.5

As we observe the figure the angle x is opposite to the 90 degrees

The angle x and angle 90 degrees are vertical angles

We know that the vertical angles are equal or same

∠x = 90 degrees

Hence, the value of angle x is 90 degrees from the circle

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Answer:

Number 4

Step-by-step explanation:

Answer:

The probability that it came from A, given that is defective is 0.362.

Step-by-step explanation:

Define the events:

A: The element comes from A.

B: The element comes from B.

C: The element comes from C.

D: The elemens is defective.

We are given that P(A) = 0.25, P(B) = 0.35, P(C) = 0.4. Recall that since the element comes from only one of the machines, if an element is defective, it comes either from A, B or C. Using the probability axioms, we can calculate that

\(P(D) = P(A\cap D) + P(B\cap D) + P(C\cap D)\)

Recall that given events E,F the conditional probability of E given F is defined as

\(P(E|F) = \frac{P(E\cap F)}{P(F)}\), from where we deduce that

\(P(E\cap F) = P(E|F)P(F)\).

We are given that given that the element is from A, the probability of being defective is 5%. That is P(D|A) =0.05. Using the previous analysis we get that

\( P(D) = P(A)P(D|A)+P(B) P(D|B) + P(C)P(D|C) = 0.05\cdot 0.25+0.04\cdot 0.35+0.02\cdot 0.4 = 0.0345\)

We are told to calculate P(A|D), then using the formulas we have

\( P(A|D) = \frac{P(A\cap D)}{P(D)}= \frac{P(D|A)P(A)}{P(D)}= \frac{0.05\cdot 0.25}{0.0345}= 0.36231884\)

Answer:

The answer is below

Step-by-step explanation:

Given that k(x) = -125x² +670x - 125, where x is the charge per cone and P = k(x) is the weekly profit

a) The maximum profit is at P'(x) = 0. Therefore we have to find the derivative of the profit equation and equate it to 0.

P'(x) = k'(x) = 0

k'(x) = -250x + 670 = 0

-250x + 670 = 0

250x = 670

x = $2.68

P = k(2.68) = -125(2.68²) + 670(2.68) - 125 = $772.8

Hence the maximum profit is $772.8 when the price of each ice cream cone is $2.68

b) At break even, the profit is 0. Hence P= k(x) = 0

-125x² + 670x - 125 = 0

x = 5.17 or x = 0.19

Therefore to break even, the price of the ice cream cone needs to be $0.19 or $5.17

c) g(x) = k(x - 2)

g(x) = -125(x - 2)² + 670 (x -2) - 125

Maximum profit is at g'(x) = 0

g'(x) = -250(x-2) + 670

-250(x-2) + 670 = 0

-250x + 500 + 670 = 0

250x = 1170

x = 4.68

g(4.68) = -125(4.68 - 2)² + 670(4.68 -2) - 125 = $772.8

Therefore function g has the same maximum value as function k

Answer:

When you multiply two integers with the same signs, the result is always positive.

Step-by-step explanation:

When you multiply two integers with the same signs, the result is always positive. Just multiply the absolute values and make the answer positive. When you multiply two integers with different signs, the result is always negative.

Answer:

✔ 1

5-foot by 4-foot face(s)

✔ 2

5-foot by 3-foot face(s)

✔ 2

4-foot by 3-foot face(s)

Step-by-step explanation:

EDGE 2021

The faces that must be included are two faces that measure 5ft*3ft = 15 ft², another two faces that measure 4ft*3ft = 12ft², and one face that measures 5ft*4ft = 20ft².

For the pool, we need to consider the four lateral face and the bottom face . (not the top, as it is a hole actually).

So if we have:

Then we have two faces that measure 5ft*3ft = 15 ft², another two faces that measure 4ft*3ft = 12ft², and one face that measures 5ft*4ft = 20ft².

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The median of cumulative frequency is 67.86 and the interquartile range is 32.86.

The mean is "the middle number is sorter, ascending or descending, list of numbers and can be more descriptive of that data set than the average".

The interquartile range is "measure of where the 'middle fifty' is in data set".

According to the question,

Score               Mid value    Frequency       Cumulative frequency

10 ≤ x < 20            15                       1                                 1

20≤x < 30             25                      3                                 4

30≤x < 40             35                      6                                 10

40≤x < 50            45                       15                               25

50≤x < 60            55                       14                               39

60≤x < 70            65                        28                             67

70≤x < 80            75                         18                              85

80≤x < 90            85                         11                               96

90≤x < 100           95                         4                               100

Uniform interval is 10.

a) The median of examination mark

Frequency = 1+3+6+15+14+28+18+11+4 = 100

Median = \(l+\frac{(\frac{N}{2} - m )}{f}\) × c       where l = lower limit of the median class, N = total frequency, m = cumulative frequency of the pre median class,

f = frequency of the median class, c = uniform class interval.  

            = 50 + \(\frac{\frac{100}{2} - 25 }{14}\)  × 10

            = 50 + \(\frac{50 - 25}{14}\)  × 10

            = 50 +\(\frac{25}{14}\) × 10

           = 50 + 1.786 × 10

           = 50 + 17.86  

           = 67.86.

Thus, the median of examination mark is 67.86.

b) The number of students score less than 65 marks.

In order to find the number of students score less than 65 marks sum of all frequency below 65.

= 1 + 3 + 6 + 15 + 14

= 39

Thus, the number of students score less than 65 marks is 39.

c) The number of students scored between 50 and 80 marks

In order to find the number of students scored between 50 and 80 marks only if add frequency between 50 and 80 marks.

= 14 + 28 + 18 + 11

= 71

Thus, the number of students scored between 50 and 80 marks is 71.

d) The number of students failed, given that the pass mark is 50.

In order to find the number of students failed, given that the pass mark is 50 only if add frequency below 50.

= 1 + 3 + 6 + 15

= 25.

Thus,  the number of students failed, given that the pass mark is 50 is 25.

f) The interquartile range

Interquartile range =  Q₃ - Q₁    [In words, difference between upper quartile range and lower quartile range]

Q₁ =  l₁ + \(\frac{\frac{N}{4} - m }{f}\) × c  where l₁ is the lower limit of the Q₁ class, m₁ is the cumulative frequency of the pre median class, f₁ is the Frequency of the Q₁ class, c is the class interval, N  is the total frequency.

\(\frac{N}{4}\) = \(\frac{100}{4} = 25\); \(\frac{3N}{4}\) = 75

     = 40 + \(\frac{25 - 25}{6}\) * 10 = 40

Q₁ = 40

Q₃ = l₃ + \(\frac{3\frac{N}{4} - m3 }{f3}\)  × c

   = 60 + \(\frac{75 - 39}{28}\) × 10

   = 60 + \(\frac{36}{28}\) × 10

   = 60 + 1.2857 × 10

   =   60 + 12.857

   = 72.857

Interquartile range = upper quartile range - lower quartile range

                                 = 72.857 - 40

                                 = 32.8571  ≈ 32.86.

Thus, interquartile range is 32.86.

Hence, a) The median of examination mark is 67.86.

b) The number of students score less than 65 marks is 39.

c) The number of students scored between 50 and 80 marks is 71.

d) The number of students failed, given that the pass mark is 50 below 50 is 25.

f)  The interquartile range is 32.86.

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Answer:

It has a slope of -2/3 and the y intercept is 3

Step-by-step explanation:

Answer:

Step-by-step explanation:

The surface area of a cube is given by the formula:

SA = 6s^2

where s is the length of an edge.

Substituting s = 6.44 cm into the formula, we get:

SA = 6(6.44 cm)^2

SA = 6(41.4736 cm^2)

SA = 248.8416 cm^2

Therefore, the surface area of the cube is 248.8416 cm^2.

Answer:

1728 square ft²

Step-by-step explanation:

48x36=1728

Answer:

\(\large \boxed{\mathrm{Area}}\) = \(\large \boxed{\mathrm{12 \ ft^2}}\)

Steps:

12 inches = 1 foot

48 / 12 = 4 \(\meduim \boxed{\mathrm{feet}}\)

36 / 12 = 3 \(\large \boxed{\mathrm{feet}}\)

Answer:

3 x 4 = 12 ft²