please help with problem 25​

The correct answer is option C, when the distribution of the data is approximately symmetric and bell-shaped.

According to the Empirical Rule, also referred to as the 68-95-99.7 Rule, for a normal distribution, roughly 68% of the data will lie within one standard deviation of the mean, 95% of the data will lie within two standard deviations of the mean, and 99.7% of the data will lie within three standard deviations of the mean.

Only when the distribution of the data is symmetric and bell-shaped does this rule hold.

The Empirical Rule cannot be used to estimate percentages if the data is skewed to the left or right.

The Empirical Rule can be used to predict the population from which the data were taken, making it a useful tool when examining data with a normal distribution.

It's crucial to remember that this rule is merely an estimation and may not be correct depending on whether the data follows a normal distribution.

Complete Question:

The empirical rule can be used to estimate some specific percentages _______.

Select one:

A. when the distribution of the data is skewed to the right.

B . when the distribution of the data is skewed to the left.

C. when the distribution of the data is approximately symmetric and bell-shaped.

D. when the distribution of the data has any shape.

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If the parent function \(\sf y=(1.6)^x\) is translated 5 units up and 9 units to the right, then you should subtract 9 from x and add 5 to the whole function. Thus,

1) translation the parent function \(\sf y=(1.6)^x\) 9 units to the right gives you the function \(\sf y=(1.6)^{x-9}\).

2) translation the function \(\sf y=(1.6)^{x-9}\) 5 units up gives you the function \(\sf y=(1.6)^{x-9}+5\)

Therefore, the correct choice is C

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Answer:

  108°

Step-by-step explanation:

The two given angle are vertical angles, which means they are congruent.

  (x +81)° = 4x°

  81 = 3x . . . . . . . subtract x, divide by °

  27 = x . . . . . . . . divide by 3

  (27 +81)° = 108° . . . . find the angle measure

The two marked angles have measures of 108°.

EXPLANATION:

1.The first thing we must do is use a suitable method that allows us to find the value of y for the two equations of the line

2. The correct and most appropriate method is the matching method.

The exercise is as follows:

Answer:

\(\pm 1, \pm\dfrac{1}{3},\pm\dfrac{1}{9},\pm 7, \pm\dfrac{7}{3},\pm\dfrac{7}{9}\).

Step-by-step explanation:

According to the Rational Root Theorem, the potential roots of a polynomial are

\(x=\pm\dfrac{p}{q}\)  

where, p is a factor of constant and q is a factor of leading term.

The given polynomial is

\(f(x)=9x^8+9x^6-12x+7\)

Here, 9 is the leading term and 7 is constant.

Factors of 9 are ±1, ±3, ±9.

Factors of 7 are ±1, ±7.

Using rational root theorem, the rational or potential roots are

\(x=\pm 1, \pm\dfrac{1}{3},\pm\dfrac{1}{9},\pm 7, \pm\dfrac{7}{3},\pm\dfrac{7}{9}\)

Therefore, the potential root of f(x) are \(\pm 1, \pm\dfrac{1}{3},\pm\dfrac{1}{9},\pm 7, \pm\dfrac{7}{3},\pm\dfrac{7}{9}\).  

Answer:

its D, 3/7.

Step-by-step explanation:

just did it egen2020

Answer:

-3/8 is the slope of the line

Step-by-step explanation:

Answer:

t ≥ 2

Step-by-step explanation:

3t ≥ 15-9

3t ≥ 6

t ≥ 6/3

t ≥ 2

Answer:

-7

Step-by-step explanation:

first find the input, -1, on the graph.

go up the y-axis from there and you'll find your output, -7.

Answer:

I'm pretty sure it's C I may be wrong though

Step-by-step explanation:

30 inches squared or 30 in^2

All you have to do to find area of a parallelogram is length times width

So 5 times 6 is 30

Don’t forget the unit, which in this case is inches, and anytime you have area, you have to have a squared, or an exponent 2

Hope this helps, and please consider marking branliest if this did.

Answer:

42w in²

hope this answer will help you.

The difference between units and square units is  unit square is a square with sides measuring 1 unit, while a square unit is a unit of measurement .

Given :

difference between units and square units

Square units :

In geometry, a square unit can be defined as the metric unit used to measure area.

ex :

In a rectangle the area is l * b  square units .

Units :

A unit may also mean the standard units used for measurement.

ex :

length of side = 5 units.

Hence the units are single measurement the square of units is double measurement.

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Answer:

Just do scan and solve by brainly really helpful ngl

Step-by-step explanation:

The rectangular coordinates of the polar coordinates (√35, -π/8) are approximately (5.932, -0.3927).

To convert polar coordinates (r, θ) to rectangular coordinates (x, y), we can use the following relationships:

x = r * cos(θ)

y = r * sin(θ)

In this case, we have the polar coordinates (√35, -π/8).

First, we calculate x:

x = √35 * cos(-π/8) ≈ 5.932 * cos(-0.3927) ≈ 5.932 * 0.919 ≈ 5.453

Next, we determine y:

y = √35 * sin(-π/8) ≈ 5.932 * sin(-0.3927) ≈ 5.932 * (-0.394) ≈ -2.337

Therefore, the rectangular coordinates of the polar coordinates (√35, -π/8) are approximately (5.932, -0.3927). The x-coordinate represents the horizontal distance from the origin, and the y-coordinate represents the vertical distance from the origin. The negative angle indicates a counterclockwise rotation from the positive x-axis.

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The correct answer is a)True  c)True The order of the cyclic group is determined by the number of elements in the group, whereas the order

a. True. If a nonempty subset H of a group G is closed under the binary operation of G, contains the identity element of G, and contains the inverse of each of its elements, then H is a subgroup of G.

c. A is true but B is false. Every cyclic group is indeed abelian, but the order of the cyclic group is not necessarily the same as the order of its generator. The order of the cyclic group is determined by the number of elements in the group, whereas the order of the generator refers to the smallest positive exponent that generates all elements of the group.

a. Zero has no inverse. In the set of real numbers under the usual multiplication operation, the element zero does not have a multiplicative inverse. Every nonzero real number has an inverse, but zero itself does not. In a group, every element should have an inverse, so the set of all real numbers under multiplication does not form a group.

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The quadratic equation of the form ax² + bx + c = 0.

The value of x = 4 and x = -3

No solution

No real-valued solution

The quadratic equation of the form

ax² + bx + c = 0.

The form is called the standard form of the quadratic equation.

Let the given equation be x² = x + 12

By using quadratic equation, ax² + bx + c = 0

ax² + bx + 12 = 0

x² = x + 12

⇒ x² - x - 12 = 0

Let the quadratic equation be

\($x=\frac{\left(-b\right)\pm \sqrt{\left(b)^2-4\cdot \:a\cdot \left(c)}}{2\cdot \:a}\)

a = 1, b = -1 and c = -12

Substitute the values in the above equation, we get

\($x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\cdot \:1\cdot \left(-12\right)}}{2\cdot \:1}\)

simplifying the above equation, we get

\($x_{1,\:2}=\frac{-\left(-1\right)\pm \:7}{2\cdot \:1}\) and

\($x_{1,\:2}=\frac{-\left(-1\right)\a++ \:7}{2\cdot \:1}\)

\($x_{1,\:2}=\frac{-\left(-1\right)\a+- \:7}{2\cdot \:1}\)

x = 4 and x = -3

Therefore, the value of x = 4 and x = -3

No solution

No real-valued solution

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Answer:

565.59$ + c = $ 965.58

Step-by-step explanation:

The natural logarithm is commonly used to approximate growth rates in various fields such as finance, economics, and biology. However, there are potential problems that can arise when using the natural logarithm for this purpose. Some of these problems include:

1. Non-linear growth: The natural logarithm assumes a constant growth rate over time, which may not accurately represent real-world scenarios. In many cases, growth rates may change over time, leading to non-linear patterns that cannot be accurately captured using the natural logarithm.
2. Negative growth rates: The natural logarithm cannot handle negative growth rates. If a variable experiences negative growth, such as a population declining or a stock losing value, the natural logarithm will produce an undefined result. This limitation can hinder the use of the natural logarithm in situations where negative growth rates are present.
3. Sensitivity to small changes: The natural logarithm is highly sensitive to small changes in values. This means that even a slight deviation in the growth rate can result in a significant difference in the calculated approximation. This sensitivity can introduce errors and inaccuracies in the estimation of growth rates.
4. Lack of interpretability: While the natural logarithm provides a mathematical approximation of growth rates, it may not always have a clear interpretation in real-world terms. For example, if the natural logarithm yields a growth rate of 0.05, it may not be immediately obvious what this means in practical terms. This lack of interpretability can make it challenging to communicate and understand the results.

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Answer:

(-2, 5/3)

Step-by-step explanation:

Substitute x with -2 and solve

y = 2/3(-2) + 3

Multiply 2/3 and -2

y = -4/3 + 3

Add

-4/3 + 3 = 5/3

y = 5/3

Final answer:

(-2, 5/3)

The value of ∠GFH=59°, in the given question.

What do you mean by angle?

Two straight lines or rays intersect at a same terminus to make an angle. The vertex of an angle is the point at which all points meet.

According to the data in the given question,

We have :

∠EFH=127°

∠EFG=(8x-4)°

∠GFH=(5x+14)°

Now, we have to solve the value of ∠GFH,

∠EFG+∠GFH=∠EFH

Putting the values given and solve for x,

(8x-4)°+(5x+14)°=127°

8x°-4°+5x°+14°=127°

13x°+10°=127°

13x°=127°-10°

13x°=117°

x=9

Then, putting the value of x in ∠GFH,

∠GFH=(5x+14)°

=(5(9)+14)°

=(45+14)°

=59°

Therefore, the value of ∠GFH=59°.

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Answer: 2

Step-by-step explanation:

The values of \(x^+ = \begin{bmatrix} 316 \\ 64 \end{bmatrix}\) and \(y(t) = 632\) using the state-space representation of a dynamical system.

\(\textbf{Given:}\)

The state transition matrix \(A\) can be calculated using the formula:

\(A = \begin{bmatrix} 10 & -2 \\ 2 & 1 \end{bmatrix}\).

The value of \(x(t)\) can be calculated as:

\(\begin{bmatrix} x^+ \\ y(t) \end{bmatrix} = \begin{bmatrix} 10 & -2 \\ 2 & 1 \end{bmatrix} \begin{bmatrix} 32 \\ 0 \end{bmatrix} = \begin{bmatrix} 316 \\ 64 \end{bmatrix}\).

Therefore, \(x^+ = \begin{bmatrix} 316 \\ 64 \end{bmatrix}\).

The value of \(y(t)\) can be calculated as:

\(y(t) = \begin{bmatrix} 2 & 1 \end{bmatrix} \begin{bmatrix} x(t) \\ y(t) \end{bmatrix} = \begin{bmatrix} 2 & 1 \end{bmatrix} \begin{bmatrix} 316 \\ 64 \end{bmatrix} = 632\).

Therefore, \(y(t) = 632\).

Thus, we can find the values of \(x^+ = \begin{bmatrix} 316 \\ 64 \end{bmatrix}\) and \(y(t) = 632\) using the state-space representation of a dynamical system.

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Answer:

median is 7 because it's frequency is 3

Step-by-step explanation:

we were just learning these in o.maths.

The median,range and mode will be equal to 9,5 and 7.

The Median is the middlemost value of the numbers arranged in the ascending orders.

The mode will be defined as the number which is repeated mostly in the sequence.

The Range is the difference between the highest and the lowest value in the series.

The Median will be calculated as:-

7,7,7,8,10,11,12,12

median = (8+10)/2=9

The mode will be:-

7,7,7,8,10,11,12,12

Mode =7

The range will be:-

7,7,7,8,10,11,12,12

Range= 12-7=5

Hence the median,range and mode will be equal to 9,5 and 7.

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Question 1a

To calculate the book value at the end of the first year using straight-line depreciation, we need to determine the annual depreciation expense first. The straight-line method assumes that the asset depreciates by an equal amount each year over its useful life. Therefore, we can use the following formula to calculate the annual depreciation:

Annual Depreciation = (Cost - Salvage Value) / Useful Life

Substituting the given values, we get:

Annual Depreciation = ($200,000 - $20,000) / 10 years = $18,000 per year

This means that the tractor will depreciate by $18,000 each year for the next 10 years.

To determine the book value at the end of the first year, we need to subtract the depreciation expense for the year from the original cost of the tractor. Since one year has passed, the depreciation expense for the first year will be:

Depreciation Expense for Year 1 = $18,000

Therefore, the book value of the tractor at the end of the first year will be:

Book Value = Cost - Depreciation Expense for Year 1

= $200,000 - $18,000

= $182,000

So the book value of the tractor at the end of the first year, December 31, 2022, using straight-line depreciation is $182,000. so the answer is D

Question 1(b)

To determine the farmer's noncurrent liabilities, we need to use the information provided to calculate the total liabilities and then subtract the current liabilities from it. Here's the step-by-step solution:

Calculate the total current liabilities using the current ratio:

Current Ratio = Current Assets / Current Liabilities

2 = $80,000 / Current Liabilities

Current Liabilities = $80,000 / 2

Current Liabilities = $40,000

Calculate the total liabilities using the debt/equity ratio:

Debt/Equity Ratio = Total Liabilities / Owner Equity

1.0 = Total Liabilities / $100,000

Total Liabilities = $100,000 * 1.0

Total Liabilities = $100,000

Subtract the current liabilities from the total liabilities to get the noncurrent liabilities:

Noncurrent Liabilities = Total Liabilities - Current Liabilities

Noncurrent Liabilities = $100,000 - $40,000

Noncurrent Liabilities = $60,000

Therefore, the farmer's noncurrent liabilities are $60,000. so the answer is B.

Shawn saved approximately \(15.85\)‰ of their original bill with the coupon.

The amount remained with Shawn by subtracting the final bill from the original bill -

Saved amount \(= 31.58 - 26.58\)

                      \(= 5.00\)

To convert the amount saved in percentage, divide the amount saved by the original bill and multiply by 100:

Percentage Saved \(=\) (Amount Saved / Original Bill) × \(100\)

Percentage Saved \(=\) (\(5\) ÷ \(31.58\) ) × \(100\)

                             \(=\) \(15.85\) ‰

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\(-11\frac{1}{5} : 5\frac{1}{4} =\\\\-\frac{56}{5} : \frac{21}{4} =\\\\-\frac{56}{5} . \frac{4}{21} = -\frac{224}{105}\)

 ⇒ To calculate the fraction division, we must multiply the first fraction by the inverse of the second.

Answer: x = -1

Step-by-step explanation:

Answer:

x = - 1

Step-by-step explanation:

Given a parabola in standard form , f(x) = ax² + bx +c ( a ≠ 0 )

Then the axis of symmetry is calculated using

x = - \(\frac{b}{2a}\)

f(x) = x² + 2x - 8 ← is in standard form

with a = 1 and b = 2 , then axis of symmetry is

x = - \(\frac{2}{2}\) = - 1, that is

x = - 1

The functions x1(t) = t and x2(t) = t^4 are linearly independent and satisfy the given second-order linear ordinary differential equation (ODE). The unique solution that satisfies the initial conditions x(1) = 0 and x'(1) = -3 is x(t) = t^5 / 3.

To show that x1(t) = t and x2(t) = t^4 are a fundamental solution set for the given second-order linear ordinary differential equation (ODE), we need to demonstrate two things: linear independence and that they both satisfy the ODE.

1. Linear Independence:

To show that x1(t) = t and x2(t) = t^4 are linearly independent, we can check their Wronskian. The Wronskian of two functions x1(t) and x2(t) is given by:

W(t) = | x1(t)  x2(t) |

      | x1'(t)  x2'(t) |

Taking the derivatives:

x1'(t) = 1

x2'(t) = 4t^3

Substituting into the Wronskian:

W(t) = | t  t^4 |

      | 1  4t^3 |

Calculating the determinant:

W(t) = t(4t^3) - (t^4)(1)

    = 4t^4 - t^4

    = 3t^4

Since the determinant is non-zero for all t ≠ 0, the functions x1(t) = t and x2(t) = t^4 are linearly independent.

2. Satisfying the ODE:

Now we need to verify that both x1(t) = t and x2(t) = t^4 satisfy the given second-order ODE:

t^2(d^2x/dt^2) - 4t(dx/dt) + 4x = 0.

For x1(t) = t:

LHS = t^2(0) - 4t(1) + 4t

    = 0 - 4t + 4t

    = 0

    = RHS.

For x2(t) = t^4:

LHS = t^2(12t^2) - 4t(4t^3) + 4(t^4)

    = 12t^4 - 16t^4 + 4t^4

    = 0

    = RHS.

Both x1(t) = t and x2(t) = t^4 satisfy the ODE.

Therefore, x1(t) = t and x2(t) = t^4 form a fundamental solution set for the given ODE.

To find the unique solution satisfying the given initial conditions x(1) = 0 and x'(1) = -3, we can use the method of variation of parameters or the initial value problem formula.

Using the initial value problem formula, the solution is given by:

x(t) = x1(t) * y2(1) / W(1) - x2(t) * y1(1) / W(1),

where y1(t) and y2(t) are the fundamental solutions and W(t) is the Wronskian.

Plugging in the values:

x(t) = t * t^4 / W(1) - t^4 * 0 / W(1)

    = t^5 / W(1),

where W(1) is the Wronskian evaluated at t = 1, which is 3(1)^4 = 3.

Therefore, the unique solution satisfying the given initial conditions x(1) = 0 and x'(1) = -3 is:

x(t) = t^5 / 3.

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