Please help!! With decomposition of water

In the decompensation of water why is twice as much hydrogen as oxygen formed?

A.) there are two atoms of hydrogen and one atom of oxygen in a water molecule

B.) some oxygen gas escapes the reaction and hydrogen gas is conserved

C.) hydrogen atoms are twice the size of oxygen atoms

D.) hydrogen gas has two atoms and oxygen gas has one atom

Answer:

i wonder...................

Explanation:

False. b-dicarbonyl compounds generally have a greater concentration of the keto form over the enol form.

The keto-enol tautomerism refers to the interconversion between the keto form and the enol form in certain compounds, such as b-dicarbonyl compounds. In the keto form, the carbonyl groups are fully saturated, while in the enol form, one of the carbonyl groups is converted into a double bond with a hydrogen atom attached.

Typically, the keto form is more stable than the enol form due to the resonance stabilization of the carbonyl groups. As a result, the keto form is favored over the enol form and exists in a higher concentration. However, it's important to note that the equilibrium between the two forms can be influenced by factors such as temperature, solvent, and substitution effects on the b-carbon.

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Answer:

Explanation:

well there is many things in our solar system and a moon is one of them. the moons in our solar system are big and small and orbit our planets. the moon is unique because it shines in the dark while it lets the sun shine in the light.

Thats what i would say but its an eh answer

According to the question the percentage yield to one decimal place is 77.5%.

Percentage yield is a measure of the efficiency of a chemical reaction, which compares the amount of desired product obtained from a reaction to the maximum theoretical yield that could be obtained. It is calculated by dividing the actual yield of a product by the theoretical yield, and multiplying by 100. This measure helps chemists understand how efficient a reaction is, so they can make adjustments to maximize their product yields.

The percentage yield is calculated by dividing the amount of product obtained (15.5g) by the theoretical yield (20g) and multiplying by 100.
Percentage yield = (15.5/20) * 100 = 77.5%.

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Answer:

- Molecules move from high concentrations to low concentrations.

- Molecules are evenly distributed at the end.

Explanation:

:)

Number of particles : 8.603 x 10²³

Standard conditions for temperature and pressure are used as a reference in certain calculations or conditions

Assumption⇒ Standard Conditions

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.

1 mol = 6.02 x 10²³ particles (atoms, ions, or molecules)

32.0 liters of Helium

\(\tt mol=32:22.4=1.429\)

Number of particles :

\(\tt 1.429\times 6.02\times 10^{23}\\\\=8.603\times 10^{23}\)

Find the number of moles, we divide the given mass (125 g) by the formula mass (262.9 g/mol):  125 g / 262.9 g/mol = 0.475 mol, However, we need to multiply this by the number of phosphorus atoms in one formula unit of magnesium phosphate.

In one formula unit of mg3(po4)2, there are 2 atoms of phosphorus.
Therefore, the total number of phosphorus atoms in 125 g of magnesium phosphate can be calculated as: 0.475 mol x 2 atoms/mol = 0.950 atoms .

Calculate the number of moles of Mg3(PO4)2 in 125 g:
moles = mass / molar mass = 125 g / 262.9 g/mol = 0.475 moles
2. Determine the number of moles of phosphorus (P) in Mg3(PO4)2:
Mg3(PO4)2 has 2 moles of P per 1 mole of the compound, so 0.475 moles Mg3(PO4)2 × 2 moles P/1 mole Mg3(PO4)2 = 0.95 moles P
3. Calculate the number of atoms of phosphorus:
atoms = moles × Avogadro's number = 0.95 moles P × 6.022 x 10^23 atoms/mol = 1.43 x 10^23 atoms P.

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To answer this question, there are approximately 5.72 x 10^23 atoms of phosphorus in 125 g of magnesium phosphate.

we first need to find the molar mass of magnesium phosphate. The formula mass given in the question is 262.9 g/mol.
Now, we can use the formula mass to find the number of moles of magnesium phosphate in 125 g of the compound.
Moles of Mg3(PO4)2 = mass / molar mass
Moles of Mg3(PO4)2 = 125 g / 262.9 g/mol
Moles of Mg3(PO4)2 = 0.4754 mol
Next, we need to determine the number of moles of phosphorus in this amount of magnesium phosphate. We can use the formula of the compound to determine the ratio of magnesium to phosphorus.
There are 2 phosphorus atoms in each molecule of magnesium phosphate, so we can multiply the number of moles of Mg3(PO4)2 by 2 to get the number of moles of phosphorus.
Moles of P = 0.4754 mol Mg3(PO4)2 x 2
Moles of P = 0.9508 mol P
Finally, we can use Avogadro's number (6.022 x 10^23) to convert the number of moles of phosphorus to the number of atoms of phosphorus.
Number of P atoms = moles of P x Avogadro's number
Number of P atoms = 0.9508 mol P x 6.022 x 10^23 atoms/mol
Number of P atoms = 5.72 x 10^23 atoms
Therefore, there are approximately 5.72 x 10^23 atoms of phosphorus in 125 g of magnesium phosphate.

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Ecell for each of the following reactions i.e. (1, 2, 3) reactions are (-1.52 V, non-spontaneous); (1.99 V, spontaneous); (1.51 V, spontaneous) respectively.

1) 2Cu(s)+Mn2+(aq)→2Cu+(aq)+Mn(s).

To calculate the Ecell∘ for this reaction, we need to know the standard reduction potentials (E0) of the half reactions.

Cu2+(aq) + 2e- → Cu(s) E0 = +0.34 V

Mn2+(aq) + 2e- → Mn(s) E0 = -1.18 V

Ecell = E0 (products) - E0 (reactants)

Ecell = (-1.18 V) - (+0.34 V) = -1.52 V

Since the Ecell value is negative, this means that the reaction is not spontaneous as written (it is non-spontaneous or endothermic) and it would require an input of energy to occur.

2) MnO2(s)+4H+(aq)+Zn(s)→Mn2+(aq)+2H2O(l)+Zn2+(aq)

To calculate the Ecell∘ for this reaction, we need to know the standard reduction potentials (E0) of the half-reactions.

MnO2(s) + 4H+ + 2e- → Mn2+ + 2H2O(l) E0 = +1.23 V

Zn(s) + 2e- → Zn2+(aq) E0 = -0.76 V

Ecell = E0 (products) - E0 (reactants)

Ecell = (+1.23 V) - (-0.76 V) = 1.99 V

Since the Ecell value is positive, this means that the reaction is spontaneous as written (it is exothermic) and it would release energy as it occurs.

3) Cl2(g)+2F−(aq)→F2(g)+2Cl−(aq)

To calculate the Ecell∘ for this reaction, we need to know the standard reduction potentials (E0) of the half-reactions.

Cl2(g) + 2e- → 2Cl-(aq) E0 = +1.36 V

2F-(aq) + 2e- → F2(g) E0 = +2.87 V

Ecell = E0 (products) - E0 (reactants)

Ecell = (+2.87 V) - (+1.36 V) = 1.51 V

Since the Ecell value is positive, this means that the reaction is spontaneous as written (it is exothermic) and it would release energy as it occurs.

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Answer:

metal,middle of the periodic table,solid

Explanation:

Because they have an extended structure, elements that are metal tend to be in the middle of the periodic table state at room temperature as solid

Because they have an extended structure, elements that are metal, tend to be in the middle of the periodic table, and stay solid state at room temperature.

Metals are those elements of the periodic table which are malleable soft and ductile the full stop, they are very reactive because they have valence electrons in their outermost shells. They are present in the middle of the periodic table.

Some metals are Aluminum, magnesium, titanium iron zinc, bronze, etc.   There are 92 metals are present in the periodic table. Metals are useful for making many things such as jewelry, wires, foil papers, and gates. Steel is the most useful metal in the world.

Thus, metal elements tend to be in the middle of the periodic table and maintain their solid state at ambient temperature because of their elongated structure.

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Answer:

Your answer will be "Over the ocean"

Explanation:

Have a good day/night

Hope this helps! :)

Mark as brainliest?

Answer:
I think it's land or lakes and rivers

The reaction between \(I_{2}\) (iodine) and Zn (zinc) is a redox reaction.

This is because the reaction involves a transfer of electrons from one substance to another. Zinc is a reducing agent, meaning it loses electrons during the reaction, while iodine is an oxidizing agent, meaning it gains electrons.

During the reaction, zinc atoms lose electrons to form \(Zn^{2+}\) ions, while iodine molecules gain electrons to form \(I^{-}\) ions. The zinc atoms that lose electrons are said to be oxidized, while the iodine molecules that gain electrons are said to be reduced. This is where the term "redox" comes from.

The reaction between iodine and zinc can be represented by the following equation:

Zn + \(I_{2}\) → \(ZnI_{2}\)

This equation shows that one zinc atom reacts with one iodine molecule to form one molecule of zinc iodide. The reaction is exothermic, meaning it releases heat as the reaction proceeds.

Overall, the reaction between iodine and zinc is an example of a redox reaction, where electrons are transferred between substances. The reaction produces zinc iodide, which is a white crystalline solid that is often used in the manufacturing of dyes, pharmaceuticals, and other chemical compounds.

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The reaction between iodine and zinc is a redox, single-replacement reaction. Zinc displaces iodine and gets oxidized, thereby reducing iodine. The resultant product is zinc iodide (ZnI2).

The reaction between iodine (I2) and zinc (Zn) is a type of redox reaction, specifically, a single-replacement reaction. In this reaction, Zinc, a more reactive metal, displaces the iodine, thereby reducing the iodine and undergoing oxidation itself. The chemical equation for this reaction is Zn + I2 → ZnI2.

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The answer is (E) 5.0 x 10^-3. KOH is a strong base, meaning it dissociates completely in water to form OH- ions

At equilibrium, a solution of a weak base in water is a mixture of the nonionized base, the conjugate acid of the weak base, and hydroxide ion with the nonionized base present in the greatest concentration. Thus, a weak base increases the hydroxide ion concentration in an aqueous solution (but not as much as the same amount of a strong base). . The concentration of OH- ions in a 0.0050 M KOH solution can be calculated using the equation:

[OH-] = Kw / [H+]

where Kw is the ion product constant for water (1.0 x 10^-14 at 25°C).

Since KOH is a strong base, we can assume that [OH-] is equal to the concentration of KOH (0.0050 M). Therefore:

[OH-] = 0.0050 M

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Answer:

A

Explanation:

Answer:

Hyperkalemia

Explanation:

The condition of acidosis can also cause Hyperkalemia because the higher H concentration diffuses to the ICF, pushing K towards the ECF.

The best that represents a physical change is condensation. Option D is correct.

A physical change is a change in the physical properties of a substance, without any change in its chemical composition or identity. Examples of physical changes include changes in the state of matter (such as melting, boiling, freezing, and condensation), changes in size, shape, or texture, and changes in density or solubility.

However, condensation is the only example that represents a physical change. Condensation is the process by which a gas or vapor changes into a liquid as it loses heat. It is a physical change because the chemical identity of the substance does not change during the process; only its physical state changes from a gas to a liquid.

Formation of a gas and formation of a new substance represent chemical changes, which involve the formation of new chemical compounds and the breaking of chemical bonds. Bubbling could represent either a physical or chemical change, depending on the specific context.

Hence, D. is the correct option.

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--The given question is incomplete, the complete question is

"Which best represents a physical change? group of answer choices A) formation of a gas B) formation of a new substance C) bubbling D) condensation."--

Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl

To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7.  Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.

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Answer:

The 5R's are Reuse, Reduce, Recycle, Repair and Recover.

2. The chemical expression 147N+α is:  147N + α --> 151D + 4He

3. The chemical equation 2H+(aq)+S2−(aq)→H2S(g) is :  2H+ + S2- --> H2S

2. The expression 147N+α represents a nuclear reaction where alpha particle (α) is being emitted from the nucleus of nitrogen-14 (147N). The resulting product after the emission of alpha particle is oxygen-18 (148O).

Nuclear reactions involve the changes in the composition of an atomic nucleus, and they are different from chemical reactions which involve the interactions of electrons between atoms. In a nuclear reaction, the nucleus of an atom is altered, and one or more subatomic particles may be released.

In this case, the emission of an alpha particle from nitrogen-14 nucleus transforms it into oxygen-18 nucleus. An alpha particle consists of two protons and two neutrons, and its emission causes the atomic number of the element to decrease by two and the atomic mass to decrease by four.

Therefore, the chemical expression for the nuclear reaction 147N+α is:

14/7N + 4/2α → 18/8O

3. The chemical equation 2H+(aq)+S2−(aq)→H2S(g) represents the reaction between hydrogen ions (H+) and sulfide ions (S2-) to form hydrogen sulfide gas (H2S).

In aqueous solution, hydrogen ions are hydrated to form hydronium ions (H3O+), which are often represented as H+. Therefore, the reaction can also be written as:

2H3O+(aq) + S2-(aq) → H2S(g) + 2H2O(l)

This is an acid-base reaction where the hydronium ion (H3O+) acts as an acid and the sulfide ion (S2-) acts as a base. The reaction produces a weak acid, hydrogen sulfide, which exists mainly in the gaseous phase and is often recognized by its rotten egg-like odor.

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Taking into account the definition of calorimetry, the change in temperature of a 5.0 g sample of water that loses 1800J of heat energy is 86.12 C.

In first place, calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body can receive or give up without affecting its molecular structure. If the molecular structure does not change, the state (solid, liquid, gaseous) does not change. Since the molecular structure does not change, a change in temperature is observed.

In other words, sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Replacing in the expression to calculate heat exchanges:

1800 J= 4.18\(\frac{J}{gC}\)× 5 g× ΔT

Solving:

1800 J ÷ (4.18\(\frac{J}{gC}\)× 5 g)= ΔT

ΔT= 86.12 C

In summary, the change in temperature of a 5.0 g sample of water that loses 1800J of heat energy is 86.12 C.

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Under identical conditions, it would take the same amount of gaseous I2 to effuse from the same container as it did for N2O, but it would take longer.

This is because I2 is a larger molecule than N2O, so it has greater difficulty passing through the small spaces in the container. The larger the molecule, the slower the effusion rate.

In general, effusion rates are inversely proportional to the square root of the molecular weight of a gas. This means that the molecular weight of I2 is four times larger than that of N2O, so it would take approximately twice as long for I2 to effuse from the container. In this case, it would take approximately 98 seconds for the same amount of gaseous I2 to effuse from the container under identical conditions.

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The equilibrium constant of the reaction is 0.042.

The reaction equation is given as;

PCl5(g) ⇄ PCl3(g) + Cl2 (g)

Recall that this equation shows the decomposition of phosphorus pentachloride.

We have the following equilibrium concentrations;

[PCI5]= 0.0095 M

[PCI3] = 0.020

[CI2] = 0.020 M

The equilibrium constant, K is obtained from;

K =  [PCI3]  [CI2]/[PCI5]

K = [0.020]^2/[0.0095]

K = 0.042

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Answer:

0.313 M NaOH

Explanation:

Got it right on the test.

Taking into account the definition of molarity, the molarity of the solution is 0.313 M.

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

\(molarity=\frac{number of moles}{volume}\)

Molarity is expressed in units \(\frac{moles}{liter}\).

In this case, you know:

Replacing in the definition of molarity:

\(molarity=\frac{0.75 moles}{2.40 L}\)

Solving:

molarity= 0.313 M

Finally, the molarity of the solution is 0.313 M.

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The PESTLE and SWOT analyses provide a comprehensive assessment of the external and internal factors influencing the Harvard case "Clean Edge Razor: Splitting Hairs in Product Positioning."

The PESTLE analysis examines the external factors that may impact the case. Politically, regulations on product safety and environmental sustainability could affect the razor industry. Economically, consumer purchasing power and economic trends may impact the demand for high-end razors. Sociocultural factors, such as grooming habits and preferences, influence consumer behavior. Technological advancements, such as electric razors and online shopping, pose opportunities and challenges. Legal factors include intellectual property rights and advertising regulations. Environmental considerations involve sustainability and eco-friendly practices.

The SWOT analysis evaluates the internal strengths and weaknesses of the case. Strengths may include the Clean Edge brand reputation and innovative product features. Weaknesses could involve high manufacturing costs or limited market presence. Opportunities may arise from market growth and expanding into new segments. Threats may come from intense competition and changing consumer preferences.

By conducting both analyses, the case can gain insights into the broader industry landscape, identify potential risks and opportunities, and assess its own internal capabilities. This holistic understanding aids in making informed decisions and formulating effective strategies for positioning the Clean Edge Razor product.

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Answer:

D. all of these

Explanation:

In the classification of organisms, they are placed into groups which they appropriately fit into.

All the choices given correctly shows the process of classifying organisms. This aspect of biology is described as taxonomy.

Answer:

3.76375 * 10 ^24

Explanation:

1 mole of Nacl contains 6.022 * 10^23 Nacl formula units

Answer:

CH4 + 2O2 --> CO2 + 2H2O

Explanation:

"CO2" can be written as carbon dioxide

Answer:

show me a pic?? then I'll lyk