Mathematics High School

PLEASE HELP ME !!! 5. Jack is choosing between two pest control companies, Mouse Arrest and Hugs, not Bugs. The amount that the companies charge is shown by the equations below where y represents the total cost and x represents the number of months. a. Graph the system of equations. b. Find the solution to the system. c. What does the solution represent in the context of the situation?

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Answer 1

The solution to the equation is (5, 250) which is the point of intersection.

Linear equation

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the slope of the line and b is the y intercept.

Let y represent the total cost for renting pest company for x months.

Given the equation y = 25x + 125 and y = 50x. Graphing the equations.

The solution to the equation is (5, 250) which is the point of intersection.

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Related Questions

a measurable part of a line that consists of two points, called endpoints, and all of the points between them are

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A measurable part of a line that consists of two points, called endpoints, and all of the points between them are called Line sigments.

Geometry is a branch of mathematics that deals with how objects can be expressed as relationships of points, lines, planes, surfaces, and dimensions. When we draw lines in geometry, we use an arrow at each end to show that it expands infinitely. A line is a path between two points that can be measured. Since line segments have a defined length, they can form the sides of any polygon. The figure below shows the line AB, where the length of the line AB is related to the distance between its endpoints, A and B. The symbol for the line is named after its two endpoints, e.g.

$ \bar{AB}$

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a measurable part of a line that consists of two points, called endpoints, and all of the points between

Please solve i'll give 50 points find the area

Answers

Step-by-step explanation:

lets first find area of trapezium

1/2 x (a+b)x h

1/2 x (8x10) x6 (10 because 6 plus 4)

1/2 x 80 x 6

1/2 x 480

240 cm square is area of trapezium

now to find area of triangle

1/2x b x h

1/2 x 6 x 6

1/2x 36

18cm square

now if u want area of shaded part

trapezium minus triangle

240 minus 18

222cm square

Find the average value of the function over the given interval. f(x) = 6 x on [0, 9]

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The average value of the function f(x) = 6x over the interval [0, 9] is 27.

To find the average value of a function over a given interval, you need to take the definite integral of the function over that interval, and divide by the length of the interval. In this case, the function is f(x) = 6x, and the interval is [0, 9].

So first, we need to find the definite integral of 6x over [0, 9]:

∫[0,9] 6x dx = 3x^2 |[0,9] = 243

Next, we need to find the length of the interval, which is simply 9 - 0 = 9.

Finally, we divide the definite integral by the length of the interval:

Average value of f(x) = (1/9) * 243 = 27

So the average value of the function f(x) = 6x over the interval [0, 9] is 27.

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Helen flips a coin and rolls a dice calculate the probability of getting 4 and tails

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Answer:

1/12 or 0.0833

Step-by-step explanation:

P(Coin) = 1/2

P(Dice) = 1/6

1/2 × 1/6 = 1/12

claculate with Residu? \[ \begin{array}{l} \oint_{|z|=1} \frac{1}{z^{2} \sin z} d z \cdot . \\ \oint_{z \mid=2 \pi} \tan z d z \cdot \lambda \end{array} \] \[ \frac{1}{2 \pi i} \int_{0}^{1} \frac{d s}

Answers

Using the residue theorem, the values of the given integrals can be calculated by finding the residues at the singular points within the contour and applying the theorem.

To calculate the integral using the residue theorem, we need to find the residues of the given functions at their singular points within the contour.

For the first integral, $\oint_{|z|=1} \frac{1}{z^{2} \sin z} dz$, the singularities occur at $z = 0$ and $z = k\pi$ (where $k$ is an integer). We can calculate the residues at these points and sum them up using the residue theorem to find the value of the integral.

For the second integral, $\oint_{z \mid=2 \pi} \tan z dz$, the function $\tan z$ has singularities at $z = (2k+1)\frac{\pi}{2}$ (where $k$ is an integer). We find the residues at these points and use the residue theorem to evaluate the integral.

The third expression, $\frac{1}{2 \pi i} \int_{0}^{1} \frac{ds}{s}$, does not require the residue theorem. It simplifies to $\frac{1}{2 \pi i}$ times the natural logarithm of $1$, which is $0$.

Performing the necessary residue calculations and applying the residue theorem for the first two integrals, we can obtain their respective values.

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Transcribed image text: T8.7 A marketing assistant for a technology firm plans to randomly select 1000 customers to estimate the pro- portion who are satisfied with the firm's performance. Based on the results of the survey, the assistant will construct a 95% confidence interval for the propor- tion of all customers who are satisfied. The market- ing manager, however, says that the firm can afford to survey only 250 customers. How will this decrease in sample size affect the margin of error? (a) The margin of error will be about 4 times larger. (b) The margin of error will be about 2 times larger. (c) The margin of error will be about the same size. (d) The margin of error will be about half as large. (e) The margin of error will be about one-fourth as large. T8.8 Thirty-five people from a random sample of 125 work- ers from Company A admitted to using sick leave when they weren't really ill. Seventeen employees

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The answer is (b) The margin of error will be about 2 times larger.

The margin of error in a confidence interval is affected by the sample size, so decreasing the sample size will generally increase the margin of error. Specifically, the margin of error is inversely proportional to the square root of the sample size.

That is, if we reduce the sample size by a factor of k, then the margin of error will increase by a factor of sqrt(k).

In this case, the original sample size was 1000, and the proposed sample size is 250, which is 1/4 of the original size. Therefore, the margin of error for the smaller sample will be:

sqrt(1000/250) times the original margin of error.

Simplifying this expression, we get:

sqrt(4) times the original margin of error.

So the margin of error for the smaller sample will be about 2 times the original margin of error.

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Answer:

Step-by-step explanation:

Graph the equation y = 2.

Answers

Y=2 is a point on positive 2 on the y axis and a horizontal line across it

A procedure for approximating sampling distributions (which can then be used to construct confidence intervals) when theory cannot tell us their shape is:
a) residual analysis.
b) the bootstrap.
c) standardization.
d) least squares.

Answers

The procedure for approximating sampling distributions when the shape is unknown is the bootstrap method.

When theory cannot provide information about the shape of the sampling distribution, the bootstrap method is commonly used. The bootstrap is a resampling technique that allows us to estimate the sampling distribution by repeatedly sampling from the original data.

Here's how the bootstrap method works:

1. We start with a sample of data from the population of interest.

2. We randomly select observations from the sample, with replacement, to create a resampled dataset of the same size as the original sample.

3. We repeat this process numerous times, creating multiple resampled datasets.

4. With each resampled dataset, we calculate the statistic of interest (e.g., mean, median, standard deviation).

5. The distribution of these calculated statistics from the resampled datasets approximates the sampling distribution of the statistic.

By generating an empirical approximation of the sampling distribution through resampling, the bootstrap allows us to construct confidence intervals and make statistical inferences even when the underlying distribution is unknown or cannot be determined through theoretical means.

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there is a busy intersection between two one-way streets main street and 1st street avenue. Cars passing through the intersection can only pass through one at a time. When multiple cars arrive at the intersection at the same time, two queues can build up -- each for one street complete the function getResult

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The program that van be used to illustrate the information is given below.

How to illustrate the program?

The program that depicts the cars will be:

def getResult(arrival, street):

# Write your code here

result = []

# The first car arrives on Main Street at time 0. The first car arrives on 1st Avenue at time 0. The second car arrives on Main Street at time

1. The third car arrives on 1st Avenue at time 5.

time = 0

main_street_queue = []

first_avenue_queue = []

while len(main_street_queue) > 0 or len(first_avenue_queue) > 0:

if len(main_street_queue) == 0:

car_to_add_to_result = first_avenue_queue.pop(0)