\(\sf{n=\dfrac{7}{2}}\)
Explanation:-
\((\sqrt{3})^{7}=3^{n}\\\\(3^{\footnotesize{\dfrac{1}{2}}})^{7}=3^n\\\\3^{\small{\dfrac{7}{2}}}=3^{n}\\\\n=\dfrac{7}{2} \)\(\sf{ }\)
the sum of 5 consecutive positive integers is 2020. what is the largest of these numbers?
The largest of five consecutive positive integers whose sum is 2020 is 406.
We need to find the largest of five consecutive positive integers, and we know that the sum of these integers is 2020.
This is a problem that can be solved by using algebraic expressions.
Let's assume that x is the smallest of the five integers.
Therefore, the remaining four integers will be x+1, x+2, x+3, and x+4.
Adding these five numbers will give us the sum of the five consecutive integers as shown below;
x + (x+1) + (x+2) + (x+3) + (x+4) = 2020
Simplifying this equation, we have;
5x + 10 = 2020
Subtracting 10 from both sides, we get;
5x = 2010
Dividing both sides by 5, we get;
x = 402
Therefore, the five integers are;402, 403, 404, 405, 406
The largest of these five numbers is 406.
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chegg determine whether the vector field is conservative. if it is, find a potential function for the vector field.
The given vector field F = (2xy, x², y²) is conservative because its curl is zero. The potential function for this vector field can be found by integrating each component of the vector field with respect to the corresponding variable, resulting in a potential function of f(x, y, z) = x²y + xy² + C, where C is an arbitrary constant.
To determine whether a vector field is conservative, we can use the curl of the vector field. If the curl of the vector field is zero, then the vector field is conservative.
Let's consider a sample vector field F = (2xy, x², y²).
To determine if this vector field is conservative, we need to calculate its curl:
Curl(F) = (∂F₃/∂y - ∂F₂/∂z, ∂F₁/∂z - ∂F₃/∂x, ∂F₂/∂x - ∂F₁/∂y)
Calculating the partial derivatives, we have:
∂F₁/∂x = 2y
∂F₂/∂y = 0
∂F₃/∂z = 0
∂F₂/∂x = 0
∂F₃/∂y = 2y
∂F₁/∂z = 0
Substituting these values into the curl formula, we get:
Curl(F) = (0 - 0, 0 - 0, 2y - 2y)
= (0, 0, 0)
Since the curl of the vector field is zero, we can conclude that the vector field F = (2xy, x², y²) is conservative.
To find a potential function for this vector field, we integrate each component of the vector field with respect to the corresponding variable:
∫F₁ dx = ∫2xy dx = x²y + C₁(y, z)
∫F₂ dy = ∫x² dy = xy² + C₂(x, z)
∫F₃ dz = ∫y² dz = y²z + C₃(x, y)
Here, C₁, C₂, and C₃ are arbitrary functions of the variables that do not depend on the integration variable.
The potential function for the vector field F is given by:
\(f(x, y, z) = x^2y + xy^2 + y^2z + C\)
Where C is an arbitrary constant that incorporates the integration constants from each component of the vector field.
Thus, the potential function for the vector field \(F = (2xy, x^2, y^2)\) is \(f(x, y, z) = x^2y + xy^2 + y^2z + C\).
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What is the area of this figure?
13 in
6 in
8 in
s in
5 in
17 in
10 in
Write your answers using decimals, If necessary.
Answer:
If i am correct the area should 337inches..........
Step-by-step explanation:
my reason is becuase if you multiply these numbers
13* 6 = 78 and 8 * 8 = 64 and 10 * 17 + 170 and last 5 * 5 = 25
they you add 170+ 78 + 64 + 25 = 337inches so means the answer is 337 Your Welcome :D
Let g(x) = 5x +6x if x <5 a if x-5
3x+I if x > 5 a. Determine the value of a for which g is continuous from the left at 5 b. Determine the value of a for which g is continuous from the right at 5. c. Is there a value of a for which g is continuous at 5?
g(x) = 5x +6x if x <5 a if x-5
3x+I if x > 5 a
The value of a for which g is continuous from the right at 5 is 15.
Let g(x) = 5x +6x if x < 5 and 3x+a if x > 5.
a. To determine the value of a for which g is continuous from the left at 5, we set the left-hand limit equal to the right-hand limit and solve for a:
5 + 6(5) = 3(5) + a
30 = 15 + a
a = 15
Therefore, the value of a for which g is continuous from the left at 5 is 15.
b. To determine the value of a for which g is continuous from the right at 5, we set the right-hand limit equal to the left-hand limit and solve for a:
3(5) + a = 5 + 6(5)
15 + a = 30
a = 15
Therefore, the value of a for which g is continuous from the right at 5 is 15.
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Complete the sequence.
1/2,3/5,5/8,7/11, ___ , ____
(will mark brainliest)
Answer:
1/2,3/5,5/8,7/11,9/14,11/17
Explanation:
Each time, the numerator of the fraction goes up by 2 and the denominator goes up by 3.
Answer:
9/14, 11/17
Step-by-step explanation:
The pattern observed is :
Numerator increases by 2Denominator increases by 3Hence, the next 2 terms are :
9/14, 11/17Which equation is equivalent to the formula r = st? t equals s over r t = rs s equals r over t s = rt.
Answer:
Step-by-step explanation:
r = st------------Other correct expressions:
t = r/s
s = r/t
------------------
Choices
1) t = s/r No
2) t = rs No
3) s =r/t Yes
4) s = rt No
The equation that is equivalent to the given equation is \(s = r/t\) and this can be determined by using the arithmetic operations.
Given :
Equation is \((r = st)\).
The following steps can be used in order to determine the equation that is equivalent to the given equation:
Step 1 - Write the given equation.
\(r = st\) --- (1)
Step 2 - The arithmetic operations can be used in order to determine the equation that is equivalent to the given equation.
Step 3 - Now, divide 't' on both sides in the equation (1).
\(\dfrac{r}{t} = \dfrac{st}{t}\\\\\\dfrac{r}{t}=s\)
Therefore, the correct option is C).
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Please help asap ill give you brainlest
Consider − 196 14. Which THREE statements are correct?
A) The quotient is 14.
B) The quotient is −14.
C) The quotient is − 1 14.
D) −196 14 is equivalent to the expression.
E) 196 −14 is equivalent to the expression.
Answer:
B, E, and D are correct
Step-by-step explanation:
A bag contains 20 coloured marbles. Copy and
complete the table below to show the probability of
picking each colour at random and the number of
each colour marble in the bag. What is the
probability, as a percentage (%), of picking a purple
marble at random? How many purple marbles are in
the bag?
Colour
Yellow
Blue
Green
Purple
Probability
10%
15%
Number of marbles
6
Mario and Carlos, two brothers, play for the same basketball team. Here are the points they scored in 10 games:
The highest point scored is by Carlos with 19 points. Mario's highest was 15. so, Carlos scored 4 points more than Mario.
In the 7th game, Carlos scored 19 points which is the highest point of his game. In the 1st game, Mario scored 15 points which was the highest point he scored. Therefore, Carlos had the highest scoring game between the two of them. Carlos scored 4 points more than Mario did in his highest-scoring game. You can also construct a box plot for this question which will help you visualise this better. The box plot can be made by drawing a number line and marking the following points: minimum, first quartile, median, third quartile and maximum.
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The full question is:
Mario and Carlos, two brothers, play for the same basketball team. Here are the
points they scored in 10 games:
Game 1 2 3 4 5 6 7 8 9 10
Mario 15 X X 12 7 11 12 11 10 11
Carlos 10 X 9 12 15 X 19 11 12 12
(Xs mark games each one missed.) Which brother had the
highest-scoring game? How many more points did he score in
that game than the other brother did in his highest-scoring game?
How to find the b value in slope intercept form.
20 chaarcareatcers because i accidentally submitted the question to mathematics
Answer:
Step-by-step explanation:
Its 8273.8
Which product of prime polynomials is equivalent to 30x3 – 5x2 – 60x? a. 5(2x2 – 3)(3x 4) b. x(10x 3)(3x – 4) c. 5x(2x – 3)(3x 4) d. 5x(2x 3)(3x – 4)
The product of prime polynomials which is equivalent to 30x3 – 5x2 – 60x is option C) 5x(2x – 3)(3x + 4).
We have 30x³ - 5x² - 60x
We take common value out so
5x(6x² - x - 12)
By following the factorization method we get,
6x² - x - 12
b²-4ac = -1² - 4x6x(-12)
= 289
x = -b ± √289/2a
= 1 ± 17/-2
x = 3/2 or x = -4/3
So,
6x² - x - 12
6(x-3/2)(x-(-4/3))
(2x-3) (3x+4)
Therefore,
30x³ - 5x² - 60x = 5x(6x² - x - 12)
= 5x (2x-3) (3x+4)
The product of prime polynomials is equivalent to 30x3 – 5x2 – 60x is 5x(2x – 3)(3x + 4).
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ertanyaan
Use the fifth partial sum of the exponential series to approximate each value. Round to three decimal places.
�
−
2.5
e
−2.5
using the fifth partial sum of the exponential series, the approximation for e^(-2.5) is approximately 1.649 (rounded to three decimal places).
To approximate the value of e^(-2.5) using the fifth partial sum of the exponential series, we can use the formula:
e^x = 1 + x + (x^2 / 2!) + (x^3 / 3!) + (x^4 / 4!) + ... + (x^n / n!)
In this case, we have x = -2.5. Let's calculate the fifth partial sum:
e^(-2.5) ≈ 1 + (-2.5) + (-2.5^2 / 2!) + (-2.5^3 / 3!) + (-2.5^4 / 4!)
Using a calculator or performing the calculations step by step:
e^(-2.5) ≈ 1 + (-2.5) + (6.25 / 2) + (-15.625 / 6) + (39.0625 / 24)
e^(-2.5) ≈ 1 - 2.5 + 3.125 - 2.60417 + 1.6276
e^(-2.5) ≈ 1.64893
Therefore, using the fifth partial sum of the exponential series, the approximation for e^(-2.5) is approximately 1.649 (rounded to three decimal places).
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The question is in the image below.
The fourth:
The second equation in system 2 is the difference of the equations in system 1. The first equation in system 2 is the first equation in system 1.
Ax + By - (Lx + My) = Ax + By - Lx - My = (A - L)x + (B - M)y
Answer:
The answer is __
because of __
Step-by-step explanation:
Boi was driving from mombasa to nairobi at an average speed of 63.8 km/h. he drove for hours then his car broke down. what distance had he covered when his car broke down
\( 350 \mathrm{y} \) C P sas \( \cos u \)
The given expression, \(\(350y \cdot C \cdot \cos(u)\)\), involves variables \(\(y\), \(C\)\), and \(\(u\)\) and their respective operations and functions.
The expression \(\(350y \cdot C \cdot \cos(u)\)\) represents a mathematical equation involving multiplication and the cosine function. Let's break down each component:
1. \(\(350y\)\) represents the product of the constant value 350 and the variable \(y\).
2. \(\(C\)\) is a separate variable that is being multiplied by \(\(350y\)\).
3. \(\(\cos(u)\)\) represents the cosine of the variable \(\(u\)\).
The overall expression represents the product of these three terms: \(\(350y \cdot C \cdot \cos(u)\)\).
To evaluate this expression or derive any specific meaning from it, the values of the variables \(\(y\), \(C\)\), and \(\(u\)\) need to be known or assigned. Without specific values or context, it is not possible to provide a numerical or simplified result for the given expression.
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Which value is NOT greater than [-4.2] A [-4.2]
B [3.5]
C [4.1]
D [-4.5]
The value that is NOT greater than [-4.2] is D. [-4.5]
The values [-4.2], [3.5], and [4.1] are all greater than [-4.5]. To determine which value is the greatest, we can use a number line or compare the numbers directly. On a number line, we can see that [-4.5] is located to the left of [-4.2], [3.5], and [4.1]. This means that [-4.2], [3.5], and [4.1] are all greater than [-4.5].
Alternatively, we can compare the values directly. We know that -4.5 is less than -4.2 since -4.5 is farther to the left on the number line. We also know that 3.5 and 4.1 are positive values, which are greater than any negative value. Therefore, the answer is [-4.5] is not greater than [-4.2]. Hence, option D is correct.
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What is the domain of the following function? {-3, 1} {-4, -3, 1, 2, 6, 9} All Real Numbers {-4, 2, 6, 9}
Answer:
{-4, 2, 6, 9}
Step-by-step explanation:
I took the quiz lol
vanessa tried to prove that \triangle klm\cong \triangle mnk△klm≅△mnktriangle, k, l, m, \cong, triangle, m, n, k. statement reason 1 \overline{kl}\cong\overline{mn} kl ≅ mn start overline, k, l, end overline, \cong, start overline, m, n, end overline given 2 \overline{lm}\cong\overline{nk} lm ≅ nk start overline, l, m, end overline, \cong, start overline, n, k, end overline given 3 \triangle klm\cong \triangle mnk△klm≅△mnktriangle, k, l, m, \cong, triangle, m, n, k side-side-side congruence what is the first error vanessa made in her proof? choose 1 answer: choose 1 answer:
What is the first error Vanessa made in her proof: B. Vanessa only established some of the necessary conditions for a congruence criterion.
What are the properties of similar triangles?In Mathematics and Geometry, two triangles are said to be similar when the ratio of their corresponding side lengths are equal and their corresponding angles are congruent.
Additionally, the lengths of three (3) pairs of corresponding sides or corresponding side lengths are proportional to the lengths of corresponding altitudes when two (2) triangles are similar.
Based on the reflexive property of equality, we can logically deduce the following congruent and similar triangles:
KM ≅ KM
ΔKLM ≅ ΔMNK (SSS similarity theorem).
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
11111111111111111111111111111111x2222222222222222222222222222222222222222222222222222222222222
Answer:
222222222222222222
Step-by-step explanation:
4. The side of a square measures 4x+ 1 feet. The perimeter is 260 feet. Find x, then find
the side length of the square.
Answer:
Step-by-step explanation:
Perimeter = s+s+s+s = 4s
4(4x+1) = 260
16x + 4 = 260
16x = 256
x = 16
4(16) + 1 = 65
Graph the following exponential function given the table of
values.
Answer:
D
Step-by-step explanation:
Here, we want to select the graph of the given exponential function values
Let us take a look at the y-intercept
At the y-intercept, the value of x is 0
The y-intercept for this particular equation is 1
This mean that the y-intercept value is 1
hence, the graph will touch the y-axis at the point y = 1
looking at the graphs , only the graph D provides this, and that should be our answer
If the m\angle∠Y = (4x + 21)o and m\angle∠Z = (6x + 12)o, find m\angle∠Z.
Answer:
Step-by-step explanation:
*PLEASE ANSWER!!! I DON'T GET IT!!!*
EXPLAIN W DETAILS IF NEEDED OFC. TY<3
Answer: A
Step-by-step explanation:
When x=-2, y=1. This would imply that the constant of proportionality is -1/2.
However, then x=3 and y=6, implying the constant of proportionality would be 2.
Since these are different, it is not a direct variation.
Find the area of the region that lies inside the first curve and outside the second curve. 25. r2-8 cos 20, r= 2 29-34 Find the area of the region that lies inside both curves. 29. r= 3 cose, r=sin
25. The area of the region that lies inside the first curve and outside the second curve is 4[√3/2 - 2π/3] square units.
29. The area of the region that lies inside both curves is approximately 1.648 square units.
What is cylinder?A 3D solid shape called a cylinder is formed by connecting two parallel and identical bases with a curving surface. The shape of the bases is similar to a disc, and the axis of the cylinder runs through the middle or connects the two circular bases.
25. To find the area of the region that lies inside the first curve and outside the second curve, we need to find the points where the two curves intersect, and then integrate the difference in the areas between the two curves from one intersection point to the other.
The two curves are given by:
r² = 8 cos θ (first curve)
r = 2 (second curve)
To find the intersection points, we substitute r = 2 into the first equation and solve for θ:
2² = 8 cos θ
cos θ = 1/2
θ = ±π/3
So the two curves intersect at θ = π/3 and θ = -π/3. To find the area between the curves, we integrate the difference in the areas between the two curves from θ = -π/3 to θ = π/3:
A = ∫[-π/3,π/3] [(1/2)r² - 2²] dθ
Using the equation r² = 8 cos θ, we can simplify this to:
A = ∫[-π/3,π/3] [(1/2)(8 cos θ) - 4] dθ
A = ∫[-π/3,π/3] (4 cos θ - 4) dθ
A = 4 ∫[-π/3,π/3] (cos θ - 1) dθ
\(A = 4 [sin \theta - \theta]_{(-\pi/3)^{(\pi/3)\)
A = 4 [sin(π/3) - π/3 - (sin(-π/3) + π/3)]
A = 4 [√3/2 - 2π/3]
Therefore, the area of the region that lies inside the first curve and outside the second curve is 4[√3/2 - 2π/3] square units.
29. To find the area of the region that lies inside both curves, we need to determine the points where the two curves intersect and then integrate the area enclosed between the curves over the appropriate range of polar angles.
The two curves are given by:
r = 3 cos(θ) (first curve)
r = sin(θ) (second curve)
To find the intersection points, we substitute r = 3 cos(θ) into the equation r = sin(θ) and solve for θ:
3 cos(θ) = sin(θ)
tan(θ) = 3
θ = tan⁻¹(3)
The intersection point lies on the first curve when θ = tan⁻¹(3), so we need to integrate the area enclosed between the curves from θ = 0 to θ = tan⁻¹(3).
The area enclosed between the curves at any angle θ is given by the difference in the areas of the circles with radii r = sin(θ) and r = 3 cos(θ). Thus, the area enclosed between the curves is:
A = ∫[0,tan⁻¹(3)] [(1/2)(3 cos(θ))² - (1/2)(sin(θ))²] dθ
Simplifying, we get:
A = ∫[0,tan⁻¹(3)] [9/2 cos²(θ) - 1/2 sin²(θ)] dθ
Using the identity cos(2θ) = cos²(θ) - sin²(θ), we can simplify this to:
A = ∫[0,tan⁻¹(3)] [(9/2)(cos²(θ) - (1/2)) + (1/2)cos²(2θ)] dθ
We can evaluate the first term of the integrand using the identity cos²(θ) = (1 + cos(2θ))/2, and the second term using the identity cos²(2θ) = (1 + cos(4θ))/2:
A = ∫[0,tan⁻¹(3)] [(9/4)(1 + cos(2θ)) - (1/4)(1 + cos(4θ))] dθ
Integrating each term separately, we get:
\(A = [(9/4)\theta + (9/8)sin(2\theta) - (1/16)sin(4\theta)]_{0^{(tan^-1(3))\)
Simplifying and evaluating, we get:
A = (9/4)tan⁻¹(3) + (9/8)sin(2tan⁻¹(3)) - (1/16)sin(4tan⁻¹(3))
Using the identity sin(2tan⁻¹(3)) = 6/10 and simplifying, we get:
A = (9/4)tan⁻¹(3) + (27/40) - (3/40)tan⁻¹(3)
Therefore, the area of the region that lies inside both curves is approximately 1.648 square units.
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68 is the product of Victor's savings and 4.
Just tell me the equation and ill answer it
Cody's heart beats 4,380 times per hour
when he is at rest. How many beats is
that per minute?
Answer:
Divide 4,380 by 60
4,380 ÷ 60 = 73
Step-by-step explanation:
which was EAV-Secure Prove the opposite - i.e. if G is not a PRG, then 3.17 cannot be EAV-secure. Let G be a pseudorandom generator with expansion factor ℓ. Define a private-key encryption scheme for messages of length ℓ as follows: - Gen: on input 1n, choose uniform k∈{0,1}n and output it as the key. - Enc: on input a key k∈{0,1}n and a message m∈{0,1}ℓ(n), output the ciphertext c:=G(k)⊕m. - Dec: on input a key k∈{0,1}n and a ciphertext c∈{0,1}ℓ(n), output the message m:=G(k)⊕c. A private-key encryption scheme based on any pseudorandom generator. THEOREM 3.18 If G is a pseudorandom generator, then Construction 3.17 is a fixed-length private-key encryption scheme that has indistinguishable encryptions in the presence of an eavesdropper. PROOF Let Π denote Construction 3.17. We show that Π satisfies Definition 3.8. Namely, we show that for any probabilistic polynomial-time adversary A there is a negligible function negl such that Pr[PrivKA,Πeav(n)=1]≤21+neg∣(n)
To prove the opposite, we need to show that if G is not a pseudorandom generator (PRG), then Construction 3.17 cannot be EAV-secure.
Assume that G is not a PRG, which means it fails to expand the seed sufficiently. Let's suppose that G is computationally indistinguishable from a truly random function on its domain, but it does not meet the requirements of a PRG.
Now, consider the private-key encryption scheme Π described in Construction 3.17 using G as the pseudorandom generator. If G is not a PRG, it means that its output is not sufficiently pseudorandom and can potentially be distinguished from a random string.
Given this scenario, an adversary A could exploit the distinguishability of G's output and devise an attack to break the security of the encryption scheme Π. The adversary could potentially gain information about the plaintext by analyzing the ciphertext and the output of G.
Therefore, if G is not a PRG, it implies that Construction 3.17 cannot provide EAV-security, as it would be vulnerable to attacks by distinguishing the output of G from random strings. This contradicts Theorem 3.18, which states that if G is a PRG, then Construction 3.17 achieves indistinguishable encryptions.
Hence, by proving the opposite, we conclude that if G is not a PRG, then Construction 3.17 cannot be EAV-secure.
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When doing a pull-up, a physics student lifts her 42 kg body to a distance of 0.25 m in 2 seconds. What is the power delivered by the student's biceps?
The power delivered by the student's biceps is 51.45 watts (W).
To calculate the power delivered by the student's biceps while doing a pull-up, we use the formula:
Power = Work/Time
Since the physics student lifts her 42 kg body to a distance of 0.25 m, the work done is given by:
Work = Force x Distance
The force exerted by the student is equal to her weight, which is given by:
F = mg
where m = 42 kg (mass of the student) and
g = 9.8 m/s² (acceleration due to gravity)
Therefore,
F = 42 kg x 9.8 m/s²
= 411.6 N (weight of the student)
Hence, the work done by the student is:
Work = Force x Distance
= 411.6 N x 0.25 m
= 102.9 J (joules)
The time taken by the student to complete the pull-up is given as 2 seconds.
Therefore:Time = 2 s
Now we can substitute the values into the formula for power:
Power = Work/Time
= 102.9 J/2 s
= 51.45 W
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Find the angle of the sector given the radius and the area of the sector.
Radius = 12 ft
Area of sector is 339.3 ft2
Answer:
270 degrees
Step-by-step explanation:
\(Area \: of \: the \: sector \\ \\ = \frac{ \theta}{360 \degree} \times \pi {r}^{2} \\ \\ 339.3 = \frac{ \theta}{360 \degree} \times 3.14 {(12)}^{2} \\ \\ 339.3 = \frac{ \theta}{360 \degree} \times 3.14 \times 144 \\ \\ \theta = \frac{339.3 \times 360 \degree}{3.14 \times 144} \\ \\ \theta = \frac{122,148\degree}{452.16} \\ \\ \theta= 270.143312 \degree \\ \\ \theta \approx \: 270\degree\)