Please help I need it asap

you will need to be sure to count all of atoms on each side of the chemical equation. Once you know how many of each type of atom you can only change the coefficients (the numbers in front of atoms or compounds) to balance the equation for Aluminum + Iron (II) oxide

Explanation:

34.31+35.45(2)=

27.31+70.90=

95.21g/mol

Answer:

\(56 \times { \frac{01514344}{?} }^{2} 5566648443hffii51 \\ \div 232333\)

Answer:

write a letter to the presiding member of your district assessment telling him or her about two of the achievement of your community over the last five years and the plans for the future

Answer:

becomes less stable

Explanation:

Answer: when electron is excited a higher energy orbital it gets farther away from the atom. The further the orbital is from the nucleus, the higher the potential energy of an electron at that energy level.

Explanation:

Nucleic acids are made by forming phosphodiester bonds between nucleotide monomers. This is an example of a condensation reaction.

Condensation reactions are chemical reactions where two molecules combine to form one single molecule while releasing a small molecule as a byproduct. The formation of a phosphodiester bond between nucleotides is an example of a condensation reaction. This is because during this process, the phosphate group is removed from the nucleotide, releasing water. This reaction involves the joining of two monomers with the release of water, leading to the formation of a polymer. Nucleotides are the monomers that make up nucleic acids, including DNA and RNA. The nucleotide monomer consists of three parts: a nitrogenous base, a five-carbon sugar, and a phosphate group. When nucleotides bond together, they form a nucleic acid chain. The bond between the nucleotides is known as the phosphodiester bond, which is formed between the phosphate group of one nucleotide and the sugar molecule of another nucleotide.

nucleic acids are made by forming phosphodiester bonds between nucleotide monomers. This reaction is a condensation reaction that results in the release of water as a byproduct.

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Answer:

0.97 kg/l

Explanation:

Answer: Gains an extra electron in 2p orbitals it's option Y (1s²,2s², 2p⁶

The given statement is true that nonenzymatic E1 reactions can often result in a mixture of more than one alkene product. This is due to the presence of different possible elimination products.

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we use the formula

pV=nRT

we convert Kilo Pascals to mmHg

253.25 KPa=253250 pascals

1mmHg is equal to 133.322 pascals

xmmHg are equal to 253250pascals

x=253250/133.322=1900mmHg

now we convert mmHg to atmospheres

1 atmosphere is equal to 760mmHg

x atmospheres are equatl to 1900mmHg

x=1900/760=2.5 atmospheres

in the formula:

pV=nRT

p-pressure

V-volume

n-number of moles

R-ideal constant of gases

T-temperature

the only missing variable is temperature since we know that  R=0.082

250ml=0.25L

0.25*2.5=0.1*0.082T

T=0.625/0.0082=76.219K

Answer:C

Explanation:

Diagram C shows the repeating groups of atoms that make up the samples Damian mixed together.

A homogenous combination of multiple parts with particles smaller than 1 nm is referred to as a solution. Solutions come in many forms, including soda water, salt and sugar solutions, and others.

Damian mixed two samples together: red liquid that smells irritating and a black solid with no smell. He analyzed the results and found two ending substances. One of the ending substances was a yellow solid. This ending substance is made up of the repeating group of atoms shown above. Diagram C  shows the repeating groups of atoms that make up the samples Damian mixed together.

Therefore, diagram C  shows the repeating groups of atoms that make up the samples Damian mixed together.

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Explanation:

When we have direct sunlight, the temperature is higher compared to indirect sunlight.

Direct sunlight is usually overhead whereas indirect sunlight is at an angle to the surface.

Answer: The correct option is A. The moon's orbit around Earth

Explanation: Newtons first law of motion says that an object in motion will always remain in motion and an object in erst will always stay at rest untill an external force acts upon it. This law is also called law of inertia which is the property of a body to resist any change in its state of rest or motion. Since moon is also revolving around the earth so it is in motion always and it continues its motion.

Answer:

the moon’s orbit around Earth

Explanation:

To calculate the final temperature of a water-metal mixture, you need to use the principle of conservation of energy. The equation for this is:

where m1 and m2 are the masses of the metal and water, c1 and c2 are their respective specific heat capacities, and ΔT1 and ΔT2 are the changes in their temperatures. You can solve for the final temperature by rearranging this equation.

The actual temperature of the mixture may differ from the calculated final temperature due to several factors, such as the heat loss to the environment during the experiment, imperfect mixing of the water and metal, and measurement errors. These factors can introduce uncertainties in the experimental results, leading to differences between the predicted and actual temperatures.

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The calculated final temperature was slightly lower than the actual temperature of the water-metal mixture. This difference is most likely due to the heat loss due to the environment and also the heat capacity of the mixture.

The calculated final temperature which was slightly lower than that of the actual temperature of the water-metal mixture. This difference in temperature is most likely due to the heat loss due to the environment and heat capacity of the metal-water mixture.

To calculate the final temperature of a water-metal mixture, a person need to use the principle of conservation of energy. The equation for this condition is:

m₁c₁ΔT₁ + m₂c₂ΔT₂ = 0

where m₁ and m₂ are the masses of the metal and water, c₁ and c₂ are their respective specific heat capacities, and ΔT₁ and ΔT₂ are the changes in their temperatures.

The actual temperature of the metal-water mixture may differ from that of the calculated final temperature due to several different factors, such as the heat loss to the environment during the experiment, imperfect mixing of the water and metal element, and the measurement errors. These factors can introduce uncertainties in the experimental results as well, which lead to the differences between the predicted and actual temperatures.

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Given parameters:

Density of the rock = 2.2g/cm³

Volume of rock = 66.5mL

Unknown:

Mass of the rock = ?

Solution:

Density is the mass per unit volume of a body. It is mathematically expressed as shown below;

          Density  = \(\frac{mass}{volume}\)

So;

         Mass = Density x Volume

We need to take the given parameters to the same unit before we solve;

              convert mL to cm³

                 1mL  = 1cm³;  66.5mL is the same as 66.5cm³

Now solve;

          Mass  = 2.2 x 66.5  = 146.3g

The mass of the rock is 146.3g

1) Balance the chemical equation.

Step 1: Assign oxidation numbers

PbO2: Pb (+4) and O (-2)

Mn2+: Mn (+2)

Pb2+: Pb (+2)

MnO4-: Mn (+7) and O (-2)

Step 2: Figure out what's being reduced and what's being oxidized.

Mn has been oxidized. It changed from (+2) to (+7)

Pb has been reduced. It changed from (+4) to (+2)

Step 3: Write half-reaction

Oxidation half-reaction

Reduction half-reaction

Step 4: Balance all elements EXCEPT for hydrogen and oxygen

Oxidation half-reaction

Reduction half-reaction

Step 5: Balance oxygens. We do so by adding water molecules to the half-reactions as needed.

Oxidation half-reaction

Reduction half-reaction

Step 6: Balance hydrogens. We do so by adding protons (H+) to the half-reactions as needed.

Oxidation half-reaction

Reduction half-reaction

Step 7: Balance charges. We do so by adding electrons

Oxidation half-reaction

Reduction half-reaction

Step 8: Multiply half-reactions to make the number of electrons equal.

Oxidation half-reaction.

New oxidation half-reaction.

Reduction half-reaction

New reduction half-reaction

Step 9: Cancel electrons and combine the half-reactions

Overall reaction

Step 10: Balance the chemical equation by reducing the number of water molecules and protons.

Overall reaction

2) The balanced chemical equation

Overall reaction

.

The pH of the resulting solution after adding 0.0248 moles of hydrochloric acid to the buffer containing 0.348 M ammonium chloride and 0.339 M ammonia is approximately 7.967.

To calculate the pH of the resulting solution after adding hydrochloric acid to a buffer containing 0.348 M ammonium chloride and 0.339 M ammonia, follow these steps:

1. Determine the initial moles of ammonium chloride (NH₄Cl) and ammonia (NH₃) in the solution:
- Moles of NH₄Cl = (0.348 M) x (0.125 L) = 0.0435 moles
- Moles of NH₃ = (0.339 M) x (0.125 L) = 0.042375 moles

2. Calculate the moles of NH₄Cl and NH₃ after the reaction with HCl:
- Moles of HCl added = 0.0248 moles
- The reaction between NH₃ and HCl produces NH₄Cl: NH₃ + HCl → NH₄Cl
- Moles of NH₄Cl after reaction = 0.0435 moles (initial) + 0.0248 moles (from HCl) = 0.0683 moles
- Moles of NH₃ after reaction = 0.042375 moles (initial) - 0.0248 moles (reacted with HCl) = 0.017575 moles

3. Calculate the new concentrations of NH₄Cl and NH₃:
- [NH₄Cl] = 0.0683 moles / 0.125 L = 0.5464 M
- [NH₃] = 0.017575 moles / 0.125 L = 0.1406 M

4. Use the Henderson-Hasselbalch equation to find the pH:
- pH = pKₐ + log ([NH₃] / [NH₄⁺])
- The pKₐ of ammonia (NH₃) is 9.25
- pH = 9.25 + log (0.1406 / 0.5464) = 9.25 - 1.283 = 7.967

The pH of the resulting solution after adding 0.0248 moles of hydrochloric acid to the buffer containing 0.348 M ammonium chloride and 0.339 M ammonia is approximately 7.967.

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Answer:

A test variable is a user-defined, name-value pair that stores and refers to information throughout a test and between tests.

Provide a default value to the variable during declaration.

Change the value of the variable using Set Variable statement. You can use the Add and Insert menus of the Test Editor to create Set Variable statements.

Set hard-coded value or value retried from a data source, such as dataset or reference that appears before the Set statement to the variable.

If a variable is initialized at various places such as test, compound test, schedule, or user group, the product uses the following order to initialize the value of the variable when running the test. The variable set in the variable table of the compound test editor takes the highest precedence followed by others:

Compound test setting in the variable table UI

Compound test specified in a var file

User group setting in the variable table UI

User group specified in a var file

Schedule specified setting in the variable table UI

Schedule specified in a var file

Command line

Outcome variables are usually the dependent variables which are observed and measured by changing independent variables. These variables determine the effect of the cause (independent) variables when changed for different values. The dependent variables are the outcomes of the experiments determining what was caused or what changed as a result of the study.

For a simple example, the marks a student obtains in an exam is a result of the hard word measured in the number of hours put behind studying and the intelligence measured in IQ are the independent variables. The marks obtained thus represents the dependent or outcome variable. When the values of the independent variables are changed, the marks may or may not change and hence dependent variables are dependent on the independent variables while the opposite is implausible i.e., when the marks are changed, it doesn’t change the number of hours of study or the IQ of the student.

The response variable is also called as the dependent variable because it depends on the causal factor, the independent variable. Depending on the various input values of the experimental variables, the responses are recorded.

Answer:

7.224 × 10^28 atoms

Explanation:

The number of moles contained in a substance (n) can be calculated from this expression:

nA = n × 6.02 × 10^23 atoms

Where;

nA = number of atoms of substance

n = number of moles of substance

Avagadro's number or constant = 6.02 × 10^23 atoms

Using nA = n × 6.02 × 10^23 atoms

In this question, there are 1.2 x 10^5 moles of neon (N). The number of atoms (nA) is as follows:

nA of neon = 1.2 x 10^5 × 6.02 × 10^23

nA = 7.224 × 10^ (5 + 23)

nA = 7.224 × 10^28 atoms

The number of neon atoms in 1.2 x 10^5 is 7.224 × 10^28 atoms.

\(\\ \rm\dashrightarrow \Delta T_f=ik_fm\)

Moles of NaCl

Molality

\(\\ \rm\dashrightarrow \Delta T_f=i(-1.86)(8.68)\)

\(\\ \rm\dashrightarrow \Delta T_f=-16.14i\)

i is vant Hoff factor

For NaCl vant Hoff factor is 2( Actually 1.9)

\(\\ \rm\dashrightarrow \Delta T_f=-16.14(2)=-32.28°C\)

Moles of NaCl

\(\\ \tt{:}\dashrightarrow \dfrac{1000g}{23g/mol}\)

\(\\ \tt{:}\dashrightarrow 43.4mol\)

Find Molality

\(\boxed{\sf Molality=\dfrac{Moles\:of\:solute}{Volume \:of\: solution\:in\:kg}}\)

\(\\ \tt{:}\dashrightarrow m=\dfrac{43.4}{6}=7.2m\)

Vant Hoff factor

\(\\ \tt{:}\dashrightarrow NaCl\longrightarrow Na^++Cl^-\)

Freezing point depression

\(\\ \tt{:}\dashrightarrow \Delta T_f=iK_fm\)

\(\\ \tt{:}\dashrightarrow \Delta T_f=2(-1.86)(7.2)\)

\(\\ \tt{:}\dashrightarrow \Delta T_f=-26.7°C\)

Answer:

D

Explanation:

Van der Waal  forces are  small dipole attractions between molecules caused by a temporary electron shift ,here, the option D  is correct.

Van der Waals forces exist among all kinds of atoms and molecules. The origin of this  force stems from the instantaneous dipole-induced dipole interactions among adjacent polar atoms and molecules.

Among polar molecules, there are three components that contribute to the total  forces: the induction force, the orientation force and the dispersion force.

The  Van Der Waal forces that act between macroscopic bodies and surfaces in a solvent medium are relevant to the phenomena of protein adsorption.

Van Der Waal forces are the small dipole attractions between molecules caused by a temporary electron shift , thus, option D is correct.

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During an experiment, spectrophotometer is calibrated after inserting the cuvette containing the analyte,to reduce errors in results.

Errors in chemical analysis result when there is a difference between observed value and the true value.If the magnitude of errors is large , it results in decrease in accuracy, reproducibility, and precision.

There are three types of errors:1) random error 2) systematic error 3) human error.The cause of random errors are difficult to quantify while the human errors can be minimized by taking a range of readings to reduce the error.

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Answer:

The equation is not balanced.

Explanation:

The Law of Conservation of Matter is also called the law of conservation of mass or the Lomonosov-Lavoisier Law. This law postulates that "the mass is neither created nor destroyed, it only transforms." This means that the reactants interact with each other and form new products with different physical and chemical properties than the reactants because the atoms of the substances are arranged differently. But the amount of matter or mass before and after a transformation (chemical reaction) is always the same, that is, the amounts of the masses involved in a given reaction must be constant at all times, not changing in their proportions when the reaction ends. . In other words, then the mass before the chemical reaction equals the mass after the reaction. The exception to the rule is nuclear reactions, in which it is possible to convert mass into energy and vice versa.

This is, te law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts.  

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

Then, taking into account all of the above, you can determine the amount of elements on each side of the equation:

Left side: 2 hydrogen H and 2 oxygen O  

Right side: 2 hydrogen H and 3 oxygen O

Since the quantity of each element is different on each side of the reaction, the equation is not balanced.

The balanced equation is:

2 H₂O₂ → 2 H₂O + O₂  

Answer: C

Explanation: This is because of a nice thing called guessing

Answer: 5.747 * 10^14 Hz

Explanation:

Convert 522nm to m = 522 * 10^-9 m (since 1nm=10^-9m)

If c = wavelength * frequency, where c is the speed of light (3.0 * 10^8 m/s), then you can manipulate the equation to solve for frequency (f).

f = c / wavelength

Plug in the given numbers:

f = (3.0 * 10^8) / (10^-9)

f = 5.747 * 10^14 Hz

Answer:

The wavelength λ is the distance between successive peaks in a wave. The frequency f of a wave is the number of complete waves that pass a point in a given time. where c is the speed of light. In your case, λ = 522 nm = 522 × 10⁻⁹ m and c = 2.998 × 10⁸ m·s⁻¹

Explanation:

The concentration of the pollutant in the 3.0 kg sample of pond water is determined to be 1.2 ppm by converting the mass and calculating the ratio.

To find the concentration of the pollutant in the 3.0 kg sample of pond water in parts per million (ppm), you can follow these steps:

1. Convert the mass of the sample to milligrams (mg), as the mass of the pollutant is given in mg. There are 1,000,000 mg in 1 kg, so:
3.0 kg * 1,000,000 mg/kg = 3,000,000 mg

2. Determine the ratio of the mass of the pollutant to the mass of the sample:
3.6 mg pollutant / 3,000,000 mg sample

3. Calculate the concentration in parts per million (ppm) by multiplying the ratio by 1,000,000:
(3.6 mg pollutant / 3,000,000 mg sample) * 1,000,000 = 1.2 ppm

So, by calculating we can say that the concentration of the pollutant in the 3.0 kg sample of pond water is 1.2 ppm.

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Airborne Gases Composure of the atmosphere The byproducts of the species that are really nourished by this have a significant influence on the composition of the Earth's environment.

Dry air from the earth's atmosphere contains 0.038% of carbon dioxide, 20.95% of oxygen, 78.08% of nitrogen, and 0.93% of argon.

The environment, a layer of gases that regulates temperatures within a specific range and deflects dangerous solar radiation, covers all life on Earth.

The atmosphere is the term used to describe the layer of gases that covers the Earth and contains the air we breathe. It remains near the planet's surface due to the gravitational attraction of its neighbour, Earth. Utilize a barometer to determine the air pressure. Nitrogen, oxygen, and argon make up the atmosphere's three main constituents.

One or more compounds completely change in composition as a result of chemical change from the original substances. The reaction reorganises the initial components and/or compounds into new product compounds or elements. The original matter's chemical makeup is changed via a chemical change.

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Answer:

Na 1s2 2s2 2p6 3s1

Ar 1s2 2s2 2p6 3s2 3p6

Explanation:

The pKa values for the given carboxylic acids are ICH₂COOH (pKa) = 4.8, CH₃COOH (pKa) = 4.8 and CF₃COOH (pKa) = 0.2

The quantitative behavior of acids and bases in solution can be understood only if their pKa values are known. Ka denotes the acid dissociation constant. It measures how completely an acid dissociates in an aqueous solution.

The larger the value of Ka, the stronger the acid as acid largely dissociates into its ions.

pKa is the negative base -10 log of the acid equilibrium constant (Ka) of a solution.

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Mass of water is 45.2 grams.

Overall chemical equation for reaction of combustion a propane (C₃H₈):

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.

m(C₃H₈) = 53.5 g; mass of the propane

m(O₂) = 15.0 g; mass of oxygen

m(CO₂) = 23.3 g; mass of carbon dioxide

m(H₂O) = ?; mass of water

Conservation of matter states that the mass of the reactants have to be equal to the mass of the products.

m(C₃H₈) + m(O₂) = m(CO₂) + m(H₂O)

53.5 g + 15.5 g = 23.3 g + m(H₂O)

m(H₂O) = 69.0 g - 23.3 g

m(H₂O) = 45.2 g; mass of water

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