PLEASE HELL ME!!!!


Find the density of a cylinder on Earth that weighs 14 kg, a height of 25 cm, and a diameter of 4 cm.​

Answer:

C) 57.4 grams

Explanation:

According to the law of conservation of mass/matter, mass can neither be created nor destroyed. This means that the amount of matter present in the reactants must be equal to that of the products since no amount can be lost.

Hence, according to this question which states that the mass of reactants are 44.6 grams (Fe) and 12.8 grams (O2), hence the total mass of reactants is 44.6 + 12.8 = 57.4 grams.

If the amount of mass in the reactants is 57.4 grams, then the amount of mass in the product(s) must also be 57.4 grams in conformity to the law of conservation of mass.

The mass of the product (  Fe₂O₃ )  will be ; ( C ) 57.4

The mass of the product when Fe reacts with O₂ will be equal to the summation of the masses of the reactants i.e. ∑ M₁ + M₂. and this is because of the  law of conservation of mass

Reaction equation :  Fe + 0₂ = Fe₂O₃

mass of Fe ( M₁ )  = 44.6 g

mass of O₂ ( M₂ ) = 12.8 g

Therefore the mass of Fe₂O₃

= 44.6 g + 12.8 g = 57.4 grams

Hence we can conclude that the mass of a product will be 57.4 grams .

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Answer:

103.6°C

Explanation:

We solve this problem, with the Ideal Gases Law. We know that moles of gas are not changed through time.

P . V = n . R . T

So n (number of moles) and R (Ideal Gases constant) are the same, they are cancelled. In the two different states, we can propose:

P₁ . V₁ / T₁ = P₂ . V₂ /T₂

We need to make some conversions:

100 mL . 1 L/ 1000mL = 0.1L

500 kpa . 1atm / 101.3 kPa = 4.93 atm

300°C + 273 = 573 K

We replace data:

4.93 atm . 10L / T₂ = 750 atm . 0.1L / 573K

4.93 atm . 10L = (750 atm . 0.1L / 573K) . T₂

(4.93 atm . 10L) / (750 atm . 0.1L / 573K) → T₂

T₂ = 376.65 K

We convert K to °C →  376.65 K - 273 = 103.6 °C

a. The potential for an Fe3+/Fe2+ half cell when using a saturated calomel electrode (SCE) is +0.9944V, and when using a standard hydrogen electrode (SHE) is +0.750V. When using a standard silver/silver chloride electrode (Ag/AgCl) the potential is +0.947V.

Here, correct answer will be

b. A selective electrode is an electrode that is designed to measure the activity of a specific ion in an aqueous solution. Selective electrodes are able to measure the activity of the ion of interest in the presence of other ions that are present in the solution.

c. Ion selective membranes are thin, permeable layers that allow only certain ions to pass through them. They are used in ion-selective electrodes, which are specialized electrical meters that measure the activity of a particular ion in a solution. Ion-selective membranes can be made from organic materials, such as cellulose acetate, or from inorganic materials, such as silica.

d. Alternating current (AC) is an electric current that reverses direction periodically. In contrast, direct current (DC) is an electric current that flows in one direction only.

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The statement which is true about credentialing of a medical assistant is that CMA credentialing is obtained through the American Association of Medical Assistants (AAMA), thus option B is correct.

The CMA  credential designates a medical assistant who has achieved certification through the Certifying Board of the American Association of Medical Assistants (AAMA).

The CMA has been educated and tested in a wide scope of general, clinical, and administrative responsibilities as outlined in the Content Outline for the CMA Certification Exam.

Every day the AAMA responds to more than 100 employer requests for CMA  certification verification—for both current and potential employees.

The CMA  Fact Sheet offers a quick take on the reasons a CMA credential attests to medical assistants’ high level of knowledge and competence.

Thus,  statement which is true about credentialing of a medical assistant is that CMA credentialing is obtained through the American Association of Medical Assistants (AAMA), thus option B is correct.

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Answer:

Explanation:

This question appears incomplete but can however still b answered.

The purpose of the experiment is to test the effectiveness of the new sunscreen.

An independent variable is the variable that is changed (directly or indirectly) during the course of an experiment. The independent variable here are the sunscreen.

A dependent variable is the variable that is been tested in the course of the experiment. The dependent variable here is the redness of the skin.

The first group here (this could be in the missing part of the question, hence response not certain) is the control group. The control group consists of the arms sprayed with the leading/old sunscreen formula.

The second group is the test group. It consists of the arms sprayed with the new sunscreen formula.

The factors that are kept constant (or control variable) are the duration under the sun (4 hrs) and the participants' arms used.

The test group is the second group while the group used for comparison (to be sure the new sunscreen is more effective) is the first group.

The mass of water, H₂O produced from the reaction is 72.06 g

We'll begin by calculating the mass of NH₄NO₃ that reacted and the mass of H₂O produced from the balanced equation.

NH₄NO₃ —> N₂O + 2H₂O

Molar mass of NH₄NO₃ = 80.03 g/mol

Mass of NH₄NO₃ from the balanced equation = 1 × 80.03 = 80.03 g

Molar mass of H₂O = 18.01 g/mol

Mass of H₂O from the balanced equation = 2 × 18.01 = 36.02 g

From the balanced equation above,

80.03 g of NH₄NO₃ reacted to produce 36.02 g of H₂O

Finally, we shall determine the mass of H₂O produced by the reaction of 160.1 g of NH₄NO₃.

From the balanced equation above,

80.03 g of NH₄NO₃ reacted to produce 36.02 g of H₂O.

Therefore,

160.1 g of NH₄NO₃ will react to produce = (160.1 × 36.02) / 80.03 = 72.06 g of H₂O.

Thus, the mass of water, H₂O produced from the reaction is 72.06 g

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Positively charged metal ions.

Metallic bonding is a type of chemical bonding caused by the electrostatic attraction of conduction electrons (in the form of an electron cloud of delocalized electrons) to positively charged metal ions.

As chemistry matured into a discipline, it became obvious that metals dominated the periodic table of elements, and significant progress was made in the description of the salts that may be generated in interactions with acids. With the advent of electrochemistry, it became known that metals normally enter solution as positively charged ions, and the oxidation processes of the metals in their electrochemical series were well recognized. Metals were shown as positive ions bound together by an ocean of negative electrons.

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Answer:

In my opinion the third one is write.

Explanation:

soil.

468 mL of the antacid solution was neutralized in the 25.00 mL sample that was titrated.

C(NaOH) = (mol NaOH) / (V(NaOH) in L)

where,

mol NaOH = mol HCl (since they react in a 1:1 ratio)

= (C(HCl) x V(HCl)) in moles

= (0.1 M x 0.025 L) in moles

= 0.0025 moles

V(NaOH) in L = 29.2 mL / 1000 mL/L

= 0.0292 L

C(NaOH) = 0.0025 moles / 0.0292 L

= 0.0856 M

calculate the amount of acid that was neutralized:

mol NaOH used in titration = C(NaOH) x V(NaOH) used in titration

= 0.0856 M x 0.0137 L

= 0.00117 moles

mol acid in 25.00 mL of antacid solution = 0.00117 moles

mol acid in 1000 mL of antacid solution = (0.00117 moles / 0.025 L) x 1000 mL/L

= 46.8 moles/L

So the volume of the antacid solution that was titrated is:

V(titrated) = (46.8 moles/L) / (0.1 moles/L)

= 468 mL

Antacids are a group of medications used to neutralize stomach acid, relieve heartburn, and treat acid indigestion. Antacid solutions are formulations that contain an active ingredient that reacts with hydrochloric acid (HCl) in the stomach to form a salt and water, thereby reducing the acidity of the stomach.

Most antacid solutions contain alkaline substances such as calcium carbonate, magnesium hydroxide, aluminum hydroxide, and sodium bicarbonate. These substances act as bases, reacting with HCl to form salt and water. Antacid solutions work by increasing the pH of the stomach, which helps to reduce symptoms such as heartburn, acid indigestion, and upset stomach. Antacids are available in various forms, including tablets, liquids, and chewable tablets.

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Option C  a diprotic base was titrated with a strong acid  is indicated by the shape of the titration curve.

The titration curve is a plot of the analyte solution's pH versus the volume of titrant added as the titration progresses. Titrations are frequently documented on graphs known as titration curves, which generally include the quantity of the titrant also as explanatory variables and the pH value of the solution as the predictor variables. The equivalence point of the graph is where the titrant has nullified all of the starting solution. Titration curves are a low-cost, valuable, and versatile method for gaining sophisticated information about the acidity of acidic water. The information on the current buffer system's strength can aid in understanding and documenting the complicated nature of acidified mining moisture buffer systems.

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Answer:

Experiments with gases that first became possible at the turn of the nineteenth century led John Dalton in 1803 to propose a modern theory of the atom based on the following assumptions. 1. Matter is made up of atoms that are indivisible and indestructible.

When the reaction is subjected to pressure, the equilibrium will shift to the side with fewer gas molecules, which is the left side. Therefore, the answer is c. left.

According to Le Chatelier's principle, when a system at equilibrium is subjected to a change in pressure, it will respond by shifting in a way that reduces the effect of the change. In this case, increasing the pressure would cause the equilibrium to shift towards the side with fewer gas molecules to alleviate the increase in pressure.

Since there are fewer gas molecules on the left side of the reaction (2 CO + O2), the equilibrium will shift to the left to reduce the total number of gas molecules. This means that the concentrations of CO and O2 will increase, while the concentration of CO2 will decrease until a new equilibrium is established. Thus, the equilibrium will shift to the left.

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PRACTICE MULTIPLE CHOICE QUESTIONS FROM UNIT 10

1.) A cylinder is filled with 2.00 moles of nitrogen, 3.00 moles of argon, and 5.00 moles of helium. If

the gas mixture is at STP, what is the partial pressure of the argon?

(A) 152 torr (B) 228 torr (C) 380. torr (D) 760. torr

2.) Compared to the average kinetic energy of 1 mole of water at 0 oC, the average kinetic energy

of 1 mole of water at 298 K is

(A) the same, and the number of molecules is the same

(B) the same, but the number of molecules is greater

(C) greater, and the number of molecules is greater

(D) greater, but the number of molecules is the same

3.) If the pressure on a given mass of gas in a closed system is increased and the temperature

remains constant, the volume of the gas will

(A) decrease (B) increase (C) remain the same

4.) Which gas has approximately the same density as C2H6 at STP?

(A) NO (B) NH3 (C) H2S (D) SO2

5.) At a temperature of 273 K, a 400. milliliter gas sample has a pressure of 760. millimeters of

mercury. If the pressure is changed to 380. millimeters of mercury, at which temperature will

this gas sample have a volume of 551 milliliters?

(A) 100 K (B) 188 K (C) 273 K (D) 546 K

Get the answers to these questions

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Considering the Dalton's partial pressure and STP conditions, the total pressure of argon in the mixture of gases is 0.3 atm.

On one side, the STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

On the other side, the pressure exerted by a particular gas in a mixture is known as its partial pressure.

So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

\(P_{T} =P_{1} +P_{2} + ... + P_{n}\)

where n is the number of gases in the gaseous sample.

Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture.  

So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:

\(P_{A} =x_{A} P_{T}\)

In this case, the mole fraction of the argon can be calculated knowing that:

Then:

\(x_{argon} =\frac{3 moles}{10 moles} = 0.3\)

So, if the gas mixture is at STP, the total pressure of the gas mixture is 1 atm and the partial pressure of argon can be calculated as:

\(P_{argon} =x_{argon} P_{T}\)

\(P_{argon} =0.3x 1 atm\)

\(P_{argon} =0.3 atm\)

In summary, the total pressure of argon in the mixture of gases is 0.3 atm.

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Answer: D) The sun

Explanation:

The mole ratio of the Al:Al₂O₃ is given from the question that we have as 3:1

A mole ratio is the ratio of the number of moles of one substance to the number of moles of another substance in a chemical reaction. It is often used to determine the stoichiometry of a reaction, which is the relationship between the relative amounts of reactants and products.

Mole ratios can be used to determine the amounts of reactants and products needed to achieve a specific reaction yield, or to calculate the expected yield of a reaction.

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For the reaction of aluminum metal and ammonium perchlorate, the mole ratio of Al to Al₂O₃ is 3 : 1 (3 is to 1).

Mole ratio requires a balanced equation, the coefficients of the elements and a division of the coefficients.

To find the mole ratio of Al to Al₂O₃, we need to look at the coefficients in the balanced equation.

The balanced equation is:

3Al + 3NH₄ClO₄ → Al₂O₃ + AlCl₃ + 3NO + 6H₂O

The coefficient of Al is 3 and the coefficient of Al₂O₃ is 1.

Therefore, the mole ratio of Al to Al2O3 is 3:1.

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Answer:

aluminium is more reactive than carbon. carbon is used to displace less reactive metals from their compounds. this happens since the carbon reacts with the other substance(s) in the compound, and the less reactive metal does not.

Answer:

Explanation: aluminium is more reactive than carbon. carbon is used to displace less reactive metals from their compounds. this happens since the carbon reacts with the other substance(s) in the compound, and the less reactive metal does not.It is highly reactive, though the metal is protected by a surface layer of inert transparent oxide (Al2O3) that forms rapidly in air, providing excellent corrosion resistance.

The disadvantage of increasing our use of solar energy is that unfortunately currently, the production and storage of solar energy is bit as cost efficient when compared to obtaining the same quantity of energy from fossil fuels.



Answer:

42.2075 grams

Explanation:

Gentian violet, a dye used in DNA gel electrophoresis, exhibits a yellow color in strongly acidic solutions and turns purple in solutions with higher pH levels, such as neutral or basic solutions. This color change aids in the visualization of DNA fragments during the gel electrophoresis process.

Gentian violet is a common dye used in DNA gel electrophoresis to stain DNA bands. It is a cationic dye that binds to DNA molecules, making them visible under UV light. Gentian violet appears yellow in strongly acidic solutions and purple in solutions with a higher pH. During electrophoresis, the DNA is separated by size and charge, resulting in distinct bands on the gel. Gentian violet stains these bands, allowing scientists to visualize the DNA fragments. However, excessive use of gentian violet can damage DNA, so it is important to use it in moderation. In summary, gentian violet is a vital tool for DNA analysis, but its use must be carefully controlled to prevent any negative effects on the DNA samples.
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Answer:

1. The balanced equation for the thermal decomposition of potassium chlorate is:

2KClO3(s) → 2KCl(s) + 3O2(g)

2. Using the stoichiometry of the balanced equation, we can see that 2 moles of KClO3 produce 3 moles of O2. Therefore, 9.50 moles of O2 are produced by (9.50 moles O2 / 3 moles O2 per 2 moles KClO3) = 6.33 moles KClO3. The heat produced by the decomposition of 6.33 moles of KClO3 is:

q = nΔHrxn = (6.33 mol)(-89.4 kJ/mol) = -566 kJ

3. To solve this problem, we need to use the ideal gas law to calculate the volume of O2 produced. First, we convert 307 g of KClO3 to moles:

n = m/M = 307 g / 122.55 g/mol = 2.50 mol KClO3

Using the stoichiometry of the balanced equation, we can see that 2 moles of KClO3 produce 3 moles of O2. Therefore, 2.50 moles of KClO3 produce (3/2 x 2.50) = 3.75 moles of O2. Now we can use the ideal gas law to calculate the volume of O2 produced:

PV = nRT

V = nRT/P = (3.75 mol)(0.08206 L·atm/mol·K)(305.15 K)/(723 torr/760 torr/atm) = 8.59 L

4. The heat produced by the decomposition of 307 g of KClO3 is:

n = m/M = 307 g / 122.55 g/mol = 2.50 mol KClO3

q = nΔHrxn = (2.50 mol)(-89.4 kJ/mol) = -223 kJ

5. We can use the equation q = mcΔT to calculate the final temperature of the water. First, we need to calculate the heat capacity of the water:

C = mc = (74.2 L)(1.00 kg/L)(4.18 J/g·K) = 310 kJ/K

Now

Explanation:

The molarity of the sodium sulfate solution is 0.0732 M.

To calculate the molarity of a sodium sulfate  solution that contains 5.2 grams of sodium sulfate diluted to 500 mL, we need to convert the mass of sodium sulfate to moles and divide it by the volume in liters.

First, we calculate the molar mass of sodium sulfate:

Na = 22.99 g/mol (atomic mass of sodium)

S = 32.07 g/mol (atomic mass of sulfur)

O = 16.00 g/mol (atomic mass of oxygen)

Molar mass of Na2SO4 = (2 * 22.99) + 32.07 + (4 * 16.00) = 142.04 g/mol

Next, we convert the mass of sodium sulfate to moles:

moles = mass / molar mass

moles = 5.2 g / 142.04 g/mol = 0.0366 mol

Now, we convert the volume of the solution to liters:

volume (in liters) = 500 mL / 1000 mL/L = 0.5 L

Finally, we calculate the molarity of the solution:

molarity (M) = moles / volume

molarity (M) = 0.0366 mol / 0.5 L = 0.0732 M

Therefore, the molarity of the sodium sulfate solution is 0.0732 M.

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The major product of the reaction between p‑fluoroanisole and sulfur trioxide and sulfuric acid is p‑fluorobenzene sulfonic acid. The sulfonic acid group (-SO3H) substitutes for the methoxy group (-OCH3) on the benzene ring. The product is shown below:

    F

     |

H3C--O--C6H4--SO3H

     |

     H

Note that the sulfur atom has an expanded octet, with 10 electrons in its valence shell.

One of the most well-known instances of an electrophilic aromatic substitution reaction is the reaction of p-fluoroanisole with sulphur trioxide and sulfuric acid. The electrophile in this reaction is a highly reactive sulphur trioxide-sulfuric acid complex, and the sulphur trioxide and sulfuric acid serve as its sources. The electrophile assaults the p-electron-rich fluoroanisole's aromatic ring, removing the methoxy group and replacing it with a sulfonic acid (-SO3H) group.

P-fluorobenzenesulfonic acid is a helpful intermediate in many chemical synthesis reactions due to the sulfonic acid group's high acidity and polarity. Additionally, a variety of chemical processes, including esterification, amidation, and reduction, can be used to further modify the sulfonic acid group in order to produce other derivatives.

The sulfonic acid group's sulphur atom has an extended octet, which implies it contains more than eight valence electrons in its outer shell. For lesser elements like carbon, nitrogen, and oxygen, this is unusual, but for heavier elements like sulphur and phosphorus, it is rather typical. Expanded octets are typically seen when the central atom can interact with empty d orbitals that can form bonds.

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Answer:

4

Explanation:

Nitrogen (N)

hydrogen (H)

sulfur (S)

oxygen (O)

Bycatch can negatively affect species consisting of seafood dolphins, sea turtles, protected fish, and whales by way of harming animals, contributing to population declines, and impeding populace recuperation.

Bycatch occurs because modern fishing is very efficient, often covers an extensive area, and can be highly unselective different influences of fisheries on marine mammals may additionally encompass elimination of their favored prey and once in a while habitat harm.

Bycatch is part of most business fishing operations. it's miles created whilst marine life is by chance stuck with the aid of fishing vessels. Fish and other undesirable aquatic animals are then tossed and returned to the ocean. Many are both lifeless or lose of life when they're thrown lower back.

Despite new technologies and the enterprise's reputation the difficulty, of bycatch continues to be a first-rate problem. now not handiest does it cause avoidable deaths and injuries, but the fishing strategies can be dangerous to the marine environments wherein they're employed.

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Answer:

135.6

Explanation:

12 * 11.3 = 135.6

To find the mass you have to multiply the density and volume together

If you already have the mass you divide the mass by either the density or volume

Answer:

25% gold.

Explanation:

6 is 25 percent of 24, so 6 karat gold would be 25% gold.

Changes in the level of atmospheric CO₂ will affect marine organisms such as crustaceans.

Diesel and gasoline engines compliant with CO₂ emission standards not be banned.

Atmospheric CO₂ refers to carbon dioxide present in the atmosphere.

Atmospheric CO₂ is required by marine organisms such as crustaceans to make their shells.

Therefore, changes in the level of atmospheric CO₂ will affect the marine organisms such that depend on it to make its shells such as crabs.

Diesel and gasoline engines are associated with CO₂ emission. However, an increase in CO₂ emission has been implicated in global warming as  CO₂ is a known greenhouse gas.

Therefore, diesel and gasoline engines compliant with CO₂ emission standards not be banned.

In conclusion, increase in atmospheric CO₂ levels due to increased emission leads to global warming.

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