phil applies 100 n to a pulley system and raises a load one-tenth of his downward pull. ideally, the weight of the load is

The electric field at the position of the electron is 2.12 × \(10^{4}\) N/C.

An electrically charged particle or set of particles is surrounded by an electric field, which is a force field. It is described as the amount of force per unit of charge that a charged particle would encounter in a field. Positive or negative electric fields are possible, and the size and dispersion of the charges that generate them determine how strong they are. Electric field lines, which describe the direction and strength of the force at each point in the field, can be used to illustrate them. Electric fields are crucial for many scientific applications, including particle accelerators and medical imaging, as well as for many daily technologies, like electrical power distribution, electronics, and telecommunications.

The electrostatic force on an electron is given by:

F = qE

where q is the charge of the electron and E is the electric field.

We know that the force acting on the electron is 3.4 × 10^-15 N, and the charge of an electron is 1.602 × 10^-19 C.

Therefore, the electric field can be found by rearranging the formula:

E = F/q

E = (3.4 × 10^-15 N)/(1.602 × 10^-19 C)

E = 2.12 × 10^4 N/C

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The comet that is beyond neptune belongs to the oort cloud

The Oort Cloud is an icy celestial mass predicted to be more distant than any other cloud in the solar system. This is consistent with observations of comets in the planetary regions of the solar system, but scientists have yet to observe an object in the Oort Cloud itself. The Oort Cloud is about two light years away from Earth. This means that light travels 300,000 kilometers per second and takes two years to travel from the Oort Cloud to Earth. The Oort Cloud is sometimes used to mark the edge of the solar system. 

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Answer: False

Explanation: You'll be able continuously tell a blend, since each of the substances can be isolated from the group in numerous physical ways. You'll be able continuously get the sand out of the water by sifting the water absent. Some of the time a blend partitioned on their possess eg. water & cooking oil.

8n downwards

since downwards force is greater than upwards just minus

With a world-record leap with a maximum height of 58.7 cm above the ground. By the given launch angle of 58.0° and assuming a takeoff speed of 4.00 m/s, the horizontal distance covered is calculated.

To determine the horizontal distance covered by the froghopper, we can use the equations of projectile motion. Given the launch angle and takeoff speed, we can break down the initial velocity into its horizontal and vertical components.

The initial vertical velocity (v0y) can be found using the takeoff speed and the launch angle:

v0y = v * sin(θ),

v0y = 4.00 m/s * sin(58.0°),

v0y ≈ 3.36 m/s.

Next, we can calculate the time it takes for the froghopper to reach its maximum height. At the peak of the trajectory, the vertical component of the velocity becomes zero.

Using the equation for vertical velocity:

v = v0y - g * t,

0 = 3.36 m/s - 9.8 m/s^2 * t,

t ≈ 0.343 s.

Since the total time of flight is twice the time it takes to reach the maximum height, the total time is approximately 2 * 0.343 s = 0.686 s.

Finally, we can calculate the horizontal distance covered using the horizontal component of the initial velocity and the time of flight:

x = v0x * t,

x = v * cos(θ) * t,

x = 4.00 m/s * cos(58.0°) * 0.686 s,

x ≈ 1.64 m.

Therefore, for this world-record leap, the froghopper covered a horizontal distance of approximately 1.64 meters.

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A 40 kg crate is pulled at a constant velocity. The coefficient of kinetic friction is 0.5 and the crate moves 7 m . The amount of work done is 140 joule.

When an object is moved over a distance by an external force, at least a portion of that force must be applied in the direction of the displacement.

By multiplying the length of the path by the component of the force acting along the path, work can be calculated if the force is constant. The work W is equal to the force f times the distance d, or W = fd, to mathematically describe this idea.

The work is W = fd cos if the force is applied at an angle of to the displacement. Performing work on a body involves moving it in its entirety from one location to another as well as.

Therefore, A 40 kg crate is pulled at a constant velocity. The coefficient of kinetic friction is 0.5 and the crate moves 7 m . The amount of work done is 140 joule.

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The volume of the air that we have from the question is 829 L

The ideal gas equation, also known as the ideal gas law, is a fundamental equation in thermodynamics that describes the relationship between the pressure (P), volume (V), temperature (T), and number of moles (n) of an ideal gas.

We know that;

PV = nRT

P = pressure

V = volume

n = Number pf moles

R = gas constant

T = Temperature

Then;

Number of moles of the air = 1000 g/29 g/mol

= 34.5 moles

Then;

V = nRT/P

V = 34.5 * 0.082 * 293/1

V = 829 L

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Answer:

Alice works with natural rubber and Julio works with vulcanised rubber.

Explanation:

Answer:

B. Alice works with natural rubber, and Julio works with vulcanized rubber.

Explanation:

I just took the test and got 100 percent.

I hope this helps you!!!!

Please mark my answer the Brainiset. Thank You!!!!!

The ideal gas equation of state to calculate the final pressure of the system is PV = n .

Final pressure is a term used to describe the pressure at the end of a thermodynamic process, such as a cooling or heating cycle. It is the pressure that remains after all of the energy in the system has been converted into work. In other words, it is the pressure that is reached after all of the energy has been used up. Final pressure is a measure of the total energy in the system, including kinetic and potential energy. It is an important factor in determining the efficiency of a system and its overall performance.

The isothermal expansion of a system means that the temperature remains constant. Therefore, the initial temperature of 160°C is also the final temperature.The energy balance for this system is : Q + W = ΔU

Since the process is reversible, the work done by the system is equal to the change in enthalpy, which is given by the following equation:W = ΔH

Since the temperature remains constant, the change in enthalpy is equal to the change in internal energy: ΔH = ΔU

Substituting this into the energy balance equation, we get: Q + ΔH = ΔU

Substituting the known values, we get: 2700 kJ + ΔH = 0

Solving for ΔH, we get: ΔH = -2700 kJ.

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Answer:

USE RUBBER CLOVES

USE A PLIER

USE CONDUCTIVE WIRES

SWITHC OFF THE MAIN SWITCH WHILE WIRRING

Explanation:

Answer:

b

Explanation:

Total, 0.751 grams of aluminum metal can be produced per hour in the electrolysis of a molten aluminum salt by a current of 23 A.

To determine the mass of aluminum metal produced per hour in the electrolysis of a molten aluminum salt, we need to consider Faraday's laws of electrolysis.

Faraday's laws state that the amount of substance produced or consumed during electrolysis is directly proportional to the amount of electric charge passed through the electrolyte. The relationship is given by the equation;

m = (Q × M) / (z × F)

Where;

m will be the mass of the substance produced (in grams),

Q is the electric charge passed (in coulombs),

M is the molar mass of the substance (in grams per mole),

z is the number of moles of electrons transferred per mole of substance, and

F is the Faraday constant, which is approximately 96,485 coulombs per mole of electrons.

For aluminum, the molar mass (M) is 26.98 g/mol, and the number of moles of electrons transferred (z) is 3 (since aluminum has a charge of +3 when it forms ions).

Given that the current passing through the electrolyte is 23 A (amperes) and the time is 1 hour (3600 seconds), we can calculate the electric charge (Q) passed using the equation;

Q = I × t

Where;

I is the current (in amperes) and

t is the time (in seconds).

Let's calculate the mass of aluminum produced per hour using the provided values;

Q = 23 A × 3600 s = 82,800 C

m = (82,800 C × 26.98 g/mol) / (3 × 96,485 C/mol)

m = 0.751 g

Therefore, approximately 0.751 grams of aluminum metal can be produced per hour in the electrolysis of a molten aluminum salt by a current of 23 A.

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Answer:

Explanation:

For entropy change the formula is

ΔS = ΔQ / T

ΔQ = Δ H

ΔS = Δ H / T

Given

Δ H = + 162.8 kJ

We can take equilibrium temperature as average temperature of the whole process

So, T = 273 + 87 = 360 K

ΔS = Δ H / T

=  162.8 kJ  / 360

= +  0.508 kJ / K .

When the magnitude of the heat transfer for the process is 162.8 kJ, Then the entropy change for the mixing process, in kJ/K is = + 0.508 kJ / K

For The entropy change, the formula is

Then ΔS = ΔQ / T

After that ΔQ = Δ H

Then ΔS = Δ H / T

Given as per question are:

Then Δ H = + 162.8 kJ

Now We can take equilibrium temperature as average temperature of the whole process are:

So, T is = 273 + 87 = 360 K

Then ΔS = Δ H / T

After that = 162.8 kJ / 360

Therefore, = + 0.508 kJ / K.

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Answer:

All options presented were applied to the answer.

Explanation:

The sample response presented in the question above, refers to a closed system where two molecules after colliding satisfy the conservation of momentum law, which can also be called the conservation law of linear momentum. This law states that in a closed system the initial state of the components must be maintained and remain the same until the final state, that is, the two molecules maintain their ideal momentum before and after the collision. This means that if they had 1.5 kg • m/s before the collision, this value must be maintained after the collision. All these concepts are presented in the sample response.

Answer:

What did you include in your response? Check all that apply. The law of conservation of momentum is satisfied. The momentum before the collision is 1.5 kg • m/s. The momentum after the collision is 1.5 kg • m/s. The momentum before and after the collision is the same.

Explanation:

The sample response presented in the question above, refers to a closed system where two molecules after colliding satisfy the conservation of momentum law, which can also be called the conservation law of linear momentum. This law states that in a closed system the initial state of the components must be maintained and remain the same until the final state, that is, the two molecules maintain their ideal momentum before and after the collision. This means that if they had 1.5 kg • m/s before the collision, this value must be maintained after the collision. All these concepts are presented in the sample response.

The work input required is 180 J.

The formula gives the work input:

Work input = Force x Distance

In this instance, a force of 20 N is used, and 5 m is moved. As a result, the force's work is:

Work done by force = 20 N x 5 m = 100 J

A 400 N weight can be moved by the machine 20 cm (or 0.2 m) away.

Using the following formula, we can estimate the work performed by the machine:

Work done by machine = Load x Distance moved by the load

Work done by machine = 400 N x 0.2 m = 80 J

As a result, the amount of work needed to move the load with the machine is:

Work input = Work done by force + Work done by machine

Work input = 100 J + 80 J = 180 J

Therefore, the work input required is 180 J.

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The concentration of the solutions the nurse should mix in part (a) and the amount to be invested by the woman at each rate in (b), found by solving the simultaneous equations obtained from the parameters are;

(a) 20% : 7 cc

5% : 3 cc

(b) 2%: $74,000

12%: $68,000

An equation is a statement indicating that two mathematical expressions are equivalent by joining them with an '=' sign.

let x represent the volume of the 20% concentration solution, let y represent the volume of the 5% solution, we get;

x + y = 10...(1)

0.2·x + 0.05·y = 0.155 × 10 = 1.55...(2)

Equation (1) indicates; x = 10 - y

Therefore;

0.2·(10 - y) + 0.05·y = 1.55

2 - 0.15·y = 1.55

0.15·y = 2 - 1.55 = 0.45

y = 0.45/0.15 = 3

x = 10 - y

x = 10 - 3 = 7

Therefore; the nurse should mix 7 cc of the 20% solution and 3 cc of the 5% solution to obtain the 10 cc 15.5% solution

2. Let x represent the amount the woman invests at 2% per year, and y represent the amount the woman invests at 12% per year, we get the following simultaneous equations;

x + y = 142,000...(1)

0.02·x + 0.12·y = 9640...(2)

Therefore; y = 142,000 - x

0.02·x + 0.12·(142,000 - x) = 9640

17,040 - 0.1·x = 9640

0.1·x = 17,040 - 9640 = 7400

x = 7400/0.1 = 74,000

y = 142,000 - 74,000 = 68,000

The amount invested at 2% is; x = $74,00

The amount the woman invests at 12% is; $68,000

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Explanation:

Average speed =total distance ÷ total time

speed = d ÷ t

d= 74400

t= 16

then,

speed = 74400÷16

=4650

The phenomenon you are describing is called habituation.

Once the cupcake has been on your desk for a while, your brain becomes accustomed to its presence and it no longer registers as noteworthy or interesting.

Habituation is defined as a behavioral response decrement that results from repeated stimulation and that does not involve sensory adaptation/sensory fatigue or motor fatigue.

Habituation is the reduction of a behavioral response to a stimulus after repeated presentations of that stimulus  Habituation can occur to stimuli detected by any of your senses. You may become habituated to loud sounds, bright lights, strong odors, or physical touch.

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The heating of air inside the balloon causes the volume to expand (Charles's Law), resulting in a decrease in the pressure compared to the surrounding air (Boyle's Law).

Hot-air balloon flight can be explained by the combined principles of Charles's Law, Archimedes' Principle, and Boyle's Law.

Charles's Law states that the volume of a gas is directly proportional to its temperature, assuming the pressure remains constant. In the case of a hot-air balloon, the air inside the balloon is heated, causing the gas molecules to move faster and increase in temperature. As a result, the volume of the gas expands, leading to an increase in the volume of the balloon.

Archimedes' Principle states that an object immersed in a fluid experiences an upward buoyant force equal to the weight of the fluid displaced by the object. In the context of a hot-air balloon, the heated air inside the balloon is less dense than the surrounding cool air. The buoyant force acting on the balloon is equal to the weight of the air displaced by the balloon. This buoyant force is greater than the weight of the balloon itself and the payload, causing the balloon to rise.

Boyle's Law states that the pressure of a gas is inversely proportional to its volume, assuming the temperature remains constant. When the air inside the balloon is heated, the volume increases. As a result, the pressure inside the balloon decreases relative to the surrounding air pressure. The pressure difference creates a net upward force, contributing to the balloon's ascent.

In summary, the combined effects of Charles's Law, Archimedes' Principle, and Boyle's Law explain hot-air balloon flight. The heating of air inside the balloon causes the volume to expand (Charles's Law), resulting in a decrease in the pressure compared to the surrounding air (Boyle's Law). The buoyant force (Archimedes' Principle) acting on the less dense heated air allows the balloon to rise.

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Here's a two-hour practice session plan for tennis:

Warm-up (15 minutes):

Jogging: Start with a light jog around the court to increase heart rate and warm up the muscles.

Dynamic Stretches: Perform dynamic stretches such as arm circles, leg swings, high knees, and lunges to improve flexibility and range of motion.

Mini Tennis: Play a short game of mini tennis (half-court) with a partner to warm up hand-eye coordination and footwork.

Skills and Technique (45 minutes):

Forehand and Backhand Groundstrokes: Practice proper grip, footwork, and stroke technique for forehand and backhand shots. Focus on generating power and accuracy.

Volleys and Overheads: Work on volleying techniques at the net and overhead shots. Practice the correct hand positioning and timing for these shots.

Serve Practice: Spend time working on the serve technique, focusing on the toss, racquet motion, and follow-through. Practice different types of serves (flat, slice, kick) and aim for consistency and accuracy.

Strategy and Game Situations (30 minutes):

Singles Tactics: Discuss and practice various singles strategies such as serving patterns, approaching the net, playing defensively, and exploiting opponents' weaknesses.

Doubles Tactics: Cover doubles strategies like communication, positioning, serving and returning as a team, and effective net play. Practice doubles-specific drills and scenarios.

Match Play and Conditioning (30 minutes):

Point Play: Play practice points or mini sets with a partner or group, focusing on implementing the strategies and techniques learned earlier.

Conditioning Exercises: Incorporate fitness drills such as shuttle runs, agility ladder drills, or interval sprints to improve stamina and quickness on the court.

Cool-down and Stretching (15 minutes):

Gentle Jog or Walk: Cool down with a light jog or walk around the court to gradually lower your heart rate.

Static Stretches: Perform static stretches targeting major muscle groups to improve flexibility and aid in recovery.

A basketball player jumps vertically off the ground 5.6m/s how long were they in the air

Given that

To find

So, according the question

We have,

preliminary velocity u = five.6 m/s

and acceleration due to gravity g = - 9.81 m/s² ( - signal for upward movement )

( ∴ basketball participant jumps vertically and he travelled inside the air on the action of gravity so we recall his acceleration as g. )

Now, from first equation of motion.

     v = u + at

velocity at highest point will be zero so

     v = 0 ,   u = 5.6 m/s and a = g = - 9.81 m/s²

Now, putting the all values on first equation of motion.

       0 = 5.6 - 9.81 × t

   -5.6 = -9.81 × t

        \(t = \frac{5.6}{9.81}\)

       t = 0.58 s.

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(a) The hunter and canoe move to the right with a velocity of 0.093 m/s after the spear is released.

(b) The hunter and canoe would move to the right with a velocity of 0.047 m/s after a spear of greater mass is thrown at the same velocity.

To solve this problem, we can use the conservation of momentum principle, which states that the total momentum of a system before an event is equal to the total momentum of the system after the event, as long as there are no external forces acting on the system. In this case, the system consists of the hunter, canoe, and spear.

Before the spear is released, the total momentum of the system is zero, since everything is stationary:

m1v1 + m2v2 + m3v3 = 0

where;

After the spear is released, the momentum of the spear changes from mv to 0, where m is the mass of the spear and v is its velocity. This change in momentum is balanced by an equal and opposite change in the momentum of the hunter and canoe. Let's assume that the hunter and canoe move together after the spear is released with a velocity of v:

m1v1 + m2v2 + m3v3 = (m1 + m2 + m3)v

Substituting the given values, we get:

75 kg × 0 m/s + 10 kg × 0 m/s + 0.72 kg × 12 m/s = (75 kg + 10 kg + 0.72 kg) × v

Solving for v, we get:

v = 0.093 m/s

b) If a spear of greater mass was thrown at the same velocity, the momentum of the system would still be conserved, but the velocity of the hunter and canoe would be lower than before. This is because the total mass of the system would be greater, so the same change in momentum would result in a smaller change in velocity.

To see this, let's use the same equation as before, but with a greater mass for the spear:

75 kg × 0 m/s + 10 kg × 0 m/s + (2 × 0.72 kg) × 12 m/s = (75 kg + 10 kg + 2 × 0.72 kg) × v

Solving for v, we get:

v = 0.047 m/s

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If the board has a non-zero mass of 26 kg, the placement of the pivot for balance would be different than if it had zero mass. To find the new pivot point, we need to take into account the weight of the board. The pivot point should be placed at a distance from the center of mass of the board so that the moments on both sides of the pivot are equal.

To calculate the pivot point, we need to use the equation:

M1 x d1 = M2 x d2

Where M1 and M2 are the masses on either side of the pivot, and d1 and d2 are the distances from the pivot to each mass. In this case, we have one mass (the person) on one side of the pivot, and the board on the other side. We can assume the person has a negligible mass compared to the board.

Let's say the person is standing 1 meter from the pivot. We also need to know the center of mass of the board, which we can assume is at the center of the board. If the board is 2 meters long, the center of mass would be 1 meter from either end.

Using the equation above, we can set up the following equation:

26 kg x (d1) = 60 kg x (2 - d1)

Solving for d1, we get:

d1 = 1.23 meters

So the pivot should be placed 1.23 meters from the end of the board where the person is standing in order to balance the board with a non-zero mass of 26 kg.

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To find the volume of a three-dimensional symmetrical shape using integration, we can use the method of cylindrical shells. This method involves dividing the shape into thin cylindrical shells and then integrating their volumes.

Let's say we have designed a symmetrical solid in the shape of a sphere with a cylindrical cavity running through its center. We will place the flat side (R) of the sphere against the x-y plane. The sphere will be revolving around the z-axis since it is symmetrical about that axis.

To find the volume, we first need to determine the equations for the sphere and the cavity.

The equation for a sphere centered at the origin with radius R is:

x^2 + y^2 + z^2 = R^2

The equation for the cylindrical cavity with radius r and height h is:

x^2 + y^2 = r^2,  -h/2 ≤ z ≤ h/2

The volume of the solid can be found by subtracting the volume of the cavity from the volume of the sphere. Using the method of cylindrical shells, the volume of each shell can be calculated as follows:

dV = 2πrh * dr

where r is the distance from the axis of rotation (the z-axis), and h is the height of the shell.

Integrating this expression over the appropriate range of r gives the total volume:

V = ∫[r1, r2] 2πrh * dr

where r1 and r2 are the radii of the cavity and the sphere, respectively.

Substituting the expressions for r and h, we get:

V = ∫[-h/2, h/2] 2π(R^2 - z^2) dz - ∫[-h/2, h/2] 2π(r^2 - z^2) dz

Simplifying and evaluating the integrals, we get:

V = π(R^2h - (1/3)h^3) - π(r^2h - (1/3)h^3)

V =  πh( R^2 - r^2 ) - (1/3)πh^3

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Average speed = total distance covered/ total time taken

here on the graph y-axis is represented as distance and x-axis is showing time

So for the average speed of Train (line A)

total distance covered (d) = 1500 m

total time taken to reach that distance (t) = 150 s

so by a simple formula

For the average speed of  Car (line B)

Total distance covered (d) = 1500 m

total time taken to reach that distance (t) = 120 s

so by

For Maximum speed of roller- coaster (LineC)

So in the time between 70-80 seconds, it has the highest slop which shows the speed maximum at that time

In that 10 seconds, it covered 200 meters which shows its maximum speed which is

For the average speed of a Roller- coaster (line C)

Total distance covered (d) = 1300 m

total time taken to reach that distance (t) = 150 s

For the Train to Stoped at a station we can see from 40 seconds to 90 Seconds train has covered almost 0 distance which clearly shows that it was stopped which is 90-40= 50 seconds.

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The correct answer is (b) Rank them according to the speed of the block at point B, greatest first.

In situation 1, the block is initially at rest and is dropped, so it starts from zero speed and gains speed as it falls.

In situation 2, the block is initially at rest and is allowed to slide down the ramp, so it starts from zero speed and gains speed as it slides down.

In situation 3, the block is initially at the top of the ramp and is allowed to slide down, so it starts from zero speed and gains speed as it slides down.

In situation 4, the block is initially at the top of the ramp and is allowed to slide down, so it starts from zero speed and gains speed as it slides down.

In situation 3 and 4, the speed of the block is the same at point B, which is the maximum speed that the block can attain.

In situation 1 and 2, the speed of the block is different at point B, with situation 1 having a higher speed.

Therefore, the correct answer is (b) Rank them according to the speed of the block at point B, greatest first.  

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Full Question ;

The figure shows four situations-one in which an initially stationary block is dropped t and three in which the block is allowed to slide down frictionless ramps. Rank the situations according to the speed of the block at point B, greatest first. a 1,2, 3,4 1,2 and 3 tie, 4 c. 1, 3 and 4 tie, 2 d. 3 and 4 tie, 2, 1 e. none of the above

Answer:

43.58 m/s

Explanation:

The final velocity, initial velocity, distance traveled and acceleration are related by the equation

v² = u² - 2ad  [1]

where

v = final velocity

u = initial velocity

a = acceleration

d = displacement

Given u = 10 m/s, a = 1.5 m/s², d = 600 m

v² = 10 ^2+ 2 x 1.5 x 600

v² = 100 + 1800

v² = 1900

v = √1900 = 43.58 m/s

Answer:

velocity = 29.4 m/s

Explanation:

We have been told to calculate the velocity of a ball after 3 seconds of freefall. To do this, we can use the following formula:

\(\boxed{v = u + at}\),

where:

• v = final velocity

• u = initial velocity

• a = acceleration

• t = time of freefall

In this case, u = 0 m/s, because the ball is initially stationary before it is released. Also, a = 9.81 m/s² because the ball is falling while inside the Earth, where the acceleration of freefall is 9.81 m/s².

Using the above information along with the formula, we can calculate the velocity of the ball after 3 seconds of freefall:

v = 0 m/s + (9.81 m/s² × 3 s)

  = 29.4 m/s

A subatomic particle found in the nucleus of every atom and the particle has a positive electrical charge : proton.

Proton is a subatomic particle found in the nucleus of every atom and the particle has positive electrical charge, equal and opposite to that of electron. If isolated, then a single proton would have mass of only 1.673 * 10^-27 kilogram, just slightly less than mass of a neutron.

A proton is a stable subatomic particle, with symbol p , H⁺, or ¹H⁺ with positive electric charge of +1 e elementary charge. It's mass is slightly less than that of neutron and 1,836 times the mass of electron.

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