Pete dad usually deposits $25 into his bank account every week.for the next weeks he wants to deposit more than the usually $25 and he wants the extra amount deposited to be the same each week.Which inequality and solution show how much more he can deposit each week and keep the total of his deposit above $500 for those 8 weeks? Yo

Answer:

Therefore, 7/8 is equal to 87.5 percentage

Step-by-step explanation: brainliest?

Answer:

1)The rocket hit the ground at     \(x = \frac{5}{4}\)

2)The maximum height of the rocket = 12.468 feet

Step-by-step explanation:

Step(i):-

Given equation  

                y = -2 x² + 5 x + 7 ...(i)

Differentiating equation (i) with respective to 'x' , we get

             \(\frac{dy}{dx} = -2( 2x) +5(1) = -4x +5\)

Equating zero

            \(\frac{dy}{dx} = 0\)

⇒      -4 x +5 =0

⇒      -4 x = -5

⇒          \(x = \frac{5}{4}\)

The rocket hit the ground at     \(x = \frac{5}{4}\)

Step(ii):-

    \(\frac{dy}{dx} = -4x +5\)  ...(ii)

Again differentiating equation (ii) with respective to 'x' , we get

 \(\frac{d^{2} y}{dx^{2} } = - 4(1) <0\)

The maximum height at x = \(\frac{-5}{4}\)

  y = -2 x² + 5 x + 7

 \(y = -2 (\frac{5}{4})^{2} + 5 (\frac{5}{4} ) + 7\)

\(y = \frac{-2(25)+ 25 (16)+7(64)}{64}\)

\(y = \frac{798}{64} = 12.468 feet\)

The maximum height of the rocket = 12.468 feet

The monthly income of the first person is $600.

Given that, the average monthly income of three persons is RS 3,600.

The income of the first is 1/5 of the combined income of the other two.

Here, Let income of the first be A, let income of the second be B and let Income of the third be C.

A+B+C=3600 -----(i)

Income for the first person = 1/5(B+C) -----(ii)

Substitute equation (ii) in equation (i), we get

(B+C)/5 +B+C =3600

B+C+5B+5C=3600×5

6B+6C=18000

6(B+C)=18000

B+C=3000 ------(iii)

Substitute (iii) in equation (i), we get

A=$600

Therefore, the monthly income of the first person is $600.

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The class of the equation and the cross section equation are;

The equation is a hyperboloid of two sheets

The cross sections are;

Equation at z = 0 is; y²/8 - x²/8 = 1

Equation at y = -4 is; x²/8 + z² = 1

Equation at y = 0 is; x²/8 + z² = -1

Equation at y = 4 is; x²/8 + z² = 1

Equation at x = 0 is; y²/8 - z² = 1

An equation is a mathematical statement which indicates the equivalence two expressions by joining them with the '=' sign.

The equation can be presented as follows;

y² = x² + 8·z² + 8

y² - x² - 8·z² = 8

y²/8 - x²/8 - z² = 1

The above equation is the equation of an hyperboloid of two sheets, where;

a² = 8, b² = 1, and c² = 8

Please find attached the diagram of the surface, created with an online 3D graphing tool.

The equation for the cross section at z = 0, can be obtained by plugging in z = 0, into the equation as follows;

y²/8 - x²/8 - 0 = 1

y²/8 - x²/8 = 1

The above equation is the equation of an hyperbola in the xy plane

The equation for the cross section at y = -4, can be obtained by plugging in y = -4, into the equation as follows;

4²/8 - x²/8 - z² = 1

- x²/8 - z² = 1 - 4²/8 = -1

- x²/8 - z² = -1

x²/8 + z² = 1

The above is an equation of an ellipse in the xz plane

The equation for the cross section at y = 0, can be obtained by plugging in y = 0, into the equation as follows;

0²/8 - x²/8 - z² = 1

- x²/8 - z² = 1

Therefore; x²/8 + z² = -1

The equation for the cross section at y = 4, can be obtained by plugging in y = 4, into the equation as follows;

4²/8 - x²/8 - z² = 1

- x²/8 - z² = 1 - 2 = -1

x²/8 + z² = 1

The above equation is the equation of an ellipse in the xz plane

The equation for the cross section at x = 0, can be obtained by plugging in x = 0, into the equation as follows;

y²/8 - 0²/8 - z² = 1

y²/8 - z² = 1

The equation is the equation of an hyperbola in the yz plane

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Therefore, the cylinder stretch in the new 6.00 m length of steel pipe is 0.094% of its original length, or about 5.64 mm.

The cylinder, which is frequently a three-dimensional solid, is one of the most primitive curved geometric forms. In simple geometry, it is known as a prismatic with a circular as its basis. The term "cylinder" is also used to refer to an infinitely curved surface in a number of modern domains of geometry and topology. A "cylinder" is a three-dimensional object made up of curved surfaces with round tops and bottoms.

Here,

The total weight supported by the new 6.00 m length of pipe is the weight of the pipe and drill bit beneath it, which is:

W = (20.0 kg/m)(3.00 km) + 100 kg

W = 60,100 kg

The equivalent diameter of the solid cylinder is 5.00 cm, or 0.05 m, so its radius is 0.025 m. The cross-sectional area of the steel pipe is therefore:

A = πr^2 = π(0.025 m)^2 = 0.0019635 m^2

The modulus of elasticity for steel is typically around 200 GPa (gigapascals), or 200,000,000 N/m^2. Using the formula for the stretch of a rod under tension, which is:

ΔL/L = F/(AE)

ΔL/L = (Wg)/(AE)

where g is the acceleration due to gravity (9.81 m/s^2).

Substituting the values we have calculated, we get:

ΔL/L = [(60,100 kg)(9.81 m/s^2)]/[(0.0019635 m^2)(200,000,000 N/m^2)]

ΔL/L = 0.0009397 or 0.094%

Therefore, the stretch in the new 6.00 m length of steel pipe is 0.094% of its original length, or about 5.64 mm.

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Answer:

380 dollars

Step-by-step explanation:

John earns $437 a week after a 15% pay rise.

Let the initially pay of John be x

x + (15% of x) = 437

x + 0.15x = 437

1.15x = 437

x = \frac{437}{1.15}

1.15

437

x = 380

Answer:

I have no idea how to do that.

Answer:

You're correct, it is -1.5,-2.5.

Step-by-step explanation:

ill take a guess on what the actual question is..

        area: 2,436

perimeter: 710

Answer:

um i think it's cheese

Step-by-step explanation:

Because i like cheese

We are given the area of a square and we are asked to find its side length. To do that, let's remember the formula for the area of a square:

Where:

We solve for the side length "l", by taking square roots on both sides:

Since we are given that the area is:

Replacing:

Solving the operations:

Therefore, the side length is 9.1 cm.

Answer:

B

Step-by-step explanation:

You must follow step by step to add 3/4x

Answer:

the second answer

Step-by-step explanation:

cause 0+0.8 is 0.8 and 0.8+0.3 is 1.1

Answer:

A

Step-by-step explanation:

To graph the inequality k > 5 on a number line, mark an open circle at 5 and shade the region to the right.

To graph the solutions to the inequality k > 5 on a number line, follow these steps:

Draw a horizontal line and mark a point for the number 5 on the line.

-------------------|---|---|---|---|---|---|---|---|---|---|

0 1 2 3 4 5 6 7 8 9 10

Since the inequality is k > 5, the solution includes all values greater than 5. Therefore, draw an open circle (○) at the number 5 to represent that 5 itself is not included in the solution.

-------------------|---|---|---|---○---|---|---|---|---|---|

0 1 2 3 4 5 6 7 8 9 10

Shade the region to the right of the open circle. This shading represents all values that are greater than 5 and satisfy the inequality k > 5.

-------------------|---|---|---|---○===================>

0 1 2 3 4 5 6 7 8 9 10

The resulting number line graph illustrates that any value to the right of the open circle (excluding 5 itself) satisfies the inequality k > 5.

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Answer: Can you give more of an explination?

Step-by-step explanation:

Answer:

False. The center of a semisimple Lie algebra is usually not trivial.

Step-by-step explanation:

The center of a semisimple Lie algebra is the set of elements of the Lie algebra that commute with all other elements in the algebra. In most cases, the center of a semisimple Lie algebra is not trivial, meaning it contains at least one non-zero element. For example, the center of the simple Lie algebra sl(2,C) contains the two-dimensional Lie algebra spanned by the scalar matrices I and -I. The center of the Lie algebra so(5,C) is spanned by the five-dimensional Lie algebra spanned by the matrices diag(1,1,1,-1,-1). These examples demonstrate that the center of a semisimple Lie algebra is usually not trivial.

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To determine the area of the remaining piece of cardboard expressed in terms of x when a square of side length x inches is cut out from a rectangular piece of cardboard having a length of 6x+2 inches and a width of 2x-4 inches, use the following steps.

Draw and label a diagram of the problem. The rectangle should be labeled as 6x+2 inches by 2x-4 inches, and the square cut out should be labeled as x inches by x inches. This is how the diagram looks like: Determine the area of the rectangle, Arect.

The area of the rectangle is given by the product of its length and width. Thus, Arect = (6x + 2)(2x - 4) Determine the area of the square, Asq. The area of the square is given by the square of its side length. Thus, Asq = x²Step 4: Determine the area of the remaining cardboard after the square is cut out, Ar.

This is the difference between the area of the rectangle and the area of the square. Thus, Ar = Arect - Asq= (6x + 2)(2x - 4) - x²= 12x² - 20x - 16

Simplify the expression. The final answer is given in terms of x. Thus, Ar = 12x² - 20x - 16.The area of the remaining piece of cardboard is expressed in terms of x as 12x² - 20x - 16.

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Answer:

See below

Step-by-step explanation:

If you are given slope (m) and intercept (b) , then write the line equation like this:

y = mx + b

Answer:

140

If that's wrong, try 147

Step-by-step explanation:

With this brief sequence of numbers, we can see that the function is linear, and increases by 7 each term, with the first term at -21, and therefore, the "0th" term, or the y-intercept, at -28. With this information we can create a function in slope intercept form (y=mx+b):

\(y=7x-28\\\),

where our m (slope) is 7, and our b (y-intercept) is -28.

If this doesn't make sense, then the easiest way is to just keep adding seven to the previous number until you get to the 24th term.

Hope this helps!

AA - the angle-angle similarity postulate. We’re one pair of equivalent angles (angle B = angle D = 50 degrees), and angles CDE and ACB are equivalent by the fact that they’re vertical angles to each other.

We will get y = -7x + 6  in graph y-intercept 6 and slope-7.

The equation of the line with a y-intercept of 6 and a slope of -7 can be written in slope-intercept form as:

y = mx + b

where m is the slope and b is the y-intercept.

Substituting the given values, we get:

y = -7x + 6

So the equation of the line is y = -7x + 6.

slope -7 and y - intercept 6.

Slope intercept form: y = mx + b, m=slope, b = y-intercept

y = -7x + 6

Just plug in a value for x and solve for y

x     y=-7x+6

------------------

0           6

1          -1

If you plot these two points and draw a straight line through them,

that is the graph of the line.

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The height of the hill is approximately 25.73 ft. Where v0 is the initial velocity (108 ft/s), g is the acceleration due to gravity \((-32.2 ft/s^2)\),

To find the height of the hill, we can use the formula for the vertical position of an object under constant acceleration:

h = h0 + v0t + 1/2at^2

where h is the final height, h0 is the initial height, v0 is the initial velocity, t is the time, and a is the acceleration due to gravity (-32.2 ft/s^2).

In this case, we are given that the initial height h0 is 3 ft, the initial velocity v0 is 108 ft/s, and the time t is 9.5 s. We want to find the height of the hill, which we can denote as h_hill. The final height is the height of the plain, which we can denote as h_plain and assume is zero.

At the highest point of its trajectory, the arrow will have zero vertical velocity, since it will have stopped rising and just started to fall. So we can set the velocity to zero and solve for the time it takes for that to occur. Using the formula for velocity under constant acceleration:

v = v0 + at

we can solve for t when v = 0, h0 = 3 ft, v0 = 108 ft/s, and a = -32.2 ft/s^2:

0 = 108 - 32.2t

t = 108/32.2 ≈ 3.35 s

Thus, it takes the arrow approximately 3.35 s to reach the top of its trajectory.

Using the formula for the height of an object at a given time, we can find the height of the hill by subtracting the height of the arrow at the top of its trajectory from the initial height:

h_hill = h0 + v0t + 1/2at^2 - h_top

where h_top is the height of the arrow at the top of its trajectory. We can find h_top using the formula for the height of an object at the maximum height of its trajectory:

h_top = h0 + v0^2/2a

Plugging in the given values, we get:

h_top = 3 + (108^2)/(2*(-32.2)) ≈ 196.78 ft

Plugging this into the first equation, we get:

h_hill = 3 + 108(3.35) + 1/2(-32.2)(3.35)^2 - 196.78

h_hill ≈ 25.73 ft

If the arrow is launched at t0, the equation describing velocity as a function of time would be:

v(t) = v0 - gt

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Answer:

B. Seraphina is not correct. The sum of the squares of the two legs of the triangle is not equal to the square of the hypotenuse.

Step-by-step explanation:

If KLM is a right triangle, then 12^2+16^2=19^2,

144+256 = 361

400 = 361 false

so, KLM is not a right triangle as the sum of the squares of the two legs are not equal to the square of the hypotenuse.

The sum of the squares of the two legs of the triangle is not equal to the square of the hypotenuse. Seraphina is incorrect.

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

|AC|^2 = |AB|^2 + |BC|^2    

where |AB| = length of line segment AB. (AB and BC are the rest of the two sides of that triangle ABC, AC being the hypotenuse).

Seraphina says that ΔKLM is a right triangle.

Let us check whether triangle ΔKLM is a right triangle or not.

By the Pythagoras theorem, we have

19² = 16² + 12²

361 = 256 + 144

361 ≠ 400

Thus, the triangle is not a right triangle.

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9514 1404 393

Answer:

  x^2/81 -y^2/19 = 2500

Step-by-step explanation:

The time difference between signals is 3 µs, so the distance difference is ...

  (300 m/µs)(3 µs) = 900 m

If we assume the coordinates of Q are (-500, 0), then the distances from point X to the control towers are ...

  XQ = √((x +500)^2 +y^2)

  XR = √((x -500)^2 +y^2)

We want the difference in distances to be 900, so we have the equation ...

  |XQ -XR| = |√((x +500)^2 +y^2) -√((x -500)^2 +y^2)| = 900

Squaring both sides gives ...

  (x +500)^2 +2(x +500)y +y^2 -2√(((x +500)^2 +y^2)((x -500)^2 +y^2)) +((x -500)^2 +y^2) = 810000

Separating the root from the rest of the equation, squaring again, and simplifying the rather messy expression, we can arrive at the equation ...

  x^2/81 -y^2/19 = 2500 . . . . . a hyperbola opening horizontally

Answer:

75.27

Step-by-step explanation:

Rectangle = 20+2+2+20-11=47

quarter circle = 1/4(2)(11)(3.14)=17.27 + 11 = 28.27

47+28.27=75.27

Answer:

75.27.cm

Step-by-step explanation:

it works i got a 100 on the test

Answer:

to be fair, this one is tough  :D

Step-by-step explanation:

So,  we need to figure out what 56 * 8.50 is , it's  476, now subtract that from the total sales.   3136-476=2660 ... the 2660 is the amount of sales when the adults and the kids were at the same amount.... sooo use a common variable like X.... and add up the ticket prices of 10.50+8.50 so that you have an eqution of  

x*19.00=2660.00

x=140    people

nice we have the Adults and kids ... each of 140

now just add 140+56=196 kids went to the movies

196 kids

Answer:

P(5,6) = 63

Step-by-step explanation:

Test each point to see which ordered pair maximizes the objective function:

(0,0): p = 3(0) + 8(0) = 0

(2,7): p = 3(2) + 8(7) = 6 + 56 = 62

(5,6): p = 3(5) + 8(6) = 15 + 48 = 63

(8,1): p = 3(8) + 8(1) = 24 + 8 = 32

Hence, (5,6) is the ordered pair that maximizes the objective function.

The three consecutive multiples of 3 are 15, 18 and 21

First, let's determine three successive multiples of 3:

The subsequent two would be "x+3" and "x+6" if we call the initial number "x".

Since we are aware that the third number (x+6) is one more than the first two numbers (x + x+3), we can write the following equation:

2/3(x + x+3) = (x+6) + 1

Simplifying this equation, we get:

2/3(2x+3) = x+7

Multiplying both sides by 3, we get:

2(2x+3) = 3(x+7)

Expanding and simplifying, we get:

4x + 6 = 3x + 21

Subtracting 3x and 6 from both sides, we get:

x = 15

Therefore, the three consecutive multiples of 3 are 15, 18 and 21

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Answer:

13

Step-by-step explanation:

cos 13 x 2 = 26

13 is a factor that is more than 4 and less then 26

The factor of the number 26 that is between 4 and 26 is 13. Factors are the numbers that can divide into a number without leaving a remainder. In this case, the factors of 26 are 1, 2, 13, and 26.

In mathematics, a factor of a number is a number that divides into another number without leaving a remainder. In the case of the number 26, its factors include 1, 2, 13, and 26. The factor of 26 that is between 4 and 26 is 13.

To find this, you can go through the factors of 26 one by one. The factors are found by dividing 26 by all the numbers up to 26, and the numbers that give a remainder of 0 are the factors. In this case, 1, 2, 13, and 26 divide evenly into 26, and so are the factors of 26. Of these, only 13 lies between 4 and 26.

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