Parallelogram be is a scaled copy of parallelogram U what is the value of w ( please answer ASAP I'm in a rush)

Answer:

5x

Step-by-step explanation:

Answer:

Area =  3π.

Step-by-step explanation:

This is 3/4 of a circle whose area is 3/4πr^2

= 3/4 * 2^2 * π

= = 3/4 * 4 *  π

= 3π

Answer:

i think 223/499

Step-by-step explanation:

Answer: X=147

Step-by-step explanation:

33+114= 147

two angles added together equals x

x=147

Answer: 1.247834e+15

Step-by-step explanation: Used Calculator

The diameter d(c d) of the opening 20cm from the vertex is approximately 16.33cm.


To find the diameter of the opening 20cm from the vertex, we can use the fact that the cross-section of a cone is a circle. We can also use the formula for the slant height of a cone, which is given by the equation:
s = sqrt(r^2 + h^2)
where s is the slant height, r is the radius of the circular base, and h is the height of the cone.

In this case, we know that the height of the cone is 20cm from the vertex. We also know that the radius of the circular base is d/2, where d is the diameter we are trying to find.
So, using the formula for the slant height, we can write:
s = sqrt((d/2)^2 + 20^2)
We also know that the slant height of the cone is equal to the distance from the vertex to any point on the circumference of the base. Therefore, we can write:
s = r
where r is the radius of the circle formed by the cross-section of the cone at a height of 20cm from the vertex.
Now, equating the expressions for s and r, we get:
sqrt((d/2)^2 + 20^2) = d/2
Squaring both sides and simplifying, we get:
d^2 - 4d - 800 = 0
Using the quadratic formula, we can solve for d and get:
d = (4 + sqrt(4^2 + 4*800))/2
d = 4 + sqrt(3204))/2
d ≈ 16.33
Therefore, the long answer to your question is that the diameter of the opening 20cm from the vertex is approximately 16.33cm.

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Substitute \(x=e^t\). By the chain rule,

\(\dfrac{dy}{dx} = \dfrac{dy}{dt}\cdot\dfrac{dt}{dx}\)

Now \(t=\ln(x)\implies\frac{dt}{dx}=\frac1x\), so

\(\dfrac{dy}{dx} = \dfrac1x \dfrac{dy}{dt} \\\\ ~~~~~~~~ \iff \dfrac{dy}{dt} = x\dfrac{dy}{dx}\)

Differentiate both sides again to recover the second and third derivatives.

\(\dfrac{d^2y}{dx^2} = -\dfrac1{x^2}\dfrac{dy}{dt} + \dfrac1x \dfrac{d\frac{dy}{dt}}{dx} \\\\ ~~~~~~~~ = -\dfrac1{x^2}\dfrac{dy}{dt} + \dfrac1x \left(\dfrac{d\frac{dy}{dt}}{dt}\cdot\dfrac{dt}{dx}\right) \\\\ ~~~~~~~~ = -\dfrac1{x^2} \dfrac{dy}{dt} + \dfrac1{x^2}\dfrac{d^2y}{dt^2} \\\\ ~~~~~~~~ \iff \dfrac{d^2y}{dt^2} - \dfrac{dy}{dt} = x^2 \dfrac{d^2y}{dx^2}\)

\(\dfrac{d^3y}{dx^3} = \dfrac2{x^3}\dfrac{dy}{dt} - \dfrac1{x^2}\dfrac{d\frac{dy}{dt}}{dx} - \dfrac2{x^3} \dfrac{d^2y}{dt^2} + \dfrac1{x^2}\dfrac{d\frac{d^2y}{dt^2}}{dx} \\\\ ~~~~~~~~ = \dfrac2{x^3} \dfrac{dy}{dt} - \dfrac1{x^2}\left(\dfrac{d\frac{dy}{dt}}{dt}\cdot\dfrac{dt}{dx}\right) - \dfrac2{x^3} \dfrac{d^2y}{dt^2} + \dfrac1{x^2}\left(\dfrac{d\frac{d^2y}{dt^2}}{dt}\cdot\dfrac{dt}{dx}\right) \\\\ ~~~~~~~~ = \dfrac2{x^3} \dfrac{dy}{dt} - \dfrac1{x^3} \dfrac{d^2y}{dt^2} - \dfrac2{x^3} \dfrac{d^2y}{dt^2} + \dfrac1{x^3}\dfrac{d^3y}{dt^3} \\\\ ~~~~~~~~ \iff \dfrac{d^3y}{dt^2} - 3 \dfrac{d^2y}{dt^2} + 2 \dfrac{dy}{dt} = x^3 \dfrac{d^3y}{dx^3}\)

The ODE then transforms to a linear one,

\(3\left(\dfrac{d^3y}{dt^2} - 3 \dfrac{d^2y}{dt^2} + 2 \dfrac{dy}{dt}\right) + 28\left(\dfrac{d^2y}{dt^2} - \dfrac{dy}{dt}\right) + 55\dfrac{dy}{dt} + 9 y = 0\)

or using Lagrange's prime notation,

\(3(y''' - 3y'' + 2y') + 28(y'' - y') + 55y' + 9y = 0\)

\(3y''' + 19y'' + 33y' + 9y = 0\)

The characteristic equation is

\(3r^3 + 19r^2 + 33r + 9r = (r + 3)^2 \left(r + \dfrac13\right) = 0\)

with roots at \(r=-3\) and \(r=-\frac13\), so the general solution is

\(y(t) = C_1 e^{-1/3\,t} + C_2 e^{-3t} + C_3 t e^{-3t}\)

Back in terms of \(x\), we get

\(\boxed{y(x) = C_1 x^{-1/3} + C_2 x^{-3} + C_3 x^{-3}\ln(x)}\)

Answer:

D and C should be correct.

Step-by-step explanation:

The Longest Increasing Subsequence (LIS) problem is a classic problem in dynamic programming. Given a sequence of numbers, the problem is to find the longest subsequence in which the numbers are in increasing order. For example, given the sequence {3, 1, 5, 2, 4}, the longest increasing subsequence is {1, 2, 4}, which has length 3.

The LIS problem can be solved using dynamic programming by defining an array to store the length of the longest increasing subsequence that ends at each position in the sequence. The array is initialized to 1, and then for each position i in the sequence, the length of the longest increasing subsequence that ends at i is calculated by finding the maximum length of any subsequence that ends at a position j < i and has a smaller value than the value at i. The final solution is the maximum length of any subsequence in the array.

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Answer:

$36.25

Step-by-step explanation:

Shipping and tax are 25% the price of online book, thus it will be 25/100 x 29 = $7.25

Thus, total will be 29 + 7.25 = $36.25

The measure of <TKZ is 18 degree.

The length of KZ is 17.3082 m.

The  height of the kite K from the ground is 18.3082 m.

We have,

Angle of Elevation = 72

TK = 18.2 m

Using trigonometry

sin 72 = P/ H

sin 72 = P / 18.2

P = 17.3082

Now, cos 72 = B/H

cos 72 = B/ 18.2

B = 5.6238

Now, <TKZ = 180 - 90 - 72 (angle Sum property)

<TKZ = 18 degree

and, length of KZ = 17.3082 m

Not, the height of the kite K from the ground

= 18.3082 m

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Answer:

$13.20

Step-by-step explanation:

A dozen consists of 12 items. If you have 3 you must multiply the current amount by 4 to get 12. Therefore you must also multiply the price by 4.

3.30*4=13.20

The possible rational roots are

The constant is 14, and its factors are:

The lead coefficient is 1, and its factors are:

Then, the possible rational roots for this equation are

Since, 7 is a possible rational root, the answer is option C

The opposite of 2(3x-8) is 1/(6x-16)

The inverse of an expression is thesame as the opposite of an expression.

Inverse operations are pairs of mathematical manipulations in which one operation undo the action of the other. The inverse of a number usually means its reciprocal.The product of a number and its inverse will be equal to 1.

For example the reciprocal of 5 is 1/5. That is 5×1/5= 1

Also the inverse of a fraction like 5/7 is 7/5. That is 5/7× 7/5 = 1

Similarly, the inverse of 2(3x-8) will be 1/2(3x-8)

= 1/6x- 16.

Therefore the inverse of 2(3x-8) = 1/(6x-16)

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The power series representation of f(x) is f(x) = (1/6) * (1 - x/6 + x²/36 - x³/216 + ...) and centered at x = 0. Also, the interval of convergence for the power series representation.

The function f(x) = 1/(6x) can be represented as a power series using the geometric series formula. Recall that the geometric series formula is:

1 / (1 - r) = 1 + r + r² + r³ + ...

In this case, we can rewrite f(x) as:

f(x) = 1/(6x) = (1/6) * (1/x) = (1/6) * (1/(1 - (-x/6)))

Now, we can identify that the function is in the form of a geometric series with a common ratio of -x/6. Therefore, we can use the geometric series formula to write f(x) as a power series:

f(x) = (1/6) * (1/(1 - (-x/6)))

    = (1/6) * (1 + (-x/6) + (-x/6)² + (-x/6)³ + ...)

Simplifying the expression:

f(x) = (1/6) * (1 - x/6 + x²/36 - x³/216 + ...)

This is the power series representation of f(x) centered at x = 0.

To determine the interval of convergence, we need to find the values of x for which the power series converges. In this case, the power series is a geometric series, and we know that a geometric series converges when the absolute value of the common ratio is less than 1.

In our power series, the common ratio is -x/6. So, for convergence, we have:

|-x/6| < 1

Taking the absolute value of both sides:

|x/6| < 1

-1 < x/6 < 1

-6 < x < 6

Therefore, the interval of convergence for the power series representation of f(x) is -6 < x < 6.

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Answer:

28.75 inches

Step-by-step explanation:

1.) 5 3/4 x 5/1 = 28 3/4

2.) 28 3/4 simplified is 28.75

Hope that helps!

In order to prove that △VWZ ~ △YXZ by SAS theorem we must have ∠VZW ≅ ∠YZX. Thus, option c is the most appropriate choice.

To prove that △VWZ ~ △YXZ by SAS theorem, we must prove that two sides of each triangle such that the angle between these sides is congruent are also congruent.

now △VWZ ~ △YXZ is to be proved, it implies that -

∠V ↔︎ ∠Y

∠W ↔︎ ∠X

∠Z ↔︎ ∠Z

thus  ∠VZW ≅ ∠YZX should be true.

hence, option c is correct and that automatically strikes out option d.

now the sides involving Z should also be congruent to prove that

△VWZ ~ △YXZ

thus, side WZ ≅ side XZ and side VZ ≅ side YZ

since we don't have such an option- options a and b are not the correct choices for this question.

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The complete question is -

In the diagram, VZ/YZ=WZ/XZ

To prove that VWZ~YXZ by the SAS similarity theorem, Which other sides or angles should be used?

a. WV and XY

b. WV and YZ

c. ∠VZW ≅ ∠YZX

d. ∠VWZ ≅ ∠YXZ

The values within the range of the piecewise-defined function are

y = -6,  y = -4, y = 1 and y = 3.

A piecewise function, or f(x), is a function with various definitions at various intervals of x. A piecewise function's graph is divided into sections that each correspond to one of its definitions. A very good illustration of a piecewise function is the absolute value function.

Given f(x) = 2x + 3,   if x < -3

f(x) = x, if  x = -3

f(x) = -x - 2, if  x > -3

the function will be at x ≤ -3 and x ≥ -3

We now wish to determine which values fall within this function's range. Keep in mind that the set of possible outputs from a function constitutes its range.

The range of the first part of the function f(x) = 2*x + 2 has an upper bound at x = -3

f(-3) = 2*-3 + 2 = -6 + 2 = -4

Then the range of the first part is (-∞, -4)

Notice that the actual value -4 belongs to the range because x is smaller than and equal to -3.

The range of the second part has a lower bound for x = -3, the lower bound is:

f(-3) = -(-3) - 2 = 1

Then the range of this part is (1, ∞)

Then the range of the piecewise function is:

(-∞, -4) U (1, ∞)

and including -4 and 1

y = -6,  y = -4

y = 1,     y = 1

Hence values in the range are y = -6,  y = -4, y = 1, and y = 3.

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Answer:

f(1) = 42

Step-by-step explanation:

Step 1: Switch all x out to 1 for f(1) which would look like this: f(1)=4(1)^2+3(1)+13

Step 2: You would then simplify it starting with 4(1)^2 which would equal 4 squared which equals 16.

Step 3: After simplifying you would have f(1)=16+3+13

Step 4: You then just add and get 42

Hope this helped :D

Answer:

The correct answer is option C.

Step-by-step explanation:

1) Simplify -5 - 3 to -8.

\( | - 8| - 8\)

2) Simplify | -8 | - 8 to 8.

\(8 - 8\)

3) Simplify.

\(0\)

Therefor, the answer is Option C. 0.

Answer:

0

Step-by-step explanation:

|-5 - 3| + (-8)

First simplify the absolute value

|-5 - 3|  = |-8|  and absolute value is positive so 8

8 + (-8) =0

The probability that a student enrolled in algebra is also enrolled in health is 0.8.

Let's denote the event of a student being enrolled in algebra as A and the event of a student being enrolled in health as H. We are given that 25% of the students are enrolled in algebra (P(A) = 0.25) and 20% of the students are enrolled in both algebra and health (P(A ∩ H) = 0.20).

We want to find P(H|A), the probability that a student is enrolled in health given that the student is enrolled in algebra.

Using the conditional probability formula:

P(H|A) = P(A ∩ H) / P(A)

We substitute the given values:

P(H|A) = 0.20 / 0.25

Simplifying this expression:

P(H|A) = 0.80

Therefore, the probability that a student enrolled in algebra is also enrolled in health is 0.80, or 80%.

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Answer:

(-4,3)

Step-by-step explanation:

The result for the division of the fractions in this problem is given as follows:

\(\frac{x^3 + 6x^2 + 7x + 18}{(x - 3)(x + 9)(x^2 - 9)}\)

The division of two fractions is given by the multiplication of the first fraction by the inverse of the second fraction.

The first fraction in this problem is composed by the sum of two fractions, as follows:

\(\frac{x + 5}{x + 9} + \frac{x + 7}{x^2 - 9}\)

Applying the subtraction of perfect squares, we have that:

x² - 9 = (x - 3)(x + 3).

The second fraction is given as follows:

(x² - 9)/(x + 3).

Considering the factoring of x² - 9, the second fraction is given as follows:

x - 3.

Hence the inverse is of:

1/(x - 3).

Then the entire quotient is given as follows:

\(\left(\frac{x + 5}{x + 9} + \frac{x + 7}{x^2 - 9}\right) \times \frac{1}{x - 3}\)

The addition of the two fractions is given as follows:

\(\frac{(x + 5)(x^2 - 9) + (x + 7)(x + 9)}{(x + 9)(x^2 - 9)} = \frac{x^3 + 6x^2 + 7x + 18}{(x + 9)(x^2 - 9)}\)

Applying the multiplication by x - 3 in the denominator, the quotient is given as follows:

\(\frac{x^3 + 6x^2 + 7x + 18}{(x - 3)(x + 9)(x^2 - 9)}\)

The problem asks for the quotient between the two fractions.

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The functions g and h, have values for the inverse functions g⁻¹(9) = 1 and h⁻¹(-1) = -1. The composite function (h o h⁻¹)(-1) is equal to -1.

A function is said to have an inverse if it is both one-to-one and onto

for the function g using y = mx + c, when x = 1 and y = 9

m = 8/5 and c = 37/5

g(x) = (8/5)x + 37/5

g⁻¹(x) = (5x - 37)/8

g⁻¹(9) = [5(9) - 37]/8

g⁻¹(9) = (45 - 37)/8

g⁻¹(9) = 8/8

g⁻¹(9) = 1

for the function h(x) = -3x - 4, the inverse;

h⁻¹(x) = -(x + 4)/3

h⁻¹(-1) = -(-1 + 4)/3

h⁻¹(-1) = -3/3 = -1

(h o h⁻¹)(-1) = -[3(-1)] - 4

(h o h⁻¹)(-1) = -(-3) - 4

(h o h⁻¹)(-1) = 3 - 4

(h o h⁻¹)(-1) = -1.

Therefore, for the functions g and h, the values for the inverse functions g⁻¹(9) = 1 and h⁻¹(-1) = -1. The composite function (h o h⁻¹)(-1) is equal to -1.

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Answer:

Step-by-step explanation:

think that there are 15 ways ... call the boxes A, B, and C.

You could put all four b***s into either box A, or box B, or box C  --->  3 ways.

You could put three ball into one box and the other ball into another box:

-- 3 into A, 1 into B, 0 into C; or 3 into A, 0 into B, 1 into C; or 1 into A, 3 into B, 0 into C; or 1 into A, 0 into B, 3 into C; or 0 into A, 3 into B, 1 into C; or 0 into A, 1 into B, 3 into C  --->  6 ways

You could put two balls into one box and the other two balls into another box:

-- 2 into A, 2 into B, 0 into C; or 2 into A, 0 into B, 2 into C; or 0 into A, 2 into B, 2 into C  --->  3 ways.

You could put two b***s into one box and one ball into each of the other two boxes:

-- There are three boxes that could get the two b***s  --->   3 ways

Total:  3 + 6 + 3 + 3  =  15 ways.

Answer:

c

Step-by-step explanation:

Answer:

the first one

Step-by-step explanation:

The measure of each of the acute angles of the right triangle is 32° and 58°.

A right triangle is a kind of triangle which has a right angle (90°) and two acute angles (less than 90°).

Let x = measure of one of the acute angles

If the measure of one acute angle of a right triangle is 6 less than twice the measure of the other acute angle, then

measure of the other acute angle = 2x - 6

The sum of all the angles of any triangle is equal to 180°. Hence,

90° + x + 2x - 6 = 180°

Solve for the value of x.

3x = 96

x = 32

Solve for the measure of the other acute angle.

2x - 6 = 2(32) - 6 = 58

Hence, the two angles are 32° and 58°.

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Answer:

i think it will be chose 3 times

Step-by-step explanation:

im not sure thats my pridiction

Answer:

0.4

Step-by-step explanation:

It would take the two painters together eight hours to paint the house

Step-by-step explanation: Given that, One painter can paint the entire house in twelve hours. The second painter takes eight hours to paint a similarly-sized house. To find, How long would it take the two painters together to paint the house? Suppose one painter takes x hours to paint the house.

Therefore, the other painter will take x-4 hours to paint the same house. According to the question, \(1/x+1/(x-4)=1/12+1/8\) Multiply by LCM, \(8(x-4)=12x+12(x-4)8x-32=6x+484x=80x=20\)Therefore, the first painter will take 20 hours to paint the house. The second painter will take 16 hours (20-4). Together they will take, \(1/20+1/16=0.1+0.0625=0.1625\) Thus, they will take 6.1538 hours which can be rounded to 4.8 hours.

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Given,

The stem and leaf plot of the data is shown in question.

The first statement is median is 30.

Here, the median of the data is 30.

Hence, statement 1 is correct.

The second statement is that the number of student who read less than 20 pages are 10.

But the number of student who reads less than 20 pages are 4.

Hence, statement 2 is also incorrect.

The third statement is over 50% of students read less than 20 pages

Here,

total number of students are 20.

The number of student who can read only pages less than 20 are 4.

4 is 20% of 20.

Hence, statement 3 is also incorrect.

The forth statement is the range of the data is 52.

Range= larger value - smaller value

= 67 - 12

= 55

Here, the range of the given data is the 55.

Hence, statement 4 is not correct.