The list in order that best describes the ball's motion as it drops into the spring is e, b, d, a, f and c.
The order is as follows:
e) The ball is dropped from rest and then negatively accelerates due to gravityb) The push from the spring exceeds the force of gravity. The ball momentarily comes to rest.d) Acceleration of the ball changes from negative to positive due to an upward push from the spring.a) The acceleration of the ball decreases as the spring extendsf) The ball leaves the spring with a large positive velocity. The acceleration is negative due to gravity.c) The velocity decreases due to negative gravitational acceleration.Option (e) come first because it the starting point. (b) comes next as the ball comes to rest as the spring is fully compressed. (d) comes next as the ball started its upward movement. (a) comes next as the spring is extending. (f) comes next as the ball has completely left the spring. (c) comes next as it indicates the balls movement after leaving the spring.+
Therefore, e, b, d, a, f and c is the correct order of explanation of the ball's movement.
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Please answer. Find the maximum height
The maximum height be 3.01 m.
What is conservation of energy?According to the law of conservation of energy: The total energy of the system is conserved in a closed system, also known as an isolated system.
Given parameters:
Mass of the box: m = 2.0 kg
Spring constant: k = 2000 N/m.
Compression of spring: x = 20 cm = 0.2m
Angle of inclination: θ = 37°
Coefficient of friction: μ = 0.1
If the box raises up to distance d then according to law of conservation of energy:
1/2kx² = mgdsin37° + μ mg d sin37°
1/2kx² = mgdsin37°(1 + μ)
d = 1/2kx²/(1+μ)mgsin37° = 1/2 × 2000 × 0.2²/{(1+0.1) × 2 × 10 × sin37°}
= 3.01 m.
Hence, The maximum height be 3.01 m.
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What is the subject Physic about
Explanation:
Physics is the branch of science concerned with the study of the properties and interactions of space, time, matter and energy.
Answer:
if you are very excited to know why ball doesn't go up
The Sun radiates energy at a rate of about 4×1026W. At what rate is the mass decreasing?
4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.
The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.
To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.
Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.
ΔE = 4×10^26 W
c = 3×10^8 m/s (speed of light)
Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².
Substituting the values, we have:
Δm = (4×10^26 W) / (3×10^8 m/s)²
Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.
This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.
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Rhea is driving north in a straight line. After driving for 2.4 kilometers, she turns west, and drives for 3.1 km. At the end of her drive, what is the magnitude of her displacement vector? To find the magnitude of a resultant vector, use the Pythagorean theorem: a² + b² = c² A) 3.9 km B) 5.5 km (this one is incorrect) C) 2.8 km D) 2.3 km
Option A) 3.9 km is the correct answer. the magnitude of Rhea's displacement vector is approximately 3.92 km.
In order to find out the magnitude of Rhea's displacement vector, we have to add up all of the displacement vectors.
Then we can use the Pythagorean theorem to calculate the magnitude of the resultant vector.
Since Rhea is first driving north for 2.4 km and then west for 3.1 km, we can represent her displacement vectors as follows: Δx = 0 km and Δy = 2.4 km for the first vector, and Δx = -3.1 km and Δy = 0 km for the second vector.
We can then add these vectors together by adding their components: Δx = 0 km + (-3.1 km) = -3.1 km and Δy = 2.4 km + 0 km = 2.4 km.
This gives us a resultant vector of -3.1 km east and 2.4 km north.
Using the Pythagorean theorem, we can find the magnitude of this vector: \(\sqrt{(\(-3.1 km)^{2} + (2.4 km)^{2} ) } = \sqrt{(9.61 + 5.76) km^{2} } = \sqrt{15.37 km^{2} } \approx 3.92 km.\)
Therefore, the magnitude of Rhea's displacement vector is approximately 3.92 km.
Therefore, option A) 3.9 km is the correct answer.
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1.How are elements arranged on the periodic table in terms of valence electrons?
2. Show some evidence using data tables
3. Explain how the evidence supports your claim. Explain how the evidence from your data table shows the trends for valence electrons for both groups and periods on the periodic table.
Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.
1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.
2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:
Element | Electron Configuration | Group | Period |
--------------------------------------------
Hydrogen | 1s^1 | 1 | 1 |
Lithium | [He] 2s^1 | 1 | 2 |
Carbon | [He] 2s^2 2p^2 | 14 | 2 |
Oxygen | [He] 2s^2 2p^4 | 16 | 2 |
Neon | [He] 2s^2 2p^6 | 18 | 2 |
--------------------------------------------
3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.
- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.
- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.
By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.
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I don’t understand what it’s asking me to do
Because the mass and displacement are already given in Kg and m, respectively, in the first part of your question, there is no need to convert them. However, in the second part of your question, you must use the given equation to calculate the spring constant.
if the table data is given in grams and cm you have to convert it using the following conversion,
1. To convert grams to kilograms, we divide the mass values by 1000.
2. To convert centimeters to meters, we divide the displacement values by 100.
But here in the given table it's already given the mass in kg and the displacement in meters (m). so no need to convert it.
Now comes the second part of your question,
To calculate the spring constants for the given data, we can use the equation:
k = -mg/Δx
where:
k is the spring constant (in N/m),
m is the mass (in kg), and
Δx is the displacement of the spring (in m).
Let's calculate the spring constants using the provided data:
Mass (kg): 0.05 0.1 0.2 0.3 0.4 0.5 0.6
Displacement of Spring (m): 0.012 0.027 0.065 0.1 0.135 0.17 0.199
Using the equation
k = -mg/Δx,
we can calculate the spring constant for each data point:
For the first data point (m = 0.05 kg, Δx = 0.012 m):
k = -0.05 kg * 9.8 m/s² / 0.012 m
k ≈ -40.833 N/m
Similarly, we can calculate the spring constants for the other data points:
For the mass of 0.05 kg, the spring constant is approximately -40.833 N/m.
For the mass of 0.1 kg, the spring constant is approximately -18.519 N/m.
For the mass of 0.2 kg, the spring constant is approximately -6.154 N/m.
For the mass of 0.3 kg, the spring constant is approximately -3.267 N/m.
For the mass of 0.4 kg, the spring constant is approximately -2.222 N/m.
For the mass of 0.5 kg, the spring constant is approximately -1.716 N/m.
For the mass of 0.6 kg, the spring constant is approximately -1.449 N/m.
Therefore, In the first part of the question, there is no need to convert the mass into kg and the displacement cm into m because it is already given in kg and m respectively, and in the second part question you have to calculate the spring constant using the given equation.
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in 1977 steve weldon ate 91 m of spaghetti in 29 s. at the same speed, how long would it take Mr. weldon to eat 5 m of spaghetti?
The time that would be taken is 1.6 s.
What is the speed?We know that the speed would be the ratio of the distance to the time that have been taken and that is how we would be able to solve the problem that we have in the case that is ahead of us in this question
We have that the speed is; Distance/Time
= 91 m/29s
= 3.1 m/s
At the same speed;
Time = Distance/Speed
= 5 m / 3.1 m/s
= 1.6 s
Hence we k now that the spaghetti would be able to take a time that is about 1.6 s
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Using the given data table, calculate the acceleration of the skateboarder. You can use either form of the
equation:
The acceleration of skateboard on road A will be 7.74 \(m/s^{2}\)
The acceleration of skateboard on road B will be 3.87 \(m/s^{2}\)
The acceleration of skateboard on road C will be 9.68 \(m/s^{2}\)
force = mass * acceleration
mass1 = 62 kg
force1 = 480 N
acceleration1 = force / mass
= 480 / 62 = 7.74 \(m/s^{2}\)
mass2 = 62 kg
force2 = 240 N
acceleration 2 = 240 / 62 = 3.87 \(m/s^{2}\)
mass 3 = 62 kg
force 3 = 600 N
acceleration 3 = 600 / 62 = 9.68 \(m/s^{2}\)
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need in hurry please
Effective sex education must engage _____ more than _____.
Answer:
pregnant
Explanation:
no interest at school
which object has a weight of about 22.5 n the book the rock the box the fish
Answer: The rock
Explanation:
what is renewable and non-renewable energy?
Renewable resources:
A renewable resource is one that can be used repeatedly and does not run out because it is naturally replaced.
Nonrenewable resource:
A nonrenewable resource is a natural substance that is not replenished with the speed at which it is consumed. It is a finite resource.
Thenks and pls mark me brainliestt :))
Answer:
Renewable energy includes solar, hydro, and wind energy. Non-renewable energy includes coal, gas, and oil.Explanation:
Renewable energy is useful energy that is collected from renewable resources, which are naturally replenished on a human timescale. A non-renewable resource is a natural resource that cannot be readily replaced by natural means at a pace quick enough to keep up with consumption.
a body of mass x is raised to a height of 2m above the ground what it's potential energy if the body is allowed to fall what is it's kinetic energy when half way down
Answer:
hey i dont know what it is
Explanation:
According to The Flash, The heroes top speed is Mach 3.3, or 2,500 miles per hour. How
long would it take for him to run around the planet? (circumference of the earth is
roughly 25,000 miles) *
Answer:
nearly 2 days or less hes fast but not that fast
Explanation:
but maybe he can run it in five minutes
. Dan drags a box across the floor. He uses 95 N of force and moves the box 12 m. How much work does he do? 0.13 J 1,140 J 7.9 J 107 J
Answer:
\(1140\:\mathrm{J}\)
Explanation:
Work is given by \(W=F\Delta x\), where \(F\) is force and \(\Delta x\) is displacement.
Plugging in given values, we get:
\(W=95\:\mathrm{N}\cdot12\:\mathrm{m}=\fbox{$1140\:\mathrm{J}$}\).
Why was miasma theory replaced?
An 8.0 Kg mass is placed at = 3 where should a 10 Kg mass be placed along the − so that the center of mass will be located ay = 4.5?
Answer:
Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.
Explanation:
To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:
x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)
Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.
Given:
m1 = 8 kg
x1 = 3 m
x_cm = unknown (to be found)
m2 = 10 kg
y_cm = 4.5 m
Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.
To solve for x2, we can rearrange the formula as follows:
x2 = (x_cm * (m1 + m2) - m1 * x1) / m2
Substituting the given values:
x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg
Simplifying:
x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg
Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:
4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)
Simplifying:
4.5 m = (24 kg + 10 kg * x2) / 18 kg
Multiplying both sides by 18 kg:
81 kg*m = 24 kg + 10 kg * x2
Subtracting 24 kg from both sides:
10 kg * x2 = 81 kg*m - 24 kg
Dividing both sides by 10 kg:
x2 = (81 kg*m - 24 kg) / 10 kg
Simplifying:
x2 = 8.1 m - 2.4 m
x2 = 5.7 m
(brainlest?) ples:(
Answer:
the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.
Explanation:
To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.
The center of mass of a system is given by the equation:
x_cm = (m1x1 + m2x2) / (m1 + m2),
where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.
Given:
m1 = 8 kg,
x1 = 3 m,
m2 = 10 kg,
y_cm = 4.5 m.
To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:
y_cm = (m1y1 + m2y2) / (m1 + m2),
where y1 and y2 are the positions along the y-axis.
Rearranging the equation and substituting the given values:
4.5 = (83 + 10y2) / (8 + 10).
Simplifying the equation:
4.5 = (24 + 10*y2) / 18.
Multiplying both sides by 18:
81 = 24 + 10*y2.
Rearranging the equation:
10*y2 = 81 - 24,
10*y2 = 57.
Dividing both sides by 10:
y2 = 5.7.
Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.
To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:
x_cm = (m1x1 + m2x2) / (m1 + m2).
Substituting the given values:
x_cm = (83 + 10x2) / (8 + 10).
Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:
0 = (83 + 10x2) / (8 + 10).
Rearranging the equation:
83 + 10x2 = 0.
24 + 10*x2 = 0.
10*x2 = -24.
Dividing both sides by 10:
x2 = -2.4.
An object that is spinning, but not orbiting anything, has zero angular momentum.
True
False
HELP!! ASAP I DONT KNOW HOW TO THIS
A piece of copper weighing 400g is heated to 100°c and quickly transferred to a copper calorimeter of mass 10g containing 100g of liquid of unknown specific heat capacity at 30°c. If the final temperature of the mixture is 50°c, calculate the specific heat capacity of the liquid. (S.H.C of copper is 390J/kg/k)
A piece of copper at 100°C is transferred to a copper calorimeter with a liquid at 30°C. The final temperature is 50°C. By applying the principle of conservation of energy, the specific heat capacity of the liquid is calculated to be approximately 2100 J/kg/°C.
To calculate the specific heat capacity of the liquid, we can apply the principle of conservation of energy. The heat lost by the copper piece will be equal to the heat gained by the liquid and calorimeter.
The heat lost by the copper piece can be calculated using the formula:
Heat lost = Mass of copper × Specific heat capacity of copper × Temperature change
Given:
Mass of copper = 400 g
Specific heat capacity of copper = 390 J/kg/°C (assuming it remains constant)
Temperature change of copper = 100°C - 50°C = 50°C
Heat lost = 400 g × 390 J/kg/°C × 50°C
Heat lost = 7,800,000 J
The heat gained by the liquid and calorimeter can be calculated using the formula:
Heat gained = (Mass of liquid + Mass of calorimeter) × Specific heat capacity of liquid × Temperature change
Given:
Mass of liquid = 100 g
Mass of calorimeter = 10 g
Temperature change of liquid = 50°C - 30°C = 20°C
Heat gained = (100 g + 10 g) × Specific heat capacity of liquid × 20°C
Now, by equating the heat lost and heat gained:
7,800,000 J = (110 g) × Specific heat capacity of liquid × 20°C
Specific heat capacity of liquid = 7,800,000 J / (110 g × 20°C)
Specific heat capacity of liquid ≈ 3545.45 J/kg/°C
Therefore, the specific heat capacity of the liquid is approximately 3545.45 J/kg/°C.
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a large mass m1=5.75 kg and is attached to a smaller mass m2=3.53 kg by a string. The string is hung over a pulley as shown in the figure, and the mass of the pulley and string are negligible compared to the other two masses. Mass 1 is started with an initial downward speed of 2.13 m/s. What is the speed of mass 2 after it has moved ℎ=2.47 meters?
The speed of the second mass after it has moved ℎ=2.47 meters will be 1.09 m/s approximately
What are we to consider in equilibrium ?Whenever the friction in the pulley is negligible, the two blocks will accelerate at the same magnitude. Also, the tension at both sides will be the same.
Given that a large mass m1=5.75 kg and is attached to a smaller mass m2=3.53 kg by a string and the mass of the pulley and string are negligible compared to the other two masses. Mass 1 is started with an initial downward speed of 2.13 m/s.
The acceleration at which they will both move will be;
a = (\(m_{1}\) - \(m_{2}\)) / (\(m_{1}\) + \(m_{2}\))
a = (5.75 - 3.53) / (5.75 + 3.53)
a = 2.22 / 9.28
a = 0.24 m/s²
Let us assume that the second mass starts from rest, and the distance covered is the h = 2.47 m
We can use third equation of motion to calculate the speed of mass 2 after it has moved ℎ=2.47 meters.
v² = u² + 2as
since u =0
v² = 2 × 0.24 × 2.47
v² = 1.1856
v = √1.19
v = 1.0888 m/s
Therefore, the speed of mass 2 after it has moved ℎ=2.47 meters will be 1.09 m/s approximately
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A wave that has smaller amplitude than another carries less _______
Answer:
A wave that has smaller amplitude than another carries less what
Waves that have smaller amplitude have less energy. the particles of the waves. rarefactions are far amplitude waves. Wavelength is the distance from one crest to the next crest or from one trough to the next trough.
Explanation:
a An object is tarown up with a velocity v = 6.02 +7.0j. Calculate the (1) time taken reach the maximum height (ii) the horizontal range (s = 10m/s2).
Answer:
(i) 0.6s (ii) 8.42m
Explanation:
U² = 6.02² + 7²
U = 9.23
angle of projection
tanø = 6.02/7
ø = 40.7
Time of fligt
t = Usinø/g
t = 9.23 sin 40.7/10
t = 0.6
H range = U²sin2ø/g
H = 9.23²sin 81.4/10
H = 8.42m
The time taken reach the maximum height is 0.6s and the horizontal range is 8.42m.
What is Velocity?Velocity is defined as the directional motion of an object which is indicated by the rate of change of position as observed from a particular frame of reference. It is measured by a particular standard of time. It is a vector quantity as it has both magnitude and direction.
It can be expressed as:
v= d/t
Where. v is the velocity in m/s
d is the displacement measured in meter 'm'
t is the time measured in seconds 's'
For above given information,
v = 6.02 +7.0j, so the initial velocity will be u
u² = 6.02² + 7²
u = 9.23m/s
Angle of projection, tanø = 6.02/7
ø = 40.7
Time taken= t = u sinø/g
t = 9.23 sin 40.7/10
t = 0.6s
Horizontal range = u²sin2ø/g
H = 9.23²sin 81.4/10
H = 8.42m
Thus, the time taken reach the maximum height is 0.6s and the horizontal range is 8.42m.
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Describe how you would use an uncalibrated force probe and the springs in Question 1 to develop a quantitative scale of force. How could you measure forces that do not correspond to exact numbers of stretched springs?fyi: Question 1 states you are given 10 identical springs. Describe how you would develop a scale of force using these springs.
Given 10 identical springs, we can use multiple springs in parallel to measure larger forces. We can attach the force probe to multiple springs and measure the amount of stretch.
To use the uncalibrated force probe and the springs in Question 1 to develop a quantitative scale of force, we can follow these steps:
1. Attach the uncalibrated force probe to one end of the spring and attach an object of known mass to the other end.
2. Record the length of the spring when it is at rest and when the object is attached. The difference between these two lengths will be the amount the spring is stretched by the weight of the object.
3. Repeat this process for different masses, recording the amount of stretch for each mass.
4. Plot the amount of stretch (in meters) versus the weight (in Newtons) for each mass. This will create a linear relationship between the amount of stretch and the weight.
5. Using this linear relationship, we can calibrate the force probe and develop a quantitative scale of force. We can now use the scale to measure the force applied to the probe by other objects by observing the amount of stretch in the spring.
If we encounter forces that do not correspond to exact numbers of stretched springs, we can estimate the force by interpolating between the values on the scale. For example, if a force stretches the spring to a length that is between the length for one and two stretched springs, we can estimate the force by interpolating between the force values for one and two springs.
Given 10 identical springs, we can use multiple springs in parallel to measure larger forces. We can attach the force probe to multiple springs and measure the amount of stretch for a given force. By combining the results from multiple springs, we can extend the range of forces we can measure with the setup
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a car, which has a mass of 2000kg traveled a distance of 200 meters in 5 seconds. After 20 seconds the car was raveling at a speed of 60 m/s what is the force of the car?
Answer:
Explanation:
vi = 200/5 = 40 m/s
a = (vf - vi)/t = (60 - 40)/20 = 1 m/s²
F = ma = 2000(1) = 2000 N
When a car is stopped, facing upwards on a hill, which way does friction act?
When a car is stopped, facing upwards on a hill, the friction acts in the opposite direction to the motion that the car would naturally take if it were not stopped.
In this case, the car would roll backwards down the hill due to the force of gravity. The friction between the tires and the road surface acts in the opposite direction to this motion, providing a force that opposes the car's tendency to roll backwards. Therefore, the friction acts in the forward direction, up the hill, to prevent the car from rolling backwards.
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If a marathon runner runs 9.5 miles in one direction, 8.89 miles in another direction, and 2.333 miles in a third direction, how much distance did the runner run?
We have that the total distance covered by the runner is
\(d_t=20.723miles\)
The total distance covered by the runner is a sum of all miles covered by the runner
Therefore
With
\(d_t\)=Total distance
\(d_t=d_1+d_2+d_3\\\\d_t=9.5+8.89+2.333\)
\(d_t=20.723miles\)
in conclusion
The total distance covered by the runner is
\(d_t=20.723miles\)
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2.- a person weighing 70 kg travels at 2m / s. What is the value of his kinetic energy?
Answer:18 watts
Explanation:i just got this question trust me
\
A horizontal spring with a constant of 3000 N/m is compressed 4.0 cm from equilibrium. A 2.0 kg mass is placed on front of the compressed spring and then is released. The object drags on a flat surface with a coefficient of friction equal to .23 and eventually comes to rest. How far from the spring does the mass travel?
Regarding a spring-mass system's duration, the square root of the mass and the spring constant have opposing correlations. The length of spring will be longer and vice versa as the mass grows. Therefore, the mass influences spring.
What far from the spring does the mass travel?They swing back and forth around a stationary point. Classic examples of this type of vibrating motion are a simple pendulum and a mass on a spring.
Therefore, The use of motion detectors demonstrates that the vibrations of these objects have a sinusoidal nature, even if this is not obvious from plain viewing.
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changes in energy causes matter to change phase. true or false
it's true because we'll engery and causes of matter work together I think