Observation
Aqueous
sodium hydroxide
was added dropwise and then in
excess.

In this closed rigid system, the partial pressure exerted by the neon gas is 1.6 atm.

To find the partial pressure exerted by the neon gas in a closed rigid system containing 7.0 mol CO₂, 7.0 mol Ar, 7.0 mol N₂, and 4.0 mol Ne, with a total pressure of 10.0 atm, we'll use Dalton's Law of Partial Pressures.

Step 1: Calculate the total number of moles of all gases present.
Total moles = moles of CO₂ + moles of Ar + moles of N₂ + moles of Ne
Total moles = 7.0 + 7.0 + 7.0 + 4.0
Total moles = 25.0 moles

Step 2: Determine the mole fraction of neon gas.
Mole fraction of Ne = moles of Ne / total moles
Mole fraction of Ne = 4.0 / 25.0
Mole fraction of Ne = 0.16

Step 3: Calculate the partial pressure of neon gas.
Partial pressure of Ne = mole fraction of Ne * total pressure
Partial pressure of Ne = 0.16 * 10.0 atm
Partial pressure of Ne = 1.6 atm

In this closed rigid system, the partial pressure exerted by the neon gas is 1.6 atm.

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The influence of two solvents, water and hexane, on the pKa of acetic acid can be explained as follows:


1. Water has a high dielectric constant, while hexane has a low dielectric constant. The dielectric constant of a solvent affects the strength of the electrostatic interaction between charged species. In water, the electrostatic interaction between the negatively charged carboxylic acid group and the proton is stronger, resulting in a lower pKa for acetic acid.

2. In hexane, which has a low dielectric constant, the electrostatic interaction between the carboxylic acid group and the proton is weaker. As a result, the pKa for acetic acid is higher in hexane compared to water.

In summary, the pKa of acetic acid is lower in water due to the stronger electrostatic interaction between the carboxylic acid group and the proton, which is influenced by the high dielectric constant of water. Conversely, the pKa is higher in hexane due to the weaker electrostatic interaction caused by the low dielectric constant of hexane.

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Answer:

chemical formula

Explanation:

This problem is providing us with a reaction between sodium hydroxide and copper (II) chloride, so the spectator ions are required. At the end, these turn out to be Na⁺ and Cl⁻.

In chemistry, a significantly great number of chemical reactions involve the exchange of ions for them to occur. Thus, one can have three versions of a chemical reaction; the complete equation, complete ionic equation and net ionic equation.

In such a way, to exemplify this, the complete equation for the given reaction is just:

\(2NaOH(aq) + CuCl_2(aq) \rightarrow 2NaCl(aq) + Cu(OH)_2 (s)\)

Which of course, must be balanced. Next, for the complete ionic equation, one must separate the aqueous species into ions:

\(2Na^+(aq)+2OH(aq) + Cu^{2+}(aq)+2Cl^-(aq) \rightarrow 2Na^+(aq)+Cl^-(aq) + Cu(OH)_2 (s)\)

Where the copper (II) hydroxide is clearly nonionizing as it remains as a precipitate (solid).

Finally, the net ionic equation omits the spectator ions, which are basically ions that appear on both reactants and products side, in this case both Na⁺ and Cl⁻:

\(2OH^-(aq) + Cu^{2+}(aq)\rightarrow Cu(OH)_2 (s)\)

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Answer:

Cannot be determined

Explanation:

Hi there,

Could you please add an attachment of the table? We cannot tell what the errors are if there is no table.

Answer: 0.000187 mg of iron is produced.

Explanation:

To calculate the moles :

\(\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}\)    

\(\text{Moles of} Mg=\frac{0.120g}{24g/mol}=0.005moles\)  

\(3Mg+2FeCl_2\rightarrow 2Fe+3MgCl_2\)

As \(FeCl_2\) is the excess reagent,  \(Mg\) is the limiting reagent.

According to stoichiometry :  

3 moles of \(Mg\) give = 2 moles of \(Fe\)

Thus 0.005 moles of \(Mg\) give =\(\frac{2}{3}\times 0.005=0.0033moles\)  of \(Fe\)

Mass of \(Fe=moles\times {\text {Molar mass}}=0.0033moles\times 56g/mol=0.187g=0.000187mg\)       (1g=1000mg)

Thus 0.000187 mg of iron is produced.

Answer:

Large leaves help plants to receive more sunlight when in tropical rainforests.

Answer:

D, adding a second plant to the test tube

Two chemical tests that could be used to distinguish between 2-pentanone and 3-pentanone are the iodoform test and the Tollens' test.

The iodoform test is used to detect the presence of a methyl ketone functional group, which both 2-pentanone and 3-pentanone possess. In the presence of iodine and a base such as sodium hydroxide, methyl ketones react to form a yellow precipitate of iodoform (CHI3).

However, 2-pentanone produces a stronger positive test result than 3-pentanone due to its more favorable position of the methyl group in the molecule.

The Tollens' test, on the other hand, is used to distinguish between aldehydes and ketones. Only aldehydes will react with Tollens' reagent (a solution of silver nitrate in ammonia) to produce a silver mirror on the inner surface of the reaction vessel.

Therefore, if the two compounds are treated with Tollens' reagent, only 2-pentanone will not produce a silver mirror, indicating that it is a ketone, while 3-pentanone will not react, indicating that it is not an aldehyde.

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Answer:

  3.0 g/mL

Explanation:

The volume is the difference in water levels:

  17.5 mL -15.0 mL = 2.5 mL

The density is the ratio of mass to volume:

  (7.50 g)/(2.5 mL) = 3.0 g/mL

__

Taking the difference of "large" numbers reduces the number of significant figures to 2, so that is the number the answer must use. All other numbers here have 3 significant digits.

Launching a projectile over a significant distance, such as several hundred miles, presents a range of complex challenges that must be carefully addressed. The success of achieving such a long range relies on accounting for various factors that influence the projectile's trajectory, including aerodynamics, atmospheric conditions, Earth's curvature, and external forces.

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Sorry this question is incomplete.

The effect on the rate of reaction for this SN1 process when doubling the concentration of t-butyl bromide is an increase by a factor of 2, while quadrupling the concentration of methanol will have no impact on the rate.

In the solvolysis of t-butyl bromide in methanol, t-butyl methyl ether is produced through an SN1 reaction. When discussing the rate of an SN1 reaction, it's important to note that it is a two-step process involving the formation of a carbocation intermediate. The rate-determining step (RDS) is the first step, which involves the ionization of t-butyl bromide to form a carbocation and a bromide ion.

The rate of an SN1 reaction is directly proportional to the concentration of the substrate (t-butyl bromide) and independent of the concentration of the nucleophile (methanol). Thus, doubling the concentration of t-butyl bromide will double the rate of reaction, as it increases the availability of the substrate for ionization.

On the other hand, quadrupling the concentration of methanol will not affect the rate of the reaction, as it is not involved in the RDS. Methanol reacts with the carbocation in the second step, which is a fast step and does not determine the overall rate.

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The source of hydrogen during the loss of the leaving group to form the free amine is water donates two protons during this phase of the reaction, option C.

Solar energy, or electromagnetic radiation, is produced in large quantities by the sun. Only a small portion of this energy, known as "visible light," is visible to humans. Waves may be used to explain and quantify how solar energy moves. The distance between two successive, comparable locations in a succession of waves, such as from crest to crest or trough to trough, is known as the wavelength and allows scientists to calculate the energy of a wave.

A certain range of wavelengths characterises each form of electromagnetic radiation. Less energy is carried when the wavelength is longer (or looks to be stretched out). The most energy is carried by short, tight waves. It might seem illogical at first, but picture a moving rope to help you understand. A person can move a rope in long, broad waves with little effort. One would have to use much more force to make a rope move in short, tight waves.

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Answer:

partial pressure of gas D Pd = 15.5 kPa

Explanation:

As per the Dalton's law of partial pressure, in a mixture, pressure exerted by each gas when summed gives the total partial pressure exerted by mixture.

P(Total) = P1+P2+P3.....

Given P(Total) = 35.7 kPa

Partial pressure of gas A Pa = 7.8 kPa

Partial pressure of gas B Pb = 3.7 kPa

Partial pressure of gas C Pc =  8.7 kPa

There, Partial pressure of gas D Pd = P(Total) -(Pa+Pb+Pc)

Pd = 35.7-(7.8+3.7+8.7) = 35.7-20.2 kPa = 15.5 kPa

Therefore, partial pressure of gas D Pd = 15.5 kPa

Answer:

The answer is B. sound; light

Explanation:

Answer:

1.92

Explanation:

Answer:

The physical property that best separates compounds into ionic or covalent is solubility in water.

Explanation:

This is sequel to the fact that Ionic compounds are generally highly soluble in water, while covalent compounds have low solubility in water. This is because ionic compounds are composed of charged ions that are attracted to the polar water molecules, resulting in the compound dissolving in water. On the other hand, covalent compounds are usually nonpolar or have weak polarity, which makes them less soluble in polar solvents like water.

And now the physical property that is least helpful in separating compounds into ionic or covalent is melting point or boiling point. This is because both ionic and covalent compounds can have high or low melting and boiling points, depending on their composition and bonding. For example, some covalent compounds like diamond have very high melting and boiling points, while some ionic compounds like sodium chloride have relatively low melting and boiling points.

Explanation:

To convert a temperature from degree Celsius to Kelvin add 273 to the value in degree Celsius

That's

K = 273 + °C

where

K is the temperature in Kelvin

°C is the temperature in degree Celsius

So we have

960.8° C = 273 + 960.8 = 1233.8 K

2212°C = 273 + 2212 = 2485 K

Hope this helps you

Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature. The temperature at which the vapour pressure at the surface of a liquid becomes equal to the pressure exerted by the surroundings is called the boiling point of the liquid.

The vapor pressure of a liquid is the point at which equilibrium pressure is reached, in a closed container, between molecules leaving the liquid and going into the gaseous phase and molecules leaving the gaseous phase and entering the liquid phase.

The most common unit for vapor pressure is the torr. 1 torr = 1 mm Hg (one millimeter of mercury). Most materials have very low vapor pressures.

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The strong bases are hydroxides of group 1 and 2 metals (ex. Sodium, Potassium) or larger group transition metals (Copper, Iron), or oxides of the same metals.

It follows from structure of strong bases that they are composed of highly electropositive metals of groups 1 and 2 and the hydroxide ion.

Additionally, transition metals may also form bases with the hydroxide ion or oxides of this transition metals.

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Answer:

iron, it is more dense than aluminum

Explanation:

Answer:

Aluminium

Explanation:

Explanation:

1. Count each type of atom in reactants and products. ...

2. Place coefficients, as needed, in front of the symbols or formulas to increase the number of atoms or molecules of the substances. ...

3. Repeat steps 1 and 2 until the equation is balanced.

To calculate the standard enthalpy change, ΔH°rxn, for the given reaction, we need to use the standard enthalpy of formation (ΔH°f) values of the involved compounds. By applying Hess's Law and using the given values, we can determine the enthalpy change for the reaction. The correct answer can be determined by summing up the products' enthalpies and subtracting the sum of the reactants' enthalpies. In this case, the correct answer is option [a], -62 kJ.

Hess's Law states that the enthalpy change of a reaction is independent of the pathway taken and depends only on the initial and final states. We can use this principle to calculate ΔH°rxn by considering the enthalpies of formation of the reactants and products involved.

To calculate ΔH°rxn, we need to sum up the enthalpies of formation of the products and subtract the sum of the enthalpies of formation of the reactants. According to the given data, the enthalpy of formation (ΔH°f) for SO2Cl2(g) is -564 kJ/mol, for H2O(l) is -158 kJ/mol, for HCl(g) is -84 kJ/mol, and for H2SO4(l) is -956 kJ/mol.

In the balanced chemical equation, the stoichiometric coefficients indicate the number of moles involved. Thus, we multiply the ΔH°f values by their respective coefficients. For the products, we have 2 HCl(g) and H2SO4(l), resulting in a sum of (-84 kJ/mol * 2) + (-956 kJ/mol) = -244 kJ/mol. For the reactants, we have SO2Cl2(g) and 2 H2O(l), giving us (-564 kJ/mol) + (2 * -158 kJ/mol) = -880 kJ/mol.

Finally, we subtract the sum of the reactants' enthalpies from the sum of the products' enthalpies: (-244 kJ/mol) - (-880 kJ/mol) = 636 kJ/mol. However, the question asks for ΔH°rxn, which represents the enthalpy change per mole of reaction. Therefore, we divide the result by the stoichiometric coefficient of the reaction, which is 1, resulting in ΔH°rxn = 636 kJ/mol / 1 = 636 kJ/mol.

Among the given answer choices, the closest value to 636 kJ/mol is option [a], -62 kJ, which is the correct answer.

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at the given temperature, HI will decompose into H2 and I2.

Given that the following reaction has an equilibrium constant value of

K = 46 at 783K: H2 (g) + l2 (g) = HI (g).

Initial pressures were given to be 55kPa for both hydrogen and iodine and 78kPa for hydrogen iodide which is at equilibrium. In this problem, Qp is the reaction quotient for pressures at the given instant. Qp has the same expression as Kp, but with initial pressures instead of equilibrium pressures.

Qp = p(HI) / [p(H2) . p(I2)] = 78 / [55 . 55] = 0.0241

K is the equilibrium constant and Q is the reaction quotient.Q is less than K. This implies that the reaction quotient will increase to match the equilibrium constant.

As a result, the reaction will shift forward to produce more HI. Thus, at the given temperature, HI will decompose into H2 and I2.

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Answer:

liquid water

Explanation:

becouse liquid water is 30C

Answer:

one: b

two: b

three: a

four: b

Explanation:

In cake, the ingredients have been changed to the baked cake, so the order of putting the ingredients has no effect on the mass of matter. Thus, option A is correct.

The baking of cake has been corresponds with the addition of the ingredients, thereby process mixing in order to create the reactant mixture that has been heated at the specific temperature for a specified time period. The resultant has been the baked cake matter.

The reagents and products all are matter, and baking has been the chemical reaction. According to the law of conservation of mass, matter cannot be created nor be destroyed in a chemical reaction; it can be changed from one form to another.

In cake, the ingredients have been changed to the baked cake, so the order of putting the ingredients has no effect on the mass of matter. Thus, option A is correct.

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