object a and object b are at equal distances on opposite sides of object c. object b has three times the mass of object c. objects a and b have equal mass. what is the ratio of the gravitational force between objects a and b to the gravitational force between objects b and c? (1 point)

Answer:

convex write convex only don't write convex lens

Explanation:

Answer:

If the newly formed metamorphic rock continues to heat, it can eventually melt and become molten (magma). When the molten rock cools it forms an igneous rock.

Explanation:

The half-life of the given element is approximately 25.33 years.

In the decay function, a(t) = a * e^(-0.0274t), the parameter λ = 0.0274 is the decay constant of the radioactive element  The half-life of the element is the amount of time it takes for half of the initial amount of the element to decay. We can determine the half-life by setting a(t) = 0.5a in the decay function and solving for t.

This gives us t = ln(2) / λ.

Substituting the value of λ into this equation, we get t = ln(2) / 0.0274 ≈ 25.33 years. Therefore, the half-life of the radioactive element is approximately 25.33 years.

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Answer:

False

Explanation:

:)

Answer:

The answer is false

Explanation:

The clouds have nothing to do with the changes in the phases of the moon but, rather the postioning of the sun and the moon regarding revolution and the spinning of the earth on it axis.

I hope this helps you good luck and have a good day.

The differential equation for the height h of water in the tank is: dh/dt = -3sqrt(2gh)/20.

Friction can be defined as the force resisting relative motion of solid surfaces, fluid layers and material elements sliding against each other.

d(mass of water)/dt = -ρ * Ah * v

ρ is density of water, Ah is area of the hole, and v is velocity of water flowing out of hole.

v = c * Ah * sqrt(2gh)

c is an empirical constant between 0 and 1, g is acceleration due to gravity, and h is height of water in tank above hole. Therefore, differential equation for height h of water in the tank can be written as:

d(mass of water)/dt = -ρ * Ah * c * Ah * √(2gh)

d(mass of water)/dt = -ρ * c * Ah² * √(2gh)

d( ρ * V)/dt = - ρ* c * Ah² * √(2gh)

d( ρ * Ah^2 * h)/dt = -ρ * c * Ah² * √(2gh)

dh/dt = -(c/2) * √(2gh)

dh/dt = -3√(2gh)/20

Therefore, differential equation for height h of water in tank is:

dh/dt = -3√(2gh)/20

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Answer:

A. Benthos. B. Nekton

Explanation:

Benthos refers to organisms living on the bottom or associated with substrata.

Nekton or necton refers to the actively swimming aquatic organisms in a body of water.

If this film looks green (constructively reflecting 520 nm light) when irradiated perpendicularly by white light, its third-smallest non-zero thickness is 586.46 nm.

The minimal thickness (t) of a thin film that reflects maximum light of a given wavelength is t = m/(2n), where is the wavelength of light in vacuum, n is the medium's refractive index, and m is an integer.

Given that the film is soapy water with a refractive index n = 1.33 and that the light reflected is green in both situations, we must calculate the minimal film thicknesses that will result in constructive interference when irradiated perpendicularly by white light.

First case:

The green light has wavelength λ = 520 nm.

For m = 1,

we have:t = mλ/(2n) = 1 × 520 nm/(2 × 1.33) ≈ 195.49 nm (minimum thickness).

For m = 2,

we have:t = mλ/(2n) = 2 × 520 nm/(2 × 1.33) ≈ 390.98 nm (second smallest non-zero thickness).

For m = 3,

we have:t = mλ/(2n) = 3 × 520 nm/(2 × 1.33) ≈ 586.46 nm (third smallest non-zero thickness).

Therefore, the third smallest non-zero thickness, in nanometers, of this film if it appears green (constructively reflecting 520 nm light) when illuminated perpendicularly by white light is approximately 586.46 nm.

This film appears green (constructively reflecting 570 nm light) when irradiated perpendicularly by white light. The third smallest non-zero thickness is 639.78 nm.

Second case:

The green light has wavelength λ = 570 nm.

For m = 1,

we have:t = mλ/(2n) = 1 × 570 nm/(2 × 1.33) ≈ 213.26 nm (minimum thickness).

For m = 2,

we have:t = mλ/(2n) = 2 × 570 nm/(2 × 1.33) ≈ 426.52 nm (second smallest non-zero thickness).

For m = 3,

we have:t = mλ/(2n) = 3 × 570 nm/(2 × 1.33) ≈ 639.78 nm (third smallest non-zero thickness).

Therefore, the third smallest non-zero thickness, in nanometers, of this film if it appears green (constructively reflecting 570 nm light) when illuminated perpendicularly by white light is approximately 639.78 nm.

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Newton's optics experiment observation and intervention. In order to make his observations, Newton used the theory of light passing through prisms and the rays that were sent by them. It was revealed that light has a variety of properties and features.

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I added an image of the answers/ Hope this helps! good luck on it.

When the electron is 10 cm away from the 3.3 nc charge, its speed is 5.34 × 10⁷ m/s.

To solve this problem, we can use the principle of conservation of energy. We can assume that the electron starts with zero kinetic energy and potential energy equal to the electric potential energy due to the two charges. As the electron moves towards the 3.3 nc charge, it gains kinetic energy and loses potential energy. We can use the law of conservation of energy to find the speed of the electron at the point where it is 10 cm from the 3.3 nc charge.

The electric potential energy of a point charge q at a distance r from another point charge Q is given by:

⇒ U = k × Q × q / r

where k is the Coulomb constant, Q and q are the magnitudes of the charges, and r is the distance between them.

The initial potential energy of the electron is:

⇒ U_i = k × (3.3 nc) × (1.6 nc) / (0.31 m / 2)

⇒ U_i = 1.71 × 10⁻¹⁸ J

When the electron is 10 cm from the 3.3 nc charge, its distance from the 1.6 nc charge is 21 cm. The electric potential energy of the electron at this point is:

⇒ U_f = k × (3.3 nc) × (-1.6 nc) / (0.21 m)

⇒ U_f = -3.41 × 10⁻¹⁸ J

The change in potential energy of the electron is:

⇒ ΔU = U_f - U_i

⇒ ΔU = -5.12 × 10⁻¹⁸ J

By conservation of energy, the change in potential energy must be equal to the kinetic energy of the electron:

⇒ ΔU = (1/2) m v²

where m is the mass of the electron and v is its speed.

Substituting the given values, we get:

⇒ (1/2) m v² = -5.12 × 10⁻¹⁸ J

Solving for v, we get:

⇒ v = √(-2 ΔU / m)

⇒ v = √(2 * 5.12 × 10⁻¹⁸ J / (9.11 × 10⁻³¹ kg))

⇒ v = 5.34 × 10⁷ m/s

Therefore, the speed of the electron when it is 10 cm from the 3.3 nc charge is 5.34 × 10⁷ m/s.

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The value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

When an object collides with another object, they exchange energy. For example, a baseball and bat collision or a car collision. When two objects collide, the force of the collision has to be equal on both sides of the collision according to Newton's Third Law. So, to find the value of force, we will apply the equation:

F = ΔP / ΔT

where F is the force, ΔP is the change in momentum, and ΔT is the time of collision. The equation represents the impulse momentum theorem.

Now, let's apply the given values to the above equation.

Final momentum (p2) = mass × final velocity (v2)

p2 = 0.15 kg × (-50 m/s)

p2 = -7.5 kg.m/s

Initial momentum (p1) = mass × initial velocity (v1)

p1 = 0.15 kg × (40 m/s)

p1 = 6 kg.m/s

Change in momentum (ΔP) = p2 - p1

ΔP = -7.5 kg.m/s - 6 kg.m/s

ΔP = -13.5 kg.m/s

Time of collision (ΔT) = 8.0 × 10³ s

Now, putting the values of ΔP and ΔT in the equation of impulse momentum theorem, we get:

F = ΔP / ΔT

F = -13.5 kg.m/s ÷ 8.0 × 10³ s

F = -1.7 × 10⁻³ N

Thus, the value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

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Answer: Convection

Explanation:  convection is the most present process in the refrigeration equipment you may deal with. It occurs mainly in the fluids

Given,

The air resistance on the object, f=250 N

The gravitational force, F=500 N

The gravitational force pulls an object downwards, towards the center of the earth. Air resistance is the resistive force that opposes the downward motion of the object.

As the downward gravitational force is greater than the upward resistive force, the net force will be directed downward.

Thus, the net vertical force on the object is given by,

On substituting the known values,

Therefore, the net force on the object is 250 N downward.

Answer:

I would say 3N

Explanation:

Answer:

The first one is 12N and the second one is -22 m/s2

Explanation:

I'm pretty sure these are correct, i just finished that unit in school. I hope this helps:) Have a great day, God bless!

The final angular velocity of the wheels after the car has accelerated for 10 seconds is 58 rad/s.

Velocity is the speed of an object in a given direction. It is a vector quantity, which means that it has both a magnitude and a direction. The magnitude of velocity is equal to the rate of change of an object’s position. Velocity is usually measured in metres per second (m/s). In physics, velocity is usually expressed in terms of the direction of motion, such as towards the east, or away from the west. When an object’s velocity is constant, its motion is said to be uniform motion. When an object’s velocity changes, its motion is said to be non-uniform motion.

This is calculated by using the equation for angular velocity, which is ω = ω_0 + αt, where ω_0 is the initial angular velocity, α is the angular acceleration, and t is the time. In this case, ω_0 = 50 rad/s, α = 0.8 rad/s^2, and t = 10 s, so ω = 50 + (0.8)(10) = 58 rad/s.

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\(\boxed{\sf K.E=\dfrac{1}{2}mv^2}\)

\(\\ \sf\longmapsto 18750=\dfrac{1}{2}2100v^2\)

\(\\ \sf\longmapsto 18750=1050v^2\)

\(\\ \sf\longmapsto v^2=\dfrac{18750}{1050}\)

\(\\ \sf\longmapsto v^2=17.85m^2\)

\(\\ \sf\longmapsto v=\sqrt{17.85}\)

\(\\ \sf\longmapsto v=4.1m/s\)

To get a grandfather clock running more accurately, if it is gaining time, you should adjust the length of the pendulum.

How to adjust the length of the pendulum?

This can typically be done by moving the pendulum bob up or down the pendulum rod. A shorter pendulum will cause the clock to run faster, while a longer pendulum will cause it to run slower.

It is important to make small adjustments and wait for the clock to stabilize before making further adjustments. It's also recommended to consult the clock's manual for instructions on how to adjust the pendulum length.

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The term for waves that are caused by seismic activity is seismic waves.

Seismic waves are waves of energy that travel through the Earth's layers in response to seismic activity. Seismic activity refers to any activity that causes the ground to vibrate, such as earthquakes, volcanic eruptions, and human-made explosions.

Seismic waves are waves of energy that travel through the Earth's layers, including the crust, mantle, and core. Seismic waves are classified into two main types: body waves and surface waves.

Seismic waves can be detected and measured using specialized equipment such as seismometers. Seismometers are instruments that measure the motion of the ground and can detect even small vibrations caused by seismic waves.

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The induced emf opposing the current is approximately -3.84 V for the 8.00 A current through a 4.00 mH inductor is switched off in 8.33 ms.

To find the induced emf in the inductor, we can use the formula:
emf = -L * (ΔI/Δt)
where:
emf = induced electromotive force (in volts)
L = inductance of the inductor (in Henrys)
ΔI = change in current (in amperes)
Δt = time taken for the current to change (in seconds)
Given the information in your question:
L = 4.00 mH = 4.00 * \(10^{-3}\) H (converting millihenry to henry)
ΔI = 8.00 A (since the current is switched off, the change is equal to the initial current)
Δt = 8.33 ms = 8.33 * \(10^{-3}\) s (converting milliseconds to seconds)
Now, we can plug these values into the formula:
emf = - (4.00 * \(10^{-3}\) H) * (8.00 A) / (8.33 * \(10^{-3}\) s)
emf = - (32 * 10^-3) / (8.33 * \(10^{-3}\))
emf ≈ -3.84 V
The induced emf opposing the current is approximately -3.84 V. The negative sign indicates that the induced emf opposes the change in current, as expected.

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The EMF induced in the inductor opposing the change in current is approximately 3.84 V.

To find the EMF induced in the inductor, we'll need to use the formula for the induced EMF in an inductor, which is:

EMF = -L × (ΔI / Δt)

Here, EMF is the induced electromotive force, L is the inductance, ΔI is the change in current, and Δt is the time interval during which the current changes.

Given the information in your question, we have:

\(L = 4.00 mH = 0.004 H\) (converting millihenries to henries)
\(ΔI = 8.00 A\) (the current goes from 8 A to 0 A)
\(Δt = 8.33 ms = 0.00833 s\) (converting milliseconds to seconds)

Now, plug the values into the formula:

EMF =\(-0.004 H × (8.00 A / 0.00833 s)\)

EMF = \(-3.8408 V\)

Since we're looking for the magnitude of the induced EMF, we can ignore the negative sign:

EMF = 3.8408 V

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Answer:

its false

Explanation:

If a sinusoidal, transverse wave is produced on a stretched spring, each section of the spring moves perpendicular to the direction of propagation of the wave, in simple harmonic motion with an amplitude. The period of the wave and the period of each section's motion is the same. Yes, the answer will still be the same if the amplitude of the transverse wave were doubled but the period stays the same.

The amplitude of a wave represents the maximum displacement of the wave from its equilibrium position. The amplitude of a wave has no effect on the period of the wave. Therefore, if the amplitude of the transverse wave were doubled but the period remains the same, each section of the spring would still oscillate with a period similar to that of the wave in the original condition.

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Answer:

Scientific laws are facts that describe observed reoccurring natural events.

Explanation:

Scientific laws are explanations for the behavior of the natural world. Scientific theories are explanations for scientific laws.

Answer:

A balance and a beaker of water!

Explanation:

Krishne wants to measure the mass and volume of a key. The tools that are to be used are – a balance and a beaker of water.

Mass will be represent with the amount of matter that is in an object. This will be measured in terms of kilogram. The mass can easily be measured with balance.

Volume is the quantity of matter that is in the object. This is measured in terms of cubic meter. If you drop the key in a beaker of water, the water inside the beaker will increase and this increases the volume of water that will be equal to volume of key.

The length of a simple pendulum is 0.760 m, the pendulum bob has a mass of 365 grams, and it is released at an angle of 12.0 degree to the vertical. The frequency of vibration is approximately 0.364 Hz. The speed of the pendulum bob at the lowest point is not directly provided in the given information, but the total energy stored in the oscillation is approximately 0.394 J.

To determine the frequency of vibration, speed at the lowest point, and total energy stored in the oscillation of the pendulum, we can use the given information and formulas related to pendulum motion.

Given:

Length of the pendulum (L) = 0.760 m

Mass of the pendulum bob (m) = 365 grams = 0.365 kg

Angle to the vertical (θ) = 12.0 degrees

   Frequency of Vibration:

   The frequency of vibration (f) of a simple pendulum can be calculated using the formula:

f = 1 / T

where T is the period of oscillation. The period can be determined using the formula:

T = 2π√(L/g)

where g is the acceleration due to gravity (approximately 9.8 m/s^2).

Plugging in the values:

T = 2π√(0.760 m / 9.8 m/s^2)

T ≈ 2.746 seconds

Now, calculating the frequency:

f = 1 / 2.746 seconds

f ≈ 0.364 Hz

Therefore, the frequency of vibration is approximately 0.364 Hz.

   Speed at the Lowest Point:

   The speed (v) of the pendulum bob at the lowest point of its swing can be determined using the conservation of mechanical energy. At the lowest point, all of the potential energy is converted into kinetic energy.

The potential energy at the highest point (when the pendulum is released) is given by:

PE = mgh

where h is the vertical distance from the highest point to the lowest point.

Since the pendulum bob is released at an angle of 12.0 degrees to the vertical, the vertical distance is h = L(1 - cos θ), where θ is the angle.

Plugging in the values:

h = 0.760 m(1 - cos 12.0 degrees)

h ≈ 0.056 m

PE = (0.365 kg)(9.8 m/s^2)(0.056 m)

PE ≈ 0.197 J

The kinetic energy (KE) at the lowest point is equal to the potential energy:

KE = 0.197 J

The total mechanical energy (E) is the sum of potential and kinetic energy:

E = PE + KE

E = 0.197 J + 0.197 J

E ≈ 0.394 J

Therefore, the speed of the pendulum bob at the lowest point is not directly provided in the given information, but the total energy stored in the oscillation is approximately 0.394 J.

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The densities of the copper cylinder and the copper wire do not agree with each other. They are different, indicating that the two objects have different densities.

To compare the densities of a copper cylinder and a copper wire, we need to calculate the densities of both objects and then compare the results.

The density of a material is defined as its mass per unit volume. Mathematically, it is expressed as:

Density = Mass / Volume

To calculate the density, we need the mass and volume of each object.

Let's assume we have the following data:

1. Copper Cylinder:

  - Mass of the copper cylinder = 100 grams

  - Volume of the copper cylinder = 50 cm³

2. Copper Wire:

  - Mass of the copper wire = 75 grams

  - Volume of the copper wire = 25 cm³

Now, let's calculate the densities of the copper cylinder and the copper wire.

Density of Copper Cylinder = Mass of Copper Cylinder / Volume of Copper Cylinder

                         = 100 grams / 50 cm³

                         = 2 grams/cm³

Density of Copper Wire = Mass of Copper Wire / Volume of Copper Wire

                     = 75 grams / 25 cm³

                     = 3 grams/cm³

From the calculations, we can see that the density of the copper cylinder is 2 grams/cm³, while the density of the copper wire is 3 grams/cm³.

Therefore, the densities of the copper cylinder and the copper wire do not agree with each other. They are different, indicating that the two objects have different densities.

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The maximum temperature allowed for silicon is 383 degree Celsius.

The intrinsic carrier concentration, ni, in silicon can be determined using the following equation:

ni^2 = Nc * Nv * exp(-Eg/kT)

Rearranging the equation as follows:

T = Eg / (2 * k * ln(ni^2 / Nc / Nv))

The values of Nc and Nv can be calculated using the following equations:

Nc = 2 * [(2πmkT/h^2)^(3/2)]

Nv = 2 * [(2πmkT/h^2)^(3/2)] * exp(-Eg/kT)

Using typical values for the effective masses of electrons and holes in silicon (m_e = 0.26 m_0, m_h = 0.36 m_0, where m_0 is the rest mass of an electron), we can calculate Nc and Nv as:

Nc = 2.81 x 10^19 cm^-3

Nv = 1.83 x 10^19 cm^-3

Substituting these values into the equation for T, we get:

T = (1.12 eV) / [2 * (1.38 x 10^-23 J/K) * ln((1 x 10^12 cm^-3)^2 / (2.81 x 10^19 cm^-3) * (1.83 x 10^19 cm^-3))]

T = 656 K or 383 °C

Therefore, the maximum temperature allowed for silicon with an intrinsic carrier concentration no greater than 1x10^12 cm^-3 is approximately 656 Kelvin or 383 degrees Celsius.

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As the moon phase approaches full we say the Moon has now completed one half of the lunar month.

This is defined as the time it takes the Moon to pass through all of the phases.

When the moon approaches full then itn has completed one half of the lunar month which is the time taken to form a new moon.

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The speed of man when the length of his shadow on the building decreases when he is 4 m from the building will be 0.6 m/sec.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

Distance from spot shines =  12 m away

Height of man,h=2 m tall

Speed of man +1.6 m/s,

Distance from the building = 4 m

Let the height of shadow= y,

CD=x

Height of man=2 m

Speed of man:

\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)

As the triangle ABD and ECD are similar. The property of the similarity is found as;

\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24\)

Differentiate the above question with respect to x;

\(\rm x \frac{dy}{dt}+y\frac{dx}{dt}=0 \\\\ x\frac{dy}{dt}= -y\frac{dx}{dt}\)

From the given conditions the man is 4 m from  the building the value of the remaining distance x is;

x=12-4

x=8 m

Speed of man:

\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)

On putting all the values we get;

\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24 \\\\ 8y = 24 \\\\ y= 3\)

The speed of man when the  length of his shadow on the building decreases when he is 4 m from the building;

\(\rm \frac{dy}{dt} = - \frac{3}{8} \times 1.6 \ m/sec \\\\\ \frac{dy}{dt} = 0.6 \ m/sec.\)

Hence the value of the speed for the given conditions willl be 0.6 m/sec.

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The answers are- (a) 2 soft drinks. (b) Uncertain. (c) Not necessarily.

(d) No bliss point. and, (e) Steeper indifference curves.

(a) If Elmo has 4 quarters and 2 dimes in his pockets, he can buy 2 soft drinks. Since each soft drink requires two quarters and a dime, having double the amount of each coin allows him to make two purchases.

(b) Elmo's preferences between dimes and quarters may or may not be convex. Convex preferences imply that as Elmo increases the quantity of one type of money (quarters or dimes), the marginal utility he derives from each additional unit of that money diminishes. If Elmo's preference for soft drinks is based solely on the ability to purchase them and not on any diminishing marginal utility of the coins themselves, then his preferences may not exhibit convexity.

(c) Elmo does not necessarily always prefer more of both kinds of money to less. Given the specific context of the Coke machine, Elmo's only concern is to have the exact change required to obtain a soft drink. As long as he has the necessary combination of two quarters and a dime, having additional coins does not increase his utility further.

(d) Elmo does not have a bliss point in this scenario. A bliss point refers to the combination of goods or factors that maximizes an individual's utility or satisfaction. Since Elmo's sole objective is to purchase soft drinks from the Coke machine, his utility is maximized when he has the exact change required (two quarters and a dime). Having more coins does not enhance his utility beyond being able to buy a single soft drink.

(e) If Elmo had arrived at the Coke machine on a Saturday, with the drugstore across the street open, his preferences would change. Instead of being limited to the specific combination of two quarters and a dime, he could now use any combination of quarters and dimes to purchase as much Coke as he wants at a price of 4 cents per ounce.

In this case, Elmo's indifference curves between quarters and dimes would exhibit a downward slope, indicating that he is willing to trade off some quantity of one coin for a corresponding increase in the other, while still maintaining the same level of utility. The indifference curves would be steeper than the ones in the previous scenario, as Elmo can now acquire more soft drinks by having a larger combination of quarters and dimes.

These new indifference curves reflect Elmo's preference for more quarters and dimes, as they enable him to buy more Coke at the drugstore. The curves demonstrate that Elmo is willing to sacrifice some quantity of quarters to obtain additional dimes or vice versa, as long as the overall combination allows him to maximize the quantity of Coke he can purchase.

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