Nikolas had an idea that he could use the compressed carbon dioxide in a fire extinguisher to propel him on his skateboard. Nikolas, the fire extinguisher, and the skateboard have a combined mass of 50 kg. What force would the fire extinguisher have to produce to propel nikolas if he wanted to accelerate at a rate of 1. 2 m/s^2?.

When borosilicate glass is undergoing change in temperature, heat is transferred.  The specific heat of borosilicate glass is 837.4 J/kg. °C

The specific heat is the amount of heat stored per kilogram of substance by 1 degree rise in temperature.

Given is the mass of borosilicate glass m =100 g =0.1 kg, heat transferred Q = 309J, temperature change ΔT = 3.69°C

Q = m x Cp x  ΔT

309 = 0.1 x Cp x 3.69

Cp = 837.4 J/kg. °C

Thus, the specific heat of borosilicate glass is 837.4 J/kg. °C

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The velocity of water at the smaller cross-section is 25 m/s.

Area of larger cross section, A₁ = 100 cm²

Area of larger cross section, A₂ = 5 cm²

Velocity of water at larger section, v₁ = 1.25 m/s

According to equation of continuity,

A₁v₁ = A₂v₂

Therefore, the velocity of water at the smaller cross-section,

v₂ = A₁v₁/A₂

v₂ = 100 x 1.25/5

v₂ = 25 m/s

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Answer:

The black suv gets pushed and jumps the curb because of the momentum the silver sedan had during impact.

Explanation:

Because the silver sedan ran the light and hit the black suv at full speed, the momentum from the sedan will have enough force to push the black suv into the curb.

Answer:

it is the protons

Explanation:

the protons is positively charged and the number can tell you the element in the periodic table

Answer:

Hope this helps

Explanation:

The fundamental reason for having a refrigerator is to keep food cold. Cold temperatures help food stay fresh longer. The basic idea behind refrigeration is to slow down the activity of bacteria which all food containsso that it takes longer for the bacteria to spoil the food.

The second thinnest coating of magnesium fluoride for a lens system primarily used for 695 nm red light is approximately 503 nm.

Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire.

To determine the second thinnest coating of magnesium fluoride for a lens system primarily used for 695 nm red light, we will use the formula for thin film interference:

t = (mλ) / (2n)
where t is the thickness of the coating, m is the order of interference (1 for the thinnest coating, 2 for the second thinnest, etc.), λ is the wavelength of light (695 nm), and n is the index of refraction of MgF₂.

For the second thinnest coating (m=2), we can calculate the thickness:
t = (2 * 695 nm) / (2 * 1.38) ≈ 503 nm

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Answer:

The larger the amplitude of the waves, the louder the sound. Pitch (frequency) – shown by the spacing of the waves displayed. The closer together the waves are, the higher the pitch of the sound.

Explanation:

Answer:

Explanation:idek

The net force acting on the body will be 250 N since there is significant friction also. Thus, the acceleration of the 50 Kg body is 5 m/s².

Friction is a kind of force acting on a body to resist it from motion. Thus, frictional force will always be negative. The frictional force acting on a body is the the product of the coefficient of friction and the normal force.

Here the normal force = 1250 N

coefficient of friction = 1.2

Frictional force = 1250 N × 1.2 = 1500 N

Net force = 1500 N - 1250 N = 250 N

Acceleration = net force/ mass

                     = 250 N/50 Kg

                     = 5 m/s²

Therefore, the acceleration of the body from rest is 5 m/s².

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Scientific models area unit accustomed make a case for and predict the behaviour of real objects or systems.

A system of ideas, events, or processes is described physically, mathematically, conceptually, or conceptually in an exceedingly scientific model. By victimisation their scientific experience to produce explanations that create it doable to forecast the patterns, scientists work to recognise and comprehend the patterns that exist in the environment.

Scientific model illustrations include:

a simulation of the sun, moon, and earth's motions (which you participated in last year) a way for statement eclipses. The weather will be foretold victimisation models that describe weather events.

Models will assist you in mentally imagining one thing that's difficult to ascertain or comprehend. Models will aid in scientific prediction, understanding of processes, and communication of ideas.

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The energy of the high energy neutron is 940.51 MeV.

Speed is nothing but the distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity with the SI unit meter/second.

We know that mass of the neutron m₀ = 939.6 MeV/c²

A high energy neutron is travelling at a speed of 18 million m/s.

Given that, v = 1.8 * 10⁷ m/s

The energy of neutron is calculated with the formula, m₀* c²/√(1 - v²/c²)

⇒ 939.6 * (3* 10⁸)²/√[1 - (1.8 * 10⁷)²/(3* 10⁸)²]

⇒ 940.51 MeV

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Answer:

I need help with the same question

Explanation:

The variables for the given parcel with a temperature of 30°C and a dewpoint of 20°C at 1000mb are as follows:

i. Actual vapor pressure (e)

ii. Saturation vapor pressure (es)

iii. Actual mixing ratio (r)

iv. Saturation mixing ratio (r5)

v. Total water mixing ratio (rT)

vi. Available supersaturation (SA)

vii. Excess water mixing ratio (rF)

To calculate the variables, we can use the following equations and physical relations:

i. Actual vapor pressure (e):

We can use the Clausius-Clapeyron equation to calculate the actual vapor pressure:

e = es(T) * (rh/100)

where es(T) is the saturation vapor pressure at temperature T, and rh is the relative humidity.

ii. Saturation vapor pressure (es):

We can use the Arden Buck equation to calculate the saturation vapor pressure:

es = 6.112 * exp((17.67 * T)/(T + 243.5))

where T is the temperature in °C.

iii. Actual mixing ratio (r):

The actual mixing ratio can be calculated using the following equation:

r = (0.622 * e)/(p - e)

where e is the actual vapor pressure and p is the atmospheric pressure.

iv. Saturation mixing ratio (r5):

The saturation mixing ratio can be calculated using the following equation:

r5 = (0.622 * es)/(p - es)

v. Total water mixing ratio (rT):

The total water mixing ratio can be calculated by summing the actual mixing ratio and the excess water mixing ratio:

rT = r + rF

vi. Available supersaturation (SA):

The available supersaturation can be calculated using the following equation:

SA = (rT - r5)/r5 * 100

vii. Excess water mixing ratio (rF):

The excess water mixing ratio can be calculated by subtracting the saturation mixing ratio from the actual mixing ratio:

rF = r - r5

By using these equations and the given starting conditions, we can calculate the values of the variables mentioned above.

The calculations for the variables mentioned involve utilizing several equations and physical relations related to atmospheric thermodynamics. These equations are derived from fundamental principles and empirical relationships that describe the behavior of water vapor in the atmosphere. By applying these equations to the given conditions, we can determine values such as actual vapor pressure, saturation vapor pressure, actual mixing ratio, saturation mixing ratio, total water mixing ratio, available supersaturation, and excess water mixing ratio. These variables provide valuable information about the moisture content and saturation levels of the parcel of air being analyzed. Each equation serves a specific purpose in quantifying these properties and allows for a comprehensive understanding of the thermodynamic state of the parcel.

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Answer:

Kepler made extensive measurements and created a mathematical model of the movement of the planets around the sun, these analyzes are written in the form of three laws

Explanation:

Answer:

Earth is not the center

Explanation:

Answer:

39.2m/s

Explanation:

gravitational force= 9.8m/s

9.8x4.0=39.2m/s

The differential of the process X(t)Y(t) is:  d(X(t)Y(t)) = tY(t)dW(t) + 2tW(t)dY(t).

To find the differential of the process X(t)Y(t), we can use Itô's Lemma. Let's start by applying Itô's Lemma to the product X(t)Y(t).

Let Z(t) = X(t)Y(t).

By Ito's Lemma, we have:

dZ(t) = (∂Z/∂t)dt + (∂Z/∂X)dX(t) + (∂Z/∂Y)dY(t) + (1/2)(∂²Z/∂X²)d[X(t)]² + (∂²Z/∂X∂Y)dX(t)dY(t) + (1/2)(∂²Z/∂Y²)d[Y(t)]².

Now let's calculate each partial derivative term by term:

(∂Z/∂t) = 0

(∂Z/∂X) = Y(t)

(∂Z/∂Y) = X(t)

(∂²Z/∂X²) = 0

(∂²Z/∂X∂Y) = (∂Z/∂Y) = X(t)

(∂²Z/∂Y²) = 0

Now we substitute these derivatives back into the expression for dZ(t):

dZ(t) = (∂Z/∂t)dt + (∂Z/∂X)dX(t) + (∂Z/∂Y)dY(t) + (1/2)(∂²Z/∂X²)d[X(t)]² + (∂²Z/∂X∂Y)dX(t)dY(t) + (1/2)(∂²Z/∂Y²)d[Y(t)]²

= 0 + Y(t)dX(t) + X(t)dY(t) + 0 + X(t)dY(t) + 0

= Y(t)dX(t) + 2X(t)dY(t).

Now let's substitute the expressions for X(t) and dX(t):

dX(t) = tdW(t),

X(t) = tW(t).

Substituting these back into dZ(t):

= Y(t)(tdW(t)) + 2(tW(t))dY(t)

= tY(t)dW(t) + 2tW(t)dY(t).

Therefore, we have:

d(X(t)Y(t)) = tY(t)dW(t) + 2tW(t)dY(t).

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This experiment help us understand their behavior as well as how the people will cop up with the rules and regulation the society wants to apply on them

In a two-week simulation of a prison setting, the Stanford prison experiment was meant to look at the impact of situational factors on participants' responses and behaviors.

Hence, this experiment allows us to better understand their behavior, as well as how individuals will respond to the laws and regulations imposed by society.

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The branches that sometimes occur along the length of an axon are called axon collaterals.

Axon collaterals are the branches that occasionally emerge from the main axon shaft. They can extend at various points along the axon's length and allow for communication between different neurons or neuronal circuits. Axons are long, slender projections of nerve cells responsible for transmitting electrical impulses, known as action potentials, away from the cell body. These axonal branches or collaterals can diverge and form connections with other neurons, enabling the transmission of signals to multiple targets simultaneously.

Axon collaterals play a vital role in neuronal communication and the integration of information within the nervous system. They provide a mechanism for branching connectivity, allowing a single axon to relay signals to multiple target cells. This branching architecture enables the coordination and synchronization of neural activity across different regions of the brain and facilitates complex information processing. Axon collaterals contribute to the extensive network of interconnected neurons, forming the basis for neural circuits and enabling the transmission of information throughout the nervous system.

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Answer:

B

Explanation:

a straight yellow is a no pass zone

Answer:

c

Explanation:

The texture of the string. I took this test a week ago I got a 90% it is c!

Answer: 42

Explanation: 2 x 3 = 6 x 7 = 42

Answer:

42

Explanation

The Barbie would be moving with speed 27.69 ft/s at the bottom of the path.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Mass of the Barbie = 0.23 kg.

Initial height of the Barbie: h= 11 ft 11 inches = ( 11 + 11/12) feet = 11.92 feet.

Acceleration due to gravity: g = 32.17 ft/s²

Hence, the speed of the Barbie at the bottom of the path = √(2gh)

= √( 2 × 32.17 ×11.92) ft/s

= 27.69 ft/s.

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Answer: It prevents us from seeing most of the galactic disk with visible and ultraviolet light.

(hope this helps) :)

Between 15s-30s is the time when the train is traveling at its highest speed.

Speed is a scalar variable that expresses how much an object's location varies over time or how much it moves per unit of time. It is frequently abbreviated as "s." The distance traveled by an object during a period of time divided by the length of the period gives the average speed of the object throughout that period.

The speed-related measures are time divided by distance. The most prevalent unit of speed in daily life is the kilometer per hour (kph), but the SI measure of speed is the meter per second (m/s).

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Answer:

B

Explanation:

The wording of this question leaves a lot to be desired.  The way it reads, it should be 60J., but I'm almost certain that is not the intended answer.

The answer looks like it should be 100J of some kind. It's worded in such a way that it does 80 J of work on the surroundings and in addition, releases another 20 joules in the form of heat. It doing this, the system should be losing 100 Joules so the answer should be B.

There are no guarantees here. That is just my best proposal.

Answer:

ANION is the answer

Answer:

Vf = 25.7 [m/s]

Explanation:

To solve this problem we must use the following kinematics equation:

\(v_{f} ^{2}= v_{i} ^{2}-(2*a*x)\)

where:

Vf = final velocity [m/s]

Vi = initial velocity = 30 [m/s]

a = desacceleration = 2 [m/s^2]

x = distance = 60 [m]

Note: the negative sign in the equation means that the car slows down.

Now replacing:

\(v_{f}^{2}=(30)^{2}-(2*2*60)\\ v_{f}^{2} = 660\\v_{f} =\sqrt{660} \\v_{f}=25.7[m/s]\)

Cardiovascular drug classes are Beta-blockers, Diuretics, Calcium channel blockers, and ACE inhibitors. The correct answer is options are A, B, D, and F.

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The correct question would be as

Which of the following are cardiovascular drug classes? Select all that apply.

A) Beta-blockers

B) Diuretics

C) Antibiotics

D) Calcium channel blockers

E) Antidepressants

F) ACE inhibitors

Contacting the tractor-trailer truck's driver who was operating it when the accident occurred.

When responding to any incident, first responders must be on the lookout for dangerous chemicals. The dispatcher may give details like odd indications and symptoms (such a strong stench or itchy eyes) or the address may hint that the call may entail a chemical release. When unpleasant odors, gasoline, or corrosive liquid spills are present, it may be easy to see that hazardous items are present. When dealing with odorless yet toxic and/or combustible vapors and liquids, radioactive materials, or other circumstances, the dangerous character of the chemical(s) may not always be obvious. It is safe to presume that the cargo is dangerous if a vehicle has a diamond-shaped placard or an orange-numbered panel on the side or back.

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Answer:

It keeps our body hydrated.

Explanation: