(NH4)2SO4. How many N are there?

The atomic mass of the new atom will be 251, the atomic number of the atom will be 98. The atomic symbol of the new atom will be Cf. The type of decay will be gamma decay.

The kind of decay in which there is no variation in atomic number as well as atomic mass will be considered as gamma decay.

The given reaction is :

\(^{251} Cf_{98}\) → \(^{0} Y_{0} + ^{A} X_{Z}\)

It can be seen that there is no any changes in atomic number and atomic mass. Hence, it will be gamma decay.

The atomic mass of the new atom = 251

The atomic number of the atom = 98

The atomic symbol of the new atom = Cf

The type of decay = gamma decay.

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Answer:

Step 1

Brush foam latex mold release into the mold or baking sheet being used. The baking sheet is for flat sheets of foam rather than a specific shape, for which a mold is used.

Step 2

Allow the mold release to dry and buff off any excess buildup.

Step 3

Pour one-third of a pound of latex base into a mixing bowl, followed by 1 ounce of foaming agent and a half ounce of curing agent.

Step 4

Measure a half ounce of gelling agent in a separate cup.

Step 5

Mix the foam at the following speeds: one for 1 minute; then 10 for 4 minutes; then four for 1 minute; and finally one again for 4 minutes. These speeds and times are specifically for a KitchenAid mixer. For other brands, see the references.

Step 6

Slowly add the gelling agent after 10 minutes. Drizzle it in over the course of 30 seconds; do not dump it in.

Step 7

Allow the foam to mix for one more minute.

Step 8

Remove the bowl from the mixer and brush or pour the foam into the mold or baking sheet. Close the mold and strap it together if it has more than one piece.

Step 9

Put the mold or baking sheet in the oven when the foam has gelled. If you can poke the foam with your finger without it sticking to the foam, the foam has gelled.

Step 10

Bake the foam at 180 degrees F for 2 to 3 hours for small molds and baking sheets, 3 to 4 hours for large molds.

Explanation:

If this does not help look it up on google.

also did not know what type of foam this is foam rubber.

Wind and Erosion lead to Washing away of top soil.

Erosion is the process that lead to the washing away of top soil leading to loss of nutrient, holes and many more.

The agents of erosion include wind, water and so on.

Strong wind will lead to the top soil to be remove when it is blowing. Water also when is is flowing turbulently maybe when rain fall can lead to loss of top soil.

Therefore, Wind and Erosion lead to Washing away of top soil.

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Answer

The theoretical Van't Hoff factor i for C12H22O11 is 1

Explanation

The Van't Hoff factor, i, is the number of particles formed in a solution from one formula unit of solute.

The Van't Hoff factor, i, is a property of the solute. In an ideal solution, i does not depend on the concentration of the solution.

For a nonelectrolyte, like (C12H22O11), which does not separate into ions in solution, Van''t Hoff factor, i = 1 because 1 molecule of sucrose (C12H22O11) forms only one particle in solution.f

Answer:

Diffusion is the movement of particles from an area of high concentration to an area of low concentration.

Explanation:

Entropy can be thought of as the amount of disorder in a system.

Entropy is a physical concept of order and disorder in a system, and it can be thought of as the measure of the amount of disorder in a system. In thermodynamics, entropy is a measure of the number of ways a system can rearrange its components and still be in the same state.

                                 The units of entropy are Joules per Kelvin (J/K), and the symbol used for entropy is S. The more ways there are for the molecules in a system to be arranged, the higher the entropy of that system. The entropy of a perfect crystal at absolute zero temperature is zero.

                                   As the temperature of a crystal increases, the entropy of the crystal increases as well. When the crystal melts, the entropy of the liquid is even greater because there are more ways for the molecules to move about.However, in a closed system, entropy will always increase over time. That's because over time, there are more ways for the molecules in the system to arrange themselves, and therefore, the entropy of the system increases.

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4396.5 L of air at the given density 1.23 kg/m3 is needed to completely burn 350 g of propane. The equation for the reaction is: \(C_{3}H_{8} + 5O_{2}\) → \(3CO_{2} + 4H_{2}O\).

The density given for air corresponds roughly to a temperature of 15 °C and 1 atm pressure.

Let us assume that 1 liter of air is 21% \(O_{2}\),

We will need 4240 L of air at STP. The density of air at STP is 1.2754 kg/m³. Since the air given here is at a lower density, then we will need more air proportionate to the density, or 4396.5 L of air at the density that has been given.

Volume is the three-dimensional area that a closed surface encloses. Mass per unit volume is density. Volume and density have a direct proportional relationship. In other words, if the volume changes, the density will change, and vice versa.

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Answer:

atomic number

Explanation:

atomic number is the number of protons

it's not a very stable compound

Answer:

they are bacteria

Explanation:

Answer:

Good bacteria keeps you healthy by supporting your immune function and controlling inflammation. Certain types of good bacteria can also: Help your body digest food. Keep bad bacteria from getting out of control and making you sick.

Explanation:

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number of protons, neutrons, and electrons for an atom of any element. Atoms are made of protons, neutrons, and electrons. Protons carry a positive electrical change, while electrons are negatively charged, and neutrons are neutral.

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The given question is 98, 99, 100 , 90, 98 , 100

Mean= \(\frac{Sum of observations}{Number of observations}\)

In mathematics and statistics, the average is the average of a set of values. The mean can be calculated in a number of ways, including the simple arithmetic mean (adding the numbers and dividing the sum by the number of observations), the geometric mean, or the harmonic mean.

Sum of observations is 98+99+100+90+98+100

The summation is 585

The number of observations is 6.

= \(\frac{98+99+100+90+98+100}{6}\)

= 97.5

So, the answer is 97.5

Answer:

2.7 g/mL

Explanation:

Density = mass/volume

To find the mass, we subtract the new water volume by the original water volume

15.46 - 10 = 5.46

The volume of the aluminum is 5.46 mL

We already got the mass of aluminum, 14.74

Now we just divide mass by volume to find the density

14.74 ÷ 5.46 = 2.699633

Side product which is obtained during the dehydration of cyclohexanol  which is a organic type of chemical reaction is dicyclohexyl ether .

Chemical reactions are defined as reactions which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical reaction.

There are several characteristics of chemical reactions like change in color, change in state , change in odor and change in composition . During chemical reaction there is also formation of precipitate an insoluble mass of substance or even evolution of gases.

There are three types of chemical reactions:

1) inorganic reactions

2)organic reactions

3) biochemical reactions

During chemical reactions atoms are rearranged and reactions are accompanied by an energy change as new substances are formed.

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The value of the parameter k in the equation for Fick's Law is:

Fick's Law is given by the equation:

J = -D * A * (∆n / ∆x)

where:

J is the flux or rate of diffusion,

D is the diffusion coefficient,

A is the surface area of the membrane,

∆n is the change in concentration,

∆x is the thickness of the membrane.

In this case, we need to find the value of the parameter k in the equation for Fick's Law.

The value of k is related to the diffusion coefficient (D) by the equation:

k = D / (∆n / ∆x)

We are given the following information:

Membrane thickness (∆x) = 5 × 10^(-8) m

Surface area (A) = 4 × 10^(-8) m

Initial concentration inside the cell (n(0)) = 1.4 M

Concentration after observation (n(0.8)) = 0.91 M

Concentration outside the cell (n(outside)) = 0.9 M

To find the change in concentration (∆n), we can subtract the concentration after observation from the initial concentration:

∆n = n(0.8) - n(0)

∆n = 0.91 M - 1.4 M

∆n = -0.49 M

Substituting the given values into the equation for k, we have:

k = D / (∆n / ∆x)

k = D / (-0.49 M / 5 × 10⁻⁸ m

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Microstructure of only alpha will represent an alloy that is below the solubility limit for component b in the alpha phase.

The alpha and beta phases are phases that represent a solid solution of elements A and B. The alpha phase will have a crystal structure like pure A and will contain some B substituting in the crystal lattice. Likewise,  beta phases will have an element B crystal structure with A substituting for some B atoms.

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HgO is the limiting reactant. Cl\(_2\) is the excess reactant. The limiting reactant, also known as the limiting reagent.

In a chemical reaction, the limiting reactant, also known as the limiting reagent, controls how much product is produced. Calculating the theoretical yield of such a reaction is achievable if the limiting reactant has been identified.

Because elements and compounds in a balanced chemical system react in accordance with their mole ratios, there must be a limiting reactant.

HgO + 2Cl\(_2\) →HgCl\(_2\) + Cl\(_2\)O

moles of HgO =11.50/ 216.5=0.05moles

moles of Cl\(_2\) =12.46/70.9=0.17moles

To find the limiting reactant, divide the moles by stoichiometry. HgO is the limiting reactant. Cl\(_2\) is the excess reactant.

Therefore, HgO is the limiting reactant. Cl\(_2\) is the excess reactant.

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The Kinetic Molecular Theory (KMT) explains the behavior of gases. According to KMT, gases are composed of tiny particles that are in constant random motion, colliding with each other and the walls of the container they are in. True, when a sealed container of gas is opened, gas will flow from the region of higher pressure to the region of lower pressure. When the push button on an aerosol spray can is pressed, the pressure inside the can decreases, causing the gas and liquid inside to expand and be released in a spray or mist.


The kinetic molecular theory explains the behavior of gases. When you use a pump to add gas to a rigid container, conditions change as the pressure inside the container increases due to more gas molecules colliding with the walls. If too much gas is pumped into a sealed, rigid container, the pressure can become extremely high, causing the container to potentially rupture or explode.
True: When a sealed container of gas is opened, gas will flow from the region of higher pressure to the region of lower pressure.
When the push button on an aerosol spray can is pressed, the pressure inside the can is released, allowing the gas and the liquid product to be expelled through the nozzle as a fine spray.

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False , The most abundant cation in intracellular fluid is potassium (K+), not sodium (Na+). Potassium ions are found in higher concentrations inside cells, contributing to the positive charge within the intracellular environment.

Sodium ions, on the other hand, are more abundant in extracellular fluid. The concentration gradient of sodium and potassium across the cell membrane plays a crucial role in various cellular processes, including the generation of action potentials and the maintenance of cell volume and osmotic balance.

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The answer to your question is "CBr4"

Answer:

it is a

watch for kJ vs J as the enthalpy is in kJ and entropy is in J

Explanation:

If a strong acid is added, this does not become a buffer and does not dampen sudden changes in pH .

Buffers are used to keep the pH of a solution in a more stable state. This can be done in one of two ways: you can use a weak base to neutralize a strong acid or vice versa.

In order for this to work, the solution must have a pH below 7. For example, a strong acid with a pH of 1 would have a pH of 7 once a weak base was added. This can be tricky when using acids and bases of the same molarity.

The addition of a strong base to a weak acid does not make a buffer. However, the ratio is irrelevant when it comes to whether or not it is a buffer.

So,  If a strong acid is added, this does not become a buffer and does not dampen sudden changes in pH .

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No, a mixture of KI and Na2SO3 would not perform the same reduction and precipitation of copper(II) as a mixture of NaI and Na2SO3. This is because the reducing power of the two mixtures is different due to the different nature of the cations (K+ vs Na+).

What is Reduction?

Reduction is a chemical process in which a substance gains electrons and undergoes a decrease in oxidation state. It is a key aspect of many chemical reactions, including combustion, corrosion, and the synthesis of organic compounds.

In the reduction of copper(II) to copper(I), iodide ion (I-) acts as the reducing agent, which gets oxidized to iodine (I2). In the presence of sodium sulfite (Na2SO3), the iodine reacts with sulfite ion (SO32-) to form iodide ion and sulfate ion (SO42-), while copper(I) ions get precipitated as copper(I) sulfite.

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Answer:

Limiting reactant is FeCl3; 1.7 g of Mg remain.

Explanation:

From the question;

The equation is;

3Mg(s) + 2FeCl₃(s) → 3MgCl₂(s) + 2Fe(s)

Amount of Mg = 41 g/24.31 g/mol = 1.687 moles

The limiting reactant yields the least amount of MgCl2

3 moles of Mg yields 3 moles of MgCl2

Hence 1.687 moles of Mg yields yields 1.687 moles of MgCl2

FeCl₃ = 175 g/162.2 g/mol = 1.0789 moles

2 moles of FeCl3 yields 3 moles of MgCl2

1.0789  moles of FeCl3 yields 1.0789  * 3/2 = 1.61835 moles of MgCl2

Hence FeCl3 is the limiting reactant

3 moles of Mg reacts with 2 moles of FeCl3

x moles of Mg reacts with 1.0789  of FeCl3

x = 3 * 1.0789  /2 = 1.61835 moles of Mg

Mass of Mg reacted = 1.61835 moles * 24.31 = 39.342 g

Mass of excess Mg = 41 g - 39.342 g = 1.7 g

The total volume of the solution is 1005 mL after adding 5 mL of 0.50 M HCl, we can assume that the volume change is negligible, and the concentrations of HA and A- remain the same.

A buffer typically consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer's ability to resist changes in pH comes from the equilibrium between the weak acid and its conjugate base.

To calculate the pH after adding 5.0 mL of 0.50 M HCl to 1 liter (1000 mL) of the buffer solution, we need to consider the buffer's composition and the effect of the added acid.

Since you haven't provided the exact composition of the buffer, I'll assume it consists of a weak acid and its conjugate base. Let's denote the weak acid as HA and its conjugate base as A-. The buffer is designed to resist changes in pH when small amounts of acid or base are added.

When HCl is added, it will dissociate into H+ and Cl- ions. The H+ ions from HCl will react with the conjugate base A- in the buffer, forming the weak acid HA. This reaction helps maintain the pH of the buffer.

To calculate the pH after the addition of HCl, we need to know the initial concentrations of HA and A- in the buffer and the pKa of the weak acid HA. With this information, we can use the Henderson-Hasselbalch equation:

pH = pKa + log ([A-]/[HA])

Given that the total volume of the solution is 1005 mL after adding 5 mL of 0.50 M HCl, we can assume that the volume change is negligible, and the concentrations of HA and A- remain the same.

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After adding 5.0 mL of 0.50 M HCl to 1 liter of a buffer solution with an initial concentration of 0.10 M and a \(pKa\) of 5.0, the pH of the buffer will be determined using the Henderson-Hasselbalch equation: \(pH = 5.0 + log([0.10 M + (0.50 M x (5.0 mL/1005 mL))]/[0.10 M])\).

The pH of a buffer solution can be calculated using the Henderson-Hasselbalch equation, which is \(pH = pKa + log([A-]/[HA])\).
In this case, 5.0 mL of 0.50 M HCl is added to 1 liter of the buffer solution, resulting in a total volume of 1005 mL. To calculate the pH, we need to know the \(pKa\) value of the buffer and the concentrations of the acidic form \(([HA])\) and the conjugate base \(([A-])\).
Let's assume the \(pKa\) of the buffer is 5.0. We can use the equation to calculate the ratio \([A-]/[HA]\). Since the concentration of HCl added is much higher than the initial concentration of the buffer, we can assume that the concentration of [HA] remains approximately the same. Therefore, the concentration of [A-] will be equal to the initial concentration of the buffer plus the concentration of HCl added.
Let's say the initial concentration of the buffer is 0.10 M. After adding 5.0 mL of 0.50 M HCl, the concentration of [A-] would be 0.10 M + (0.50 M x (5.0 mL/1005 mL)).
Now, substitute the values into the Henderson-Hasselbalch equation: \(pH = 5.0 + log(([A-]/[HA]))\). Calculate the ratio \([A-]/[HA]\) and substitute it into the equation to find the \(pH\).
This calculation will give you the pH of the buffer solution after adding the HCl.

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Answer:

Doubling the volume of the reaction vessel and adding more oxygen to the reaction vessel will change the concentrations and will affect equilibrium concentrations.

Explanation:

Answer:

Wavelength = \(4.48*10^{-5}m\)

Explanation:

Given the following data;

Speed of light, V = 3 * 10^{8}m/s

Frequency, F = 6.700 * 10^{12}Hz.

To find the wavelength

We know that that the speed of light is given by the formula;

\( Speed of light, V = wavelength * frequency \)

Making wavelength the subject of formula, we have;

\( Wavelength = \frac {speed \; of \; light}{frequency} \)

Substituting into the equation, we have;

\( Wavelength = \frac {3 *10^{8}}{6.700 ✕ 10^{12}} \)

Simplifying the equation, we have;

Wavelength = 4.48*10^{-5} m

Therefore, the wavelength of the electromagnetic radiation is \(4.48*10^{-5} meters\)

Answer:

F has the smallest atomic radius.

Explanation:

Atomic radius is one of the perIodic properties defined by the Periodic Table.

Atomich radius is the distance to the nucleus that comprises 95 % of the density  electronic load.  It can be defined  as a function of the internuclear distance. Although this distance varies, depending on whether the atoms are linked by a chemical bond or simply in contact without forming  link.

Atomic radius is a periodic property that increases by period (from the top to below) and decreases (from left to right) by group.

In the same group are O and F, so F < O

In the same group, we have S and Cl, so Cl < S

As Cl and F are in the same period, we define the atomic radius Cl > F and

S > Cl (In the same period)

The right way to order the elements are S > Cl > O > F  

Answer:

Cadmium has larger atomic radius than sulfur.

Explanation:

Down a period, atomic radii decrease from left to right due to the increase in the number of protons and electrons across a period: when a proton is added the pull of the electrons towards the nucleus is larger, so the size of the atom decreases.

Hence, you can compare the elements that belong to a same period and predict that the atom with lower atomic number (number of protons) will haver larger atomic radius. With that:

Oxygen and fluorine are in the period 3, being oxygen to the left of fluorine, so oxygen is larger than fluorine.

Sulfur and chlorine are in the period 4, being sulfur to the left of chlorine, so sulfur is larger than chlorine.

Now see whan happens down a group. Atomic radius increases from top to bottom within a group due to electron shielding. That permits you to compare the size of the elements in a group:

Fluorine and chlorine are in the same group (17), with chlorine directly below fluorine, so the atomic radius of chlorine is larger than the atomic radius of fluorine.

Sulfur and oxygen are in the same group (16), with sulfur directlly below oxygen, so sulfur the atomic radius of sulfur is larger than the atocmi radius of oxygen.

So far, you can rank the atomic radius of sulfur, chlorine, fluorine, and oxygen, in increasing order as:

O < F < Cl < S, concluding that O, F, and Cl have smaller atomic radius than S.

Cadmiun, Cd, is to the left and below sulfur, so both electron shielding (down a group) and increase of the number of protons (down a period) lead to predict the cadmium has a larger atomic radius than sulfur.

Examples of erosion or corrosion caused by water include: An coastal beach's rocks are battered by the waves. Small rocks are carried down a hillside by a river. A tunnel is created when underground water dissolves limestone.

Rust, which results from oxidation, and acid rain, which is brought on when carbonic acid dissolves rocks, are two instances of chemical weathering. additional molecular weathering.

On a mountainside, tiny rock fragments break off due to wind and precipitation. Chemical and mechanical mechanisms can cause weathering. The migration of particles away from their source is erosion. A tiny rock fragment is carried away from a mountainside by the wind as an illustration of erosion.

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