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"Create a new matrix by copying elements greater than or equal to 25 from the original matrix."

To process a given n×m matrix with the provided rules, we need to create a new matrix that retains only the elements greater than or equal to 25 from the original matrix. We can start by initializing an empty new matrix of the same size as the original matrix. Then, we iterate through each element of the original matrix. For each element, we check if it is greater than or equal to 25. If it satisfies this condition, we copy that element to the corresponding position in the new matrix.

By applying this process for all elements in the original matrix, we generate a new matrix that contains only the elements greater than or equal to 25. The new matrix will have the same dimensions as the original matrix, and the elements in the new matrix will be placed in the same positions as their corresponding elements in the original matrix

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Based on the information provided, we can conduct a hypothesis test to determine if a majority of all students at Ohio University believe the academics are 'very strong'.

Let's set up the null and alternative hypotheses:

Null hypothesis (H₀): The proportion of all students who believe the academics are 'very strong' is equal to 50% or less.

Alternative hypothesis (H₁): The proportion of all students who believe the academics are 'very strong' is greater than 50%.

To test these hypotheses, we can use a one-sample proportion test. We will compare the sample proportion (55%) to the hypothesized proportion (50%) and assess if the difference is statistically significant.

Using appropriate statistical methods, such as calculating the test statistic and obtaining the p-value, we can evaluate the evidence against the null hypothesis. If the p-value is less than the chosen significance level (e.g., 0.05), we would reject the null hypothesis and conclude that a majority of all students at Ohio University believe the academics are 'very strong'. Otherwise, if the p-value is greater than the significance level, we would fail to reject the null hypothesis and conclude that there is not enough evidence to support the claim of a majority belief.

Please note that without the actual test results or the p-value, we cannot make a definitive conclusion in this particular case.

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Answer:

Explanation:

We would apply the formula for calculating the future value of an annuity which is expressed as

S = R[(1 + i)^n - 1)/i]

where

R is the payment at the end of each period

i is interest rate per period.

n is the number of periods.

S is the future value

Since it is compounded quarterly, that means that payments are made 4 times per year. thus,

i = r/4

n = 4 x time

From the information given,

R = 10000

r = 4.25% = 4.25/100 = 0.0425

i = 0.0425/4 =

Congruent triangles are also frequently employed in architectural designs, carpet patterns, stepping stone patterns, and geometric art.

The following are the two most typical instances of this: Equilateral triangles are used to make truss bridges, which are built on both sides.

Congruence :

If all three corresponding sides and all three corresponding angles are equal in size, two triangles are said to be congruent. Slide, twist, flip, and turn these triangles to create an identical appearance. They are in alignment with one another when moved. A term used to describe an object and its mirror counterpart is congruence. If two things or shapes superimpose on one another, they are said to be congruent. They are identical in terms of size and shape. Line segments having the same length and angles with the same measure are congruent in the context of geometric figures.

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Answer:

3.12

Step-by-step explanation:

The probability that the iPhone will not die before t hours, given an average battery life of 10 hours, can be calculated using the exponential distribution. The reliability of the device is equal to the probability of surviving beyond t hours, which is given by the equation \(\[P(T > t) = e^{-\lambda t}\]\), where \(\(\lambda\)\) is the rate parameter. In this case, since the average battery life is 10 hours, \(\(\lambda = \frac{1}{10}\)\). Therefore, the probability of reliability is \(\[P(T > t) = e^{-\frac{t}{10}}\]\).

To find the probability of reliability, we use the exponential distribution formula. The exponential distribution is commonly used to model the time until an event occurs, such as the battery dying in this case. The rate parameter, \(\(\lambda\)\), is the reciprocal of the average time until the event occurs.

In this scenario, the average battery life is given as 10 hours. Therefore, the rate parameter \(\(\lambda\)\) is \(\(\frac{1}{10}\)\). The probability that the iPhone will not die before t hours is calculated by finding the complement of the probability that it will die before t hours.

The complement of the event "the iPhone will die before t hours" is "the iPhone will survive beyond t hours." This is represented as \(\(P(T > t)\)\), where T is the time until the battery dies.

Substituting the value of \(\(\lambda\)\) into the exponential distribution formula, we get \(\(P(T > t) = e^{-\frac{t}{10}}\)\). This equation gives us the probability that the iPhone will not die before t hours, which is the reliability of the device.

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The angle between vectors A and B is approximately 89.78 degrees.

To find the angle between vectors A and B, we can use the dot product formula:

A · B = |A| |B| cos(θ)

Given that Ā· B = 4 and knowing the magnitudes of vectors A and B:

|A| = √(22² + 33²)

    = √(484 + 1089)

    = √(1573)

    ≈ 39.69

|B| = √((-1)² + 23² )

    = √(1 + 529)

    = √(530)

    ≈ 23.02

Substituting the values into the dot product formula:

4 = (39.69)(23.02) cos(θ)

Now, solve for cos(θ):

cos(θ) = 4 / (39.69)(23.02)

cos(θ) ≈ 0.0183

To find the angle θ, we take the inverse cosine (arccos) of 0.0183:

θ = arccos(0.0183)

θ ≈ 89.78 degrees

Therefore, the angle between vectors A and B is approximately 89.78 degrees.

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Based on the given information and performing a one-sample t-test, the conclusion is that if the population mean (μ) is greater than 30.8294 km per litre, we reject the null hypothesis.

Given:

Sample mean (x') = 30 km per litre

Sample standard deviation (s) = 3.5 km per litre

Sample size (n) = 50

Significance level (α) = 0.05 (5%)

Null hypothesis \((H_0)\): The mean petrol consumption of the new car is equal to or higher than that of the existing car.

Alternative hypothesis \((H_1)\): The mean petrol consumption of the new car is lower than that of the existing car.

We'll calculate the test statistic (t-value) and compare it with the critical t-value.

The formula for the t-value is:

t = (x' - μ) / (s / √n)

where μ is the population mean (mean petrol consumption of the existing car).

First, we need to calculate the critical t-value from the t-distribution table. Since we have a significance level of 0.05 and (50 - 1) degrees of freedom, the critical t-value for a one-tailed test is approximately -1.677.

Now, let's calculate the t-value:

t = (30 - μ) / (3.5 / √50)

To reject the null hypothesis, the t-value should be less than the critical t-value.

Simplifying the equation:

t = (30 - μ) / (0.495)

To find the critical value, we compare it with the calculated t-value:

-1.677 > (30 - μ) / (0.495)

Multiplying both sides of the inequality by 0.495:

-0.8294 > 30 - μ

Rearranging the inequality:

μ > 30 + 0.8294

μ > 30.8294

Therefore, if the population mean (μ) is greater than 30.8294 km per litre, we reject the null hypothesis in favor of the alternative hypothesis, concluding that the mean petrol consumption of the new car is lower than that of the existing car.

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Answer:

200

Step-by-step explanation:

Good luck <3

Answer:

200

Step-by-step explanation:

hope it helps

Answer: 33

Step-by-step explanation:

Answer:

-0.13157894736

Step-by-step explanation:

We can use the stars and bars method to fix this issue. This provides us a total of 191 allocations from which to choose: 191 choose 11 is equal to frac(191!11!180!) = 6,176,424,853,430.

ii. There are two options available for each of the 10 journeys since each one can be either express or local. Therefore, there are a total of $210 = 1024 potential sequences.

iii. Three scenarios should be taken into account: when there are three, four, or five vehicles in the train.

If there are 3 cars in the train, there are $7 choose 3 = 35 options to select them.

If there are 4 cars in the train, there are $7 * 4 * 35 options to select the cars.

If there are 5 cars in the train, there are 7 * 5 * 21 options to select the cars.

$35+35+21=91 is the total amount of trains that could run.

iv. This issue can be resolved by combining permutation and combination. Selecting the first two or three intermediate stations for the express train is necessary. There are $8choose 2+$8choose 3=28+56=84$ different methods we can allocations this.

Therefore, (84 times 1) + (84 times 2) = 252 is the total number of possible express train trips.

v. We need $20ngeq $20 to ensure that we have opened each of the three doors in every conceivable combination. Using the n-solve, we obtain: n = log 20(20) / 2 = 1.

To ensure that the same three doors have been opened six times, we must make at least one halt.

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Answer:

g(x) = 5(x - 5) + 4

Step-by-step explanation:

None of the answers listed are correct

Answer:

C

Step-by-step explanation:

Answer:

She has to pay $37.8

Step-by-step explanation:

25+10=35

35*0.08+35

2.8+35

=37.8

Answer:

13

Step-by-step explanation:

A is going to be my version of the triangle:

if A ABC =~ A GHI then all of the line segments and area should be the same.

Answer:

x = 0 , x = 3

Step-by-step explanation:

Equate the 2 expressions and solve for x

3x² - 2x + 1 = 7x + 1 ( subtract 7x + 1 from both sides )

3x² - 9x = 0 ← factor out 3x from each term

3x(x - 3) = 0

Equate each factor to zero and solve for x

3x = 0 ⇒ x = 0

x - 3 = 0 ⇒ x = 3

Answer:

the slope is -7

Step-by-step explanation:

\(\frac{-2-5}{3-2} =\frac{-7}{1}\)

The range of the given function in the figure is R - {0, 1, 2, 3}.

The given mapping shows a function f(x).

There are 4 inputs to the function and 5 outputs.

So, the domain set for the given function is written as D = {0, 5, 10, 15}

And the range set for the given function is written as R = {0, 1, 2, 3}

(Since the 5th output is repeating, in the range it is considered only once).

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Answer:

400/1000×100%

40% is the percent of decrease from 1,000 to 400.

Answer:

We know that,

\((a^{x}) ^{y} =a^{xy}\)

\(a^{x} *a^{y} =a^{x+y}\)

\(\frac{a^{x} }{a^{y} } =a^{x-y}\)

Let's solve now.

1) \((3^{8})^{4} =3^{32}\)

2)  \(7f^{3} * 9f^{9} =63f^{12}\)

3) \(12^{4} *12^{10} =12^{14}\)

4) \((6m^{5} )^{3} =6m^{15}\)

5)  \(\frac{2^{5} }{2^{-3} } =2^{8}\)

6)  \(\frac{42g^{7} }{7g^{2} } =6g^{5}\)

7)  \(\frac{3^{9}*3^{6} }{3^{5} } =\frac{3^{15} }{3^{5} } =3^{10}\)

8)  \(\frac{11^{6}*11^6 }{11^2*11^3} =\frac{11^{12}}{11^5} =11^7\)

9) \(7^{-2} =\frac{1}{7^2} =\frac{1}{49}\)

10) \(3^{-3} =\frac{1}{3^3} =\frac{1}{27}\)

Hope this helps you.

Let me know if you have any other  questions :-)

If lines A, B and C shows proportional relationships, then the line A has a constant of proportionality between y and x is 5

Given the line A, B and C

The constant of proportionality is the ratio of the y coordinates to the x coordinate

k = y /x

Where k is the constant of proportionality

Consider the line A

One point on the line = (1, 5)

Constant of proportionality K = 5/1

= 5

Consider the line B

One point on the line = (3, 5)

Constant of proportionality k = 5/3

Consider the line C

One point on the line = (7, 5)

Constant of proportionality = 5/7

Therefore, the line A has the constant of proportionality of 5

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The given question is incomplete, the complete question is

Lines A, B, and C show proportional relationships. Which line has a constant of proportionality between y and x of 5?

Answer:

96.0 or 96.01499407

Step-by-step explanation:

r = C / (pi x 2)

  a1
   |\
   | \
   |  \
   |   \
a2 |    \
   |     \
   |      \
   |       \
   |        \
   |         \
  b1---------b2
```


1. Draw two parallel lines, a1 and a2, by marking them with the same direction arrows.
2. Draw two more parallel lines, b1 and b2, also marking them with the same direction arrows, but different from the ones used for a1 and a2.
3. Make sure that a1 is neither parallel nor perpendicular to b1. You can do this by ensuring that the angle formed between a1 and b1 is not 0° (parallel) or 90° (perpendicular).

In this configuration, you have successfully illustrated the given conditions: a1 is parallel to a2, b1 is parallel to b2, and a1 is neither parallel nor perpendicular to b1.

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Answer:

hol up

x=-1/8  negative one over eight

Step-by-step explanation:

Answer:

8, he added 8 fish a day

Step-by-step explanation:

if you divide 72 by 9 you get 8. 8 shows how much was added each day.

Answer:

the answer is C

Step-by-step explanation:

Answer:

c

you neeed to do the INVERSE  option

* is into /

+ is into -

- is into +

/ is into*

Answer:

44

Step-by-step explanation:

If I is an ideal of R and R/I is a field, then I is maximal.

(a) To prove that I + J is an ideal of R, we need to show that it satisfies the properties of an ideal. Firstly, since I and J are both ideals of R, it follows that I + J is a subset of R. Secondly, for any elements (a + b) and c in I + J, where a, b ∈ I and c ∈ J, we have (a + b) + c = a + (b + c) ∈ I + J, showing closure under addition. Similarly, for any element r in R and (a + b) in I + J, where a ∈ I and b ∈ J, we have r(a + b) = ra + rb ∈ I + J, showing closure under multiplication by elements of R. Therefore, I + J is an ideal of R.

(b) Using part (a), let's consider the quotient ring R/I. Since I is a maximal ideal, for any nonzero element a + I in R/I, the ideal generated by a, denoted as (a) = aR, is contained in R/I. By part (a), (a) + I is an ideal of R. But since I is maximal, we must have (a) + I = R/I. Therefore, every nonzero element in R/I has an inverse, making R/I a field.

(c) If I is an ideal of R and R/I is a field, then every nonzero element in R/I has an inverse. This implies that no proper ideal J of R can contain I, because if J contains I, then J/I would not be equal to R/I, contradicting the fact that R/I is a field. Hence, I must be maximal, as there is n

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Answer:

$460.

Step-by-step explanation:

\(Percentage\ change = (\frac{Original\ Price\ - Discounted\ Price}{Original\ Price})100\\\\15=(\frac{x-391}{x})100\\\\15x=(x-391)100 \\\\15x/100=x-391\\0.15x=x-391\\391=x-0.15x\\391=0.85x\\391/0.85=x\\460=x\\\)

So the price yesterday was $460

Answer:

yes it is

Step-by-step explanation: