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To calculate the duration of the shift, you need to subtract the clock-in time from the clock-out time.

In this case, the shift worker clocked in at 1730 hours (5:30 PM) and clocked out at 0330 hours (3:30 AM). However, since the clock is based on a 24-hour format, it's necessary to consider that the clock-out time of 0330 hours actually refers to the next day.

To calculate the duration of the shift, you can perform the following steps:

1. Calculate the duration until midnight (0000 hours) on the same day:

  - The time between 1730 hours and 0000 hours is 6 hours and 30 minutes (1730 - 0000 = 6:30 PM to 12:00 AM).

2. Calculate the duration from midnight (0000 hours) to the clock-out time:

  - The time between 0000 hours and 0330 hours is 3 hours and 30 minutes (12:00 AM to 3:30 AM).

3. Add the durations from step 1 and step 2 to find the total duration of the shift:

  - 6 hours and 30 minutes + 3 hours and 30 minutes = 10 hours.

Therefore, the duration of the shift was 10 hours.

Answer: x= -7/5 procedure: -2x-8-1=3x-6+4       -2x-9=3x-2   -2x-3x= -2+9    -5x= 7   answer: x= -7/5

The price of the watch before the discount is calculated to be £24.44.

As the total price of the watch and a pair of trainers is £53. 55 and the price of the trainer before the discount was £38, we first calculate the price of the trainers after the discount as follows;

discount on a pair of trainers = 15/100 × 38 =  £5.7

cost of trainers after discount =  £38 - 5.7 =  £32.3

Now the price of the watch after the discount can be calculated by subtraction as follows;

price of watch after discount = total price - price of trainers after discount

price of watch after discount =  £53. 55 - £32.3

price of watch after discount = £21.25

Now the price of the watch before the discount can be calculated as follows;

price of watch before discount = £21.25 × 15/100

price of watch before discount = £21.25 + £3.1875

price of watch before discount = £24.44

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Answer: A monomial representation is a way to express a polynomial as a product of powers of its variables, where each power is a non-negative integer. For example, the polynomial 2x^3 + 4x^2 - 6x + 8 can be represented as a monomial representation of (2x^3)(x^2)(-6x)(8).

Symmetric polynomials are polynomials that are invariant under permutation of their variables. A symmetric presentation is a way of expressing a symmetric polynomial as a sum of elementary symmetric polynomials, which are defined as the sum of all possible products of variables taken i at a time, where i ranges from 1 to the number of variables. For example, the symmetric polynomial x^3 + y^3 + z^3 can be expressed as a symmetric presentation of x + y + z.

Step-by-step explanation:

Yes, the tangent constraint can be applied between a line and an arc in many CAD (Computer-Aided Design) software programs.

In CAD, a tangent constraint is a geometric constraint that forces two entities (lines, arcs, circles, etc.) to share a common tangent at their point of contact. When you apply a tangent constraint between a line and an arc, the software will ensure that the line and the arc are always tangent to each other at their point of intersection.

This constraint is useful for designing mechanical components, such as gears or cams, where you need to ensure that the contact between two parts is smooth and continuous. It is also commonly used in architecture, where a building's curved surfaces may need to be tangent to adjacent straight lines or walls.

In short, the tangent constraint can be applied between a line and an arc, and it is a useful tool in many different fields of design.

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The value of the equation is A = 56x + 21

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

A = ( -7 ) ( -8x - 3 )   be equation (1)

On simplifying the equation , we get

A = ( -7 ) ( -8x ) - ( 7 ) ( -3 )

On further simplification , we get

A = 56x + 21

Hence , the equation is A = 56x + 21

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2x-3=7

The answer would be 5.

Answer:

x=5

Step-by-step explanation:

2x−3=7

Add 3 to both sides.

2x=7+3

Add 7 and 3 to get 10.

2x=10

Divide both sides by 2.

x=10/2

Divide 10 by 2 to get 5.

x=5

We know a or b != 0

but a-b==0 so both are the same unknown number

b/a must = 1

so

a/b is equivalent to b/a as a/b=1 as well.

So the last answer choice.

The matrix can be represented as:

\(\left[\begin{array}{ccc}1&0&0\\0&1&1\\0&0&0\end{array}\right]\)

Therefore, the matrix is an identity matrix.

The matrix can be represented as:

\(\left[\begin{array}{ccc}8\\-1\\0\end{array}\right]\)

​

Therefore, the matrix is a column matrix.

The matrix can be represented as:

\(\left[\begin{array}{ccc}0&0&0\\0&0&0\\0&0&0\end{array}\right]\)

Therefore, the matrix is a zero matrix.

The matrix can be represented as:

\(\left[\begin{array}{ccc}14&5&6\\4&5&6\\\end{array}\right]\)

Therefore, the matrix is a row matrix.

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A 25-meter-long towing vessel is pulling barges forward. The ship is required to display a minimum of two white masthead lights at night.

A commercial vessel that is pulling, pushing, hauling aboard, or any mixture of pulling, pressing, or hauling alongside, is referred to as a towing vessel.

Thus, a 25-meter-long towing vessel is pulling barges forward. The ship is required to display a minimum of two white masthead lights at night.

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Answer:

In cooking (recipes).

Step-by-step explanation:

If the serving size for a recipe is not adequate for the number of people you are serving, you will have to convert the amounts(measurements) of the ingredients to suit your needs. You will do this by first creating a ratio defining the relationship between the serving size of the given recipe to the number of people needed to be served. For example, if a recipe serves 4 people, and you need to serve 8, your ratio would simplify to 1/2. This means you must proportionally relate this ratio to the individual amounts of each ingredient.

Answer:

Step-by-step explanation:

\(\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}\)

we have shown that it is possible to color the graph G using A(G) + 1 colors, contradicting our assumption that X(G) > A(G) + 1. Hence, X(G) ≤ A(G) + 1.

To prove that X(G) ≤ A(G) + 1, where G = (V, E) is a graph and A(G) is the maximum degree of the vertices, we will use a proof by contradiction.

Assume that X(G) > A(G) + 1. This means that we require more than A(G) + 1 colors to color the vertices of G such that no adjacent vertices have the same color.

We will order the vertices v₁, v₂, ..., vn and use a greedy coloring algorithm. According to the greedy coloring algorithm, we color each vertex in the order of v₁, v₂, ..., vn, using the smallest available color that is not used by any of its adjacent vertices.

Now, consider the vertex v with the maximum degree in G, denoted by A(G). Let's say v is adjacent to vertices v₁, v₂, ..., vm. Since v has the maximum degree, it is adjacent to the maximum number of vertices among all vertices in G.

According to the greedy coloring algorithm, when we color vertex v, we will have at most A(G) adjacent vertices, and therefore we will have at most A(G) used colors among its neighbors. Since there are A(G) colors available (A(G) + 1 colors in total), we will always have at least one color available to color vertex v.

This means that we can color vertex v with a color that is not used by any of its adjacent vertices. Since v has the maximum degree, we can repeat this process for all vertices in G.

Therefore, we have shown that it is possible to color the graph G using A(G) + 1 colors, contradicting our assumption that X(G) > A(G) + 1. Hence, X(G) ≤ A(G) + 1.

This completes the proof.

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Answer:

-36

Step-by-step explanation:

21, 18, 15, 12....

All you have to do is subtract 3 less on each number you get, until u get to the twentieth term....

21, 18, 15, 12, 9, 6, 3, 0, -3, -6, -9, -12, -15, -18, -21, -24, -27, -30, -33, -36

-36 is the twentieth term of this arithmetic sequence

Hope this helped!

Have a supercalifragilisticexpialidocious day!

Answer:

square root 32 using iterative process

Answer:

12%

Step-by-step explanation:

140/125= 1.12

Now ignore the one that lies before the decimal because technically percentage is based on hundreds so both 125 and 140 are over 12%

Answer:

£6886

Step-by-step explanation:

P x e^r x t is the formula for compound interest

P x e^0.05 x 3 = 8000

P x 1.162 = 8000

P = 6885.66 = £6886 (round to the nearest pound)

Answer: £6910.71

Step-by-step explanation:

im not sure but i got this

Answer:

BC=\(\sqrt{95}\)

Angle A (or BAC)=54.31466...

Angle C (or ACB)=35.68533...

Step-by-step explanation:

\(\frac{7}{\sin \left(\angle \:ACB\right)}=\frac{12}{\sin \left(90\right)}\)

\(BC=\sqrt{12^2-7^2}\)

\(\sqrt{12^2-7^2}=\sqrt{95}\)

\(\frac{\sqrt{95}}{\sin \left(\angle \:BAC\right)}=\frac{12}{\sin \left(90\right)}\quad :\quad \angle \:BAC=54.31466\)

\(\frac{7}{\sin \left(\angle \:ACB\right)}=\frac{12}{\sin \left(90\right)}\quad :\quad \angle \:ACB=35.68533\)

Using the pythagorean theorem

\(AC^2=AB^2+BC^2\\BC=\sqrt{AC^2-AB^2}\\BC=\sqrt{12^2-7^2}\\BC=\sqrt{144-49}\\BC=\sqrt{95}\)

\(sin A=\frac{BC}{AC}=\frac{\sqrt{95} }{12}\\A = sin^{-1}(\frac{\sqrt{95} }{12})\\A = 54.31\)

\(A + C = 90\\C = 90-A\\C= 90- 54.31\\C = 35.69\)

Answer:

There are 102 marbles in the jar

Step-by-step explanation:

16+18 = 34

34 = 1/3

3×34 = total marbles

3×34 = 102

Answer:

hiii my pic lol (✿^‿^)(✿^‿^)(✿^‿^)(✿^‿^)

Both 9/3 and 54/18 come out to 3, so your answer is:

18:54

Answer:

18:54

Step-by-step explanation:

We have to simplify these ratios.

If the most simplified form of the ratios are equal, they are equivalent

3:9

24:54

18:54

Same ratio as 3:9, so 18:54 is equivalent to 3:9

36:81

The unit price is $2.5

34 mile taxi ride will cost $85

18 mile taxi ride costs $7.20

The cost of 1 mile is

= 18/7.20

= 2.5

The unit price is $2.5 for 1 mile

The cost of 34 mile taxi ride can be calculated as follows

= 2.5 × 34

= 85

Hence the 34 mile taxi ride will cost $85

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Answer:

$22.50

Step-by-step explanation:

The forecasts for periods 11 through 15 are: F11 = 297.4, F12 = 296.7, F13 = 297.1, F14 = 296.9, F15 = 297.0

Given: Smoothing constant α = 0.45, Forecast for period 10 = 297

We need to calculate the forecasts for periods 11 through 15 using the essential smoothing forecast method.

The essential smoothing forecast is given by:Ft+1 = αAt + (1 - α)

Ft

Where,

At is the actual value for period t, and Ft is the forecasted value for period t.

We have the forecast for period 10, so we can start by calculating the forecast for period 11:F11 = 0.45(297) + (1 - 0.45)F10 = 162.35 + 0.45F10

F11 = 162.35 + 0.45(297) = 297.4

For period 12:F12 = 0.45(At) + (1 - 0.45)F11F12 = 0.45(297.4) + 0.55(297) = 296.7

For period 13:F13 = 0.45(At) + (1 - 0.45)F12F13 = 0.45(296.7) + 0.55(297.4) = 297.1

For period 14:F14 = 0.45(At) + (1 - 0.45)F13F14 = 0.45(297.1) + 0.55(296.7) = 296.9

For period 15:F15 = 0.45(At) + (1 - 0.45)F14F15 = 0.45(296.9) + 0.55(297.1) = 297.0

Therefore, the forecasts for periods 11 through 15 are: F11 = 297.4, F12 = 296.7, F13 = 297.1, F14 = 296.9, F15 = 297.0 (All values rounded to two decimal places)

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The interpretation gives us the total number of cases that would occur during those 30 days under the given disease model.

The integral ∫₀³⁰ (20 + 2e^(0.25t)) dt represents the area under the curve of the function N(t) = 20 + 2e^(0.25t) over the interval from 0 to 30. This integral calculates the total accumulation of cases over the 30-day period.

To evaluate the integral, we can break it down into two parts: ∫₀³⁰ 20 dt and ∫₀³⁰ 2e^(0.25t) dt. The integral of a constant (20 in this case) with respect to t is simply the constant multiplied by the interval length, which gives us 20 * (30 - 0) = 600.

For the second part, we can integrate the exponential function using the rule ∫e^(ax) dx = (1/a)e^(ax), where a = 0.25. Evaluating this integral from 0 to 30 gives us (1/0.25)(e^(0.25 * 30) - e^(0.25 * 0)) = 4(e^(7.5) - 1).

Adding the results of the two integrals, we get the final value of ∫₀³⁰ (20 + 2e^(0.25t)) dt = 600 + 4(e^(7.5) - 1). This value represents the total number of cases that would accumulate over the 30-day period based on the given disease model.

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Answer:

Questions 1 and 3 already answered

Angles 1 and 3 are corresponding angles and therefore have same value:

The equation that represents the total number of apples that Sally has will be the equations x + y = 8 and 8x + 14y = 58

System of equations are equations that consists of two or more equations.

Let the number of small fruits basket be y

Large fruit basket be y

If Sally buys a total of 5 fruit baskets, then;

x + y = 8

If there are 8 apples in a small fruit basket and 14 apples in a large fruit basket with a combined total of 58 apples, then;

8x + 14y = 58

The equation that represents the total number of apples that Sally has will be the equations x + y = 8 and 8x + 14y = 58

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Answer:

The value of t = 18

Step-by-step explanation:

202 = 2t + 5 + t + 3t - 2 + 5t +1  Combine like terms

202 = 11t + 4  Subtract 4 from both sides

198 = 11\(\frac{11x}{11}\)x  Divide both sides by 11

\(\frac{198}{11}\) = 18

Is the question the value of t or the length of each side?

Each side

2t + 5

2(18) + 5

41

T

18

3T - 2

3(18) - 2

52

5T + 1

5(18) + 1

91

91 + 52 + 18 + 41 = 2002

Helping in the name of Jesus.

The integral for the surface area is \(Area = \int\limits^2_{-2} {8 - 2x^2} \, dx\)

From the question, we have the following parameters that can be used in our computation:

y = x² and y = 8 - x²

The intervals where curve intersect is

-2 ≤ x ≤ 2

For the surface area between around the region bounded by the curves, we have

Area = ∫[a, b] [f(x)] dx

This gives

\(Area = \int\limits^2_{-2} {8 - x^2 - x^2} \, dx\)

Evaluate

\(Area = \int\limits^2_{-2} {8 - 2x^2} \, dx\)

Hence, the integral for the surface area is \(Area = \int\limits^2_{-2} {8 - 2x^2} \, dx\)

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Answer:

100π - (96 + (13/2)√231 ) m^2

Step-by-step explanation:

We will solve this by finding the area of the triangles (the quadrilateral is cut by the diameter) and subtract it from the area of the circle.

There is a circle theorem which states that if a triangle is in the semicircle and the hypothenuse extends to the length of the diameter, the angle at B here is 90 degrees.

Since angle B is 90 degrees we can use the Pythagorean theorem (a^2 + b^2 = c^2) to find Line AC.

so 144 + 256 = 400

√400 = 20

So diameter is 20

Finding the area of the top triangle:

1/2(12x16) = 96cm^2

For the bottom triangle, we need the side DC to find the area. To find it we will apply the theorem once again.

400 = 169 + DC^2

DC^2 = 231

DC = √231

so the area of the bottom triangle is 1/2(13√231) = (13/2)√231

Now we add the area of the triangles for the quadrilateral and subtract from the circle area.

The circle area is 100π (πr^2)

Hence, the area of the shaded region is:

100π - (96 + (13/2)√231 ) m^2