need help with evaluating this Expression ​

Answer:

4

Step-by-step explanation:

m = 4

Answer:

See attached image

Step-by-step explanation:

Answer:

The answer is A and C

Step-by-step explanation:

Supplementary angles added together = 180.

True. The null hypothesis (denoted as H0) is a statement about a population parameter, typically a population mean or proportion, and it is formulated based on the assumption that there is no effect, relationship, or difference in the population.

However, in statistical hypothesis testing, data is often collected from a sample, not the entire population, due to practical limitations.

The sample data is then used to assess the evidence against the null hypothesis.

The null hypothesis is always stated in terms of the population, even though the data being analyzed comes from a sample.

A = x·(350 - 2x)

Therefore we get quadratic function:

A(x) = -2x² + 350x

where x = h is one of the dimensions and k = A(h) is the largest area

\(h=\dfrac{-b}{2a}=\dfrac{-350}{2\cdot(-2)}=87.5\ m\)

250-2x = 350 - 2·87.5 = 350 - 175 = 175 m

\(A(h)=-2(87.5)^2+350\cdot87.5=15312.5+30450=45762.5\ m^2\)

Answer:

See below

Step-by-step explanation:

You can always plug in x's and solve for y.

The "central-tenet" in his system was : (d) Workers should earn "higher-wages" and work "shorter-hours", which creates new pool of consumers with income and leisure to purchase car.

Henry Ford's system, known as Fordism, was characterized by the belief that by paying workers higher wages and reducing their working hours, they would have the means and leisure time to become consumers of the products they were producing, particularly automobiles.

Ford implemented the 8-hour workday and a $5 daily wage for his workers, which was significantly higher than the prevailing wages at the time. This approach aimed to increase the purchasing-power of workers and stimulate consumer demand, ultimately benefiting the economy as a whole.

Therefore, the correct option is (d).

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The given question is incomplete, the complete question is

Henry Ford is known for refining the assembly line and the Model T. He also adopted an attitude that came to be known as Fordism. What was a central tenet in his system?

(a) Workers could easily tolerate working on an assembly line, so they should be paid lower wages and work longer hours.

(b) Workers should be drawn from a pool of immigrant labor, which was cheaper and willing to tolerate the grueling work of an assembly line.

(c) Workers should earn lower wages and work shorter hours, since they were easily replaced on the assembly line.

(d) Workers should earn higher wages and work shorter hours, creating a new pool of consumers with the income and leisure to purchase a car.

The sum of the fractions (- 3/5 + 1/5) in simplest form is - 11/20.

A fraction is written in the form of p/q, where q ≠ 0.

Fractions are of two types they are proper fractions in which the numerator is smaller than the denominator and improper fractions where the numerator is greater than the denominator.

Given, Are two proper fractions - 3/4 and - 1/5, and we are required to take the difference which is,

= - 3/4 - (- 1/5).

Now the negative signs will distribute to positive which is,

= - 3/4 + 1/5.

Now, the LCM of 4 and 5 is 20.

= {(-3×5) + (1×4)}/20.

= (- 15 + 4)/20.

= - 11/20.

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There are 1470 commuters take both the bus and the subway.

To find the number of commuters who take both the bus and the subway, we can use the principle of inclusion-exclusion.

Let's denote:

A = Number of commuters who take the subway

B = Number of commuters who take the bus

N = Total number of commuters

From the given information:

A = 1190 (number of commuters who take the subway)

B = 640 (number of commuters who take the bus)

N = 1700 (total number of commuters)

We also know that 180 commuters do not take either the bus or the subway.

To find the number of commuters who take both the bus and the subway, we can use the formula:

A ∪ B = A + B - A ∩ B

where A ∪ B represents the union of A and B, and A ∩ B represents the intersection of A and B.

Substituting the values we have:

A ∪ B = 1190 + 640 - 180

A ∪ B = 1650

Therefore, 1650 commuters take either the bus or the subway (or both). To find the number of commuters who take both the bus and the subway, we subtract the number of commuters who take neither:

Number of commuters who take both the bus and the subway = A ∪ B - Neither

Number of commuters who take both the bus and the subway = 1650 - 180

Number of commuters who take both the bus and the subway = 1470

Therefore, 1470 commuters take both the bus and the subway.

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Answer:

A)  x³+y³

Step-by-step explanation:

The information that is needed to write the equation of a line in point-slope form is the location of one ordered pair that lies on the line and the line's slope. The correct option is the first option

From the question, we are to determine the information that is needed to write the equation of a line in point-slope form.

The point-slope form of a line is given as

y - y₁ = m(x - x₁)

Where, (x₁, y₁) is a point on the line

and m is the slope of the line

Thus, in order to write the equation of a line in the point-slope form, the information that are needed are:

1. An ordered pair on the line

2. The slope of the line

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Answer:

A

Sorry I just have to right more to turn it in but good luck with your math work.

Answer: it's the first option.

Step-by-step explanation: i just graphed it out, and it showed as the y-intercept was -1.5, and the x-intercept was -1.

Answer: A

Step-by-step explanation:

took the test

No, it is not possible for a power series centered at 0 to converge for x = 1, diverge for x = 2, and converge for x = 3.

By the properties of power series, if a power series centered at 0 converges for a value x = a, then it converges absolutely for all values of x such that |x| < |a|.

Conversely, if a power series centered at 0 diverges for a value x = b, then it diverges for all values of x such that |x| > |b|.

Therefore, if a power series converges for x = 1 and diverges for x = 2, then it must also diverge for all values of x such that |x| > 1.

Similarly, if a power series converges for x = 3, then it must converge for all values of x such that |x| < 3.

Since the interval (1, 2) and (2, 3) are disjoint, it is not possible for a power series to converge for x = 1, diverge for x = 2, and converge for x = 3.

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4. f(x,y) is homogeneous of degree 2.

5. a) f(x,y) is homothetic with h(x,y) = xy and g(x) = x-1

4. Show that f(x,y)=\(x^2\)y is homogeneous, and find its degree of homogeneity:

A function is said to be homogeneous of degree k, if it satisfies the condition:

f(tx,ty) = \(t^k\)f(x,y)

We have f(x,y) = \(x^2\)y. Let’s check if it satisfies the above condition:

f(tx,ty) = \((tx)^2(ty) = t^3x^2y = t^2(x^2y\)) = \(t^2\)f(x,y)

Hence f(x,y) is homogeneous of degree 2.

5. Which of the following functions f(x,y) are homothetic? Explain.

(a) f(x,y)=\((xy)^2\)+1

(b) f(x,y)=\(x^2+y^3\)

Let us first understand the meaning of homothetic transformation.

A homothetic transformation is a non-rigid transformation of the Euclidean plane that preserves the direction of the straight lines but not their length. It stretches or shrinks the plane by a constant factor called the dilation.

Let’s now find out whether the given functions are homothetic or not.

(a) f(x,y)=\((xy)^2\)+1

In order to check if f(x,y) is homothetic or not, we need to check if the function satisfies the following condition:

f(x,y) = g(h(x,y))

where g is a strictly monotonic function and h is a homogeneous function with degree 1

We have

f(x,y) = \((xy)^2\)+1

Let’s assume g(x) = x - 1, then g(x+1) = x

Similarly, let’s assume h(x,y) = (xy), then h(tx,ty) = \(t^2\)h(x,y)

Now, we have

g(h(x,y)) = h(x,y) - 1 = (xy) - 1

Thus f(x,y) is homothetic with h(x,y) = xy and g(x) = x-1

(b) f(x,y)=\(x^2+y^3\)

We can’t write this function in the form f(x,y) = g(h(x,y)) where h(x,y) is a homogeneous function with degree 1. Hence this function is not homothetic.

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If A, B, and C are nxn invertible matrices, the equation   C^-1(A+X)B^-1=I(n) has a solution which is X=CB-A. Since invertible matrices are those whose inverse matrix exists.

For A to be the matrix  here A⁻¹ is the inverse of it, so AA⁻¹=I, here I is the identity matrix ,since the matrix equation given to us is: C⁻¹(A+X)B⁻¹=In, now multiplying B on the right side and  C on the left side we get :CC⁻¹(A+X)B⁻¹B=CIₙB

=>Iₙ(A+X)Iₙ=CIₙB

=>A+X=CB, according to the property  of the identity matrix.Now adding -A on both sides we get,

=>A+X+(-A)=CB+(-A)

=>X=CB-A, so here the solution for the given matrix equation is: X=CB-A

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Answer:

x = -8

Step-by-step explanation:

16 = -2x

x = 16/-2

  = -8

BRAINLIEST.

SIMPLE AND EZ.

Answer:

-8

Step-by-step explanation:

-8

x =-8

x =-16 /-2

ok give me five star

Answer:

A and E

Step-by-step explanation:

This is an example of the distributive property.

28n-25 is the base

E shows 7(4n-5)

7*4=28=28n

7*5=35

7(4n-5)=28n-35

Answer:

the tank is 3 feet deep

Step-by-step explanation:

I got 15.65 then rounded up to 3

The maximum value of the objective function z is 19, and it occurs at the point (5, 1).Hence, the optimal solution is (5, 1), and the optimal value of the objective function is 19.

1. Graphically determine the optimal solution, if it exists, and the optimal value of the objective function of the following linear programming problems.
maximize z = x₁ + 2x₂ subject to 2x1 +4x2 ≤6, x₁ + x₂ ≤ 3, x₁20, and x2 ≥ 0.

To solve the given linear programming problem, the constraints are plotted on the graph, and the feasible region is identified as shown below:

Now, To find the optimal solution and the optimal value of the objective function, evaluate the objective function at each corner of the feasible region:(0, 3/4), (0, 0), and (3, 0).

        z = x₁ + 2x₂ = (0) + 2(3/4)

                    = 1.5z = x₁ + 2x₂ = (0) + 2(0) = 0

                        z = x₁ + 2x₂ = (3) + 2(0) = 3

The maximum value of the objective function z is 3, and it occurs at the point (3, 0).

Hence, the optimal solution is (3, 0), and the optimal value of the objective function is 3.2.

maximize subject to z= X₁ + X₂ x₁-x2 ≤ 3, 2.x₁ -2.x₂ ≥-5, x₁ ≥0, and x₂ ≥ 0.

To solve the given linear programming problem, the constraints are plotted on the graph, and the feasible region is identified as shown below:

To find the optimal solution and the optimal value of the objective function,

        evaluate the objective function at each corner of the feasible region:

                                (0, 0), (3, 0), and (2, 5).

                          z = x₁ + x₂ = (0) + 0 = 0

                          z = x₁ + x₂ = (3) + 0 = 3

                           z = x₁ + x₂ = (2) + 5 = 7

The maximum value of the objective function z is 7, and it occurs at the point (2, 5).

Hence, the optimal solution is (2, 5), and the optimal value of the objective function is 7.3.

maximize z = 3x₁ +4x₂ subject to x-2x2 ≤2, x₁20, and X2 ≥0.

To solve the given linear programming problem, the constraints are plotted on the graph, and the feasible region is identified as shown below:

To find the optimal solution and the optimal value of the objective function, evaluate the objective function at each corner of the feasible region:(0, 1), (2, 0), and (5, 1).

                         z = 3x₁ + 4x₂ = 3(0) + 4(1) = 4

                      z = 3x₁ + 4x₂ = 3(2) + 4(0) = 6

                      z = 3x₁ + 4x₂ = 3(5) + 4(1) = 19

The maximum value of the objective function z is 19, and it occurs at the point (5, 1).Hence, the optimal solution is (5, 1), and the optimal value of the objective function is 19.

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Answer:

y=2/5x+62/5

Step-by-step explanation:

Answer:

C)-1

Step-by-step explanation:

You can not spend a negative hour playing golf.

The domain of the function, t = 25x + 12.50 is x ≥ 0, hence the negative value is not a part of the domain, so option C is correct.

The function is a relationship between a set of potential outputs and a set of possible inputs, where each input has a single relationship with each output. This means that if an object x is present in the set of inputs (also known as the domain), then a function f will map that object to exactly one object f(x) in the set of potential outputs (called the co-domain).

Given:

The function of the total cost,

t = 25x + 12.50

Here when you put a negative value of x then the result will be negative, but the cost can not be negative and the value of time also can't be negative,

Domain of function = x ≥ 0

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(a) Country X's economy can be illustrated on a production possibilities curve (PPC) with increasing opportunity cost. The current operating point is labeled as point X.

(b) If the government of Country X reduces tax rates on interest earned from household savings, the national savings would increase. This is because lower tax rates provide an incentive for individuals to save more of their income.

(c) On a loanable funds market graph, the policy change mentioned in part (b) would shift the demand curve for funds to the right, leading to an increase in the equilibrium real interest rate and equilibrium quantity of funds.

(d) Assuming Country X is still maximizing resource use, the change in real interest rates would affect the PPC graph from part (a). A higher real interest rate would lead to a decrease in investment, shifting the PPC inward, resulting in a new production point labeled as point R.

(e) In the long run, the long-run aggregate supply of Country X would stay the same. Changes in real interest rates in the short run do not impact the potential output of an economy.

(a) Country X's economy is represented on a production possibilities curve (PPC), which shows the maximum combinations of consumer goods and capital goods that can be produced with the given resources and technology. Assuming increasing opportunity cost, the PPC would be concave, reflecting the trade-off between producing different types of goods. Point X on the curve represents the current operating point of the economy, where resources and employment are maximized.

(b) Reducing tax rates on interest earned from household savings would incentivize individuals to save more. This increase in savings would contribute to national savings. When individuals save more, it means they are consuming less of their income, allowing resources to be allocated towards investment. As a result, the national savings would increase.

(c) The policy change mentioned in part (b) would impact the loanable funds market. Lower tax rates on interest earned would increase the supply of loanable funds. This would shift the supply curve to the right, leading to a decrease in the equilibrium real interest rate and an increase in the equilibrium quantity of funds. The lower real interest rate would incentivize borrowing and investment, stimulating economic growth.

(d) Assuming Country X is still maximizing resource use, a change in real interest rates would impact the PPC graph from part (a). An increase in real interest rates would raise the cost of borrowing for firms, reducing their investment. This decrease in investment would result in a decrease in the production capacity of the economy, shifting the PPC inward. The new production point, labeled as point R, would reflect the short-run impact of the change in real interest rates.

(e) In the long run, changes in real interest rates do not affect the potential output or long-run aggregate supply of an economy. The long-run aggregate supply is determined by the economy's available resources, technology, and efficiency. While changes in real interest rates may impact investment and production in the short run, they do not alter the economy's productive capacity in the long run. Therefore, the long-run aggregate supply of Country X would stay the same.

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a) the dimension of its column space is also 2. b) the rank of A is 2. c) the nullity of matrix A is 1. d) the dimension of the solution space of the homogeneous system \(A_x = 0\) is also 1.

(a) The dimension of the row space of a matrix is equal to the dimension of its column space. So, if the dimension of the row space of matrix A is 2, then the dimension of its column space is also 2.

(b) The rank of a matrix is defined as the maximum number of linearly independent rows or columns in the matrix. Since the dimension of the row space of matrix A is 2, the rank of A is also 2.

(c) The nullity of a matrix is defined as the dimension of the null space, which is the set of all solutions to the homogeneous equation Ax = 0. In this case, the matrix A is a 3 x 3 matrix, so the nullity can be calculated using the formula:

nullity = number of columns - rank

nullity = 3 - 2 = 1

Therefore, the nullity of matrix A is 1.

(d) The dimension of the solution space of the homogeneous system Ax = 0 is equal to the nullity of the matrix A. In this case, we have already determined that the nullity of matrix A is 1. Therefore, the dimension of the solution space of the homogeneous system \(A_x = 0\) is also 1.

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The population of the study is club members who were asked whether they preferred a new sauna or new steam room

Answer:

36:12. 36 is the teeth on the front socket and 12 is the teeth on the rear socket. All you need to do is simplify by finding the greatest common factor (GCF) of 36 and 12-which is 12, then divide by the GCF. This gives you 3:1. The gear ratio for the bike is 3 teeth on the front socket for every 1 teeth on the rear socket (3:1)

If you want to add friends on brainly click their profile picture you will see send friend request click on it and then boom you are friends with that person but you have to wait until the person add you back.

Step-by-step explanation:

Mark me as brainliest

The ratio would start as 36:12

The front number (36) can be divided by the back number (12)

The 36:12 can be reduced to 3:1

The ratio is 3:1

I think when you click on someone name and go to their profile there is a button to request as a friend.

n = ceil(sqrt((2008/4phi)[90 - arccos(k(2 cos(phi/2008)))]))

       2 [cos(alpha) sin(alpha) + cos(4 alpha) sin(2 alpha) + cos(9 alpha) sin(3 alpha) + ... + cos(n^2 alpha) sin(n alpha)]

     = [sin(2 alpha) + sin(8 alpha) + sin(18 alpha) + ... + sin(n^2 alpha)].

        sin(2 alpha) + sin(8 alpha) + sin(18 alpha) + ... + sin(n^2 alpha)

     = (sin(2 alpha) - sin(2n^2 alpha))/(1 - sin(2 alpha))

     = (2 sin(n^2 alpha) cos(n^2 alpha))/(2 cos(alpha) - 1)

     = [sin(2n^2 phi/2008)]/(2 cos(alpha) - 1)

        [sin(2n^2 phi/2008)]/(2 cos(alpha) - 1)

        sin(2n^2 phi/2008) = k(2 cos(alpha) - 1)

        cos(90 - 2n^2 phi/2008) = k(2 cos(alpha) - 1)

       90 - 2n^2 phi/2008 = ±arccos(k(2 cos(alpha) - 1))

       n^2 = (2008/4phi)[90 ± arccos(k(2 cos(alpha) - 1))]

       n = ceil(sqrt((2008/4phi)[90 - arccos(k(2 cos(phi/2008)))]))

We can find the smallest positive integer n by incrementing the value of k starting from 1 until ceil(k^2*alpha) is greater than or equal to n.

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The derivative of the function f(x) = \(6 + 7/x + 2/x^2\) is f'(x) =\(-7/x^2 - 4/x^3\). Evaluating the derivative at x = 2, we find f'(2) = -7/4 - 4/8 = -7/4 - 1/2 = -9/4.

To find the derivative of f(x), we use the power rule and the quotient rule. The power rule states that if we have a term of the form\(ax^n,\) the derivative is given by \((d/dx)(ax^n) = anx^(n-1)\). Applying this rule to the terms 7/x and \(2/x^2\), we get\(-7/x^2\) and -\(4/x^3\), respectively.

Next, we add the derivatives of the individual terms to find the derivative of the entire function. Thus, f'(x) = \(-7/x^2 - 4/x^3\).

To find f'(2), we substitute x = 2 into the derivative expression. We get f'(2) = -\(7/(2^2) - 4/(2^3) = -7/4 - 4/8 = -7/4 - 1/2 = -9/4\). Therefore, f'(2) is equal to -9/4.

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The solution to the given differential equation that satisfies the initial condition P(1) = 3 is

\(P(t) = 3e^(t-1).\)

To solve the differential equation, we can start by separating the variables and integrating. The given equation is dP/dt = Ce, where C is a constant.

Separating the variables:

dP/Ce = dt

Integrating both sides:

∫ dP/Ce = ∫ dt

Applying the integral:

ln|P| = t + K, where K is the constant of integration

Simplifying the natural logarithm:

ln|P| = t + ln|C|

Using properties of logarithms, we can combine the logarithms into one:

ln|P/C| = t + ln|e|

Simplifying further:

ln|P/C| = t + 1

Exponentiating both sides:

|P/C| = e⁽ᵗ⁺¹⁾

Removing the absolute value:

P/C = e⁽ᵗ⁺¹⁾ or P/C = -e⁽ᵗ⁺¹⁾

Multiplying both sides by C:

P = Ce⁽ᵗ⁺¹⁾ or P = -Ce⁽ᵗ⁺¹⁾

To find the particular solution that satisfies the initial condition P(1) = 3, we substitute t = 1 and P = 3 into the equation:

3 = Ce¹

Simplifying:

3 = Ce²

Solving for C:

C = 3/e²

Substituting the value of C back into the general solution, we get the particular solution:

P(t) = (3/e²)e⁽ᵗ⁺¹⁾

Simplifying further:

P(t) = 3e₍ₜ₋₁₎

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The histogram shows that the most common audit time is between 13 and 17 days, and the least common audit time is between 21 and 25 days.

Frequency, Cumulative Frequency, and Cumulative Percent Frequency Table:

The histogram shows that the most common audit time is between 13 and 17 days, and the least common audit time is between 21 and 25 days.

Frequency, Cumulative Frequency, and Cumulative Percent Frequency Table:

Year-end Audit Time (in Days)        Frequency        Cumulative Frequency        Cumulative Percent Frequency

13        3        3        15.00%

14        1        4        20.00%

15        1        5        25.00%

17        2        7        35.00%

19        1        8        40.00%

21        1        9        45.00%

22        1        10        50.00%

24        1        11        55.00%

25        1        12        60.00%

26        1        13        65.00%

27        1        14        70.00%

29        2        16        80.00%

30        1        17        85.00%

32        3        20        100.00%

b. Histogram Chart:

30  |                        

   |                        

   |                        

   |                        

25  |                        

   |             *          

   |             *          

   |             *          

20  |                        

   |             *          

   |             *          

   |             *          

15  |  *          *     *      

   |  *          *     *      

   |  *          *     *      

   |  *     *    *     *      

10  |  *     *    *     *      

   |  *     *    *     *      

   |  *     *    *     *      

   |  *     *    *     *      

   |------------------------

      13    17    21    25    29    33

In the histogram, the horizontal axis shows the range of values of the year-end audit time (in days), and the vertical axis shows the frequency. The asterisks (*) represent the frequency of each range. The histogram shows that the most common audit time is between 13 and 17 days, and the least common audit time is between 21 and 25 days.

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