Answer: -1/3
Step-by-step explanation:
Because 0.3333 is a decimal and -1/3 is a fraction.
The value of x of the given equation −3.7 = −5.4x − 5.5 will be -0.33.
What is the equation?There are many different ways to define an equation. The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.
As per the given equation,
−3.7 = −5.4x − 5.5
5.4x = -5.5 + 3.7
x = -0.33
Hence "The value of x of the given equation −3.7 = −5.4x − 5.5 will be -0.33".
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Make w the subject of the formula 4(g-w)=5w-3
Answer:
Step-by-step explanation:
5w - 3 = 4g - 4w
9w - 3 = 4g
9w = 4g + 3
w= (4g + 3)/9
The box plots display data collected when two teachers asked their classes how many pencils they lose in a school year.
A box plot uses a number line from 5 to 47 with tick marks every one unit. The box extends from 8 to 14 on the number line. A line in the box is at 11. The lines outside the box end at 7 and 45. The graph is titled Mr. Johnson's Class, and the line is labeled Number Of Pencils.
A box plot uses a number line from 0 to 51 with tick marks every one unit. The box extends from 12 to 21 on the number line. A line in the box is at 14.5. The lines outside the box end at 0 and 50. The graph is titled Mr. Simpson's Class, and the line is labeled Number Of Pencils.
Which class lost the most pencils overall based on the data displayed?
Mr. Simpson's class; it has a larger median value 14.5 pencils
Mr. Johnson's class; it has a larger median of 11 pencils
Mr. Simpson's class; it has a narrow spread in the data
Mr. Johnson's class; it has a wide spread in the data
Answer:
A) Mr. Simpson's class; it has a larger median value 14.5 pencils.
Step-by-step explanation:
A box plot is a visual display of the five-number summary:
Minimum value = The value at the end of the left whisker.Lower quartile (Q₁) = The left side of the box.Median (Q₂) = The vertical line inside the box.Upper quartile (Q₃) = The right side of the boxMaximum = The value at the end of the right whisker.From inspection of the box plots (attached), the measures of central tendency (median) and dispersion (range and IQR) are:
Mr Johnson's class:
Median = 11IQR = Q₃ - Q₁ = 14 - 8 = 6Range = max - min = 45 - 7 = 38Mr Simpson's class:
Median = 14.5IQR = Q₃ - Q₁ = 21 - 12 = 9Range = max - min = 50 - 0 = 50In a box plot, the median is a measure of central tendency and tells us the location of the middle value in the dataset. It divides the data into two equal halves, with 50% of the values falling below the median and 50% above it.
The median number of pencils lost in Mr Simpson's class is greater than the median number of pencils lost in Mr Johnson's class. Therefore, Mr. Simpson's class has a larger median value.
The spread of data in a dataset can be measured using both the range and the interquartile range (IQR).
As Mr Simpson's class has a greater IQR and range than Mr Johnson's class, the data in Mr Simpson's class is more spread out than in Mr Johnson's class.
In summary, as Mr Simpson's class has a larger median 14.5 and a wider spread of data, then Mr Simpson's class lost the most pencils overall.
BONJOUR AIDEZ MOI SIL VOUS PLAIT
The distance from the center of the Earth to the point where the net gravitational force is zero is one-ninth the distance from the Earth to the Moon.
Let's assume that the distance from the center of the Earth to this point is denoted as x.
Given:
Mass of the Moon (M\(_{moon}\)) = 1/81 × M\(_{earth}\)
Distance from Earth to Moon (d\(_{moon}\)) = distance on center
According to the principle of gravitational equilibrium, the gravitational force from the Earth and the gravitational force from the Moon acting on an object at that point must balance out. Mathematically, we can express this as:
F\(_{earth}\) = F\(_{moon}\)
The gravitational force between two objects can be calculated using Newton's law of universal gravitation:
F \(_{gravity}\)= G × (m₁ × m₂) / r²
Where:
G is the gravitational constant (approximately 6.67430 x 10⁻¹¹m²/kg/s²)
m₁ and m₂ are the masses of the two objects
r is the distance between the centers of the two objects
Considering the gravitational forces involved:
F\(_{gravity}\)\(_{earth}\) = G ₓ (M\(_{EARTH}\) ₓ m\(_{OBJECT}\)) / (d\(_{earth}\))²
F\(_{gravity}\) \(_{moon}\) = G ₓ (M \(_{moon}\) ₓ m\(_{object}\)) / (d \(_{moon}\))²
Since we are looking for the point where the net gravitational force is zero, we set these two forces equal to each other:
G × (M\(_{earth}\) × m\(_{object}\)) / (d\(_{earth}\))² = G × (M \(_{moon}\) × m\(_{object}\)) / (d \(_{moon}\))²
Canceling out the common factors of G and m\(_object}\), and substituting the given values:
(M\(_{earth}\) × 1) / (d\(_{earth}\))² = (M \(_{moon}\) × 1) / (d \(_{moon}\))²
Rearranging the equation:
(d\(_{earth}\))²/ (M\(_{earth}\)) = (d \(_{moon}\))² / (M \(_{moon}\))
Taking the square root of both sides:
d\(_{earth}\) / √(M \(_{moon}\))) = d_moon / √(M \(_{moon}\))
Substituting the given values:
d\(_{earth}\) /√(M\(_{earth}\)) = d\(_{moon}\) / √(1/81 × M\(_{earth}\))
Simplifying further:
d\(_{earth}\) / √(M\(_{earth}\)) =d\(_{moon}\) / (1/9 × √(M\(_{earth}\)))
Multiplying both sides by √(M\(_{earth}\)):
d\(_{earth}\) = (1/9) × d\(_{moon}\)
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What is the slope of the line on the graph below?
In the 2012 Olympics a U.S. athlete Nathan Adrian finished the 100-meter freestyle swim in 47.52 seconds. If nathan swam the same pace in a regular 25-meter pool what would his time have been per lap?
At the same rate as his 100-meter freestyle swim in the 2012 Olympics, Nathan Adrian could have completed one loop of a 25-meter pool in 11.88 seconds.
To solve this problem
The idea of proportionality can be applied. The time it would take Nathan Adrian to complete one lap in a 25-meter pool is known to be 47.52 seconds for the 100-meter freestyle. Since the tempo is constant while the distance varies, we can establish a ratio:
100 meters / 47.52 seconds = 25 meters / x seconds
where x is the unknown time for one lap in the 25-meter pool.
To solve for x, we can cross-multiply:
100 meters * x seconds = 47.52 seconds * 25 meters
100x = 1188
Dividing both sides by 100, we get:
x = 11.88 seconds
Therefore, at the same rate as his 100-meter freestyle swim in the 2012 Olympics, Nathan Adrian could have completed one loop of a 25-meter pool in 11.88 seconds.
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find the selling price for the item flash drive: $12 markup:35%
Answer:
16.2
Step-by-step explanation:
12*1.35=16.2
(can I get brainliest pls)
The rate of growth of the population of a city is predicted to be the following, where p is the population at time t is measured in years from the present. dp dt = 1000t1.07 Suppose that the current population is 100,000. (a) What is the predicted rate of growth 7 years from the present? (Round your answer to the nearest integer.) people per year (b) What is the predicted population 7 years from the present? (Round your answer to the nearest integer.)
predicted rate of growth of population after 7 years = 7490.
Population 7 years from the present = 126215
What is population growth rate?Generally, rate of change of population over the time is termed as population growth rate.
What is the predicted rate of growth 7 years from the present and predicted population 7 years from the present?
given, rate of growth of population of a city, dp/dt = 1000t ×1.07
where. p is the population at time t.
predicted rate of growth 7 years from the present = 1000×7×1.07
= 7490
we rewrite the equation, dp = (1000t ×1.07)dt
integrating the both side,
∫dp = ∫dt (1000t×1.07)
p = 1/2 (1070 t²) +c [ c is integration constant]
p = 535 t² + c
we are given. current population = 100000
let, at present time t = 0
100000 = 0 + c
c = 100000
hence, predicted population after 7 years from present, p = 535 × (7)² + 100000
p = 126215
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The figure shows three tennis balls in a can with each tennis ball having a diameter of 2.5 inches. What is the total volume of the air space around the three tennis balls?
The total volume of the air space of spherical ball is A = 12.265625 inches³
Given data ,
Since each tennis ball has a diameter of 2.5 inches, the radius of each ball is 1.25 inches.
The air space around the balls can be thought of as a cylinder with a height equal to the diameter of one ball and a radius equal to the radius of one ball.
The height of the cylinder is 2.5 inches, and the radius is 1.25 inches.
The formula for the volume of a cylinder is:
V = πr²h
V = ( 3.14 ) ( 1.25 )² ( 7.5 )
V = 36.796875 inches³
where V is the volume, r is the radius, and h is the height.
So, the volume of the one ball is:
V₁ = ( 4/3 )π(1.25)³
V₁ = 8.177083 inches³
The total volume of three balls is = volume of 3 spherical balls
V₂ = 3V₁ = 3(8.177083) ≈ 24.53125 cubic inches
Therefore, the total volume of the air space around the three tennis balls is approximately A = 36.796875 inches³ - 24.53125 inches³
A = 12.265625 inches³
Hence , the volume of air space is A = 12.265625 inches³
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. In a fort, there were provisions for 400 men for 23 weeks. 60 more men joined them. How long will the provisions
last?
The additional 60 men, the provisions will last for approximately 20 weeks.
To determine how long the provisions will last with the additional 60 men, we need to consider the total number of people and the original duration the provisions were meant to last.
Originally, the provisions were intended to sustain 400 men for 23 weeks. This means that the provisions were estimated to be sufficient for a total of 400 * 23 = 9200 person-weeks.
Now, with the additional 60 men, the total number of men becomes 400 + 60 = 460.
To calculate how long the provisions will last with the increased number of men, we divide the total person-weeks by the new number of men:
Provisions last = Total person-weeks / Number of men
= 9200 / 460
≈ 20 weeks (rounded to the nearest whole number)
The additional 60 men will extend the supply's shelf life to around 20 weeks.
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the table shows a proportional relationship. what is the unit rate? write an equation that describes the relationship.
The unit rate of a proportional relationship can be found by dividing a value of the dependent variable over the corresponding value of the independent variable.
In this case, the bushels of wheat depend on the number of acres. Then, divide the amount of bushels of wheat by the corresponding number of acres to find the unit rate. Use, for instance, that there are 140 bushels of wheat on 5 acres:
\(\frac{140}{5}=28\)Notice that the same unit rate is found when other pairs of data are used:
\(\begin{gathered} \frac{224}{8}=28 \\ \frac{420}{15}=28 \end{gathered}\)The equation of a proportional relationship between the independent variable x and the dependent variable y with a unit rate k, is:
\(y=kx\)If the unit rate k is equal to 28, then the equation that describes the relationship, is:
\(y=28x\)Therefore, the unit rate is equal to 28 bushels of wheat per acre, and the equation that describes the relationship, is:
\(y=28x\)A die is rolled one thousand times. The percentage of aces should be around ____ or so. the first step iin computing this problem should be
Answer:
Following are the solution to the given question:
Step-by-step explanation:
Please find the complete question in the attached file.
\(Box \ average =\frac{1}{6} \\\\SD = \frac{1}{6} \times \frac{5}{6} = \frac{5}{36} \approx 0.373\\\\Expected \ value= 1000 \times \frac{1}{6} \approx 166.7\\\\SE = 1000 \times 0.373 \approx 11.8\\\\\)
The total number of aces is approximately 167, 12 or more. The SE is 12 out of 1000, which is 1.2 percent.
The percentage of aces is expected to be around 16.67% , or 1.2%.
A right circular cone is intersected by a plane that passes through the cone's
vertex and is parallel to its base, as in the picture below. What is produced
from this intersection?
OA. A pair of intersecting lines
OB. A point
OC. A pair of parallel lines
OD. A parabola
Answer:
B. A point
Step-by-step explanation:
You want a description of the intersection between a plane and a cone given that the plane is parallel to the base and passes through the vertex of the cone.
VertexThe vertex of a cone is a single point. If a plane passes through that, but does not intersect the base of the cone, it will not intersect anywhere else.
The intersection is one point.
__
Additional comment
Figure f in the attachment illustrates this case.
The weights X of an animal are distributed according to the
probability distribution shown.
What is the probability that the animal's weight will be less than
151 pounds?
O 0.25
O 0.50
O 0.60
O 0.75
The probability that the animal's weight will be less than 151 pounds is 0.50.
The correct option is B.
What is the probability that the animal's weight will be less than 151 pounds?Since the given probability distribution ranges from 148 to 152, and we need to find the probability that the animal's weight will be less than 151 pounds, we can add the probabilities corresponding to the weights less than 151.
From the distribution, we see that the probability of the animal's weight being less than 151 pounds is 0.2 + 0.3 = 0.5.
Therefore, the answer is O 0.50.
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A bank wants to estimate the difference in the proportion of its "big" customers who have a second account with a different bank and the proportion of its "small" customers who also have an account with another bank. Of the 200 “big” customers who were randomly selected, 160 claimed to also bank with other banks. Of the 300 “small” customers who were randomly selected, 120 claimed to also bank with other banks.
Based on the 99% confidence interval (0.297, 0.503), is there convincing evidence of a difference in the proportion of “big” bank customers who bank with more than one bank as compared with the “small” customers who bank with more than one bank?
Because
contained in the interval, there is
to believe there
a difference in the proportion of “big” bank customers who bank with more than one bank as compared to the “small” customers who bank with more than one bank.
Yes, based on the 99% confidence interval (0.297, 0.503), there is convincing evidence of a difference in the proportion of "big" bank customers who bank with more than one bank compared to the "small" customers who bank with more than one bank.
The confidence interval (0.297, 0.503) represents the range of values within which the true difference in proportions between the two customer groups is likely to fall with 99% confidence. Since the interval does not include zero (0), we can conclude that there is a statistically significant difference between the proportions.
To further explain, the confidence interval was constructed using the sample proportions and the standard error. The sample proportion for the "big" customers who bank with other banks is 160/200 = 0.8, and for the "small" customers, it is 120/300 = 0.4. The standard error takes into account the sample sizes and proportions, and it measures the uncertainty in the estimation.
Since the confidence interval does not include zero, it indicates that the true difference in proportions is unlikely to be zero. In other words, there is strong evidence that the proportion of "big" bank customers who bank with more than one bank is higher than the proportion of "small" customers who do the same.
Therefore, based on the provided data and the confidence interval, we can conclude that there is convincing evidence of a difference in the proportion of "big" bank customers who bank with more than one bank compared to the "small" customers who bank with more than one bank.
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Which best describes the composition of tranformations that maps ∆LMN to ∆L'M'N'. 0,0 is the center of the dilation in each choice.
A. a reflection over the line y=3 followed by a dilation of scale factor 2
B. a dilation of scale factor 2 followed by a dilation of scale factor 12
C. a dilation of scale factor 12 followed by a translation left 1 down 3
D. a dilation of scale factor 2 followed by a translation right 1 up 3
Triangle LMN was dilated by a scale factor of 2 followed by a translation 1 unit right and 3 unit up to form triangle L'M'N'
What is transformation?Transformation is the movement of a point from its initial location to a new location. Types of transformations are reflection, translation, rotation and dilation.
Rigid transformation preserves the shape and size of the figure. Reflection, translation, rotation are rigid transformations.
Triangle LMN was dilated by a scale factor of 2 followed by a translation 1 unit right and 3 unit up to form triangle L'M'N'
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Indicate whether the sentence or statement is true or false. (2 + 3) + 5 = 2 + (3 + 5)
Answer:
True
Step-by-step explanation:
(2 + 3) + 5 = 2 + (3 + 5)
5+5=2+8
10=10
this statement is true
Find (g ○ f )(x ) where `f(x)=x2+8,g(x)=5x-2.
Answer:
(g ○ f)(x) = 5x² + 38
Step-by-step explanation:
to find (g ○ f)(x) substitute x = f(x) into g(x) , that is
g(f(x)
= g(x² + 8)
= 5(x² + 8) - 2
= 5x² + 40 - 2
= 5x² + 38
If the length of each square represents 100 miles, what is the distance between Airport X and Airport Y?
Answer:
Out of all possible choices you've shown, I'd say the best answer would be A
Step-by-step explanation:
Find the product
3(z+4)(x-5)
Answer:
3zx-15z+12x-60
Step-by-step explanation:
first do parenthesis and distribute (z+4)(x-5) into zx-5z+4x-20
then distribute the 3 to get the answer
3. When we simplify radicals containing variables with exponents, we are tasked first withidentifying if the exponent is perfect. What do you look for to determine if an expression withexponents("power") is perfect? Be specific and use a complete sentence.
When we simplify more complicated radical expressions, we will see that writing radicals with rational exponents can make things simpler.
Define radical.Any expression that contains the radical (√) sign is referred to as a radical expression in mathematics. This symbol, which is frequently used to calculate the square root of a number, is frequently called the "square root" symbol by mistake. But it can also refer to a cube root, a fourth root, or something higher.
Given,
When we simplify radicals containing variables with exponents, we are tasked first with identifying if the exponent is perfect.
When we simplify more complicated radical expressions, we will see that writing radicals with rational exponents can make things simpler. Algebraic expressions can be expressed and written in a variety of ways, giving us more freedom in how we solve and simplify them. When writing, it's like having a thesaurus; you want to have a variety of ways to express yourself. Fractional exponents and radicals are two different ways to say the same idea.
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Which set of measurements could be the side lengths of a triangle?
A.2 cm, 8 cm, 12 cm
B.9 cm, 4 cm, 4 cm
C.13 cm, 7 cm, 4 cm
D.7 cm, 10 cm, 8 cm
what is 3.5 multiplied by 15.2 please
what is 3.5 multiplied by 15.2
|| Answer ||3.5 × 15.2 = 53.2 [ Refer the attachment ]
____________________Explanation :-
First multiply the numbers.
Then,
In the First number and the Second number,
That is 15.2 and 3.5
In these numbers, We have the point before one number if we count from last.
So, To the product, That is 53.20..
From the last, we have to count.. two places and put the point.
After placing the point,
The Product will be 53.20 = 53.2
Hello random community i have a question to ask what is 7/8 - 3/4
Answer: 1/8
Step-by-step explanation:
First make the bottom half the same:
3/4*2/2=6/8
We don’t need to change the first portion since they have a common factor
7/8-6/8=1/8
Identify the unit rate in each graph. Then, order the graphs by unit rate, from least to greatest.
The required rates are: Unit rate of graph K = 3, Unit rate of graph P = 0.5, and Unit rate of graph F = 1. The order from lower to greater is Graph P, graph F, graph K
How did we determine their unit rates?Step 1: As we know that Unit Rate
Step 2: Notice that the in graph K line passes through the point (1,3)
Step 3: (1,3)
It means the value of function is 3 when x= 1
Step 4: So the unit rate of graph K is, 3/1
Step 5: Simplify the expression.
3/1 = 3
Step 6: Similarly we can see that the graph P have the point (2, 1)
Step 7: So the unit rate of graph P will be 1/2
Step 8: Simplify the expression.
1/2 = 0.5
Step 9: The graph F have point (1, 1) so it have unit rate of 1/1
Step 10: Simplify the expression.
1/1 = 1
Step 11: So we have unit rate of graph K = 3, F= 1 and graph P = 0.5
Step 12: Putting them in least to greater order as,
0.5, 1, 3
It follows that;
graph P, graph F, graph K
Therefore, the required answer is,
Unit rate of graph K = 3
Unit rate of graph P = 0.5
Unit rate of graph F = 1
And the order from lower to greater is, Graph P, graph F, graph K
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is -4 greater than -1/4
Answer:
No
Step-by-step explanation:
You would think -4 is, but because they are both negative, -1/4 is closer to zero
Answer:
no
Step-by-step explanation:
think of in a way where the number that's closest to 0 is bigger
The coordinates of the midpoints of the four sides of a square are S(-4,11), Q(2,5), U(-4,-1), A (-10,5)
The perimeter and area of the square are; 24√2 units and 12 units² respectively
Given the coordinates of the midpoints of the four sides of a square are S(-4,11), Q(2,5), U(-4,-1), A (-10,5)
But since we have the midpoints of all the sides, we can assume they're equidistant from one another since the figure is a square.
SQ = √(x₂ - x₁)² + (y₂ - y₁)²
SQ = √(2 - (-4)² + (5 - 11)²
SQ = 6√2
Let's find QU
QU = √(-4 - 2)² + (-1 - 5)²
QU = 6√2
Let's find UA ;
UA = √(-10 - (-4))² - (5 - (-1)²
UA = 6√2
And the distance AS = 6√2
The perimeter of the square = 4 (6√2)
Perimeter = 24√2 units
The area of the square = l²
Area of the square = (6√2)²
Area of square = 12 units²
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21.5 sq. Cm
43 sq. Cm
100 sq. Cm
68.6 sq. Cm
\( \large \boxed{ \boxed{ \mathrm{21.5 \: \: cm {}^{2}} }}\)
Solution :By Observing the Above figure, we can conclude that the area of shaded region is equal to the Area of Square minus the sum areas of two equal semicircles (since their diameters are equal)
let's solve for area of square :
\(\longrightarrow \: \mathrm{side {}^{2} }\)
\(\longrightarrow10 {}^{2} \)
\(\longrightarrow \mathrm{100 \: cm {}^{2} }\)
Now,
Radius of the both semicircles measure :
\(\longrightarrow \dfrac{10}{2} \)
\(\longrightarrow5 \: cm\)
now, let's solve for their area
\( \longmapsto 2 \times \dfrac{\pi {r}^{2} }{2} \)
(Since, there are two semicircles)
\(\longrightarrow3.14 \times 5 \times 5\)
\(\longrightarrow78.5 \: cm {}^{2} \)
Area of Shaded region = Area of Square - Area of Semicircles, that is
\(\longrightarrow100 - 78.5\)
\(\longrightarrow \mathrm{21.5 \: cm {}^{2} }\)
\(\large\mathfrak{{\pmb{\underline{\orange{hope \: it \: helps \: you \: }}{\orange{.....}}}}}\)
help help exponents help
Answer:
3
Step-by-step explanation:
The base is the number below the exponent.
Which statement(s) are true? multiple choice question
Step-by-step explanation:
the more likely an event the closer it is to being certain
the more unlikely an event the closer it is to being impossible
If S is a compact subset of R and T is a closed subset of S, then T is compact. Prove this using the definition of compactness.
Answer:
It has been proved that T is compact
Step-by-step explanation:
To prove this using the definition of compactness, let's assume that T is
not compact. Now, if that be the case, an open cover of T will exist. Let's call this open cover "A". Now, this open cover will have no finite subcover.
Now, from the question, since T is closed, it’s complement R\T will be open.
Therefore, if we add the set R\T to the collection of sets A, then we'll have an open cover of R and also of S.
Due to the fact that S is compact, this
cover will have a finite sub - cover which we will call B.
Finally, either B itself or B\{R\T} would be a finite sub - cover of A. This is a contradiction.
Thus, it proves that T has to be compact if S is to be a compact subset of R and T is to be a closed subset of S.