Need help on number 5. Super complex. Have had some tutors that can’t answer.

All of that energy is used to compress the bumper by x, which is equal to 6 inches, or 0.5 feet, and it is stored as spring potential energy in the bumper. (1/2)*k*x2 is the formula for that energy.So, (1/2)*m*u2 = (1/2)*k*x2 Simplifying and rearranging results in k = (m*u2) / x2 Based on the data provided, k = 20 000 lb/ft.

Energy is the capacity to work in physics. It could be potential, kinetic, thermal, electrical, chemical, nuclear, or some other form. Heat and work are also present—for instance when energy is transferred from one body to another.

The body's mass (m) will change by an amount equal to E/c2 whenever the body's energy changes in any form, as shown by the Albert Einstein equation, commonly stated as E = mc2.

Energy is defined as the "ability to do work, which is the ability to exert a force causing the displacement of an object." The meaning is quite clear, despite this perplexing definition: Energy is the only thing that moves things. Energy can be divided into two categories: potential and kinetics

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The acceleration of the car is 0.5 meters per seconds square.

Given the following data:

Note: The final velocity (V) of the car would be zero (0) m/s when it comes to a stop.

To find the acceleration of the car, we would use the third equation of motion;

Mathematically, the third equation of motion is given by the formula;

\(V^2 = U^2 - 2aS\\\\0 = 30^2 - 2a(900)\\\\0 = 900 - 1800a\\\\1800a = 900\\\\a = \frac{900}{1800}\)

Acceleration, a = 0.5 \(m/s^2\)

Therefore, the acceleration of the car is 0.5 meters per seconds square.

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Answer:

Infinity. Yes, specific value of water during phase change is infinity. This is because, as long as water is present and it is changing phase (at boiling point or at any other constant temperature), the temperature of the water does not change no matter what amount of heat you are supplying to the water. Thus, its specific heat value is infinity.

Gerard's average velocity for the ride is 6 meters per second.

To find Gerard's average velocity for the ride, we can use the formula:

Average velocity = Total displacement / Total time

First, we need to convert the distance traveled from kilometers to meters:

7.20 kilometers * 1000 = 7200 meters

Next, we convert the time from minutes to seconds:

20.0 minutes * 60 = 1200 seconds

Now, we can calculate the total displacement by subtracting the initial position from the final position. Since Gerard is riding directly east, there is no change in the east-west direction, so the displacement is equal to the distance traveled:

Total displacement = 7200 meters

Finally, we substitute the values into the average velocity formula:

Average velocity = 7200 meters / 1200 seconds

Average velocity = 6 meters per second

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The psychologist who emphasizes the social learning perspective explain this behavior would say that Ibrahim has observed others who model aggressive behavior. Option B

According to social psychology, aggression refers to any conduct or action intended to hurt a person, an animal, or cause physical injury to property. Here are a few instances of aggressive behavior: physical harm. screaming, cursing, and foul language.

Aggression is an overt or covert social engagement that is frequently harmful and intended to cause harm to another person.

Aggressive behavior is forceful, reactive, and impulsive behavior that frequently leads to breaching social norms or the law.

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Answer:

3m/s

Explanation:

Speed is distance/time,

36m/12s = 3m/s

The value of the rate constant at 457 K is 0.478 M/s.

The rate constant, k, at a given temperature can be related to the activation energy, Ea, and the gas constant, R, through the Arrhenius equation:

\(k = Ae^{(-Ea/RT)}\)

where A is the pre-exponential factor and T is the temperature in Kelvin.

Given k1 = 0.178 M/s at T1 = 280 K, and Ea = 37.8 kJ/mol, we can calculate the rate constant, k2, at T2 = 457 K as:

k2 = A * \(e^{(-Ea/R * T2)}\) = 0.178 * \(e^{(-37.8 kJ/mol / (8.314 J/mol K) * 457 K)}\) = 0.478 M/s.

This means that the reaction will proceed faster at 457 K than it does at 280 K, due to the increase in temperature leading to an increase in the rate constant, k.

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When a clock uses a harmonic oscillator as its timekeeper, the clock will continue to run on time even if the oscillator's amplitude fluctuates.

An oscillator is a mechanical or electronic device that operates according to the oscillation principle, which describes oscillation as a regular fluctuation between two objects caused by changes in energy. Among the various gadgets that use oscillators are computers, clocks, watches, radios, and metal detectors.

A basic form of the mechanical oscillator is a clock pendulum. The oscillation of atoms within the atomic clock, the most precise timekeeper in existence, maintains time. In computers, wireless receivers and transmitters, and audio-frequency devices, in particular music synthesizers, electronic oscillators are used to generate signals. Although there are many different kinds of electronic oscillators, they all work on the same fundamental premise: an oscillator always uses a sensitive amplifier whose output is relayed back to the input in phase.

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The resulting charge in sphere A from the two given different charges is determined as +2 μC.

The resulting charge of the two spheres is determined by suming the two individual charges together as shown below;

Resulting charge = +6 μC - 2 μC

Resulting charge = +4 μC

The resulting charge will be distributed uniformly between the two spheres and charge in sphere A and B will be equal.

Charge in sphere A = charge in sphere B = ¹/₂ x +4 μC = + 2 μC

Thus, the resulting charge in sphere A from the two given different charges is determined as +2 μC.

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Answer:

The height from which the diver jumped can be calculated using the laws of motion and the principle of conservation of energy.

Let's assume that the diver jumped from a platform with an initial velocity of zero. The potential energy (PE) of the diver at the top of the platform is given by:

PE = mgh

Where m is the mass of the diver, g is the acceleration due to gravity (9.8 m/s^2), and h is the height from which the diver jumped.

When the diver jumps, the potential energy is converted into kinetic energy (KE) as the diver moves downwards. The kinetic energy of the diver just before hitting the water is given by:

KE = (1/2)mv^2

Where v is the velocity of the diver just before hitting the water.

According to the principle of conservation of energy, the potential energy at the top of the platform is equal to the kinetic energy just before hitting the water. Therefore, we can equate the two equations above and solve for h:

mgh = (1/2)mv^2

h = (1/2)v^2/g

We need to find the value of v to calculate h. We can use the kinematic equation:

v^2 = u^2 + 2as

Where u is the initial velocity (which is zero in this case), a is the acceleration due to gravity (9.8 m/s^2), and s is the distance travelled by the diver (which is equal to h).

Substituting the values, we get:

v^2 = 2gh

v^2 = 2 * 9.8 * h

v^2 = 19.6h

Therefore:

h = v^2/(19.6)

Now, let's assume that the velocity of the diver just before hitting the water was 10 m/s (a reasonable value for a diving competition). Then:

h = (10^2)/(2*9.8) = 51 meters

Therefore, the height from which the diver jumped is approximately 51 meters.

Answer: See explanation

Explanation:

The reason why astronomers think that the rates of impact for the Moon must have been higher earlier than 3.8 billion years ago is because on the older highlands, there are ten times more craters than on the younger maria.

It is believed that the impact rate was higher earlier and thus can be seen when the numbers of the craters that can be seen on the lunar highlands is being compared to that on the maria. It should be noted that there are about 10 times more craters that can be found on the highlands than those on the maria.

If there was a constant rate of impact throughout the history of the Moon, then the highlands be about 10 times older and therefore will have been formed about 38 billion years ago.

The ways to solve this problem is through knowledge dissemination, citizens who were outraged by the article about the negative statements and malicious stories about Filipinos, could submit positive articles about the culture of the Filipino people.

Another way could be through open dialogue, with Filipino internet users, publicly apologizing seeking to become more involved with the Filipino community.

Therefore, the best way to solve the problem is through ethically-based freedom of expression, avoiding stereotypes of a culture you don't belong to, and looking for a way to disseminate respectful and empathetic information about a people.

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The magnitude of the force on the left-hand pole is mathematically given as

f'=0.167N

Q=45 degrees

Generally, the equation for Force is  mathematically given as

\(\frac{mg}{sin \theta}\)

Therefore

\(F=\frac{17.1*10^{-3}*9.8}{sin45}\)

F=0.237N

Considering horizontal axis or plane

f'-fcos=0

Therefore

f'=0.237*cos45

f'=0.167N

In conclusion, the slope

\(tan\theta= 30/30\\\\tan\theta=1\\\\\theta=45\)

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Answer:

penis

Explanation:

Answer:

The 6000 lines per cm grating, will produces the greater dispersion .

Explanation:

A diffraction grating is an optical component with a periodic (usually one  that has ridges or rulings on their surface rather than dark lines) structure that splits and diffracts light into several beams travelling in different directions.

The directions of the light beam produced from a diffraction grating depend on the spacing of the grating, and also on the wavelength of the light.

For a plane diffraction grating, the angular positions of principle maxima is given by

(a + b) sin ∅n = nλ

where

a+b is the distance between two consecutive slits

n is the order of principal maxima

λ is the wavelength of the light

From the equation, we can see that without sin ∅ exceeding 1, increasing the number of lines per cm will lead to a decrease between the spacing between consecutive slits.

In this case, light of the same wavelength is used. If λ and n is held constant, then we'll see that reducing the distance between two consecutive slits (a + b) will lead to an increase in the angle of dispersion sin ∅. So long as the limit of sin ∅ not greater that one is maintained.

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Answer:

When a load resistance is connected, current flows through the cell and a voltage develops across the internal resistance. This voltage is not available to the circuit so it is called the lost volts, .

Explanation:

The initial velocity of the car in m/s is 26.41 m/s

We can convert 95.0 km/hr to m/s as illustrated below:

1 km/h = 0.278 m/s

Therefore,

95 km/h = 95 × 0.278

95 km/h = 26.41 m/s

Thus, the initial velocity in m/s is 26.41 m/s

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v = u + a t

where u = initial velocity (25 m/s), v = final velocity (0), a = acceleration, and t = time (45 s). So

0 = 25 m/s + a (45 s)

a = (-25 m/s) / (45 s)

a ≈ -0.56 m/s²

Answer:

The speed of the plane after it decelerates is 50 m/s

Explanation:

Motion with Constant Acceleration

When an object gains or losses velocity in time, it acquires acceleration. If this value is constant, we can calculate the final velocity (or speed in scalar terms) as:

\(v_f=v_o+at\)

Where vf is the final speed, vo is the initial speed, a is the constant acceleration, and t is the time the acceleration is acting.

The plane is originally traveling at vo=80 m/s and it slows down at a constant rate of \(a=-0.25\ m/s^2\) during t=120 seconds. Note we have added the negative sign to the acceleration because the plane is slowing down, i.e., the acceleration is against the speed.

Thus, the final speed is:

\(v_f=80-0.25*120\)

\(v_f=80-30=50\)

\(v_f = 50\ m/s\)

The speed of the plane after it decelerates is 50 m/s

Answer: 0.04

Explanation:

Given

Radius of turntable \(r=0.8\ m\)

Block is present at a distance of \(r_o=0.4\ m\)

Turntable rotates at a speed of \(v=0.8\ m/s\)

angular speed of turntable \(\omega =\dfrac{v}{r}\)

\(\Rightarrow \omega =\dfrac{0.8}{0.8}\\\Rightarrow \omega =1\ rad/s\)

block will experience a force i.e. centripetal force equal to \(m\omega ^2r\). This must balance the friction force \(\mu mg\)

\(\Rightarrow m\omega^2 r_o=\mu mg\\\Rightarrow 1^2\times 0.4=\mu \times 9.8\\\Rightarrow \mu =0.04\)

Thus, the coefficient of static friction force is \(0.04\)

Answer:

The answer is 6, because 2×y is equal to 12.

The distance between the toyota camry and the student after 5 seconds would be 37.8 meters.

Since the Toyota Camry is moving only along the x-direction and the student is moving only along the y-direction, we can treat their motions independently.

Let's first find how far the Toyota Camry will travel along the x-direction in 5 seconds, using the equation:

x = xo + v0t + (1/2)at^2

where xo = 0 m (since it starts from rest), v0 = 0 m/s (since it starts from rest), a = 3 m/s^2 (the constant acceleration), and t = 5 s.

Plugging in the values, we get:

x = (1/2)(3 m/s²)(5 s)^2 = 37.5 m

So after 5 seconds, the Toyota Camry will be 37.5 meters away from its starting position, in the positive x-direction.

Now let's find how far the student will travel along the y-direction in 5 seconds, using the equation:

y = yo + vt

where yo = 0 m (since the student starts from rest), v = 1 m/s (the constant speed), and t = 5 s.

Plugging in the values, we get:

y = (1 m/s)(5 s) = 5 m

So after 5 seconds, the student will be 5 meters away from their starting position, in the positive y-direction.

To find the distance between the Toyota Camry and the student, we can use the Pythagorean theorem, since their motions are perpendicular:

distance = sqrt(x^2 + y^2)

distance = sqrt((37.5 m)^2 + (5 m)^2)

distance = 37.8 m (rounded to one decimal place)

Therefore, the distance between the Toyota Camry and the student after 5 seconds is approximately 37.8 meters.

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The flux through the circle loop of wire is determined as 7.96 N/C.m².

The flux through the circle loop of wire is calculated by applying the following formula.

Ф = EA cosθ

where;

The area of the wire is calculated as follows;

A = πr²

A = π (2 m)²

A = 12.57 m²

The flux through the circle loop of wire is calculated as;

Ф = EA cosθ

Ф = 1.5 x 12.57 x cos (65)

Ф = 7.96 N/C.m²

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Answer:

(A-) Number of turns in secondary coil will be less than 125.

(B-) EXPLAIN- The voltage is to be lowered. The voltage will be reduced from 120 to 9 volts. As a result, a step down transformer will be used, indicating that the secondary coil's number of turns would be less than 125.

(C-) The number of turns on the secondary coil is 12.5

Explanation:

In electrical networks and transmission lines, a step-down transformer can be used in a number of ways.

Step down transformer formula-

                  \(V_s=\frac{N_s\times V_p}{N_p}\)

We are given with the -

Primary voltage \(V_p\) = 120V

Secondary voltage \(Vs=12V\)

Number of primary turns \(N_p=125\)

       Since , the transformer ratio is given as -

                   \(\frac{N_s}{N_p} =\frac{V_s}{V_p}\)

So, the number of turns on the secondary coil is - \(N_s=N_p\times\frac{V_p}{V_s}\)

            Putting , the given values -:

                \(125\times\frac{12}{120}\)

         =   12.5

Therefore , the number of turns on secondary coil is 12.5 .

The tension in the string holding the tassel and the vertical will the tension in the string

Generally, the equation for Tension is  mathematically given as

\(TCos\theta = mg\)

Therefore

\(TCos6.58^{o} = 19.8*10^{-3}*9.8\)

T = 0.1953 N

b).

Where

\(T* sin \theta = ma\)

\(0.1953*Sin6.58 \textdegree = 19.8*10^{-3}*a\)

a = 1.13 m/s^2

In conclusion

T* sinФ = ma

2msinФ = ma

2sinФ = a

\(sin\theta = \frac{a}{2}\)

\(\theta = sin^{-1}\frac{a}{2} \\\\\theta= sin^{-1}\frac{1.13}{2}\)

Ф = 34.4 °

In conclusion, The tension in the string holding the tassel and the vertical will the tension in the string

T = 0.1953 N

Ф = 34.4 °

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Answer:

Muscle Tissue

Explanation:

Sorry if I'm wrong

The particle’s acceleration is 0.268 m/s².

The initial velocity of the particle before 13.3 seconds is 3.56 m/s.

The time when the particle is at rest is 32.68 seconds.

The acceleration of the particle is calculated as follows;

a = Δv/Δt

a = (7.95 m/s - 4.38 m/s) / 13.3 s

a = 0.268 m/s²

u = at

u = 0.268 m/s² x 13.3 s

u = 3.56 m/s

s = ut + ¹/₂at²

0 = -4.38t + ¹/₂(0.268)t²

0.134t² = 4.38t

0.134t = 4.38

t = 32.68 seconds

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