need help ASAP. please and thank you ​

The “father of psychology”, conducted the first psychological experiments is the man called Wilhelm Wundt.

Psychology s a science that studies human behavior and the mental processes. Thus the scope of psychology goes beyond just the study of the behavior of individuals. The other aspect of cognitive function falls under the aspect of cognitive psychology.

Now, the “father of psychology”, conducted the first psychological experiments is the man called Wilhelm Wundt.

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Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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Answer:

The correct answer is (C), as explained below. The transpose of a matrix is created by interchanging corresponding rows and columns.

Switching Rows

You can switch the rows of a matrix to get a new matrix.

Explanation:

If A is an m × n matrix and AT is its transpose, then the result of matrix multiplication with these two matrices gives two square matrices: A AT is m × m and AT A is n × n. ... Indeed, the matrix product A AT has entries that are the inner product of a row of A with a column of AT.

The fitness assessments helps as, they ensure that the program is meeting the desired goals.

option C.

Fitness assessment is defined as a process of evaluating an individual's physical fitness levels and overall health.

Fitness assessment typically involves a series of tests, measurements, and evaluations that are designed to assess various components of physical fitness, such as;

Thus, fitness assessments ensure that the program is meeting the desired goals.

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Answer:

Explanation:

The Workdone is the product of force and distance, Hence, the Workdone on the box from distance x = 0 meters and x = 16 meters is 0 Joules.

Using the graph given :

The work done from x = 0 to x = 16 metres ;

The distance can be split evenly into :

(x = 0 to x = 8) and (x = 8 to x = 16)

Workdone = Force × distance

Workdone from ; x = 0 to x = 8 ;

Force at a distance of 8 meters = - 40N

Workdone = - 40N × 8 m = -320 Nm

Workdone from ; x = 8 to x = 16 ;

Force at a distance of 16 meters = 40 N

Workdone = 40 N × 8 m = 320 Nm

The total workdone :

(-320 + 320) Nm = 0 J

.

Therefore, the Workdone ls 0 Joules.

Answer:

5N

Explanation:

We have a simple problem of momentum here.

ΔMomentum= mΔv= FΔt

Solve for F

mΔv/Δt=F

Plug in givens

1*(2-1.5)/0.1=F

F=5N

The amount of force that the wall imparts on the ball is 5.0N

According to Newton's second law, the formula for calculating the force applied is expressed as:

\(F=ma\)

m is the mass of the object

a is the acceleration of the object

Since acceleration is the change in velocity of an object, hence \(a=\frac{\triangle v}{t}\)

The applied force formula becomes \(F=\frac{m\triangle v}{t}\)

Given the following parameters

m = 1.0kg

\(\triangle v=2.0-1.5\\\triangle v=0.5m/s\)

t = 0.1sec

Substitute the given parameter into the formula

\(F=\frac{1.0\times 0.5}{0.1}\\F=\frac{0.5}{0.1}\\F=5N\)

Hence the amount of force that the wall imparts on the ball is 5.0N

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(a) To determine the acceleration of the ball while it is in flight, we can use the equation of motion:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

In this case, the ball is thrown straight up, so its final velocity at the highest point is 0 m/s. The initial velocity is unknown, the acceleration is due to gravity and is approximately -9.8 m/s^2 (negative since it acts in the opposite direction of motion), and the time of flight is 2.21 s.

Using the equation, we can solve for the acceleration:

0 = u - 9.8 * 2.21

u = 9.8 * 2.21

u ≈ 21.658 m/s

Therefore, the acceleration of the ball, while it is in flight, is approximately 21.658 m/s^2 in the upward direction.

(b) When the ball reaches its maximum height, its velocity is 0 m/s. This occurs when the ball is momentarily at rest before falling back down. Therefore, the magnitude of the velocity when the ball reaches its maximum height is 0 m/s.

(c) To find the initial velocity of the ball, we can use the equation:

v = u + at

At the highest point, the final velocity is 0 m/s, the acceleration is -9.8 m/s^2 (due to gravity), and the time is 2.21 s.

0 = u - 9.8 * 2.21

u = 9.8 * 2.21

u ≈ 21.658 m/s upward

Therefore, the initial velocity of the ball is approximately 21.658 m/s upward.

(d) The maximum height reached by the ball can be determined using the equation for vertical displacement:

s = ut + (1/2)at^2

At the highest point, the final displacement is 0 m, the initial velocity is 21.658 m/s upward, and the time of flight is 2.21 s.

0 = 21.658 * 2.21 + (1/2) * (-9.8) * (2.21)^2

0 = 47.864 + (-5.5294)

5.5294 = 47.864

Therefore, there seems to be an error in the calculations as the equation does not hold true. Please check the given values and equations to ensure accuracy.

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From the graph attached below the dependent variables are located on the Y axis of the graph while the independent variables are located on the x-axis of the graph.

Independent variables have direct effect on dependent variables in an experiment when manipulated. also independent variables have direct effect on dependent variables even when not manipulated.

Data involving the comparison of the effect of independent variables on dependent variables can be represented with a bar graph or line graph .

Hence we can conclude that the answers to your questions are as listed above.

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Answer:

LED stands for light emitting diode. LED lighting products produce light up to 90% more efficiently than incandescent light bulbs.

So, the angular frequency of the blades approximately 36.43π rad/s.

Hi ! Here I will discuss about the angular frequency or what is also often called the angular velocity because it has the same unit dimensions. Angular frequency occurs, when an object vibrates (either moving harmoniously / oscillating or moving in a circle). Angular frequency can be roughly interpreted as the magnitude of the change in angle (in units of rad) per unit time. So, based on this understanding, the angular frequency can be calculated using the equation :

\( \boxed{\sf{\bold{\omega = \frac{\theta}{t}}}} \)

With the following condition :

We know that :

What was asked :

Step by step :

\( \sf{\omega = \frac{\theta}{t}} \)

\( \sf{\omega = \frac{2,000 \pi}{54.9}} \)

\( \boxed{\sf{\omega \approx 36.43 \pi \: rad/s}} \)

So, the angular frequency of the blades approximately 36.43π rad/s.

1/80 Hour...................

Hence, we can conclude that energy is released in a nuclear fusion reaction based on mass-energy equivalence because for small nuclei, the binding energy of the lighter nuclei is greater than the binding energy of the heavier nucleus.

Answer:

A

Source:

Trust me bro

in the service producing sector

The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

This observation that electromagnetic radiation behaves like particles is known as the photoelectric effect.

It provides evidence that electromagnetic radiation exhibits particle-like properties. When EMR with sufficient energy (above a certain threshold) interacts with a metal surface, it can cause the ejection of electrons from the metal.

This behavior indicates that EMR behaves as discrete packets of energy called photons, which transfer their energy to the electrons and cause their release. The photoelectric effect supports the particle nature of EMR and is a fundamental concept in the field of quantum mechanics.

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The height of the satellite Aldock in orbit is approximately 1,419,288 meters or 1,419.3 kilometers above the Earth's surface.

The height of a satellite in orbit around the Earth can be calculated using the following formula:

h = (GMt/4π²)^(1/3) - Re

where:

To solve for h, we need to know the mass of the satellite and the speed of its orbit. However, we can use the given information that the Earth exerts a force of 5000N on the satellite to calculate the speed of the orbit using the centripetal force equation:

F = mv^2/r

where:

Solving for v, we get:

v = √(Fr/m)

v = √((5000 N) * (6,371,000 m)) = 7919.26 m/s

Now that we know the speed of the orbit, we can use the first formula to solve for the height of the satellite:

h = (GMt/4π²)^(1/3) - Re

Substituting the given values, we get:

h = [(6.67430 × 10^-11 m^3/kg/s^2) * (5.972 × 10^24 kg) / (4π²)]^(1/3) - 6,371,000 m

= 1,419,288 m

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The time taken for the ball to reach its maximum height is 1 second.

To calculate the time taken for the ball to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

In this case, the ball is thrown vertically upwards, so the initial velocity (u) is 10 m/s (considering upwards as positive) and the acceleration (a) is -10 m/s² (negative because it opposes the motion).

The final velocity (v) at the maximum height will be zero because the ball momentarily comes to a stop before reversing its direction. Therefore, we can rewrite the equation as:

0 = 10 - 10t

Simplifying the equation, we get:

10t = 10

Dividing both sides by 10, we find:

t = 1 second

Therefore, the time taken for the ball to reach its maximum height is 1 second.

During this time, the ball covers the distance required to reach the maximum height, overcoming the gravitational acceleration. After reaching the maximum height, it will start to descend towards the ground due to the gravitational pull.

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Answer:

C. 2000kg rated sling

Explanation:

ensures better safety and can carry twice more mass than current mass.

Answer:

Environmental means relating to or caused by the surroundings in which someone lives or something exists. It protects against environmental hazards such as wind and sun. The form the human family takes is a response to environmental pressures.

Explanation:

I HOPE IT HELPS!!

THANX!!!

STAY SAFE!!!!

The mass M of the object 500KG ,the impulse delivered to the car-object system from 10 to 1 = 2.0 s. is 10,909, the resisting force on the car-object system after the collision as a function of  N'S (1+56) 2

a) Calculate the mass M of the object.

P2 = PMcanVi=(Mcm + M) Vf

COLLISION HAPPENS AT too

(1000)(12)== (1000+ M) (8)

12000 = 8000 + 8M

v (o) =8 1+5(0)=

४%,| M =500ky+dx=dt

४ 1+56

Jdx:

४=11+5€

LET u = 1+5t8du = 5dt5

(b) Assuming an initial position of x = 0, determine an expression for the position of the car-object system after the collision as a function of time t.

814Sisi det४=en (1+5€)

(c) Determine an expression for the resisting force on the car-object system after the collision as a function of

time t.drd840a ==Je de1+5+(1+5t)F=ma = (1500) (-(1500) (-2)60,000=

(1+56) 2

(d) Determine the impulse delivered to the car-object system from 10 to 1 = 2.0 s.

I= op = M(AU) = = 1500 (THS (2)8

1+5(2)m.

M (V(2)-V(0))४1 +56);)=|-

10,909 N'S

There are two different types of collisions among two bodies: 1) Head-on collisions, or one-dimensional collisions, where the speed of each skin just before impact coincides with the line of impact, and 2) Quasi collisions, oblique collisions, or two-dimensional collisions, where the speed of each body just before

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Answer:

Step 1: We make the assumption that 125 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that $100\%=125$.

Step 4: In the same vein, $x\%=125$.

Step 5: This gives us a pair of simple equations:

$100\%=125(1)$.

Explanation:

Yes the egg will crack when it hits the ground because its final velocity of 3.58 m/s is greater than the minimum velocity that will prevent it from cracking.

option A is the correct answer.

The time of motion of the egg is the time taken for the egg to hit the ground and it is calculated as follows;

h = vt + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

t = √(2h/g)

t = √(2 x 16 / 0.4)

t = 8.94 seconds

The final velocity of the egg when it hits the ground is calculated as;

vf = vi + gt

vf = 0 + 8.94 s  x 0.4 m/s²

vf = 3.58 m/s

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In terms of the amount of light years energy received, star A should appear 100 times brighter than star B. This is due to the fact that received energy diminishes according to squared distance.

Contact binaries are binary star systems with members whose distance from one another is so great that their outer envelopes actually touch. This structure can actually be rather stable, with typical lifetimes measured in millions or even billions of years, which may surprise you.

When the Earth is at the other end of the star's orbit, six months later, astronomers take another measurement of the star's position. This results in a base line that is equal to the sum of the two angles used to measure the star and the double distance from Earth to the Sun's center (about 300,000,000 km). The distance to a nearby star can be calculated using these three variables in a very straightforward trigonometric manner.

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The vector whose magnitude is 36 and inclination is 60° is v = <18, 18√(3)>.

The inclination of a vector is the angle between the vector and a reference line. In this case, the reference line is the horizontal axis. Let the components be x and y. We know that the magnitude of the vector is 36, so,

magnitude = √(x² + y²) = 36

Squaring both sides of this equation, we get,

x² + y² = 1296

We also know that the inclination is 60°. The tangent of 60° is √(3), which is equal to the ratio of the vertical component to the horizontal component of the vector,

tan(60°) = y/x

y/x= √(3)

Multiplying both sides by x, we get,

y = √(3)x

Now we can substitute y in terms of x in the equation x² + y² = 1296,

x² + (√(3)x)² = 1296

Simplifying this equation, we get,

4x² = 1296

x² = 324

Taking the square root of both sides, we get,

x = +/- 18

Since the vector is making an angle of 60° with the horizontal, it must be in the first or fourth quadrant, where x is positive. Therefore, we take x = 18. Using y = √(3)x, we get,

y = sqrt(3)18

y = 18√(3)

So the vector is,

v = <18, 18√(3)>

Therefore, the vector whose magnitude is 36 and inclination is 60° is v = <18, 18√(3)>.

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Answer:

10,000 N

Explanation:

Using Newton's Second Law of Motion, Force = Mass*Acceleration.

Plugin 2500 kg for the mass and 4 m/s^2 for the acceleration.

Force = 2500 kg*4 m/s^2 = 10000 Newtons

(SI unit of force is Newtons)

The period of non-strenuous activity that slowly prepares the body for more vigorous exercise is called a warm-up. A warm-up is an essential part of any exercise routine as it helps to prepare the body physically and mentally for more intense physical activity.

Explain non-strengthening activity that gradually prepares the body for more strenuous exercise?

During a warm-up, the body's muscles, heart, and lungs gradually increase their activity levels, and the body's temperature begins to rise. This gradual increase in activity and temperature helps to reduce the risk of injury and improves performance during more intense exercise.

A typical warm-up can last between 5 to 15 minutes, depending on the intensity of the upcoming exercise. Some common warm-up activities include light aerobic exercises like jogging or cycling, dynamic stretching, and mobility exercises.

It is important to note that a warm-up should not be too strenuous activity , as this can cause fatigue and decrease performance during the main workout. Instead, it should be a gentle and gradual increase in activity level to prepare the body for the upcoming exercise.

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Answer:

a) The total surface area of tin G in terms of π is 170π cm².

b) The mass of tin H is 336 g.

To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.

a) Total surface area of tin G in terms of π:

The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:

Lateral surface area = 2πrh

where r is the radius of the base and h is the height of the cylinder.

In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:

Lateral surface area = 2π(5 cm)(12 cm)

Lateral surface area = 120π cm²

Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:

Area of a circle = πr²

The radius of the circular base of tin G is 5 cm, so the area of each circular base is:

Area of each circular base = π(5 cm)²

Area of each circular base = 25π cm²

To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:

Total surface area of tin G = Lateral surface area + 2 × Area of each circular base

Total surface area of tin G = 120π cm² + 2 × 25π cm²

Total surface area of tin G = 120π cm² + 50π cm²

Total surface area of tin G = 170π cm²

Therefore, the total surface area of tin G in terms of π is 170π cm².

b) Mass of tin H:

We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:

(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)

Using the given values, we have:

(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)

Cross-multiplying and solving for the mass of tin H, we get:

(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)

mass of tin H = (72 g) × (792π cm²) / (170π cm²)

mass of tin H = 336 g

Therefore, the mass of tin H is 336 g.

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