Name:
1. What changes when you switch from a + charge to a - charge?

Answer:

i think A

Explanation:

power of the bulb  = 40 watt

Briefing

Power: In physics, the term "power" refers to the rate at which a task is completed, or how much energy is used during the allotted time.

What is energy now?

In physics, energy refers to the ability to do a task. It may exist in different forms, including potential, kinetic, thermal, electrical, chemical, radioactive, and others.

Consequently, in light of the posed query:

2400 J of energy

60 seconds in a minute is time.

As a result, we know that Power = Energy/Time.

p = E/t p = (2400-/60) joules/sec

p=40 W

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Answer:horse

Explanation:

Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.

According to the Ohm's Law,  the current through a conductor between two points is directly proportional to the voltage across the two points.

Mathematically,

V ∝ I

V = IR

where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.

Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.

Hence All of the above option in the given question are true.

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Answer:

s = 11250 m = 11.25 km

Explanation:

The distance covered by the sound wave while traveling from submarine to ocean floor and then back to submarine can be given as follows:

\(s = vt\)

but, the distance between the floor and the submarine will be half of this value:

\(s = \frac{1}{2}vt\)

where,

s = distance between submarine and ocean floor = ?

v = velocity of sound = 1500 m/s

t = time taken for the round trip = 15 s

Therefore,

\(s = \frac{1}{2}(1500\ m/s)(15\ s)\)

s = 11250 m = 11.25 km

Answer:

0.007

Explanation:

A = F/P

Force = 1730

P = 2.45 = 2.47 * 10^5

1730/(2.47*10^5) = 0.007

Answer:

Hi.

The answer to this problem is 0.007

Explanation:

It was correct for Acellus

How to solve it:

P=F/A

Rearrange it for A, plug in the numbers and solve!

A=F/P

F=1,730

P=2.45

The work done by the force on the block is approximately 311.2 Joules.

To calculate the work done by the constant force of magnitude F = 45 N over a distance of 8 m at an angle of 30 degrees to the horizontal, we need to find the component of the force that acts parallel to the displacement.

The horizontal component of the force can be calculated using trigonometry:

F_horizontal = F * cos(angle)

            = 45 N * cos(30 degrees)

            = 45 N * (√3 / 2)

            ≈ 38.9 N

Now, we can calculate the work done by the force using the equation:

Work = Force * Distance * cos(theta)

where theta is the angle between the force and the displacement.

Work = F_horizontal * Distance * cos(0)

     = 38.9 N * 8 m * cos(0)

     = 38.9 N * 8 m

     = 311.2 Joules

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A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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There are 54 turns in the coil.

The electromotive force produced by N turns is given as

                         ε=NBAω

From this, we can solve for the number of turns in the coil as

                        N = ε / BAω

Substituting the area of the coil, which is a rectangle, we get

                     N = ε / abBω

According to the question,

A bicycle generator rotates at 1,925 rad/s, producing a 20.0 v peak emf. It has a 1.00 by 3.00 cm rectangular coil in a 0.640T field.

Solving numerically, we find

                  \(N =\frac{20}{0.01 * 0.03 * 0.64 * 1925}\) ( substitute the values )

                  \(N =\frac{20}{0.3696}\)

                    N = 54

So, there are 54 turns in the coil.

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​

The complete question is:

A bicycle generator rotates at 1925 rad/s, producing a 20.0 V peak emf. It has a 1.00 by 3.00 cm rectangular coil in a 0.640 T field. How many turns are in the coil?

Answer:

0.4

Explanation:

\( \frac{1}{2} mv ^{2} \)

kinetic energy formula , potential energy is not considered

0.5×0.2×2×2

Answer:

t = 3.924 s

Explanation:

First, we will calculate the amount of work required to get the astronaut back to the capsule:

\(W = Fd\\\)

where,

W = work required = ?

F = Force = Weight = mg = (80 kg)(9.81\ m/s²) = 784.8 N

d = distance = 5 m

Therefore,

\(W = (784.8\ N)(5\ m)\\W = 3924 J\)

Now the time can be calculated as:

\(Power = \frac{W}{t}\\t = \frac{W}{Power}\\\\t = \frac{3924\ J}{1000\ W}\\\\\)

t = 3.924 s

Answer:

4.4.

Explanation:

Hello,

In this considering the attached picture, we can see that the eastward movement is represented from O to A, the northward displacement from A to B and the westward displacement from B to C, which means that the resulting displacement is marked from O to C which includes the northwards movement since eastward and westward movement are the same.

In such a way, the magnitude of the displacement is simply 4.4 cm as no other dimension is taken into account due to the return to the same initial's x-axis position.

Regards-

Answer:

\(62.5[\frac{km}{h}]\)

Explanation:

if the required speed is 's', then it is possible to make up the next equation:

\(\frac{100}{8} =\frac{s}{5};\)

finally,

s=100*5/8=62.5 [km/h].

This indicates that to increase the temperature of the water in the bathtub from 2°C to 7°C, roughly 62,760 kJ of heat energy were added.

While scientists typically use the Centigrade (or Celsius) scale, where water freezes at 0 degrees and boils at 100 degrees, we typically measure temperature in the United States using the Fahrenheit scale, where water freezes at 32 degrees and boils at 212 degrees.

According to the data given, the bathtub once held 300 kg of water at 2°C.

we can use the specific heat capacity of water and the formula:

Q = m * c * ΔT

The specific heat capacity of water is 4.184 J/(g°C), or 4184 J/(kg°C). Therefore, the amount of heat energy absorbed by the water is:

Q = 300 kg * 4184 J/(kg°C) * (7°C - 2°C)

Q = 62,760 kJ

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The first harmonic of the standing wave on a string with a loose end represents half a wavelength.

The fraction of a wavelength represented by the first harmonic is 1/2.

The higher harmonics of a standing wave on a string with a loose end are odd-number multiples of the first harmonic.

1. The first harmonic of a standing wave on a string with a loose end occurs when there is a node near the driver end and an antinode at the loose end. To measure the frequency of the first harmonic, we need to determine the fraction of a wavelength represented by this standing wave.

The first harmonic of the standing wave on a string with a loose end represents half a wavelength.

The first harmonic of a standing wave on a string with a loose end consists of a node near the driver end and an antinode at the loose end. This configuration creates the simplest standing wave pattern.

In a standing wave, a node is a point where the amplitude of the wave is always zero, representing a point of minimum displacement. An antinode, on the other hand, is a point of maximum displacement, where the amplitude is at its highest.

Since the loose end does not invert the phase of the wave upon reflection, the reflected wave and the original wave constructively interfere at the loose end, resulting in an antinode.

In the first harmonic, there is exactly half a wavelength between the node near the driver end and the antinode at the loose end.

Therefore, the fraction of a wavelength represented by the first harmonic is 1/2.

2. To predict the frequencies of higher harmonics, we can use the relationship that the frequency of each harmonic is a multiple of the frequency of the first harmonic. The higher harmonics can be calculated as follows:

Second Harmonic: The second harmonic consists of two nodes and one additional antinode compared to the first harmonic. The fraction of a wavelength for the second harmonic is 1/2 * 2 = 1. Thus, the second harmonic has a frequency that is twice that of the first harmonic.

Third Harmonic: The third harmonic consists of three nodes and two additional antinodes compared to the first harmonic. The fraction of a wavelength for the third harmonic is 1/2 * 3 = 1.5. Thus, the third harmonic has a frequency that is three times that of the first harmonic.

Fourth Harmonic: The fourth harmonic consists of four nodes and three additional antinodes compared to the first harmonic. The fraction of a wavelength for the fourth harmonic is 1/2 * 4 = 2. Thus, the fourth harmonic has a frequency that is four times that of the first harmonic.

In general, the higher harmonics of a standing wave on a string with a loose end are odd-number multiples of the first harmonic.

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Answer:

The final velocity after 6.0 s is

1304.2 .

What is velocity?

velocityis the most fundamental quantity of physics . Work is said to be done when a force applied to an object cause a displacement of a object.

Solution -

As per the given-

Mass of runner m = 74kg

initial velocity of runner u=4.8 m/s

final velocity of runner v =0

Coefficient of friction ¥=0.7

Let's d be the distance moved by runner till the stop.

a- mechanical energy lost due to friction

As friction does negetive work causing the runner to stop.

As we know,

Mechanical energy lost= Kinetic energy of runner

Mechanical energy lost =

1/2 mv^2 = 1/2 ×74×4.8^2=852.2

Distance move by runner-

Work done by friction = mechanical energy lost

-¥×mg×d =852.2 j

-0.7×74×9.8×d = -491.2

Solving the equation we get

1304.2.

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Answer:

-17.89 m/s  (or 17.89m/s downward)

edit:

if we round this to the nearest whole number, the answer is -18m/s (or 18m/s downward)

Explanation:

recall that one of the equations of motion can be expressed as:

v² = u² + 2as,

where

v = final velocity = given as 20 m/s

u = initial velocity = given as 7.0 m/s

a = acceleration. Since it is freefalling downwards, the acceleration it would experience would be the acceleration due to gravity = -9.81 m/s²

s = displacement (we are asked to find)

simply substitute the known values into the equation:

v² = u² + 2as

20² = 7² + 2(-9.81)s

400 - 49 = -19.62s

-19.62s = 351

s = 351/-19.62

s = -17.8899

s = -17.89 m/s (or -18 m/s rounded to nearest whole number)

A watermelon is thrown down from a skyscraper with a speed of v7.0 m/s. It lands with an impact velocity of 20 m/s. We can ignore air resistance.

What is the displacement of the watermelon?

Answer: -18

A 50.0-kg wagon is pulled with a constant force of 380 N. Neglecting friction, the wagon's acceleration will be 7.6 m/s².

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Answer:

A calorie is defined as the amount of energy needed to raise the temperature of one gram of water one degree Celsius.

Explanation:

The other unit used to measure heat is the joule. The joule is the SI (System International) unit

Answer:

\(M_b=6kg\)

Explanation:

From the question we are told that:

Coefficient of restitution \(\mu=1.00\)

Mass A \(M_a=6kg\)

Initial Velocity of A \(U_a=6m/s\)

Initial Velocity of B \(U_b=0m/s\)

Generally the equation for Coefficient of restitution is mathematically given by

 \(\mu=\frac{V_b-V_a}{U_a-U_b}\)

 \(1=\frac{v_B}{6}\)

 \(V_b=6*1\)

 \(V_b=6m/s\)

Generally the equation for conservation of linear momentum  is mathematically given by

 \(M_aU_a+M_bU_b=M_aV_a+M_bV_b\)

 \(6*6+=M_b*6\)

 \(M_b=6kg\)

The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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Answer:

75 cm/second.

Explanation:

Formula:

Walking speed = stride length / time per step

Walking speed = 90cm/time per step

                         = 90cm/1.2 seconds (a common estimate time per step)

                         = 75cm/second.

To calculate the weight of the block, we can use the formula:

Weight = Mass x Gravity

Where gravity is approximately 9.8 m/s^2.

First, we need to find the mass of the block. We can use the formula:

Density = Mass / Volume

The volume of the block is:

Volume = Length x Width x Height

Volume = 10 cm x 3 cm x 2 cm

Volume = 60 cm^3

We don't know the density of the metal, so we can't calculate the mass directly. However, we can use the spring balance reading to find the weight of the block.

The spring balance has a maximum reading of 10 Newtons, which corresponds to a length of 20 cm. When the block is hung on the balance, it stretches the string by 15 cm. The extension of the spring is proportional to the weight of the block, so we can use the following proportion:

Extension of spring / Total length of spring = Weight of block / Maximum weight of spring balance

Substituting the values we have:

15 cm / 20 cm = Weight of block / 10 N

Solving for the weight of the block:

Weight of block = 7.5 N

Now we can find the mass of the block:

Mass = Weight / Gravity

Mass = 7.5 N / 9.8 m/s^2

Mass = 0.765 kg

Finally, we can calculate the density of the metal:

Density = Mass / Volume

Density = 0.765 kg / 60 cm^3

Density = 0.01275 kg/cm^3

So the weight of the block is 7.5 N, the mass of the block is 0.765 kg, and the density of the metal is 0.01275 kg/cm^3.

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V² = U² + 2aS

30.6² = 18.5² + 2*226a

936.36 = 342.25 + 452a

936.36 - 342.25 = 452a

594.11/452

a= 1.31m/s^2

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Answer:

v = 4.0 m/s

Explanation:

       \(p_{f} = m_{w} * v_{w} + m_{g+w} *v_{g+w} = 0 (1)\)

       \(v_{g+w} =- \frac{m_{w} *v_{w}}{m_{g+w} } = - \frac{36.0kg *6.5m/s}{58.0kg } = -4.0m/s (2)\)

Answer: 326m

Explanation:

To find the the wavelength of the radio waves, we can use the equation:

Wavelength = c/f

where,

c = 3 × 10^8 m/s

f = 920 × 10^3 kHz

Wavelength = 3 × 10^8 / 920 × 10³

Wavelength = 326.08696

Wavelength = 326m