Name the 4 functions that C++ provides in every class if they are not explicitly defined by the programmer?

Answer:

See the image for solution

Answer:

a) 764.45K

b) 210.48 kJ/kg

c) 30.14%

Explanation:

pressure ratio = 10

minimum temperature = 295 k

maximum temperature = 1240 k

isentropic efficiency for compressor = 83%

Isentropic efficiency for turbine = 87%

a) Air temperature at turbine exit

we can achieve this by interpolating for enthalpy

h4 = 783.05 kJ/kg ( calculated in the background ) at state 4 using Table A-17  for  Ideal gas properties of air

T4 ( temperature at Turbine exit ) = 760 + ( 780 - 760 ) \((\frac{783.05-778.18}{800.13-778.18} )\) = 764.45K

b) The net work output

first we determine the actual work input to compressor

Wc = h2 - h1  ( calculated values )

     = 626.57 - 295.17 =  331.4 kJ/kg

next determine the actual work done by Turbine

Wt = h3 - h4  ( calculated values )

     = 1324.93 - 783.05 = 541.88 kJ/kg

finally determine the network output of the cycle

Wnet = Wt - Wc

         = 541.88 - 331.4  = 210.48 kJ/kg

c) determine thermal efficiency

лth = Wnet / qin  ------ ( 1 )

where ; qin = h3 - h2

equation 1 becomes

лth = Wnet / ( h3 - h2 )

      = 210.48 / ( 1324.93 - 626.57 )

      = 0.3014  =  30.14%

Therefore, it is impossible to answer this question. Please provide complete information about the orientation of the element to determine the principal stresses.

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In an iterative process called dynamic coordination, both interdependent tasks feed information to one another.

Different coordination modalities provide the foundation for the coordination of design systems. Negotiation around intermediary objects and prescriptive activity sequences are complementary techniques to resolving this problem. They both work on actual design projects. One of the two strategies is frequently at the centre of models to facilitate this global coordination. In fact, models are rarely thorough enough to manage both's complexity. Dynamic entities offer a means of finishing and adapting a model to the continuously negotiated situation and liberate the system to be customised on very precise design modes.

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The work done on air during the compression process is 3.327 KJ in 8l piston-cylinder device contains air at 300 kpa and 300 k.

One of the main ways a thermodynamic system interacts with its environment and exchanges energy is through work in thermodynamics. A process that allows the system to spontaneously exert macroscopic forces on its surroundings, or the opposite, facilitates an exchange of energy.

Work is considered to have been completed on a system when a force is applied and the system experiences a displacement. A system is considered to have completed work when it exerts force on an object and results in displacement.

The formula for work is W=Fd

Given that

P1 = 300k pa , V1 = 8L

v2 = 2L

Temperature remains constant it means that this is isothermal process

For isothermal process P1V1 = P2V2

We know that work for isothermal process  

W = P1V1 ln P1/P2

Now by putting the values

W = 300 * 8 * 10^-3 ln 2/8

W = -3.327 KJ

Negative sign indicates is process is compression

W=3.327 KJ

Work done on air during this compression process is 3.327 KJ

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When Courtney compiles the code it will be produced a programming model.

Machining learning is a branch of artificial intelligence that consists of educating the machine so that it performs functions following a reasoning similar to human thinking, so that it can make its own decisions. That is, machine learning seeks to automate the system.

It is possible to educate the machine through machine learning algorithms. In a nutshell, machine learning algorithms are ordered sequences of rules, commands, and instructions. By combining the algorithms with data, they arrive at a certain result.

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Technicians A is correct in the given scenario. The correct option is C.

Exhaust gas is a byproduct of combustion that exits the tailpipe of an internal combustion engine.

It consists of a gas mixture that includes carbon dioxide (CO2), carbon monoxide (CO), nitrogen oxides (NOx), hydrocarbons (HC), and particulate matter (PM).

Technician B is mistaken. CO2 levels in the exhaust should be less than 15%, preferably between 13% and 14.5% for petrol engines and 11% to 13% for diesel engines.

High CO2 levels can actually indicate inefficient engine operation, as it means that not all of the fuel in the engine is being burned and is being wasted as exhaust.

Thus, C is the correct answer. A technician is correct.

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Answer: its A

Explanation:

A) double

According to the kinetic-molecular theory, the temperature of a gas is a measure of the average kinetic energy of the gas molecules. The kinetic energy of a molecule is the energy it possesses due to its motion. As the temperature of a gas increases, the average kinetic energy of the molecules increases.

If the temperature of a gas is raised from 100°C to 200°C, the average kinetic energy of the molecules will double. This is because the temperature increase is a 100% increase, and the average kinetic energy of the molecules will also increase by 100%.

It is important to note that this is only true if the volume and number of molecules in the gas are held constant. If the volume or number of molecules changes, the relationship between temperature and average kinetic energy may be different.

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The dynamic pressure on the right side / dynamic pressure on the left side is 81

To determine the ratio of F2/F1, we can use the concept of fluid pressure.

According to Bernoulli's principle, the total pressure at any point in a fluid system is the sum of the static pressure, dynamic pressure, and potential energy per unit volume.

Since the height on the right (h2) is four times the height on the left (h1), we can assume that the potential energy per unit volume on the right side is four times that on the left side. Therefore, the pressure difference due to potential energy is negligible.

The dynamic pressure is proportional to the square of the velocity. Since the velocity of the upper plate on the right (V2) is three times that of the upper plate on the left (V1), the dynamic pressure on the right side is nine times that on the left side.

The static pressure is the same on both sides because the bottom surface is stationary and the fluid is not being compressed.

Therefore, the ratio of F2/F1 is equal to the ratio of the dynamic pressures:

F2/F1 = dynamic pressure on the right side / dynamic pressure on the left side

     = \((9V2^2) / (V1^2)\)

     =\((9(3V1)^2) / (V1^2)\)

     = 81

So, the ratio of F2/F1 is 81.

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Answer: True

Explanation: Iron is magnetic

Answer:

a

Explanation:

because if you do its right

Bedload refers to the gravel, pebbles, stones, and boulders that are too large to be picked up and carried in suspension by the flow of water or air.

The bed load of a stream or river is composed of the particles that travel along the bed, rolling, sliding, and bouncing along the bottom of the channel.

In this context, bed load is moved by all of the above: traction, saltation, and suspension.

Traction is the process by which large and heavy particles are rolled along the stream or riverbed by the force of the water or wind.

Saltation occurs when smaller particles, like sand and pebbles, are bounced along the bed by the turbulence of the flow.

Suspension is the process by which even smaller particles, like silt and clay, are held up and transported by the flow of water or air.

When the bedload is moved by a group of answer choices that is traction and saltation.

This happens because in a stream or river, the larger particles are usually too heavy to be lifted by the water,

so they move along the bottom by rolling, sliding, or bouncing.

Meanwhile, the smaller particles are lifted up and transported by the turbulence of the flow, bouncing along the bed as they go.

This combination of processes results in a mix of traction and saltation as the bedload moves along the stream or riverbed.

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b) The PDA for the language of all strings of 0's and 1's such that no prefix has more 1's than 0's can be designed as follows:  Use an empty stack PDA. Push 0 for each input 0. For each input 1, pop a symbol if the stack is not empty; otherwise, reject.

The PDA starts in the initial state with an empty stack. For each input symbol 0 encountered, we push it onto the stack. This action represents counting the number of 0's encountered so far. Whenever an input symbol 1 is read, the PDA checks if the stack is empty or not. If the stack is not empty, it means there is a matching 0 for the 1, so we can pop a symbol from the stack. This action ensures that no prefix has more 1's than 0's. If the stack is empty when encountering a 1, it implies that there is no matching 0 for the 1, and thus we reject the input.

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Answer:

21.6 kw

Explanation:

Given data:

m = 50 kg/s

Inlet pressure (p1) = 2 bar

outlet pressure(p2) = 6.2 bar

suction ( h1 ) = -2.2 m

delivery ( h2 ) = 8.5 m

d1 = 200 mm = 0.2 m

d2 = 100 mm = 0.1 m

Vs of water = 0.001 m^3/kg

next we have to determine the Q value

Q = V*A

Q = 0.001 * 50 = 0.05 m^3/s

next we have to calculate the various V's

V1 = Q/A1 = \(\frac{0.05*4}{\pi *0.2^2}\)  = 1.59 m/s

V2 = Q/A2 = \(\frac{0.05*4}{\pi *0.1^2}\) = 6.37 m/s

Determine the capacity of the electric motor

attached below is the detailed solution

In certain locations in the United States, the Authority Having Jurisdiction (AHJ) may not allow the use of nonmetallic sheathed cable in residential construction due to fire and safety concerns.

The alternative wiring method that is most often used in these cases is metal conduit. Metal conduit provides better protection for electrical wiring, as it is made of metal and provides a physical barrier against fire, moisture, and other environmental factors. The wiring is installed inside the conduit and is protected from damage, which can reduce the risk of electrical fires and other safety hazards.

It's important to note that each AHJ has different requirements and codes, so it's important to consult with the local authority to determine the specific requirements for the area. If metal conduit is required, it is important to use it correctly and to follow all applicable codes and standards to ensure the safety and functionality of the electrical system.

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Answer: i believe it’s acoustics

Explanation:

The probability that one telephone call passes through the switchboard in three minutes is 1.49%.

Using the Poisson probability formula, we can calculate the probability of exactly one call passing through the switchboard in 3 minutes as follows:

P(X = 1) = (e^(-6) * 6^1) / 1!

Where

6 = 2 per minute * 3 minute

X is the number of calls passing through the switchboard in 3 minutes.

So, we have

P(X = 1) = (e^(-6) * 6^1) / 1!

= (0.00248 * 6) / 1

= 0.0149

Therefore, the probability that one telephone call passes through is approximately 0.0149, or about 1.49%.

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Answer:

Unit of,

momentum = kg×m/s

momentum per unit area = kg×m/s×m² = kg/m×s

momentum per unit area per unit time= kg/ms²

force = kg×m/s²

force per unit area = kg×m/s²×m² = kg/ms²

Explanation:

Answer:

Umm.... because the spit that comes up of your mouth when you talk mixes with the air

Explanation:

Answer:

can you explain how to do this

Explanation:

Answer:

A. a material cycle

Explanation:

The material cycle is the cycle of materials on the Earth through living organisms and the environment.

Answer:

they are used for electrical currents so that they can flow along the appropriate wires in the circuit

Explanation:

To ensure safety and reliable electrical connections, polarized electrical receptacles are employed.

It is frequently seen in both residential and commercial structures and has two slots, one of which is broader than the other.

In a polarised outlet, the neutral slot is broader than the hot slot, which is smaller. To ensure that electrical appliances or gadgets are connected correctly and consistently, this design was created.

By ensuring a steady flow of energy through the instrument, polarization lowers the chance of electric shock.

Thus, it's crucial to remember that not all electrical appliances need polarized plugs.

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Answer:

Its specific resistance will be around 0.015

a. The equal-frequency partitioning for the given sales price records would be as follows: Bin 1: 5, 10, 11, 13  Bin 2: 15, 35, 50, 55  Bin 3: 72, 92, 204, 215

(a) Equal-Frequency (Equidepth) Partitioning:

Equal-frequency partitioning divides the data into bins of equal frequency. In this case, we have 12 records, so we need to partition them into three bins.

Now, we can assign the records to the bins based on their order. Starting from the lowest value, we assign four records to each bin until all records are assigned. If there are any remaining records, we distribute them evenly across the bins.

Using this method, the equal-frequency partitioning for the given sales price records would be as follows:

Bin 1: 5, 10, 11, 13

Bin 2: 15, 35, 50, 55

Bin 3: 72, 92, 204, 215

(b) Equal-Width Partitioning:

Equal-width partitioning divides the data into bins of equal width or range. In this case, we need to determine the range of the data and then divide it into three equal-width bins.

The range of the data is the difference between the maximum and minimum values, which is 215 - 5 = 210.

Each bin will have a width of 210 / 3 = 70. Starting from the minimum value, we assign the records to the bins based on their value falling within the corresponding width range.

Using this method, the equal-width partitioning for the given sales price records would be as follows:

Bin 1: 5, 10, 11, 13, 15, 35

Bin 2: 50, 55, 72, 92

Bin 3: 204, 215

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Polymers is the referred to the class of material which is generally considered to be the weakest at room temperature, offering the lowest elastic moduli and tensile strengths and is denoted as option B.

This refers to a type of compound which are long chained and are formed from smaller repeating chemical units known as monomers through the process which is referred to as polymerization

They are usually in the form of plastics or resins and have features such as lowest elastic moduli and tensile strengths thereby making it the most appropriate choice.

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The options incliude:

A.Metal

B.Polymer

C.Ceramics

D.Composites

Answer:0.00234

Explanation:

Answer:

Explanation:

In this context, we are dealing with the cooling of hot air as it flows through tubes exposed to atmospheric air. Based on this, we can make the following statements:

a. Heat transfer coefficient inside the tube will be higher - This statement is false. As the hot air flows through the tube and comes into contact with the cooler atmospheric air outside the tube, heat transfer occurs between the two fluids. In this process, the temperature difference between the two fluids drives the heat transfer. Therefore, the heat transfer coefficient inside the tube will be lower because the hot air will have a higher temperature than the atmospheric air, and the temperature difference will be smaller.

b. Heat transfer coefficient inside the tube will be lower - This statement is true, as explained in the previous statement.

c. Fins should be attached to the outside of the tube - This statement is true. Fins are used to increase the surface area of the tube, which in turn increases the rate of heat transfer between the hot air inside the tube and the atmospheric air outside. Attaching fins to the outside of the tube will increase the surface area exposed to the atmospheric air, facilitating faster cooling of the hot air.

d. Fins should be attached to the inside of the tube - This statement is false. Attaching fins to the inside of the tube will actually reduce the effective cross-sectional area of the tube, restricting the flow of air and hindering the heat transfer process. Therefore, fins should be attached to the outside of the tube to maximize the surface area and facilitate efficient heat transfer.