my Chemistry questions

How can you burn an apple, blueberry, rose and pumpkin without leaving any ashes but retaining the smell of it?

The correct model is the one on the right, as it shows that the total number of atoms on the reactant side  is equal to the total number of atoms on the product side .

Reactant is a substance that participates in a chemical reaction and is consumed in the process. Reactants are typically the starting materials or elements in a chemical reaction, and the resulting products are known as the products of the reaction. Reactants may be either organic molecules or inorganic compounds, and they can be either a single element or a combination of elements. Reactants are transformed during the course of the reaction into the products, which are usually different from the reactants. Reactants can be identified by the chemical equations that represent the reaction.

The correct model is the one on the right, as it shows that the total number of atoms on the reactant side (4 atoms of nitrogen and 4 atoms of hydrogen) is equal to the total number of atoms on the product side (3 atoms of nitrogen and 3 atoms of hydrogen). Therefore, the mass is conserved in the reaction.

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Answer

47.73 g CuO

Explanation

Given:

Chemical equation: 3CuO+ 2H3PO4 = Cu3(PO4)2 + 3H20

mass of orthophosphate acid (Cu3(PO4)2) = 39.2 g

Required: The mass of CuO

Solution:

Second method:

Step 1: Find the moles of H3PO4

n = m/M where m is the mass and M is the molar mass of H3PO4

n = 39.2g/97.994g.mol^-1

n = 0.400 mol

Step 2: Use the stoichiometry to find the moles of CuO

The molar ratio between CuO and H3PO4 is 3:2

Therefore the moles of CuO = 0.400 mol x (3/2) = 0.600 mol

Step 3: Find the mass of CuO, now that we have moles

m = n x M m is the mass, n is the moles and M is the molar mass

m = 0.600 mol x 79,545 g/mol

m = 47.73 g

The correct answer is All of the answer choices are correct.

A biochemical process that involves the addition of phosphate to an organic compound. In biological systems, this reaction is vital for the cellular storage and transfer of free energy using energy carrier molecules.

The first step in the metabolism of carbohydrates is frequently their phosphorylation. Because the phosphate group stops the molecules from migrating back across the transporter, phosphorylation enables cells to store carbohydrates. Glucose phosphorylation is a crucial step in the metabolism of sugar.

The chemical formula for the first step of glycolysis, which involves the conversion of D-glucose to D-glucose-6-phosphate, is provided by

          D-glucose + ATP → D-glucose-6-phosphate + ADP

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The complete question is :

The process of phosphorylation

(a) adds a phosphate group to a molecule.

(b) may energize the target molecule.

(c) removes a phosphate group from a molecule.

(d) may change the shape of the target molecule.

(e) All of the answer choices are correct

Using this formula, we can calculate the confidence interval once we have the sample data, without the sample data, it is not possible to provide an accurate confidence interval estimate.

To construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system, we would need the sample data, specifically the number of cell phone users and the number of users who developed cancer. Without the sample data, it is not possible to provide an accurate confidence interval estimate.

However, if we assume that we have the necessary sample data, we can proceed with the calculation. The formula for calculating a confidence interval for a proportion is:

Confidence interval

\(=�^±�×�^(1−�^)�Confidence interval= p^​ ±z× np^​ (1− p^​ )​ ​ where:�^p^​\)

 is the sample proportion (number of users with cancer divided by the total number of cell phone users).

\(�\)

z is the z-score corresponding to the desired confidence level (90% confidence level corresponds to a z-score of approximately 1.645).

\(�\)

n is the sample size (total number of cell phone users).

Using this formula, we can calculate the confidence interval once we have the sample data.

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Taking into account the reaction stoichiometry, 33.108 grams of NH₄HO are formed if excess ammonium sulfate reacts with 35.0 grams of calcium hydroxide.

In first place, the balanced reaction is:

(NH₄)₂SO₄ + Ca(OH)₂ → CaSO₄ + 2 NH₄HO

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amount of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 74 grams of Ca(OH)₂ form 70 grams of NH₄HO, 35 grams of Ca(OH)₂ form how much mass of NH₄HO?

mass of NH₄HO= (35 grams of Ca(OH)₂ ×70 grams of NH₄HO) ÷74 grams of Ca(OH)₂

mass of NH₄HO= 33.108 grams

Finally, 33.108 grams of NH₄HO are formed.

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Answer:

true I think ?38363849472

Answer:

true

Explanation:

Explanation:

Ionizable Amino Acids

Seven out of the twenty amino acids contain readily ionizable side chain groups. That means that at specific pH values, each side chain can participate in an acid-base reaction in which it can exchange a hydrogen atom with some other biomolecule. Since these side chains can form ions, that implies that they can also participate in forming ionic bonds. On top of these seven amino acids with ionizable side chains, all of the amino acids contain an ionizable alpha amino group and an alpha carboxyl group. The pKa value of each side chain group determines the pH value at which there will be equal concentrations of the acid and its conjugate base. The pKa value of the alpha amino group is 3.1 while the pKa value of the alpha amino group is 8.0. The pkA values of glutamic acid and aspartic acid are 4.1, the pKa of cysteine is 6.0, the pKa value of lysine is 8.3, the pKa value of lysine is 10.8, the pKa value of tyrosine is 10.9 and the pKa value of arginine is 12.5.

Answer:

For Feo is 2+

For Fe2O3 is 3+

Btw I did it and got it right!

Explanation:

The charge of the Fe ion in the compound \(\rm FeO\)is +2 and the charge of the Fe ions in the compound \(\rm Fe_2O_3\) is +3, respectively.

Ion can defined as any atom or molecule having positive or negative charge on it.

In \(\rm FeO\): In the compound, oxygen is in group 16 and has a charge of -2, the iron ion must have a charge of +2 to balance the charges and make the compound neutral.

In \(\rm Fe_2O_3\): In the compound, oxygen is in group 16 and has a charge of -2, the three oxygen atoms in \(\rm Fe_2O_3\) contribute to a total charge of -6. To make the compound neutral, the two iron ions must have a total charge of +6. Therefore, each iron ion must have a charge of +3 to balance the charges and make the compound neutral.

Therefore, Fe ion has a charge of +2 in the compound \(\rm FeO\) and has a charge of +3 in the compound \(\rm Fe_2O_3\).

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The temperature vs time graph is effectively used to predict the melting and boiling points of the substance and it can be used to detect if a reaction is endothermic or exothermic.

So, the boiling point of the substance is 150°C , melting point is 90°C and the reaction is exothermic as it involve the release of energy.

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Answer:

1) Zn(s) + 2HCl(aq) --> ZnCl2(aq) + H2(g)

You would see the reaction forming bubbles vigorously. Hydrogen gas is produced in the process.

Answer: Basic

Explanation:

A solution with a pH of more than 7 is considered basic.

Yes, the can will sweat in the given conditions.

When a cold object comes in contact with a warm, humid environment, it causes the air around the object to cool down, leading to condensation of water vapor from the air onto the surface of the can. This process is known as sweating. The temperature difference between the can and the surrounding air, along with the relativehumidity, determines the amount of condensation. In this case, the temperature of the can is lower than the room temperature, and the relative humidity is high enough to cause the can to sweat.

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Answer: C, 0

Explanation: just a mere guess

The balanced equation for the formation of 1 mol of liquid methanol (CH₃OH) to produce CO₂ and H₂O is CH₃OH + O2 →  CO₂ + 4 H₂O This means that for every mole of methanol that react, 1 mole of carbon dioxide and 2 moles of water are produced.

To write a balanced equation for the formation of 1 mol of liquid methanol (CH₃OH) to produce CO2 and H2O, follow these steps:

1. Write down the reactants and products: CH₃OH (reactant) → CO₂ (product) + H₂O (product)
2. Balance the equation by adjusting the coefficients of the reactants and products.

The balanced equation for the formation of 1 mol of liquid methanol to produce CO₂ and H₂O is:

CH₃OH (l) → CO₂ (g) + 2 H₂O (l)

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Answer:

No

Explanation:

The air is really a mixture of many different gases, and each gas has its own properties. The composition of air is not constant. It can vary from time to time and place to place

Answer:

D

Explanation:

It states that D has oxygen, and is closer to the Sun.

Hope this helped, and please mark as Brianliest <3

Answer:

I am pretty sure it is B

Explanation:

The others would either burn u like a crispy chicken nugget or freeze you like a popsicle

Answer:

\(\boxed {\boxed {\sf 146 \ g \ NaNO_3}}\)

Explanation:

To convert from moles to mass, the molar mass is used. This tells us the grams in 1 mole of a substance.

We know the compound is sodium nitrate.

Sodium has an oxidation state of +1 and nitrate's is -1. When they bond, sodium gives an electron to nitrate and the charges balance out. We don't need to add any additional subscripts.

The molar mass is found on the Periodic Table. It is the same as the atomic mass, but the units are grams per mole. Look up the values for the individual elements.

Notice that in the formula, oxygen has a subscript of 3. We must multiply oxygen's molar mass by 3 before adding the other molar masses.

Use the molar mass as a ratio.

\(\frac {84.9937693 \ g \ NaNO_3}{1 \ mol \ NaNO_3}\)

Multiply by the given number of moles: 1.72

\(1.72 \ mol \ NaNO_3 *\frac {84.9937693 \ g \ NaNO_3}{1 \ mol \ NaNO_3}\)

The units of moles of sodium nitrate cancel.

\(1.72*\frac {84.9937693 \ g \ NaNO_3}{1}\)

\(146.1892832 \ g \ NaNO_3\)

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we found, that is the ones place.

The 1 in the tenths place tells us to leave the 6.

\(146 \ g \ NaNO_3\)

1.72 moles of sodium nitrate has a mass of approximately 146 grams.

Answer:

density =mass/ volume

Explanation:

isn't this physics ...

so is the mass is 19 g and volume = 25 ml first convert to same units (g/cm3)

1ml = 1cm3

same units so no need to convert

19 divided by 25 = 0.76

0.76 g/cm3

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Answer:

1) C

2) A

3) B

4) E

Explanation:

Answer: 4.8 grams of hydrogen is 2.4 moles, and 38.4 grams of oxygen is 1.2 moles. This is exactly the Stoichiometry ratio of the reaction, therefore the two will both completely react giving rise to the same total mass of water.

Answer:

C

Explanation:

Read it from my 8th grade text book a few years back.

Answer:

C   l i f e

Explanation:

Answer:

Now, we have to determine the limiting reagent.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g of

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂O

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂OMaximum amount of water that can be formed is 27 g.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂OMaximum amount of water that can be formed is 27 g.For, amount of oxygen left of unreacted, Only 24 g of oxygen will react.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂OMaximum amount of water that can be formed is 27 g.For, amount of oxygen left of unreacted, Only 24 g of oxygen will react.But 29 g is the given amount. Amount of oxygen unreacted = 29 - 24 = 5 g

The theoretical yield of the given chemical equation is 64 g and limiting reactant is oxygen.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

As per the equation 4 g hydrogen reacts with 32 g oxygen thus 8 g hydrogen will react with 8×32/4=64 g oxygen.

Thus, the  theoretical yield of the given chemical equation is 64 g .

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The substance in the image above would be classified as a mixture of elements (option E).

A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.

On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.

According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.

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As the compound has alkyne as the functional group the correct option is A.

Functional group is defined as a substituent or a group of atoms or an atom due to which chemical reactions are carried out. Each functional group will react in the same way regardless to the parent carbon chain to which it is attached.This helps in prediction of chemical reactions.

The reactivity of functional group is increased by making modifications in the functional group .Atoms that  are present in functional groups are linked to each other by means of covalent bonds.They are named along with the organic compounds according to IUPAC nomenclature.

As the compound has alkyne as the functional group the correct option is A.

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During the electrolysis of an aqueous solution of potassium sulfate, multiple products can be produced at the cathode depending on the experimental conditions like hydrogen gas (H2), hydroxide ions (OH-). It is also possible for electrons to be reduced at the cathode like copper. Additionally, if the solution is acidic, oxygen gas (O2) can be produced at the anode and migrate to the cathode, where it can be reduced to form water.

Hydrogen gas (H2) is formed when water is reduced at the cathode. The reduction of water produces hydroxide ions (OH-) and hydrogen ions (H+), with the hydrogen ions being reduced to hydrogen gas.

Hydroxide ions (OH-), which can also be produced by the reduction of water. The presence of hydroxide ions can be detected by observing the solution turning pink due to the phenolphthalein indicator.
It is also possible for electrons to be reduced at the cathode, which can result in the formation of other products such as copper. If copper electrodes are used, copper ions from the solution can be reduced to form copper atoms that plate onto the electrode. Additionally, if the solution is acidic, oxygen gas (O2) can be produced at the anode and migrate to the cathode, where it can be reduced to form water.
It is important to note that the experimental conditions can greatly influence the products produced at the cathode. For example, if the electrodes are not of the same material or if the voltage is unevenly distributed, it is possible for twice as much gas to form at one electrode than the other. If the solution is not stirred or agitated, gas bubbles may only be visible at one electrode. Additionally, the presence of different indicators on each side of the cell can cause different colors to form at each electrode. For example, a brown color may form at one electrode and disappear at the other, or the indicator on one side may turn yellow while the other turns blue.

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The one that best describes the regioselectivity and stereospecificity in the Bronsted acid-catalyzed addition of water to an alkene reaction is Markovnikov orientation with syn-addition. Hence option A.

The preference of E and Y for bonds with carbon atoms an or b is referred to as the Markovnikov orientation. The example below demonstrates how, depending on the reaction conditions, a proton acid HY can add to the -bond of an unsymmetrical alkene with either a Markovnikov or an anti-Markovnikov orientation.

When hydrogen itself forms a double bond with the least-substituted carbon atom in asymmetrical alkenes or alkynes, the Markownikoff or Markovnikov rule determines the orientation of the electrophilic addition of hydrogen halides. (or triple bond). So, as conculsion, option A is correct.

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Complete question - which of the following describes correctly about the regioselectivity and stereospecificity in the bronsted acid-catalyzed addition of water to an alkene reaction?

Group of answer choices

1. markovnikov orientation with syn-addition

2. markovnikov orientation with anti-addition

3. anti-markovnikov orientation with syn-addition

4. anti-markovnikov orientation with anti-addition

5. markovnikov orientation with both syn- and anti-addition

Answer:

O 6

Explanation:

Oxygen has six valence electrons, two in the 2s subshell and four in the 2p subshell.

Explanation:

Sodium is the element having one valance electron and 3 energy level and is a metal.Its atomic number is 11 .So in first energy level ,there is 2 electrons ,in second energy level,there is 8 electrons and in third energy level,there is one electron.The one electron in the third energy level is called valance electron and it is a metal in the sence it has only one valance electron and it can easily loose it and gain +ve charge.

A central atom in a molecule that is sp hybridized contains two sp hybrid orbitals.

When a central atom in a molecule undergoes sp hybridization, it produces two sp hybrid orbitals. Hybridization happens when the core atom's valence electrons are rearranged to produce a new set of hybrid orbitals with a certain shape.

One s orbital and one p orbital from the central atom combine to generate two sp hybrid orbitals in the case of sp hybridization. These hybrid orbitals are utilised to form bonds with other atoms in the molecule and are orientated linearly with an angle of 180 degrees between them.

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