Mr. Beber feeds his dog 1/5 of a cup of dog food each day. How long will 9 cups of dog food last?

The measure of the smaller interior angle is approximately 144 degrees.

The measure of the larger interior angle is 36 degrees.

Let's denote the measure of the smaller interior angle as x.

According to the given information, the measure of one interior angle (let's call it y) is 0.25 times the measure of the smaller angle. Therefore, we can write the equation:

y = 0.25x

Since a parallelogram has opposite angles congruent, we know that the sum of the measures of the smaller and larger angles is 180 degrees. Hence, we can write another equation:

x + y = 180

Substituting the value of y from the first equation into the second equation, we have:

x + 0.25x = 180

Combining like terms:

1.25x = 180

To find the measure of the smaller angle (x), we divide both sides of the equation by 1.25:

x = 180 / 1.25

x ≈ 144

Therefore, the measure of the smaller interior angle is approximately 144 degrees.

To find the measure of the larger interior angle, we substitute the value of x into the equation:

y = 0.25x

y = 0.25 * 144

y = 36

Hence, the measure of the larger interior angle is 36 degrees.

Learn more about interior angle here

https://brainly.com/question/12834063

#SPJ11

Answer:

B

Step-by-step explanation:

====================================================

Explanation:

Divide by the smallest prime 2

90/2 = 45

Then divide by the next smallest prime 3 (since 2 won't go into 45)

45/3 = 15

Repeat the last step

15/3 = 5

We stop because the result is prime.

Note the denominators are 2, 3, 3. The final result is 5 which is prime.

So the prime factors are 2, 3, 3,  and 5

They multiply to 2*3*3*5 = 90.

We can condense it to 2*3^2*5 = 90 because 3*3 = 3^2.

Answer and Step-by-step explanation:

The prime factorization of 90 is 2 × 3 × 3 × 5 or 2 × 32 × 5, where 2, 3, and 5 are the prime numbers. You can find "prime factorization" by following two simple steps. Step 1: Start by dividing the number by the first prime number 2 and continue dividing by 2 until you get a decimal or remainder. Then divide by 3, 5, 7, etc. until the only numbers left are prime numbers. Step 2: Write the number as a product of prime numbers.

Hope you found this helpful! Have a wonderful day! <3

Answer:

h = 0.79591836734694 m

Step-by-step explanation:

h = height

s = slant height

a = side length

P = perimeter of base

e = lateral edge length

r = a/2

V = volume

L = lateral surface area

B = base surface area

A = total surface area

Answer:

no because the lines are not parallel

The probability density function (PDF) for a uniform distribution ranging between 2 and 6 is 0.25 i.e., the correct option is D.

In a uniform distribution, all values within the range have an equal probability of occurring. The PDF is used to describe the distribution of probabilities over the range. For a uniform distribution ranging between 2 and 6, the PDF would be a horizontal line with a height of 1/4 (or 0.25) between 2 and 6, and zero outside that range. However, at any specific point within the range, the PDF does not have a defined value.

The reason for this is that the PDF for a continuous random variable in a uniform distribution is defined as a constant value divided by the width of the range. Since the range for this uniform distribution is 4 (from 2 to 6), the constant value would be 1/4.

However, at any specific point within the range, the width of the range becomes zero, resulting in an undefined value for the PDF.

Therefore, the PDF for a uniform distribution ranging between 2 and 6 is indeed 0.25, as it provides a constant probability density over the entire range.

Learn more about probability density function (PDF) here:

https://brainly.com/question/30895224

#SPJ11

We want to know the cost for 7 rides and for 10 rides. We see that for each ride the price increases by $3.50. And thus the price for 7 rides will be:

And the price for 10 rides will be:

Now, for finding the equation we use that the state fair charges $8 for a general admission, and $3.50 for each ride. This can be written as:

where x represents the number of rides.

For example, if we want to know the cost for 18 rides, we replace the value of x by 18, and we get:

Then, the cost for 18 rides is $71.

Answer:

Step-by-step explanation:

Answer is 65 simple

Answer:

soln;

given equation is 6x + 5 = 2y

or, 6x -2y + 5 = 0

comparing with ax + by + c = 0

a = 6, b = -2, c = 5

Answer:

Step-by-step explanation:

ratttt

For a uniform distribution random variable X, the probability that the random variable has a value between 0.6 and 2.1 is equals to 0.1875. So, option(a) is right one.

The uniform distribution is defined as a continuous probability distribution and the events are equally likely to occur. In other words in this distribution every possible outcome has an equal probability. There is a uniform distribution of variable. Let the random variable be denoted by X be uniformly distributed. The above figure shows uniform density curve for X. That is \( X \: \tilde \: \: U( 0, 8) \).

Probability density function is f(x) = \(\frac{ 1}{8} = 0.125\)

We have to determine probability that the random variable has a value between 0.6 and 2.1, P(0.6 ≤ X ≤ 2.1). So, required probability is P(0.6 ≤ X ≤ 2.1) = \(\int_{0.6}^{2.1} f(x) dx \).

\(= [ 0.125x ]_{0.6}^{2.1}\)

= 0.125 ( 2.1 - 0.6)

= 0.125 ( 1.5)

= 0.1875

Hence, required value is 0.1875.

For more information about uniform probability distribution, visit:

https://brainly.com/question/28984186

#SPJ4

Complete question:

the above figure complete the question.

Using the uniform distribution density curve answer the question :

what is the probability that the random variable has a value between 0.6 and 2.1?

a) 0.1875

b) 0.4625

c) 0.3375

d) 0.2125

The required rates for maintaining mud properties constant downstream of the centrifuge are as follows:

Bentonite: 0 lbm/min

Deflocculant: 0 lbm/min

Water: 1.74 gal/min

Barite: 130 lbm/min

The recommended treatment upon increasing the mud weight to 17.5 lbm/gal would include adjustments in the following areas:

Barite: Add barite at a suitable rate to achieve the desired mud weight.

Bentonite: Adjust the rate of bentonite addition to maintain a consistent solids content.

Deflocculant: Monitor the yield point and plastic viscosity, adjusting the deflocculant as necessary.

Water: Adjust the water content to achieve the desired mud weight.

Here, we have,

To compute the rate at which bentonite, deflocculant, water, and API barite should be added downstream of the centrifuge to maintain the mud properties constant, we need to balance the input and output of each component.

Bentonite:

The rate of bentonite addition should be equal to the rate of bentonite removal in the centrifuge to maintain constant mud properties. the rate of bentonite addition downstream of the centrifuge would be zero.

Deflocculant:

The rate of deflocculant addition should also be equal to the rate of deflocculant removal in the centrifuge to maintain constant mud properties. Again, assuming negligible removal in the centrifuge, the rate of deflocculant addition downstream of the centrifuge would be zero.

Water:

Water entering the centrifuge:

Rate of water entering = 10 gal/min

Water carried over in the overflow:

Rate of water carried over = (20 gal/min) * (9.5 lbm/gal) / (23 lbm/gal) ≈ 8.26 gal/min

Rate of water addition downstream of the centrifuge = Rate of water entering - Rate of water carried over = 10 gal/min - 8.26 gal/min = 1.74 gal/min

Barite:

Mud density increase in the centrifuge:

Density increase = (23 lbm/gal) - (16.5 lbm/gal) = 6.5 lbm/gal

Rate of barite addition downstream of the centrifuge = 6.5 lbm/gal * 20 gal/min = 130 lbm/min

Therefore, the required rates for maintaining mud properties constant downstream of the centrifuge are as follows:

Bentonite: 0 lbm/min

Deflocculant: 0 lbm/min

Water: 1.74 gal/min

Barite: 130 lbm/min

To determine the recommended treatment upon increasing the mud weight to 17.5 lbm/gal,

Given:

Current mud weight: 15 lbm/gal

Solids content: 29% (expressed as a fraction, i.e., 0.29)

Plastic viscosity: 32 cp

Yield point: 20 lbf/100 sq ft

Desired mud weight: 17.5 lbm/gal

Desired density (lbm/gal) = Target mud weight (lbm/gal)

Desired density = 17.5 lbm/gal

Volume of mud (gal) = Current volume of mud (gal) * (Desired density - Current density) / (Density of solids - Current density)

Current volume of mud can be calculated as follows:

Current volume of mud (gal) = (Total mud weight - Weight of solids) / Density of mud

Weight of solids (lbm) = Current volume of mud (gal) * Solids content

Density of mud (lbm/gal) = Current mud weight

Density of solids (lbm/gal) = 1 (since the solids are assumed to have a density of 1 lbm/gal)

Barite:

Assuming the density of barite is 22 lbm/gal:

Density of barite = 22 lbm/gal

Bentonite:

Assuming the density of bentonite is 23 lbm/gal:

Density of bentonite = 23 lbm/gal

Deflocculant:

Assuming the target yield point is 15 lbf/100 sq ft:

Target yield point = 15 lbf/100 sq ft

Water:

Assuming the density of water is 8.34 lbm/gal:

Density of water = 8.34 lbm/gal

Now, let's calculate the treatment requirements using the above formulas:

Barite:

Volume of mud (gal) = (Total mud weight - Weight of solids) / Density of mud

Weight of solids = Current volume of mud (gal) * Solids content

Density of barite = 22 lbm/gal

Desired volume of barite (gal/min) = Volume of mud (gal) * (Density of barite - Current density) / (Density of barite)

Bentonite:

Density of bentonite = 23 lbm/gal

Desired volume of bentonite (gal/min) = Volume of mud (gal) * (Density of bentonite - Current density) / (Density of bentonite)

Deflocculant:

Target yield point = 15 lbf/100 sq ft

Desired weight of deflocculant (lbm/min) = Weight of solids (lbm) * (Target yield point - Current yield point) / (Target yield point)

Water:

Density of water = 8.34 lbm/gal

Desired volume of water (gal/min) = Volume of mud (gal) * (Target density - Density of solids) / (Density of water - Target density)

In summary, the recommended treatment upon increasing the mud weight to 17.5 lbm/gal would include adjustments in the following areas:

Barite: Add barite at a suitable rate to achieve the desired mud weight.

Bentonite: Adjust the rate of bentonite addition to maintain a consistent solids content.

Deflocculant: Monitor the yield point and plastic viscosity, adjusting the deflocculant as necessary.

Water: Adjust the water content to achieve the desired mud weight.

learn more on density click;

https://brainly.com/question/33294102

#SPJ4

Answer:

X = 5

Step-by-step explanation:

To find the solution to a problem like this remember the order of PEMDAS.

According to pemdas parenthesis comes first, do you would solve for this part of the equation by multiplying the outer number by each side inside the parenthesis

Aka 3 × X and 3 × 1

This would make your new equation

3x + 3 = 18

Then, you would try to shorten the equation by removing or adding something to both sides.

In the given equation that would be subtracting 3 by either side, leaving over

3x = 15

Lastly, to find X you would divide 3x and 15

3 ÷ 15 = 5

Therefore X = 5

Answer:

x = 5

Step-by-step explanation:

1. First we need to simplify both sides of the equation.

( 3 )( x ) + ( 3 )( 1 ) = 18 Distribute the equation.

= 3x + 3 = 18

2. Now subtract 3 from both sides.

3x + 3 − 3 = 18 − 3

3x = 15

3.  Now divide both sides by 3.

3x/3 = 15/3

x = 5

Answer:

the answer is yes  

because it is within the shaded region of both inequalities

Answer:

C. 35

Step-by-step explanation:

7 ÷ \(\frac{1}{5} \7\) = 35

Answer:

C. 35

Step-by-step explanation:

There are 5 1/5 cup servings in one cup. And 5*7=35

The value of f[g(x)] is - 64x³ - 336x² - 588x - 340 and the value of g[f(x)] is -4x³ + 19

The functions are as follows; f(x) = -x³ +3 and g(x) = 4x+7

The value of f[g(x)] is obtained by replacing every x in f(x) with the value of g(x) as given below

f[g(x)] = f(4x + 7) = - (4x + 7)³ + 3

When we expand (4x + 7)³, it gives us 64x³ + 336x² + 588x + 343

Then

f[g(x)] = - 64x³ - 336x² - 588x - 340

Similarly, g[f(x)] is obtained by replacing every x in g(x) with the value of f(x) as shown below;

g[f(x)] = g(-x³ + 3) = 4(-x³ + 3) + 7g

[f(x)] = -4x³ + 19

Therefore,

f[g(x)] = - 64x³ - 336x² - 588x - 340

g[f(x)] = -4x³ + 19

Learn more about the function at

https://brainly.com/question/32520165

#SPJ11

Answer:

267

Step-by-step explanation:

Answer:    Use Gauth Math. What is the topic about?

Step-by-step explanation:

Answer:

A (?)

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

if you look at the graph the area thats purple for texas is farther up it meaning the tempature is higher.

Answer:

\(12\) cm

Step-by-step explanation:

If Kelsey knit a total of \(6\) cm of scarf over \(2\) nights, then we know that she can knit \(\frac{6}{2}=3\) cm each night. Therefore, after \(4\) nights of knitting, Kelsey would have knit a total of \(3*4=12\) cm of scarf in total. Hope this helps!

Answer:

20 L volume and 12.5 cm depth.

Step-by-step explanation:

See attached image.

Answer:

N ( a number) \(\leq\) 40

Step-by-step explanation:

Or just say

N \(\leq\) 40

Answer:

x≤40

Step-by-step explanation:

x (x is number in this case)

x≤40

The special sign used has the line under it because it includes 40 as well (at most is used not less than).

:) Hope this helps :)

The equation of the sphere that passes through the point (3, 6, 3) and has center (5, 1, -1) is (x - 5)^2 + (y - 1)^2 + (z + 1)^2 = 45.

To find the equation of a sphere that passes through the point (3, 6, 3) and has center (5, 1, -1), we can use the general equation of a sphere:

(x - h)^2 + (y - k)^2 + (z - l)^2 = r^2

Where (h, k, l) represents the center of the sphere, and r represents the radius.

Given that the center of the sphere is (5, 1, -1), we have h = 5, k = 1, and l = -1.

To find the radius, we can use the distance formula between the center of the sphere and the given point (3, 6, 3):

r = sqrt((3 - 5)^2 + (6 - 1)^2 + (3 - (-1))^2)

= sqrt((-2)^2 + 5^2 + 4^2)

= sqrt(4 + 25 + 16)

= sqrt(45)

= 3√5

Substituting the values of the center and the radius into the equation, we have:

(x - 5)^2 + (y - 1)^2 + (z - (-1))^2 = (3√5)^2

(x - 5)^2 + (y - 1)^2 + (z + 1)^2 = 45

Therefore, the equation of the sphere that passes through the point (3, 6, 3) and has center (5, 1, -1) is (x - 5)^2 + (y - 1)^2 + (z + 1)^2 = 45.

Learn more about sphere here

https://brainly.com/question/20394302

#SPJ11

Answer:

0

Step-by-step explanation:

13 is visibly less then 6 meters, you cant cut any amount of rope with the same thickness that is 13 meters long from it.

Answer:

Does the answer help you?

Answer:

\(\frac{1}{70}\)

Step-by-step explanation:

P(gold) = \(\frac{gold}{total}\) = \(\frac{5}{350}\) = \(\frac{1}{70}\)

Answer:

14/61 cm per day

Step-by-step explanation:

Use the slope formula  \(\frac{y_{2} - y_{1}}{x_{2} - x_{1}}\)

Plug it in \(\frac{16-2}{61-0}\)

Simplify \(\frac{14}{61}\)

If the graph shows the height of a plant over a 2-month growth period. The rate of change per day will be 14/61.

It is defined as the change in values of a dependent variable with respect to the independent variables. Analyze the points first, then calculate the y-values for each interval. After that, subtract the input and output values. Divide and then simplify the differences to determine the rate of change.

It is given that, the graph shows the height of a plant over a 2-month growth period

The kind of graph must be considered when calculating the rate of change. Finding the ratio between the change in output values and the change in their corresponding input values is how linear graphs with constant rates of change are determined. Look at the following linear graph.

The slope of a linear function represents the pace of change. We have two points to determine the slope,

The rate of change per day is found as,

=y₂-y₁/x₂-x₁

=16-2/61-0

=14/61

Thus, if the graph shows the height of a plant over a 2-month growth period. The rate of change per day will be 14/61.

Learn more about the rate of change here:

brainly.com/question/12786410

#SPJ2

Answer:

That ain't gonna fit in the box because the side is 19.3cm and the side of the box is 15 cm,also its to tall