If the entire amount is 50.0 mL, the pH of this fluid at the equivalence point is 5.13.
What is equivalence point?The titration's equivalence point is the point at which the titrant concentration is just right to fully eliminate the analyte solution. In such an acid-base titration, the equivalence point occurs when moles of base equal molecules of acid and the only components of the fluid are sodium and water. Equivalence point diagram.
How is the equivalence point determined?The equilibrium point for acid-base titrations can be identified very quickly. A simple pH metre is used to measure the pH of the fluid being titrated after different amounts of titrant have been introduced to create a titration curve. The slope can then be read to determine the equality point.
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An ethylene glycol solution contains 30.8 g of ethylene glycol (C2H6O2) in 96.6 mL of water. (Assume a density of 1.00 g/mL for water.) Determine the freezing point of the solution. Determine the boiling point of the solution
The freezing point of the solution is -11.8 °C.
The boiling point of the solution is 103.31 °C.
To determine the freezing point of the solution, we can use the equation:
ΔTf = Kf * m
where:
ΔTf is the freezing point depression,
Kf is the cryoscopic constant (for water, Kf = 1.86 °C/m),
m is the molality of the solution (moles of solute per kilogram of solvent).
First, let's calculate the molality (m) of the solution:
Molar mass of ethylene glycol (C2H6O2):
C = 12.01 g/mol
H = 1.01 g/mol (x 6) = 6.06 g/mol
O = 16.00 g/mol (x 2) = 32.00 g/mol
Total molar mass = 12.01 g/mol + 6.06 g/mol + 32.00 g/mol = 50.07 g/mol
Number of moles of ethylene glycol (C2H6O2) = mass / molar mass
Number of moles = 30.8 g / 50.07 g/mol = 0.615 mol
Mass of water = volume x density = 96.6 mL x 1.00 g/mL = 96.6 g
Now, let's calculate the molality:
Molality (m) = moles of solute / mass of solvent (in kg)
Molality = 0.615 mol / 0.0966 kg = 6.36 mol/kg
Now we can calculate the freezing point depression (ΔTf):
ΔTf = Kf * m
ΔTf = 1.86 °C/m * 6.36 mol/kg = 11.8 °C
To find the freezing point of the solution, subtract the freezing point depression from the freezing point of pure water (0 °C):
Freezing point = 0 °C - 11.8 °C = -11.8 °C
To determine the boiling point of the solution, we can use the equation:
ΔTb = Kb * m
where:
ΔTb is the boiling point elevation,
Kb is the ebullioscopic constant (for water, Kb = 0.52 °C/m),
m is the molality of the solution (same value as calculated before: 6.36 mol/kg).
ΔTb = 0.52 °C/m * 6.36 mol/kg = 3.31 °C
To find the boiling point of the solution, add the boiling point elevation to the boiling point of pure water (100 °C):
Boiling point = 100 °C + 3.31 °C = 103.31 °C
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for a neutralization reaction, would you expect the magnitude of q to increase, decrease, or stay the same if the concentration of only the acid were doubled? why? group of answer choices increase; if only the concentration of acid were doubled more neutralization reaction would occur because there is more acid than base stay the same; if only the concentration of acid were doubled no additional neutralization reaction would occur decrease; if only the concentration of acid were doubled less neutralization reaction would occur because there is less base than acid
For a neutralization reaction, more heat is evolved and Q is doubled.
When the concentration of the acid alone is twice in a neutralization process, the value of q (heat of neutralization) is increased twofold. A neutralizing reaction happens when an acid and a base are combined.A neutralization reaction is a reaction in which an acid undergoes a reaction with a base to form salt and water. Ionically, a neutralization reaction goes as follows; H^+(aq) + OH^-(aq) ------> H20(l).The heat of neutralization (Q) of the system depends on the concentration of the solutions. Since Q is dependent on concentration, if the concentration of any of the reactants is doubled, more heat is evolved hence Q is doubled.To learn more about neutralization reaction visit:
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Which protozoan is a ciliate?
A. Paramecium
B. Giardia
C. Amoeba
D. Plasmodium
3) The nucleus in a photograph of a cell measures 3 mm across. If the magnification in the photograph is x 500, what is the actual size of the nucleus?
Answer:
1500mm oqkwndbdjdhdndjdd
A sample of 0.53 of carbon dioxide was obtained by heating 1.31 grams of calcium carbonate. What is the percent yield for this reaction?
Step 1
The reaction:
CaCO3 + heat => CaO + CO2 (completed and balanced)
-----------------------
Step 2
Information provided:
Actual yield = 0.53
Which compound is a tertiary halogenoalkane?
A. (CH3CH2)2CHBr
B. CH3(CH2)3CH2Br
C. (CH3)2CHCH2CH2Br
D. CH3CH2C(CH3)2Br
The compound that is a tertiary halogenoalkane is D. CH3CH2C(CH3)2Br, since it has a tertiary carbon (bonded to three other carbon atoms).
A halogen atom (Br, Cl, I, or F) is joined to a carbon atom that is connected to three more carbon atoms to form a tertiary halogenoalkane. Option D creates a tertiary halogenoalkane by bonding the Br-attached carbon atom to three additional carbon atoms. The Br-attached carbon is connected to two other carbon atoms, making Option A a secondary halogenoalkane. Because the carbon atom with the Br attached is only connected to one other carbon atom, option B is a primary halogenoalkane. Because the Br-attached carbon is connected to two additional carbon atoms, option C also qualifies as a secondary halogenoalkane.
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1) Which diagram shows an element?
2) which diagram shows a mixture?
3) which diagram shows a compound?
4)which diagram only shows atoms chemically bonded together?
5) which diagram shows different atoms of matter physically combined together?
Answer:
r
I think 1 option okkkkkkkkkkkkk
Explanation:
mhfs4trfsetc fthcfeencfgeh,cbwjh vbytbnmdtuh3lg dl5flnfwk3t kqre,fvbt,klkkkjh
______ is a water-soluble vitamin that is especially important in amino acid metabolism, and is a coenzyme in over 100 chemical reactions.
Vitamin B-6 is the water-soluble vitamin important in amino acid metabolism, and is a coenzyme in over 100 chemical reactions.
What is a vitamin?Vitamins are organic molecules, essential micronutrients that organisms need in small amounts for the proper functioning of their metabolism. Essential nutrients cannot be synthesized by the body or are not available in sufficient amounts and must be obtained from food.
The vitamins are classified as either fat-soluble (vitamins A, D, E, K) or water-soluble (vitamins B, C). The difference between these two groups determines how each vitamin functions in the body. Water-soluble vitamins are absorbed quickly and excess is released, whereas fat-soluble vitamins dissolve slowly and excess is stored in the liver, means that it may cause problems.
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use equation 7.24 and the data in chapter 4 (table 4.2) to calculate the standard molar entropy of cl2 (g) at 298.15 k. compare your answer with the experimental value of 223.1 jmol-1k-1
The standard molar entropy of cl2 (g) at 298.15 k is -0.05 J/mol K which is very small and may even be within the experimental error.
To calculate the standard molar entropy of Cl2 (g) at 298.15 K, we can use equation 7.24:
ΔS° = ΣS°(products) - ΣS°(reactants)
Using the data from chapter 4, we can find the standard molar entropy of Cl2 (g) and its elements:
S°(Cl2, g) = 223.07 J/mol K
S°(Cl2, l) = 223.15 J/mol K
S°(Cl, g) = 223.06 J/mol K
Since we are only interested in the gas phase, we will use the value for S°(Cl2, g). The equation for the formation of Cl2 (g) from its elements is:
Cl2 (g) = Cl (g) + Cl (g)
So, the reactants are two Cl (g) atoms, and the products are one Cl2 (g) molecule. Therefore:
ΔS° = S°(Cl2, g) - 2S°(Cl, g)
ΔS° = 223.07 J/mol K - 2(223.06 J/mol K)
ΔS° = -0.05 J/mol K
This value is very small and may even be within the experimental error, but it indicates that the formation of Cl2 (g) from its elements slightly decreases the entropy of the system.
Comparing this result to the experimental value of 223.1 J/mol K, we see that there is a small difference, which may be due to the approximations made in the calculation or the experimental error. However, the two values are very close, which indicates that the theoretical model used to calculate the standard molar entropy is a good approximation for this system.
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Complete Question:
container a holds 712 ml 712 ml of ideal gas at 2.10 bar2.10 bar . container b holds 134 ml 134 ml of ideal gas at 4.80 bar4.80 bar . if the gases are allowed to mix together, what is the partial pressure of each gas in the total volume?
The saturation pressure of every gas in the entire volume, if somehow the gases being allowed to mix, is 2.5 atm.
Describe gases.In comparison to other forms of matter, like solids and liquids, vapors have a lower density. Particles have a great deal of kinetic energy yet aren't very attracted to one another, thus there is a lot of unoccupied space between them. A sampling of matter that assumes the shape of the bottle it is stored in and develops a consistent density on the inside of the container is referred to as a gas.
Pressure = 2.10 atm
Temperature = T K
Volume = 712 mL
= 0.712 L (1 mL = 0.001 L)
PV=nRT,
2.10 atm × 0.712 L = n × 0.0821 L.atm/K.mol × T K
n = 19.2232 / T moles
For Container B :
Pressure = 4.80 atm
Temperature = T
Volume = 134 mL
= 0.134 L (1 mL = 0.001 L)
= 4.80 atm × 0.134 L = n × 0.0821 L.atm/K.mol × 298 K
= n = 6.3435 / T moles
Total moles = 19.2132 / T moles + 6.3435 / T moles
= 25.5567 /T moles
Total Volume = 712 + 134 mL = 846 mL = 0.846 L
P × 0.846 L = 25.5567 /T × 0.0821 L.atm/K.mol × T
Total P = 2.5 atm
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10. How much energy is needed to melt 30 g of H20 at 0°C ?
Given the pKa’s for H2CO3: pKa1 = 6.35; pKa2=10.33, what is the pKb1 of CO32- (Kb1 is the equilibrium constant of the reaction: CO32- + H2O ⇌ HCO3- + OH-)?
(A) 14.00
(B) 10.33
(C) 3.67
To determine the pKb1 of CO32-, we can use the relationship between pKa and pKb for conjugate acid-base pairs:
pKa + pKb = pKw
where pKw is the ionization constant of water, which is approximately 14. Therefore, we can rearrange the equation to solve for pKb:
The pKb value represents the negative logarithm of the equilibrium constant (Kb) for the reaction of a base with water. In this case, we are interested in the equilibrium reaction between CO32- and water, which can be represented as CO32- + H2O ⇌ HCO3- + OH-.
By utilizing the relationship pKa + pKb = pKw, we can rearrange the equation to solve for pKb. Given that pKa1 of H2CO3 is 6.35, we subtract this value from pKw (approximately 14) to obtain pKb1
pKb = pKw - pKa
pKb1 = 14 - 6.35 = 7.65
Since none of the given answer choices matches the calculated value, it seems there might be an error or omission in the available options. Please double-check the answer choices provided or refer to additional information to obtain the correct pKb1 value for CO32-.
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What is the nuclear equation for decay of Am - 241
Americium is a radioactive element .
It goes through alpha decay during nuclear reactions .The nuclear reaction.is given by
\(\rm {}^{241}_{95}Am\longrightarrow {}^{237}_{93}Np+{}^4_2\alpha\)
Np stands for NuptuniumHere alpha can be written as He too
Which of the following is not a chemical property?
an oxygen atom with 9 neutrons in its nucleus (Enter your answer using the format AX.)
You Do 3: How many weeks are there in 3.87 x 10 minutes?
What is an object that allows electricity to flow through it?
conductor
open circuit
insulator
Answer:
its a conductor
Explanation:
Conductors allow electricity to flow through them like metal wires
Answer: It is a conductor because a conductor allows electricity or heat to pass through and it is right because i took the quiz
Find the empirical formula of a compound found to contain 26.56% potassium, 35.41% chromium, and the remainder oxygen.
The empirical formula of a compound found to contain 26.56% potassium, 35.41% chromium, and the remainder oxygen is K₂Cr₂O₇.
What is an empirical formula ?The term an Empirical formula is defined as the chemical formula of a compound that gives the ratios of the elements present in the compound but not the actual numbers or arrangement of atoms.
The number of mole of each element in the compound can be identified by dividing each element's percentage with their respective molar weights:
Potassium K = 26.56%
= 26.56 / 39.1
= 0.68
Chromium, Cr = 35.41%
= 35.41/52
= 0.68
Oxygen,
O = 100 - 26.56+35.41
= 38.03/16
= 2.38
Divide each number of moles by the smallest.
K = 0.68/0.68
= 1
Cr = 0.68/0.68
= 1
O = 2.38/0.68
= 3.5
Thus, the empirical formula would be KCrO₃.₅
Multiply all by 2 to remove the fraction:
Then the empirical formula would be K₂Cr₂O₇.
Thus, the empirical formula of a compound found to contain 26.56% potassium, 35.41% chromium, and the remainder oxygen is K₂Cr₂O₇.
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Part A (a) A mixture is prepared by mixing 70 mL of ethanol with 30 mL of H20. In this mixture, H2O is the solute solid solvent O ionic compound O solution Submit Request Answer
In the solution water is solute and ethanol is solvent.
Binary solution
A mixture of two liquids that are completely miscible one with another is known as a Binary solution. The boiling point of binary solution depends upon the composition of the solution.
A binary solution consists of a solute and a solvent.
The solute is usually present in smaller quantity and solvent is in larger quantity.
If a solution has 70 ml ( larger quantity ) of ethanol , it means ethanol is the solvent .
water with 30 ml of quantity ( smaller quantity ) will be the solute.
So , in the mixture, water is the solute.
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4 nuclear chemistry questions.
The correct options for 8, 9 and 10 are C, A and A respectively.
8. Nuclear reactions, including nuclear fusion and nuclear fission, both involve the conversion of mass into energy and the release of large amounts of energy.
9. The correct reaction is Be+,He-12C+1on.
The process of producing a nuclear reaction by colliding atomic nuclei with particles is called artificial transmutation. In this example, an alpha particle (He-12C) is used to bombard a beryllium nucleus (Be) to create a separate nucleus.
10. The picture shows a neutron colliding with a heavy nucleus, causing the nucleus to break into smaller pieces. This process is named nuclear fission.
11. Nuclear fission is a type of nuclear reaction that equation 1 shows. In this reaction a neutron is absorbed by a uranium-235 nucleus, resulting in the release of krypton-92, barium-142, another neutron, and energy. Nuclear fission, which is characterized by the breaking of a heavy nucleus into smaller pieces, occurs during this reaction.
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In some circumstances, materials that are being heated in the lab could catch fire. If a flammable substance in a beaker should catch fire while you are working but the flames are relatively contained, what is a simple method for extinguishing the flame
If a flammable substance in a beaker should catch fire while you are working but the flames are relatively contained, the simple method for extinguishing the flame is to cover the beaker with a watch glass or a larger beaker.
By doing so, the oxygen supply to the fire is cut off and the flame will extinguish.
Fire is a complex chemical process that occurs when a substance reacts with oxygen and releases heat and light in the form of flames. In laboratories, fires can occur due to various reasons such as faulty electrical connections, misuse of heating equipment, or the presence of flammable materials.
A flammable substance is a material that ignites easily and burns rapidly in the presence of a spark or open flame. Common examples of flammable substances found in laboratories include solvents, alcohols, and fuels.
A watch glass is a circular, slightly convex-shaped piece of glass used in laboratories to cover beakers or as a surface for evaporating small amounts of liquid. It is also used to hold solids when being weighed. It is relatively lightweight and can withstand high temperatures.
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Which element is not conserved in this unbalanced chemical equation?
2NaOH + H2S04 - NaSO4 + 2H20
Ο Α. Η
O B. S
O c. O
O D. Na
In the given unbalanced reaction, the number of sodium is not balanced. There must have two sodium in the product side also. The correct formula of sodium sulphate is Na₂SO₄.
What is mass conservation law?According to the law of conservation of mass, the total mass of a system is conserved. Thus, mass can neither be created nor be destroyed. Therefore, for a chemical reaction, the total mass in the product side must be equal to the total mass in the reactant side.
The balanced equation of a chemical reaction thus, obeying the mass conservation law where, each element have to be equal in number in both sides.
In the given reaction, the number of Na in reactant side is 2 and that in product side is 1 only. Thus total mass of sodium is not conserved. It can be corrected as Na₂SO₄ in the product side.
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which probing question lies within the scope of physics
A probing question that lies within the scope of physics could be: "What is the nature of dark matter and dark energy, and how do they influence the expansion of the universe?
Dark matter and dark energy are hypothetical forms of matter and energy that are believed to exist based on their observed gravitational effects on galaxies and the expansion of the universe.
Dark matter is thought to be a type of matter that does not interact with light or other electromagnetic radiation, while dark energy is an unknown form of energy that is causing the universe to expand at an accelerated rate.
Exploring the nature of dark matter and dark energy falls under the purview of physics because it involves understanding the fundamental forces and particles that govern the behavior of the universe.
Physicists study these phenomena by analyzing the gravitational effects they have on visible matter, conducting experiments to detect dark matter particles, and developing theoretical models to explain their properties and interactions.
Addressing this probing question requires the application of various branches of physics, such as cosmology, astrophysics, particle physics, and quantum mechanics.
Researchers employ observational data, theoretical frameworks, and advanced technologies to investigate the nature and origin of dark matter and dark energy, contributing to our understanding of the fundamental nature of the universe and its evolution.
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If a car travels 150 km in 3.0 hours, the speed is ?
Answer:
50km per hour.
Part of the speed, distance, time triangle.
To get speed, just divide distance by time. 150/3=50
I have a few minutes left! Will award 25 points!!
_____ Are useful for comparison purposes to determine the size of microscopic cell structures? A. Sizing beads B. Eye dropper bottles C. Meter sticks I am not sure between A or C?
Gold-198 is used to treat liver cancer. its half-life is 2.7 days. if you ingest 3.75 mg of au-198, how long would you have to wait for the amount of au-198 to fall to 0.75 mg?
To wait for the amount of Au-198 to fall to 0.75 mg when Gold-198 is used to treat liver cancer and has half-life is 2.7 days if ingest 3.75 mg of Au-198 would wait 6.26 days.
Gold-198 has a half-life of 2.7 days, which means that after 2.7 days, half of the initial amount of gold-198 would decay. To find out how long it would take for the amount of gold-198 to fall to 0.75 mg, we can use the following formula:
Final amount = Initial amount × (1/2)^(number of half-lives)
Let's assume that the initial amount of gold-198 is 3.75 mg, and we want to find out how many half-lives it would take for the amount to fall to 0.75 mg. We can set up the equation as follows:
0.75 mg = 3.75 mg × (1/2)^(number of half-lives)
Dividing both sides by 3.75 mg, we get:
0.2 = (1/2)^(number of half-lives)
Taking the logarithm of both sides, we get:
log(0.2) = number of half-lives x log(1/2)
Solving for the number of half-lives, we get:
number of half-lives = log(0.2) / log(1/2)
Using a calculator, we get:
number of half-lives ≈ 2.32
Therefore, it would take approximately 2.32 x 2.7 days = 6.26 days for the amount of gold-198 to fall to 0.75 mg.
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What can cause an offspring to have a physical trait neither of its parents has?
Answer: The main way that an offspring can exhibit a different physical trait than its parents is due to the fact of genetic mutation.
Explanation: A mutation within a parents sex cells can cause different traits to be shown in the offspring because these genetic mutations cause DNA to form that has crucial differences to the original DNA composition which can manifest itself as differences in physical characteristics. These can be not so serious mutations (such as someone being born with an extra finger) or they can be more serious such as leg or arm mutations which can mean arms can be crooked or shorter than they are supposed to be. I hope this has been of assistance to you and if you have any further questions please do not hesitate to ask :)
The temperature of a sample of liquid water changes from 50°C to 30°C. Which statement best explains the change
that must happen at the molecular level?
ОООО
The molecules move more quickly and their average kinetic energy increases.
The molecules move more slowly and their average kinetic energy decreases.
The molecules move more quickly and their average kinetic energy decreases.
The molecules move more slowly and their average kinetic energy increases.
Answer:
The molecules move more slowly and their average kinetic energy decreases
Explanation:
The increased temperature meant that the atoms in liquid had a greater average energy of motion so as the temperature decreases the reaction would be inverse.
The branch of science which deals with the chemicals bond is called chemistry.
The correct option is B.
The energy which is produced by the motion of the particles is called kinetic energy. Temperature increases the motion of the particles. So, the kinetic energy increases when the temperature rises.
According to the question, the temperature of the water decreases therefore the kinetic energy decreases.
Hence, the correct option is B that is the molecules move more slowly and their average kinetic energy decreases.
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Calculate the number of moles in 0.48 g of Cu.
1) Convert grams to moles
The molar mass of Cu is 63.546 g/mol.
\(molCu=0.48gCu\cdot\frac{1molCu_{}}{63.546gCu_{}}_{}=0.007553molCu\)0.007553 mol of Cu is equal to 7.6*10^-3 mol of Cu.
.
How did lithium get verified as a new element? (PLS HELP!)
Answer:
The element was discovered on Earth in 1817 by Johan August Arfvedson (1792-1841) in Stockholm when he investigated petalite, one of the first lithium minerals to be discovered. (It was observed to give an intense crimson flame when sprinkled on to a fire.)