Molecules of _________, ________, _________ move at different rates through a medium as simple as paper.

Dendrites is the part of the neuron that receives input in the form of chemical stimuli.

Axons provide synaptic signals to dendrites, and the sum of these signals determines whether the neuron will fire an action potential.

Appendages called dendrites are made to receive signals from neighboring cells. They generate projections that are triggered by other neurons and transmit the electrical charge to the cell body, giving them the appearance of a tree-like structure.

Several other neurons send signals to dendrites, which then transmit those signals to the cell body. A neuron will release an action potential, an electrical impulse that stimulates neighboring neurons, if it has been sufficiently activated. These neurons are arranged in vast networks that interact to produce ideas and actions.

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C4H5N2O is the empirical formula. A compound has a molecular weight of 345, 86.88% carbon, 13.12% hydrogen, and a molecular weight of 107.9 gmol carbon.

Divide through by 12.011gmol, which is the atomic mass of carbon. Hence, C9H is the empirical formula.

The simplest whole-number ratio of the different atoms in a compound is represented by an empirical formula.

The precise number of various atom types contained in a compound's molecule is indicated by the molecular formula.

The sorts of atoms and their quantities in a molecule or compound are described using chemical formulae.

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5ED4 - 07A4 when these values represent unsigned 16-bit hexadecimal numbers is equal to 7E30 in hexadecimal.

Given, 5ED4 - 07A4 when these values represent unsigned 16-bit hexadecimal numbersTo subtract two hexadecimal numbers, we will follow these

steps:If the number on the left is smaller than the number on the right, add 16 to the leftmost number and subtract as usual. Convert all hexadecimal digits to decimal and perform the subtraction on the decimal numbers obtained.

step 2.Convert the difference obtained in

step 3 into a hexadecimal number if the question asks for it.

So, let's subtract the given hexadecimal numbers: 5ED4 - 07A4. We have to ensure that the leftmost number is greater than or equal to the rightmost number. So, add 16 to 5E.5E + 16 = 7E. So,

the given hexadecimal subtraction problem becomes: 7E D4 - 07 A4.Now, convert the hexadecimal digits to decimal.7E D4 = (7 × 16³) + (14 × 16²) + (13 × 16¹) + (4 × 16⁰) = 32,116.07 A4 = (0 × 16³) + (7 × 16²) + (10 × 16¹) + (4 × 16⁰) = 1,940.Now, subtract the decimal numbers obtained in

step 2.32,116 - 1,940 = 30,176.Now, we have to convert the difference obtained in step 3 into a hexadecimal number, as the question asks for it.Converting 30,176 to hexadecimal:Divide 30,176 by 16. We get a quotient of 1,886 and a remainder of 0.Divide 1,886 by 16. We get a quotient of 117 and a remainder of 14. (We represent 14 by E, as we are dealing with hexadecimal numbers)Divide 117 by 16. We get a quotient of 7 and a remainder of 5. (We represent 5 by 5)Divide 7 by 16. We get a quotient of 0 and a remainder of 7. (We represent 7 by 7)The required answer is: 7E30. Therefore, 5ED4 - 07A4 when these values represent unsigned 16-bit hexadecimal numbers is equal to 7E30 in hexadecimal.

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Answer:

b. 760 g

Explanation:

The mass of the solution = 800 g

5% of NaCl by mass of the solution can be determined as follows;

    5% of 800  =  \(\frac{5}{100}\) × 800

                       = 5 × 8

                       = 40 g

The mass of NaCl in the solution is 40 g.

The mass of water = mass of solution - mass of NaCl

                               = 800 - 40

                              = 760 g

Therefore, the mass of water required is 760 g.

Since the ore is 31.1% nickel by mass, every 100 g of the ore contains 31.1 g of nickel. To have 70.0 g of nickel, we need  2.25 kg of the ore.

When we say that ore is 31.1% nickel by mass, we mean that 31.1 g of nickel is present in every 100 g of the ore. We can use this information to calculate the amount of ore needed to obtain a certain amount of nickel.

To find the amount of ore needed to get 70.0 g of nickel, we can divide the desired amount of nickel by the amount of nickel present in 100 g of the ore:

70.0 g / (31.1 g/100 g) = 70.0 g / 0.311 = 2.25 kg

So, we would need to dig up 2.25 kg of the ore to get 70.0 g of nickel.

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The condensed structural formula for the product of the reaction of 2-butene with water and a strong acid catalyst is shown below ,

First write the condensed structural formula of 2-butene and indicate that it reacts with water. Then write the condensed structural formula of 2-butanol after the reaction arrow to indicate that it is the product. Finally, write the formula for the catalyst above the arrow.

The acid first attack at double bonded carbon of 2-butene and produce stable carbocation then water molecule attack on carbocation followed by deprotonation .

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Answer:

Paleontologists have uncovered new fossils from Tiktaalik roseae, which, while still a fish, is considered a transitional fossil that also has traits common to the first four-footed animals. This more complete picture of Tiktaalik suggests that the creature had strong, mobile hind fins.

Explanation:

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3 g/mL is the density in grams per millititer to three significant figures.

To express the density of a cube of butter in grams per milliliter, we need to convert the weight from pounds to grams and the volume from cubic inches to milliliters.

1 pound is approximately equal to 453.592 grams, so the weight of the cube of butter in grams would be:
0.260 lb * 453.592 g/lb = 117.81992 g (rounded to three significant figures as 118 g)

1 cubic inch is equal to approximately 16.387 milliliters, so the volume of the cube of butter in milliliters would be:
\(1303 cubic inches * 16.387 mL/in^3 = 21,365.861 mL\) (rounded to three significant figures as 21,400 mL)

Therefore, the density of the cube of butter would be:
Density = Mass / Volume

= 118 g / 21,400 mL

= 0.00551 g/mL (rounded to three significant figures as 0.005 g/mL)

For the gem, we already have the mass as 600 g and the volume as 200 mL.

Therefore, the density of the gem would be:
Density = Mass / Volume

= 600 g / 200 mL

= 3 g/mL (rounded to three significant figures)

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Answer:

Below are some patterns in the charge for elements in each group.

Group 1 elements : 1 valence electron and form ions with charge +1

Group 2 elements : 2 valence electrons and form ions with charge + 2

Group 3 elements : 3 valence electrons and form ions with charge + 3(there are some exceptions as well)

Elements in groups 4 and 5 are unpredictable also the D block elements consist of multiple oxidation states..

Group 6 elements : 6 valence electrons, form ions with charge -2

Group 7 elements: 7 valence electrons, form ions with charge -1  

The octet rule is being followed, the elements form either ionic bond or covalent bond to fulfill it.

eg: when a K atom forms a K+ ion, the ion has the same electron configuration as the noble gas Ar (argon).

When an O atom gains 2 electrons to form the O²⁻ ion, the ion has the same electron configuration as the noble gas Ne (neon).  

Note: Boron (B) is in Group 3 but doesn't form ions.

A noticeable pattern in the charge for elements in each group of the periodic table is that: Elements in the same group have the same charge.

Discussion:

The pattern in the charge for elements in each group is characterized by the adoption of the same charge for elements in the same group irrespective of the period they are situated in.

An example is evident in the alkali metal, halogen and alkali Earth metals group.

The alkali metals lose their only Valence electron, to assume the octet configuration of the preceeding noble gas.

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Answer:

11 is the atomic number of alkali metal

Explanation:

The Group 1 elements are called the alkali metals. ... All the Group 1 elements are very reactive . They must be stored under oil to keep air and water away from them. Group 1 elements form alkaline solutions when they react with water, which is why they are called alkali metals.

To find the percent of decrease in the number of industrial accidents from last month to this month, we need to calculate the difference between the two numbers, divide it by the original number, and then multiply by 100. The difference between last month's number of accidents (1193) and this month's number (977) is: 1193 - 977 = 216

To get the percent decrease, we divide the difference by the original number (1193) and multiply by 100: 216/1193 x 100 = 18.1% Therefore, the percent decrease in the number of industrial accidents this month is 18.1%. This means that there were 18.1% fewer accidents this month than there were last month. It's a positive trend that indicates that safety measures may be working and that people are taking the necessary precautions to avoid accidents. It's important to continue to monitor and improve safety practices to ensure that the number of industrial accidents continues to decrease over time.

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In the given chemical reaction \(\rm NaOH + CO_2 \rightarrow Na_2CO_3 + H_2O\), the limiting reagent is carbon dioxide and \(\rm Na_2CO_3\) that can be produced is 1.00 mol, and 0.85 mol of NaOH remains unreacted after the completion of the reaction.

The limiting reagent is the reactant that gets completely consumed in a chemical reaction, thereby limiting the amount of product that can be formed.

The balanced chemical equation for the reaction between sodium hydroxide and carbon dioxide is:

\(\rm NaOH + CO_2 \rightarrow Na_2CO_3 + H_2O\)

To determine which reactant is limiting, we need to calculate the number of moles of sodium hydroxide and carbon dioxide present and compare the mole ratios of the reactants in the balanced equation.

Moles of NaOH = 1.85 mol

Moles of \(\rm CO_2\) = 1.00 mol

The balanced equation shows that the mole ratio of NaOH to \(\rm CO_2\) is 2:1, which means that 2 moles of NaOH react with 1 mole of \(\rm CO_2\) .

Using the mole ratio, we can calculate the maximum number of moles of Na2CO3 that can be produced by each reactant:

Moles of NaOH / 2 = 0.925 mol \(\rm Na_2CO_3\)

Moles of\(\rm CO_2 \times 1\) /1 = 1.00 mol \(\rm Na_2CO_3\)

Since the calculated number of moles of \(\rm Na_2CO_3\) from \(\rm CO_2\) is less than the calculated number of moles of \(\rm Na_2CO_3\) from NaOH, \(\rm CO_2\) is the limiting reactant.

According to the balanced equation, 1 mole of \(\rm CO_2\) reacts to form 1 mole of \(\rm Na_2CO_3\) . Therefore, the number of moles of \(\rm Na_2CO_3\) produced is 1.00 mol.

To determine the amount of excess reactant remaining after the reaction, we need to calculate the amount of NaOH that did not react.

Moles of NaOH remaining = Moles of NaOH - (Moles of \(\rm Na_2CO_3\) produced x 2)

= 0.85 mol NaOH

Therefore, 0.85 mol of NaOH remains unreacted after the completion of the reaction.

In conclusion, carbon dioxide is the limiting reactant, and 1.00 mol of \(\rm Na_2CO_3\) can be produced. 0.85 mol of NaOH remains unreacted after the completion of the reaction.

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The question is incomplete. The complete question is:

Sodium hydroxide reacts with carbon dioxide as follow:

\(\rm NaOH + CO_2 \rightarrow Na_2CO_3 + H_2O\)

Which reagent (reactant) is limiting when 1.85 mol of sodium hydroxide and 1.00 mol carbon dioxide are allowed to react? How many moles of sodium carbonate can be produced? How many moles of the excess reactant remain after the completion of the reaction?

Answer

a. C₂H₂O + 2O₂ → 2CO₂ + H₂O

b. 8 moles of O₂

c. 64 g of O₂

d. The grams of CO₂ produced is 262 g and the mass of H₂O produced is 53.6 g.

Explanation

a. The balanced chemical equation gasohol is a fuel containing liquid ethanol (C₂H₂O) that burns in oxygen gas to give carbon dioxide and water gases is:

b. The moles of O₂ needed to completely react with 4.0 moles of C₂H₂O?.

The mole ratio of O₂ to C₂H₂O in the balanced equation is 2:1.

Therefore, 4.0 moles of C₂H₂O will completely react with (2 x 4) = 8 moles of O₂.

c. The mass in grams of O₂ that is used up in the reaction if a car produces 88 g of CO₂.

The molar mass of CO₂ = 44.01 g/mol

The molar mass of O₂ = 31.999 g/mol

The mole ratio of O₂ to CO₂ is 2:2

This implies (2 mol x 31.999 g/mol) = 63.998 g of O₂ is used up to produce (2 mol x 44.01 g/mol) = 88.02 g of CO₂

Therefore x g of O₂ will be used up to produce 88 g of CO₂

That is;

Hence, the mass in grams of O₂ that is used up in the reaction if a car produces 88 g of CO₂ is 64 g.

d. The grams of CO₂ and H₂O that can be produced if 125 g of C₂H₂O were burnt.

1 mole of C₂H₂O = 42.04 g

1 mole of CO₂ = 44.01 g

1 mole of H₂O = 18.01 g

Mass of CO₂ produced:

From the balanced, the mole ratio of C₂H₂O to CO₂ is 1:2

The grams of CO₂ produced is 262 g.

Mass of H₂O produced:

From the balanced, the mole ratio of C₂H₂O to H₂O is 1:1

The mass of H₂O produced is 53.6 g

You would multiple the percentages times the atomic mass and then add each of them together.

Ex. (23.995)(.7899)+(24.986)(.10)+(25.992)(.1101). = 24.3139 amu

The required heat in BTU, for the water at 50°C to become ice at -50°C is 209 BTU/lb.

To determine the required heat in BTU, for the water at 50°C to become ice at -50°C, we need to calculate the heat of fusion and the heat of cooling of water. We can use the following formula to calculate the required heat.

Q = mL

Where:Q is the required heat in BTU.

m is the mass of water in pounds.L is the specific heat of water at the desired temperature.

Lf is the heat of fusion of water.

Lc is the specific heat of ice.

Using the above formula, we get;

Q = mLf + mL + mLc

The heat of fusion of water is 144 BTU/lb

The specific heat of water at 50°C is 1.00 BTU/lb °F.

The specific heat of ice is 0.5 BTU/lb°F.

We know that: 1°C = 1.8°F.

So,50°C = 122°F and -50°C = -58°F

Also, the mass of water is not given, so let us assume that the mass of water is 1 lb.

Thus;

Q = mLf + mL + mLc

Q = 1(144) + 1(1.00)(122-32) + 1(0.5)(-50-0)

Q = 144 + 90 + (-25)

Q = 209 BTU/lb

Therefore, the required heat in BTU, for the water at 50°C to become ice at -50°C is 209 BTU/lb.

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The  amount of air that is moved between the atmosphere and alveoli in 1 minute is alveolar ventilation, option B.

Alveolar ventilation is the process by which the alveoli and the surrounding environment exchange gases. It is a procedure that allows oxygen to enter the lungs from the atmosphere and carbon dioxide that was brought into the lungs by mixed venous blood to be expelled from the body. Alveolar ventilation is typically defined as the amount of fresh air that enters the alveoli each minute. However, this definition also includes the amount of alveolar air that leaves the body each minute.

With each inspiration, 350 mL of fresh air containing approximately 21% oxygen enters the 3 L of gas already present in the lungs, and with each exhalation, 350 mL of fresh air containing approximately 5% to 6% carbon dioxide exits the lungs. The alveolar air diffuses approximately 300 milliliters of oxygen into the pulmonary capillary blood per minute, and the pulmonary capillary blood diffuses approximately 250 milliliters of carbon dioxide into the alveoli per minute.

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Complete question:

The amount of air that is moved between the atmosphere and alveoli in 1 minute is Multiple Choice

pulmonary ventilation.

alveolar ventilation.

internal respiration.

airflow.

external respiration.

The number of moles of NaCl present in 276.50 mL of 1.55 M NaCl solution is 0.429 mol.

To find the number of moles of NaCl in a given solution, we can use the formula: moles of solute = concentration of solution x volume of solution We are given the following information:Concentration of solution = 1.55 MVolume of solution = 276.50 mL

To use this formula, we need to convert the volume of the solution from milliliters (mL) to liters (L).1 L = 1000 mLTherefore, 276.50 mL = 0.27650 LNow, we can substitute the given values in the formula and calculate the number of moles of NaCl present in the solution:moles of solute = concentration of solution x volume of solution= 1.55 M x 0.27650 L= 0.429 molTherefore, there are 0.429 moles of NaCl in 276.50 mL of 1.55 M NaCl solution. Hence, the correct option is 0.429.

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The main difference between a recipe for baking a cake and a chemical reaction is that baking a cake is a chemical change whereas a chemical reaction may be a chemical and physical change.

The similarities between a recipe for baking a cake and a chemical reaction is that the molecules react with each other and in both new substances are formed at the end.

When you bake a cake, the ingredients pass through a chemical change. A chemical change occurs when the molecules are rearranged to form a new substance. When you start baking, you have many ingredients. Baking a cake is a chemical change because the ingredients rearrange to form a new substance which is not reversed. The sugar, flour, and eggs can't be separated from each other. The properties of the materials have changed so it is considered as a chemical change.

So we can conclude that baking a cake and a chemical reaction is different due to the presence of chemical change whereas chemical reactions have both chemical and physical change. The similarity between a recipe for baking a cake and a chemical reaction is that in both new substances are formed at the end.

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Answer:

Sodium Phosphide + Fluorite --------- Sodium Fluoride + Calcium Phosphide

Answer:

117g

Explanation:

Given parameters:

Number of moles = 2moles

Unknown:

Mass of NaCl  = ?

Solution:

To solve the problem, we need to use the expression below;

    Mass of NaCl  = number of moles x molar mass

Molar mass of NaCl  = 23 + 35.5  = 58.5g/mol

So;

Insert the parameters and solve;

     Mass of NaCl  = 2 x 58.5  = 117g

Answer

7.53% 97% if you divide it you can get the answer

Explanation:

The amount of COCl₂ in grams in the equilibrium mixture is approximately 0.403 mg.

To determine the amount of COCl₂ in grams in the equilibrium mixture, we can use the given equilibrium concentrations and the volume of the flask.

Here's how to calculate it:

Calculate the moles of CO and Cl₂ in the flask:

Moles of CO = [CO] * Volume of flask

Moles of Cl₂ = [Cl₂] * Volume of flask

Moles of CO = (1.6×10⁻⁶ M) * (4.89 L) = 7.82×10⁻⁶ mol

Moles of Cl₂ = (8.3×10⁻⁷ M) * (4.89 L) = 4.06×10⁻⁶ mol

Use the stoichiometry of the balanced equation to determine the moles of COCl₂:

From the balanced equation: 1 mol CO + 1 mol Cl₂ -> 1 mol COCl₂

The moles of COCl₂ will be the same as the limiting reactant, which is the reactant with fewer moles.

In this case, since the moles of COCl₂ are not provided, we assume it to be zero initially.

Moles of COCl₂ = 0 + (moles of limiting reactant)

Moles of COCl₂ = 0 + 4.06×10⁻⁶ mol = 4.06×10⁻⁶ mol

Convert moles of COCl₂ to grams using its molar mass:

The molar mass of COCl₂ is the sum of the atomic masses of carbon, oxygen, and two chlorine atoms.

Molar mass of COCl₂ = (12.01 g/mol) + (2 * 16.00 g/mol) + (2 * 35.45 g/mol)                                  = 98.96 g/mol

Mass of COCl₂ = Moles of COCl₂ * Molar mass of COCl₂

Mass of COCl₂ = (4.06×10⁻⁶ mol) * (98.96 g/mol) = 0.403 mg (rounded to three significant figures)

Therefore, the amount of COCl₂ in grams in the equilibrium mixture is approximately 0.403 mg.

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Complete Question:

Consider the reaction: CO(g)+Cl₂(g)⇌COCl₂(g) Keq= 2.9×1010 at 25 ∘C A 4.89⁻ L flask containing an equilibrium reaction mixture has [CO]= 1.6×10⁻⁶ M and [Cl2]= 8.3×10⁻⁷ M .

How much COCl₂ in grams is in the equilibrium mixture?

The volume of the gas will not have any effect by changing the size of the strip.

The volume of the gas would not change if the magnesium strip was 10 cm. This is because the volume of a gas is not determined by the size of the solid material that it is reacting with, but rather by the pressure and temperature of the system. If the pressure and temperature of the system remain constant, then the volume of the gas will also remain constant, regardless of the size of the magnesium strip. Therefore, changing the size of the magnesium strip would not have any effect on the volume of the gas.

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Answer:

earth I think like that because earth is the second planet

Modern chemical fertilizers include one or more of the three elements that are most important in plant nutrition: nitrogen, phosphorus, and potassium. Of secondary importance are the elements sulfur, magnesium, and calcium.

Answer: The most common useful element in fertilizer is mostly nitrogen since it is also found in air

Answer:

Polar easterlies are dry, cold prevailing winds that blow from the east. They emanate from the polar highs, areas of high pressure around the North and South Poles. Polar easterlies flow to low-pressure areas in sub-polar regions. Westerlies. Westerlies are prevailing winds that blow from the west at midlatitudes.

Explanation:

I hope this helps

Answer:

As the concentration of Sodium Thiosulphate increases the length of time for cross to disappear decreases. This is because the increase of concentration of Sodium Thiosulphate will increase the rate of reaction between Hydrochloric acid and sodium Thiosulphate particles.

Explanation:

Logic...