Answer:
\($MnO^-_4$\) is a strong oxidizing agent.
Explanation:
The 5d orbitals of Re are higher in energy than 3 d orbitals of Mn. So an LMCT ligand to metal charge transfer excitation requires more energy of \($ReO^-_4$\).
Also, since the molecular orbitals are derived primarily from 3d orbitals of \($MnO^-_4$\) are lower in energy than the corresponding MO's of \($ReO^-_4$\), \($MnO^-_4$\) is better able to accept the electrons.
So it is a better oxidizing agent.
The ligand to metal charge transfer band in ReO4- occurs in the near UV region hence ReO4 - appears colorless.
The electron configuration of Re is Xe 4f14 5d5 6s2 and the electron configuration of Mn is [Ar] 3d5 4s2. We can see that Mn^7+ and Re^7+ have empty d orbitals.
The color of MnO4 - must result from ligand to metal charge transfer hence the purple color of MnO4 -. In the case of ReO4 -, the ligand to metal charge transfer occurs at a much higher energy owing to the fact that 5d orbitals are involved. This transition occurs in the near UV region hence ReO4 - appears colorless. The ligand to metal charge transfer in MnO4- involves lower energy 3d orbitals hence it occurs in the visible region of the spectrum.
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The boiling point at 1.00 atm of an aqueous solution of CaCl2 is 105.3 °C. What is the concentration of CaCl2
in the solution? Kb (H2O) = 0.512 °C/m. Assume an ideal van't Hoff factor for CaCl2.
d.2.93m.CaCl2 is present in the solution with a 2.93m concentration.
The boiling point of a solution is directly related to its concentration. The boiling point elevation of a solution, ΔTb, is equal to the product of the van't Hoff factor (i) and the molality of the solution (m).The quantity of moles of solute per kilogramme of solvent is known as molality.
Therefore, we can solve for the molality of the solution using the following equation:
ΔTb
\(= i *m\\105.3\°C= i * m\\\)
\(m =\frac{ 105.3 \°C }{i}\)
Assuming an ideal van't Hoff factor for CaCl2 (i = 2), the molality of the solution is:
\(m =\frac{ 105.3 \°C }{ 2}\\m = 52.65 m = 52.65 mol/kg\)
The concentration of CaCl2 in the solution is then:
\(C = m * Kb\\C = 52.65 mol/kg * 0.512 \°C/m\\C = 2.93 mol/kg\)
Therefore,The concentration of CaCl2 in the solution is 2.93m.
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complete question:The boiling point at 1.00 atm of an aqueous solution of CaCl2 is 105.3 °C. What is the concentration of CaCl2 in the solution? Kb (H2O) = 0.512 °C/m. Assume an ideal van't Hoff factor for CaCl2.
a.3.45m
b.4.40m
c.8.79m
d.2.93m
The picture shows two cars moving at the same speed. Which car has more kinetic energy?
Answer:
car 2/red
Explanation:
give me crown
120cm3 of a gas at 25°c exerts a pressure of 750mmHg. calculate its pressure if its volume increased to 150cm3 at 40°c.
Answer:
P2 = 1125 mmHg
Explanation:
Gas Pressure Calculation
To solve this problem, we need to use the combined gas law, which relates the pressure, volume, and temperature of a gas under different conditions. The combined gas law is given by:
(P1V1)/T1 = (P2V2)/T2
where P1, V1, and T1 are the initial pressure, volume, and temperature of the gas, and P2, V2, and T2 are the final pressure, volume, and temperature.
Let's start by calculating the initial conditions:
P1 = 750 mmHg
V1 = 120 cm^3
T1 = 25°C + 273.15 = 298.15 K (temperature in Kelvin)
Now we can plug in these values and solve for P2:
(P1V1)/T1 = (P2V2)/T2
(750 mmHg x 120 cm^3) / 298.15 K = (P2 x 150 cm^3) / (40°C + 273.15)
Simplifying this equation, we get:
P2 = (750 mmHg x 120 cm^3 x (40°C + 273.15)) / (298.15 K x 150 cm^3)
P2 = 1125 mmHg
Therefore, the pressure of the gas would increase to 1125 mmHg if its volume increased to 150 cm^3 at 40°C.
ChatGPT
why are phase changes horizontal on a heating curve
Answer:
A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it. The plateaus on the curve mark the phase changes.The second change of phase is boiling, as the temperature stays the same during the transition to gas.
Explanation:
Will y’all find this answer real quick for me !!
The mass (in grams) of sodium carbonate, Na₂CO₃ required to produce 85 grams of barium carbonate, BaCO₃ is 45.7 grams
How do i determine the mass of sodium carbonate, Na₂CO₃ required?First, we shall observe the balanced equation to obtain useful information. This is shown below:
Na₂CO₃ + BaSO₄ -> BaCO₃ + Na₂SO₄
Molar mass of BaCO₃ = 197 g/molMass of BaCO₃ from the balanced equation = 1 × 197 = 197 g Molar mass of Na₂CO₃ = 106 g/molMass of Na₂CO₃ from the balanced equation = 1 × 106 = 106 gFrom the balanced equation above,
197 g of BaCO₃ were obtained from 106 g of Na₂CO₃
With the above information, we can obtain the mass of sodium carbonate, Na₂CO₃ required to produce 85 grams of barium carbonate, BaCO₃. This is illustrated below:
From the balanced equation above,
197 g of BaCO₃ were obtained from 106 g of Na₂CO₃
Therefore,
85 g of BaCO₃ will be obtain from = (85 × 106) / 197 = 45.7 g of Na₂CO₃
Thus, we can conclude from the above calculation that the mass of sodium carbonate, Na₂CO₃ required is 45.7 grams
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Balance using the redox method:
(a)MnSO4 (b)PbO2 + (c)H,SO4
+
(d)HMnO4 + (e)PbSO4 + (f)H2O
If you are given 22.990 g of sodium and 12.011 g of carbon, which sample do you expect to have more particles?
Answer:
they are expected to have the same particles because their masses are the same with there molar mass
assume in a different experiment, you prepare a mixture containing 10.0 M FeSCN2+, 1.0 M H+, 0.1 MFe3+ and 0.1 M HSCN. Is the initial mixture at equilibrium? If not, in what direction must the reactionproceed to reach equilibrium? (Hint: You will need to use the value of Kc you determined in the lab
Answer:
The mixture is not in equilibrium, the reaction will shift to the left.
Explanation:
Based on the equilibrium:
Fe³⁺+ HSCN ⇄ FeSCN²⁺ + H⁺
kc = 30 = [FeSCN²⁺] [H⁺] / [Fe³⁺] [HSCN]
Where [] are concentrations at equilibrium. The reaction is in equilibrium when the ratio of concentrations = kc
Q is the same expression than kc but with [] that are not in equilibrium
Replacing:
Q = [10.0M] [1.0M] / [0.1M] [0.1M]
Q = 1000
As Q > kc, the reaction will shift to the left in order to produce Fe³⁺ and HSCN untill Q = Kc
Put the following in order from SMALLEST to LARGEST: cell, nucleus, gene,
chromosome, DNA, organism,
Answer:
Here is the correct order (ascending order):
gene, DNA, chromosome, nucleus, cell, organism.
A gene is a segment of DNA that contains the instructions for building a protein or RNA molecule. DNA is the molecule that carries genetic information and makes up genes. A chromosome is a structure made of DNA and protein that carries genes. A nucleus is a membrane-bound organelle that contains chromosomes. A cell is the smallest structural and functional unit of living organisms, consisting of a nucleus (or nucleoid in prokaryotes) and cytoplasm. An organism is an individual living entity, such as a plant, animal, or bacterium, that consists of multiple cells.
(1132 CHCH2CH = CH2
12. Give the complete IUPAC name for each of the following compounds:
(a) (CH3)2CHF
(b) CH3CHCICHCICH3
(C)
CH3CHCH;
CH2CH3
(d) CH3 CH2 CH = CHCHZ
(e)
CH3CH2CH2CHBCH2CH3
CH2CH=CH2
Answer:
Ok:
Explanation:
a) 2-fluoropropane
b) 2,3 dichlorobutane
c) pent-2-ene or 2 pentene (I assume the semicolon was a typo)
d) Same as c (I assume Z is a typo too)
e) non-1-ene or 1-nonene (I assume the B is a 2)
Which of the following statements is true?
Electrons have a positive charge.
Protons and neutrons are found in the nucleus.
Electrons and protons are found in the nucleus.
All shells can hold up to eight electrons.
Answer:
2/ Protons and neutrons are found in the nucleus.
Explanation:
What would make oppositely charged objects attract each other more?increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged objectdecreasing the positive charge of the positively charged object and decreasing the negative charge of the negatively charged objectincreasing the distance between the positively charged object and the negatively charged objectmaintaining the distance between the positively charged object and the negatively charged object
Answer:
increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object would make the oppositely charged objects attract each other more.
How does an atom become a positively charged ion?
Can H2 be broken down? (Not H)
Hello, this is Bing. I can help you with your question. Based on the information I found on the web, **H2** can be broken down into its two atoms of hydrogen (H) by supplying enough energy to overcome the bond that holds them together⁴. This process is called **dissociation** and requires an energy equal to or greater than the **dissociation energy** of H2, which is about 436 kJ/mol⁴.
One way to break down H2 is by using **electricity** to split water (H2O) into hydrogen (H2) and oxygen (O2) through a process called **electrolysis**¹. In this process, water is decomposed into its elements by passing an electric current through it. The electric current is provided by a battery or another source of electricity and the water needs to have an **electrolyte**, such as salt or acid, added to it to make it conductive¹. Two electrodes, usually made of metal or other conductive material, are inserted into the water and connected to the battery. The electrode connected to the positive terminal of the battery is called the **anode** and the one connected to the negative terminal is called the **cathode**¹. When the electric current flows through the water, hydrogen gas bubbles form at the cathode and oxygen gas bubbles form at the anode¹. The overall chemical reaction for electrolysis of water is:
2 H2O → 2 H2 + O2
Another way to break down H2 is by using **heat** to cause a reaction between hydrogen and oxygen that produces water and releases a large amount of energy. This reaction is called **combustion** or **oxidation** and can be ignited by a spark or a flame³. The reaction is very fast and explosive and can be dangerous if not controlled. The overall chemical reaction for combustion of hydrogen is:
2 H2 + O2 → 2 H2O
I hope this helps you understand how H2 can be broken down and what methods are used to do so.
The density of ethanol is 0.789 g/cm^3. A flask holds 165.0 g of ethanol. What is the volume of the ethanol?
a. 4.78 x 10^-3 g
b. 130. g
c. 209 g
The volume of the ethanol that has a density of ethanol is 0.789 g/cm³ is 209.13cm³.
How to calculate volume?The volume of a substance can be calculated by dividing the mass of the substance by its density as follows:
Volume = mass ÷ density
According to this question, the density of ethanol is 0.789 g/cm³. A flask holds 165.0 g of ethanol and the volume can be calculated as follows:
Volume = 165.0g ÷ 0.789g/cm³
Volume = 209.13cm³
Therefore, the volume of the ethanol that has a density of ethanol is 0.789 g/cm³ is 209.13cm³.
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Aluminum undergoes a single-displacement reaction with copper (II) sulfate to form aluminum sulfate and _______________.
Be sure to answer all parts.
A slice of cheese has a mass of 67 g and a volume of 35 cm'. What is the density of the cheese in units of
g/cm² and g/mL?
Answer:
d = 1.91 g/cm³
d = 1.91 g/mL
Explanation:
Given data:
Mass of cheese = 67 g
Volume of cheese = 35 cm³
Density of cheese = ?
Solution:
Formula:
d = m/v
by putting values,
d = 67 g/ 35 cm³
d = 1.91 g/cm³
1cm³ = 1mL
d = 1.91 g/mL
Which of the following is a pure substance that cannot be broken down into simpler substances by chemical means?
a- homogenous mixture
b-chemical compound
c-chemical element
d-heterogeneous mixture
e-solution
Answer: c
Explanation:
Chemical element, please if you now the answers of my two last questions help me
Chemical elements are pure substances that cannot be broken down into simpler substances by chemical means
WHAT IS A PURE SUBSTANCE:
In chemistry, a pure substance is referred to as a substance that contains constant or uniform composition. Chemical elements as pure substances are substances that contain a only one type of atom. All chemical elements are pure substances because they contain only one type of atom in constant proportions. Hence, they cannot be broken down into simpler substances by chemical means.Therefore, chemical elements are pure substances that cannot be broken down into simpler substances by chemical means.
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a gas has an initial volume of 3,480 mL and an initial temperature of - 70.0 C. what must be the temperature of the gas in kelvin if its volume is reduced to 2,450 mL
The temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.
To determine the temperature of the gas in Kelvin after its volume is reduced, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature for a given amount of gas.
The combined gas law equation is:
(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂
Where P₁ and P₂ are the initial and final pressures, V₁ and V₂ are the initial and final volumes, T₁ is the initial temperature in Kelvin, and T₂ is the final temperature in Kelvin.
Given that the initial volume V₁ is 3,480 mL, the initial temperature T₁ is -70.0 °C (which needs to be converted to Kelvin), and the final volume V₂ is 2,450 mL, we can substitute these values into the equation.
To convert -70.0 °C to Kelvin, we add 273.15 to it, resulting in T₁ = 203.15 K.
Now we can solve for T₂:
(T₂ * V₁) / T₁ = V₂
T₂ = (V₂ * T₁) / V₁ = (2,450 mL * 203.15 K) / 3,480 mL
Simplifying the equation, we find:
T₂ ≈ 143.27 K
Therefore, the temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.
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What mass of NaCl is needed to produce a 26.4 mol/L with a 1.7 L volume?
we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.
To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.
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Solve this whole experiment,
I'll be so glad . thanks
●do the above experiment
●give detailed answers
THANKS
HELP ME PLLSS (with both)
2. What is the ratio of moles of CuSO4 to moles of NaOH?
Answer: 1. 1 : 2 2. NaOH is the limiting reactant
Explanation: Hope this helps you
Answer:
2. Ratio 1CuSO4 : 2NaOH
Explanation:
CuSO4 + 2NaOH ⟶ Cu(OH)2 + Na2SO4
so 1 mole of CuSO4 will react with 2 moles of NaOH
therefore the ratio is 1:2
Hope this helps
At constant current is passed through an electrolytic cell containing molten MgCl2 for 18 hr. if 4.8 x 105 g of Cl2
are obtained. Calculate the current in Amperes.
The current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.
To calculate the current in amperes, we need to use Faraday's laws of electrolysis and the stoichiometry of the reaction.
Faraday's laws state that the amount of substance produced or consumed during electrolysis is directly proportional to the quantity of electricity passed through the cell. The relationship is given by:
Q = nF
Where Q is the electric charge in coulombs (C), n is the number of moles of substance involved in the reaction, and F is Faraday's constant, which is equal to 96,485 C/mol.
In this case, the substance being produced is Cl2, and we know the mass of Cl2 produced, which is 4.8 x 10^5 g.
First, we need to calculate the number of moles of Cl2 produced:
Molar mass of Cl2 = 35.45 g/mol
Moles of Cl2 = mass / molar mass = (4.8 x 10^5 g) / (35.45 g/mol) ≈ 1.354 x 10^4 mol
Now we can calculate the quantity of electricity passed through the cell using Faraday's laws:
Q = nF
Q = (\(1.354 x 10^4\)mol) * (96,485 C/mol)
Q ≈ 1.308 x 10^9 C
The quantity of electricity is given in coulombs. To find the current, we need to divide this value by the time in seconds.
Given that the time is 18 hours, we convert it to seconds:
Time = 18 hours * 60 minutes/hour * 60 seconds/minute
Time = 6.48 x 10^4 seconds
Finally, we can calculate the current:
Current (I) = Q / Time
I = (1.308 x 10^9 C) / (6.48 x 10^4 s)
I ≈ 2.02 x 10^4 Amperes
Therefore, the current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.
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Suppose that at room temperature, a certain aluminum bar is 1.0000 mm long. The bar gets longer when its temperature is raised. The length lll of the bar obeys the following relation: l=1.0000+2.4×10−5Tl=1.0000+2.4×10−5T, where TTT is the number of degrees Celsius above room temperature. What is the change of the bar's length if the temperature is raised to 12.2 ∘C∘C above room temperature?
The change of the bar's length is ΔL =0. 000312 m if the temperature is raised to 12.2 ∘C∘C above room temperature.
Given that
At room temperature ( T = 25 ∘C) ,L= 1 m
L=1+2.4 X 10-5T
So the length at 13.0 ∘C above room temperature:
L=1+2.4 X 10-5T
L=1+2.4 X 10-5x13
L=1.000312 m
So the change in length
ΔL = 1.000312 - 1.0000 m
ΔL =0. 000312 m
Since the length of the aluminum bar, L is given by , L = 1.0000 + 2.4 × 10⁻⁵T and T = 14.1°C, we substitute the value of T into L. So, we have L = 1.0000 + 2.4 × 10⁻⁵ × 14.1°C = 1.0000 + 0.0003384 = 1.0003384 m. The change in length is thus 1.0003384 - 1.0000 = 0.0003384 m ≅ 0.00034 m.
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Imagine that you mix 25 g of water at 25 ºC with 25 g of water at 65 ºC. Predict the final temperature of the sample.
The final temperature of the mixture given that 25 g of water at 25 °C is mixed with 25 g of water at 65 °C, is 45 °C
How do i determine the final temperature of the mixture?The final temperature of the mixture can be obtained by calculating the equilibrium temperature of the mixture. This is shown below:
Mass of cold water (M) = 25 gTemperature of cold water (T) = 25 °CMass of warm water (Mᵥᵥ) = 25 gTemperature of warm water (Tᵥᵥ) = 65 °CEquilibrium temperature (Tₑ) =?Heat loss by warm water = Heat gain by cold water
MᵥᵥC(Tᵥᵥ - Tₑ) = MC(Tₑ - T)
Cancel out C
Mᵥᵥ(Tᵥᵥ - Tₑ) = M(Tₑ - T)
25× (65 - Tₑ) = 25 × (Tₑ - 25)
Cancel out 25
65 - Tₑ = Tₑ - 25
Collect like terms
65 + 25 = Tₑ + Tₑ
90 = 2Tₑ
Divide both side by 2
Tₑ = 90 / 2
Tₑ = 45 °C
Thus, we can conclude that the final temperature the mixture is 45 °C
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Weight is best defined as _____. A the amount of space an object takes up B the speed of an object C the force of gravity on an object D the amount of energy in an object
Weight is best defined as the force of gravity on an object (option C).
What is weight?Weight is the force on an object due to the gravitational attraction between it and the Earth (or whatever astronomical object it is primarily influenced by).
Weight is different from mass being that weight is a dependent on the gravitational force of the object's habitation, however, mass is not.
For example, the mass of an object on Earth can be 10kg, however, the weight of the object is 100N because the gravitational force of the Earth is 10m/s².
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Calculate the N/Z ratio for elements with atomic numbers 104 through 109. Are they in the belt of stability? Are they stable? How do you know?
The ratio of neutrons to protons, or the N/Z ratio, plays a crucial role in determining a nucleus' stability. The range of N/Z ratios in which nuclei are stable is generally referred to as the belt of stability.
How can you tell whether a substance is stable or unstable?If the forces between the constituents of the nucleus are equal, an atom is stable. If these forces are out of balance or if the nucleus has an excessive amount of internal energy, an atom is unstable (radioactive).
Z = 104 for Rutherfordium, element 104. The isotopes 261Rf and 262Rf, having masses of 261 and 262, respectively, have the longest half-lives. Accordingly, N/Z ratios are:
261Rf: N/Z = (261-104)/157 = 1.08
262Rf: N/Z = (262-104)/158 = 1.09
These N/Z ratios are a little bit higher than the average belt of stability values, which are about 1.0 for heavy nuclei. These isotopes are thought to be reasonably stable because they are close enough.
Z = 109 for Meitnerium, element 109. The isotopes 278Mt and 282Mt, with masses of 278 and 282, respectively, have the longest half-lives. Accordingly, N/Z ratios are:
278Mt: N/Z
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When sunshine warms your face,_______occurs.
A.conduction
B.radiation
C.convection
Answer:
B.
Explanation:
Sunshine is Radiant energy.
Answer:
The ans. is B.radiation
A sample of carbon monoxide initially at 79.0 °C was heated to 158 °C. If the volume of the carbon monoxide sample is 990.4 mL at 158 °C , what was its volume at 79.0 °C?
Answer:
V₁ = 808.9mL
Explanation:
Based on Charles's law, the volume of a sample of gas is directely proportional to its absolute temperature. The formula is:
\(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)
Where V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas.
The initial state is:
V₁ = Our incognite
T₁ = 79°C + 273.15 = 352.15K
Final state is:
V₂ = 990.4mL
T₂ = 158°C + 273.15 = 431.15K
Replacing:
\(\frac{V_1}{352.15K} =\frac{990.4mL}{431.15K}\)
V₁ = 808.9mLConsidering the Charles's Law, the volume at 79 °C is 808.86 mL.
Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is maintained at a constant pressure.
This law says that for a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement they have the gas molecules.
In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:
\(\frac{V}{T}=k\)
Studying two different states, an initial state 1 and a final state 2, it is satisfied:
\(\frac{V1}{T1}=\frac{V2}{T2}\)
In this case, you know:
V1= ?T1=79 C= 352 K (being 0 C= 273 K)V2= 990.4 mLT2= 158 C= 431 KReplacing in Charles's law:
\(\frac{V1}{352 K}=\frac{990.4 mL}{431 K}\)
Solving:
\(V1=\frac{990.4 mL}{431 K}x352 K\)
V1=808.86 mL
Finally, the volume at 79 °C is 808.86 mL.
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