Answer:
0.875 miles/minute
Explanation:
The formula for velocity if final position - initial position divided by final time - initial time. Here, the final position
of the van was 49 km away from house, and its initial was 0, because you didn't travel anywhere initially. The final time was 56 minutes because that was how long it took to get home, and the initial was 0, because you were 0 minutes into travel at the beginning.
how big is the moon +5 points
Answer:
1,079.6 mi is answers correct
Answer:
it is big
Explanation:
The moon is a bit more than 27 percent the size of Earth
Two hoops or rings (I = MR2) are centered, lying on a turntable. The smaller ring has radius = 0.050 m; the larger has radius = 0.10 m. Both have a mass of 3.0 kg. What is the total moment of inertia as the turntable spins? Ignore the mass of the turntable.
A total moment of inertia of 0.0375 kg·m² as the turntable spins.
What is the total moment of inertia as the turntable spins?The total moment of inertia of the two hoops or rings on the turntable can be calculated using the formula I = MR². The moment of inertia of each hoop can be calculated separately and then added together to find the total moment of inertia.
For the smaller hoop, the moment of inertia would be I = (3.0 kg)(0.050 m)² = 0.0075 kg·m².
For the larger hoop, the moment of inertia would be I = (3.0 kg)(0.10 m)² = 0.030 kg·m².
Adding these two values together gives a total moment of inertia of 0.0375 kg·m² as the turntable spins.
It's important to note that the mass of the turntable is ignored in this calculation, as instructed in the question. Also, the term "moment" in this context refers to moment of inertia, which is a measure of an object's resistance to rotational motion.
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The volume per second of a fluid flowing through a horizontal pipe of length l is given by kpa/n where k is constant, p is the excess pressure (force per unit area) a is the radius of the pipe and U is the frictional quantity of dimension MLT-1 by dimensions find the number x
According to the given statement the number x is 2. The number x represents the dimensions of the term p * a in the given equation.
By comparing the dimensions of both sides of the equation, we find that x is equal to 2.
The equation given is:
Volume per second = k * (p * a) / n
Where:
- k is a constant
- p is the excess pressure (force per unit area)
- a is the radius of the pipe
- n is the frictional quantity of dimension MLT⁻¹
To find the number x, we need to determine the dimensions of each term in the equation.
1. Dimension of Volume per second:
- Volume has the dimension L³ (length cubed)
- Time has the dimension T (time)
- Therefore, Volume per second has the dimension L³ / T
2. Dimension of k:
- The equation states that k is a constant. Constants are dimensionless.
3. Dimension of p * a:
- Pressure has the dimension M / (L * T² ) (mass divided by length and time squared)
- Radius has the dimension L (length)
- Multiplying pressure by radius results in the dimension M / (L * T² ) * L = M / (L² * T² )
4. Dimension of n:
- Given in the question, n has the dimension MLT⁻¹
(mass times length times time to the power of -1)
Now, we can equate the dimensions:
L³ / T = k * (M / (L² * T² )) * MLT⁻¹
Simplifying the dimensions:
L³ / T = k * M / (L² * T² ) * MLT⁻¹
L³ / T = k * M / L² * M / T² * L^-1 * T⁻¹
L³ / T = k * M² / L² * T⁻¹
To equate the dimensions, both sides of the equation must have the same dimensions. Therefore:
L³ / T = k * M² / L² * T⁻¹
Comparing the dimensions on both sides, we can conclude:
L³ / T = k * M² / L²* T⁻¹
The dimensions on the left side are L^3 / T, and the dimensions on the right side are (k * M²) / (L² * T).
Therefore, the number x is 2.
The number x represents the dimensions of the term p * a in the given equation.
By comparing the dimensions of both sides of the equation, we find that x is equal to 2.
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The brakes on a car do 110,095J of work as they apply an average force of 8,450N. How far in meters does the car continue before stopping
13.02 meters
Explanation
the work done by the brakes makes the car stops, so the change in energy equals the work done
hence
\(\text{work}=\Delta Ek=\frac{1}{2}mv^2\)also, the work done by a force is given by
\(\text{work}=\text{ force}\cdot dis\tan ce\)then, let
\(\begin{gathered} \text{work}=\text{ 110095 J} \\ \text{Force}=8450\text{ N} \end{gathered}\)replace
\(\begin{gathered} \text{work}=\text{ force}\cdot dis\tan ce \\ 110095\text{ J=8450 N}\cdot distnace \\ \text{divide both sides by 8450 N} \\ \frac{110095\text{ J}}{\text{8450 N}}\text{=}\frac{\text{8450 N}\cdot}{\text{8450 N}}distance \\ 13.02m=\text{distance} \end{gathered}\)therefore, the answer is
13.02 meters
I hope this helps you
a baseball has a mass of 0.15 kg and radius 3.7 cm. in a baseball game, a pitcher throws the ball with a substantial spin so that it moves with an angular speed of 39 rad/s and a linear speed of 35 m/s. assuming the baseball to be a uniform solid sphere, determine the rotational and translational kinetic energies of the ball in joules.
The translational kinetic energy of the ball is 76.1 J, The rotational kinetic energy of the ball is 13.9 J.
A baseball has a radius of 3.7 cm and a mass (m) of 0.15 kg (0.037 m). A pitcher tosses the ball at a 39 rad/s angular speed and a 35 m/s linear speed. Suppose the baseball is a solid, uniform sphere.
Rotational kinetic energy of the ball (KRot): The rotational kinetic energy of a solid sphere is given by
KRot = (2/5)mr²ω²
Where ω is the angular speed and r is the radius of the ball. Substituting the given values, we get
KRot = (2/5) × 0.15 × 0.0372 × 392= 13.9 J
Therefore, the rotational kinetic energy of the ball is 13.9 J.
Translational kinetic energy of the ball (KTr): The translational kinetic energy of a body is given by
KTr = (1/2)mv²
Where v is the linear speed and m is the mass of the body. Substituting the given values, we get
KTr = (1/2) × 0.15 × 352= 76.1
The translational kinetic energy of the ball is 76.1 J.
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Jeffrey pulls a spring with a spring constant k = 50.0 N/m, stretching it from its rest length of 0.10 m to 0.90 m.
What is the elastic potential energy stored in the spring?
The elastic potential energy stored in the spring having a spring constant of 50.0 N/m is 16 J
How do I determine the potential energy stored in the spring?We'll begin by obtaining the extension of the spring. This is given below:
Initial length = 0.10 mNew length = 0.90 mExtension =?Extension = New length - initial length
Extension = 0.90 - 0.10
Extension = 0.80 m
Finally, we shall determine the potential energy stored by the spring. Details below
Spring constant (K) = 50.0 N/mExteension (e) = 0.80 mPotential energy stored =?PE = ½Ke²
PE = ½ × 50 × 0.8²
PE = 25 × 0.64
PE = 16 J
Thus, from the above calculations, we can conclude that the potential energy stored is 16 J
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describe relative motion with an examples
Answer:
The measurement of an object's motion with respect to any other object that is moving or stationary is called Relative Motion.
HELPPPPPPP MEEEEEEE ASAP PLZZZZZZZZZ
Based on what you have learned about self-esteem, reflect on your own sense of self-esteem. In the space below, explore and discuss the things that impact your self-esteem and ways you use to maintain high or positive self-esteem.
Self-esteem is based on the opinions and beliefs of the individuals. This helps us to value or perceive ourselves. It defines your self-worth and how you treat yourself.
Self-esteem refers to the positive (high self-esteem) and negative (low self-esteem) feelings that we have ourselves. High self-esteem or positive self-esteem is defined as self-love,self-value, self-respect, and dignity.
Positive self-esteem means believing in your own capability to do things on your own. When there is a lack of self-confidence, self-love leads to negative self-esteem.
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6. a 21.00-kg child initially at rest slides down a playground slide from a height of 3.40 m above the bottom of the slide. if her speed at the bottom is 2.30 m/s, how much energy is lost due to friction?
If a 21.00-kg child slide from a height of 3.40 m above the bottom of the slide and her speed at the bottom is 2.30 m/s, the amount of energy lost due to friction is 644.18 J.
The potentiаl energy of аn object depends on the locаtion of the object from the bottom reference floor аnd the mаss of the object. The аmount of energy contаins by the object аt аny height is known аs the potentiаl energy of thаt object.
We are given:
The energy of the child at the upper end of the slide is,
\(E_{u}\) = mgh
Substitute the values in the above equation
\(E_{u}\) = 21 kg × 9.8 m/s2 × 3.40 m
= 699.72 J
The energy at the bottom of the slide is,
\(E_{b}\) = \(\frac{1}{2}(mv^{2})\)
Substitute the values in the above equation.
\(E_{b}\) = \(\frac{1}{2}(21.2.30^{2})\)
\(E_{b}\) = 55.54 J
The energy lost due to friction is,
\(E_{f}\) = \(E_{u}\) - \(E_{b}\)
Substitute the values in the above equation
\(E_{f}\) = 699.72 - 55.54
\(E_{f}\) = 644.18 J
Thus, the energy lost due to friction is 644.18 J.
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An FM radio station broadcasts on a frequency of 91MHz ( 9.1 x 10^7 Hz). What is the wavelength of the wave that carries the coded information
The wavelength of the wave that carries the coded information for the FM radio station is approximately 3.30 m.
The wavelength of an electromagnetic wave can be determined using the equation:
wavelength = speed of light / frequencywhere the speed of light is approximately 3.00 x 10⁸ m/s.
Substituting the given frequency of 91 MHz (or 9.1 x 10⁷ Hz) into the equation yields:
wavelength = 3.00 x 10⁸ m/s / 9.1 x 10⁷ Hzwavelength ≈ 3.30 mTherefore, the wavelength of the wave that carries the coded information for the FM radio station is approximately 3.30 m.
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a racing car traveling with constant acceleration increases its speed from 10 m/s to 30 m/s over a distance of 60 m? how long does this take?
The racing car takes 1 second to accomplish this acceleration.
The time it takes for the racing car to increase its speed from 10 m/s to 30 m/s can be calculated using the equation of motion for uniformly accelerated linear motion.
First, we need to find the acceleration of the car.
We can use the formula:
a = (v_f - v_i) / t,
where a is the acceleration, v_f is the final velocity (30 m/s), v_i is the initial velocity (10 m/s), and t is the time taken.
Rearranging the equation, we have:
t = (v_f - v_i) / a.
Next, we need to find the acceleration of the car.
To do this, we can use the formula:
a = (v_f^2 - v_i^2) / (2 * d),
where d is the distance traveled (60 m), v_f is the final velocity (30 m/s), and v_i is the initial velocity (10 m/s).
Plugging in the values, we have:
a = (30^2 - 10^2) / (2 * 60) = 20 m/s^2.
Now we can substitute the value of acceleration into the equation for time:
t = (30 - 10) / 20 = 1 s.
Therefore, it takes 1 second for the racing car to increase its speed from 10 m/s to 30 m/s over a distance of 60 m.
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why you demagnetize a permanent magnet by heating it ?
A car travels with 214j of force at a speed of 32mph. that means it has a mass of kg.
The information given in the question is not sufficient to determine the mass of the car. Force (F) is given in joules (J), which is a unit of energy, and cannot be directly used to determine the mass of the car.
Additionally, speed (v) is given in miles per hour (mph), which is not a standard unit in the SI system of units.
To calculate the mass of the car, we need either the acceleration or the time for which the force is applied. Once we have either of these values, we can use the equation:
F = ma
where F is the force, m is the mass, and a is the acceleration.
We also need to convert the speed from mph to m/s, which is the standard unit of velocity in the SI system. To do this, we can use the conversion factor:
1 mph = 0.44704 m/s
So, 32 mph = 32 × 0.44704 = 14.33168 m/s
Without additional information about the acceleration or time, we cannot calculate the mass of the car. Mass is a fundamental physical quantity that measures the amount of matter in an object. It is typically measured in kilograms (kg) or grams (g). Mass is distinct from weight, which is the force exerted on an object due to gravity.
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During an isothermal process, 10 j of heat is removed from an ideal gas. What is the work done by the gas in the process?
The work done in the isothermal process is 10 joule.
We need to know about the isotherm process to solve this problem. The isotherm process can be described as a process where the initial temperature system will be the same as the final temperature. Hence, the internal energy change will be zero.
ΔU = 0
Hence,
ΔU = Q - W
0 = Q - W
Q = W
It means that the heat transferred is the same as the work done.
From the question above, we know that the heat transferred is 10 joule. Thus, the work done in the isothermal process is 10 joule.
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The frequency of a sound wave is 457 Hz. What is the period?
a
0.0032 s
b 0.078 s
C 0.0010 s
d 0.0022 s
The period of the sound wave having frequency of 457Hz is 0.0022 s.
What is frequency?
The frequency refers to the number of waves that pass a fixed point in unit time.
What is the relation between frequency and time period?
Time period is equal to the reciprocal of frequency.
i.e. T = 1 / f
So, The period of the sound wave having frequency of 457Hz will be
T = 1/457
∴ T = 0.002188 s
Now , rounding to the nearest value we get , 0.0022 s
Thus , The period of the sound wave having frequency of 457Hz is 0.0022 s.
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the acceleration due to gravity on mars is 3.8 m/s2. how much would an object with a mass of 16 kg weight on mars? a 16 n b 61 n c 96 n d 4.2 n
The weight of the object is equal to 60.8 N when its mass is 16 kg on mars.
What is the weight of the object?The weight of a body can be described as the force exerted on the object due to gravity. Weight can be specified as a vector quantity if the gravitational force is acted on the object.
The measurement unit for weight is similar to that of force newton (N). A body with a mass of 1 Kg on the surface of the Earth has a weight of 9.8 N, and about one-sixth on the Moon.
The mathematical formula to evaluate the weight of an object is mentioned below:
W = mg
Given, the mass of an object, m = 16 Kg
The acceleration due to gravity on the object on mars, g = 3.8 m/s²
The weight of an object on mars will be equal to:
W = 16 Kg × 3.8 m/s²
W = 60.8 N
Therefore, the weight of the object is 60.8 N.
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Questions about light polarization, I just need some help on these two problems
The light is at its lowest possible intensity.
The final intensity of the emerging light is (lo/2) × 0.75 = 0.375 × lo.
How to determine intensity?3. When the first polarizer is rotated clockwise to 90°, it becomes perpendicular to the incident unpolarized light. Therefore, no light can pass through the first polarizer. The intensity of the light is reduced to zero.
4. When the first polarizer is rotated clockwise to 45°, the intensity of the light passing through is reduced by cos²(45°) = 0.5.
This means the intensity becomes half of its original value (lo/2).
When the second polarizer is rotated anticlockwise to 30°, the intensity of the light passing through is further reduced by cos²(30°) = 0.75.
Therefore, the final intensity of the emerging light is (lo/2) × 0.75 = 0.375 × lo.
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Classify each measurement as a scaled or vector a 20 books on a shelf
a) Scalar quantity, b) Vector quantity, c) Vector quantity, d) Scalar quantity, e) Vector quantity, f) Scalar quantity, g) Scalar quantity, h) Scalar quantity.
What is the difference between scalar and vector quantity?A scalar quantity is a physical quantity with a single numerical value. Scalar quantities include mass, temperature, and velocity.
A vector quantity is a physical quantity that has a magnitude as well as a direction. Displacement, velocity, and acceleration are examples of vector quantities. Scalar quantities may be stated as a single numerical value, but vector quantities must be expressed as a magnitude and a direction.
In physics, vector quantities are frequently employed to describe physical qualities such as force, velocity, and acceleration. The parallelogram technique can be used to add and subtract vector values. Scalar quantities, on the other hand, cannot be added or subtracted in the same way. Scalar quantities are easily added and subtracted.
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A helicopter flies over the arctic ice pack at a constant altitude, towing an airborne 130-kg laser sensor that measures the thickness of the ice (see the drawing). The helicopter and the sensor both move only in the horizontal direction and have a horizontal acceleration of magnitude 2.57 m/s2. Ignoring air resistance, find the tension in the cable towing the sensor.
Answer:T=1316.21 N
Explanation:
The tension has two components: Vertical and Horizontal. The
horizontal component is ma, the vertical component is mg. Using
Pythagoras theorem, we can find the tension as:
T=((ma)^2 (mg)^2)^(1/2)
So
T=((129*2.84)^2 (129*9.8)^2)^(1/2)
T=1316.21 N
Which of the following situations will cause a current to be induced in a conductive loop in a uniform magnetic field B? a. The conductive loop lies in the plane of B. The area of the loop is increased. b. The conductive loop is oriented so that it is perpendicular to B. The area of the loop is decreased. C. The conductive loop lies in the plane of B. The
magnitude of B is increased. d. The conductive loop is oriented so that it is perpendicular to B. The loop is moved parallel to the field lines of B. e. The conductive loop is oriented so that it is perpendicular to B. The loop is moved perpendicular to the field lines of B. mo
In the given options, the situations that will cause a current to be induced in a conductive loop in a uniform magnetic field B are:
b. The conductive loop is oriented so that it is perpendicular to B. The area of the loop is decreased.
d. The conductive loop is oriented so that it is perpendicular to B. The loop is moved parallel to the field lines of B.
e. The conductive loop is oriented so that it is perpendicular to B. The loop is moved perpendicular to the field lines of B.
Explanation:
According to Faraday's law of electromagnetic induction, a changing magnetic field through a conductor induces an electromotive force (EMF) that causes a current to flow in the conductor.
In situation b, when the area of the loop is decreased while maintaining its perpendicular orientation to the magnetic field B, the magnetic flux passing through the loop decreases. This change in magnetic flux induces an EMF and subsequently a current in the loop.
In situation d, when the conductive loop is moved parallel to the field lines of B, the magnetic flux passing through the loop changes. This change in magnetic flux induces an EMF and subsequently a current in the loop.
In situation e, when the conductive loop is moved perpendicular to the field lines of B, the magnetic flux passing through the loop changes. This change in magnetic flux induces an EMF and subsequently a current in the loop.
It's important to note that in situations a and c, although the loop lies in the plane of B and the magnitude of B may change, there is no change in the magnetic flux passing through the loop. Therefore, no current will be induced in the loop in these situations.
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The volume V of a cube with sides of length x in. is changing with respect to time. At a certain instant of time, the sides of the cube are 7 in. long and increasing at the rate of 0.3 in./s. How fast is the volume of the cube changing (in cu in/s) at that instant of time
Answer:
my big long peen for ur mom
Explanation:
A parallel beam of light of wavelength 450nm is incident normally on a diffraction grating which has 300lines/mm what is the total number of intensity maxima observed?
The total number of intensity maxima observed is determined as 15.
Number of intensity maxima observedThe number of intensity maxima observed is calculated as follows;
\(n = \frac{1}{\lambda N}\)
n = (1) / (450 x 10⁻⁹ x 300 x 10³)
n = 7.4
The total number of intensity maxima observed;
nt = 2n + 1
nt = 2(7) + 1
nt = 15
Thus, the total number of intensity maxima observed is determined as 15.
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A point charge of 5.7 µc moves at 4.5 × 105 m/s in a magnetic field that has a field strength of 3.2 mt, as shown in the diagram. a field of circles labeled b. there is a positively charged particle with a velocity vector pointing 37 degrees north of east labeled v. what is the magnitude of the magnetic force acting on the charge? 6.6 × 10–3 n 4.9 × 10–3 n 4.9 × 103 n 6.6 × 103 n
The magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N
What is magnetic force?Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.The magnitude of the magnetic force acting on the charge is given by:
\(\rm F=qvBsin\theta\)
where
The magnitude of the charge \(q=5.7\ \mu C =5.7\times 10^{-6} \ C\)
The velocity of the charge \(v=4.5\times 10^5\ \frac{m}{s}\)
The magnitude of the magnetic field \(3.2\ mT=0.0032\ T\)
The angle between the directions of v and B \(\theta =90^o-37^o=53^o\)
By substituting the values we will get:
\(F=(5.7\times 10^}-6})(4.5\times 10^5)(0.0032)(Sin53^o)\)
\(F=6.6\times 10^{-3}\ N\)
Hence the magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N
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Answer:
a - on edge
Explanation:
yes
What is the absolute magnitude of the reduction in the variation of Y when times is introduced into the regression model? What is the relative reduction? What is the name of the latter measure?
1. The absolute magnitude of the reduction in variation of Y when time is introduced into the regression model can be calculated by subtracting the variance of Y in the original model from the variance of Y in the new model.
2. The relative reduction can be calculated by dividing the absolute magnitude by the variance of Y in the original model.
3. The latter measure is called the coefficient of determination or R-squared and represents the proportion of variance in Y that can be explained by the regression model.
When time is introduced into a regression model, it can have an impact on the variation of the dependent variable Y. The absolute magnitude of this reduction in variation can be measured by calculating the difference between the variance of Y in the original model and the variance of Y in the new model that includes time. The relative reduction in variation can be calculated by dividing the absolute magnitude of the reduction by the variance of Y in the original model.
The latter measure, which is the ratio of the reduction in variation to the variance of Y in the original model, is called the coefficient of determination or R-squared. This measure represents the proportion of the variance in Y that can be explained by the regression model, including the independent variable time. A higher R-squared value indicates that the regression model is more effective at explaining the variation in Y.
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What most directly determines an object's state of matter? (Please help)
A. the shape and texture of the object
B. the location of the object on Earth
C. the size of the particles in the object
D. the amount of motion and energy that the object's particles have
Answer:
I would say D
Explanation:
because the amount of energy in molecules of matter determines the state of matter
(if I'm wrong I'm sorry)
a plane electromagnetic wave, with wavelength 6 m, travels in vacuum in the positive x direction with its electric vector e, of amplitude 299.9 v/m, directed along y axis. what is the time-averaged rate of energy flow in watts per square meter associated with the wave?
The average energy flow rate of the wave is approximately 6.7 × 10⁻¹⁵ watts per square meter.
The time-averaged rate of energy flow in watts per square meter associated with the wave can be calculated using the formula:
P = (1/2) * ε₀ * c * E²
where P is the power density (energy flow per unit area), ε₀ is the vacuum permittivity (8.85 × 10⁻¹² F/m), c is the speed of light in vacuum (3 × 10⁸ m/s), and E is the amplitude of the electric field.
Substituting the given values into the formula:
P = (1/2) * (8.85 × 10⁻¹² F/m) * (3 × 10⁸ m/s) * (299.9 V/m)²
P ≈ 6.7 × 10⁻¹⁵ W/m²
Therefore, the time-averaged rate of energy flow associated with the wave is approximately 6.7 × 10⁻¹⁵ watts per square meter
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a negatively charged electroscope has separated leaves. (a) suppose you bring a negatively charged rod close to the top of the electroscope, but not touching. how will the leaves respond? (b) how will the leaves respond if you bring a positively charged rod close to the top of the electroscope, but not touching?
The leaves of a negatively charged electroscope will move apart if a positively charged rod is brought close to the top of the electroscope, but not touching it.
What is an electroscope?
An early scientific tool used to find an electrical charge on a body is called an electroscope. The movement of a test object caused by the Coulomb electrostatic force is used to detect charge. An object's charge is inversely proportional to its voltage.
part a) leaves will repel. leaves will move further apart.
part b) all the negative moves to the top to get closer to the positive leaves go back together as an excess negative move to the top. leaves separate less.
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What do we call a push or pull on an object?
Answer:
a force
Explanation:
Depending on the size of a solid particle, the gas behaves like particles (Epstein law, regime (1)), viscous fluid (Stokes law, regime (II)), or ideal fluid (regime (III)). Find the radius of a particle on the boundary between the regime (1) and regime (II) and that on the boundary between the regime (II) and the regime (III) when a solid particle is located at 5AU in the Hayashi model.
The Hayashi model is a theoretical model used to describe the temperature distribution and conditions in the protoplanetary disk. However, it does not provide explicit information about the gas-solid interaction regimes or the particle size boundaries.
To determine the particle radius on the boundaries between the different regimes, we need to consider the relevant laws and models related to gas-solid interactions.
Regime (1): Epstein Law
Regime (II): Stokes Law
Regime (III): Ideal Fluid
In the context of gas-solid interactions, these regimes represent different flow regimes based on the size of solid particles and the behavior of the gas surrounding them.
The Epstein Law (Regime 1) applies when the mean free path of gas molecules is greater than the particle radius, and individual gas molecules collide with the particle. In this regime, the gas behaves like individual particles.
Stokes Law (Regime II) applies when the particle size is large enough that gas molecules can no longer individually collide with the particle but instead adhere to its surface, causing a viscous drag. In this regime, the gas behaves like a viscous fluid.
The Ideal Fluid (Regime III) represents the limit where the particle size is large enough that the gas behaves like an ideal fluid, and the viscous drag becomes negligible.
To determine the particle radius on the boundaries between these regimes in the Hayashi model, more specific information about the model is needed. The Hayashi model is a theoretical model used to describe the temperature distribution and conditions in the protoplanetary disk. However, it does not provide explicit information about the gas-solid interaction regimes or the particle size boundaries.
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