Melanie would MOST LIKELY observe the plant's stem bending towards the hole in the side of the box.
This phenomenon is known as phototropism, which is the movement of a plant towards or away from a source of light. The plant will bend towards the hole in the box where it can receive more light, as this will help the plant carry out photosynthesis more efficiently. The roots of the plant will not be affected by the light coming from the hole, and therefore will not bend towards it. The leaves may turn towards the light if they are shaded, but this is not as likely as the stem bending towards the hole. Therefore, option D is the most likely observation.
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How much energy is required to move an electron through a potential difference of
12 V?
1) 1.9 x 10^- 18 )
2) 7.5 x 10^- 18 )
3) 1.3 x 10^-20)
4) 7.5 x 10^18 J
in an experiment searching for the photoelectric effect, an incident beam of green light did not eject any electrons from a metal. in order to eject electrons, the experimenter should
Increase the frequency of the incident light. The photoelectric effect occurs when light of a sufficient frequency strikes a metal and frees electrons from the metal's surface. The energy of the incident photons must be greater than the energy required to remove the electrons, known as the work function. Thus, increasing the frequency of the incident light will result in higher energy photons, increasing the likelihood of electron ejection in the photoelectric effect.
The kinetic energy of the photoelectrons that are released will grow as the light amplitude increases, according to the wave model of light, yet the measured current will increase as the frequency increases. In contrast to expectations, studies revealed that raising the light's frequency and amplitude raised the current and the photoelectrons' kinetic energy, respectively.
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A projectile has an initial horizontal velocity of 34.0 M/s at the edge of a roof top. Find the horizontal and vertical components of its velocity after 5.5s
I need shown work !
Answer:
\(v_x=34 m/s\)
\(v_y=53.9\ m/s\)
Explanation:
Horizontal Launch
When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it eventually hits the ground.
The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:
vx=v
The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:
\(v_y=g.t\)
The horizontal component of the velocity is always the same:
\(v_x=34 m/s\)
The vertical component at t=5.5 s is:
\(v_y=9.8*5.5=53.9\)
\(v_y=53.9\ m/s\)
Question 8 of 35
A car has a mass of 1000 kg and is travelling at a speed of 26 m/s. Calculate the kinetic energy of the
car. Use the word equation below to help you.
kinetic energy = 0.5 x mass x (speed)?
Answer:
338,000 JExplanation:
The kinetic energy of an object can be found by using the formula
\(k = \frac{1}{2} m {v}^{2} \\\)
m is the mass
v is the velocity
From the question we have
\(k = \frac{1}{2} \times 1000 \times {26}^{2} \\ = 500 \times 676 \\ = 338000\)
We have the final answer as
338,000 JHope this helps you
Question #8. Don’t pay attention to question number 9 it’s only there because I couldn’t crop it out
Given:
The distance traveled towards the north is d= 12 km
The velocity is v = 6.5 km/h
To find: the time
Explanation:
The formula to calculate time is
\(\begin{gathered} v=\frac{d}{t} \\ t=\frac{d}{v} \end{gathered}\)Substituting the values, the time will be
\(\begin{gathered} t=\text{ }\frac{12}{6.5} \\ =1.86\text{ h} \end{gathered}\)Final Answer: The time taken is 1.86 h
A 14.0-m uniform ladder weighing 520 N rests against a frictionless wall. The ladder makes a 57.0 angle with the horizontal. (a) Find the horizontal forces the ground exerts on the base of the ladder when an 830-N firefighter has climbed 4.20 m along the ladder from the bottom. (b) If the ladder is just on the verge of slipping when the firefighter is 9.20 m from the bottom, what is the coefficient of static friction between ladder and ground?
(a) The horizontal force exerted on the ladder by the ground is 196.97 N.
(b) The coefficient of static friction between the ladder and the ground is 0.428.
(a) First, we'll find the torque about the bottom of the ladder. Torque = Force × Distance × sin(Angle). Torque due to firefighter: 830 N × 4.20 m × sin(57°) = 2871.77 Nm.
Torque due to ladder's weight: 520 N × (14 m / 2) × sin(57°) = 3619.83 Nm. Sum of torques = 0, so horizontal force (Fh) = (Torque_firefighter - Torque_ladder) / (14 m × sin(57°)) = 196.97 N.
(b) When on the verge of slipping, the vertical force (Fv) due to friction balances the weight forces.
Fv = 830 N + 520 N = 1350 N.
The force of static friction (Fs) = Fh = 196.97 N. The coefficient of static friction (μs) = Fs / Fv = 196.97 N / 1350 N = 0.428.
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A machine puts out 20 watts of power for every 100 watts put into it what’s the efficiency of the machine?
12. a) What is the gravitational attraction of the sun
on the earth? (b) of the earth on the sun?
Answer:
About 3.54x1022 N.
Explanation: The gravitational force between the Sun and the Earth is about 3.54x1022 N. This force keeps the Earth orbiting around the Sun. The gravitational force from the other planets does slightly affect the Earth's orbit, but the gravitational pull from the other planets and the Moon is still very small. Sorry if I get this wrong. I am in 5th grade! ♥
In a region of space there is an electric field 'E' that is in the z-direction and that has magnitude E = (747 N/(C*m))x. Find the flux for this field through a square in the xy-plane at z = 0 and with side length 0.370m . One side of the square is along the +x -axis and another side is along the +y-axis.
The flux through each side is zero, the total flux through the square is also zero. Therefore, the electric field does not pass through the square in the xy-plane at z = 0.
The flux of an electric field through a surface is given by the dot product of the electric field and the surface area vector. In this case, the electric field E is in the z-direction, so it does not contribute to the flux through the xy-plane. Therefore, we only need to consider the flux through the sides of the square that are perpendicular to the z-axis. These sides are along the +x and +y axes and have length 0.370m each.
The surface area vector for the +x side is (0.370m) * (0m) * (+1), and for the +y side it is (0m) * (0.370m) * (+1). The dot product of the electric field E and the surface area vector for each side gives:
For the +x side: (747 N/(C*m))x * (0.370m) * (0m) * (+1) = 0
For the +y side: (747 N/(C*m))x * (0m) * (0.370m) * (+1) = 0
Since the flux through each side is zero, the total flux through the square is also zero. Therefore, the electric field does not pass through the square in the xy-plane at z = 0.
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if the lens of your eye is diffraction limited, at what distance are the two headlights marginally resolved? assume a wavelength of 575 nm and that the index of refraction inside the eye is 1.33. (your eye is not really good enough to resolve headlights at this distance, due both to aberrations in the lens and to the size of the receptors in your retina, but it comes reasonably close.)
To calculate the distance at which two headlights are marginally resolved by a diffraction-limited eye lens, we can use the Rayleigh criterion:
sin(θ) = 1.22 * λ / (D * n)
Where θ is the angle between the two headlights, λ is the wavelength of light (575 nm in this case), D is the diameter of the pupil (which we'll assume to be 5 mm), and n is the index of refraction inside the eye (1.33 in this case).
Solving for the angle θ gives:
θ = sin^-1(1.22 * λ / (D * n))
θ = sin^-1(1.22 * 575 nm / (5 mm * 1.33))
θ ≈ 0.002 radians
Now, we can use basic trigonometry to calculate the distance between the two headlights that corresponds to this angle. If we assume the headlights are at the same height as our eyes (about 1.6 meters), we get:
distance = (1.6 m) * tan(θ / 2)
distance ≈ 4.4 km
So, if the lens of your eye is diffraction-limited, you could resolve two headlights that are about 4.4 kilometers apart. However, as mentioned earlier, this is not the only limitation to resolving headlights at a distance – there are other factors such as the size of the receptors in the retina that come into play.
Hi! To determine the distance at which two headlights are marginally resolved when the lens of your eye is diffraction-limited, we can use the Rayleigh criterion. The Rayleigh criterion states that two points are just resolvable when the central maximum of one's diffraction pattern coincides with the first minimum of the other's diffraction pattern.
The formula for the angular resolution (θ) based on the Rayleigh criterion is:
θ = 1.22 * (λ / D)
where λ is the wavelength of light (575 nm) and D is the diameter of the lens (approximated as the pupil size). In the human eye, the pupil size varies, but let's assume a typical diameter of 5 mm or 0.005 m.
θ = 1.22 * (575 * 10^(-9) m / 0.005 m)
θ ≈ 1.4 * 10^(-4) radians
Now, let's use the small angle approximation (θ ≈ sin(θ) ≈ tan(θ)) to find the distance (L) at which the headlights are marginally resolved:
θ ≈ (headlight separation) / L
Assuming a standard headlight separation of 1.2 meters, we can solve for L:
1.4 * 10^(-4) ≈ 1.2 m / L
L ≈ 1.2 m / (1.4 * 10^(-4))
L ≈ 8,571 meters
So, when the lens of your eye is diffraction-limited, the two headlights are marginally resolved at approximately 8,571 meters. Keep in mind that this is a theoretical calculation and might not exactly match real-life observations due to aberrations in the lens and the size of the receptors in your retina.
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Rock A is thrown horizontally off a cliff with a velocity of 20 m/s. The rock lands
60 m from the base of the cliff. Refer to the information and diagram shown
below. A second rock (Rock B) is dropped from the same height from which Rock
A was thrown. If both rocks are released simultaneously, which rock will strike the
ground first? *
Answer:
They will strike at the same time
Explanation:
Both will hit the ground at the same time.
What is total energy ?
Total energy of any object under consideration is the sum of potential energy (P.E) and kinetic energy (K.E) and is constant throughout the motion.
Here, it is given that the both rocks are falling from same height and
there is no initial velocity in vertical direction for both rocks
The only external force that is applied on them is gravitation force which is also constant in both cases.
Therefore, they will hit the ground at the same time considering air resistant and all others factors neglected.
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solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid are called ________.
Concentrated solar power facilities are solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid .
What is solar power?Solar power refer to electric power or electricity that is generated from sun rays or radiations while using solar panels and other technologies.
Therefore, Concentrated solar power facilities solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid.
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Which of the following is not a component of fitness? A. Cardiovascular fitness B. Muscular endurance C. Pulmonary endurance D. Body composition
Answer:
C. Pulmonary endurance
Explanation:
I'm pretty sure it's "C" because cardiovascular and pulmonary endurance are the same thing and usually you'd hear cardiovascular more than pulmonary.
Sorry if I'm wrong!
Answer:
c
Explanation:
i just took the test
what if you were a mother for a day boys and girls
A 56 kg student stands atop aspring in an elevator that is acceleratingupward at 3.5 m/s2m/s2. The springconstant is 2900 N/mN/m. Part A Byhow much is the spring compressed
Given data,
Mass,
\(m=56\text{ kg}\)Acceleration,
\(a=3.5m/s^2\)Spring constant,
\(k=2900\text{ N/m}\)Acceleration due to gravity,
\(g=9.8m/s^2\)Accelerating upward,
\(\begin{gathered} a^{\prime}=(a+g) \\ a^{\prime}=3.5m/s^2+9.8m/s^2 \\ a^{\prime}=13.3m/s^2 \end{gathered}\)Comsider the formula for force.
\(\begin{gathered} F=kx \\ ma^{\prime}=kx \\ 56kg\times13.3m/s^2=2900\text{ N/m}\times x \\ x=25.68\text{ cm} \end{gathered}\)Thus, the spring compression is 25.68 cm.
Write the importance of international bureau of weight and measures in the country
Answer:
International Bureau of Weights and Measures (BIPM) is an international organization founded to bring about the unification of measurement systems, to establish and preserve fundamental international standards and prototypes, to verify national standards, and to determine fundamental physical constants. The bureau was established by a convention signed in Paris on May 20, 1875, effective January 1876. In 1921 a modified convention was signed. The convention provides for a General Conference that meets every four years to consider required improvements or modifications in standards. An International Committee of Weights and Measures, composed of 18 scientists elected by the conference, meets annually to monitor worldwide uniformity in units of measure.
Hope this helps!!! :)
(If not please comment I will try to help)
Please assist me with this question.
The diagram of a thermocouple that can be used to measure the temperature of the sulfur as it cools, created with MS Word is attached.
What is a thermocouple?A thermocouple is a device that consists of two different types of metal wires joined together at one end. When the junction of the two metals are heated or cooled, a voltage is produced that can be correlated to temperature. Thermocouple are commonly used to measure temperature in a variety of applications because they are rugged, inexpensive and can measure a wide range of temperatures.
To use a thermocouple to measure the temperature of molten sulfur in a beaker, you would need to insert the junction (the end where the two metal wires are joined) into the molten sulfur. The other ends of the metal wires would need to be connected to a device that can measure the voltage produced by the thermocouple. As the sulfur cools and its temperature changes, so will the voltage produced by the thermocouple. By measuring this voltage and using a reference table or equation that correlates voltage with temperature for that specific type of thermocouple, the temperature of the sulfur as it cools can be determined.
Please find attached the drawing of a thermocouple which can be used to determine the sulfur as it cools.
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which of the following cell components are are most involved in determing an organisms traits?
The :Gene, chromosomes, and nucleus is the cell components are are most involved in determining an organisms traits.
What is meant by organism traits?As it relates to genetics, a trait is a unique quality about a person. Genes, environmental influences, or a combination of both can influence traits. Qualitative traits, like eye color, can also be quantitative (such as height or blood pressure).
Your traits, which are features or characteristics that you inherit from your parents, are determined by the information carried by your genes (say: trates). In the human body, each cell has between 25,000 and 35,000 genes.
A trait is a unique attribute, propensity, or characteristic that someone, something, or both have. In those early months, many of our personality traits are formed. Humans are creative beings. Synonyms: trait, quality, feature, attribute additional words for characteristic
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how to burn your module?
sabog na sabog nako eh
Answer:
get some
get some ⛽⛽⛽⛽⛽
pour the ⛽ on the module,
get that on itttttt and booooooommmm
Explanation:
a 12.5-kg board, 4.00 m long, is being held up on one end by Ahmed. He calls for help in lifting the board, and Judi responds
F min=61.25N Ahmed is supporting a 12.5 kg, 4.00 m long board on one end. Judi responds to his request for assistance by accelerating the speed of the motion, and is the rate for which velocity varies over time.
Explain what an acceleration is.acceleration is the rate of change in both speed and the direction of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. So because direction is constantly changing, even motion on the a circle accelerates at a constant pace.
What happens if you speed up?This means that a velocity change can be either an alteration in the speed or direction of motion of an object. Acceleration is the process by which an item alters its direction, speed, or both.
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The force of electrostatic repulsion between two small positively charged objects, A and B, is 3.6 x 10⁻⁵ N when AB = 0.12m. What is the force of repulsion if AB is increased to 0.24 m
Given data:
* The electrostatic force of repulsion between the charged bodies in the initial state is,
\(F=3.6\times10^{-5}\text{ N}\)* The distance between the charged bodies in the initial state is,
\(d=0.12\text{ m}\)* The distance between the charged bodies in the final state is,
\(\begin{gathered} d^{\prime}=0.24\text{ m} \\ d=2\times0.12 \\ d^{\prime}=2d \end{gathered}\)Solution:
According to Coulomb's law, the electrostatic force of repulsion between the charged bodies in the initial state is,
\(F=\frac{kq_1q_2}{d^2}\)where k is the electrostatic force constant, q_1 is the charge on the first charged body and q_2 is the charge on the second charged body,
The electrostatic force of repulsion between the charged bodies in the final state is,
\(\begin{gathered} F^{\prime}=\frac{kq_1q_2}{(2d)^2} \\ F^{\prime}=\frac{kq_1q_2}{4d^2} \\ F^{\prime}=\frac{1}{4}\times\frac{kq_1q_2}{d^2} \\ F^{\prime}=\frac{F}{4} \end{gathered}\)Substituting the known values,
\(\begin{gathered} F^{\prime}=\frac{3.6\times10^{-5}}{4} \\ F^{\prime}=0.9\times10^{-5}\text{ N} \end{gathered}\)Thus, the electrostatic force of repulsion between the charged bodies in the final state is,
\(\text{0}.9\times10^{-5}\text{ N}\)If Kaden throws the football 60 meters in 3 seconds, what is the speed of the football?
Answer:
I believe this problem is 60 divided by 3 = 20m/s
That’s the formula.
Explanation:
Analyze What could you do to change the
volume of a gas?
You can change the volume, pressure, or temperature of a gas.
Change the volume of a gas to raise or lower the temperature. As the temperature increases, the gas expands and increases in volume. Conversely, as the temperature decreases, the volume of the gas decreases. As the temperature increases, the volume of the gas increases. Conversely increasing the pressure will decrease the volume of the gas.
Reducing the gas volume increases the gas pressure. An example of this is when gas is trapped inside a cylinder by a piston. When the piston is pushed in, the volume occupied by the gas decreases, so there is less room for gas particles to move. The relationship between pressure and volume Boyle's Law. As the pressure of a gas increases the gas particles are pushed together thus decreasing the volume of the gas.
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A rat is placed in an environment where the floor gives the rat small electric shocks. The only way to get rid of the shocks is to press a lever in the corner of the box. The rat quickly learns to press the lever. This is an example of
Pressing a lever in the box's corner is the sole method to get rid of the shocks. The rat picks up pressing the lever quite quickly. This is an illustration of negative reinforcement.
What is negative reinforcement?The technique of negative reinforcement can be applied to aid in teaching particular actions.
When something unpleasant or uncomfortable is taken away in response to a stimulus, this is known as negative reinforcement.
Target behavior should gradually grow better with the hope that the unpleasant item will go away.
A rat is placed in an environment where the floor gives the rat small electric shocks. The only way to get rid of the shocks is to press a lever in the corner of the box.
The rat quickly learns to press the lever. This is an example of negative reinforcement
Hence the given condition is an example of negative reinforcement.
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When work is done by a system, does the internal energy of the system increase or decrease?
Decrease
Explanation:The mathematical relationship between heat, internal energy and work done by the system is given as:
△U = Q + W
where △U is the change in the internal energy
W is the workdone by the system
Q is the heat energy in the system
Since the workdone by the system is negative, when a system does work, there is a depletion in the amount of energy possessed by the system.
Due to this loss of energy by the system as a result of the workdone, the internal energy decreases.
10) A 57-kg packing crate is pulled with constant speed across a rough floor with a rope that is at an angle of 37° above the horizontal. If the tension in the rope is 142 N, how much work is done on the crate to move it 6.1 m?
F=m*a
T = 142N
Work = Force x distance
distance = 6.1 M
Force = 142 x cos 37 = 113.4 N
W= 113.4N x 6.1M = 691.78 J
Recoil is noticeable if we throw a heavy ball while standing on roller skates. If instead we go through the motions of throwing the ball but hold onto it, our net recoil will be?.
Answer:
zero
Explanation:
If the orbital distance of earth was greater than its actual value, the parallax angle to nearby stars would be.
If the orbital distance of earth was greater than its actual value, the parallax angle to nearby stars would be Higher.
What connection exists between distance and parallax angle?Because of the inverse relationship between parallax angle and distance, the parallax angle decreases as the distance to the star rises.
What is the reference point that astronomers use to calculate the parallax of the closest stars?The Earth's orbit around the sun. There are no two eyes that can accurately determine the distances to other stars. Instead, the starting point for these calculations is the Earth's orbit around the sun.
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Question 4 Marks: 1 A filter of 2 mm of aluminum will absorb the soft, or less penetrating, radiation.Choose one answer. a. True b. False
I am a field physicist and I perform QA measurements of various types of X-ray units. Due to recent changes in legal requirements in my country, we have to provide the radiation output value for each unit tube measured in m Gy MA's at 1 meter from focal spot) at filtration of 2,5 mm Al equivalent. a. True
This unfortunately cannot be directly achieved for interventional radiology units, some CTs and occasionally other types of X-ray units. A filter of 2 mm of aluminum will absorb the soft, or less penetrating, radiation. Aluminum is often used as a filter in radiography because it effectively absorbs low-energy, soft X-rays, while allowing more penetrating, higher-energy X-rays to pass through. This helps improve image quality and reduce patient exposure to unnecessary radiation.
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uh could i get a little help please im very confused
1) Frequency
2) I dont know this one sorry