MEANING OF 万華鏡 AND ビアクガン

Answer:

0.111

The probability of two blue marbles being drawn from the bag to all marbles is 2/18, and 2/18 ----> 0.11 rounded to nearest thousandth.

Step-by-step explanation:

\(\begin{cases}2x-9y=-51\\2x-3y=-9\end{cases}\\\\\\\begin{cases}(2x-9y)(-1)=-51(-1)\\2x-3y=-9\end{cases}\)

\(\begin{cases}-2x+9y=51\\2x-3y=-9\end{cases}\)     (adding the second equation to the first one)

\(\begin{cases}\qquad6y=42\\2x-3y=-9\end{cases}\\\\\\\begin{cases}\qquad y=7\\2x-3y=-9\end{cases}\\\\\\\begin{cases}y=7\\2x-3(7)=-9\end{cases}\\\\\\\begin{cases}y=7\\2x-21=-9\end{cases}\\\\\\\begin{cases}y=7\\2x=12\end{cases}\\\\\\\begin{cases}x=6\\y=7\end{cases}\)

The matrix B that organizes the data is given as follows:

B = [13, 36, 27,

      10, 15, 0,

       23, 51, 27].

The matrix that shows the total value of each cap size in each location is given as follows:

C = [247, 684, 513,

      190, 285, 0,

      437, 969, 513].

The matrix B is defined considering that it will have three rows and three columns, as follows:

Then the matrix B is defined as follows:

B = [13, 36, 27,

      10, 15, 0,

       23, 51, 27].

The cost of each baseball cap is of $19, thus the cost matrix is obtained multiplying the matrix B by the constant of 19.

When a matrix is multiplied by a constant, all the elements of the matrix are multiplied by the constant, hence the cost matrix is given as follows:

C = [247, 684, 513,

      190, 285, 0,

      437, 969, 513].

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Answer: i think it is D

we have:

\(\frac{z}{w}= \frac{6(cos\frac{\pi }{3}+i.sin\frac{\pi }{3} ) }{3(cos\frac{\pi }{6}+i.sin\frac{\pi }{6}) }\\\\\\<=>\frac{z}{w}=\frac{2(\frac{1}{2}+i.\frac{\sqrt{3} }{2}) }{\frac{\sqrt{3} }{2}+i.\frac{1}{2} }\\\\<=>\frac{z}{w}= \frac{2+2\sqrt{3}.i }{\sqrt{3}+i }\)

Step-by-step explanation:

Answer:

2 one that's the right one

Answer:

9

Step-by-step explanation:

t < 13 - 4

t < 9

again as far as it goes

The -value of the test is 1.90. This indicates that the mean processing time is significantly greater than 5.5 hours, supporting the manufacturer's desire to set a standard time required by employees to complete a certain process

The t-value will be equal to 1.39 for the given statistics.

To test if the mean processing time exceeds 5.5 hours, we can use a one-sample t-test.

The null hypothesis is that the mean processing time is less than or equal to 5.5 hours:

H0: µ ≤ 5.5

The alternative hypothesis is that the mean processing time is greater than 5.5 hours:

Ha: µ > 5.5

We will use a significance level of 0.05.

The formula for the t-test statistic is:

t = (X - µ) / (s / √n)

Where:

X = sample mean

µ = hypothesized population mean

s = sample standard deviation

n = sample size

Substituting the given values, we get:

t = (6 - 5.5) / (2 / √21) = 1.386

The degree of freedom for the t-test is n-1 = 20.

Using a t-table or calculator, the p-value associated with a t-value of 1.386 and 20 degrees of freedom is 0.093.

Since the p-value (0.093) is greater than the significance level (0.05), we fail to reject the null hypothesis. Therefore, there is not enough evidence to suggest that the mean processing time exceeds 5.5 hours.

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Four cats were left at the end if there were 4 cats but another 4 came but five cats left then 8 more came but 7 cats left and ratio of the cats left is 4/8.

At first, there were 4 felines. At the point when another 4 felines showed up, the absolute number of felines became 8. Notwithstanding, 5 felines left, leaving just 3 felines. Then, at that point, 8 additional felines showed up, making the absolute number of felines 11. Be that as it may, 7 felines left, leaving just 4 felines toward the end.

In more detail, we can separate the issue into each step:

At first, there were 4 felines.

Another 4 felines showed up, making the absolute number of felines 8.

Nonetheless, 5 felines left, leaving just 3 felines.

8 additional felines showed up, making the absolute number of felines 11.

At last, 7 felines left, leaving just 4 felines toward the end.

Thusly, the response is 4 felines were left toward the end. We can sum up this issue utilizing the accompanying condition:

4 + 4 - 5 + 8 - 7 = 4

This condition shows that we start with 4 felines, add 4, deduct 5, add 8, and afterward take away 7 to come by the end-product of 4 felines left.

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Answer:

D

Step-by-step explanation:

the zero is the value of x where the line crosses the x- axis, that is

zero is x = - 2

To determine the assignment of employees to jobs that minimizes the total time required to perform the four jobs, we need to consider the time taken by each person to complete each job. Using the given Table 50, we can analyze the data and identify the optimal assignment.

By examining Table 50, we can identify the minimum time taken by each person for each job. Starting with Job 1, we see that Person 4 takes the least time of 16 hours. Moving to Job 2, Person 2 takes the least time of 18 hours. For Job 3, Person 1 takes the least time of 25 hours. Lastly, for Job 4, Person 4 takes the least time of 14 hours.

Therefore, the optimal assignment would be:

- Person 4 for Job 1 (16 hours)

- Person 2 for Job 2 (18 hours)

- Person 1 for Job 3 (25 hours)

- Person 4 for Job 4 (14 hours)

This assignment ensures that the minimum total time is required to perform the four jobs, resulting in a total time of 16 + 18 + 25 + 14 = 73 hours.

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If you make annual payments of $1400 for 8 years at a 6% interest rate compounded annually, the total amount accumulated over the 8-year period would be approximately $12,350.

To explain further, when you make annual payments of $1400 for 8 years, you are essentially depositing $1400 into an account each year. The interest rate of 6% compounded annually means that the interest is added to the account balance once a year.

To calculate the total amount accumulated, you can use the formula for the future value of an ordinary annuity:

FV = P * ((1 + r)^n - 1) / r

where FV is the future value, P is the payment amount, r is the interest rate per compounding period (in this case, 6% or 0.06), and n is the number of compounding periods (in this case, 8 years).

Plugging in the values, we have:

FV = $1400 * ((1 + 0.06)^8 - 1) / 0.06

≈ $12,350

Therefore, the total amount accumulated over the 8-year period would be approximately $12,350.

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The probability that the entire shipment will be kept by Dell even though the shipment has 10% defective microprocessors is approximately 0.5905. Hence the correct answer is (a) 0.5905.

To calculate the probability that the entire shipment will be kept by Dell even though the shipment has 10% defective microprocessors, we can use the concept of binomial probability.

Let's denote the probability of a microprocessor being defective as p = 0.10 (10% defective) and the number of microprocessors Dell tests as n = 5.

We want to calculate the probability that all five tested microprocessors are non-defective, which is equivalent to the probability of having zero defective microprocessors in the sample.

Using the binomial probability formula, the probability of getting exactly k successes (non-defective microprocessors) in n trials is:

\(\[P(X = k) = \binom{n}{k} \cdot p^k \cdot (1 - p)^{n - k}\]\)

For this case, we want to calculate P(X = 0), where X represents the number of defective microprocessors.

\(\[P(X = 0) = \binom{5}{0} \cdot 0.10^0 \cdot (1 - 0.10)^{5 - 0} \\= 1 \cdot 1 \cdot 0.9^5 \\\\approx 0.5905\]\)

Therefore, the correct answer is (a) 0.5905.

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Answer:

2500

Step-by-step explanation:

the sum of the squares of the odd integers between 0 and 100 is 2500

A bicycle repair shop that offers two service packages: a tune-up and a complete overhaul.

The shop operates for 60 hours per week and receives an average of 180 bicycles each week. To analyze the capacity and utilization of the process, we need to consider the time taken at each stage and the demand for each service option. We'll break down the problem into multiple parts and provide a detailed explanation using mathematical terms.

a) Creating the Demand Matrix:

To create a demand matrix, we need to determine the number of bicycles going through each stage of the process. Let's denote the demand for tune-up as T and the demand for additional services as A.

Given that the average number of bicycles received per week is 180 and 25% of customers opt for additional services, we can calculate the demands as follows:

Demand for tune-up (T) = Total demand - Demand for additional services

T = 180 - (0.25 * 180)

T = 180 - 45

T = 135

Demand for additional services (A) = 0.25 * Total demand

A = 0.25 * 180

A = 45

Now, we can create a demand matrix based on the demand for each service option:

Demand Matrix:

Tune-up Additional Services Wheel Balancing

Tune-up  [135  0  0]

Additional [0  45  0]

Services

Total [ 135  45  0 ]

The demand matrix shows the number of bicycles flowing through each stage of the process.

b) Daily Capacity at Each Stage:

To calculate the daily capacity at each stage, we need to consider the time taken for each service option. Given that the shop operates for 60 hours per week, we can calculate the daily capacity at each stage:

Tune-up technician time per bicycle (\(T_{tuneup}\)) = 75 minutes

Additional services technician time per bicycle (\(T_{additional}\)) = 72 minutes

Wheel balancing specialist time per bicycle (\(T_{balancing}\)) = 20 minutes

Daily Capacity (C) = (60 hours * 60 minutes) / (\(T_{tuneup}\) + \(T_{additional}\) + \(T_{balancing}\))

Substituting the given values:

C = (60 * 60) / (75 + 72 + 20)

C = 21600 / 167

C ≈ 129.34 bicycles per day

Therefore, the daily capacity at each stage of the process is as follows:

Tune-up: 129 bicycles per day

Additional Services: 129 bicycles per day

Wheel Balancing: 129 bicycles per day

c) Implied Utilizations:

To find the implied utilizations, we need to compare the demand and the capacity at each stage of the process. Utilization can be calculated as the demand divided by the capacity.

Implied Utilization (U) = Demand / Daily Capacity

For the Tune-up stage:

\(U_{tuneup}\) = 135 / 129 ≈ 1.05

For the Additional Services stage:

\(U_{additional}\) = 45 / 129 ≈ 0.35

For the Wheel Balancing stage:

\(U_{balancing}\) = 0 / 129 = 0

The implied utilizations show how efficiently each stage of the process is being utilized. Utilization values greater than 1 indicate that the stage is operating beyond its capacity.

d) Weekly Capacity of the Process:

To calculate the weekly capacity of the process, we multiply the daily capacity by the number of days the shop is open per week:

Weekly Capacity = Daily Capacity * Number of days shop is open per week

Given that the shop is open for 60 hours per week, the number of days the shop is open per week can be calculated as follows:

Number of days shop is open per week = 60 hours / 24 hours per day = 2.5 days

Therefore, the weekly capacity of the process is:

Weekly Capacity = Daily Capacity * Number of days shop is open per week

Weekly Capacity = 129 bicycles per day * 2.5 days

Weekly Capacity = 322.5 bicycles per week

e) Flow Rate and Constraint Analysis:

To determine if the flow rate of the process is capacity-constrained or demand-constrained, we compare the weekly capacity to the demand for each service option.

Demand for Tune-up (\(T_{demand}\)) = 135 bicycles per week

Demand for Additional Services (\(A_{demand}\)) = 45 bicycles per week

Comparing the demands with the weekly capacity:

\(T_{demand}\) < Weekly Capacity (135 < 322.5)

\(A_{demand}\) < Weekly Capacity (45 < 322.5)

Since both the demands for tune-up and additional services are less than the weekly capacity, the flow rate of the process is demand-constrained. This means the shop has the capacity to handle the current demand without operating beyond its limits.

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The number of more games that Lucy sells than Finley will be 28 games.

The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.

Mathew, Lucy, and Finley sold a total of 56 games at a car boot sale. The ratio of games that they each sold is 2:5:1.

Let 'x' be the common factor. Then the equation is given as,

2x + 5x + 1x = 56

8x = 56

x = 7

Then the number of more games that Lucy sells than Finley will be given as,

⇒ 5 × 7 - 1 × 7

⇒ 35 - 7

⇒ 28

The number of more games that Lucy sells than Finley will be 28 games.

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Answer:

\(x^{2} -xz-xy+yz\)

Step-by-step explanation:

To answer this question we have to multiply each value of a bracket by every value from the other bracket!

It is super important to make sure that we take in consideration the operations of each value

Firstly, we are going to multiply the x in the first bracket by every value in the other bracket...

Now we are going to multiply the \(-y\) by everything in the other bracket...

This leaves us with \(x^{2} -xz-xy+yz\)

Hope this helps, have a lovely day! :)

Answer: \(x>-3\)

Step-by-step explanation:

\(5-4x<17\)

\(5-4x-5<17-5\)

\(-4x<12\)

Multiply both sides by -1 and reverse the inequality:

\(\left(-4x\right)\left(-1\right)>12\left(-1\right)\)

\(4x>-12\)

\(x>-3\)

Answer:  

x-int = 4.5  

y-int = -1

Buddy you don't need to spam the question btw

The polar coordinates of the point (6, 6) are approximately (8.49, 0.79) in radians.

To convert the point (6, 6) from Cartesian to polar coordinates, we can use the formulas:

r = √(x² + y²)

θ = arctan(y/x)

Given that the point is (6, 6), we can substitute the values into the formulas to find the polar coordinates.

r = √(6² + 6²) = √(36 + 36) = √72 ≈ 8.49

θ = arctan(6/6) = arctan(1) = π/4 ≈ 0.79 (radians)

In polar coordinates, the value of r represents the distance from the origin (0, 0) to the point, and the value of θ represents the angle (measured in radians) between the positive x-axis and the line connecting the origin to the point. The angle θ is usually measured counterclockwise from the positive x-axis.

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Complete question is:

Convert the point from Cartesian to polar coordinates. Write your answer in radians. Round to the nearest hundredth.

(6,6)

The Hermite curve with four control points P0(0,0), P1(1,1), P2(2,-1), and P3(3,0) has tangent vectors P0'(1,1) and P3'(1,1) at the endpoints. To determine the intermediate points on the curve at t = 1/3 and t = 2/3, we can use the Hermite interpolation formula.

The Hermite interpolation formula allows us to construct a curve based on given control points and tangent vectors. In this case, we have four control points P0, P1, P2, and P3, and tangent vectors P0' and P3'.

To find the intermediate point at t = 1/3, we use the Hermite interpolation formula:

P(t) = \((2t^3 - 3t^2 + 1)P0 + (-2t^3 + 3t^2)P3 + (t^3 - 2t^2 + t)P0' + (t^3 - t^2)P3'\)

Substituting the given values:

\(P(1/3) = (2(1/3)^3 - 3(1/3)^2 + 1)(0,0) + (-2(1/3)^3 + 3(1/3)^2)(3,0) + ((1/3)^3 - 2(1/3)^2 + (1/3))(1,1) + ((1/3)^3 - (1/3)^2)(1,1)\)

Simplifying the equation, we can find the coordinates of the intermediate point at t = 1/3.

Similarly, for t = 2/3, we use the same formula:

\(P(2/3) = (2(2/3)^3 - 3(2/3)^2 + 1)(0,0) + (-2(2/3)^3 + 3(2/3)^2)(3,0) + ((2/3)^3 - 2(2/3)^2 + (2/3))(1,1) + ((2/3)^3 - (2/3)^2)(1,1)\)

Calculating the equation yields the coordinates of the intermediate point at t = 2/3.

In this way, we can use the Hermite interpolation formula to determine the intermediate points on the Hermite curve at t = 1/3 and t = 2/3 based on the given control points and tangent vectors.

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Answer:

pls give me brainliest

Step-by-step explanation:

0.83333333333

Answer:

5/6

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

Basically insert 18 where the X is and go from there!

2/3 (18) - 4

2/3 × 18 = 12

12 - 4 = 8

Answer:

in what? if you meant 8 hours in 24 hours than 3 times

Step-by-step explanation:

Answer:

The answer is 3 times.

Step-by-step explanation:

\(since \: 8 \times 3 =24

then \: you \: can \: fit \: 8 \: hours \: 3 \: times \: in \: 24 \: hours.\)

Answer:

Rational ...................

Step-by-step explanation:

A rational number is a number that can be express as the ratio of two integers. A number that cannot be expressed that way is irrational. For example, one third in decimal form is 0.33333333333333 (the threes go on forever). However, one third can be express as 1 divided by 3, and since 1 and 3 are both integers, one third is a rational number

The logarithmic equation 2log4 - log3 + 2logx - 4 = 0 can be solved by rewriting the equation using logarithmic properties and then solving for x. The exact value of x depends on the logarithmic base used.

To solve the logarithmic equation 2log4 - log3 + 2logx - 4 = 0, we can start by applying logarithmic properties. Using the properties

log(a) - log(b) = log(a/b) and log(a^b) = b log(a), we can rewrite the equation as log(4^2) - log(3) + log(x^2) - log(10,000) = 0.

Simplifying further, we have 2 log(16) - log(3) + 2 log(x) - 4 = 0.

Next, we can combine the logarithmic terms using the property

log(a) + log(b) = log(a * b). This gives us log(16^2 * x^2 / 3) - 4 = 0. Simplifying the logarithm, we have log(256x^2/3) - 4 = 0.

To isolate the logarithm, we can apply the property a = b implies 10^a = 10^b. In this case,

10^(log(256x^2/3) - 4) = 10^0. This simplifies to 256x^2/3 = 10^4.

Finally, we solve for x by rearranging the equation. Multiplying both sides by 3/256, we get x^2 = (3/256) * 10^4. Taking the square root of both sides, we have x = ±√(3/256) * 10^2. Thus, the exact value of x depends on the logarithmic base used, but this provides the general form of the solution.

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Answer: 5

Step-by-step explanation:

He is opening a dialog box to access a second workbook by pressing F12 and then clicking tool box.

A dialog box is a temporary window an application creates to retrieve user input. An application typically uses dialog boxes to prompt the user for additional information for menu items.It (also spelled dialogue box, also called a dialog) is a common type of window in the GUI of an operating system. The dialog box displays additional information, and asks a user for input. For example, when you are using a program and you want to open a file, you interact with the "File Open" dialog box.

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The probability of passing a 10-question multiple-choice quiz by random guessing is about 2.4%.

A quiz consists of 10 multiple-choice questions, each with 6 possible answers. for someone who makes random guesses for all of the answers, find the probability of passing if the minimum passing grade is 50 %.

The probability of a random guess being correct for a single multiple-choice question with 6 options is 1/6, or approximately 0.17.

To find the probability of passing the quiz with a minimum passing grade of 50%, we need to calculate the probability of getting 5 or more correct answers out of 10.

This can be calculated as the sum of the probabilities of getting exactly 5, 6, 7, 8, 9, or 10 correct answers:

P(pass) = P(5) + P(6) + P(7) + P(8) + P(9) + P(10)

where P(x) is the probability of getting exactly x correct answers.

This can be calculated using the binomial distribution and its cumulative distribution function (CDF). The result is approximately 0.024, or 2.4%.

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