The term in the velocity formula that represents the initial velocity is "v0."
The complete formula for velocity is v = v0 + at, where v is the final velocity, a is the acceleration, and t is the time elapsed. This formula is used to calculate the final velocity of an object undergoing constant acceleration, taking into account the initial velocity and the time elapsed.
The interpretation of this formula is that the final velocity of the object is equal to the initial velocity plus the product of the acceleration and the time elapsed.
Therefore, if the acceleration is positive, the final velocity will be greater than the initial velocity, and if the acceleration is negative, the final velocity will be less than the initial velocity.
This formula is commonly used in physics and engineering to predict the motion of objects and to design systems that involve acceleration.
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Un automovil de 900 kg toma una curva de radio de 40 m con una rapidez constante de 50 km/h. Cual es la fuerza neta necesaria para mantener al automovil moviendose en la curva circular
Answer:
Fc = 4340,93 Newton
Explanation:
Dados los siguientes datos;
Masa = 900 kg
Velocidad, V = 50 km/h a metros por segundo = (50 * 1000)/(60 * 60) = 50000/3600 = 13,89 m/s
Radio, r = 40 m
Para encontrar la fuerza centrípeta;
Fc = mv² / r
Fc = (900 * 13,89²)/40
Fc = (900 * 192,93)/40
Fc = 173637/40
Fc = 4340,93 Newton
If Emily throws the ball at an angle of 30∘ below the horizontal with a speed of 14m/s, how far from the base of the dorm should Allison stand to catch the ball? Assume the vertical distance between where Emily releases the ball and Allison catches it is 4.0m.
Emily throws the ball at 30 degree below the horizontal
so here the speed is 14 m/s and hence we will find its horizontal and vertical components
v_x = 14 cos30 = 12.12 m/sv
x
=14cos30=12.12m/s
v_y = 14 sin30 = 7 m/sv
y
=14sin30=7m/s
vertical distance between them
\delta y = 4 mδy=4m
now we will use kinematics in order to find the time taken by the ball to reach at Allison
\delat y = v_y *t + \frac{1}{2} at^2\delaty=v
y
∗t+
2
1
at
2
here acceleration is due to gravity
a = 9.8 m/s^2a=9.8m/s
2
now we will have
4 = 7 * t + \frac{1}{2}*9.8 * t^24=7∗t+
2
1
∗9.8∗t
2
now solving above quadratic equation we have
t = 0.44 st=0.44s
now in order to find the horizontal distance where ball will fall is given as
d = v_x * td=v
x
∗t
here it shows that horizontal motion is uniform motion and it is not accelerated so we can use distance = speed * time
d = 12.12 * 0.44 = 5.33 md=12.12∗0.44=5.33m
d+x 8. A wire of 2 mm cross-sectional area and 10.3 cm long contains 2x1020 electrons. It has a 10 2 resistance. What is the drift velocity of the charges in the wire when 5 Volts battery is applied a
The drift velocity v will give us the answer.
\(v = (5 V) / ((2x10^20 electrons/m³) * (2x10^-6 m²) * (1.6x10^-19 C))\)
\(v = (5 V) / (4x10^-14 m³) * (1.6x10^-19 C)?\)To find the drift velocity of charges in the wire, we can use Ohm's Law, which states that the current flowing through a conductor is directly proportional to the applied voltage and inversely proportional to the resistance. The equation for Ohm's Law is:
I = V / R
Where:
I is the current flowing through the wire,
V is the applied voltage (in this case, 5 Volts),
R is the resistance of the wire (given as 10^2 Ohms).
Now, we need to calculate the current flowing through the wire using Ohm's Law. The current is the rate at which charges (electrons) move through the wire. The equation for current is:
I = n * A * v * q
Where:
n is the number of charges per unit volume (given as 2x10^20 electrons),
A is the cross-sectional area of the wire (given as 2 mm² or 2x10^-6 m²),
v is the drift velocity of the charges (what we need to find),
q is the charge of each electron (1.6x10^-19 C).
Rearranging the equation and solving for v, we have:
v = I / (n * A * q)
Substituting the given values:
v = (5 V) / ((2x10^20 electrons/m³) * (2x10^-6 m²) * (1.6x10^-19 C))
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Weathering is the breaking down of rock. Erosion is the wearing away of rock so that it is moved from its original location. Which parts of your experimental investigation modeled the weathering of rock by water? Which parts modeled the erosion of rock by water? What kinds of weathering did you model? (5 points)
The parts of an experimental investigation that model the weathering of rock by water would involve observing changes in the rocks due to exposure to water, while the parts that model the erosion of rock by water would involve observing how water moves rocks from one location to another.
What is an experimental investigation?In order to gather data to support or disprove a causal relationship, experimental investigations entail a process in which a "fair test" is designed and variables are actively manipulated, controlled, and measured. A control group is used in experimental studies that receives no treatment.
Here, the weathering of rock by water can be modeled by exposing rocks to water and observing how they change over time. For example, if you were to place rocks in a container of water and leave them for a few days or weeks, you might observe changes in the rocks due to the effects of water. These changes could include physical weathering etc.
For erosion of rock by water, this can be modeled by observing how water moves rocks from one location to another. For example, if you were to create a miniature stream by running water over a surface with rocks, you could observe how the water moves the rocks downstream and changes their location. This process can also cause physical and chemical weathering.
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1. What physical benefits can a person gain from playing floor hockey?
Answer:
strengthens ur muscles
Acceleration on Earth at sea level is approximately 10 m/s2, what would be the
force of your egg drop package if the mass was 0.56 kg?
The correct answer is 5.6 Newton is the force on the egg .
Using newtons 2 law of motion
force = mass * accelaration
now accelaration =10 m / s^2
mass = 0.56 kg
force = 0.56 * 10
force = 5.6 newton
Newton's second law of motion governs the behavior of objects when all available forces are not balanced. The second law states that an object's acceleration is determined by two variables: the net force acting on the object and the object's mass. The acceleration of an object is proportional to the net force acting on it and inversely proportional to its mass. The acceleration of an object increases as the force acting on it increases. The acceleration of an object decreases as the mass of the object increases.
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I need chapter one section three
A banana has a mass of 1.4 kg. What is its weight, in Newtons?
Answer
given :
m=1.4 kg
r/q = N
N = m(9.8)
= 1.4 kg(9.8)
= 13.72 Newton
Answer:
9.8066500286389 N
Explanation:
a 1200-kg car traveling at a constant 20 m/s drives along a horizontal, circular track with an 800 meter radius of curvature. 800 m a. determine the centripetal acceleration of the car (0.5 m/s2) b. calculate the centripetal force on the car. c. if the centripetal force in part (b) is due to friction, and the car is just about to slide, determine the coefficient of (static) friction between tires and the road. (0.051) d. if you doubled the speed of this car, what coefficient (in part c) would you need now?
a. The centripetal acceleration of the car is 0.5 m/s².
b. The centripetal force on the car is 600 N.
c. The coefficient of static friction between tires and the road is 0.051.
d. The car's speed is doubled, we need a coefficient of static friction of 0.204 to prevent the car from sliding.
a. The formula for the centripetal acceleration of the car is given as below:
ac = v²/r
where ac is the centripetal acceleration,
v is the speed, and
r is the radius of curvature of the circular path.
Substituting the values given in the problem, we get:
ac = (20 m/s)²/800 m = 0.5 m/s²
b. The formula for the centripetal force of the car is given as below:
F = mac
where F is the centripetal force,
m is the mass of the car, and
ac is the centripetal acceleration.
Substituting the values given in the problem, we get:
F = (1200 kg)(0.5 m/s²) = 600 N
c. The formula for the maximum static frictional force is given as below:
\(f_{max}\) = μsN
where \(f_{max}\) is the maximum static frictional force,
μs is the coefficient of static friction, and
N is the normal force acting on the car.
For a car moving in a circular path, the normal force is equal to the weight of the car, which is given by:
N = mg
where m is the mass of the car and g is the acceleration due to gravity (9.8 m/s²).
Substituting the above equations and solving for μs, we get:
\(f_{max}\) = μsN
⇒ μs = \(f_{max}\) / N
Substituting the values given in the problem, we get:
\(f_{max}\) = mac = (1200 kg)(0.5 m/s²) = 600 N and
N = mg = (1200 kg)(9.8 m/s²) = 11760 N
Therefore,μs = 600 N/11760 N = 0.051
d. Doubling the speed of the car will cause the centripetal acceleration to double as well.
The formula for centripetal acceleration is given as:
ac = v²/r,
where ac is the centripetal acceleration,
v is the speed, and
r is the radius of curvature of the circular path.
Substituting the new speed (40 m/s) into this formula, we get:
ac = (40 m/s)²/800 m = 2 m/s²
Therefore, the new centripetal acceleration is 2 m/s².
Using the same formula as in part (c), we can find the new coefficient of static friction.
The maximum static frictional force is still equal to the centripetal force, which is given by:
F = mac = (1200 kg)(2 m/s²) = 2400 N
Therefore,
μs = \(f_{max}\)/N = 2400 N/11760 N = 0.204
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If it takes 20 N to move a box, how much power will be needed to move the box a distance of 5meters in 5 seconds?
Answer:
It will need 20 Watts power to move the box 5 meters in 5 seconds.
Step-by-step explanation:
The power is defined as the work per unit time or the rate of doing work:
W=dL/dt
Where de work L, can be calculated by multiplying the force by the displacement d:
L=F.d
To this example, F and D are known, therefore the work is:
L=20N . 5m=40 Nm
We know that the work is doing within a time of 5 seconds:
W= 40 Nm / 5s = 20 Nm/s = 20 Watts
A velocity-time graph is plotted showing the motion of a car. If the graph is a curved line, it means that
(a) The car started at rest
(b) Acceleration was constant
(c) Velocity is increasing uniformly
(d) Velocity is changing non uniformly
If the velocity time graph is curved, it then means that the velocity is changing non uniformly.
What is the velocity time graph?The velocity time graph is used to describe the changes in the velocity of a body with time. The slope of the graph is known as the acceleration of the motion.
If the velocity time graph is curved, it then means that the velocity is changing non uniformly.
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if the angle the mop handle makes with the horizontal is increased to 65 ∘ , does the work done by the janitor increase, decrease, or stay the same?
If the angle the mop handle makes with the horizontal is increased to 65°, the work done by the janitor will stay the same.
1. The work done by the janitor in cleaning the floor depends on the force applied and the distance over which the force is applied. It is given by the equation: Work = Force × Distance × cos(θ), where θ is the angle between the force and the direction of motion.
2. When the angle the mop handle makes with the horizontal is increased to 65°, the angle between the force applied by the janitor and the direction of motion also increases. However, the cosine of 65° is less than the cosine of 0° (horizontal).
3. Since the cosine of 65° is smaller than the cosine of 0°, the work done by the janitor will remain the same or decrease slightly. This is because the component of the force in the direction of motion decreases as the angle increases.
In summary, when the angle the mop handle makes with the horizontal is increased to 65°, the work done by the janitor will stay the same or decrease slightly.
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express the current i1 going through resistor r1 in terms of the currents i2 and i3 going through resistors r2 and r3. use the direction of the currents as specified in the figure.
To express the current i1 in terms of the currents i2 and i3, we can use Kirchhoff's current law (KCL), which states that the sum of currents entering a node is equal to the sum of currents leaving the node. In this case, the node where i1, i2, and i3 meet is the point of interest.
Based on the direction of the currents specified in the figure, we can write the equation:
i2 + i3 = i1
This equation represents the application of KCL at the node where i1, i2, and i3 are connected. According to KCL, the sum of currents entering the node (i2 and i3) is equal to the sum of currents leaving the node (i1).
Therefore, the expression for the current i1 in terms of i2 and i3 is:
i1 = i2 + i3
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two resistors of resistance 6 ohm and 3 ohm are connected in series and then in parallel .calculate the equivalent series resistance and equivalent parallel resistance.
Answer:
a. RT = 9 Ohms
b. RT = 0.5 Ohms
Explanation:
Let the two resistors be A and B.
Let RT be equivalent resistance.
Given the following data;
Resistor A = 6ohms
Resistor B = 3ohms
a. To find the equivalent series resistance;
RT = RA + RB
RT = 6 + 3
RT = 9 Ohms
b. To find the equivalent parallel resistance;
RT = 1/RA + 1/RB
Substituting into the equation, we have
RT = 1/6 + 1/3
RT = 3/6
RT = 0.5 Ohms
As here the 6 ohm and 3 ohm resistors are first connected in series and then parallel, so we can just find out the equivalent series resistance by the formula of it, which is the individual sum of all resistors (for series) and for parallel combination, the reciprocal of the total resistance is the individual reciprocal sum of all resistors, so if we apply same Formula here for series first, then we will be having :
\({:\implies \quad \sf R_{s}=6+3}\)
\({:\implies \quad \boxed{\bf{R_{s}=9\Omega}}}\)
Now, for parallel combination:
\({:\implies \quad \sf \dfrac{1}{R_{p}}=\dfrac13 +\dfrac16}\)
\({:\implies \quad \sf \dfrac{1}{R_{p}}=\dfrac{2+1}{6}}\)
\({:\implies \quad \sf \dfrac{1}{R_{p}}=\dfrac36}\)
\({:\implies \quad \sf \dfrac{1}{R_{p}}=\dfrac12}\)
\({:\implies \quad \boxed{\bf{R_{p}=2\Omega}}}\)
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https://brainly.com/question/27101567Is gravitational potential energy mechanical energy?
The gravitational energy accelerates the object converting the gravitational potential energy into mechanical energy.
What is Mechanical energy?The combination of the potential and kinetic energy due to the gravitational force of the Earth leads to the formation of mechanical energy. The capacity of an object to draw nearby bodies closer to it is known as gravitational energy.
The gravitational attraction of the object transforms its gravitational potential energy into kinetic energy, converting gravitational energy to mechanical energy.
Any gravitational energy held by an object will be transformed into mechanical energy once it is subjected to an external force or falls freely from a height.
Therefore, The gravitational energy accelerates the object converting the gravitational potential energy into mechanical energy.
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can someone help me please?
Answer:
is this math of science
Explanation:
Which of the following is the correct unit to measure the current in a radio?
Watts
Volts
Amps
Tons
Answer:
watts
Explanation:
Answer:
its a.) watts
Explanation:
The horizontal displacement of a cart attached to the end of a spring is given by the following equation: y=(0.5m) sin (2/s t) determine the acceleration of the cart at time t = 3s.
The acceleration of the cart at time t = 3s in terms of the sine function: a = (-2π²m/s²)sin(6π).
To determine the acceleration of the cart at time t = 3s, we need to find the second derivative of the displacement equation with respect to time (t).
Given the displacement equation: y = (0.5m)sin(2πt/s)
First, let's find the first derivative (velocity):
v = dy/dt = (0.5m)(2π/s)cos(2πt/s)
Next, let's find the second derivative (acceleration):
a = dv/dt = d²y/dt² = (0.5m)(2π/s)(-2π/s)sin(2πt/s)
Substituting t = 3s into the equation:
a = (0.5m)(2π/s)(-2π/s)sin(2π(3)/s)
a = (-2π²m/s²)sin(6π)
Now we have the expression for acceleration at t = 3s. However, since the question does not provide a specific value for the constant m, we cannot calculate the exact numerical value of the acceleration. We can, however, express it in terms of the sine function:
a = (-2π²m/s²)sin(6π)
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The chart lists the masses of four balls that have the same momentum. A 2-column table with 4 rows. The first column labeled Ball Color has entries Green, Red, Yellow, Purple. The second column labeled Mass (kilograms) has entries 0.5, 1.2, 0.9, 1.7. Which correctly compares two of the balls? The green ball has a lower velocity than the purple ball. The red ball has a greater velocity than the purple ball. The yellow ball has a higher velocity than the green ball. The red ball has a greater velocity than the green ball.
Answer: The red ball has a greater velocity than the purple ball
Explanation:
Given the chart :
Ball : Green - - - Red - - - Yellow - - - Purple
Mass : 0.5 - - - - - - 1.2 - - - - - 0.9 - - - - - - 1.7
The four balls have the same momentum
Momentum = mass × velocity
Since momentum is directly proportional to the product of Mass and velocity, and the balls have the same momentum. Therefore the lower the mass of the ball, the higher or greater it's Velocity.
Because if the balls with lower masses have lower Velocities than balls with higher masses, both balls cannot have the same momentum.
Therefore, the only viable option above is, The red ball has a greater velocity than the purple ball, because the red ball has a lower mass than the purple ball
Answer:
B in edg
Explanation:
Hello people ~
It becomes possible to define potential at a point in an electric field because electric field
(a) is a conservative field
(b) is a non-conservative field
(c) is a vector field
(d) obeys principle of superposition
Answer:
It’s called a conservative field.
Explanation:
I think it’s going to be the conservative field because in the question it talks about how it is able to become possible to define potential at a point in an electric field because electric field.
Answer:
It's called conservative field
Explanation:
It's possible to define the potential at any point in an electric field because electric field is conservative field.
Morehow the electric field obeys the law of conservation of charge
which implies
charge can neither be created nor be destroyed.
Option A
A series RLC circuit has a resistance of 20 , a capacitance of 10-2 F, an inductance of 10 H and an applied voltage E(t) = 200 cos 5t Volts. Assuming no initial current and charge when voltage is first applied, find the subsequent current in the system.
The subsequent current in the series RLC circuit is given by the equation: i(t) = I * cos(5t - Φ), where I is the amplitude of the current and Φ is the phase angle.
To find the subsequent current, we need to calculate the amplitude (I) and the phase angle (Φ) of the current.
First, let's calculate the resonant frequency (ω) of the circuit:
ω = 1 / √(LC) = 1 / √(10 * 10^(-2)) = 1 / √1 = 1 rad/s.
The applied voltage can be written as E(t) = E * cos(ωt), where E is the amplitude of the voltage.
Comparing this with the given voltage E(t) = 200 * cos(5t), we can equate the angular frequencies: ω = 5.
Now, let's find the impedance (Z) of the circuit:
Z = √(R^2 + (Xl - Xc)^2),
where R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance.
R = 20 Ω
Xl = ωL = 1 * 10 = 10 Ω
Xc = 1 / (ωC) = 1 / (5 * 10^(-2)) = 20 Ω
Plugging in these values, we get:
Z = √(20^2 + (10 - 20)^2) = √(400 + 100) = √500 ≈ 22.36 Ω.
The amplitude of the current (I) can be calculated using Ohm's Law:
I = E / Z = 200 / 22.36 ≈ 8.94 A.
The phase angle (Φ) can be found using the relationship between resistance, inductive reactance, and capacitive reactance:
tan(Φ) = (Xl - Xc) / R = (10 - 20) / 20 = -0.5.
Therefore, Φ ≈ -0.464 rad.
The subsequent current in the series RLC circuit is given by i(t) = 8.94 * cos(5t + 0.464) A.
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A 1.00 kg sphere M, suspended by a string from point P, is lifted to a height h. The sphere is released and passes through the lowest point in its swing at a speed of 10.0 meters per second. [Neglect friction.]
a. Calculate the height from which the sphere was released. [Show all work including equation and substitution with units]
b. Compared to the sphere’s speed through the lowest point of its swing when released from h, the sphere’s speed through the lowest point when released from 2h would be
Answer:
(a) h = 5.1 m
(b) v = 14.13 m/s
Explanation:
(a)
We will use the law of conservation of energy. For this situation it states that:
Loss in Potential Energy of Sphere = Gain in Kinetic Energy of the Sphere
mgh = (1/2)mv²
h = v²/2g --------------- equation (1)
where,
h = height = ?
v = speed at lowest point = 10 m/s
g = 9.8 m/s²
Therefore,
h = (10 m/s)²/(2)(9.8 m/s²)
h = 5.1 m
(b)
using the equation (1)
h = v²/2g
v = √2gh
where,
v = velocity = ?
g = 9.8 m/s²
h = height = 2(5.1 m) = 10.2 m
Therefore,
v = √[2(9.8 m/s²)(10.2 m)]
v = 14.13 m/s
The height from which the sphere was released is 5.1 m
When the height is doubled, the speed of the sphere becomes 14.14 m/s.
The given parameters:
Mass of the sphere, m = 1.0 kgSpeed of the sphere, v = 10 m/sThe height from which the sphere was released is calculated as follows;
\(P.E = K.E\\\\mgh = \frac{1}{2}mv^2\\\\gh = \frac{1}{2}v^2\\\\h = \frac{v^2}{2g}\\\\h = \frac{(10)^2}{2(9.8)} \\\\h = 5.1 \ m\)
When the height is doubled, the speed of the sphere becomes;
\(h = \frac{v^2}{2g} \\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2 \times 9.8 \times (2 \times 5.1)} \\\\v = 14.14 \ m/s\)
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what gauge pressure, in pascals, is required to lift a car with a mass of 1200 kg ? express the result of part a in atmospheres.
The pressure to atmospheres, divide the pressure by 101,325 Pa, which is the atmospheric pressure at sea level 116.1 atm.
What is atmospheres?Atmospheres is a measure of atmospheric pressure, defined as the pressure exerted by the weight of air above a given point. It is typically measured with a barometer, a device which measures the pressure of the surrounding air. Atmospheric pressure decreases with increasing altitude and is measured in units of atmospheres (atm). The average atmospheric pressure at sea level is approximately one atmosphere, or 101.3 kilopascals (kPa). The effects of atmospheric pressure can be seen in everyday life, as it affects the boiling point of water, the speed of sound, and the behavior of aircraft.
The pressure required to lift the car is:
P = (1200 kg * 9.8 m/s2) / A
Since the area is unknown, we can calculate the pressure in Pascals.
P = 11,760,000 Pa
To convert the pressure to atmospheres, divide the pressure by 101,325 Pa, which is the atmospheric pressure at sea level:
Atmospheres = 11,760,000 Pa / 101,325 Pa = 116.1 atm
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A spring has a spring constant of 300 N/m. How much force is in thespring if it is stretched 0.25 m?32
Force applied is directly proportional to displacement.
It is given by the formula
\(F=-kx\)Here F is the force , k is the spring constant , x is the displacement.
Substituting the values,
\(F=-300\text{ }\ast0.25\)\(F=-75\text{ N}\)
A firework with a mass of 1.5 kg shoots up into the air with a velocity of 25 m/s. It then explodes. Use this information to work out the total momentum of all the pieces after the firework explodes
Answer:
37.5 kg⋅m/s
Explanation:
p = mv
p = (1.5)(25) = 37.5 kg⋅m/s
Momentum is conserved in all collisions and explosions!
If the wavelength is 7.52m and the speed is 8.99m/s for a series of waves, what is the frequency of the waves?
Answer: 1.195479Hz
I think
Calculate the smallest angle θ at which you would get destructive (phase difference Δϕ = 180°) interference when 550 nm light passes two slits 50μm apart.
The smallest angle at which you would get destructive interference when 550 nm light passes two slits 50 μm apart is 0.32°.
How do we calculate?The condition for destructive interference is gotten by:
Δϕ = 2πΔx/λ = π
where Δx= path difference between the two slits,
λ = wavelength of light,
and Δϕ = phase difference.
λ/2 = Δx sinθ
Here, θ is the angle between the incident light and the line connecting the center of the slits to the point of interest on the screen.
sinθ = (λ/2) / Δx = (550 nm / 2) / (50 μm) = 0.0055
θ = sin⁻¹(0.0055) = 0.32°
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A 3-kilogram ball is accelerated from rest to a speed of 10 m/sec
The result of multiplying a particle's mass by its velocity is the fluctuation in momentum of a ball, which is 30 kg per second. Since momentum has both a magnitude and a direction, it is a vector quantity.
In the actual world, what is momentum?Almost every action that involves motion has momentum. It is an important tenet of physicsFor instance, if a team is moving forward and trying to stop, it will be difficult.
mv - mu, where u = 0 and v = 10 m/s, equals change in momentum. Note that the ball moved from rest, therefore its initial velocity was zero (u = 0).
Momentum change is equal to mv mu, which is 3*10 - 3*0, or 30.
30 kg/s = change in momentum.
What are examples and momentum?Momentum can be compared to the "power" a moving body has, or the amount of force it can exert on another body. For instance, a baseball that is thrown quickly (high velocity) and has a small bulk (big mass) can have the exact same momentum as a bowling ball that is travelling very slowly (low velocity).
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The wavelengths of solar energy that are absorbed by plants in photosynthesis are ________.
The wavelengths of solar energy that are absorbed by plants in photosynthesis are 700 nm to 400 nm.
Solar energy is the most promising, safest, cleanest, and most reliable source of energy.
It is obtained directly from the sun and is converted into thermal energy. Solar energy plays a crucial role in the photosynthesis process.
Through photosynthesis, plants transform solar energy into a form of chemical energy that can be used by all living organisms.
During photosynthesis, thermal energy is used to produce glucose and oxygen.
To sum up, visible light is a form of sunlight that is used for photosynthesis having wavelengths between 700 nm to 400 nm.
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The concorde jet was a supersonic plane created in 1976 to speed transportation across the ocean it traveled at twice the speed of sound shortening a normal seven to eight hour transatlantic trip to three and and a half hours however the concorde still had to fly in the atmospheric conditions as every other plane given this information
In Stratosphere layer the Concorde cruise, the troposphere wouldn't carry the Concorde. The temperature increases with weight in stratosphere.
The stratosphere layer is one of the layers of the atmosphere on Earth. In an upward direction, it is the second layer of the atmosphere. Right under the stratosphere is the lowest layer, the troposphere. The mesosphere is the stratosphere's higher-level neighbour. At mid-latitudes, the stratosphere's bottom is located around 10 kilometres (6.2 miles, or about 33,000 feet) above the surface. A 50 km altitude marks the stratosphere's highest point (31 miles). With latitude and seasonal changes, the height of the lower stratosphere varies. When compared to the poles, the lower boundary of the stratosphere can range from 7 km (4 miles) to 20 km (12 miles), or a height of 65,000 feet, close to the equator.
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Why Concorde jet was not cruise in Troposphere?