Martha is decorating a tree in her backyard with plastic eggs in preparation for easter. she
hangs two eggs side by side so that their centers are 0.40 m apart. martha rubs the eggs
to shine them up and in doing so, places a charge on each egg. the egg on the left
acquires a charge of 6.0 x 106 c while the egg on the right is charged with 4.0 x 10°c.
what is the electric field at a point 0.15 m to the right of the egg on the left?
Answers
The electric field at a point 0.15 m to the right of the egg on the left is: 1.35 x 10⁷ N/C.
To find the electric field at a point 0.15 m to the right of the egg on the left, we can use Coulomb's law. Coulomb's law states that the electric force between two charged objects is proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula for Coulomb's law is:
F = k * (q1 * q2) / r²
Where F is the electric force, k is Coulomb's constant (9.0 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two objects, and r is the distance between them.
In this case, we want to find the electric field at a point 0.15 m to the right of the egg on the left. To do this, we can first find the electric force between the two eggs, and then use that to find the electric field at the desired point.
The electric force between the two eggs can be found using Coulomb's law:
F = k * (q1 * q2) / r²
F = 9.0 x 10⁹ * (6.0 x 10⁻⁶) * (4.0 x 10^-6) / (0.4)²
F = 1.35 x 10⁻² N
Now that we have the electric force, we can find the electric field at the desired point using the formula:
E = F / q_test
Where E is the electric field and q_test is the test charge (assumed to be positive and very small). In this case, we can assume that the test charge is 1.0 x 10^-9 C.
E = F / q_test
E = 1.35 x 10⁻² / (1.0 x 10⁻⁹)
E = 1.35 x 10⁷ N/C
Therefore, the electric field at a point 0.15 m to the right of the egg on the left is 1.35 x 10⁷ N/C. This means that if we were to place a positive test charge of 1.0 x 10⁻⁹ C at that point, it would experience a force of 1.35 x 10⁻² N in the direction of the egg on the left.
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Related Questions
A beam of blue light causes photoelectrons to be emitted from a photoemissive surface. An increase in the intensity of the blue light will cause an increase in the__.
Answers
A beam of blue light causes photoelectrons to be emitted from a photoemissive surface. An increase in the intensity of the blue light will cause an increase in the number of photoelectrons emitted. Therefore, an increase in the intensity of blue light will cause an increase in the light intensity.
What is light? Light is a type of electromagnetic radiation that travels in waves at a velocity of 299,792 kilometers per second (km/s) in a vacuum. It is a form of energy and, like all forms of energy, can be transferred. Light, like other electromagnetic waves, has both electric and magnetic fields that oscillate perpendicularly to one another at right angles.Light has a very important property, which is its intensity. The amount of light that passes through a given area or space per unit time is known as light intensity. It is the amount of light energy that falls on a unit area in a given time. The energy of light, like all energy, can be described in terms of photons.
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Recoil is noticeable if we throw a heavy ball while standing on roller skates. If instead we go through the motions of throwing the ball but hold onto it, our net recoil will be?.
Answers
Answer:
zero
Explanation:
A 30 kg boy stands on rough horizontal ground. The coefficient of
static friction,
us is 0.8. The present static friction between the boy and the ground is
?
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Answer:
0n
Explanation:
PLEASE Help! Physics Question
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Answer:
hundred metre race on sports day started by a gun firing when the gun is fired a pop of smoke comes out of the gunners will you suggest about trigonometry right here is the sound of the explosion before or at it seems of of smoking containers out of the governor ke this answer about something I don't know I am sorry
Where do you think most of the water
will go?
split the same
though the path of little rocks
though the path of big rocka
Answers
thermal energy is transferred between objects only when they have different ______.
Answers
Thermal energy is transferred between objects only when they have different temperatures.
The movement of atoms and molecules within a substance is a form of energy known as thermal energy.
When two objects are in contact, or even in proximity, the atoms and molecules in the hotter object collide with those in the colder object.
Because of these effects, a portion of the kinetic energy from the more sizzling object is moved to the colder object, raising the temperature of the previous and bringing down the temperature of the last option.
A material's thermal conductivity — an estimation of how well it moves heat — decides how rapidly heat is moved between various sorts of materials.
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the crank ab is rotating with a constant angular velocity of 4 rad>s. determine the angular velocity of the connecting rod cd at the instant u = 30.
Answers
Based on the given information, we know that the crank AB is rotating with a constant angular velocity of 4 rad/s. To determine the angular velocity of the connecting rod CD at the instant u = 30, we need to use the equation:
cos(u) = (AB^2 + CD^2 - BC^2) / (2 x AB x CD)
where AB is the length of the crank, CD is the length of the connecting rod, and BC is the distance between the pivot points of AB and CD.
At the instant u = 30, we can calculate the values of AB, CD, and BC using trigonometry. Let's assume that AB = 10 cm, CD = 20 cm, and BC = 15 cm.
cos(30) = (10^2 + 20^2 - 15^2) / (2 x 10 x 20)
cos(30) = 0.825
Now, we can use the equation:
angular velocity of CD = angular velocity of AB x (AB/CD) x sin(u) x (1/cos(u))
angular velocity of CD = 4 rad/s x (10/20) x sin(30) x (1/0.825)
angular velocity of CD = 1.939 rad/s (rounded to three decimal places)
Therefore, the angular velocity of the connecting rod CD at the instant u = 30 is 1.939 rad/s.
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A car goes 15 miles at 45mph, then goes another 15 miles at 30mph. a. How long does the trip take? b. What is the average speed for the whole trip?
Answers
The trip takes a total of 1.5 hours and has an average speed of 40 mph.
To calculate the time taken for each leg of the trip, we can use the formula time = distance/speed.
For the first leg of the trip, the car travels 15 miles at a speed of 45 mph. Using the formula, we find that the time taken for this leg is 15/45 = 0.33 hours.
For the second leg of the trip, the car travels another 15 miles but at a speed of 30 mph. Using the formula, we find that the time taken for this leg is 15/30 = 0.5 hours.
To find the total time for the trip, we add the times for each leg: 0.33 hours + 0.5 hours = 0.83 hours.
To calculate the average speed for the entire trip, we use the formula average speed = total distance/total time. The total distance traveled is 15 miles + 15 miles = 30 miles. The total time taken is 0.83 hours. Plugging these values into the formula, we find that the average speed for the trip is 30/0.83 = 36.14 mph.
Therefore, the trip takes a total of 1.5 hours and has an average speed of 40 mph.
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What is the mass of a baseball that has a kinetic energy of 105 J and is traveling at 10 m/s?
Answers
Answer:
\(\boxed {\boxed {\sf 2.1 \ kilograms}}\)
Explanation:
Kinetic energy is the energy an object possesses due to motion. The formula 1/2 the product of mass and the squared velocity.
\(E_k=\frac{1}{2} mv^2\)
We know the baseball's kinetic energy is 105 Joules. It is also traveling at a velocity of 10 meters per second. `
First, convert the units of Joules to make unit cancellation easier later in the problem. 1 Joule (J) is equal to 1 kilogram square meter per square second (kg*m²/s²). The baseball's kinetic energy of 105 J is equal to 105 kg*m²/s².
Now we know 2 values:
\(E_k= 105 \ kg*m^2/s^2\)\(v= 10 \ m/s\)Substitute these values into the formula.
\(105 \ kg*m^2/s^2= \frac{1}{2} m (10 \ m/s)^2\)
Now we need to solve for m, the mass. Solve the exponent.
(10 m/s)²= 10 m/s * 10 m/s = 100 m²/s²\(105 \ kg *m^2/s^2 = \frac{1}{2} m (100 \ m^2/s^2)\)
Multiply on the right side.
\(105 \ kg *m^2/s^2 = m (\frac{1}{2} * 100 \ m^2/s^2)\)
\(105 \ kg *m^2/s^2 = m (50 \ m^2/s^2)\)
The variable, m, is being multiplied by 50 square meters per square second. The opposite of multiplication is division, so we divide both sides by that value.
\(\frac {105 \ kg *m^2/s^2 }{50 \ m^2/s^2}= \frac{ m (50 \ m^2/s^2)}{50 \ m^2/s^2}\)
\(\frac {105 \ kg *m^2/s^2 }{50 \ m^2/s^2}= m\)
The units of square meter per square second will cancel out.
\(\frac {105 }{50} \ kg= m\)
\(2.1 \ kg=m\)
The mass of the baseball is 2.1 kilograms.
Alistar places a 6.4 kg block on an incline plane that is 23 degrees above the horizontal. The block starts from rest, and in 2.2 seconds, travels 1.4 meters. What is the force of friction on the block?
Answers
fh= 6.4×23
fh=147.2
fv=2.2×1.4
fv=3.08
f=147.2+3.08
f=150.28
The force of friction on the block is 20.798 N.
What is acceleration?Acceleration is the rate at which speed and direction of velocity vary over time. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.
Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Given parameters:
Mass of the block: m = 6.4 kg.
Angle of inclination = 23°
Hence, Magnitude force acting along the motion = mg sin23°
= 6.4 × 9.8 × sin23° N
= 24.51 N.
The block travels 1.4 meters in 2.2 seconds. Acceleration = (2×1.4)/2.2² m/s²
= 0.58 m/s²
Hence, the force of friction on the block is = F - ma
= 24.51 N - 6.4×0.58 N
= 20.798 N
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I need to know what the answer is to this
Answers
I agree with Katelyn's statement
Explanation:Netwon's first law of motion states that an object will remain at rest or in uniform motion except acted upon by an external (unbalanced) force.
When balanced forces are acting on an object in motion, the object maintains its speed and direction.
This means that balanced forces do not change the speed and direction of an object in motion. We can say that the object is in equilibrium. It either remains at rest or in uniform motion.
Therefore, I agree with Katelyn's statement
What is the difference between liquid water and water vapor?
A.) They have different arrangements of atoms in their molecules.
B.) They differ in their number and types of atoms.
C.) They are different states of the same pure substance.
D.) They are different types of chemical compounds.
Answers
Answer:
C
Explanation: Water vapor can turn into liquid water when it cools and Liquid water turns into vapor when it heats
IN order to increase the amount of friction between two surfaces I can make the surfaces more smoothmake one of the surfaces start to movemake the surfaces more rough
Answers
The most effective way to increase the friction between two surfaces is to make them rougher. This can be done by adding more texture or ridges to the surface.
What is friction?Friction is a force that resists the relative motion or tendency of two surfaces in contact. It is caused by irregularities on the surfaces of objects, which interact and cause an opposing force. Friction is necessary for movement and plays an important role in everyday life, as it helps us move around, provides traction, and helps to keep objects from slipping away. Friction is also the force that causes objects to slow down and eventually stop moving.
Making one of the surfaces start to move can also increase friction, as the relative motion between the two surfaces can increase the contact area, which will in turn increase friction. Additionally, making the surfaces more smooth can also increase friction, as a smoother surface can allow for more even contact between the two surfaces, which will also increase friction.
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how would a planet move if the sun suddenly disappeared ?
Answers
Explanation:
The sun gravity keeps the solar system i.e planets in its place and orbits if there is no sun the planets would flying off and It would be complete and utter chaos in our solar system
two friends with mass 60.0 kg and 40.0 kg run directly toward each other with speeds 3.0 m/s and 2.0 m/s respectively. if they hold on to each other after they collide, their combined speed just after the collision will be:
Answers
If they hold on to each other after they collide, their combined speed just after the collision will be 2.6m/s
Collision: What is it?
When two bodies come into close touch with one another, a collision occurs. In this instance, the two bodies quickly exert forces on one another. The collision changes the energy and momentum of the bodies that are interacting.
For a single pair of objects with equal masses. Each ball will leave the collision with the same speed (or less) as it arrived at if we see the collision of two masses in the frame where their centers of mass are at rest.
Final speed will be 3-2 i.e. 1m/s
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ou se trouve l'eau ? read it and get 20 pnts
Answers
Answer:
Water is omnipresent in our environment on a global scale: in the seas, oceans, lakes, rivers, in glaciers and ice floes... but also in the atmosphere (clouds,
Rain, hail, snow, water vapor...). Water is also omnipresent in our environment
Daily: water to drink, to cook, to wash...
Which of the following phrases does not correctly describe BOTH bulimia nervosa and binge eating disorder?
•Involves episodes of overeating
•Can have severe health consequences
•Serious medical condition
•Symptoms include purging
Answers
The correct answer is Symptoms include purging
Explanation:
Both bulimia nervosa and binge eating disorder are medical conditions categorized as eating disorders. In this patients have unhealthy eating habits that can lead to severe consequences. In the case of bulimia, people go through episodes of excessive eating (binge eating) and these are followed by purging, which includes excessive exercise, inducing vomit, among others as people regret binge eating and want to avoid gaining weight. Similarly, in binge eating disorder people goes through an episode of excessive eating but these are not followed by purging. Indeed, purging is not considered a symptom of this condition.
A string under a tension of 170 N has a frequency of 300 Hz.What will its frequency become if the tension is increased to 340 N?
Answers
The speed of the wave on a string is given by Taylor's formula:
\(v=\sqrt[]{\frac{F}{\mu}}\)where
F = tension force
μ = linear density = mass per unit length
But also we can say the speed of any wave is given by:
\(v=\lambda\times f\)where:
λ = wave length
f = frequency
Plug the second equation in the first one. We get:
\(\lambda\times f=\sqrt[]{\frac{F}{\mu}}\)Now solve for f:
\(f=\frac{1}{\lambda}\times\sqrt[]{\frac{F}{\mu}}\)Lets say wave length is the same on the second case. Since it's the same string μ will also be the same.
See that 340 N = 2 x 170, so we can write:
\(\begin{gathered} f_{new}=\sqrt[]{2}\times\frac{1}{\lambda}\sqrt[]{\frac{F}{\mu}} \\ f_{new}=\sqrt[]{2}\times f_{old} \\ f_{new}=\sqrt[]{2}\times300 \\ f_{new}\approx424Hz \end{gathered}\)Please help! Will give brainliest. 10 points. Show work!
Answers
Answer:
421.83 m.
Explanation:
The following data were obtained from the question:
Height (h) = 396.9 m
Initial velocity (u) = 46.87 m/s
Horizontal distance (s) =...?
First, we shall determine the time taken for the ball to get to the ground.
This can be calculated by doing the following:
t = √(2h/g)
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 396.9 m
Time (t) =.?
t = √(2h/g)
t = √(2 x 396.9 / 9.8)
t = √81
t = 9 secs.
Therefore, it took 9 secs fir the ball to get to the ground.
Finally, we shall determine the horizontal distance travelled by the ball as illustrated below:
Time (t) = 9 secs.
Initial velocity (u) = 46.87 m/s
Horizontal distance (s) =...?
s = ut
s = 46.87 x 9
s = 421.83 m
Therefore, the horizontal distance travelled by the ball is 421.83 m
if a snail moves 6.5in/min, how many miles per hour does the snail travel?
Answers
Answer:
Unit Conversion
6.5in/min× 1ft/12in× 1 mile/5280ft= 0.001231 m/min0.001231 m/min× 60 min/1hr= 0.0738 miles/hrA car starts from a spotlight and is traveling with a velocity of 10 m/s Ein
20 seconds. What is the acceleration of the car?
Answers
Answer:
ANSWER
Initial Velocity (u) = 10 m/sec
Acceleration (a) = 5 m/sec
2
Distance (s) = 30 m
Final velocity (v) = ??
Using Newton's Third law of Motion,
v
2
=u
2
+2as
v
2
=10
2
+2×5×30
v
2
=100+300
v
2
=400
v =
400
v = 20 m/sec
_____________________________
ANSWER =
FINAL VELOCITY = 20 m/sec
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what is the rate at which the current though a 0.478-h coil is changing if an emf of 0.157 v is induced across the coil?
Answers
The rate at which the current though a 0.478-h coil is changing if an emf of 0.157 v is induced across the coil is 0.329 A/s.
According to Faraday's law of electromagnetic induction, a voltage is induced across a conductor that is exposed to a changing magnetic field. The magnitude of the induced emf is directly proportional to the rate of change of the magnetic field. The equation for this relationship is:ε = -N(dΦ/dt), where ε is the induced emf, N is the number of turns in the coil, and (dΦ/dt) is the rate of change of the magnetic flux through the coil.
In this case, the induced emf is given as 0.157 V. The number of turns in the coil is not given, but it is not necessary to know it in order to find the rate of change of the current. Therefore, the equation can be rewritten as:(dI/dt) = ε / L, where L is the inductance of the coil.
Substituting the given values gives:(dI/dt) = 0.157 / 0.478 = 0.329 A/s
Therefore, the rate at which the current through the 0.478 H coil is changing is 0.329 A/s.
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Calculate (in MeV) the binding energy per nucleon for 14N.
Calculate (in MeV) the binding energy per nucleon for 56Fe.
Calculate (in MeV) the binding energy per nucleon for 207Pb.
Answers
The binding energy per nucleon for ¹⁴N is 7.48 MeV.
The binding energy per nucleon for ⁵⁶Fe is 8.79 MeV.
The binding energy per nucleon for ²⁰⁷Pb is 7.87 MeV.
The formula to calculate the mass defect for \(^A_Z X\)
ΔM = (Z × mp) + (N × mn) - m
mp = mass of proton = 1.007825 umn = mass of neutron = 1.008665 um = mass of an atomic nucleusTo calculate the binding energy per nucleon
BE = (ΔM × 931.5 MeV) ÷ A
For \(^{14}_7 N\)
A = 14Z = 7N = A - Z = 14 - 7 = 7mass of nitrogen nucleus = 14.00307 uThe mass defectΔM = (Z × mp) + (N × mn) - m
ΔM = (7 × 1.007825) + (7 × 1.008665) - 14.00307
ΔM = 7.054775 + 7.060655 - 14.00307
ΔM = 0.11236 amuThe binding energy per-nucleon
BE = (ΔM × 931.5 MeV) ÷ A
BE = (0.11236 × 931.5 MeV) ÷ 14
BE = 104.66334 ÷ 14
BE = 7.48 MeV
For \(^{56}_{26} Fe\)
A = 56Z = 26N = A - Z = 56 - 26 = 30mass of iron nucleus = 55.934939 uThe mass defectΔM = (Z × mp) + (N × mn) - m
ΔM = (26 × 1.007825) + (30 × 1.008665) - 55.934939
ΔM = 26.20345 + 30.25995 - 55.934939
ΔM = 0.528461 amuThe binding energy per-nucleon
BE = (ΔM × 931.5 MeV) ÷ A
BE = (0.528461 × 931.5 MeV) ÷ 56
BE = 492.261 ÷ 56
BE = 8.79 MeV
For \(^{207}_{82} Pb\)
A = 207Z = 82N = A - Z = 207 - 82 = 125mass of lead nucleus = 206.975880 uThe mass defectΔM = (Z × mp) + (N × mn) - m
ΔM = (82 × 1.007825) + (125 × 1.008665) - 206.975880
ΔM = 82.64165 + 126.083125 - 206.975880
ΔM = 1.748895 amuThe binding energy per-nucleon BE = (ΔM × 931.5 MeV) ÷ A
BE = (1.748895 × 931.5 MeV) ÷ 207
BE = 1,629.09 ÷ 207
BE = 7.87 MeV
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How does temperature change from planets to planets in our solar system?
Answers
The further a planet is from the Sun, the colder its surface temperatures tend to be. Venus is an exception, since it has the highest surface temperature in our solar system due to its close closeness to the Sun and its thick atmosphere.
What was the temperature of the solar system when the planets first formed?The inner planets are rocky, whereas the outer planets are gaseous, which can be attributed to the early solar system's temperature. The solar system's temperature increased as the gases came together to create a protosun. Temperatures in the inner solar system reached 2000 K, whilst in the outer solar system, it was only 50 K.
The quantity of heat received is just one of many intricate aspects that go into determining the temperature.
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PLEASE HELP!! Points will be given for suitable answer! Thank you!
Answers
Answer:
its lost 91
Explanation:
What would be the diameter of the earth if it had the density of a neutron star
Answers
Answer:
At neutron star density, the Earth's whole mass would fit inside a 305-meter-diameter sphere.
Explanation:
en la video-conferencia que actividades hay y como podrían ser de utilidad.
Answers
1. how can the school and community help you to stay healthy and be aware of your health status?
2. how can you help yourself to overcome your problems?
Answers
Answer:
1.school and community helps in growth and development of you social health as when u learn how to be compatible with the people around you, you will do better in life
2. by trying and solving
by not giving
by innovating
by being motivated
BY KNOWING THAT U CAN DO IT
A mass is tied to a spring and begins vibrating periodically. The distance between its highest and its lowest position is 38cm. What is the amplitude of the vibrations?
Answers
Given that the distance between the highest and lowest positions is 38 cm, the amplitude can be calculated as:
Amplitude = (Distance between highest and lowest positions) / 2
Amplitude = 38 cm / 2
Amplitude = 19 cm
Therefore, the amplitude of the vibrations is 19 cm.
what must be the magnitude of a uniform electric field if it is to have the same energy density as possessed by a
Answers
The magnitude of a uniform electric field must be equal to the square root of the energy density to have the same energy density as possessed by the field.
The energy density (u) of an electric field is given by the equation:
u = (1/2) * ε0 * E^2
Where ε0 is the permittivity of free space and E is the magnitude of the electric field.
To find the magnitude of the electric field that has the same energy density, we can set the energy densities equal to each other:
u1 = u2
(1/2) * ε0 * E1^2 = (1/2) * ε0 * E2^2
Canceling out the common factors and taking the square root of both sides, we get:
E1 = E2
This means that the magnitude of the electric field (E) must be the same for both fields to have the same energy density.
The magnitude of a uniform electric field must be equal to the square root of the energy density to have the same energy density as possessed by the field.
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