Maltose is the alpha-1,4 glycosidic linkage of 2 glucose molecules. True or False?

Answers

Answer 1

True. Maltose is a disaccharide formed by the alpha-1,4 glycosidic linkage of two glucose molecules. Maltose is a reducing sugar. Thus, its two glucose molecules must be linked in such a way as to leave one anomeric carbon that can open to form an aldehyde group.

The glucose units in maltose are joined in a head-to-tail fashion through an α-linkage from the first carbon atom of one glucose molecule to the fourth carbon atom of the second glucose molecule (that is, an α-1,4-glycosidic linkage; see Figure 14.6.1 The bond from the anomeric carbon of the first monosaccharide unit is directed downward, which is why this is known as an α-glycosidic linkage. The OH group on the anomeric carbon of the second glucose can be in either the α or the β position, as shown in Figure 14.6.1.

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Related Questions

ACELLUS LAB-ACID BASE TITRATION

a student overshot the equivalence point when he was using NaOh to determine the concentration of an unknown acid, HA. What ions are present in the purple solution in the flask?

Answers

Answer: A-, NA+ And OH-

Explanation: Thank me later

Which molecule or ion has a trigonal planar geometry around the bold-faced atom?.

Answers

The molecule has three electron pairs and is trigonal planar geometry. Carbonate ion is found in limestone as calcium carbonate.

Each atom is composed of a nucleus and one or greater electrons sure to the nucleus. The nucleus is product of one or more protons and a number of neutrons. best the maximum common form of hydrogen has no neutrons. An atom is the smallest unit of everyday matter that bureaucracy a chemical detail.

An atom is a particle of depend that uniquely defines a chemical element. An atom includes a relevant nucleus this is surrounded via one or extra negatively charged electrons. The nucleus is definitely charged and contains one or extra pretty heavy debris known as protons and neutrons.

An atom itself is made from 3 tiny types of debris referred to as subatomic particles protons, neutrons, and electrons. The protons and the neutrons make up the center of the atom referred to as the nucleus and the electrons fly around above the nucleus in a small cloud.

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estimate (a) the maximum, and (b) the minimum thermal conductivity values (in w/m-k) for a cermet that contains 77 vol% carbide particles in a metal matrix. assume thermal conductivities of 29 and 64 w/-k for the carbide and metal, respectively.

Answers

Estimated maximum and minimum thermal conductivity values for the cermet are:
Maximum thermal conductivity = 0.77 x 29 + 0.23 x 64 = 35.33 w/m-k
Minimum thermal conductivity = 0.77 x 64 + 0.23 x 29 = 55.27 w/m-k

To estimate the maximum and minimum thermal conductivity values for a cermet containing 77 vol% carbide particles in a metal matrix, we need to use the rule of mixtures.

The rule of mixtures states that the effective thermal conductivity of a composite material can be calculated as a weighted average of the thermal conductivity values of its constituent materials, where the weight is determined by the volume fraction of each material.

In this case, we have a cermet with 77 vol% carbide particles and 23 vol% metal matrix. Using the rule of mixtures, we can estimate the maximum and minimum thermal conductivity values as follows:

(a) Maximum thermal conductivity:

The maximum thermal conductivity of the cermet would occur if all the carbide particles were perfectly aligned and in contact with each other. In this scenario, the thermal conductivity of the cermet would be equal to the thermal conductivity of the carbide particles themselves, which is 29 w/m-k.

(b) Minimum thermal conductivity:

The minimum thermal conductivity of the cermet would occur if all the carbide particles were completely dispersed within the metal matrix, with no contact between them. In this scenario, the thermal conductivity of the cermet would be equal to the thermal conductivity of the metal matrix, which is 64 w/m-k.

Therefore, the estimated maximum and minimum thermal conductivity values for the cermet are:

Maximum thermal conductivity = 0.77 x 29 + 0.23 x 64 = 35.33 w/m-k
Minimum thermal conductivity = 0.77 x 64 + 0.23 x 29 = 55.27 w/m-k

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Calculate the maximum wavelength of light capable of dissociating the f–f bond in one molecule of fluorine if the bond energy, or bond dissociation energy, is 157 kj/mol.

Answers

The calculated maximum wavelength is 495 nm

The energy needed to break a bond and create two atomic or molecular fragments, each containing one of the original shared pair of electrons, is known as the bond dissociation energy. The link between silicon and fluorine, which was previously discussed, is discovered to be the strongest chemical bond. The initial silicon-fluorine bond in a silicon tetrafluoride molecule requires 166 kcal/mol of bond dissociation energy to be broken.

ΔH=+240 kJ/mol

E=242×103/6.022×1023

=4.0186×10−19 J

Now I use the Planck Expression:

E=hf=hc/λ

∴λ=hc

Eλ=6.63×10−34×3×108/4.0186×10-19 m

λ=4.949×10−7 m

λ=495 nm.

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2. A sample of gas has a pressure of 195 kPa and a volume of 3.50 L. If the pressure
is increased to 150 kPa, what is the new volume?

Answers

Answer:

4.55 L

Explanation:

The new volume can be found by using the formula for Boyle's law which is

\(P_1V_1 = P_2V_2\)

Since we're finding the new volume

\(V_2 = \frac{P_1V_1}{P_2} \\\)

We have

\(V_2 = \frac{195000 \times 3.5}{150000} = \frac{682500}{150000} \\ = 4.55\)

We have the final answer as

4.55 L

Hope this helps you

which of the following statements is true? excited electrons do not return to ground state until they move away from the heat of the flame. only one electron can be excited at a time. an electron may fall back to ground state in a single step or in multiple steps. each element emits a single, characteristic wavelength of light during the flame test.

Answers

The statement that is true among the options provided is: "An electron may fall back to the ground state in a single step or in multiple steps."

Higher energy levels are attained by excited electrons in atoms. The extra energy is finally released as light when they reach their ground state, though. The electron may return to its ground state in a single step, emitting a photon with a certain wavelength, or it may do so in several phases, releasing photons with various wavelengths.

The following additional options' statements are untrue:

Without having to leave the heat of the flame, excited electrons can return to the ground state. The flame's heat is what initially excite the electrons, yet the atom can still return to its ground state while it is still in the flame.

The claim that only one electron can be excited at a time is untrue since several electrons can be excited simultaneously.

In a flame test, each element emits a variety of recognizable light wavelengths. The energy differences between the excited states and the ground state of various electrons in the atom are reflected in the specific wavelengths that are emitted.

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electrical double layer design for proton-coupled electron transfer electrode processes: recent advances in well-defined electrode−electrolyte interface

Answers

The article aims to highlight the most recent improvements in the PCET procedures for electrocatalysis at clearly characterized electrodeelectrolyte interfaces.

Aim : Here, we focus on the most recent developments in the PCET methods for electrocatalysis at clearly defined electrodeelectrolyte interfaces.

Method: Since the groundbreaking and ongoing studies made by Frumkin and his colleagues initiated in the 1930s, non-covalent interaction, which is controlled by the cation/anion features, is known to play a crucial role in the interfacial water and adsorbate environments correlated to electrodeelectrolyte catalytic properties.

The microscopic perspective of this interaction is still a significant scientific mystery, nevertheless. Recent research based on the well-defined surface and solid-liquid interfacial structure of single-crystal model electrodes revealed novel characteristics of the cation effect.

Practical usage: Designing high-performance electrode and electrolyte materials requires an understanding of the roles played by the electrical double layer (EDL) structure in proton-coupled electron transfer (PCET) electrode processes.

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Can frozen ice transfer thermal energy to another substance? if so, how?

Answers

Answer:

Matter can change state when thermal energy is transferred into or out of the substance. Ice melts and liquid water boils as thermal energy is added. Water vapor condenses and liquid water freezes as thermal energy is removed.

21.) This substance consists of two or more nonmetal elements in a fixed ratio.

a.) element
b.) mixture
c.) molecule
d.) compound

Answers

Answer:

Molecule

Explanation:

when two or more than two non-metal elements are combined then it form Molecule.

Please help
Science....
Thanks

Answers

Answer:

docx it is a science document

you have a lead ball with a mass of 420 g. the density of lead is 10.5 g/cm³. what is the volume of the ball

Answers

Answer:

The answer is

40.0 mL

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \)

From the question

mass = 420 g

density = 10.5 g/cm³

The volume is

\(volume = \frac{420}{10.5} \\ \)

We have the final answer as

40.0 mL

Hope this helps you

An element is a pure substance composed of only one kind of atom A compound is a pure substance made of atoms of a different elements combined in definite proportions Once separated, is each component of the solid mixture a pure element or a pure compound

Answers

Answer:

a pure compound because mixtures are formed from two or more compounds.

How does the law conservation of matter apply to machines

Answers

The Law of Conservation of Matter says that the amount of matter stays the same, even when matter changes form. ... Another way to explain the law of conservation of matter is to say that things cannot be magically created or destroyed. Please mark brainliest?

describes the
unbalanced attractive force
toward the interior of the liquid
that molecules experience at the
air-liquid interface.
A. Vapor pressure
B. Surface tension
D. Condensation
C. Boiling point

describes theunbalanced attractive forcetoward the interior of the liquidthat molecules experience at

Answers

Answer: B. Surface Tension

Explanation:

It is the tension of the surface film of a liquid caused by the attraction of the particles in the surface layer by the bulk of the liquid, which tends to minimize surface area.

How many grams of Hydronium chromate are produced when 43.4 g of Tin (IV) chromate combines with35.2 g of Hydronium hydrogen phosphate? Use the following balanced equation:2 (H3O)2HPOA + 1 Sn(CrO4)2 ---> 2 (H30)2CrOA + 1 Sm(HPOA)2

How many grams of Hydronium chromate are produced when 43.4 g of Tin (IV) chromate combines with35.2

Answers

Answer

Mass of (H30)2CrO = 38 g

Explanation

Given:

Mass of Sn(CrO4)2 = 43.4 g

Mass of (H3O)2HPO4 = 35.2 g

Required: The mass of (H30)2CrO4 that will be produced

Solution:

Calculate the possible mass that could be produced by each reactant, so as to determine the limiting reagent. Use stoichiometry.

For Sn(CrO4)2:

\(\begin{gathered} 43.4\text{ g Sn\lparen CrO}_4\text{\rparen}_2\text{ x }\frac{1\text{ mole Sn\lparen CrO}_4)_2}{350.70\text{ g Sn\lparen CrO}_4)_2}\text{ x }\frac{2\text{ mole \lparen H}_3\text{0\rparen}_2\text{CrO}_4}{1\text{ mole Sn\lparen CrO}_4)_2}\text{ x }\frac{153.9\text{ g \lparen H}_3O)_2CrO_4}{1\text{ mol \lparen H}_3O)_2CrO_4} \\ \\ =\text{ 38 g \lparen H}_3\text{O\rparen}_2\text{CrO}_4 \end{gathered}\)

For (H3O)2HPO4

\(\begin{gathered} 35.2\text{ g \lparen H}_3\text{O\rparen}_2\text{HPO}_4\text{ x }\frac{1\text{ mole \lparen H}_3\text{O\rparen}_2\text{HPO}_4\text{ }}{133.97\text{ g }(H_3O)_2HPO_4}\text{ x }\frac{2\text{ mole}}{2\text{ mole}}\text{ x }\frac{153.9\text{ g \lparen H}_3\text{O\rparen}_2\text{CrO}_4}{1\text{ mole \lparen H}_3\text{O\rparen}_2\text{CrO}_4} \\ \\ =\text{ 40.43 g \lparen H}_3\text{O\rparen}_2\text{CrO}_4 \end{gathered}\)

Sn(CrO4)2 will produce less (H30)2CrO4 therefore, Sn(CrO4)2 is the limiting reagent.

For the reaction 2Na + Cl2 -> 2NaCl, calculate the percent yield if 200. g of chlorine reacts with excess sodium to produce 240. g of sodium chloride.

Answers

The percent yield of the reaction 2Na + Cl2 -> 2NaCl, where 200 g of chlorine reacts with excess sodium to produce 240 g of sodium chloride, is approximately 64.2%.

To calculate the percent yield, we first need to determine the theoretical yield of sodium chloride (NaCl) from the given amount of chlorine (Cl2). Then, we will compare the theoretical yield to the actual yield, which is the amount of NaCl produced in the reaction.

1. Calculate the moles of Cl2:
Moles of Cl2 = mass of Cl2 / molar mass of Cl2
Moles of Cl2 = 200 g / (35.45 g/mol * 2) = 2.82 mol

2. Determine the moles of NaCl produced based on the balanced equation:
2Na + Cl2 -> 2NaCl
Moles of NaCl = moles of Cl2 * 2 = 2.82 mol * 2 = 5.64 mol

3. Calculate the theoretical yield of NaCl:
Theoretical yield of NaCl = moles of NaCl * molar mass of NaCl
Theoretical yield of NaCl = 5.64 mol * 58.44 g/mol = 329.54 g

4. Calculate the percent yield:
Percent yield = (actual yield / theoretical yield) * 100
Percent yield = (240 g / 329.54 g) * 100 ≈ 64.2%

Therefore, the percent yield for this reaction is approximately 64.2%.

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What is the density of a 234 g sample with a volume of 22 mL?

Answers

Answer: 10.63

Explanation: You divide the mass by volume.

Answer:

10.64g/cm³

Explanation:

1cm³ = 1ml

22 × 1cm³ = 22cm³

Density = Mass ÷ Volume

234 ÷ 22

Density = 10.64g/cm³ or 10640kg/

How are reflecting telescopes different from refracting telescopes?

Answers

Reflecting telescopes are preferred for scientific research because they are better suited for gathering large amounts of light and producing high-quality images. However, refracting telescopes are still popular for amateur astronomers and for viewing objects on Earth.

Reflecting telescopes are different from refracting telescopes because reflecting telescopes use mirrors, whereas refracting telescopes use lenses. The reflecting telescope was invented in 1668 by Sir Isaac Newton, and it has since become one of the most popular types of telescopes.
Reflecting telescopes use a mirror to gather and focus light, while refracting telescopes use a lens to do the same thing. Reflecting telescopes can be made much larger than refracting telescopes because it is easier to make large mirrors than it is to make large lenses. The mirror in a reflecting telescope is placed at the back of the telescope, and it gathers and reflects light back to a secondary mirror, which then reflects the light to the eyepiece. The eyepiece is where the observer looks through the telescope.In contrast, the lens in a refracting telescope is placed at the front of the telescope, and it gathers and bends light as it passes through. The lens focuses the light onto an eyepiece at the back of the telescope. Refracting telescopes are generally smaller than reflecting telescopes because of the difficulty of making large lenses.
Another difference between reflecting and refracting telescopes is the way they are constructed. Reflecting telescopes have a simple tube that houses the mirrors and eyepiece, while refracting telescopes have a more complex design with a long tube that contains the lens and eyepiece.

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How does a mixed inhibitor that has a higher affinity for the enzyme compared to the substrate affect the Michaelis-Menten constant (Km) in enzyme kinetics?

Answers

A mixed inhibitor that has a higher affinity for the enzyme compared to the substrate can affect the Michaelis-Menten constant (Km) in enzyme kinetics by increasing the value of Km.

Km is a measure of the substrate concentration required for half-maximal velocity and is a key parameter in describing enzyme catalysis. However, In the presence of a mixed inhibitor, the inhibitor molecule can bind to both the free enzyme and the enzyme-substrate complex with different affinities.

The binding of the inhibitor to the free enzyme reduces the number of active enzyme molecules available for catalysis while binding to the enzyme-substrate complex slows down the catalytic reaction. This leads to a reduction in the effective concentration of the enzyme-substrate complex, which in turn increases the apparent Km value.

In other words, the higher affinity of the mixed inhibitor for the enzyme reduces the efficiency of the enzyme-substrate complex formation, making it more difficult for the substrate to bind to the enzyme, hence increasing the value of Km. Therefore, a mixed inhibitor that has a higher affinity for the enzyme compared to the substrate can cause a decrease in the efficiency of enzyme catalysis, which is reflected in the increase in Km.

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which statement about atoms is correct
A atoms contain protons and electrons in the nucleus
B Neutrons are negatively charged
c protons are positively charged
D the nucleon number is the number of neutrons

Answers

Answer:Protons are positively charged is the correct statement about an atom

I've also corrected the other statements

Atoms contain protons and neutrons in their nucleus

Neutrons posses no charge and are neutral

The nucleon number is the total number of protons and neutrons in a nucleus

Sam believes the rock is more denser than the pencil. He measured the mass of the rock to be 8.5 grams and volume to be 4.5mL. He measured the mass of the pencil to be 2.4 grams and volume to be 4.5mL. Density is the mass per unit volume of an object. When he put the rock and pencil into the water, the pencil floated and the rock sank. Which is more denser? Give your reasoning using actual density values.

Answers

Answer:

Rock

Explanation:

Let's calculate the density of each object:

Rock:

\(Density = \frac{mass}{volume}=\frac{8.5\ g}{4.5\ mL}=1.9\ g/mL\)

Pencil:

\(Density = \frac{mass}{volume}=\frac{2.4\ g}{4.5\ mL}=0.53\ g/mL\)

Therefore the rock is denser.

What might have happened if the president had waited for Congress to draft a law making it illegal for defense industry businesses to discriminate based on race or color

Answers

Answer:

In June of 1941, President Roosevelt issued Executive Order 8802, banning discriminatory employment practices by Federal agencies and all unions and companies engaged in war-related work. The order also established the Fair Employment Practices Commission to enforce the new policy.

Explanation:

Executive Order 8802 helped to establish the foundation for Title VII of the 1964 Civil Rights Act and Executive Order 11246 in 1965. This Order prohibited all forms of discrimination in employment and public facilities. Executive Order 8802 lead to future orders that abolished discrimination in public facilities.

Please help ASAP! PLEASE DO NOT GIVE ME A RANDOM GIBBERISH ANSWER OR ELSE I WILL REPORT YOU AND GIVE YOU A LOW RATING!!!

If you're unsure of the answer just type it in the comments.

QUESTIONS:

QUESTION 1:
If the mass and volume of an object is very HIGH will the object sink or float?

QUESTION 2:
If the mass and volume of an object if very LOW will the object sink or float?

Please answer this as soon as possible, as these questions need to be done right now!

Answers

Answer:

if an object weighs more than an equal volume of water, it is more dense and will sink, and if it weighs less than an equal volume of water, it is less dense and will float.

Explanation:

Hope that helps

If I have an object with a density of 2.42 g/mL and a mass of 27 g, what is the volume, in mL ?

Answers

55ml is the volume in ml, answer is a

How would you describe the appearance of homogeneous mixture? A. Homogeneous mixtures do not have a uniform composition. B. Homogeneous mixtures have a uniform appearance. C. Homogeneous mixtures are not distributed evenly. D. Homogeneous mixtures have two phases

Answers

Answer:

i think its c somebody correct me if im wrong. but hope this help

Explanation:

Given the reaction:
Ca + 2H,0→ Ca(OH)) + H2
How many moles of H,O are needed to exactly react with
2.0 moles of Ca

Answers

Answer:

4

Explanation:

because use the molar ratio of

ca:h2o

1:2

2;4

so u times it by 2 .

hope this helps:)

describe the main diffrence between the bohr model of the atom and the rutherford model

Answers

Answer:

Bohr thought that electrons orbited the nucleus in quantised orbits. ... In Rutherford's model most of the atom's mass is concentrated into the centre (what we now call the nucleus) and electrons surround the positive mass in something like a cloud. Bohr's most significant contribution was the quantisation of the model.

Explanation:

How would an increase in temperature affect evaporation?

F) it would end evaporation
G) it would speed up evaporation
H) it would slow down evaporation
J) temperature does not affect evaporation

Answers

Answer:

G) It would speed up evaporation.

Explanation:

As the temperature increases, the rate of evaporation also increases.

JUST 43 PLEASE

Consider a solution contains both c5h5n and c5h5nhno3. Calculate the ratio [c5h5n]/[c5h5nhno3+] if the solution has the following pH values

JUST 43 PLEASEConsider a solution contains both c5h5n and c5h5nhno3. Calculate the ratio [c5h5n]/[c5h5nhno3+]

Answers

The ratio for [C\(_5\)H\(_5\)N]/[C\(_5\)H\(_5\)NH⁺] if the solution has the following pH values 4.50 is 6.30.

What is buffer?

A buffer is indeed a solution that resists pH fluctuations and contains either a weak acid as well as its salt or perhaps a weak base as well as its salt. To put it another way, a buffer is indeed an aqueous solution that includes a weak base as well as its conjugate acid, or a weak acid as well as its conjugate base.

A buffer may also be referred to as a buffer solution, hydrogen ion buffer, and pH buffer.

pOH =PKb+log[salt]/[base]

pOH =14-pH= 14-4.50=9.5

pKb= -logKb

     =-log(1.7×10⁻⁷)

     =8.7

9.5 =8.7+log[salt]/[base]

9.5 -8.7=log[salt]/[base]

0.8=log[salt]/[base]

[salt]/[base] =10^0.8=6.30

[C\(_5\)H\(_5\)N]/[C\(_5\)H\(_5\)NH⁺]=6.30

Therefore, 6.30 is the value for [C\(_5\)H\(_5\)N]/[C\(_5\)H\(_5\)NH⁺].

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a scientist wants to test how much of a base can be added to a solution before the ph of a solution cahgnes

Answers

The scientist can conduct an experiment to determine the amount of base that can be added to a solution before the pH changes.

Here's a step-by-step approach:
1. Prepare a solution with a known pH.
2. Add a small amount of base to the solution and measure the pH using a pH meter.
3. Gradually increase the amount of base added while recording the pH at each step.
4. Observe the point at which the pH starts to change significantly.
5. Repeat the experiment multiple times to ensure accuracy and consistency.
6. Calculate the average amount of base required to cause a noticeable change in pH.
7. This average value will indicate the approximate amount of base that can be added before the pH changes significantly.


For example, if the scientist starts with a solution of pH 7 and notices a significant pH change when 10 mL of base is added, then they can conclude that around 10 mL of base is the threshold before the pH changes.
Remember, the experiment can be repeated with different solutions or bases to gather more data and ensure reliable results. The scientist should also consider using appropriate safety measures and equipment during the experiment.
Overall, this experiment will help the scientist understand the relationship between the amount of base added and the resulting pH change in a solution.


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