making new compunds for high-speed tires is best done by the
A. physical chemist
B. organic chemist
C. inorganic chemist
D. biochemist

Answer:

First, convert Liters to grams. Then convert grams to moles

Explanation:

The concentration (m) of ch3oh in a solution prepared by dissolving 34.4 g of ch3oh in sufficient water to give exactly 230 ml of solution is 1.59 m

The concentration of ch3oh can be calculated using the formula:Concentration (m) = (number of moles of solute) / (volume of solution in liters)

Given: Mass of ch3oh = 34.4 g

Volume of solution = 230 mL

= 0.230 L

To calculate the concentration of ch3oh in molarity:Convert mass of ch3oh to moles

.The molar mass of ch3oh is 32.04 g/mol.Number of moles of

= Mass of ch3oh / Molar mass of ch3oh

= 34.4 g / 32.04 g/mol

= 1.074 mol

Calculate the concentration of ch3oh.

Concentration (m) = Number of moles of ch3oh / Volume of solution in liters

= 1.074 mol / 0.230 L

= 4.67 M

Thus, the concentration (m) of ch3oh in a solution prepared by dissolving 34.4 g of ch3oh in sufficient water to give exactly 230 ml of solution is 4.67 m.

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The answer is Solution!

Explanation:

Solution is a homogeneous mixture

of two or more substance. In a

sugar solution, sugar gets uniformly

mixed with water

Answer:

190

Explanation:

Gold has atomic number of 79, which is the number of protons.

Mass number = #protons + #neutrons = 79 + 111 = 190

The pressure of BrCl produced in the reaction, when transferred to a 2.65 L flask and cooled to 37 °C, is approximately 0.151 atm.

To calculate the pressure of the BrCl produced in the reaction, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature. The combined gas law equation is given as:

(P_1 * V_1) / (T_1) = (P_2 * V_2) / (T_2)

Given:

Initial pressure (P_1) = 1.83 atm

Initial volume (V_1) = 281 ml = 0.281 L

Initial temperature (T_1) = 129 °C = 402 K

Final volume (V_2) = 2.65 L

Final temperature (T_2) = 37 °C = 310 K

Using the combined gas law equation, we can rearrange it to solve for the final pressure (P_2):

P_2 = (P_1 * V_1 * T_2) / (V_2 * T_1)

Substituting the given values into the equation, we get:

P_2 = (1.83 atm * 0.281 L * 310 K) / (2.65 L * 402 K)

P_2 ≈ 0.151 atm

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The pH of a 0.10 M solution of carbonic acid is 3.12.

To calculate the pH of a solution, we use the equation pH = -log[H+], where [H+] is the concentration of hydrogen ions in the solution. In the case of carbonic acid, the dissociation equation is:

H2CO3 → H+ + HCO3-

The concentration of hydrogen ions in the solution is equal to the concentration of carbonic acid, which is 0.10 M. Plugging this value into the equation for pH, we get:

pH = -log[0.10]

pH = 3.12

Therefore, the pH of a 0.10 M solution of carbonic acid is 3.12.

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Answer:

\(4m^2\)

Explanation:

Multiply \(m\) by \(m\), by adding the exponents

21) The correct description of the compounds are options a b c.

14) The correct chemical names are b c d

11) Li forms an ionic compound with fluorine

4) The ending of name (c) would differentiate the two compounds.

The functional group on the chain is carboxyl (a)

We know that the structure of the compound would have to do with the way that the compound can be written. In this case, we have the compound that have been shown and then we have some statements about the molecules.

We must note that the structures show us how the atoms that are in the compounds can be arranged and then we can be able to deduce the structure of the molecule that has been shown.

The compound on the right hand side is a cyclic compound while the compound on the left hand side is a long chain compound. We can now be able to count up the number of the hydrogen and the carbon atoms that are present in each of the compounds.

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The reaction of Mg and oxygen (in the air, we have oxygen) is the following:

If we use carbon dioxide (CO2) to react with magnesium oxide (MgO), we can see that this compound would continue to burn. This is because the reactivity series of Mg is above the reactivity of carbon and this compound can take the oxygen from carbon dioxide to react.

Answer:

Explanation:

When two substances at different temperatures like into contact, the substance that is at higher temperature will transfer energy, in the form of heat, to the substance that is at lower temperature, until their temperatures get equal.

In this case, if the two substances are isolated of the rest of the universe, the law of conservation of energy states that the heat released by the substance initially at higher temperature is the same amount of heat gained by the substance originally at lower temperature.

According to law of conservation of mass and stoichiometry, 602.25 g of silver bromide is also produced when 206 g of cobalt (III) nitrate is produced.

It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.As there are 808.25 g of reactants in balanced chemical equation and mass of  cobalt (III) nitrate is 206 g thus, 808.25-206=602.25 g of silver bromide is also produced .

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Based on the "like dissolves like" rule, iodine (I₂) is the solid that is most likely soluble in hexane (C6H14).

The "like dissolves like" rule suggests that substances with similar polarities tend to dissolve in each other. Hexane (C6H14) is a nonpolar solvent, so it will likely dissolve substances that are also nonpolar or have low polarity.

Among the given solids:

Iodine (I₂) is a nonpolar molecule composed of nonpolar covalent bonds. It is expected to be soluble in hexane due to its nonpolar nature.

Potassium iodide (KI) is an ionic compound composed of K⁺ and I⁻ ions. It has high polarity and is more likely to be soluble in polar solvents rather than nonpolar hexane. Therefore, it is not expected to be soluble in hexane.

Potassium iodate (KIO₃), potassium periodate (KIO₄), and potassium iodite (KIO₂) are also ionic compounds and have high polarity. They are not expected to be soluble in nonpolar hexane.

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Answer:

The average for the first row: 18.67

The average for the second row: 32

Explanation:

It's easy to find the average. Add all the numbers than divide it by the total number of values in the set.

Example: 12, 8, 2, 6

Add all the numbers and you get 28. Then divide 28 by four because there is 4 numbers you added (you added 12, 8, 2, and 6). So you get 7, and that's the average!

Answer:

WHAT HE SAID GIVE ME BRAINLIEST OR ILL TURN YOU BED OVER AND S*IT ON IT SOPHIA FERNANDEZ

Explanation:

Answer: I belive it is 25%. Correct me if you know the answer or think I am wrong.

Explanation:

0.00786 moles of Cu(NO3)2 would be produced from the given reaction. To determine the number of moles of Cu(NO3)2 produced when 0.500g of solid copper reacted with 2.0ml of 16.0M HNO3, we need to first balance the chemical equation for the reaction. The balanced chemical equation for this reaction is:

3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O

From the balanced equation, we can see that 3 moles of Cu react with 8 moles of HNO3 to produce 3 moles of Cu(NO3)2. Using this ratio, we can calculate the number of moles of Cu(NO3)2 produced from the given amount of Cu and HNO3.

First, we need to convert the volume of HNO3 to moles using the concentration of HNO3:

2.0 mL HNO3 x (1 L/1000 mL) x (16.0 mol/L) = 0.032 moles HNO3

Next, we need to calculate the number of moles of Cu using its molar mass:

0.500 g Cu x (1 mol Cu/63.55 g Cu) = 0.00786 moles Cu

Finally, we use the stoichiometric ratio to calculate the number of moles of Cu(NO3)2 produced:

0.00786 moles Cu x (3 moles Cu(NO3)2/3 moles Cu) = 0.00786 moles Cu(NO3)2

Therefore, 0.00786 moles of Cu(NO3)2 would be produced from the given reaction.

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Answer:

The limiting reactant is H₂

Explanation:

The reaction of hydrogen (H₂) and carbon monoxide (CO) to produce methanol (CH₃OH) is the following:

2H₂(g) + CO(g) → CH₃OH(g)

From the balanced chemical equation, we can see that 1 mol of CO reacts wIth 2 moles of H₂. So, the stoichiometric ratio is:

2 mol H₂/1 mol CO = 2.0

We have 500 mol of CO and 750 mol of H₂, so we calculate the ratio to establish a comparison:

750 mol H₂/500 mol CO = 1.5

Since 2.0 > 1.5, we have fewer moles of H₂ than are needed to completely react with 500 moles of CO. In fact, we need 1000 moles of H₂ and we have 750 moles. So, the limiting reactant is H₂.

Answer:

ethanol

Explanation:

CO2 is carbon dioxide

C2H5OH is ethanol and we know that because that is what is left after taking out the CO2

Answer:

Noble gases

Explanation:

Answer:

Explanation:

The Tacoma Narrows Bridge is the historical name given to the twin suspension bridge—originally built in 1940—that spanned the Tacoma Narrows strait. It collapsed just four months later due to aeroelastic flutter. Since then, this topic has become popular, with several case studies discussing the failure phenomenon of suspension cable bridges.

In the state of Washington, the construction of the Tacoma Narrows Bridge was completed and opened to the traffic on July 1st, 1940. It was the very first bridge to incorporate a series of plate girders as roadbed support, and the first bridge of its type (cable suspension). It was also the third largest suspension bridge of its time, with a 2800-foot central span and two side spans of 1100 feet each.

A west-side approach had a continuous steel girder of 450ft, while the east side had a long reinforced concrete frame of 210ft.  It had two cable anchorages of 26ft. along roadways, two 5ft. sidewalks and two 8ft. deep stiffening girders. Among several other structural details, the suspension cable anchorages to which the cables were connected were made of 20,000 cubic yards of concrete, 6 lakh pounds of structural steel, and 2.7 lakh pounds of reinforcing steel. Because of its extremely long length, it was considered a ‘narrow bridge’. The overall construction cost was estimated to be a whopping $6 Million in 1940. Considering inflation, this is equivalent to almost $1 Billion, and all of this for something that lasted just four months and seven days. Yet, this remains a great engineering feature for civil engineers to ponder over.

a. CaO (calcium oxide) will form a basic solution when dissolved in water.

b. SO₂ (sulfur dioxide) will form an acidic solution when dissolved in water.

c. Cl₂O (dichlorine monoxide) will form an acidic solution when dissolved in water.

a. CaO (calcium oxide) is a metal oxide. When it reacts with water, it undergoes hydrolysis to form calcium hydroxide (Ca(OH)₂), which is a strong base. The reaction can be written as:

CaO + H₂O → Ca(OH)₂

b. SO₂ (sulfur dioxide) is a non-metal oxide. When it dissolves in water, it forms sulfurous acid (H₂SO₃) through a series of reactions with water molecules. Sulfurous acid is a weak acid, resulting in an acidic solution. The reaction can be represented as:

SO₂ + H₂O → H₂SO₃

c. Cl₂O (dichlorine monoxide) is also a non-metal oxide. It reacts with water to produce hypochlorous acid (HClO), which is a weak acid. This leads to the formation of an acidic solution. The reaction can be written as:

Cl₂O + H₂O → 2HClO

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The system at 25°C, the equilibrium will shift to the right. NH4Cl(s) will break down into NH4(aq) and Cl-(aq) forming more products as the temperature increases.

The reaction NH4Cl(s) heat ↔ NH4(aq) + Cl-(aq) is an endothermic reaction where heat is absorbed as the reactant NH4Cl(s) breaks down into NH4(aq) and Cl-(aq) at a specific temperature of 25°C.

The equilibrium will shift to the right if an increase in temperature is added to the system.

The increase in temperature will favour the endothermic reaction that requires more heat for the reaction to occur as the system shifts in the direction that will absorb more heat to replace that lost to the surroundings.

So, when an increase in temperature is added to the system at 25°C, the equilibrium will shift to the right.

Hence, NH4Cl(s) will break down into NH4(aq) and Cl-(aq) forming more products as the temperature increases.

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Answer:

486 grams

Explanation:

No of moles = mass in gram / molar mass

Mass in gram = No of moles × molar mass

Molar mass of CaCO3 = 40+12+(16*3)

= 40+12+48 = 100 amu

Mass in gram = 4.86 × 100

Mass in gram 486 grams

Answer:

c.  the mother could get an infection

Explanation:

Answer:

A. Noble gas configuration

Answer:

101.62 grams of water is given o when 62.1 g of propane burns.

Explanation:

Propane gas (C₃H₈) burns with oxygen gas and products carbon dioxide gas and liquid water. The balanced reaction is:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

By stoichiometry, the following amounts of moles of each compound participate in the reaction:

Being the molar mass of each compound:

By stoichiometry, the following mass quantities of each compound participate in the reaction:

Then you can apply the following rule of three: if by stoichiometry 44 grams of propane produces 72 grams of water, 62.1 grams of propane how much mass of water does it produce?

\(mass of water=\frac{62.1 grams of propane*72 grams of water}{44 grams of propane}\)

mass of water= 101.62 grams

101.62 grams of water is given o when 62.1 g of propane burns.

Answer:

[(x-37.5)/x]*100%

62.5%  (assuming the original sample weighs 100.0g)

Explanation:

Let's say that the original sample is x

Mass of I-125 which has decayed: x-37.5

Percentage of decayed mass: [(x-37.5)/x]*100%

Please recheck, for this may not be the correct answer

The volume of the sodium carbonate needed to precipitate is 31.248 ml. This is calculated using the dilution formula.

The molarity of the solution and the volume of the first solution can be correlated with the molarity and the volume of diluted solution. It is called as dilution formula.

Molar concentration is the another term for molarity. Molarity is a measure of the concentration of a chemical species in particular of a solute in a solution in terms of amount of substance per unit volume of solution.

The expression for molarity of the solution is,

M1 V1 = M2 V2

here we have 0.125 m sodium carbonate solution would be needed to precipitate the calcium ion from 37.2 ml of 0.105 m cacl2 solution.  

putting all the values we get,

0.105 * 37.2 = 0.125 * V2

V2 = 31.248

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