Answer:
there will a definite decrease in solute solution
Explanation:
acid reaction acting upon negative charge.
What is the type of mixture whose components are evenly distributed throughout?
The type of mixture whose components are evenly distributed throughout is a homogeneous mixture.
A homogeneous mixture is a mixture in which the components are uniformly distributed throughout. The mixture appears to be the same throughout, and it has the same physical and chemical properties throughout. The composition of the components of a homogeneous mixture is uniform. An example of a homogeneous mixture is a solution of sugar and water. Sugar dissolves in water to form a homogeneous mixture. Another example is salt and water. Salt dissolves in water to form a homogeneous mixture.
However, These are the kinds of combinations where the ingredients are evenly dispersed throughout. In other words, "they are consistent throughout. In a homogenous mixture, we can only see one phase of the substance and components are evenly distributed throughout .
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ELEMENTS ARE CLASSIFIED AS METALS, NONMETALS, AND METALLOIDS. USE THE PERIODIC TABLE AND IDENTIFY TWO OF EACH CLASSIFICATION.
Answer:
Elements are classified into- metals – Nonmetals- Metalloids – Noble gases. State which of A, B, C, D is a:
1) Metallic element
2) Non-metallic element
3) Metalloid
4) Noble gas.
A) Is non-malleable, non-ductile and a poor conductor of electricity
B) Has lustre, is malleable and ductile and a good conductor of electricity
C) Is unreactive and inert and present in traces in air
D) Shows properties of both metals and nonmetals
Explanation:
Will give brainliest... what is the [OH-] of a solution whose pOH is equal to 2.86
Answer:
the pOH of a solution is the negative logarithm of the hydroxide-ion concentration. by this yields a [OH − ] of 1.0 × 10 -10 M. Finally the pOH of the solution equals -log(1.0 × 10 -10 ) = 10.Explanation:
The concentration of hydroxide ion of a solution whose pOH value is equal to 2.86 is 1.38×10⁻³ M.
How do we calculate the concentration of OH⁻?Concentration of hydroxide ion will be calculated by using the pOH value by using the below equation as:
pOH = -log[OH⁻]
[OH⁻] = \(10^{-pOH}\)
Given that value of pOH = 2.86
On putting values we get,
[OH⁻] = \(10^{-2.86}\)
[OH⁻] = 0.00138 = 1.38×10⁻³ M
Hence concentration of hydroxide ion is 1.38×10⁻³ M.
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If the mass is 12.3 g, volume without mineral is 50ml, volume with mineral is 53ml, then what is: (a) the volume of water displaced and (b) the final density of the mineral?
a.) The Volume of water displaced is 3 ml
b.) The final density of the mineral is 4.1 g/ml.
(a) The volume of water displaced is the ratio of the volume containing mineral to the volume excluding mineral.
Volume of water displaced = Volume with mineral - Volume without mineral
Volume of water displaced = 53 ml - 50 ml
Volume of water displaced = 3 ml.
(b) The following formula can be used to determine the mineral's density:
Mass / Volume equals density.
The difference between the mass of the mineral and the mass without the mineral is the mass of the mineral.
Mass of mineral = Mass with mineral - Mass without mineral
Mass of mineral = 12.3 g - 0 g (since the mass without mineral is not given)
Mass of mineral = 12.3 g
By deducting the volume without the mineral from the volume with, one may determine the volume of the mineral.
Volume of mineral = Volume with mineral - Volume without mineral
Volume of mineral = 53 ml - 50 ml
Volume of mineral = 3 ml
Therefore, the density of the mineral is:
Density = Mass of mineral / Volume of mineral
Density = 12.3 g / 3 ml
Density = 4.1 g/ml
Therefore, the final density of the mineral is 4.1 g/ml.
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how can balancing equations support the law of conservation
Answer:
detail is given below.
Explanation:
This law was given by French chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
Law of conservation of mass:
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
For example:
In given photosynthesis reaction:
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
The given equation is balanced chemical equation of photosynthesis. There are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.
If equation is not balanced,
CO₂ + H₂O → C₆H₁₂O₆ + O₂
It can not follow the law of conservation of mass because mass is not equal on both side of equation.
A twin-turbojet airplane is cruising with a speed of Mach 1.5 at an altitude where atmospheric pressure is 32989.5 Pa, temperature is 232.778 K. Each engine is consuming 200 kg of air per second. The engine exit flow has a pressure of 32,000 Pa with a velocity of 850 m/sec. The exit area of the engine nozzle is 1.4 m
2
. How much thrust both engines are generating?
A twin-turbojet airplane is cruising with a speed of Mach 1.5 at an altitude where atmospheric pressure is 32989.5 Pa, temperature is 232.778 K. Each engine is consuming 200 kg of air per second. The engine exit flow has a pressure of 32,000 Pa with a velocity of 850 m/sec. The exit area of the engine nozzle is 1.4 m². The thrust generating in both engines is 342,678.6 Newtons.
To calculate the thrust generated by both engines, we can use the momentum equation for a nozzle:
Thrust = mass flow rate * exit velocity + (exit pressure - ambient pressure) * exit area
Given:
Speed of the airplane (V) = Mach 1.5
Atmospheric pressure (\(P_a\)) = 32989.5 Pa
Ambient temperature (\(T_a\)) = 232.778 K
Mass flow rate of each engine (m) = 200 kg/s
Exit pressure of the engine (\(P_e\)) = 32000 Pa
Exit velocity of the engine (\(V_e\)) = 850 m/s
Exit area of the engine nozzle (\(A_e\)) = 1.4 m²
First, we need to calculate the ambient density using the ideal gas law:
PV = nRT
Since the speed of the airplane is given in terms of Mach number, we can calculate the speed of sound (a) using the following formula:
a = √(gamma * R * \(T_a\))
Where gamma is the specific heat ratio of air (approximately 1.4) and R is the specific gas constant for air (approximately 287 J/(kg K)).
Next, we can calculate the ambient density (ρ) using the equation:
ρ = \(P_a / (R * T_a)\)
Now, we can calculate the thrust generated by each engine using the momentum equation:
Thrust = m* \(V_e + (P_e - P_a) * A_e\)
Finally, we can calculate the total thrust generated by both engines by multiplying the thrust of a single engine by 2.
Calculate the speed of sound:
a = √(1.4 * 287 * 232.778)
a = 438.95 m/s
Calculate the ambient density:
ρ = 32989.5 / (287 * 232.778)
ρ = 1.383 kg/m³
Calculate the thrust of a single engine:
\(Thrust_s\) = 200 * 850 + (32000 - 32989.5) * 1.4
\(Thrust_s\) = 170000 + 1339.3
\(Thrust_s\) 171339.3 N
Calculate the total thrust of both engines:
\(Thrust_t\) = 2 * \(Thrust_s\)
\(Thrust_t\) = 2 * 171339.3
\(Thrust_t\) = 342678.6 N
Therefore, both engines are generating approximately 342,678.6 Newtons of thrust.
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Which statement best summarizes the importance of Ernest Rutherford's gold foil experiment?
o It proved that all of John Dalton's postulates were true,
O It verified J. J. Thomson's work on the atomic structure.
It showed that an electron circles a nucleus in a fixed-energy orbit
O It showed that a nucleus occupies a small part of the whole atom.
Answer:
d
Explanation:
The sentences below are things people might say if they were planning to invest or not planning to invest Sort them into the correct categories . am thinking about buying stocks Planning to Invest Not Planning to Invest don't know much about investing can't afford to buy stocks don't really like to take risks need a way to manage my money want to save money for my future
Investing :
"I'm considering investing in equities."
"I need a system for handling my finances."
"I need to put money away for the future."
No Investment :
"My knowledge of investment is limited."
"I am unable to purchase stocks."
"I don't particularly enjoy taking chances."
Explanation:
These are accurate because I recently completed the course that taught me these things.
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Imagine that you are a leaf on a plant, and you realize that you are running low on supplies to do your job. You decide to text the roots to set up a delivery. Write a text message conversation between the leaf and the roots that discusses and arranges this delivery.
Be sure to answer these questions in your conversation:
• Which supplies is the leaf running out of? • What are the supplies needed to do? • How will the roots get the supplies from outside the plant? • How will the supplies get from the roots to the leaf?
The leaves of plants primarily serve to photosynthesize and require water conducted by the root to do so.
Water conduction by the rootAs a leaf of a plant running low on supplies that the root is responsible for, what I will be needing is water.
Thus, I will have to send a text message to the root to supply me with water. The root will respond by asking its foot soldiers (the root hairs) to conduct water into the root.
Once water gets into the root, it enters special cells that are responsible for conducting water inside plants - the xylems. The root sends the water through the xylem and water travels from there to me - the leaf.
Once the water gets to me, I will use it in combination with inorganic carbon (carbon dioxide) to synthesize carbohydrates.
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What makes water such a good solvent for a variety of solutes?
A) The polarity of water is strong enough to break ionic bonds.
B) It's a liquid.
C) Oils and fats are emulsified by water's hydrogen bonds.
D) As water heats, it expands.
Though not entirely accurate, 'A' is the best possible answer.
Water is considered the universal solvent. Water is polar and has a partially positive and negative charge, it readily dissolves ions and polar molecules. When an ionic substance is added to water, individual ions interact with the polar regions of the water molecules during the dissociation process, disrupting their ionic bonds. The charges associated with these molecules form hydrogen bonds with water, surrounding the particle with water molecules. This is referred to as a sphere of hydration, or a hydration shell, and serves to keep the particles separated or dispersed in the water.
A pi bond is the result of the a) overlap of two s orbitals. b) overlap of an s orbital and a p orbital. c) overlap of two p orbitals along their axes. d) sideways overlap of two parallel p orbitals. e) sideways overlap of two s orbitals.
A pi bond is the result of the d) sideways overlap of two parallel p orbitals.
Pi bonds are bonds that occur as a result of overlapping orbitals of atoms that are not in the bond axis. Each p orbital that contributes to a pi bond has two lobes and has a node at the core.
The pi orbital can hold a maximum of two pairs of electrons. Whereas each electron in a pi bond is also called a pi electron, the pi electrons are used for double bonds or triple bonds. The 2p orbital of carbon has slightly higher energy than the sp2 orbital, so the pi bond formed from two 2p orbitals has somewhat higher energy and is slightly less stable than the sp2-sp2 sigma bond.
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Which element is classified as a noble gas? HURYYYY PLSSSSSSSS!!!!!!!!!
O
N
CI
Xe
Answer:
Xe that is xenon
Explanation:
Xe that is xenon
How many grams of calcium are contained in 1.0 L of an 8.0 x 10-3 M intravenous calcium replacement solution?
0.32 g
0.40 g
0.80 g
3.2g
To determine the grams of calcium in 1.0 L of an 8.0 x 10-3 M intravenous calcium replacement solution.
We need to use the formula: mass = 0.32 g
mass = molarity x volume x molar mass
First, we need to convert the molarity from scientific notation to decimal notation: 8.0 x 10-3 M = 0.008 M
The molar mass of calcium is 40.08 g/mol. We can now plug in the values: mass = 0.008 M x 1.0 L x 40.08 g/mol
mass = 0.32064 g
Rounding to two significant figures, the answer is 0.32 g. Therefore, the correct answer is option A.
To calculate the grams of calcium in a 1.0 L solution with a concentration of 8.0 x 10^-3 M, use the formula:
mass = volume x concentration x molar mass
First, find the molar mass of calcium (Ca): 40.08 g/mol
Now, plug in the values:
mass = (1.0 L) x (8.0 x 10^-3 mol/L) x (40.08 g/mol)
mass = 0.32 g
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In the Fahrenheit temperature scale, water freezes at 32∘F and boils at 212∘F, in the Celsius scale, water freezes at 0∘C and boils at 100∘C, given that the Fahrenheit. temperature F and the Celsius temperature C are related by a linear equation, find F in terms of C. F( G )= Use your equation to find the Fahrenheit temperatures corresponding to 31∘C.21∘C,−9∘C, and −15∘C, to the nearest degree.
The Fahrenheit temperatures corresponding to Celsius 31°C, 21°C, -9°C, and -15°C are approximately 88°F, 70°F, 16° F, 5°F.
To find the equation relating Fahrenheit temperature (F) to Celsius temperature (C), we can use the given freezing and boiling points of water on both scales.
We know that at the freezing point of water:
Fahrenheit temperature = 32°F
Celsius temperature = 0°C
And at the boiling point of water:
Fahrenheit temperature = 212°F
Celsius temperature = 100°C
We can use these two points to find the equation of the line relating F and C.
First, we find the slope of the line:
Slope = (Change in Fahrenheit temperature) / (Change in Celsius temperature)
= (212°F - 32°F) / (100°C - 0°C)
= 180°F / 100°C
Next, we find the y-intercept of the line:
Using the freezing point of water (0°C, 32°F):
32°F = Slope * 0°C + y-intercept
32°F = 0.18 * 0°C + y-intercept
y-intercept = 32°F
Therefore, the equation relating Fahrenheit temperature (F) to Celsius temperature (C) is:
F = 1.8C + 32
Now, we can use this equation to find the Fahrenheit temperatures corresponding to the given Celsius temperatures:
For 31°C:
F = 1.8 * 31 + 32 = 87.8 ≈ 88°F
For 21°C:
F = 1.8 * 21 + 32 = 69.8 ≈ 70°F
For -9°C:
F = 1.8 * -9 + 32 = 15.8 ≈ 16°F
For -15°C:
F = 1.8 * -15 + 32 = 5 ≈ 5°F
Therefore, the Fahrenheit temperatures corresponding to 31°C, 21°C, -9°C, and -15°C are approximately 88°F, 70°F, 16° F, 5°F.
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(e) (i) What are the number average (Mn) and weight average (Mw) molecular weights of a polymer with equal number of chains with molecular weights of 2100, 6600 and 12000 mixed together? (ii) What is the answer if "equal number of chains" is replaced by "equal weights of chains"? (iii) What is the degree of polymerization (DP) of the polymer in the first question, if the repeating units of the three different chains have molecular weights of 126, 324 and 300?
(e) (i) Number average (Mn) = 6,900g/mol
(ii) Mn will remain the same in this case as it does not depend on weight.= 6,900g/mol
(iii) The degree of polymerization (DP) is 4492.
(i) Number average (Mn)
The number average molecular weight (Mn) is the sum of the molecular weights of all polymer chains divided by the total number of polymer chains.
Weight average (Mw)
The weight average molecular weight (Mw) is the sum of the product of the molecular weight and the fraction of the total polymer chains that have that molecular weight.
Using the given formula, let's first calculate the Mn:
(2100 + 6600 + 12000) / 3 = 6,900g/mol
Let's now calculate the Mw:
[(2100 x 2100) + (6600 x 6600) + (12000 x 12000)] / (2100 + 6600 + 12000)= 9966.67g/mol
(ii) Equal weights of chains
Mn will remain the same in this case as it does not depend on weight.
Mw, on the other hand, will change.
The following formula will be used:
2100 x (1/3) + 6600 x (1/3) + 12000 x (1/3) = 6,900g/mol
(iii) The degree of polymerization (DP)
DP refers to the number of repeating units in the polymer chain.
We can calculate the DP using the following formula:
DP = (Mn / M) * NA where M is the molar mass of the repeating unit, and NA is Avogadro's number.
Using the Mn value from part (i) and the given molecular weights for the repeating units, we can calculate the DP:
DP = (6,900 / ((126 + 324 + 300) / 3)) * 6.02 × 1023= 4492.45 (approximately 4492)
Therefore, the degree of polymerization is 4492.
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The weight average molecular weight (Mw) of the polymer will be \($$M_w=\frac{1\times2100^2+1\times6600^2+1\times12000^2{1\times2100+1\times6600+1\times12000}=8,580\;g/mol$$\).
Weight average molecular weight (Mw) of the polymer will be \($$M_w=\frac{1.0587\times2100^2+1.0587\times6600^2+1.0587\times12000^2{1.0587\times2100+1.0587\times6600+1.0587\times12000}=8,825\;g/mol$$\).
The degree of polymerization of the polymer in the first question is 25.01.
Number average (Mn) and weight average (Mw) molecular weights of a polymer are calculated using the following formula:
\($$M_n = \frac{\sum N_iM_i}{\sum N_i}$$\)
and
\($$M_w = \frac{\sum N_iM_i^2}{\sum N_iM_i}$$\)
where Ni is the number of chains with molecular weight Mi.
(i) When the number of chains with molecular weights of 2100, 6600, and 12000 are mixed together:
Molecular weight (M) Number of chains (N) 2100 1 6600 1 12000 1
Total 3
The number average molecular weight (Mn) of the polymer will be:
\($$M_n=\frac{1\times2100+1\times6600+1\times12000}{1+1+1}= 6,900\;g/mol$$\)
The weight average molecular weight (Mw) of the polymer will be:
\($$M_w=\frac{1\times2100^2+1\times6600^2+1\times12000^2}{1\times2100+1\times6600+1\times12000}=8,580\;g/mol$$\)
(ii) When the equal weights of chains are mixed together:
The total weight of the chains is:
2100 + 6600 + 12000 = 20,700 g
Number of chains with molecular weight 2100 = 2100 x n1
Number of chains with molecular weight 6600 = 6600 x n2
Number of chains with molecular weight 12000 = 12000 x n3
So, the total weight of each group of chains will be
n1M1 + n2M2 + n3M3.
Now, we can calculate the values of n1, n2, and n3 as follows:
n1 = 6600 x n2n2 = 12000 x n3M1 + M2 + M3 = 2100 + 6600 + 12000 = 20700n1M1 + n2M2 + n3M3 = 20700
Equating the value of n1 in terms of n2 and n3 and substituting it in the equation above:
n1 = 6600 x n2
\($$\frac{6600}{n1}=n2$$\)
\($$\frac{12000}{n2}=n3$$\)
\($$n1=\frac{20700}{2100+6600+12000}=0.1739$$\)
n2 = 0.0208, n3 = 0.0052
Therefore, the number of chains with molecular weight 2100 = 0.1739 x 2100 / 6600 x 0.1739 x 6600 = 0.0208 x 12000 / 6600 x 0.0208 x 6600 = 0.0052 x 2100 / 6600 x 0.0052 x 12000 ≈ 1.0587
Number average molecular weight (Mn) will be:
\($$M_n=\frac{1.0587\times2100+1.0587\times6600+1.0587\times12000}{1.0587+1.0587+1.0587}= 7,170\;g/mol$$\)
Weight average molecular weight (Mw) of the polymer will be:
\($$M_w=\frac{1.0587\times2100^2+1.0587\times6600^2+1.0587\times12000^2}{1.0587\times2100+1.0587\times6600+1.0587\times12000}=8,825\;g/mol$$\)
(iii) The degree of polymerization (DP) of the polymer in the first question will be:
Number of chains with molecular weight 2100 = 1
Number of chains with molecular weight 6600 = 1
Number of chains with molecular weight 12000 = 1
The molecular weight of the repeating units of the three different chains have molecular weights of 126, 324, and 300 respectively.
Therefore, the degree of polymerization (DP) of the polymer in the first question will be:For 2100 chain,
\($$n_1=\frac{2100}{126}=16.67$$\)
For 6600 chain,
\($$n_2=\frac{6600}{324}=20.37$$\)
For 12000 chain,
\($$n_3=\frac{12000}{300}=40.00$$\)
So, the average degree of polymerization (DP) is:
\($$DP=\frac{1\times16.67+1\times20.37+1\times40.00}{1+1+1}=25.01$$\)
Therefore, the degree of polymerization of the polymer in the first question is 25.01.
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how do you convert 761.3 mm Hg in pa
Answer:
761.3
mmHg (mm of mercury)
Select input unit of pressure: 761.3 mmHg (mm of mercury) equals to:
Pa (pascal)
hPa (hectopascal)
kPa (kilopascal)
MPa (megapascal)
kgf/cm2 (kg per sq. cm)
kgf/m2 (kg per sq. meter)
mbar (millibar)
bar
atm (standard atmosphere)
at (technical atmosphere)
torr
mmH2O (mm of water)
mmHg (mm of mercury)
inHg (inches of mercury)
psi (pounds per sq. inch)
psf (pounds per sq. foot)
101498.31907898 Pa (pascal)
1014.98319079 hPa (hectopascal)
101.498319079 kPa (kilopascal)
0.101498319 MPa (megapascal)
1.034994816 kgf/cm2 (kg per sq. cm)
10349.948155485 kgf/m2 (kg per sq. meter)
1014.98319079 mbar (millibar)
1.014983191 bar
1.001710526 atm (standard atmosphere)
1.034994816 at (technical atmosphere)
761.3 torr
10349.949664708 mmH2O (mm of water)
761.3 mmHg (mm of mercury)
29.972433492 inHg (inches of mercury)
14.721102154 psi (pounds per sq. inch)
2119.838710232 psf (pounds per sq. foot)
The pressure value 761.3 mmHg (mm of mercury) in words is "seven hundred and sixty-one point three mmHg (mm of mercury)".
Explanation:
761.3 mm Hg is equal to 101,498.31907898 Pa. Pressure can be measured by using many units such as atm, Pa, torr, bar, cmHg, mmHg and so on.
What is pa?The pascal (Pa) is the unit of pressure or stress in the International System of Units (SI). It is named after the scientist and mathematician Blaise Pascal.
1 mmHg = 133.322 pascals (Pa) pascal value x 1 Pa = mm Hg value x 133.322 Pa.
Pa value = mmHg value x 133.322.
1 atm = 760 mmHg = 101325 Pa
761.3 mm Hg= (\(\frac{01325 Pa}{760 mmHg}\)) x 761.3 mm Hg
= 101,498.31907898 Pa
Hence, 761.3 mm Hg is equal to 101,498.31907898 Pa.
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How many miles are there in 2345 feet? (1 mile=5280 ft)
2 points
Answer:
0.444 mile
Explanation:
Which of these sets of elements have similar physical and chemical properties?
Answer:
F,Cl,I,BR
Explanation:
There all non-metals
The chemical and physical properties of Fluorine, Chlorine, Bromine, and Iodine have been similar. Thus option B is correct.
The physical and chemical properties of the elements have been based on the presence of the valence electrons in the element. The valence electrons are responsible for the reactivity of the element, and thereby the physical and chemical properties.
The elements belonging to the same group have been consisted of the same number of valence electrons, and thereby possess similar chemical and physical properties.
In the given set of options, Fluorine, Chlorine, Bromine, and Iodine have been belonging to the same group 17, and all have 7 valence electrons. The chemical and physical properties of these elements have been similar. Thus option B is correct.
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gallium (III) carbonate formula
Why are triacylglycerols the major form of stored energy instead of glucose? Choose one or more: A. The fatty acids of a triacylglycerol have fewer carbons than a molecule of glucose, so it is easier to completely metabolize. B. Triacylglycerols are highly soluble in blood serum so can be readily transported. C. The hydrophobic nature of triacylglycerols means that they are not solvated by water and therefore have less mass per unit volume. The greater energy density translates into more energy stored in the same volume. D. Fatty acids are at a higher reduction state than that of glucose and therefore yield more energy for the same number of carbons upon oxidation.
Triacylglycerols are the major form of stored energy instead of glucose because they have a higher energy density due to their hydrophobic nature, they can be easily transported in the blood serum, and they yield more energy per carbon upon oxidation compared to glucose.
Triacylglycerols are more advantageous as a stored energy form compared to glucose for multiple reasons. Firstly, triacylglycerols have a higher energy density because of their hydrophobic nature. They are not solvated by water and therefore have less mass per unit volume, allowing for more energy to be stored in the same volume.
Secondly, triacylglycerols are highly soluble in blood serum, enabling efficient transportation to different parts of the body where energy is needed. This solubility facilitates the mobilization and delivery of stored energy to meet metabolic demands.
Lastly, the fatty acids in triacylglycerols are at a higher reduction state compared to glucose. This higher reduction state means that fatty acids yield more energy per carbon upon oxidation. Thus, the oxidation of fatty acids in triacylglycerols provides a greater amount of energy compared to the oxidation of glucose, making them an efficient energy source for the body.
Overall, the combination of higher energy density, easy transportability, and greater energy yield per carbon make triacylglycerols the preferred form of stored energy in the body compared to glucose.
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Which property is NOT used to separate a mixture?
Answer:
Conductivity.
Explanation:
Propose a plausible synthesis for the following transformations. A complete answer will depict all the isolated intermediate(s) compounds along the synthetic pathway. 3. a. Cl C. он Br 4. What is/are the major product(s) for the following synthesis. Show any and all intermediates isolated along the synthetic pathway. 1) Cl AICl3 2) Br2, FeBr3 3)CH3MgBr 4)H2O 5)TSCl, py 6) NaOEt 7) BH3 THF, H20 8) NaOH, H202 9) Na2Cr20. H2SO4. H20
A plausible synthesis for the given transformations would involve the following steps:
1. Starting with compound A, react it with AICl3 to form intermediate compound B (isolated).
2. React compound B with Br2 and FeBr3 to yield intermediate compound C (isolated).
What are the major product(s) for the given synthesis?The major product(s) obtained from the synthesis will be compound J. The synthesis involves a series of transformations and reactions starting from compound A and progressing through several intermediates (compounds B to I).
3. Treat compound C with CH3MgBr to obtain intermediate compound D (isolated).
4. React compound D with H2O to form intermediate compound E (isolated).
5. Treat compound E with TSCl and pyridine to yield intermediate compound F (isolated).
6. React compound F with NaOEt to obtain intermediate compound G (isolated).
7. Treat compound G with BH3/THF followed by H2O to form intermediate compound H (isolated).
8. React compound H with NaOH and H2O2 to yield intermediate compound I (isolated).
9. Finally, treat compound I with Na2Cr2O7, H2SO4, and H2O to obtain the desired product J.
The isolated intermediates are obtained at various steps to ensure the desired transformations occur. Ultimately, the synthesis leads to the formation of the target product J.
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experiments also show that any aqueous solution at 25 degree celsius, the ionic-product of water Kw is equal to a constant value:
In any aqueous solution at 25°C, the ionic-product of water (Kw) is a constant value equal to 1.0 x 10⁻¹⁴ mol²/L².
Due to the auto-ionization or self-ionization of water, water molecules dissociate into hydronium ions (H₃O⁺) and hydroxide ions (OH⁻). At 25°C, the Kw is equal to 1.0 x 10⁻¹⁴ mol²/L².
This constant value of Kw plays a crucial role in understanding the acidity and basicity of aqueous solutions. It helps to establish the relationship between the concentrations of hydronium and hydroxide ions, as their product remains constant at a given temperature. The pH and pOH scales are derived from this relationship, providing a convenient method for measuring the acidity or basicity of a solution.
In summary, the ionic-product of water, Kw, remains constant at 1.0 x 10⁻¹⁴ mol²/L² for any aqueous solution at 25°C. This constant is a result of the auto-ionization of water and helps to understand the relationship between hydronium and hydroxide ions in the context of acidity and basicity.
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a buffer is prepared with na,co3 and nahco. what is the correct net ionic equation describing what happens when a small amount of naoh is added to the buffer?
When a small amount of NaOH is added to the buffer containing Na2CO3 and NaHCO3, the following net ionic equation occurs:
NaHCO3 + OH- → H2O + CO32-
This equation shows the reaction between the bicarbonate ion (HCO3⁻) from the buffer and the hydroxide ion (OH⁻) from the added NaOH, producing the carbonate ion (CO3²⁻) and water (H2O).
In this equation, the Na2CO3 acts as a buffer to maintain the pH of the solution. The added NaOH reacts with the NaHCO3 to form water and CO32- ion, which increases the concentration of carbonate ion in the solution. However, the buffer system consisting of Na2CO3 and NaHCO3 resists changes in pH by neutralizing any additional OH- ions that are added. Therefore, the overall pH of the solution remains relatively constant.
When a buffer is prepared with Na2CO3 (sodium carbonate) and NaHCO3 (sodium bicarbonate), and a small amount of NaOH (sodium hydroxide) is added, the net ionic equation is as follows:
HCO3⁻(aq) + OH⁻(aq) → CO3²⁻(aq) + H2O(l)
This equation shows the reaction between the bicarbonate ion (HCO3⁻) from the buffer and the hydroxide ion (OH⁻) from the added NaOH, producing the carbonate ion (CO3²⁻) and water (H2O).
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an atom has 43 protons 55 neutrons and 44 electrons. what is the charge of the atom's nucleus?
What is the balance of this reaction=1N2+3H2=2NH3
N2 + 3 H2 = 2 NH3
Reaction type: synthesis
dr. gore found a strong correlation between carbon emissions and increasing ambient temperatures. can we conclude from his results that increasing temperatures is caused by carbon emissions?
Yes, we can conclude from the results by Dr. Gore that increasing temperatures are caused by carbon emissions.
Multiple well-designed studies have decisively demonstrated that increased CO2 levels brought on by the burning of fossil fuels are to blame for global warming. The link between CO2 levels and rising temperatures is just more evidence. In addition to more warming being caused by higher CO2, more CO2 is also released as a result of warming in a number of other ways. This is referred to as a positive feedback loop in which increased CO2 results in warmth, which raises CO2, which raises warming, and so on. Unfortunately, those who reject man-made global warming frequently point out that rising temperatures cause a rise in CO2 in an effort to mislead people into believing that warming is not caused by increased CO2.
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A saturated solution of silver chromate (Ag2CrO4) has a silver ion concentration of 8.66 x 10^-5 M. What would the concentration of silver ions be in a saturated silver chromate solution if solid sodium chromate (Na2CrO4) is added to form an additional 0.0600 M chromate ion?
In a saturated solution of silver chromate (Ag2CrO4), the silver ion concentration is already given as 8.66 x 10^-5 M. We have to determine the concentration of silver ions in the solution when solid sodium chromate (Na2CrO4) is added.
When solid sodium chromate is added, it dissociates into sodium ions (Na+) and chromate ions (CrO4^2-). Since silver chromate is a sparingly soluble salt, it establishes an equilibrium between the dissolved ions and the solid salt.
The balanced chemical equation for the dissolution of silver chromate can be represented as:
Ag2CrO4 ⇌ 2 Ag+ + CrO4^2-
The addition of solid sodium chromate does not directly affect the concentration of silver ions (Ag+). However, it increases the concentration of chromate ions (CrO4^2-) in the solution. Given that the concentration of chromate ions (CrO4^2-) is 0.0600 M, and assuming that the dissociation of silver chromate is complete, the concentration of silver ions remains the same at 8.66 x 10^-5 M.
Therefore, the concentration of silver ions in a saturated silver chromate solution, when solid sodium chromate is added to form an additional 0.0600 M chromate ion, would still be 8.66 x 10^-5 M. The addition of sodium chromate increases the concentration of chromate ions but does not affect the concentration of silver ions.
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carbonyl compounds have a natural tendencey to undergo tautomerization to its corresponding enol. however, keto form exists as the major tautomer. what is the reasion for this behavior
The reason for the predominance of the keto form over the enol form in tautomeric equilibrium of carbonyl compounds is primarily due to thermodynamic stability and resonance stabilization.
The keto form, characterized by a carbonyl group (C=O), is more stable than the enol form, which contains a hydroxyl group (-OH) attached to a carbon-carbon double bond. This stability arises from the stronger double bond character of the carbon-oxygen bond in the keto form compared to the carbon-carbon bond in the enol form.
Resonance stabilization also contributes to the preference for the keto form. In the keto form, the lone pair of electrons on the oxygen atom can participate in resonance with the adjacent carbon-oxygen double bond. This delocalization of electrons enhances the stability of the keto form.
On the other hand, the enol form has a higher energy due to the presence of a carbon-carbon double bond and an oxygen-hydrogen single bond, which are generally less stable than the carbon-oxygen double bond in the keto form.
Overall, the thermodynamic stability and resonance stabilization of the keto form make it the more favorable tautomer, leading to its predominance over the enol form in most carbonyl compounds.
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Table salt (NaCl) is a compound. Every molecule of table salt has the same properties as every other molecule of table salt because they all have one sodium (Na) atom and one chlorine (Cl) atom. This is referred to as ____________.
A. atomic number
B. fixed composition
C. a formula
D. a heterogeneous mixture
Table salt (NaCl) is a compound. Every molecule of table salt has the same properties as every other molecule of table salt because they all have one sodium (Na) atom and one chlorine (Cl) atom. This is referred to as fixed composition.
Hope this helps! Please correct me if I'm wrong :)
Every molecule of table salt has the same properties as every other molecule of table salt because they all have one sodium (Na) atom and one chlorine (Cl) atom. This is referred to as " fixed composition".
What is fixed composition?A chemical compound has a predictable makeup. Every sample of a compound has almost the same composition, or even the identical proportion, by mass, of the components contained in the compound, as per Proust's reasoning.
What is a molecule?Atomic building blocks make up molecules.
Therefore, every molecule of table salt has the same properties as every other molecule of table salt because they all have one sodium (Na) atom and one chlorine (Cl) atom. This is referred to as " fixed composition".
Hence, the correct answer will be option (B)
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