Mac's Grocery has 25 employees. The average daily wage for a teen is $52, and the average daily wage for an adult is $90. If the daily payroll is $1,984, how many teens and how many adults are employed?

Answer:

See attachment >_<

Step-by-step explanation:

Because the line includes the point \((0,3)\), we'll begin our line at this coordinate.

The slope is \(7\), or, \(\frac{7}{1}\). Slope is formatted in the \(rise\) in the line over its \(run\). Or, \(\frac{rise}{run}\). This means the line rises \(7\) units and runs \(1\) unit.

From our beginning point, \((0,3)\), move up seven units and then to the right one unit.

If this line was negative (it would have a negative slope), we would run to the left. However, we have a positive slope, so we will run to the right.

By doing this, we land on the point \((1,10)\). Draw a line through this point with our beginning coordinate \((0,3)\). This is our graphed line. I've attached a photo as well :)

Good luck ^^

Answer:

the answer is the 3rd one down fnivjgoibjmvkmkfmvk

Step-by-step explanation:

Answer:

162 ft^2

Step-by-step explanation:

the formula for finding the area of a triangle is \(\frac{b*h}{2}\)

the base is 27 and the height is 12

\(\frac{27*12}{2}=\frac{324}{2} = 162\)

The unit vector u that points from point P to point Q is -0.819i+0.573j. A vector v of length 50 pointing in the same direction is -40.962i+28.639j.

A unit vector is a vector that has a magnitude of 1. Unit vectors can be expressed in terms of the Cartesian coordinates i and j. Unit vectors in the Cartesian coordinate system are called standard unit vectors because they are the basis vectors that span the space.

A unit vector u is found from the point P=(9,6) towards the point Q=(33,13). The vector that is pointing from P to Q is given by Q-P = (33-9)i + (13-6)j = 24i + 7j.

The magnitude of this vector is given by||(24i+7j)|| = sqrt(24^2+7^2) = 25The unit vector u is then-24/25 i + 7/25 j.The vector that points in the same direction as u but has length 50 can be found by multiplying u by 50.

Thus, -40.962i + 28.639j is a vector of length 50 that points in the same direction as the vector u.

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Answer:

They are the same.

Step-by-step explanation:

1.1 and 1.10 are both the same, actually. There is just an extra 0 at the end. For example, 2 and 2.0 are the same, because 0 is 0, and it doesn't change your answer. The 0 could go on as in 1.100000000 but it will still equal 1.1 .

Hope this helped :)

Answer: Normal distribution or Gaussian distribution.

Step-by-step explanation:

Normal distribution, this means that we will see something that remaind us to a Gaussian Bell (a curved shape that goes to zero in the extremes and has a maximum in the middle)

If we have some biased points in one side, suppose left, we will have a skewed distribution, that has some important differences with the normal distribution at the time of describe it mathematically.

Answer:

106 cm

Step-by-step explanation:

Given that the rectangles are similar, therefore the ratio of their corresponding sides will be equal. So , we can say that;

53cm/100cm = x/200 cm

Simplify and solve for "x" , as ;

x = 53/100 *200 cm

x = 53*2 cm

x = 106 cm

Hence the value of x is 106cm .

I will do that soon okay I will

Answer:

a) 2(4a + 7b)(4a - 7b)

b) (m - 8n)(m + 8n)

Step-by-step explanation:

\(a)32a^{2} - 98b^{2}\\=(2 * 16)a^{2} - (2*49)b^{2}\\=2(16a^{2} -49b^{2})\\=2 ([4a]^{2}-[7b]^{2})\\=2(4a+7b)(4a-7b)\)

\(b) m^{2} - 64n^{2}\\= (m)^{2} - (8n)^{2} \\= (m-8n)(m+8n)\)

happy to help:)

Answer:

The 3-day pass costs $16.67 more per day than the 7-day pass.

Step-by-step explanation:

The easiest way to do this is to find the cost of each pass for the same amount of days. To do this, we find the lowest common multiple of 3 and 7 which would be 21

Lowest common multiple = \(7*3 = 21\)

Next we find the cost of each pass for 21 days by multiplying cost of the 7 day pass by 3, and the cost of the 3 day pass by 7

Cost of 7 day pass for 21 days = \(364*3 = 1092\)

Cost of 3 day pass for 21 days = \(206*7=1442\)

From this, we know that the difference between the two passes is $350 per 21 days. Since the question asks how much more would the 3-day pass cost per a day than the 7-day pass, we have to divide the difference by 21

\(350/21 = 16.66667\)

We can round this to $16.67 which in turn can be rounded to $17. As a result, the 3-day pass costs $17 more per day than the 7-day pass.

Answer:

x<-13 or x>-3

Step-by-step explanation:

solve 9 abs(x + 8)>45 = x<-13 or x>-3

Answer:

not a sloution

Step-by-step explanation:

93÷6 is 15.5 not 15 w=15.5

Answer:

x = ± 8

Step-by-step explanation:

\(\dfrac{1}{2}x^{2}=32\)

Multiply the equation by 2

x² = 32*2

x² = 64 = 8²

x = 8

The equation of the trend line in the scatter plot is y = (6/5)x - 12/5.

We can use the two-point form of the equation of a line to find the equation of the line that passes through the points (2, 0) and (7, 6).

The two-point form states that the equation of the line passing through two points (x1, y1) and (x2, y2) is given by:

y - y1 = (y2 - y1)/(x2 - x1) * (x - x1)

where m = (y2 - y1)/(x2 - x1) is the slope of the line.

In this case, we have:

x1 = 2, y1 = 0

x2 = 7, y2 = 6

So, the slope of the line is:

m = (y2 - y1)/(x2 - x1) = (6 - 0)/(7 - 2) = 6/5

Now, we can use either point to find the y-intercept (b) of the line. Let's use the first point (2, 0):

y - y1 = m(x - x1)

y - 0 = (6/5)(x - 2)

y = (6/5)x - 12/5

Therefore, the equation of the line passing through the points (2, 0) and (7, 6) is y = (6/5)x - 12/5.

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Answer:

Pink, shiny cars were preferred by buyers at that time

Step-by-step explanation:

Rewriting the sentence, removing unnecessary words

The car will travel 29 1/3 miles in 44 minutes, 40 miles in an hour.

Step-by-step explanation:

First, find how far the car can travel in one minute.

(1 1/2)/(2 1/4)=(2/3)

Then multiply the amount of time in minutes.

(2/3)*44= 29 1/3

(2/3)*60=40

Answer:

x = 4

Step-by-step explanation:

110ₓ = 40₅    --------- change all to base ten.

the system called binary

1x²+1x ¹+0x⁰ = 45¹+0*5⁰

x² + x + 0 = 20

x² + x – 20 = 0

solve x using Quadratic equation

        -1 ± \(\sqrt{1^2 - 4* 1 (-20)}\)

x =  ------------------------------------

                        2 * 1

x = -5;  x = 4

therefore, x = 4

Initial estimates of the probabilities of events are known as Prior Probabilities.

Prior Probabilities can be defined as the probability of the event before the event takes place.

For Example ,Let there be three wells X,Y,Z with water in it . it is given that one of the wells have the water that is fit for drinking. So the prior probability that Well Z can have drinking water is 1/3 i.e. 0.333  .

Therefore , the Initial estimates of the probabilities of events are known as Prior Probabilities.

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Answer:

since sum means addition it would be c because the it represents to the sum of w and 4

Answer: C

The sum is the solution when you add two (or more) numbers together. So, the sum of w and 4 can be written as w+4.

:)

Answer:

Examples of obedience in daily society involve driving to the left (or to the right depending on the country), inviting other people to the road with a 'hello' when we see them.

Step-by-step explanation:

Hope this helps

By using Trapezoid Rule to approximate the value of the definite integral  is 7.0313.

closest option to this answer is C. 7.0313.

To use the Trapezoid Rule to approximate the definite integral:

\(\int _0^2 x^4 dx\)

with n = 4, we first need to partition the interval [0, 2] into subintervals of equal width:

[0, 0.5], [0.5, 1], [1, 1.5], [1.5, 2]

The width of each subinterval is:

Δx = (2 - 0) / 4 = 0.5

Next, we use the formula for the Trapezoid Rule:

\(\int _a^b f(x) dx \approx \Delta x/2 * [f(a) + 2f(a+ \Delta x) + 2f(a+2 \Delta x) + ... + 2f(b- \Delta x) + f(b)]\)

Plugging in the values, we get:

\(\int _0^2 x^4 dx \approx 0.5/2 * [f(0) + 2f(0.5) + 2f(1) + 2f(1.5) + f(2)]\)

where\(f(x) = x^4\)

\(f(0) = 0^4 = 0\)

\(f(0.5) = (0.5)^4 = 0.0625\)

\(f(1) = 1^4 = 1\)

\(f(1.5) = (1.5)^4 = 5.0625\)

\(f(2) = 2^4 = 16\)

Plugging these values into the formula, we get:

\(\int _0^2 x^4 dx \approx 0.5/2 \times [0 + 2(0.0625) + 2(1) + 2(5.0625) + 16]\)

\(\int _0^2 x^4 dx \approx 7.03125\)

Rounding to four decimal places, we get:

7.0313

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To use the Trapezoid Rule to approximate the definite integral integral^2_0 x^4 dx with n = 4, we first need to divide the interval [0,2] into n subintervals of equal width. The approximation of the definite integral using the Trapezoid Rule with n = 4 is 6.5625 (option D).

[0, 0.5], [0.5, 1], [1, 1.5], [1.5, 2]

The width of each subinterval is h = (2-0)/4 = 0.5.

Next, we need to approximate the area under the curve in each subinterval using trapezoids. The formula for the area of a trapezoid is:

Area = (base1 + base2) * height / 2

Using this formula, we can calculate the area of each trapezoid:

Area1 = (f(0) + f(0.5)) * h / 2 = (0^4 + 0.5^4) * 0.5 / 2 = 0.01953
Area2 = (f(0.5) + f(1)) * h / 2 = (0.5^4 + 1^4) * 0.5 / 2 = 0.16406
Area3 = (f(1) + f(1.5)) * h / 2 = (1^4 + 1.5^4) * 0.5 / 2 = 0.64063
Area4 = (f(1.5) + f(2)) * h / 2 = (1.5^4 + 2^4) * 0.5 / 2 = 4.65625

Note that we are using the function f(x) = x^4 to calculate the values of f at the endpoints of each subinterval.

Finally, we can add up the areas of all the trapezoids to get an approximation of the definite integral:

Approximation = Area1 + Area2 + Area3 + Area4 = 0.01953 + 0.16406 + 0.64063 + 4.65625 = 5.48047

Rounding this to four decimal places gives us the answer B. 5.7813.

To use the Trapezoid Rule to approximate the value of the definite integral integral^2_0 x^4 dx with n = 4 and round your answer to four decimal places, follow these steps:

1. Divide the interval [0, 2] into 4 equal parts: Δx = (2 - 0)/4 = 0.5.
2. Calculate the function values at each endpoint: f(0), f(0.5), f(1), f(1.5), and f(2).
3. Apply the Trapezoid Rule formula: (Δx/2) * [f(0) + 2f(0.5) + 2f(1) + 2f(1.5) + f(2)].

Plugging in the function values, we get:
(0.5/2) * [0 + 2(0.5^4) + 2(1^4) + 2(1.5^4) + (2^4)] ≈ 6.5625.

So, the approximation of the definite integral using the Trapezoid Rule with n = 4 is 6.5625 (option D).

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Answer:

Step-by-step explanation:

d= c/ pi

multiply both side by pi

d*pi = c

divide by d

pi= c/d

the answer to ur question is 156

Given that

log (x+y)/5 =( 1/2) {log x+logy}

We know that

log a+ log b = log ab

⇛log (x+y)/5 =( 1/2) log(xy)

We know that log a^m = m log a

⇛log (x+y)/5 = log (xy)^1/2

⇛log (x+y)/5 = log√(xy)

⇛(x+y)/5 = √(xy)

On squaring both sides then

⇛{ (x+y)/5}^2 = {√(xy)}^2

⇛(x+y)^2/5^2 = xy

⇛(x^2+y^2+2xy)/25 = xy

⇛x^2+y^2+2xy = 25xy

⇛x^2+y^2 = 25xy-2xy

⇛x^2+y^2 = 23xy

⇛( x^2+y^2)/xy = 23

⇛(x^2/xy) +(y^2/xy) = 23

⇛{(x×x)/xy} +{(y×y)/xy} = 23

⇛(x/y)+(y/x) = 23

Therefore, (x/y)+(y/x) = 23

Hence, the value of (x/y)+(y/x) is 23.

The amount of Chemical  B needed is 1.6 g.

This refers to a diagram that shows a series of one or more points, lines, line segments, curves, or areas that represents the variation of a variable when compared with that of one or more other variables.

The quantity of Chemical B is plotted against the quantity of  Chemical A.

Chemical B  is plotted on the vertical axis using the scale of 1 cm to represent 2 units. Chemical A is plotted on the horizontal axis using the scale of 1 cm to represent 1 unit.

Therefore, on the graph, the line passing through the origin of the graph shows that when  1.4 g of Chemical A is used  1.6 g of Chemical B is needed.

Chemical B  is plotted on the vertical axis using the scale of 1  cm to represent 2 units.

To get the amount of Chemical B is  on vertical axis =  2 grams

                                                                                             5 boxes

                                                                                       =0.4 g

Tracing the mass of Chemical A used 1.4 g it meets the line passing through the center at 4th line (4th box).

To get the amount of Chemical B is  on vertical axis = amount of Chemical B per box * the number of line (boxes).

To get the amount of Chemical B is  on vertical axis = 0.4 g * 4 lines (boxes)

                                                                                        = 1.6 g

Hence The amount of Chemical  B needed is 1.6 g.

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To find the length of the path r(t) = 7, ND, No, No, 3, 7+2, 3, 2+2 from t = 1 to t = 3, we need to calculate the sum of the lengths of each segment of the path.

Let's break down the given path into its individual segments:

Segment 1: 7 (length = |7 - ND| = 1)

Segment 2: ND (length = |ND - No| = 1)

Segment 3: No (length = |No - No| = 0)

Segment 4: No (length = |No - 3| = 3)

Segment 5: 3 (length = |3 - 7+2| = 6)

Segment 6: 7+2 (length = |7+2 - 3| = 6)

Segment 7: 3 (length = |3 - 2+2| = 1)

Now, let's calculate the total length of the path by summing up the lengths of each segment:

Total length = 1 + 1 + 0 + 3 + 6 + 6 + 1 = 18

Therefore, the length of the path from t = 1 to t = 3 is 18 units.

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g(x) = jawabannya A. g(x) = 7 - x2

Answer:

Check the steps given below.

Step-by-step explanation:

I hope this helps you

Answer:

n = 55

n+15 = 70

2n = 110

Step-by-step explanation:

these angles are called 'same-side interior angles' and are supplementary

so we can add them together and set them equal to 180

n+15 + 2n = 180

combine 'like terms' to get:

3n + 15 = 180

subtract 15 from each side to get:

3n = 165

divide each side by 3 to solve for 'n'

n = 165/3

n = 55

substitute 55 for 'n'

55+15 = 70

2(55) = 110

check: 70 + 110 = 180

The corresponding confidence interval is the narrowest for the 99% level of confidence, as higher confidence levels require wider intervals to provide increased certainty.

A confidence interval represents the range within which the true population parameter is likely to fall based on the sample data. The level of confidence indicates the probability that the true parameter lies within the interval.

When the level of confidence increases, the width of the confidence interval also increases. This is because a higher level of confidence requires a wider interval to capture a larger range of possible values.

In the given options, the 99% level of confidence will provide the narrowest confidence interval. This is because it allows for a higher margin of error and wider range, resulting in a narrower interval. On the other hand, lower confidence levels such as 90%, 95%, and 98% will have wider intervals to provide a higher level of certainty.

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