(a) we can determine the wavelength that leads to constructive interference and maximum reflection. (b)This can be achieved by finding the wavelength that corresponds to a phase difference of 180 degrees between the reflected waves from the two interfaces.
(a) To find the wavelength of visible light most strongly reflected, we use the formula for the reflection coefficient at an interface: R = |(n2 - n1)/(n2 + n1)|^2, where n2 is the index of refraction of the surrounding medium (water, with index 1.33) and n1 is the index of refraction of the film (with index +1.25). To achieve maximum reflection, the numerator of the formula should be maximized, which corresponds to a wavelength that creates a phase difference of 180 degrees between the waves reflected from the two interfaces. By solving for this wavelength, we can determine the color of the light most strongly reflected.
(b) To find the wavelength of visible blue light that is not seen to reflect at all, we need to consider the conditions for destructive interference. Destructive interference occurs when the phase difference between the waves reflected from the two interfaces is 180 degrees. By solving for the wavelength that satisfies this condition, we can determine the color of the light that is not reflected at all.
The specific colors corresponding to the calculated wavelengths would depend on the range of visible light. The visible light spectrum ranges from approximately 380 nm (violet) to 700 nm (red). Based on the calculated wavelengths, one can estimate the colors corresponding to the most strongly reflected light and the light that is not seen to reflect at all.
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HUUUUURRRRRYYYYY
Latent heat of fusion refers to which changes of state?
liquid to solid or solid to gas
solid to gas or gas to liquid
solid to liquid or liquid to solid
gas to liquid or liquid to gas
Answer:
solid to gas or gas to liquid
Explanation:
welcome
Answer:
solid to gas or gas to liquid
Explanation:
Edge
In the Capacitor Circuit Problem if the capacitor is placed in the closed circuit, and then you cut one of the wires in the circuit then O a. Only the capacitance changes. O b. Both the voltage across the capacitor and the charge on the capacitor changes. Oc. Only the voltage across the capacitor changes. O d. None of the above. O e. Only the charge on the capacitor changes
If the capacitor is placed in the closed circuit and one of the wires in the circuit is cut, only the voltage across the capacitor changes. The answer is c.
In a capacitor circuit, the voltage across the capacitor is related to the charge on the capacitor and the capacitance by the equation Q = CV, where Q is the charge on the capacitor, C is the capacitance, and V is the voltage across the capacitor.
When the wire in the circuit is cut, the charge on the capacitor remains constant because the capacitor acts like an open circuit, preventing the flow of current.
However, the voltage across the capacitor changes because the circuit is now incomplete, and there is no longer a closed path for the current to flow. The voltage across the capacitor will discharge over time due to its internal resistance until it reaches zero.
Therefore, option C is correct, and only the voltage across the capacitor changes.
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When you describe a liquid as thick, are you saying that it has a high or a low viscosity?
The liquid with greater thickness will be more viscous since it flow speed is lower. Therefore, the more thick liquids is more viscous and flow slowly.
What is viscosity ?Viscosity of a liquid is the resistance to its flow. Viscosity depends on the density and thickness of the liquid. The more thicker the liquid the more viscous it will be.
Less thick liquids will flow fastly. For example water is a less viscous liquid as we see it flow so quickly. Whereas, honey, oil, etc are more viscous and the mobility of their liquid particles are resisted by viscosity.
The more viscous liquids generally has higher specific heat capacity as in the case of water and oil. The particle - particle attractive force is higher in highly viscous liquids.
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There is some at the beginning of the time intervalall of the disappears before the end of the interval
Assuming that "some" refers to a certain quantity or amount of something, and "the" refers to that same thing, it seems that there is a specific amount of something present at the beginning of a given time interval, but by the end of that interval, all of it has disappeared.
There are a few possible explanations for why this might be the case. One possibility is that the thing in question is subject to decay or decomposition, meaning that it breaks down or dissolves over time. In this scenario, the initial amount of the substance would gradually decrease until it was completely gone by the end of the interval.
Another possibility is that the thing in question is being actively removed or consumed over the course of the time interval. For example, if "some" refers to a food item, it could be that the food is being eaten or otherwise used up by people or animals during the interval.
Without additional context or information about what "some" and "the" are referring to, it is difficult to say for sure what is happening. However, hopefully this explanation gives some insight into the possible reasons why "some" would disappear before the end of the interval.
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Photons with a frequency of 1.0 × 1020 hertz strike a metal surface. If electrons with a maximum kinetic energy of 3.0 x 10-14 joule are emitted, the work function of the metal is
1. 1.0 x 10-14 J
2. 2.2 x 10-14 J
3. 3.6 x 10-14 J
4. 6.6 x 10-14 J
Photons with a frequency of 1.0 × 1020 hertz strike a metal surface. If electrons with a maximum kinetic energy of 3.0 x \(10^-^1^4^\) joule are emitted, the work function of the metal is . 3.6 x\(10^-^1^4^\) J.
The correct answer is option 3.
To determine the work function of the metal, we can use the equation:
E = hf - ϕ
where:
E is the energy of the emitted electron,
h is Planck's constant (6.626 × \(10^-^3^4\) J·s),
f is the frequency of the photons,
ϕ is the work function of the metal.
Given:
Frequency of photons (f) = 1.0 × \(10^2^0\)Hz
Maximum kinetic energy of emitted electron (E) = 3.0 × \(10^-^1^4^\) J
We can rearrange the equation to solve for the work function:
ϕ = hf - E
Substituting the given values, we have:
ϕ = (6.626 × \(10^-^3^4\) J·s)(1.0 ×\(10^2^0\) Hz) - (3.0 × \(10^-^1^4^\) J)
Simplifying the equation, we get:
ϕ = 6.626 × \(10^-^1^4^\) J - 3.0 ×\(10^-^1^4^\)J = 3.626 × \(10^-^1^4^\) J
Comparing this value to the given options, we find that the closest option is:
3. 3.6 x \(10^-^1^4^\) J
Therefore, the correct option is option 3: 3.6 x \(10^-^1^4^\)J.
This indicates that the work function of the metal, which represents the minimum energy required to remove an electron from the metal surface, is approximately 3.6 x\(10^-^1^4^\) J.
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What is your centripetal acceleration when you run at 11 m/s around the curve of an Olympic track, which has a radius of 36.5 m?answer choices0.30 m/s21.2 m/s23.3 m/s22.4 m/s2
22.4 m/s² has a radius of 36.5 m.
What is accelaration?Acceleration is the rate of change of velocity over time. It is expressed in terms of a vector quantity, with both magnitude and direction. Acceleration can be caused by the application of a force, such as gravity, or by changing the speed or direction of an object. In physics, acceleration occurs when an object changes its velocity, either by increasing or decreasing its speed or changing its direction. Acceleration is measured in meters per second squared (m/s²).
The centripetal acceleration when running at 11 m/s around the curve of an Olympic track, which has a radius of 36.5 m, is 22.4 m/s². The formula for centripetal acceleration is: a_c = v²/r, where v is the velocity and r is the radius. Using this formula, the centripetal acceleration is 11²/36.5, which equals 22.4 m/s².
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238 U + 92 write the complete nuclear equation
Answer:The equation is balanced for both charge and nucleon number, as required.
Explanation:2713Al + 42He → 3015P + n
HELP ASAP!
A train with mass of 3.1x104 kg is pushed by an engine with a force of 5.0x104N for a distance of 450.0 meters in 3.5 minutes.
How much work was done on the train? ________________J
What was the Power exerted by the train? ________________W
Work was done on the train 225x10⁵ J
Power exerted by the train 1.07 x 10⁵ W
Explain work and power?Work is the amount of energy transferred to an object when it is moved a certain distance by an external force. Since work is defined as the amount of energy (transferred), it has units of energy, and work usually has units of J (joules). The equation describing the work (W) done on a body moving a distance (s) while a force (F) is acting on it in the same direction as its motion is given by:
W = F × s
Where,
W = work done
F = force applied
s = displacement
We can define force as the rate of work. It is work done in a unit of time. The SI unit for power is the watt (W), which is the joule per second (J/s). The formula for power is:
P = W / t
Where,
P = Power
W = work done
t = time taken
Now for the given question:
W = F × s
F = 5.0x10⁴ N
s = 450.0 meters
W = 5.0x10⁴ x 450.0
W = 225x10⁵J
P = W / t
P = \(\frac{225}{210}\) x10⁵
P =1.07 x 10⁵ W
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What is the magnitude of the x-component of force ?
ANSWER
EXPLANATION
If force F keeps the object in equilibrium
Answer:
See below
Explanation:
Find the x components of all of the forces shown, add them together, the x-component of the force F will be exactly opposite ( same magnitude but 180 degrees different)
30 cos 55 + 40 cos 205 + 50 cos 320 = 19.26 <====x component sum of all of the forces shown
F (the x component of ) will be Either - 19.26 At zero degrees
Or 19.26 at 180 degrees
2. (05.01 LC)
Which statement is true about the speed of light? (2 points)
A: Light travels relatively slowly.
B: Distance in space is measured using the speed of light.
C: Time in space is measured using the speed of light.
D: The speed of light is unknown.
Answer:
The speed of light is used for the measurement of the time in space
Two vehicles are traveling when they enter an intersection and crash and stick together. Both have a mass of 1,650 kg and both are traveling at 15 m/s. If one is headed North and the other is headed East, after the collision they end up traveling NE together at what speed (in m/s)? Please input your answer as a positive number with two decimal places.
Answer:
10.61 m/s
Explanation:
To find the final speed, we will use the conservation of momentum in each direction, so we can write the following equations:
\(\begin{gathered} p_{ix}=p_{fx} \\ m_1v_{1x}+m_2v_{2x}=(m_1+m_2)v_{fx} \\ \text{and} \\ p_{iy}=p_{fy} \\ m_1v_{1y}+m_2v_{2y}=(m_1+m_2)v_{fy} \end{gathered}\)Where m1 and m2 are the mass of the vehicles, v1 and v2 are their respective velocities in each direction, and Vfx and Vfy are the final velocities in each direction.
If one of the vehicles is headed north, its horizontal velocity Vx = 0 m/s. In the same way if the other is headed east, its vertical velocity Vy = 0m/s
Therefore, we can replace the values and solve the first equation as:
\(\begin{gathered} 1650(0)+1650(15)=(1650+1650)v_{fx} \\ 24750=3300v_{fx} \\ \frac{24750}{3300}=v_{fx} \\ 7.5m/s=v_{fx} \end{gathered}\)In the same way, we can solve the second equation as:
\(\begin{gathered} 1650(15)+1650(0)=(1650+1650)v_{fy} \\ 24750=3300v_{fy} \\ \frac{24750}{3300}=v_{fy} \\ 7.5m/s=v_{fy} \end{gathered}\)Now, we know that the vertical and horizontal speed was 7.5 m/s. So, we can calculate the final speed using the Pythagorean theorem as:
\(\begin{gathered} v=\sqrt[]{(v_{fx})^2+(v_{fy})^2} \\ v=\sqrt[]{(7.5)^2+(7.5)^2} \\ v=\sqrt[]{56.25+56.25} \\ v=\sqrt[]{112.5}=10.61\text{ m/s} \end{gathered}\)So, the speed after the collision was 10.61 m/s
Consider a system consisting of three particles:
m1 = 3 kg, V ?1 = < 7, -4, 14 > m/s
m2 = 7 kg,V ? 2 = < -13, 12, -3 > m/s
m3 = 5 kg,V ? 3 = < -29, 34, 18 > m/s
What is the total momentum of this system?
P ?tot = (-215, 242, 111) kg -m/s
What is the velocity of the center of mass of this system?
V ?cm = (-14.33, 16.13, 7.4) m/s
What is the total kinetic energy of this system?
Ktot = ???? J
What is the translational kinetic energy of this system?
Ktrans = ??? J
What is the kinetic energy of this system relative to the center of mass?
Krel = ??? J
a. The translational kinetic energy of this system ( K trans) is 3462.112 J
b. The kinetic energy of this system relative to the center of mass (Krel) is (-4720.612, -357.112, -2463.112) J
To find the total kinetic energy of the system, we need to calculate the kinetic energy of each particle and add them together.
The kinetic energy of a particle is given by:
K = 1/2 mv^2
where m is the mass of the particle and v is its velocity.
For particle 1:
K1 = 1/2 * 3 kg * (7, -4, 14) m/s^2 = (73.5, -42, 220.5) J
For particle 2:
K2 = 1/2 * 7 kg * (-13, 12, -3) m/s^2 = (-318.5, 252, -31.5) J
For particle 3:
K3 = 1/2 * 5 kg * (-29, 34, 18) m/s^2 = (-1012.5, 2895, 810) J
The total kinetic energy of the system is the sum of the kinetic energies of the particles:
Ktot = K1 + K2 + K3
= (73.5 - 318.5 - 1012.5, -42 + 252 + 2895, 220.5 - 31.5 + 810) J
= (-1257.5, 3105, 999) J
To find the translational kinetic energy of the system, we need to find the velocity of the center of mass and use it to calculate the total kinetic energy of the system as if all the mass were concentrated at the center of mass.
The velocity of the center of mass is given by:
Vcm = (m1V1 + m2V2 + m3V3) / (m1 + m2 + m3)
where V1, V2, and V3 are the velocities of the particles, and m1, m2, and m3 are their masses.
Plugging in the values, we get:
Vcm = (3 kg * <7, -4, 14> m/s + 7 kg * <-13, 12, -3> m/s + 5 kg * <-29, 34, 18> m/s) / (3 kg + 7 kg + 5 kg)
= (-215/15, 242/15, 111/15) m/s
= (-14.33, 16.13, 7.4) m/s
The total kinetic energy of the system as if all the mass were concentrated at the center of mass is given by:
Ktrans = 1/2 (m1 + m2 + m3) |Vcm|^2
Plugging in the values, we get:
Ktrans = 1/2 (3 kg + 7 kg + 5 kg) |(-14.33, 16.13, 7.4) m/s|^2
= 1/2 (15 kg) (461.0149 m^2/s^2)
= 3462.112 J
To find the kinetic energy of the system relative to the center of mass, we need to subtract the translational kinetic energy from the total kinetic energy:
Krel = Ktot - Ktrans
= (-1257.5, 3105, 999) J - 3462.112 J
= (-4720.612, -357.112, -2463.112) J
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A 1,725 kg car accelerates from 3.0 m/s for 4.4 s and reaches a velocity of 12.0 m/s. Ignoring friction, what is the applied force from the engine?
Given:
The mass of the car is m = 1725 kg
The initial velocity of the car is
\(v_i=\text{ 3 m/s}\)The final velocity of the car is
\(v_f=\text{ 12 m/s}\)The time is t = 4.4 s
To find the applied force.
Explanation:
The force can be calculated by the formula
\(F=\text{ ma}\)Here, a is the acceleration.
The acceleration can be calculated as
\(\begin{gathered} a=\frac{v_f-v_i}{t} \\ =\frac{12-3}{4.4} \\ =2.045\text{ m/s}^2 \end{gathered}\)On substituting the values, the force applied will be
\(\begin{gathered} F=ma \\ =1725\times2.045 \\ =3527.625\text{ N} \end{gathered}\)Thus, the applied force is 3527.625 N
Which of the following should not be used as a primary key in a table?.
A primary key is a database table's unique identifier. This key distinguishes each row in a table from the others.
There are certain things that should not be used as a primary key in a table.
One such thing is: Meaningful names should not be used as a primary key in a table.
A primary key is a database table's unique identifier. It distinguishes one row from another in a table.
The primary key can also be used to connect with other tables. It has a different value for each row in a table.
The primary key can be one or more columns. It can be a single column or a collection of columns.
It can't have a null value. It must always be unique and never change in a table.
The following should not be used as a primary key in a table:
Meaningful names: Avoid using a meaningful name as a primary key.
Because when the column name changes, the primary key will also change.
For example, if you're using a student's name as the primary key, you'd have to update it every time the student's name changes. It's not a good idea to use meaningful names as primary keys.
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If you rub a glass rod with a piece of silk, the rod becomes positively charged. This means that
Protons have moved to the rod
Friction destroyed the electrons in the rod
The silk has become negatively charged
Glass attracts more protons
Answer:
The silk has become negatively charged
what does vapor lock cause? it makes your vehicle's interior steamy, as all the vapor stays inside. it causes the power steering fluid to evaporate and lock the steering wheel. it causes the engine to run roughly or stall. it causes the brake fluid to evaporate and will lock the vehicle's brakes.
Vapor locks can cause a variety of issues in a vehicle.
When vapor lock occurs, it can lead to the engine running roughly or even stalling. This happens because the fuel vaporizes before it reaches the engine, causing a lack of fuel and thus a lack of power. Additionally, vapor lock can cause the power steering and brake fluid to evaporate, leading to a loss of control over the vehicle's steering and brakes. The vehicle's interior may also become steamy as the vapor remains trapped inside. To prevent vapor lock from occurring, it's important to ensure that the vehicle's fuel system is functioning properly and that there is adequate ventilation to prevent the buildup of excess heat and pressure.
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if a truck is accelerating at 39 MSS and it crashes into a tree within 45,000 in a force what was the mass of the truck?
Answer:
Mass of the truck is \(1154\) Kg
Explanation:
As we know that
Force is the product of mass and acceleration.
F = m * a
Here acceleration, a \(= 39\) m/s^2
Force, F \(= 45000\) Newton
Mass = \(\frac{F}{a}\)
Mass
\(= \frac{45000}{39} \\= 1154\) Kg
. Since the man is walking at a constant velocity, he has what acceleration
Low-energy lightbulbs currently cost $3.60, have a life of 9 years, and currently use $2.00 of electricity per year. Conventional lightbulbs are cheaper to buy; they currently cost only $0.60. On the other hand, they last only 1 year and currently use $7.00 of electricity per year. If the real discount rate is 4%, what are the EACs for each lightbulb? Which lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb? a. EAC( Low-energy lightbulb )=2.48 EAC( Conventional lightbulb )=7.62 Low-energy lightbulb is cheaper to operate b. EAC( Low-energy lightbulb )=3.60 EAC( Conventional lightbulb )=0.60 Conventional lightbulb is cheaper to operate c. EAC( Low-energy lightbulb) =2.00 EAC( Conventional lightbulb )=7.33 Low-energy lightbulb is cheaper to operate d. EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate
EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate. Option D
Energy cost calculationTo calculate the Equivalent Annual Costs (EAC), we need to consider the initial cost, maintenance costs, and the present value of future costs, taking into account the discount rate.
The EAC (Equivalent Annual Cost) is calculated by summing up the annual costs of the lightbulb over its lifetime, discounted at the real discount rate of 4%.
For the low-energy lightbulb:
EAC = Cost of bulb + Present value of annual electricity cost
= $3.60 + ($2.00 / (1 + 0.04)^1) + ($2.00 / (1 + 0.04)^2) + ... + ($2.00 / (1 + 0.04)^9)
≈ $18.47
For the conventional lightbulb:
EAC = Cost of bulb + Present value of annual electricity cost
= $0.60 + ($7.00 / (1 + 0.04)^1) + ($7.00 / (1 + 0.04)^2) + ... + ($7.00 / (1 + 0.04)^1)
≈ $7.33
Since the EAC for the low-energy lightbulb is $18.47 per year and the EAC for the conventional lightbulb is $7.33 per year, the conventional lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb.
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why is g called the universal gravitational constant
Explanation:
Hey there!
Universal gravitation constant (g) is the force of gravitation produced between two bodies of unit mass each separated by unit distance between their centers. The value of universal gravitation constant (g) is 6.67 Nm²/kg², which is constant all over the world. So, that's why it is called universal gravitation constant.
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Law of Reflection :
The law of reflection states that when light rays strike a smooth surface, the angle of reflection equals the angle of incidence, and the incident ray, reflected ray, and normal to the surface all lie in the same plane.
Here, let us consider, the ray A as the normal , as it is perpendicular to the surface of the plane mirror. When the incident ray hits the plane mirror at an angle say, θ with the normal ( here, incident ray A) , then, θ will be the angle of reflection.
Now if we consider all the incident rays A, B, C and D. Among them, let the ray C make an angle Θ, with the normal ( here, incident ray A).
Therefore, from the image given, clearly, θ = Θ, hence Θ is the angle of reflection, thus ray C best represents the reflected ray.
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Plz guys answer my question
Two spherical balloons are filled with water. The first balloon has a radius of 3 cm, and the second has a radius of 6 cm. How much greater is the volume of water in the larger balloon than in the smaller balloon? Use 3. 14 to approximate pi. Round to the nearest hundredth if necessary. Enter your answer as a decimal in the box.
Answer:
V = 4/3 R^3
V2 / V1 = (R2 / R1)^3 = 2^3 = 8
8.00
The volume of water in the larger balloon is 8 times greater than in the smaller balloon
We'll begin by calculating the volume of each balloon.
For smaller balloon:Radius (r) = 3 cmPi (π) = 3.14Volume (V) =?V = 4/3 πr³
V = 4/3 × 3.14 × 3³
V = 113.04 cm³For larger balloon:Radius (r) = 6 cmPi (π) = 3.14Volume (V) =?V = 4/3 πr³
V = 4/3 × 3.14 × 6³
V = 904.32 cm³Finally, we shall determine how much greater the larger balloon is to the smaller balloon
Volume of smaller balloon = 113.04 cm³Volume of larger balloon = 904.32 cm³Greatness =?Greatness => large / small
Large / small = 904.32 / 113.04
Large / small = 8
Cross multiply
Large = 8 × smallTherefore, the larger balloon is 8 times greater than the smaller balloon.
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If a current of 23A flows through a circuit and the battery produces a potential difference of 9V, calculate the resistance.
The resistance of the battery if a current of 23A flows through a circuit and the battery produces a potential difference of 9V is 0.39 ohms.
How to calculate resistance?Resistance is the force that tends to oppose motion. It is measured in ohms. The resistance of a battery can be calculated using the following formula;
V = IR
Where;
V = voltage (volts)R = resistanceI = currentAccording to this question, a current of 23A flows through a circuit and the battery produces a potential difference of 9V. The resistance can be calculated as follows:
R = V/I
R = 9/23
R = 0.39ohms
Therefore, 0.39ohms is the resistance of the battery.
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Compare the two waves. Wave A ___ (check all that apply)
Group of answer choices
has more energy
has a greater amplitude
has a lower amplitude
has a higher frequency
has less energy
has a lower frequency
Answer:
has more energy, has a greater amplitude, has a higher frequency
Explanation:
What is the total time, in minutes, of a car that traveled 60 km at a speed of 20 km/hr?
The total time, in minutes, of a car that traveled 60km at a speed of 20km/hr is 3 hours.
How to calculate speed?Average speed is the rate of motion or action or specifically the magnitude of the velocity.
The average speed of a body can be calculated by dividing the distance moved by the time taken as follows:
Average speed = Distance/time
According to this question, a car traveled 60 km at a speed of 20 km/hr. The time taken can be calculated as follows:
Time = 60km ÷ 20km/hr
Time = 3hr
Therefore, the total time, in minutes, of a car that traveled 60km at a speed of 20km/hr is 3 hours.
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The force of gravity on an object varies directly with its mass. The constant of variation due to gravity is 32. 2 feet per second squared. Which equation represents F, the force on an object due to gravity according to m, the object’s mass? F = 16. 1m F = F equals StartFraction 16. 1 Over m squared EndFraction. F = 32. 2m F = F equals StartFraction 32. 2 Over m squared EndFraction.
Answer:
F = 32.2 m
Explanation:
F = ma
F = m * 32.2
Jaune moves North 15 meters, South 5 meters, then North 8 meters. How far is Jaune DISPLACED?
Answer:
Displacement = 7 meters
Explanation:
Given that,
Jaune moves North 15 meters, South 5 meters, then North 8 meters. We need to find the displacement of Jaune.
The attached figure shows the motion of Jaune.
We know that, Displacement = final position - initial position
Initially, Jaune traveled 15 meters due North and finally, he travel 8 meters North.
Displcement = 15 m - 8 m
Displacement = 7 m
So, the displacement of Jaune is 7 meters.
what will you use to determine the magnitude and direction of the magnetic field produce by a current-carrying wire in investigation 1
To determine the magnitude and direction of the magnetic field produced by a current-carrying wire in Investigation 1, you can use Ampère's Law and the right-hand rule. Ampère's Law relates the magnetic field around a closed loop to the electric current passing through that loop.
In the case of a straight wire, the magnetic field forms concentric circles around the wire, with the field's strength decreasing as you move farther from the wire.
To calculate the magnitude of the magnetic field, you can use the formula B = (μ₀ * I) / (2 * π * r), where B represents the magnetic field strength, μ₀ is the permeability of free space (4π x 10⁻⁷ Tm/A), I is the current through the wire, and r is the distance from the wire to the point where the magnetic field is being measured.
For determining the direction of the magnetic field, you can use the right-hand rule. If you point your thumb in the direction of the current and curl your fingers, your fingers will wrap around the wire in the direction of the magnetic field. This means that if the current flows upward, the magnetic field will rotate clockwise around the wire when viewed from above.
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Chemical reactions provide support for the law of conservation of matter because which of the following is true about the atoms of the reactants and products in a chemical reaction?
Answer:
Explanatioit cn: