Write a multiplication sentence that you could use to calculate the volume for each rectangular pris
Problem 1. Include the units in your sentences.
a.
C.
REKA
TH*
TION
Student
Lesson 4:
b.
O Great Minds PBC TEKS Edition |
greatminds.org/Texas
d.
Use multiplication to calculate volume.how do I solve
The formulated sentences for each will be:
A: If length is 5cm, width 2cm, height 4cm, volume: 40 cubic centimeters.
B: If the length is 3cm, width 4cm, height 2cm, then Volume is: 24 cubic centimeters.
C: If the length is 6cm, width 2cm, height 3cm, the volume is 36 cubic centimeters.
D: If the length is 3cm, width 2cm, height 4cm, the volume 24 cubic centimeters.
What is the rectangular prism?To calculate the volume of a rectangular prism using multiplication, you need to multiply the length, width, and height of the prism. The multiplication sentence for this is:
Volume = length (m) x width (m) x height (m)
For a. The multiplication sentence for calculating the volume of rectangular prism C is:
Volume = Length x Width x HeightVolume = 6 cm x 2 cm x 3 cmVolume = 36 cubic centimetersb. The multiplication sentence for calculating the volume of rectangular prism B is:
Volume = Length x Width x HeightVolume = 3 cm x 4 cm x 2 cmVolume = 24 cubic centimetersc. The multiplication sentence for calculating the volume of rectangular prism C is:
Volume = Length x Width x HeightVolume = 6 cm x 2 cm x 3 cmVolume = 36 cubic centimetersLastly, for d. The multiplication sentence for calculating the volume of rectangular prism D is:
Volume = Length x Width x HeightVolume = 3 cm x 2 cm x 4 cmVolume = 24 cubic centimetersLearn more about rectangular prism from
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Show work for either one thanks
The maximum velocity of the pendulum is determined as 3.03 m/s.
Maximum velocity of the pendulum
The maximum velocity of the pendulum is calculated from the principle of conservation of energy as shown below;
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
h is the maximum height = 0.468 mv is the maximum velocityv = √(2 x 9.8 x 0.468)
v = 3.03 m/s
Thus, the maximum velocity of the pendulum is determined as 3.03 m/s.
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A block of weight 5 N is placed on a horizontal turntable. The maximum friction that can be developed between the block and the turntable is 2 N. If the turntable is rotating at 0.6 revolution per second, what is the greatest distance of the block from the center of rotation so that it does not slip?
The greatest distance of the block from the center of rotation so that it does not slip is approximately 0.089 meters or 8.9 centimeters.
In order for the block to remain on the turntable without slipping, the frictional force between the block and the turntable must be equal to or less than the maximum friction that can be developed, which is 2 N in this case. The maximum frictional force is given by the product of the coefficient of friction and the normal force.The normal force is equal to the weight of the block, which is 5 N. Therefore, the maximum frictional force is 2 N.
To find the greatest distance of the block from the center of rotation without slipping, we need to consider the centrifugal force acting on the block due to the rotation of the turntable. The centrifugal force is given by the product of the mass of the block, the acceleration due to the rotation (which is equal to the square of the angular velocity times the radius), and the coefficient of friction.
Since the weight of the block is 5 N, the mass can be calculated as 5 N divided by the acceleration due to gravity (approximately 9.8 m/s^2), which gives us a mass of approximately 0.51 kg.
Given that the turntable is rotating at 0.6 revolution per second, the angular velocity can be calculated as 2π times the frequency, which gives us approximately 3.77 rad/s.
Let's assume the greatest distance of the block from the center of rotation is "r" meters.
The centrifugal force is then given by m * (ω^2) * r, and this force must be equal to or less than the maximum frictional force, which is 2 N.
Therefore, we can write the equation:
m * (ω^2) * r ≤ 2 N
Substituting the values we calculated:
0.51 kg * (3.77 rad/s)^2 * r ≤ 2 N
Simplifying the equation, we find:
r ≤ 0.089 m
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Describe the setup of the electromagnet. Why does the wire need to be a conductive material?
An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.
An electromagnet is a type of magnet that is created by running an electrical current through a wire. The setup of an electromagnet involves a few basic components. First, there must be a wire that is conductive, meaning that it can conduct electricity. This wire is usually wrapped around a core, which is often made of iron, steel, or another magnetic material. When an electrical current is run through the wire, it creates a magnetic field around the wire. This magnetic field then magnetizes the core, creating an even stronger magnetic field. The strength of the electromagnet can be controlled by adjusting the amount of current that is run through the wire. The wire must be a conductive material because it needs to be able to carry the electrical current that creates the magnetic field. If the wire were not conductive, then the electrical current would not be able to flow through it, and the magnetic field would not be created. In summary, the setup of an electromagnet involves a conductive wire wrapped around a magnetic core, which is magnetized by the electrical current running through the wire. The wire must be conductive to carry the electrical current and create the magnetic field.For more questions on electromagnet
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A 5kg mass is pushed with a force of 10N for a distance of 2.5 meters. The work done is
W = 25 J
Explanation:
Work done on an object is defined as
\(W = Fd = (10\:\text{N})(2.5\:\text{m}) = 25\:\text{J}\)
The universal law of gravitation states that the force of attraction between two objects depends on which quantities?
the masses of the objects and their densities
the distance between the objects and their shapes
the densities of the objects and their shapes
the masses of the objects and the distance between them
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Subm
Kandretum
Answer:depends on the masses of the objects and the distance between them
Explanation:
According to Newton's law of universal gravitation,the force of attraction between two objects depends on the masses of the objects and the distance between them
Plz help I don’t know what to do
A basketball is picked up off the ground and carried to the top of a platform that is 160 feet up. It is then dropped to the ground. The ball rebounds one-half the height each time it hits the ground. What is the total vertical distance the ball will travel from the moment it is picked up to the moment it reaches its maximum height after the fourth bounce
Answer:
Explanation:
The total distance travelled by ball before first bounce
= 160 + 160 = 320 ft
Distance travelled between first bounce and second bounce
= 80 + 80 = 160 ft
Distance travelled between second bounce and third bounce
= 40 + 40 = 80 ft
Distance travelled between third bounce and fourth bounce
= 20 + 20 = 40 ft .
Distance travelled in fourth bounce = 10 ft
Total distance travelled = 320 + 160 + 80 + 40 + 10
= 610 ft .
mention two similarities of citizen and aliens
Answer:
The main points of difference between a citizen and alien are: (a) A citizen is a permanent resident of a state, while an alien is a temporary resident, who comes for a specific duration of time as a tourist or on diplomatic assignment. ... Aliens do not possess such rights in the state where they reside temporarily
Explanation:
A long straight conducting rod carries a current I with a non-uniform current density J = ar2, and has a radius R. The value of the constant is 28.5 A/mm4 and the radius of the rod is 5.20 mm. Determine the magnitude of the magnetic field at the following points.(a) r1 = R/2(b) r2 = 2R
The magnetic field is just a unit vector that explains the electromagnetic influence on electric currents, current flow, and magnetic fluids.
Magnetic field:Current density \(J = ar^2\)
value of the constant is= \(28.5 \ \frac{A}{mm^4}\)
radius = 5.20 mm
magnetic permeability \(\mu = 4\pi \times 10^7 \ \frac{N}{A^2}\)
calculating the area element for the straight circular conduction rod
:
\(d_A=2\pi r dr\)
Calculating the current, which is carried in the rod
\(dI = \int dA \vec{J}\)
Calculating the above equation with the limit value that is 0 to r.
\(I^{1}=\int_{0}^{r} ar^2 \times 2 \pi \cdot r d_r\)
\(=2\pi a\int_{0}^{r} r^3 d_r \\\\=\frac{\pi ar^4}{2}\)
The calculated current value which is carried by the rod is \(\boxed{\frac{\pi ar^4}{2}}\)
In option (a)
calculating the magnitude of the magnetic field at the point \(r_1= \frac{R}{2}\)
\(\to B=\frac{\mu_{0} I^{1}}{2 \pi r}\\\\\to B \times 2\pi r= \mu_{0} (\frac{\pi a}{2}r^4)\\\\\to B \times 2\pi = \mu_{0} (\frac{\pi a}{2}r^3)\\\\\to B= \frac{\mu_{0}}{4}r^3 a\\\\\)
Substituting the above value:\(\frac{R}{2} \ for \ r\)
\(B= \frac{\mu_{0}}{4}(\frac{R}{2})^3 a\)
\(B= \frac{4 \pi \times 10^{-7}}{4}(\frac{5.2 \times 10^{-3}}{2})^3 \frac{28.5}{10^{-12}}\)
\(= \frac{4 \pi \times 10^{-7}}{4} \times \frac{140.608 \times 10^{-9}}{8} \times \frac{28.5}{10^{-12}}\\\\= \frac{ 3.14 \times 10^{-7}}{1} \times \frac{140.608 \times 10^{-9}}{8} \times \frac{28.5}{10^{-12}}\\\\=\frac{1572.87624 \times 10^{-16}}{ 10^{-12}}\\\\=0.157 \ \ T\)
Thus, the magnitude of the magnetic field at the point \(r_1 =\frac{R}{2}\) is \(\boxed{0.157 \ T}\)
In option (b)
In this, we calculate the magnitude of the magnetic field at the point \(r_2= 2R\)
\(\to B=\frac{\mu_{0} I^{1}}{2 \pi r} \\\\\to B \times 2\pi r= \mu_{0} (\frac{\pi a}{2}R^4)\\\\\to B \times 2\pi 2R = \mu_{0} (\frac{\pi a}{2}R^3)\\\\\to B= \frac{\mu_{0}}{8}R^3 a\\\\\)
Substituting the values
\(B= \frac{4 \pi \times 10^{-7}}{8}(5.2 \times 10^{-3})^3(\frac{28.5}{10^{-12}})\)
\(= \frac{4 \times 3.14 \times 10^{-7}}{8} \times (5.2)^3 \times (10^{-3})^3 \times\frac{28.5}{10^{-12}}\\\\= \frac{ 3.14 \times 10^{-7}}{2} \times 140.608 \times 10^{-9} \times\frac{28.5}{10^{-12}}\\\\= 6291.50495 \times 10^{-4}\\\\= 0.629 \ \ or \ \ 0.63\\\)
Thus, the magnitude of the magnetic field at the point \(r_2 = 2R\) is \(\boxed{0.63 \ \ T}\)
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help me get the answer in Physical Science.
Answer:
lithium
Explanation:
I took physical science 2 years ago and passed with an A
A mechanical lift is used to pull an engine out of a car. The engine is attached
to the lift with chains and lifted straight up. The free-body diagram below
shows the engine when it is suspended in the air.
Force 1
Force 2
What is force 2 in this diagram?
O A. Weight
B. Tension
C. Normal force
D. Friction
Answer:
the answer is weight
Explanation:
Answer:
Weight
Explanation: Just took the quiz
What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
Oarea in contact between the two substances
specific heat of the material that makes up the substances
density of the two substances in contact
Answer:
The characteristics that determine how easily two substances change temperature are:
specific heat of the material that makes up the substancesarea in contact between the two substancesThe volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.
Explanation:
HELPPPPPP
i need to turn this assignment in soon!
Answer:
A B C
Explanation:
I think that is right. Sorry if it's not
Hope this helps :)
What force will counterbalance two forces 4.0 N and 5.0 N acting perpendicular to each other?
The force that will balance the two forces is 6.4 N
Data obtained from the questionForce 1 (F₁) = 4 NForce 2 (F₂) = 5 NResultant force (F)The resultant force, F can be obtained as follow:
F = √(F₁² + F₂²)
F = √(4² + 5²)
F = √(16 + 25)
F = √41
F = 6.4 N
Thus, the force that will balance the two forces is 6.4 N
See attached photo
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The force that will counterbalance two forces 4.0 N and 5.0 N acting perpendicular to each other is a force of 6.4 N acting in an opposite direction to the resultant of the two forces.
Equilibrant of forcesThe equilibrant of two or more forces is that single force which will have the same effect as the resultant of two or more forces but which is acting in a direction opposite to that of the resultant force.The Resultant of the two forces 4.0 N and %.0 N acting perpendicular to each other is calculated using the formula:
R² = A² + B²
where A and B are the two forces acting perpendicular to each other.
R² = 4² + 5²
R² = 41
R = 6.4 N
Therefore, the force that will counterbalance two forces 4.0 N and 5.0 N acting perpendicular to each other is a force of 6.4 N acting in an opposite direction to the resultant of the two forces.
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Spring is a time when animals reproduce. What might you see a heron do? Build a nest A. Grow feathers A. Hibernate Migrate
Answer:
A. Build a nest.
Explanation:
It wont do any of the other things and they need a place to sleep and lay eggs plus it is a bird
The heron birds belong to Ardeidae family. Some of the species among them are referred to as egrets or bitterns rather than a heron. A heron bird build a nest during Spring. The correct option is A.
What is Heron bird?The heron is known as a long-legged, long-necked, fresh water and coastal birds. It a medium to large size bird with long necks and legs. They exhibit sexual dimorphism in size. The two male and female sex of the same species show distinct attributes beyond their difference in sexual organs.
Almost all the heron species are found in water and they are essentially non-swimming water birds which feed on the margins of lakes, ponds, sea, rivers and swamps. The small species of heron are generally referred to as the dwarf bittern.
The nesting season indicates the time of year during which birds build nests and lay eggs in them. In most cases bring up their young. It is in the spring season lot of food are available.
Thus the correct option is A.
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if you lift an apple from the ground to some point above the ground, the gravitational potential energy in the system increases
Question 4 (Mandatory) (1 point)
MS-PS1-2: Which is an example of a chemical reaction?
Examples of reactions could include burning sugar or steel wool, fat reacting with sodium hydroxide, and mixing zinc with hydrogen chloride.
Define chemical reaction?A chemical reaction is a process that transforms one set of chemical substances into another.A chemical reaction is a process that converts one or more substances, known as reactants, into one or more different substances, known as products.Chemical elements and compounds are both examples of substances.Chemical reactions involve the formation of new bonds between atoms in product particles and the breaking of chemical bonds between reactant molecules (particles). The number of atoms is the same before and after the chemical change, but the number of molecules is different.When chemical bonds between atoms form or break, chemical reactions occur.To learn more about chemical reaction refer to:
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Find the principal stresses and corresponding principal directions for the stresses given in Problem 2.6. Check the result with other methods such as Mohr's circle.
The principal stresses and corresponding principal directions for the stresses in a problem can be found using various methods, one of which is Mohr's circle.
What is Mohr's circle?
Mohr's circle is a graphical representation of a two-dimensional stress state. Given the stress tensor components, the Mohr's circle can be used to visualize and determine the maximum and minimum normal stresses (i.e., the principal stresses) and the orientation of the planes on which they act (i.e., the principal directions).
It is important to note that finding the principal stresses and directions requires a thorough understanding of stress analysis, including stress transformation and the use of Mohr's circle. If you have access to the full problem statement, I would be happy to help you work through the solution.
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A mass attached to a vertical spring has position function given by s(t)=4sin(2t)where t is measured in seconds and s in inches.
Given data:
The position function of spring is s(t)=4sin(2t).
By differentiating the given position function with respect to time is the velocity of the system. It can be calculated as,
\(\begin{gathered} s(t)=4\sin (2t) \\ \frac{d}{\mathrm{d}t}s(t)=\frac{d}{\mathrm{d}t}(4\sin (2t)) \\ v(t)=4\cos (2t)\times2 \\ v(t)=8\cos (2t) \end{gathered}\)The acceleration of the system can be calculated by differentiating above velocity function with respect to time,
\(\begin{gathered} v(t)=8\cos (2t) \\ \frac{d}{\mathrm{d}t}v(t)=\frac{d}{\mathrm{d}t}(8\cos (2t)) \\ a(t)=-8\sin (2t)\times2 \\ a(t)=-16\sin (2t) \end{gathered}\)The velocity at t=2 s will be,
\(\begin{gathered} v(t)=8\cos (2t) \\ v(2)=8\cos (2\times2) \\ v(2)=8\cos 4 \\ v(2)=-5.23\text{ m/s} \end{gathered}\)The acceleration at t=2 will be,
\(\begin{gathered} a(t)=-16\sin (2t) \\ a(2)=-16\sin (2\times2) \\ a(2)=-16\sin (4) \\ a(2)=-12.1m/s^2 \end{gathered}\)Thus, the velocity and acceleration at t=2 is -5.23 m/s and -12.1 m/s² respectively.
Two students are sitting 1.50 m apart. One student has a mass of 70.0 kg and
the other has a mass of 52.0 kg. What is the gravitational force between them?
A. 8.01 x 10-9
B. 1.08 x 10-2
C. 2.28 x 10-8
Answer:
B
Explanation:
Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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PLS HELP ASAP (no links) The volume and density of a particular substance is dependent upon its
A. weight
B. length
C. state of matter
A plastic ball in a liquid is acted upon by its weight and by a buoyant force. The weight of the ball is 4 N. The buoyant force has a magnitude of 5 N and acts vertically upward. When the ball is released from rest, what is it's acceleration and direction? [2 pts] for a Free Body Diagram correctly labeled.
Answer:
The acceleration is 2.448 meters per square second and is vertically upward.
Explanation:
The Free Body Diagram of the plastic ball in the liquid is presented in the image attached below. By Second Newton's Law, we know that forces acting on the plastic ball is:
\(\Sigma F = F - m\cdot g = m\cdot a\) (1)
Where:
\(F\) - Buoyant force, measured in newtons.
\(m\) - Mass of the plastic ball, measured in kilograms.
\(g\) - Gravitational acceleration, measured in meters per square second.
\(a\) - Net acceleration, measured in meters per square second.
If we know that \(F = 5\,N\), \(m = 0.408\,kg\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the net acceleration of the plastic ball is:
\(a = \frac{F}{m} - g\)
\(a= 2.448\,\frac{m}{s^{2}}\)
The acceleration is 2.448 meters per square second and is vertically upward.
Determine which characteristics are chemical properties. Explain. A) IV. This property can only be determined by chemical reacting the sample of sulfur. B) I and II. These properties can only be determined by chemical reacting the sample of sulfur. C) III. These properties can be determined by physical measurements. The sulfur does not need to react, chemically, in order to measure these properties. D) III and IV. These properties can be determined by physical measurements. The sulfur does not need to react, chemically, in order to measure these properties.
Answer:
Explanation:
The choices are:
A) IV. This property can only be determined by chemical reacting the sample of sulfur.
B) I and II. These properties can only be determined by chemical reacting the sample of sulfur.
C) III. These properties can be determined by physical measurements. The sulfur does not need to react, chemically, in order to measure these properties.
C) III. These properties can be determined by physical measurements. The sulfur does not need to react, chemically, in order to measure these properties.
The answer is A and B as both characteristics can only be determined by chemical reacting so they are chemical properties.
Answer:
a
Explanation:
i just did this on usatestprep.
8. A rectangle is measured to be 6.4 +0.2 cm by 8.3 $0.2 cm.
a) Calculate its perimeter in cm
b) Calculate the uncertainty in its perimeter.
Answer:
a) The perimeter of the rectangle is 29.4 centimeters.
b) The uncertainty in its perimeter is 0.8 centimeters.
Explanation:
a) From Geometry we remember that the perimeter of the rectangle (\(p\)), measured in centimeters, is represented by the following formula:
\(p = 2\cdot (w+l)\) (1)
Where:
\(w\) - Width, measured in centimeters.
\(l\) - Length, measured in centimeters.
If we know that \(w = 6.4\,cm\) and \(l = 8.3\,cm\), then the perimeter of the rectangle is:
\(p = 2\cdot (6.4\,cm+8.3\,cm)\)
\(p = 29.4\,cm\)
The perimeter of the rectangle is 29.4 centimeters.
b) The uncertainty of the perimeter (\(\Delta p\)), measured in centimeters, is estimated by differences. That is:
\(\Delta p = 2\cdot (\Delta w + \Delta l)\) (2)
Where:
\(\Delta w\) - Uncertainty in width, measured in centimeters.
\(\Delta l\) - Uncertainty in length, measured in centimeters.
If we know that \(\Delta w = 0.2\,cm\) and \(\Delta l = 0.2\,cm\), then the uncertainty in perimeter is:
\(\Delta p = 2\cdot (0.2\,cm+0.2\,cm)\)
\(\Delta p = 0.8\,cm\)
The uncertainty in its perimeter is 0.8 centimeters.
4. What is the acceleration of a car that is going 50 m/s north and remains at that constant speed and direction for 10 seconds?1) 0.0 m/s/s2) 5 m/s/s3) - 5 m/s/s4) Not enough information
acceleration = change of speed / time
a = Δv / t
Since the speed remains constant, acceleration is zero.
1) 0.0 m/s
which of the following is an example of projectile motion?
a) a child tumbling down a hillside
b) a bowler rolling her ball down an alley
c) a football in flight during a field goal
d) a surfer riding a wave
Find the Equivalent Resistance for the circuit.
The equivalent resistance for the circuit, given that 188 ohms and 122 ohms are in parallel connection while the remaining resistors are in series connections is 1947 ohms
How do i determine the equivalent resistance?First, we shall obtain the equivalent resistance of 188 ohms and 122 ohms (i.e in parallel connection). Details below:
Resistor 1 (R₁) = 188 ohms Resistor 2 (R₂) = 122 ohmsEquivalent (R) = ?R = (R₁ × R₂) / (R₁ + R₂)
R = (188 × 122) / (188 + 122)
R = 74 ohms
Haven obtain the equivalent resistance of 188 ohms and 122 ohms, we shall determine the equivalent resistance for the circuit. Details below:
Resistor 1 (R₁) = 900 ohms Resistor 2 (R₂) = 125 ohmsEquivalent of 188 ohms and 122 ohms (R) = 74 ohmsResistor 4 (R₄) = 450 ohmsResistor 5 (R₅) = 398 ohmEquivalent resistance (Rₜ) = ?Rₜ = R₁ + R₂ + R + R₄ + R₅ (series connection)
Rₜ = 900 + 125 + 74 + 450 + 398
Rₜ = 1947 ohms
Thus, we can conclude that the equivalent resistance for the circuit is 1947 ohms
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When stable air is forced to rise, any clouds that are produced are generally thin and flat lying.
a) true
b) false
Answer:
a) true
Explanation:
One of the important factors behind the formation of clouds is the stability of the atmosphere. Air gets condensed with the increase in the height, while it becomes warm with a decrease in its height. A stable air is the type of air that can sink. The air which has low temperature has more density than the air it is surrounded by. When clouds are formed with stable air, the clouds formed are thin and horizontal.