Levi will take 19.23 seconds to accelerate uniformly to a stop, leaving 3 meters between Chimdi and his bumper.
To determine how long it will take for Levi's car to accelerate uniformly to a stop, we need to calculate the time it takes for the car to cover the distance between Chimdi and his bumper.
The initial distance between Levi's car and Chimdi is 99 meters, and he wants to leave 3 meters between them when the car comes to a stop. Therefore, the total distance the car needs to cover is 99 meters - 3 meters = 96 meters.
We also know that the car is traveling at a speed of 10 m/s. However, we need to convert this speed to meters per second squared (m/s²) to calculate the time for acceleration.
Let's assume the car decelerates uniformly. We can use the equation:
v^2 = u^2 + 2as,
where v is the final velocity (0 m/s since the car comes to a stop), u is the initial velocity (10 m/s), a is the acceleration, and s is the distance.
Rearranging the equation, we have:
a = (v^2 - u^2) / (2s)
a = (0^2 - 10^2) / (2 * 96)
a = -100 / 192
a ≈ -0.52 m/s²
The negative sign indicates deceleration.
Now, we can use the equation:
v = u + at,
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Substituting the known values, we have:
0 = 10 + (-0.52) * t
Simplifying, we find:
0 = 10 - 0.52t
0.52t = 10
t ≈ 19.23 seconds
Therefore, it will take approximately 19.23 seconds for Levi's car to accelerate uniformly to a stop, leaving 3 meters between Chimdi and his bumper.
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what is the critical angle of light traveling from vegetable oil into water
56.1∘
Question: A glass is half-full of water, with a layer of vegetable oil (n = 1.47) floating on top. A ray of light traveling downward through the oil is incident on the water at an angle of 56.1∘ .
A glass is half-full of water, with a layer of vegetable oil (n ...https://study.com › academy › answer › a-glass-is-half-ful...
a b) what is the Change of density due to a rise in temperature OF 500k. The Coefficient of linear expansion of the material is 12x10-6
1. Define the law of conservation of momentum in your own words.
2. Which of Newton's laws explains how momentum is conserved in all interactions between objects?
3. What do you know about the forces involved in an interaction between two objects?
4. Is momentum a vector or a scalar quantity? Based on your answer, which other value is important
besides the numerical value of momentum?
5. How do you find the total momentum of objects in a system?
6. If objects are traveling in opposite directions, what do you know about the signs of their momenta?
7. What characteristics are required for a system to be considered closed and isolated?
8. What forces are considered when we examine interactions between two objects in a closed, isolated
system?
9. If two objects begin at rest, what is the total momentum of the system before they push off from one
another? What is the momentum of the system after they push off from one another?
1. Total momentum of an isolated system before collision is always equal to total momentum after collision is called conservation of momentum.
2. Newton's third law explains how momentum is conserved in all interaction between objects.
3. Force is an unopposed interaction between two or more bodies that apply the shift in the objects state of motion. The action and reaction are two interacting forces that we called as Newton's third law of motion. There are two forces acting on two interacting objects in any interaction.
4. Momentum is a vector quantity and has the same direction as velocity. It is the product of mass (a scalar quantity) and velocity (a vector quantity).
5. To find total momentum of the system , add their individual momentums together. Calculate momentum for each object by using formula P=mv, where P is momentum, m is mass, v is velocity.
6. If the objects are travelling in opposite direction, then the overall momentum will be zero. They have same mass and velocity, when their momentum vectors add up to exactly zero when added together.
7. Closed system in which the exchange of only energy with its surroundings takes place. An isolated system in which no exchange of matter or energy takes place.
8. The internal forces are considered when we examine interaction between two objects in a closed and isolated system because these forces cause momentum of the system to be transferred between one object to another.
9. Before the push-off, the total initial momentum is zero. The total momentum after the push-off should also be zero.
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A wave where the oscillation is parallel to the motion is a _______ wave
A-standing
B-longitudinal
C-transverse
If a 9000kg water flows in a minute through a pipe of cross sectional area 0.3m², what is the speed of water in the pipe?
Answer:
5 m/s
Explanation:
We are given that 9000 kg of water flows through the pipe in 1 minute. Mass flow rate = mass/time
So, mass flow rate = 9000 kg / 1 minute = 150 kg/s
We know the cross sectional area of the pipe is 0.3 m2. From continuity equation, mass flow rate = density * area * velocity
So, 150 = 1000 * 0.3 * v (Density of water is approximately 1000 kg/m3)
Solving for v (velocity):
v = 150/(1000*0.3) = 5 m/s
Therefore, the speed of water in the pipe is 5 m/s.
When cars are equipped with flexible bumpers, they will bounce off each other during low-speed collisions, thus causing less damage. In one such accident, a 1850 kg car traveling to the right at 1.40 m/s collides with a 1450 kg car going to the left at 1.10 m/s. Measurements show that the heavier car's speed just after the collision was 0.250 m/s in its original direction.
A) What is the speed of the lighter car just after collision?
B) Calculate the change in the combined kinetic energy of the two-car system during this collision.
Answer:
Explanation:
Given that,
Mass of the heavier car m_1 = 1750 kg
Mass of the lighter car m_2 = 1350 kg
The speed of the lighter car just after collision can be represented as follows
\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\v_2=\frac{m_1u_1+m_2u_2-m_1v_1}{m_2}\)
\(v_2=\frac{(1850)(1.4)+(1450)(-1.10)-(1850)(0.250)}{1450} \\\\=\frac{2590+(-1595)-(462.5)}{1450} \\\\=\frac{2590-1595-462.5}{1450} \\\\=\frac{532.5}{1450}\\\\=0.367m/s\)
b) the change in the combined kinetic energy of the two-car system during this collision
\(\Delta K.E=(\frac{1}{2} m_1v_1^2+\frac{1}{2} m_2v_2^2)-(\frac{1}{2} m_1u_1^2+\frac{1}{2} m_2u_2^2)\\\\=\frac{1}{2} (m_1(v_1^2-u_1^2)+m_2(v_2^2-u_2^2))\)
substitute the value in the equation above
\(=\frac{1}{2} (1850((0.250)^2-(1.4)^2)+(1450((0.3670)^2-(-1.10)^2)\\\\=\frac{1}{2}(11850(0.0625-1.96)+(1450(0.1347)-(1.21))\\\\= \frac{1}{2}(11850(-1.8975))+(1450(-1.0753))\\\\=\frac{1}{2} (-3510.375+(-1559.185)\\\\=\frac{1}{2} (-5069.56)\\\\=-2534.78J\)
Hence, the change in combine kinetic energy is -2534.78J
(Figure 1) is the potential-energy diagram for a 500 g particle that is released from rest at A . What is the particle's speed at B ?
Answer:
Explanation:
according to the graph at B the potential energy of the particle is 2J
therefore we can use the kinetic energy equation to calculate the particle's velocity or speed.
\(E_{k} =1/2mv^{2}\)
2J= 1/2*1/2kg*v^2
8=v^2
v= 2√2 ms-1
An undersea research chamber is spherical with an external diameter of 6.20 m. The mass of the chamber, when occupied, is 60400 kg. It is anchored to the sea bottom by a cable. The density of sea water is 1025 kg/m3. Calculate the following: (express your answers using appropriate mks units.)
(a) the buoyant force on the chamber
(b) the tension in the cable
the electrical energy used to pump the water up to a mountain lake is 1.2 x 10 to the power 12 J only 6.2 x 10 to the power 11 J of electrical energy is generated when the water is released calculate the efficiency of this energy storage scheme
Answer:
Explanation:
ake is 1.2 x 10^12 J. Only 6.2 x 10^11 J of electrical energy is generated when the water is released. Calculate the efficiency of this energy
An 8.0 Kg mass is placed at = 3 where should a 10 Kg mass be placed along the − so that the center of mass will be located ay = 4.5?
Answer:
Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.
Explanation:
To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:
x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)
Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.
Given:
m1 = 8 kg
x1 = 3 m
x_cm = unknown (to be found)
m2 = 10 kg
y_cm = 4.5 m
Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.
To solve for x2, we can rearrange the formula as follows:
x2 = (x_cm * (m1 + m2) - m1 * x1) / m2
Substituting the given values:
x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg
Simplifying:
x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg
Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:
4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)
Simplifying:
4.5 m = (24 kg + 10 kg * x2) / 18 kg
Multiplying both sides by 18 kg:
81 kg*m = 24 kg + 10 kg * x2
Subtracting 24 kg from both sides:
10 kg * x2 = 81 kg*m - 24 kg
Dividing both sides by 10 kg:
x2 = (81 kg*m - 24 kg) / 10 kg
Simplifying:
x2 = 8.1 m - 2.4 m
x2 = 5.7 m
(brainlest?) ples:(
Answer:
the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.
Explanation:
To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.
The center of mass of a system is given by the equation:
x_cm = (m1x1 + m2x2) / (m1 + m2),
where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.
Given:
m1 = 8 kg,
x1 = 3 m,
m2 = 10 kg,
y_cm = 4.5 m.
To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:
y_cm = (m1y1 + m2y2) / (m1 + m2),
where y1 and y2 are the positions along the y-axis.
Rearranging the equation and substituting the given values:
4.5 = (83 + 10y2) / (8 + 10).
Simplifying the equation:
4.5 = (24 + 10*y2) / 18.
Multiplying both sides by 18:
81 = 24 + 10*y2.
Rearranging the equation:
10*y2 = 81 - 24,
10*y2 = 57.
Dividing both sides by 10:
y2 = 5.7.
Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.
To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:
x_cm = (m1x1 + m2x2) / (m1 + m2).
Substituting the given values:
x_cm = (83 + 10x2) / (8 + 10).
Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:
0 = (83 + 10x2) / (8 + 10).
Rearranging the equation:
83 + 10x2 = 0.
24 + 10*x2 = 0.
10*x2 = -24.
Dividing both sides by 10:
x2 = -2.4.
Callisto is a moon of Jupiter
(mass= 1.90 x 1027 kg), which orbits
the planet with a period of 16.9 days.
What is the radius of its orbit?
[?] x 10¹ m
Coefficient (green)
Exponent (yellow)
Enter
8.27 x 1013 meres is the orbital radius.
Additional details:-Jupiter's mass, 1.9 x 1027 kg, and the time interval, 16.9 days, are equal to 1.46 x 106 seconds. The radius is needed, thus r. Solution
The moon must be held in its orbit by a gravitational force equal to the centripetal force between Jupiter and the moon.
6.67 x 10⁻¹¹ N/m²kg
2 x 1.9 x 10/27 x 1.46 x 10'6 / 4 r = 6.85 x 102'7 G = 6.67 x 10'11 N/m2kg2 r = 8.27 x 10'7
What distinguishes Callisto, a huge moon orbiting Jupiter, from all other large moons in the solar system?The second-largest moon in Jupiter's orbit and the third-largest moon in the solar system is called Callisto. Of all the objects in our solar system, its surface has the most craters.
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Two charged objects, A and B, are exerting an electric force on each other. What will happen if the charge on A is increased?
А. The charge on B will decrease.
В. The charge on B will increase.
C. The electric force between A and B will decrease.
D. The electric force between A and B will increase.
Answer: The forces acting on both of them will increase in magnitude.
Explanation:
According to Coulomb's law, the electrostatic force between two bodies is proportional to the product of their two charges. If the charge on A is increased this product increases in size (it must have been non-zero to begin with, since there was a force between them at first). Thus, the force between them rises.
Answer:
d. seems like the right answer.
Explanation:
Brainlist!! Help!! The nucleus contains protons and neutrons. Being positively charged, the protons repel each other. The nucleus should fly apart due to the repulsive force. Yet, the nuclei of most atoms are stable - explain.
Answer:
The reason that the nucleus of most atoms does not fall apart despite the oppositely charged protons exerting a repulsive force on each other is the strong nuclear force.
What is the strong nuclear force?The strong nuclear force is one of the fundamental forces in nature that acts between protons and neutrons in the atomic nucleus. It is a short-range force that is much stronger than the electromagnetic force (which produces the repulsion between protons).
The strong nuclear force is responsible for holding the nucleus together.
Additionally, the ratio of protons to neutrons in a nucleus also affects its stability. Therefore, if there is an imbalance in this ratio, the repulsive force between the protons can become too strong, causing the nucleus to become unstable and undergo radioactive decay.
Overall, the nucleus remains stable due to the balance between the strong nuclear force and the repulsive force between the protons.
Consider a uniform electric field E of magnitude E = 7.2 N/C. The line segment connecting points A and B in the field is perpendicular to the direction of the field, while the line segment connecting points C and B is parallel to the field. The line segments have equal lengths of d = 0.38 m.
Find the potential difference, in volts, between point A and point B.
Enter an expression for the potential difference between point C and point B in terms of E and d.
Calculate the potential difference, in volts, between point C and point B.
a. Va-Vb= 0 volts
The two are perpendicular and therefore would have a difference of zero
b. Vc-Vb= -Ed
We already know V=Ed and in this case d is negative
c. -2.736 volts
(-7.2)*(.38)= -2.736
Plug in what was given for E and d into the equation for b
The problem is about the relation between electric field and potential difference. They both are related according to:
Vb -Va = - ∫ E× dl
The solution is:
a) V(B) - V(A) = 0
c) V(C) - V(B) = 2.74 (V)
a) The segment AB is perpendicular to the lines of the electric field, then the point product is zero and V(B) - V(A) = 0
b) The segment CB is parallel to the lines of the electric field, and it is uniform, the:
V(C) - V(B) = - ∫₀⁰°³⁸ E × dl = E× d |₀⁰°³⁸ = - (7.2)×(0.38) = - 2.74 (V)
So the expression for the potential difference between point C and point B in terms of E and d is:
V(C) - V(B) = - ( E×d)
And finally V(C) - V(B) = 2.74 (V)
Note: related problems Brainly.com/question/23899758
U1 Energy Re-Take 20-21 / 9 of 25
A student eats lunch and then rides his bike to the park. The energy stored in the food is transformed when the food is digested. Which of
the following explanations best describes how the chemical energy stored in the food compares to the heat and mechanical energy
produced by digestion and used during the bike ride?
what are the answer choices?
Need this homework for today so help 50 point
Four rods that obey Hooke's law are each put under tension.
a. A rod 50.0 cm long with cross-sectional area 1.00 mm2 and with a 200 N force applied on each end.
b. A rod 25.0 cm long with cross-sectional area 1.00 mm2 and with a 200 N force applied on each end.
c. A rod 20.0 cm long with cross-sectional area 2.00 mm2 and with a 100 N force applied on each end. Order the rods according to the tensile stress on each rod, from smallest to largest.
Order the rods according to the tensile stress on each rod, from smallest to largest.
1. c < b < a
2. a=b
3. a< b < c
4. c
Answer:
c < a<=b
Explanation:
Tensile stress = (force) /Area
for A:
Tensile stress = 200/1 =200N/mm²
For B:
Tensile stress = 200/1 =200N/mm2
For C:
Tensile stress = 100/2 =50N/mm²
Ranking from smallest to largest we have;
C<A<=B which is option 4
A ball is dropped from rest. Its energy is transformed from ________.
Answer:
gravitational potential energy
When the ball falls, some of its gravitational potential energy is converted to other forms of energy, such as kinetic energy and rotational energy. When it rebounds, these other forms of energy is converted back to gravitational potential energy.
Explanation:
to what temperature must 0.588 moles of ammonia gas have to be heated in a 15.0 L container in order for it to exert a pressure of 3.50 kPa
According to the ideal gas law, 0.588 moles of NH3 gas in a 15.0 L container must be heated to a temperature of 1088.85 K or 815.85°C in order for it to impose a pressure of 3.50 atm.
What is the temperature ?Real gases are simplified into ideal gases to make them easier to understand.It is believed to be made up of point particles that move randomly and independently.Additionally, it is believed that perfect gas molecules by themselves have no volume.Three state variables—absolute pressure (P), volume (V), and absolute temperature—define an ideal gas (T).If the quantity of material, number of moles n, remains constant and R is the molar constant of gases, then the relationship between them forms the ideal gas law, an equation that links the three variables:P×V = n×R×T Finally, to a temperature of 1088.85 K or 815.85°C must 0.588 moles of NH3 gas have to be heated in a 15.0 L container in order for it to exert a pressure of 3.50 atm.To learn more about temperature refer
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How to solve this problem?
Answer:
5.6 m/s
Explanation:
m = 0.25 kg, h = 2 m
initail energy = mgh = 0.25 * 9.81 * 2 = 4.91 J
80% of 4.91 J converted to final kinetic energy mv^2/2
so 0.8 * 4.91 = 0.25*v^2/2
v^2 = 2*0.8*4.91/0.25 = 31.4
v = 5.6 m/s
HELP ME ASAPPPPPPPPPPP
A penny sinks to the bottom of a wishing well
What type of frictional force is that?
The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.
prevailing theories about galaxies predict that there should exist numerous around large galaxies (like our milky way). observations are confirming these predictions. question 5 options:
Prevailing theories about galaxies predict that there should exist numerous dwarf galaxies around large galaxies (like our Milky Way). Observations are confirming these predictions. The correct answer is option b.
The prevailing theories about galaxies suggest that large galaxies like our Milky Way should be surrounded by numerous dwarf galaxies.
These dwarf galaxies are much smaller than large galaxies and have a much lower mass. They are thought to form around larger galaxies due to gravitational interactions between the larger galaxies and smaller gas clouds.
The predictions made by these theories are being confirmed through observations. In recent years, astronomers have discovered many dwarf galaxies around large galaxies like our Milky Way. These discoveries have helped to improve our understanding of galaxy formation and evolution.
Therefore, option b is correct.
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The probable question may be:
prevailing theories about galaxies predict that there should exist numerous ____ around large galaxies (like our milky way). observations are confirming these predictions.
options:
a) elliptical galaxies
b) dwarf galaxies
c) giant elliptical galaxies
A toy rocket is shot straight up into the air with an initial speed of 45m/s. The acceleration of gravity is -9.8m/s^2. a) How long does it take for the rocket to reach its highest point?
The rocket to reach its highest point at Δt = 4.59s.
Equation :Given data,
a = -9.8m/s²
v = 45m/s
t = ?
So using formula,
a = Δv/Δt
Where,
a is acceleration
v is velocity or speed
t is time
Now putting values,
-9.8m/s² = 45m/s / Δt
Δt = Δv/a
Δt = 45m/s / 9.8m/s²
Δt = 4.59s
What is acceleration ?Any process where the velocity changes is referred to as acceleration. There are only two ways to accelerate because velocity is a function of both speed and direction: changing your speed, changing your direction, or changing both.
The first of the three types of acceleration is
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The 7.4 N weight is in equilibrium under
the influence of the three forces acting on it.
The F force acts from above on the left at
an angle of a with the horizontal. The 5.9 N
force acts from above on the right at an angle
of 44° with the horizontal. The force 7.4 N
acts straight down.
Ĵ
44°
5.9 N
7.4 N
What is the magnitude of the force F?
Answer in units of N.
part 2 of 2
What is the angle a of the force F as shown
in the figure?
a) Magnitude of force is 5.37N
b) Angle of force is - 37.88°
What is force?In physics, we define a force is an influence that can change the motion of object. A force can cause an object with mass to change to accelerate.
Given force from above is 5.9N
∑Fₓ = F₁ₓ + F₂ₓ+F₃ₓ = 0
F₂ cos 44° + Fₓ = 0
Fₓ = - 5.9 cos44°
= - 4.24 N
Given force that acts downward as 7.4N
∑Fy= Fy1+ Fy2 +Fy3 =0
Fy+ 5.9 sin 44° - 7.4= 0
F = 3.30 N
F =√Fₓ² +Fy²
= 5.37 N
b) angle of force= tan⁻¹ (3.30/-4.24)
= - 37.88°
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Write any 3 difference between work energy power
Work is referred to as the displacement of an object when a force (push or pull) is applied to it while energy is referred to as the capacity to do the work. It exists in various forms like potential, kinetic, chemical, thermal, nuclear, electrical energy and so on. Power is the work done per unit of time.
Types of Energy:Mechanical energy.Mechanical wave energy.Chemical energy.Electric energy.Magnetic energy.Radiant energy.Nuclear energy.Ionization energy.power and energy are the same.
Work is usualy doing a task that gets rid of said energy.
HELP! An electron is accelerated from 0 m/s to 8 x 10^7 m/s by a uniform electric field. What is the potential difference (voltage) between the plates that make the field?
The potential difference (voltage) between the plates is approximately 1.45 kV.
The kinetic energy of an electron can be related to the potential difference between the plates of an electric field using the equation:
KE = qV,
where KE is the kinetic energy of the electron, q is its charge, and V is the potential difference between the plates.
We know that the electron is accelerated from rest to a final velocity of 8 x 10^7 m/s, so its change in kinetic energy is given by:
ΔKE = 1/2 mv^2 - 1/2 m(0)^2 = 1/2 mv^2
where m is the mass of the electron.
The potential difference between the plates can be found by rearranging the equation to solve for V:
V = ΔKE / q
Substituting the values we have:
V = (1/2) mv^2 / q
The mass of an electron is approximately 9.11 x 10^-31 kg, and its charge is -1.6 x 10^-19 C. Substituting these values and the final velocity of 8 x 10^7 m/s, we get:
V = (1/2) (9.11 x 10^-31 kg) (8 x 10^7 m/s)^2 / (-1.6 x 10^-19 C)
V = -1.45 kV
Therefore, the potential difference (voltage) between the plates is approximately 1.45 kV.
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please help for 21! will mark brainliest
The answer for this question is D
the set of all vectors which are scalar multiple of a nonzero vector u is a line through u and 0. a column vector in r2 is a 1 x 2 matrix. the operation of vector addition is not commutative. the magnitude of a vector cv is c times the magnitude of v, where c is any scalar. none of the choices is correct.
The set of all vectors which are scalar multiples of a nonzero vector u is a line through u and 0. a column vector in r₂ is a 1 x 2 matrix. The magnitude of a vector cv is c times the magnitude of v, where c is any scalar. The correct option is Option C.
Vector multiplication may refer to one of several products between two (or more) vectors. Multiplication of vectors is of two types. A vector has both magnitude and direction and based on this the two ways of multiplication of vectors are the dot product of two vectors and the cross product of two vectors. Dot product or "scalar product", is a binary product that takes place with two vectors and returns a scalar quantity. The dot product of two vectors can be defined as the product of the magnitudes of the two vectors and the cosine of the angle between the two vectors. Thus, A ⋅ B = |A| |B| cos θ
Cross product, or the "vector product", is a binary product on two vectors that results in another vector. So, if n is the unit vector perpendicular to the plane determined by vectors A and B,
A × B = |A| |B| sin θ n
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. A 5cm tall object is placed perpendicular to the principal axis of a convex lens of focal
length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position
and size of the image. Also find its magnification
The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.
Given:
Object height (h) = 5 cm
Focal length of the convex lens (f) = 10 cm
Object distance (u) = 15 cm (positive since it's on the same side as the incident light)
To determine the nature, position, and size of the image, we can use the lens formula:
1/f = 1/v - 1/u
Substituting the given values:
1/10 = 1/v - 1/15
To simplify the equation, we find the common denominator:
3v - 2v = 2v/3
Simplifying further:
v = 30 cm
The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.
To find the magnification (M), we use the formula:
M = -v/u
Substituting the values:
M = -30 / 15 = -2
The magnification is -2, indicating that the image is inverted and twice the size of the object.
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A watermelon seed has the following coordinates: x = -7.1 m, y = 5.6 m, and z = 0 m. Find its position vector as (a) a magnitude and (b)
an angle relative to the positive direction of the x axis. If the seed is moved to the xyz coordinates (4.7 m, Om, O m), what is its
displacement as (c) a magnitude and (d) an angle relative to the positive direction of the x axis? Put the angles in the range (-180°, 180°]
Who has so much time to measure the fμcking seeds?