Let's say you want to construct a 90% confidence interval for
the true proportion of voters who support Karol for city treasurer.
Previously, it is estimated that 60% support Karol. How large does
the
Answers
Let's assume a desired margin of error, E. If you provide a specific value for E, I can calculate the required sample size for constructing the 90% confidence interval.
To construct a 90% confidence interval for the true proportion of voters who support Karol for city treasurer, we need to determine the sample size required.
The formula for calculating the sample size for a proportion is:
n = (Z^2 * p * (1 - p)) / E^2
where:
n = required sample size
Z = Z-value corresponding to the desired confidence level (90% in this case)
p = estimated proportion (60% in this case)
E = margin of error
Since we want to estimate the true proportion with a 90% confidence level, the Z-value will be 1.645 (corresponding to a 90% confidence level). Let's assume we want a margin of error of 5%, so E = 0.05.
Plugging in the values, we have:
n = (1.645^2 * 0.6 * (1 - 0.6)) / 0.05^2
Simplifying the equation:
n = (2.706 * 0.6 * 0.4) / 0.0025
n = 2594.56
Since the sample size should be a whole number, we need to round up to the nearest whole number. Therefore, the required sample size is 2595.
Now, you can construct a 90% confidence interval using a sample size of 2595 to estimate the true proportion of voters who support Karol for city treasurer.
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Related Questions
A rocket is launched from a tower. The height of the
rocket, y in feet, is related to the time after launch, x
in seconds, by the given equation. Using this
equation, find the maximum height reached by the
rocket, to the nearest tenth of a foot.
y = –16x2 + 246x + 100
=
Answers
Answer:
1045.6 feet
Step-by-step explanation:
A graphing calculator easily shows you the vertex of the parabola. The y-coordinate there is the rocket's maximum height: 1045.6 feet.
__
Quadratic function ax^2 +bx +c has its vertex at x=-b/(2a). Here, that x-value is ...
x = -(246)/(2(-16)) = 7 11/16 . . . seconds
The corresponding height of the rocket is ...
y = (-16(7 11/16) +246)(7 11/16) +100 = 123(7 11/16) +100 = 1045 9/16 ≈ 1045.6
The maximum height reached by the rocket is 1045.6 feet.
V ⃗ = <-7,2,3> and w⃗ = <4,-3,5>. Find 1/2 ( v⃗ +4w⃗ )
- <-2. 5,-0. 5,4>
-<9,-10,-17>
-<4. 5,-5,11. 5>
-<8,-6,-10>
Answers
\(\overrightarrow{V}= < -7,2,3 > \hspace{5em}\overrightarrow{W}= < 4,-3,5 > \\\\[-0.35em] ~\dotfill\\\\ 4\overrightarrow{W}\implies 4 < 4,-3,5 > \implies < 16,-12,20 > \\\\\\ \overrightarrow{V}+4\overrightarrow{W}\implies \begin{array}{ccccllll} &-7&2&3\\ +&16&-12&20\\\cline{1-4} &9&-10&23 \end{array} \\\\[-0.35em] ~\dotfill\\\\ \frac{1}{2}\left( \overrightarrow{V}+4\overrightarrow{W} \right)\implies \frac{1}{2} < 9,-10,23 > \implies {\Large \begin{array}{llll} < 4.5~~,~~-5~~,~~11.5 > \end{array}}\)
Edward has a bag filled with green and purple M&Ms. He has a total of 36 M&Ms in the bag. There are 3 purple M&Ms for every 1 green M&M. If he randomly selects one M&M from the bag, what is the probability that it will be green?
Answers
Answer:
25% chance
Step-by-step explanation:
9 green ones in the bag. 9/36=0.25%
). a lottery offers one $1000 prize, one $500 prize, and two $50 prizes. one thousand tickets are sold at $4.00 each. find the expectation of winning amount if a person buys one ticket. create a probability distribution as part of your answer.
Answers
Expectation = ($1 + $0.50 + $0.40) x $4.00 = $7.40
The expectation of winning amount if a person buys one ticket is $7.40. This can be calculated using the probability distribution below.
Lottery Prize: | Probability: | Win Amount: | Probability x Win Amount:
$1000 | 1/1000 | $1000 | 1/1000 x $1000 = $1
$500 | 1/1000 | $500 | 1/1000 x $500 = $0.50
$50 | 2/1000 | $50 | 2/1000 x $50 = $0.40
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please help me answer this question!! I don’t understand it at all. picture attached
Answers
Answer:
Step-by-step explanation:
whats the angle between m,n,i i think thats what its asking but i dont know for sure.
The dean of Blotchville University boasts that the average class size there is 20. But the reality experienced by the majority of students there is quite different: they find themselves in huge courses, held in huge lecture halls, with hardly enough seats or Haribo gummi bears for everyone. The purpose of this problem is to shed light on the situation. For simplicity, suppose that every student at Blotchville University takes only one course per semester.
a) Suppose that there are 16 seminar courses, which have 10 students each, and 2 large lecture courses, which have 100 students each. Find the dean’s eye view average class size (the simple average of the class sizes) and the student’s eye view average class size (the average class size experienced by students, as it would be reflected by surveying students and asking them how big their classes are). Explain the discrepancy intuitively.
b) Give a short proof that for any set of class sizes (not just those given above), the dean’s eye view average class size will be strictly less than the student’s eye view average class size, unless all classes have exactly the same size.
Answers
a) Find the dean’s eye view average class size and the student’s eye view average class size:Given that there are 16 seminar courses, each having 10 students each.Number of students in seminar courses: 16 × 10 = 160There are 2 large lecture courses, each having 100 students each.
Number of students in large lecture courses: 2 × 100 = 200
Dean’s view average class size is the simple average of the class sizes:Let’s find the Dean’s view average class size. There are 18 courses in total.
This can be obtained by dividing the total number of students by the total number of classes.
Student’s view average class size = Total number of students/Total number of classes
= 360/18
= 20
Therefore, the dean’s eye view average class size is 46.67 (approximately) and the student’s eye view average class size is 20.
Now, we need to prove that D 2, then (k/(k + 1)) - (1/n) < 0.
Therefore, we have:
S - D< (c2 - c1)*[(k/(k + 1)) - (1/n)]< 0
Hence, S < D.Therefore, the dean’s eye view average class size will be strictly less than the student’s eye view average class size, unless all classes have exactly the same size.
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Problem 1. The BetterWay Insurance Company wants to introduce 2 new product lines - special risk insurance and mortgages. They expect to make profits of $5 per unit on special risk insurance and $2 per unit on mortgages Management wants to establish sales quotas for the new product lines that will maximize total expected profits. The work requirements are as follows: Department Underwriting Administration Claims Work Hours per Unit Special Risk Mortgage 3 2 0 1 2 0 Available Work Hours 2400 800 1200 a. What are the decisions to be made, the constraints on those decisions, and the measure of performance/objective for the decisions? b. Show the linear programming model for this problem, i.e., convert the verbal descriptions in (a) to quantitative expressions. C. Plot the feasible region and identify the extreme points./ d. Solve using the graphic method. e. Identify the slack associated with the optimal decision? f. Which constraints are binding the optimal solution? g. Would it be desirable for BetterWay to consider providing additional hours of claims time? h. Use the shadow price concept to determine the value of one additional hour of claims time. If the overtime cost of obtaining additional hours of claims time is $20.00 per hour, should the company consider the use of overtime? Explain. i.
Answers
a. The decisions to be made are the number of units of special risk insurance and the number of units of mortgages to produce, the constraints on those decisions are the work hours available for each department, and the measure of performance/objective is to maximize total expected profits.
b. The linear programming model is:
Maximize: 5X + 2Y
Subject to:
3X + 2Y <= 2400 (Underwriting)
2X + Y <= 800 (Administration)
X + Y <= 1200 (Claims)
X, Y >= 0 (non-negativity)
c. The feasible region and extreme points are shown in the graph below:
d. The optimal solution is found at X = 1,200 and Y = 600.
e. The slack associated with the optimal solution is 0 for the Underwriting constraint and 200 for the Administration constraint.
f. The Underwriting constraint and the Claims constraint are binding the optimal solution.
g. It would be desirable for BetterWay to consider providing additional hours of claims time.
h. The shadow price concept determines that the value of one additional hour of claims time is $1.
The overtime cost of obtaining additional hours of claims time is $20, so it is not desirable for the company to consider the use of overtime.
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Data table Activity Optimistic START 0 ABCDEFGHIK А J L FINISH 605 2607NTO TO 2-253 N N N M - NO 15 3 1 1 1 Time Estimates (days) Most Likely 0 0 10 1 20 10 2 2 2 3 1 Print Pessimisitic 0 OANAN www�
Answers
Answer:
This is gebber gabber but yes
Step-by-step explanation:
Answer this easy geometry question
Answers
Answer:
1684.8 cubic units
Step-by-step explanation:
In oblique cylinder the height (altitude) is measured from the opposite base to the base of the cylinder, but it lies outside. We can find the height using Pythagoras theorem.
h + 7² = 13²
h²= 169 - 49
h² = 120
h = √120
h = 10.95 units
radius = r = 7 units
\(\boxed{\text{\bf Volume of oblique cylinder = $\bf\pi r^2h$} }\)
= 3.14 * 7 * 7 * 10.95
= 1684.8 cubic units
SOLVE THIS
I WILL GIVE BRAINLIEST
Answers
hope it becomes helpful to you ☺️☺️
good luck
-------- = 3
5
(5) (3) = 4x-5
15 = 4x-5
15 + 5 = 4x
20 = 4x
x = 5
Please this is URGENT!!!!!! need it in the next 5 mins!!!!!!!
Please be my life saver and help me out!
Angelica uses a coordinate plane to make a map of her neighborhood. The point at (4, 3) represents the location of her house, and the point at (10, 8) to represent the location of the gas station. She wants to drive to the gas station using the straight line shown below. Use what you know about right triangles to find out how far she will drive. Each unit on the graph represents 1 mile.
In this answer, give the length of the straight line shown on the graph, and explain how you calculated it.
Answers
Answer:
distance: 7.81 miles
Explanation:
simply use distance formula: \(\sf \sqrt{(y_2 -y_1)^2 + (x_2-x_1)^2}\)
coordinates: (4, 3), (10, 8)using the equation:
\(\hookrightarrow \sf \sqrt{(8-3)^2+(10-4)^2}\)
\(\hookrightarrow \sf \sqrt{(5)^2+(6)^2}\)
\(\hookrightarrow \sf \sqrt{25+36}\)
\(\hookrightarrow \sf \sqrt{61}\)
\(\hookrightarrow \sf 7.81 \ miles\)
Consider the following data for MRP. Develop the material requirements plan for item B and C, and answer questions below
MPS start:
End item Week 1 Week 2 Week 3 Week 4 Week 5 Week 6
A 120 80
Bill of materials:
End item A is made of 1 unit of item B.
Item B is made of 2 units of item C.
MRP-related information for each item:
Item Leadtime (weeks) Lot sizing Safety stock On-hand inventory Scheduled receiptsB 1 L4L 0 30 60 in
week 1
C 2 FOQ (50) 20 80 None
What is the gross requirement for item B in Week 3?
i. 0 unit
ii. 80 units
iii. 120 units
iv. 200 units
v. 240 units
Answers
The gross requirement for item B in Week 3 is 80 units.
The gross requirement for item B in Week 3, we need to calculate the demand for item B based on the bill of materials and the requirements for item A.
From the MPS (Master Production Schedule) provided, we can see that the gross requirement for item A in Week 3 is 80 units.
According to the bill of materials, item A requires 1 unit of item B. Therefore, the gross requirement for item B can be calculated by multiplying the gross requirement for item A by the quantity needed for item B in the bill of materials.
Gross requirement for item B = Gross requirement for item A × Quantity needed for item B in bill of materials
Gross requirement for item B = 80 units × 1 unit
Gross requirement for item B = 80 units
Therefore, the gross requirement for item B in Week 3 is 80 units.
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Q1 help needed plz it’s due in 1 hour
Will appreciate it a lot
Answers
Answer:
Question 1 is ii
Step-by-step explanation:
Which of the following must always be true about vertical angles
Answers
Answer:
It is always a strait line going up.
Step-by-step explanation:
Answer:
vertical angels
angles opposite each other where two lines cross.
plz mark brainliest
Step-by-step explanation:
Given that vC(0) = 2 cos(155°) V, what is the instantaneous voltage across a 2-μμF capacitor when the current through it is i = 8 sin(106t + 25°) A? Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. (The final answer should also be in sine, not cosine form, similar to the i given above).
Answers
The instantaneous voltage across a capacitor is |2cos(155°)| sin(106t + 25° - angle(2 cos(155°))).
The instantaneous voltage across a capacitor is given by the equation:
vC(t) = vC(0) + 1/C * ∫i(t)dt
Since i(t) = 8 sin(106t + 25°), we can find the integral using the formula for the integral of a sine function:
∫i(t)dt = -8/106 cos(106t + 25°)
So,
vC(t) = 2 cos(155°) - 8/106 ∫ cos(106t + 25°)dt
vC(t) = 2 cos(155°) - 8/106 sin(106t + 25°)
The magnitude of vC(t) is positive, and the angle should be in the range of -180° to 180°. The final answer is in sine form, so we can write:
vC(t) = |2 cos(155°)| sin(106t + 25° - angle(2 cos(155°)))
where angle(2 cos(155°)) is the angle of 2 cos(155°).
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What is the length of side JN and JS (Round your answer to the nearest tenth.)
Answers
Answer:
JN = 44.3
JS = 43.1
Step-by-step explanation:
19) Use Law of Sines
sin53/39 = sin65/JN
JN = 39(sin65) / (sin53) = 44.26 ≈ 44.3
20) m∠N = 180 - 65 - 53 = 62
sin53/39 = sin62/JS
JS = 39(sin62) / (sin53) = 43.12 ≈ 43.1
WILL MARK AS BRAINLEIST!!
Question in picture!!
Note: The graph above represents both functions “f” and “g” but is intentionally left unlabeled
Answers
Answer:
f(x) is the blue graph, g(x) is the red graph.
x^2 - 3x + 17 - (2x^2 - 3x + 1) = 16 - x^2
16 - x^2 = 0 when x = -4, 4
So the area between these two graphs is (using the TI-83 graphing calculator):
fnInt (16 - x^2, x, -4, 4) = 85 1/3
I need help to solve it
Answers
Answer:
to solve what
Step-by-step explanation:
evaluate where is the upper hemisphere of radius , that is, the set of with . evaluate where is the upper hemisphere of radius , that is, the set of with .
Answers
The upper hemisphere of radius R can be expressed as the set {(x,y,z) | z ≥ 0, x² + y² + z² = R²}.
The upper hemisphere of radius R is the set of all points that lie on or above the plane that intersects the sphere at its equator and has a distance of R from the center of the sphere. The set of points in the upper hemisphere can be represented as follows:
Upper Hemisphere: { (x, y, z) | x^2 + y^2 + z^2 = radius^2 and z ≥ 0 }
Here, the hemisphere has a radius, and the points within the set are defined by their coordinates (x, y, z). The equation x^2 + y^2 + z^2 = radius^2 represents the sphere, and the condition z ≥ 0 ensures that only the upper hemisphere is considered in the set.
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"Modify the model in Problem 3 for net rate at which the population P(t) of a certain kind of fish changes by also assuming that the fish are harvested at a constant rate h > 0. Problem 3: Using the concept of net rate introduced in Problem 2, determine a model for a population P(t) if the birth rate is proportional to the population present at time t but the death rate is proportional to the square of the population present at time t.
Dp/dt = k1P ? K2P^2P(t) = population of fish at time t b=birth rate d=death rate b infinity P(t) d infinity P^2(t) b = k1P(t) d = k2P^2(t)"
Answers
In the modified model, considering a constant harvesting rate, the net rate of change of the fish population takes into account both the birth rate and the death rate, which is proportional to the square of the population. The model is given by dP/dt = k1P - k2P^2 - h, where P(t) represents the population of fish at time t, k1 is the constant of proportionality for the birth rate, k2 is the constant of proportionality for the death rate, and h is the harvesting rate.
The net rate at which the population of fish changes takes into account the birth rate, the death rate, and the harvesting rate. The birth rate is proportional to the population present at time t, represented by k1P(t). The death rate, on the other hand, is proportional to the square of the population present at time t, given by k2P^2(t). The harvesting rate, denoted by h, represents the constant rate at which fish are being harvested. Therefore, the net rate of change of the population, dP/dt, is equal to the birth rate minus the death rate minus the harvesting rate. This can be expressed as dP/dt = k1P - k2P^2 - h. This differential equation provides a model for the population dynamics of the fish, accounting for both natural processes (birth and death rates) and human intervention (harvesting rate).
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Help meeeeee with number 6, 8, 10 pls !
Answers
Answer:
sei Nao????????????????????????????????????????
Step-by-step explanation:
what should be the result ?
all I can see are very simple expressions, but with no way to e.g. solve them to a single number or do something else specifically.
so, all I can do is resolve brackets and such.
6. -(x+4) = -x - 4
8. 7a(3b - 2c + 4) = 21ab - 14ac + 28a
10. 2/3 (1/4 x - 6) = 2/12 x - 6×2/3 = 1/6 x - 2×2 = 1/6 x - 4
Plz answer this as soon as possible it’s my hw I have to submit it tomorrow.
Answers
Answer:
43
Step-by-step explanation:
-2+3×15
45-2
43 is the answer
determine whether the triangles are similar by aa , ss , or sas ??
Answers
Answer:
1. AA
2. SSS
3. I´m not sure about this one, I´m sorry
4. Not similar
Step-by-step explanation:
This photo can help you identify!! I hope this helps
What is the value of x? enter your answer in the box. x = cm
Answers
The value of x in the given equation will be 2/5
From the data,
We have to determine the value of x.
The given equation is: 18x-16=-12x-4
For determining the value of x, we will first shift the like terms on one side of the equation.
So, for solving the value of x we will shift the terms containing x and the constant on both sides of the equation.
So, shifting -12x from the right-hand side of the equation to the left-hand side of the equation,
We will get it as:
18x+12x = -4+16
30x=12
Now for solving the value of x we will shift x from the left side of the equation to the right side of the equation.
So, the value of x will be = 12/30 = 2/5
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The correct question may be:
What is the value of x
18x-16=-12x-4
Enter your answer in the box.
The first number of a pattern is 400. The pattern follows the rule divide by 2, then add 6. What are the next two terms?
Answers
Answer:
206 and 109
Step-by-step explanation:
first term:
400 divided by 2 is 200
200+6= 206
second term:
206 divided by 2 is 103
103+6=109
Answer:
206,109
Step-by-step explanation:
If u divide 400 by 2 it equals 200 then u have to add 6 so its 206.
If u divide 206 by 2 it equals 103 then u have to add 6 and u get 109.
The 3 month eurodollar futures price for a contract maturing in 6 years is quoted as 95.20. The standard deviation of the change in the short-term interest rate in 1 year is 1.1%. Estimate the forward LIBOR interest rate for the period between 6.00 and 6.25 years in the future.
Answers
The estimated forward LIBOR interest rate for the period between 6.00 and 6.25 years in the future is approximately 7.495%.
To estimate the forward LIBOR interest rate for the period between 6.00 and 6.25 years in the future, given the 3-month Eurodollar futures price of 95.20 and a standard deviation of the change in the short-term interest rate in 1 year of 1.1%, follow these steps:
1. Convert the Eurodollar futures price to an implied interest rate:
Implied Interest Rate = (100 - Eurodollar Futures Price) = (100 - 95.20) = 4.80%
2. Calculate the number of standard deviations for the 6-year period:
Number of Standard Deviations = √(6 years) = √6 ≈ 2.45
3. Multiply the number of standard deviations by the annual standard deviation of the change in the short-term interest rate:
Change in Interest Rate = Number of Standard Deviations × Annual Standard Deviation = 2.45 × 1.1% = 2.695%
4. Add the change in the interest rate to the current implied interest rate to get the forward LIBOR interest rate for the period between 6.00 and 6.25 years in the future:
Forward LIBOR Interest Rate = Implied Interest Rate + Change in Interest Rate = 4.80% + 2.695% = 7.495%
So, the estimated forward LIBOR interest rate for the period between 6.00 and 6.25 years in the future is approximately 7.495%.
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I just need help with similarity ratios. I don't understand how you get the ratios.
Answers
Then x plus 1 is 14
14 take away one
X equals to 13
According to the problem-solving strategies you learned in this lesson, what
should you do after you've gathered your resources on a problem?
A. Check your answers and present the solution.
B. Come to an answer.
C. Gather your resources again.
OD. Understand the problem.
Answers
Answer:
B.
Resources, as in details of the problem and then you do check the answers and present the solution.
Binding constraints have
surplus resources.
zero slack.
negative slack
positive slack
Answers
Binding constraints directly influence the optimal solution in a linear Programming problem, whereas constraints with positive slack are non-binding and do not directly impact the solution.
binding constraints and positive slack in the context of linear programming. In a linear programming problem, we aim to find the optimal solution for an objective function, given a set of constraints. The terms "binding constraints" and "positive slack" are related to these constraints.
1. Binding constraints: These are constraints that directly impact the optimal solution of the problem. In other words, they "bind" the feasible region (the area where all the constraints are satisfied) and affect the maximum or minimum value of the objective function. Binding constraints are active constraints, as they influence the final solution.
2. Positive slack: Slack is the difference between the left-hand side and right-hand side of a constraint when the constraint is satisfied. If this difference is positive, it means that there is some "extra" or "unused" resource in that constraint. Positive slack indicates that the constraint is non-binding, meaning it does not directly impact the optimal solution. It shows that there is some room for the constraint to be further tightened without affecting the final outcome.
In summary, binding constraints directly influence the optimal solution in a linear programming problem, whereas constraints with positive slack are non-binding and do not directly impact the solution. Knowing the difference between these terms can help you better understand and analyze linear programming problems.
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Someone answer this quick
Question number 8.
Answers
Answer:
\(142\)
Step-by-step explanation:
\(2x+8+6x+12=180\\8x+20=180\\8x=180-20\\8x=160\\x=\frac{160}{8}\\x=20\)
\(6x+12=6\cdot20+12=120+12=142\)