let's say i was standing in one spot (zero speed facing north). then i took one step (one meter) and it took me a second to do so (still facing north). did i acceleration?

All electromagnetic waves travel at the same speed in a vacuum, which is 300,000 km/sec (186,000 mph). This results from the electromagnetic waves' oscillating nature.

In general, we say that light moves in waves and that all electromagnetic radiation moves through a vacuum at a speed of around 3.0 * 108 meters per second. Nothing can move faster than the speed of light, which is what we refer to as.

The universal scientific constant known as c—the speed of light in a vacuum—is significant in many branches of physics. The exact value of the speed of light, c, is 299,792,458 meters per second.

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Answer:

30N

Explanation:

if it is pushing the object to the left then it would be 30N left and if it is pushing the object to the right it would be 30N right

Answer: 30N

Explanation:

The overall dimming of starlight passing through dust clouds is Extinction .

To find the answer, we need to know more about the Extinction.

Thus, we can conclude that, the overall dimming of starlight passing through dust clouds is Extinction .

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Answer:

pizza dont got no bone in it

Explanation:

Answer:

Pizza have no bones

Explanation:

Because it would be yucky

For a Morse potential, the vibrational force constant is not independent of the quantum number n or the displacement x-xe.

This is because the Morse potential is a more accurate description of the potential energy curve of diatomic molecules than the harmonic potential. The Morse potential takes into account the non-linear and anharmonic behavior of the molecule, which affects the force constant and the displacement of the molecule from its equilibrium position.

The vibrational energy levels in a Morse potential are also closer together than in a harmonic potential, meaning that the molecule is more likely to be in a higher vibrational state. This can lead to more complex and interesting spectroscopic behavior, such as overtones and combination bands.

Thus,  the behavior of a Morse potential is not the same as a harmonic potential when it comes to the vibrational force constant and the displacement of the molecule. The Morse potential provides a more accurate and realistic description of diatomic molecule vibrations, and its behavior is more complex and interesting than the harmonic potential.

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Answer: the force when the catapult swings has the same force as it does when coming down

Explanation:

for every reaction there is an equal opposite reaction

Answer:

μ = 0.692

Explanation:

In order to solve this problem, we must make a free body diagram and include the respective forces acting on the body. Similarly, deduce the respective equations according to the conditions of the problem and the directions of the forces.

Attached is an image with the respective forces:

A summation of forces on the Y-axis is performed equal to zero, in order to determine the normal force N. this summation is equal to zero since there is no movement on the Y-axis.

Since the body moves at a constant speed, there is no acceleration so the sum of forces on the X-axis must be equal to zero.

The frictional force is defined as the product of the coefficient of friction by the normal force. In this way, we can calculate the coefficient of friction.

The process of solving this problem can be seen in the attached image.

Thermodynamics can be said to be a branch of Physics which involves the transfer of heat and other energy forms.

Thermal energy is the energy possesed by a system due to its temperature.

In thermodynamics, during the transfer of thermal energy, energy is wasted due to entryopy. And entropy is the measure of disorder of a system.

Therefore, in amy thermodynamic system that deals with the transfer of thermal energy, the most ideal state for that system is Entropy

ANSWER:

A. Entropy

Answer:

V = 49.05 [m/s]

Explanation:

We can easily find the result using kinematics equations, first, we will find the distance traveled during the 5 seconds.

\(y =y_{o}+(v_{o}*t)+(\frac{1}{2}*g*t^{2} )\)

where:

Yo = initial position = 0

y = final position [m]

Vo = initial velocity = 0

t = time = 5 [s]

g = gravity aceleration = 9.81 [m/s^2]

The initial speed is zero, as the body drops without imparting an initial speed. Therefore:

y = 0 + (0*5) + (0.5*9.81*5^2)

y = 122.625[m]

Now using the following equation we can find the speed it reaches during the 5 seconds.

\(v_{f} ^{2}= v_{i} ^{2}+(2*g*y)\\v_{f}=\sqrt{2*9.81*122.625} \\v_{f}=49.05 [m/s]\)

Answer:

They are standing 3 feet away from each other

Explanation:

If Nathan Is standing 2 feet away from the mirror. Then Hiva is standing 7 feet away from the mirror is she is standing 5 feet further than him. They are standing 3 feet away from each other.

Answer:

a) cos30=adj/hyp

cos30= horizontal force/10

horizontal force= 8.66 N

rest of a is in the picture.

b) i believe you can continue.

Answer:

When a proton is placed directly in the path of the proton cannon, it will experience a strong electromagnetic force. The proton cannon emits a beam of protons at high energy and velocity. When the proton in the path of the cannon interacts with the beam, there will be a collision between the two protons.

During the collision, the protons may undergo a process called scattering, where they change direction and momentum. The exact outcome of the collision depends on the energy and angle of the incoming proton, as well as the properties of the target proton. It is possible that the protons may scatter off each other, transferring energy and momentum in the process.

In some cases, the collision may result in the absorption of the incoming proton by the target proton. This can lead to the formation of a more massive particle or the emission of other particles. The specifics of the interaction will depend on the energy and conditions of the proton cannon and the characteristics of the protons involved.

Overall, placing a proton directly in the path of a proton cannon will result in a collision and potential scattering or absorption of the protons, causing changes in their momentum and possibly leading to the creation of other particles.

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Answer:

metals are hated at 1,300°C

The kinetic energy of particles be increasing when metals are hated at 1,300°C.

The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. Following work, energy is transmitted to the item, which causes it to move at a new, constant speed.

Kinetic energy is energy due to motion when temperature is increased than the motion of molecule is increase so kinetic energy increases.

The kinetic energy of particles be increasing when metals are hated at 1,300°C.

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Answer:

If the wind speed increased, the plane's ground speed would be affected.

Explanation:

The ground speed of a plane is the speed at which it is traveling relative to the ground. Wind speed affects the plane's airspeed, which is the speed at which it is traveling relative to the air. If the wind speed increases, it can either help or hinder the plane's ground speed, depending on whether the wind is a headwind or a tailwind. A headwind can slow down the plane's ground speed, while a tailwind can increase it.

Answer:

C

Explanation:

The lungs and heart are organs

The resultant displacement of the bullet is  1,418.6 m.

The resultant displacement of the bullet is the total displacement of the bullet obtained by resolving the displacement into x and y component.

the horizontal component of the displacement (x)  = d cosθ

the vertical component of the displacement (y) = d sinθ

where;

For the first displacement;

x = 850 m x cos(0) = 850 m

y = 850 m x sin(0) = 0

For the second displacement;

x = 640 m  x   cos(36) = 517.8 m

y = 640 m  x  sin(36) = 376.2 m

Net horizontal and vertical displacement;

∑x = 850 m  +   517.8 m   = 1,367.8 m

∑y = 376.2 m + 0 = 376.2 m

The resultant displacement of the bullet is calculated as;

d = √(∑x² + ∑y²)

d = √(1,367.8²   +    376.2²)

d = 1,418.6 m

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The amplitude a of the motion is 0.498m.

energy-saving measures A fundamental law of physics and chemistry states that an isolated system's total energy remains constant despite internal changes. The first law of thermodynamics is based on this principle, which is most frequently stated as "energy cannot be created or destroyed."

Energy is neither created nor destroyed, according to the law of conservation of energy. For instance, when you roll a toy car down a ramp and it collides with a wall, kinetic energy is converted to potential energy.

Using conservation energy:

Loss in kinetic energy = gaining in spring

1/2mv² = 1/2kd²

mv² = kd²

d² = mv²/k

d² = 4.2×13.6/229

d² = 0.249

d = 0.498m.

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Answer

2 pounds

Explanation:

The change in length for a one-meter-long object subject to a 10-degree change in temperature would be on the order of a few millimeters, approximately 0.1 millimeters.

The change in length of an object due to a change in temperature is governed by its coefficient of linear expansion. This coefficient represents how much the length of the object changes per degree Celsius or Kelvin of temperature change. Different materials have different coefficients of linear expansion.

Assuming a linear relationship between the change in length (ΔL) and the change in temperature (ΔT), we can use the formula:

ΔL = αLΔT

where ΔL is the change in length, α is the coefficient of linear expansion, L is the original length of the object, and ΔT is the change in temperature.

For a one-meter-long object subjected to a 10-degree change in temperature, the value of α depends on the material of the object. However, as a general estimate, for most common materials, the coefficient of linear expansion is on the order of \(10^{-5}\) per degree Celsius.

Using this estimate, we can calculate the change in length:

ΔL ≈ \(10^{-5}\) per degree Celsius) * (1 meter) * (10 degrees)

= \(10^{-4}\) meters

≈ 0.1 millimeters

Therefore, the change in length for a one-meter-long object subject to a 10-degree change in temperature would be on the order of a few millimeters, approximately 0.1 millimeters.

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Since F₁ is directed towards the south and F₂ is directed towards the east, we can use the Pythagorean theorem to find the magnitude of the net force:

 F = √(F₁² + F₂²)

The magnitude of the net electrostatic force on the test charge in newtons is given by the formula: F= k(q1q2)/r²

where k is Coulomb's constant, q1 is the charge on particle a, q2 is the charge on particle b, and r is the distance between the test charge and the other two charges.

Using the given values, we can find the magnitude of the net electrostatic force on the test charge as follows: F₁

= k(2e)(-2e)/(0.0200m)²F₂

= k(2e)(3e)/(0.0200m)²

The net force is obtained by taking the vector sum of F₁ and F₂.

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Answer:

The answer is . A 46.2g

Answer:

190 is the average velocity.

Explanation:

Just add them together

The lowest air pressure at 02Z16 February was approximately 1008 mb. From 16Z15 February to 02Z16 February, the air pressure at Pittsburgh was steadily falling. The air pressure change between 16Z15 February and 02Z16 February was approximately -13 mb.

In the given options, the lowest air pressure at 02Z16 February corresponds to option (a) 1008 mb. This indicates that at that particular time, the air pressure was around 1008 millibars.

During the period from 16Z15 February to 02Z16 February, the air pressure at Pittsburgh was steadily falling. This suggests a decrease in atmospheric pressure over time, indicating the presence of a weather system or storm in the vicinity. The statement mentions that the storm system and its fronts were just to the south of Pittsburgh, having moved swiftly up from the Gulf Coast in the 12 hours prior. This movement of the storm system can explain the steady decrease in air pressure observed during the given time period.

The air pressure change between 16Z15 February and 02Z16 February was approximately -13 mb. This means that the air pressure decreased by approximately 13 millibars during that time interval. The negative sign indicates a decrease in air pressure, which is consistent with the statement mentioning the steadily falling air pressure during the given period. The air pressure change is an important parameter in weather forecasting as it provides insights into the atmospheric conditions and the movement of weather systems.

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The mass of the second box car from the calculation is  22317 Kg.

We have to note that we can be able to obtain the momentum as the product of the mass and the velocity of the object that is to be studied. In the case of the cars that we have here;

The momentum before Collison = Momentum after collision

We would then have from the question;

(10300 * 19) + (M * 0) = (10300 + M) * 6

Let the mass of the second box car be M

Then;

195700 = 61800 + 6M

M = 22317 Kg

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Answer:

308,000 or 30.8×10^3

Explanation:

v=f×lamda

v is ?, f is 875Hz, lamda is 352m

v=875×352

v=308,000

v=30.8×10^3 m/s

The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.

In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.

The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.

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