Lab Report Guide
2. What procedure did you use to complete the lab?
Outline the steps of the procedure in full sentences.

Lab Report Guide2. What Procedure Did You Use To Complete The Lab?Outline The Steps Of The Procedure

Answers

Answer 1

Answer:

Explanation:

To be lab prepared one must follow these procedures-

1. One should have the knowledge of lab assignments to make the lab experiment easier.

2. To be aware about safety equipment and their uses in lab, like- the location of fire extinguisher in lab.

3. To know the steps of experiments to be performed

4. To fill notebook of lab with information regarding the experiment

5. One should review the data sheets of chemicals material safety.

6. To put on all the necessary dressings to perform experiment.

7. To have complete understanding about the experiment disposals.


Related Questions

plants are disinfectant by adding....
a) chlorine
b) iodine
c) flourine ​

Answers

The plants are disinfectant by adding chlorine. Hence, option A is the correct answer.

Chlorine is found to have disinfectant abilities when it is used on plants, so plants are disinfectant by adding chlorine. It helps to keep the plants safe from viruses and fungus. It operates by destroying the enzymes and genetic material of microbes by breaking the cell membrane.  

However, it is critical to apply chlorine at the optimum quantity and to thoroughly rinse it off to avoid any negative effects on the quality and safety of food products.

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can an atom win a tug of war

Answers

Answer:

Yes sirrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr

There are three isotopes of X element (X):
X-17 isotope: atomic mass17.2 amu, abundance:78.99%
X-18isotope: atomic mass 18.1 amu, abundance 10.00%
X-19isotope: atomic mass:19.1 amu, abundance: 11.01%
Calculate the average atomic mass of X.

Answers

Answer:

Average atomic mass = 17.5 amu.

Explanation:

Given data:

X-17 isotope = atomic mass17.2 amu, abundance:78.99%

X-18isotope =  atomic mass 18.1 amu, abundance 10.00%

X-19isotope = atomic mass:19.1 amu, abundance: 11.01%

Average atomic mass of X = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass)  / 100

Average atomic mass  = (78.99×17.2)+(10.00×18.1) +(11.01+ 19.1) /100

Average atomic mass =  1358.628 + 181 +210.291 / 100

Average atomic mass  = 1749.919 / 100

Average atomic mass = 17.5 amu.

Most modern medications are given in doses of milligrams. Thyroid medications, however, are typically given in doses of micrograms. How many milligrams are in a dose labeled 125 µg? View Available Hint(s) Most modern medications are given in doses of milligrams. Thyroid medications, however, are typically given in doses of micrograms. How many milligrams are in a dose labeled 125 µg? 1.25 x 105 mg 0.125 mg 1.25 x 10?4 mg 1.25 x 102 mg

Answers

Answer:

0.125 mg

Explanation:

The correct answer would be 0.125 mg

According to the conversion factor, one milligram of a sample is equivalent to one thousand micrograms of the same sample.

milligram = \(10^{-3}\)

microgram = \(10^{-6}\)

Hence,

1 milligram = 1000 micrograms or 1 microgram = \(10^{-3}\) milligram

Therefore, 125 micrograms will be:

  125/1000 = 0.125 milligram

What are the missing
coefficients?
_Fe + _Cl2 → _FeCl3

Answers

the coefficients should be 2:3:2

Fission
1.Uranium-235 decays naturally, by alpha decay. Write the balanced decay equation below. (5 points)
2.Uranium-235 has a half-life of about 700 million years. If 1 kg of U-235 is put on a shelf in a laboratory, how much of it will be left after 700 million years? (5 points)
.Uranium-235 is a popular choice of fuel for nuclear reactors. But U-235 doesn't always fission the same way. Below are three ways it can split. Complete the nuclear equations so they balance. (6 points)
days. After 1 kg of U-235 undergoes fission, the mass of the products is 8.4 x 10-4 kg less than the initial 1 kg. How much energy was produced by the fission of 1 kg of U-235? (Hint: Use Einstein's equation, E = mc2, where E is energy in Joules, m is mass in kilograms, and c is the speed of light, 3 x 108 m/s.) (8 points
Fusion
5.The fusion of two hydrogen isotopes is shown below. Complete the nuclear equation so it balances. (5 points)
6.If 1 kg of fuel is used in the above fusion reaction, the resulting helium has a mass of 0.993 kg. In other words, 0.007 kg of mass is converted to energy. How much energy is produced by the fusion of 1 kg of hydrogen? (Hint: Use Einstein's equation, E = mc2, where E is energy in Joules, m is mass in kilograms, and c is the speed of light, 3 x 108 m/s.) (6 points)
Alternative Energy
7.Hydrogen fuel cells combine hydrogen and oxygen to produce water and energy. Assume 1 kg of fuel is used, and the mass of the water produced is 1.10 x 10-11 kg. How much energy is produced by this fuel cell? (Hint: Use E = mc2.) (7 points)



btw i can predict the future and i can see that a dude named jamescodwell is gonna answer this question

Answers

Answer:

Fission

1.Uranium-235 decays naturally, by alpha decay. Write the balanced decay equation below. (5 points)

235/92 U = 231/90 Th + 4/2 He (i couldn't type the arrow thingy)

2.Uranium-235 has a half-life of about 700 million years. If 1 kg of U-235 is put on a shelf in a laboratory, how much of it will be left after 700 million years? (5 points)

1/2 kg of u-235 I think

3.Uranium-235 is a popular choice of fuel for nuclear reactors. But U-235 doesn't always fission the same way. Below are three ways it can split. Complete the nuclear equations so they balance. (6 points)

it can split into Be-56, Pu-52, and un 36.

4. Instead of allowing 1 kg of U-235 to decay naturally, imagine it is used as fuel in a nuclear

reactor. It is bombarded with neutrons, causing it all to fission in a matter of days. After 1 kg of U-235 undergoes fission, the mass of the products is 8.4 x 10-4 kg less than the initial 1 kg. How much energy was produced by the fission of 1 kg of U-235? (Hint: Use Einstein's equation, E = mc2, where E is energy in Joules, m is mass in kilograms, and c is the speed of light, 3 x 108 m/s.) (8 points)

Energy = mc2

Energy = (8.4 x 10^- 4) (3 x 10^8) ^2

Energy = 7.56 x 10^13  

there will be about 75600000000000 or 7.56 x 10^13 joules of energy produced by the fission of 1 kilogram of uranium 235  

(fact: this one problem alone took me 20 min of checking and rechecking and redoing and starting over to do, and I'm still pretty sure I got the number of 0's at the end wrong lol, though lucky for me I'm in honor's algebra so it didn't take me like 2 years to find the answer UWU)

Fusion

5.The fusion of two hydrogen isotopes is shown below. Complete the nuclear equation so it balances. (5 points)

2/1 H +2/1 H = 4/2 He + 1/0 N

wow this actually makes sense now

6.If 1 kg of fuel is used in the above fusion reaction, the resulting helium has a mass of 0.993 kg. In other words, 0.007 kg of mass is converted to energy. How much energy is produced by the fusion of 1 kg of hydrogen? (Hint: Use Einstein's equation, E = mc2, where E is energy in Joules, m is mass in kilograms, and c is the speed of light, 3 x 108 m/s.) (6 points)

6.3 x 10^14 joules of energy

Alternative Energy

7.Hydrogen fuel cells combine hydrogen and oxygen to produce water and energy. Assume 1 kg of fuel is used, and the mass of the water produced is 1.10 x 10-11 kg. How much energy is produced by this fuel cell? (Hint: Use E = mc2.) (7 points)

5.76 x 10^7 joules of energy.

Comparison

8.Complete the following table and questions. (8 points)

Reaction      Mass "Lost"   Energy Produced

Fission of 1 kg of U-235   1/2 kg     7.56 x 10^13 joules

Fusion of 1 kg of hydrogen   1/3 kg     6.3 x 10^13 joules

Fuel cell with 1 kg of hydrogen and oxygen  1/3 kg   5.4 x 10^13 joules

Which type of reaction "loses" the most mass?

the fission reaction of 1 kilogram of uranium 235

Which type of reaction produces the most energy? Why?

also the fission reaction of 1 kilogram of uranium 235, one reason that I think it is the reaction that produces more energy than the two other reactions is because of its "mass lost" since it lost 1/6 more mass than the other two reactions, or it might just be the elements that they use since they used uranium for fission, hydrogen for fusion, and hydrogen and oxygen for cell fueling.

Explanation:

Alkenes undergo an addition reaction with borane in tetrahydrofuran (THF).
For the reaction below:
((image))
Draw the structure of the major organic product.
Use the wedge/hash bond tools to indicate stereochemistry.
Use wedge and hash bonds ONLY when needed to show reaction stereochemistry.
If the reaction produces a racemic mixture, just draw one stereoisomer.

Answers

Alkyne chemistry refers to the branch of chemistry that deals with triple bonds between carbon atoms. Due to the presence of pi-electrons that are not tightly bound, alkynes undergo addition reactions.

Alkynes have a triple bond, which makes it possible to add halogens, water, and other substances to them through an addition reaction. A series of steps are used to create addition goods. The development of addition products is caused by the stability of vinylic cations. Asymmetric alkynes must adhere to Markovnikov's rule in order to conduct addition reaction. Below are a few addition reactions of alkynes that are explained: Alkenes are created when alkynes react with dihydrogen in the presence of catalysts like Pt/Pd/Ni. Alkanes are created when the produced alkenes further react with dihydrogen.

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Sodium and oxygen react to produce Sodium oxide. How many moles of sodium are needed to produce 2.83 grams of Sodium oxide

Answers

Answer

The moles of sodium needed to produce 2.83 grams of sodium oxide = 0.0914 moles.

Explanation

Given:

Mass of sodium oxide produced = 2.83 grams

What to find:

The moles of sodium needed to produce 2.83 grams of sodium oxide.

Step-by-step solution:

Step 1: Step 2: Write a balance equation for the reaction.

4Na + O₂ -------> 2Na₂O

Step 2: Convert 2.83 grams sodium oxide to mole using the mole formula.

\(Mole=\frac{Mass}{Molar\text{ }mass}\)

The molar mass of Na2O = 61.9789 g/mol

So, putting mass = 2.83 g and molar mass = 61.9798 g/mol, we have;

\(Mole=\frac{2.83g}{61.9798\text{ }g\text{/}mol}=0.0457\text{ }mol\)

Step 3: Calculate the mole of sodium needed using the balance equation and the mole of sodium oxide produced.

From the balanced equation;

4 moles Na produces 2 moles Na₂O

So, the moles of Na needed to produce 0.0457 moles Na₂O will be

\(\frac{0.0457mol\text{ }Na₂O}{2\text{ }mol\text{ }Na₂O}\times4\text{ }mol\text{ }Na=0.0914\text{ }mol\text{ }Na\)

The moles of sodium needed to produce 2.83 grams of sodium oxide = 0.0914 moles

Balance it by oxidation number method:Zn +HNO3----Zn(NO3)2+NO+H2O​

Answers

Answer:

Answer:

step 1:balance skeleton equation the chemical equation:

Zn +HNO3➔Zn(NO3)2+NO+H2O

step 2: identity undergoing oxidation or reduction

here

Zn➔Zn(NO3)2

Zn is oxidized from 0 to 2 in oxidation no.

HNO3➔NO

N is reduced from 5 to 2 in oxidation no

Step 3: calculate change in oxidation no.

change in oxidation no

in Zn=0-2=-2=2

in

N=5-2=3

Step 4: Balance it by doing crisscrossed multiplication

we get;

3Zn +2HNO3➔3Zn(NO3)2+2NO+H2O

step 6:Balance other atoms except H & O

3Zn +2HNO3➔3Zn(NO3)2+2NO+H2O

3Zn +2HNO3+6HNO3➔3Zn(NO3)2+2NO+H2O

finally: balance H

3Zn +8HNO3➔3Zn(NO3)2+2NO+4H2O

Answer:

Your ans is in the picture.

Balance it by oxidation number method:Zn +HNO3----Zn(NO3)2+NO+H2O

Which substance has ionic bonds BaO?

Answers

BaO has ionic bonds because of electronegative difference.

Ionic bonds, also known as electrovalent bonds, are a type of linkage created in a chemical compound by the electrostatic attraction of ions with opposing charges. When the valence (outermost) electrons of one atom are permanently transferred to another atom, a bond of this kind is created. If an atom gains electrons, it becomes a negatively charged ion (cation), while if it loses them, it becomes a positively charged ion (cation) (anion). Following is a brief discussion of ionic bonds. To learn more, go to chemical bonding: the ionic bonding process.

Ionic or electrovalent compounds are produced by ionic bonding, and the compounds formed between nonmetals and alkali and alkaline-earth metals serve as the best examples of this type of compound. Actually, a polar covalent bond is the extreme form of an ionic bond.

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. Write the two resonance hybrids for the carbocation that would be formed by protonation at C-1 of 2-methyl-1,3-pentadiene. Without doing a calculation, would you expect C-2 or C-4 (the two end carbons of the allylic cation) to have the most positive charge on it

Answers

Answer:

Answer is explained in the explanation section below.

Explanation:

This question is requires the diagram, which I have drawn and it is attached in the attachment below. Please for this answer, refer to the diagram attached in the attachment below.

Referring to the diagram, attached. As we know that, Allylic secondary carbocations are more stable than Allylic tertiary carbocations.

Hence,

C2 will have a more positive charge since a tertiary carbocation (C2) is more stable than a secondary carbocation (C4). Therefore, the resonance structure will favor the positive charge at C2.

. Write the two resonance hybrids for the carbocation that would be formed by protonation at C-1 of 2-methyl-1,3-pentadiene.

The resonance structure formed for 2-methyl 1-3 penatdiene are allylic secondary and tertiary carbocation compounds.

What is protonation?

Protonation is the addition of hydrogen or the protons to the carbon in an organic compound. The addition of hydrogen takes place at the carbon that forms the stable compound.

The protonation of 2-methyl-1,3 pentadiene is given in the image attached.

The expected carbocation in the structure with the positive charge is C-2, as it forms a more stable product than C-4 due to less repulsion.

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. Write the two resonance hybrids for the carbocation that would be formed by protonation at C-1 of 2-methyl-1,3-pentadiene.

The survival of aquatic organisms depends on the small amount of O2 that dissolves in H2O . The diagrams above represent possible models to explain this phenomenon. Which diagram provides the better particle representation for the solubility of O2 in H2O , and why?

Answers

Answer:

Diagram 1

Explanation:

The solubility of the oxygen gas in water has to do with the interaction of the oxygen with the dipoles in water.

Water is a polar molecule having oxygen as the negative dipole and hydrogen as the positive dipole.

Water can interact with the oxygen atoms in the molecule via intermolecular hydrogen bonds with molecular oxygen as shown in diagram 1.

The survival of aquatic organisms depends on the small amount of O2 that dissolves in H2O . The diagrams

What is the frequency of a wave moving at 24 m/s with a wavelength of 3 m?

A. 72 Hz
B. 0.014 Hz
C. 0.125 Hz
D. 8 Hz

Answers

Answer:

8 Hz

Explanation:

f = v/ λ

f = 24 m/s / 3 m

f = 8/ s    Hz =1/s

f = 8 Hz

Can someone help me on this?

Can someone help me on this?

Answers

Molecules are in constant motion due to their thermal energy, which is related to their temperature.

Why do molecules move faster and spread apart when heated?

As the molecules move faster, they are more likely to overcome the intermolecular forces that hold them together, causing them to break apart and become less cohesive. This can cause a solid to melt into a liquid, or a liquid to evaporate into a gas.

In summary, heating a substance increases the kinetic energy of its molecules, causing them to move faster, collide with one another with greater force, and spread apart from each other, resulting in an increase in volume and thermal expansion.

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What mass of NaCl is needed to produce a 26.4 mol/L with a 1.7 L volume?

Answers

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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A liquid ester used to flavour food is believed to be impure. What would be the best way of testing its purity?​

Answers

Answer:

Filter it

Explanation:

02 Question (6 points) 1st attempt IH See Periodic Table Name and define the four quantum numbers that identify the highest energy electron in a francium; Fr, atomic orbital; Symbol Value Principal quantum number Ancular momentum quantum number Magnetic quantum number Spin magnetic quantum number

Answers

The four quantum numbers that identify the highest energy electron in a francium, fr, atomic orbital are n, ℓ, m, and s.

Which four quantum numbers are there?

The energy levels of an atom are connected by a set of quantum numbers. The entire and singular quantum state of a single electron in an atom, also known as its wave function or orbital, is described and explained by the four quantum numbers, n, l, m, and s. Accordingly, the four quantum numbers are n, l, m, and s.

The quantum number is used to define the location of electrons, and an orbital is a place inside the atom where an electron can be found. The quantum number of the shell orbitals of an atom depends on the number of electron shells it contains.

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Which two surfaces would have the most friction between them

Answers

Answer: sand paper against wood

Explanation:

Calculate the volume in mL of 0.279 M Ca(OH)2 needed to neutralize 24.5 mL of 0.390 M H3PO4 in a titration.



Note: the answer should have 3 significant digits. Do not include the unit mL in the answer.

Answers

The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

Balanced equation

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

The mole ratio of the acid, H₃PO₄ (nA) = 2The mole ratio of the base, Ca(OH)₂ (nB) = 3

How to determine the volume of Ca(OH)₂ Molarity of acid, H₃PO₄ (Ma) = 0.390 MVolume of acid, H₃PO₄ (Va) = 24.5 mLMolarity of base, Ca(OH)₂ (Mb) = 0.279 MVolume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(0.39 × 24.5) / (0.279 × Vb) = 2/3

9.555 / (0.279 × Vb) = 2/3

Cross multiply

2 × 0.279 × Vb = 9.555 × 3

0.558 × Vb = 28.665

Divide both side by 0.558

Vb = 28.665 / 0.558

Vb = 51.4 mL

Thus, the volume of the Ca(OH)₂ solution needed is 51.4 mL

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The naturally occurring isotopes of potassium are potassium-39, potassium-40, and potassium-41. Potassium-39 has an abundance of 93.258% and a mass of 38.964 amu. Potassium-40 has an abundance of 0.011710% and a mass of 39.964 amu. Potassium-41 has an abundance of 6.7302% and a mass of 40.962 amu. Calculate the average atomic mass of potassium

Answers

Answer:

39.099 amu

Explanation:

saw this on quizlet no cap sorry im 3 weeks late

Consider the following reaction: COCl2(g) ⇌CO(g) + Cl2(g) Kc = 7.3x10-4 Calculate [CO]eq, [Cl2eq], and [COCl2]eq, respectully, if [COCl2]init=0.730M Group of answer choices no correct answer 0.0216; 0.0216; 0.708 0.229; 0.229; 0.501 0.0416; 0.0416; 0.688 0.0229; 0.0229; 0.707

Answers

The concentration of CO at Equilibrium is 0.0361 M

What is Equilibrium Concentration ?

It is a state of dynamic equilibrium where the ratio of the product and reactant concentrations is constant.

Given ;

Kc = 8.33 x 10⁻⁴Molarity of COCl₂ = 1.6 M

Balanced equation ;

COCl₂ (g) ⇌ CO (g) + Cl₂ (g)

Now, let's calculate final concentrations ;

Initial concentration of COCl₂ = 1.6MInitial concentration of CO and Cl₂ = 0M

There will react X M of COCl₂

Since, the mole ratio is 1 : 1

Final concentration of CO and Cl₂ will be X MFinal concentration of COCl₂ will be (1.6 - X) M

Now, Let's find Kc

Kc=  [CO] x [Cl₂] /  [COCl₂]  = 8.33 x 10⁻⁴

Kc = [X] x [X] / 1.6 - X = 8.33 x 10⁻⁴

8.33 x 10⁻⁴  = X² / (1.6 - X)

8.33 x 10⁻⁴ x (1.6 - X) = X²

0.0013328 - 8.33x 10⁻⁴ X = X²

X² + 8.33*10⁻⁴ X  - 0.0013328= 0

X = 0.0361 M = [CO] = [Cl₂]

[COCl₂] = 1.6 - 0.0361 = 1.5639 M

To balance this, we can calculate the Kc

Kc = (0.0361 x 0.0361) / 1.5639 = 0.000833

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Which is a fossil fuel? A. Biomass B. Wind C. Nuclear D. Petroleum​

Answers

Answer:

(D) petroleum

Explanation:

because as we know that petroleum is obtain from the sea bed,within the remains of animals and plants which lived millions of year ago......

Petroleum is a fossil fuel

A 20.00 mL sample of aqueous oxalic acid, H2C2O4 was titrated with a 0.09113 M solution of
potassium permanganate, KMnO4:
2????????????4- ( (????????) + 5 H2????2????4 (????????)+ 6 H+ (????????) → 10 ????????2(????) + 2 ????????2+ (????????) + 8 H2???? (ℓ)
A volume of 23.24 mL was required to reach the end point. What is the oxalic acid molarity?

Answers

The molarity of the oxalic acid solution titrated with the potassium permanganate solution is 0.053 M

To determine the molarity of the solution, stoichiometric relationships and rules of three are used.

Balanced equation of the reaction

2 KMnO4 + H2C2O4 → 2 CO2 + K2O + 2 MnO3 + H2O

Determination of moles of KMnO4 used

If there are 0.09113 mol of KMnO4 in 1 liter of solution then in 0.2324 liters there are:

X moles of KMnO4 = 0.02324 x 0.09113 x 1

X moles of KMnO4 = 0.0021 mole

Stoichiometric calculation of moles of oxalic acid

If 2 mol KMnO4 combines with 1 mol H2C2O4 then 0.0021 mol KMnO4 combines with:

X mol H2C2O4 = 0.0021 mol KMnO4 x 1 mol / 2 mol KMnO4

X mol H2C2O4 = 0.0021 x 1 / 2 = 0.001 mol

Calculation of the molarity of the oxalic acid solution

If there are 0.001 mol H2C2O4 in 0.02 liters of solution then in 1 liter there are:

X mol H2C2O4 = 1 x 0.001 / 0.02 = 0.053

Therefore, the molarity of H2C2O4 is 0.053M

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A 20.00 mL sample of aqueous oxalic acid, H2C2O4 was titrated with a 0.09113 M solution ofpotassium permanganate,

You need to prepare 50.00 mL of a pH 4.75 buffer solution using 0.600 M formic acid (pKa=3.74) and a 0.3000 M sodium formate. How many milliliters of formic acid are needed to prepare this buffer?

Answers

0.766 mL volume of formic acid is needed to prepare the buffer.

What is volume of formic acid?

To calculate the amount of formic acid needed to prepare the buffer, we can use the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

where pH is the desired pH of the buffer, pKa is the acid dissociation constant of the weak acid, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid.

First, we can rearrange the Henderson-Hasselbalch equation to solve for the ratio of [A-]/[HA]:

[A-]/[HA] = \(10^{(pH - pKa)}\)

[A-]/[HA] = \(10^{(4.75 - 3.74)}\)

[A-]/[HA] = 3.52

Next, we can use the fact that the sum of the concentrations of [A-] and [HA] must be equal to the total volume of the buffer solution times the total concentration of the buffer components:

[A-] + [HA] = (0.0500 L)(0.600 M + 0.3000 M)

[A-] + [HA] = 0.0450 mol

We can also express [A-] in terms of [HA] using the ratio we calculated above:

[A-] = 3.52[HA]

Substituting this into the previous equation, we get:

3.52[HA] + [HA] = 0.0450 mol

4.52[HA] = 0.0450 mol

[HA] = 0.00994 mol

Finally, we can use the molar mass of formic acid (46.03 g/mol) to calculate the volume of formic acid needed to prepare the buffer:

volume of formic acid = (0.00994 mol)(46.03 g/mol) / (0.600 mol/L)

volume of formic acid = 0.766 mL

Therefore, 0.766 mL of formic acid is needed to prepare the buffer.

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How many grams of oxygen can be obtained from 5.00 g of KCIO3

Answers

\({{{\sf{\green{1 \: g \: of \:

\: kclo3 \: would \: \: yield \:

.78335373 \: g \: of \

: o2 \: thus \: 5 g \: \:

of \: \: kclo3 \: \: would \

: yield \: \: 5 \ \times 0.783353733 g

\: \: of \: o2 \: \: or \: 4.

0 g \: \: o2}}}}}\)

!!(100 points)!! For each of the following chemical formulas, identify the elements present and the number of atoms of each element present in each molecule of the substance: H2SO4, Ca(NO3)2

Answers

Answer:

H2SO4 Chemical Name

It contains two atoms of hydrogen, one atom of sulphur, and four atoms of oxygen. It has an atomicity of seven.

Calcium Nitrate is made up of three different elements and contains a total of nine atoms. This compound's formula is Ca(NO3)2. There is one calcium atom, two nitrogen atoms, and there are six oxygen atoms in calcium nitrate.

H2SO4:

-Elements present:

Hydrogen (H), Sulfur (S), Oxygen (O)

Number of atoms of each element present in each molecule of the substance:

Hydrogen (H): 2 atoms

Sulfur (S): 1 atom

Oxygen (O): 4 atoms



Ca(NO3)2:

Elements present:

Calcium (Ca), Nitrogen (N), Oxygen (O)

Number of atoms of each element present in each molecule of the substance:

Calcium (Ca): 1 atom

Nitrogen (N): 2 atoms

Oxygen (O): 6 atoms (2 from each NO3 group)

Hello I need help with this question

Hello I need help with this question

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Deleted answer. ......

A student performed an investigation at sea level. First she placed 400 mL of water in four different containers. Then she placed the containers on hot plates with four different temperature settings, as shown in the table.

Answers

Answer:

  C. The boiling point of water

Explanation:

We assume your question is the one attached.

Obviously, the shape of the (liquid) water is a function of the container it is in, as it is for any liquid or gas.

The rate of evaporation will depend on the temperature and on the surface area. The different containers are different in both ways, so evaporation is not a constant.

The boiling point is a physical property of the water, so will be the same across all containers.

The amount of steam released is related to the rate of evaporation. It will not be a constant across the different containers.

__

The appropriate choice is ...

  The boiling point of water

A student performed an investigation at sea level. First she placed 400 mL of water in four different

whats the energy in joules of one mole of photons of visible light having a wavelength of 4.11×10^2 nm?​

Answers

The energy in joules of one mole of photons of visible light having a wavelength of 4.11×10^2 nm? can be expressed as 2.9*10^5 J

How can the energy be calculated?

From the question we were told to find the energy and the parameters that is needed to calculate these are;

c=3*10^8

h= 6.626 * 10^-34 J.s

1 mol photons = 6.023x10^23 photon

λ = 4.11×10^2 nm  = 4.11 × 10-7 meters

The parameters can be input  as Energy of one mole photon (E) = ( 6.023x10^23 * 6.626 * 10^-34 * 3*10^8)/ (4.11 × 10^-7)

=291302

=2.9*10^5 J

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which is the graph of the function g(x) = f(-x)​

Answers

To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

What is a graph of the function g(x) = f(-x)?

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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which is the graph of the function g(x) = f(-x)
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