Kinetic Energy is the energy an object possesses because of its motion. If the brakes of a car parked on top of a hill fail, the car's potential energy will be converted to kinetic energy.

Answer:

C. Count Noun

Explanation:

There are 21 maximum cyclic tensile stress that the part can experience such that it survives at least 1 million cycles

What is cyclic tensile stress?

The repeated occurrence and redistribution of forces acting on a material is known as cyclic stress. Periodic or consistent cyclic stress conditions enhance the material's wear and tear, which accelerates material degradation and failure.

The stress at which a force causes a material to extend before breaking is known as tensile strength. The breaking strength under tension of an axially loaded material is given by the equation s=P/a, where s is the breaking strength, P is the breaking force, and an is the cross sectional area. For beams, s=M/z, where M is the bending moment that might cause the beam to fail at the extreme fibre in tension, and z is the section modulus of the beam. S is the stress at the extreme fibre in tension. The type of material, the cross-sectional area, and in the case of beams, the section modulus, all affect the tensile strength.

Thus we can say maximum cyclic tensile stress needed is 21 Mpa

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Answer:

r = 1.922 mm

Explanation:

We are given;

Yield stress; σ = 250 MPa = 250 N/mm²

Force; F = 29 KN = 29000 N

Now, formula for yield stress is;

σ = F/A

A = F/σ

Where A is area = πr²

Thus;

r² = 2900/250π

r² = 3.6924

r = √3.6924

r = 1.922 mm

Answer:

Many would pair the engineering and science behind it together. The sensor requires have a detective system for when cars pass by. It can also cycle the lights (change from red, green, and yellow). Traffic can flow uninterrupted on the main road. So, science is an important part.

Answer:

Burj Khalifa is located in dubai UAE at over 828m

Explanation:

828 metres

Answer:

The Burji Khalifa, known as the Burj Dubai prior to its inauguration in 2010, is a skyscraper in Dubai, United Arab Emirates. With a total hight of 829.8 m and a roof hight of 828 m, the Burji Khalifa has been the tallest structure and building in the world since its topping out in 2009.

The tatal resistance of the series-parallel circuit with two resistor connected in parallel which combination is connected in series to a single resistor is 9 ohms.

This can be defined as the opposition to current flow in a circuit.

To calculate the total resistance, first we need to find the total resistance of the parallel resistor.

For parallel,

Where:

R' = Total resistance of the parallel resistor.

From the question,

Given:

Substitute these values into equation 1

Finally, we combine the effective parallel resistance in series to the single resistance to the the total resistance of the circuit.

Where:

From the question,

Substitute these values into equation 2

Hence, the total resistance of the circuit is 9 ohms.

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Answer:

Shallow foundations, often called footings, are usually embedded about a metre or so into soil. ... Another common type of shallow foundation is the slab-on-grade foundation where the weight of the structure is transferred to the soil through a concrete slab placed at the surface.

Explanation:

Because I said so.

Arrows shot from untuned bows are likely to have inconsistent and inaccurate flight paths.

When a bow is not properly tuned, it means that the various components of the bow (limbs, string, and arrow rest) are not working in harmony, leading to imprecise arrow release. Consequently, arrows shot from untuned bows may wobble, drift, or experience "porpoising" is up and down oscillation during flight. These irregularities can cause the arrow to miss the intended target or have unpredictable impact points. Therefore, it is crucial to tune a bow properly to ensure better arrow flight, improved accuracy, and overall enhanced shooting performance.

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The true power is obtained as 70.7 VA.

We define the power a the rate of doing work, we know that the power in a circuit is the product of the current and the voltage. In this case, we want to find the true power thus we have to involve the use of the phase shift in degrees.

Thus;

True power = PcosΦ

P =  100 VA

Φ = 45 degrees

True power =  100 VA * cos 45 degrees

True power = 70.7 VA

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The electric field given by E = 2(av - jaz) is a left-hand circularly polarized wave.  (Option A)

The real part of the equation,  2a(v)i, represents a wave with a sinusoidal variation in the x  -direction.

The imaginary   part of the equation,2a(z)j, represents a wave with a sinusoidal variation in the z-direction. The direction of polarization of a wave is given by the direction of the electric field vector.

In this case,the electric field vector is rotating in a counterclockwise direction, which is the definition of left  -hand circular polarization.

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The volumetric pipette is the most accurate device to measure the volume of a standard solution. Therefore, the correct answer is (c) i.e. volumetric pipette.

The volumetric pipette is the most accurate pipette out of all for measuring volumetric annalysis. Volumetric pipettes are glasswares that are designed to transfer a particular small volume of sample fluid from one container to another in a very stable and controlled manner while preserving an accurate record of each sample drop.

What are pipettes?

In the context of the laboratory, pipettes are used to transfer liquid from one container to another accurately and swiftly.  While there exist several different types of pipettes, it is vital to take into account that some certain pipettes offer more accuracy as a comparison to others.

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With regard to source and drain, M OS transistor structure is entirely symmetrical. Devices that are pM OS are d onor d oped while nM OS are acceptor d oped.

Why are MO SF ETs symmetrical?

It has 4 terminals, referred to as the body (B), source (S), g ate (G), and drain (D). It is symmetrical in that emitter and collector terminals or source and drain terminals can be switched, meaning that the input and output relationships remain the same.

What is the theory of M OS transistors?

A voltage supplied to the g ate of a M OS transistor, which uses a majority-carrier design, modulates the current flowing through a channel that connects the source and drain.

Transistors have many advantages over other electronic components, such as vacuum tubes and relays. They are smaller, lighter, more reliable, and more energy-efficient. Transistors are also capable of switching and amplifying signals at much higher speeds than vacuum tubes or relays.

There are many different types of transistors, each with its own unique characteristics and applications. Some examples include MOSFETs (metal-oxide-semiconductor field-effect transistors), JFETs (junction field-effect transistors), and IGBTs (insulated-gate bipolar transistors).

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Answer:

Explanation:

myth

Answer:

(a)Tb = 330.12 K (b)Tc =304.73 K (c)19.81 K/m (d) h =60.65 W/m². K

Explanation:

Solution

Given that:

The mass flow rate of engine oil m = 1.81 x 10^-3 kg/s

Diameter of the tube, D = 1cm =0.01 m

Electrical heat rate, q =76 W/m

Wall Temperature, Ts = 370 K

Now,

From the properties table of engine oil we can deduce as follows:

thermal conductivity, k =0.139 W/m .K

Density, ρ = 854 kg/m³

Specific heat, cp = 2120 J/kg.K

(a) Thus

The wall heat flux is given as follows:

qs = q/πD

=76/π *0.01

= 2419.16 W/m²

Now

The oil mean temperature is given as follows:

Tb =Ts -11/24 (q.R/k) (R =D/2=0.01/2 = 0.005 m)

Tb =370 - 11/24 * (2419.16 * 0.005/0.139)

Tb = 330.12 K

(b) The center line temperature is given below:

Tc =Ts - 3/4 (qs.R/k)= 370 - 3/4 * ( 2419.16 * 0.005/0.139)

Tc =304.73 K

(c) The flow velocity is given as follows:

V = m/ρ (πR²)

Now,

The The axial gradient of the mean temperature is given below:

dTb/dx = 2 *qs/ρ *V*cp * R

=2 *qs/ρ*[m/ρ (πR²) *cp * R

=2 *qs/[m/(πR)*cp

dTb/dx = 2 * 2419.16/[1.81 x 10^-3/(π * 0.005)]* 2120

dTb/dx = 19.81 K/m

(d) The heat transfer coefficient is given below:

h =48/11 (k/D)

=48/11 (0.139/0.01)

h =60.65 W/m². K

Besides the display, a significant battery drain for a mobile device can be attributed to the processing power and usage of resource-intensive applications.

The display of a mobile device is indeed a significant contributor to battery consumption due to its size and the power required to illuminate it. However, the processing power required to run various applications and tasks also has a considerable impact on battery life. Resource-intensive apps such as gaming, video editing, or augmented reality applications can put a strain on the device's processor, causing it to consume more power. Additionally, background processes, multitasking, and network activities like streaming or downloading large files can further drain the battery. Optimizing app usage, closing unnecessary background processes, and managing network connectivity can help mitigate the battery drain caused by these factors.

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Answer:

The development of homosapiens

Explanation:

People adapted to the harsh weather by creating tools and used land bridges to spread to new regions

The relationship between the DC link voltage and the stator frequency is crucial in a volts/hz inverter-fed induction motor drive and is maintained through the volts/hz control scheme to ensure constant magnetic flux in the motor.

In a closed-loop volts/hz inverter-fed induction motor drive, the DC link voltage and the stator frequency have a direct relationship. The stator frequency is proportional to the DC link voltage. This means that if the DC link voltage is increased, the stator frequency will also increase, and vice versa. The volts/hz control scheme maintains this relationship by adjusting the voltage and frequency in tandem to keep the magnetic flux in the motor constant. If the motor is overloaded or underloaded, the volts/hz control scheme adjusts the DC link voltage and the stator frequency to maintain the constant magnetic flux.

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If two of these loads that's rated to use 2.2 KW at 240 volts are connected to the same electric circuit, the total circuit current is double that of one load.​

An electric circuital can be defined as an interconnection of different electrical components, in order to create a pathway for the flow of electric current (electrons) due to a driving voltage.

Generally, an electrical circuit comprises the following electrical components:

In this scenario, we can infer and logically conclude that if two of these loads that's rated to use 2.2 KW at 240 volts are connected to the same electric circuit, the total circuit current is double that of one load.​

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The flashing arrow panels are not used just at night but are used even during the day time. These are necessary to give the directional information to the drivers. Thus, the given statement is false.

The safety instructions are necessary for the drivers as absence of these would lead to increased number of accidents which could lead to death of a number of people. The flashing arrow panels is one of these instructions.

Flashing arrow panels are used during the day as well as at the night to give advance warning and directional information to the drivers where it is required to move to the right or to the left into another lane.

Some of the safety systems used at level crossings include amber and red warning lights on majority of roads, people should stop when the amber lights come on, unless vehicle has already crossed the stop line.

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The correct answer is Specific weight: w = [weight ÷ volume] = [9N ÷ 0.001m³] = 9000N/m³Density: w = [ × g] Where, g = acceleration due to gravity = 9.81m/sec². Specific gravity: G = [density of liquid ÷ density of water] As you know, The density of water = 1000kg/m³.

The density of a substance is divided by the density of water at 4 degrees Celsius to determine its specific gravity. The density of the substance and the density of the water must be represented in the same units for the calculation.distinguishes  While specific weight has dimensions, specific gravity is a dimensionless number. The gravitational field has no effect on a material's specific gravity, but it does have an effect on a material's specific weight. A substance's "Specific Gravity" is determined by dividing its mass by the mass of an equivalent volume of water at the same pressure and temperature.

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The pressure would be doubled (3800psi) as the day heats up because of the sun, the temperature increases to 105°F.

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Answer:

that answer is correct

Explanation:

This answer is correct because they explained everything they needed.

Explanation:

R = √(A²+B²–2ABCos(x°))

x⁰ = 180–135

x° = 45°

R = √(350²+180²–2(350(180))Cos(45)))

R = 256.524

The productivity index (PI) for this well is 6.9 STB/day/psi.

The Productivity Index (PI) for this well is approximately 6.9 STB/day/psi.What is Productivity Index (PI)?Productivity index (PI) is a performance metric used to assess the capacity of an oil or gas well to produce hydrocarbons. It is a measure of the well's productivity that relates to the pressure drop across the wellbore's reservoir section and the flow rate of fluids (oil, gas, or water) from the reservoir into the wellbore.When the PI value is high, it means the well is very productive. When the PI is low, it means that the well is not very productive.The formula for the Productivity Index (PI) is as follows:PI = (2πkhd)/(μln(r_e/r_w) + s)Where:k = average permeability, mdh = net reservoir thickness, ftμ = fluid viscosity, cpd = drainage area, acr = wellbore radius, fts = skin factorPI Calculation:Given data,Net pay thickness (h) = 75 ftNet to gross ratio = 0.9Porosity (φ) = 6.5%Average permeability, k = 2 md and 15 md in the vertical and horizontal directions, respectivelyRelative permeability (kro) = 0.82Oil viscosity (μ) = 0.55 cpFormation volume factor (Bo) = 1.22 bbl/STBWellbore radius (rw) = 6 in. or 0.5 ftDrainage area (Ad) = 55 acres = (55 × 43560) ft² = 2395800 ft²Well length (L) = 1500 ftSkin value (s) = 0.8Correction factor for wellbore friction = 1.0The first step is to calculate the effective drainage radius (re) using the formula,re = (0.00708 × (φ^2) × (kh/μ))^(1/2)× (kro/Bo) × ln(r_e/r_w)Let's plug in the values of given parameters,re = (0.00708 × (0.065^2) × ((2+15)/2/μ))^(1/2) × 0.82/1.22 × ln(r_e/r_w)re = (0.04226/μ)^(1/2) × ln(r_e/r_w)We know, k = 2 md and 15 md in vertical and horizontal directions. So we use the harmonic average permeability.1/kh = 1/2 + 1/15kh = 2.14 mdUsing μ = 0.55 cp, the effective drainage radius is calculated as,re = 174.86 ftUsing the formula of PI,PI = (2πkh)/[μln(re/rw) + s]PI = (2 × 3.1416 × 2.14 × 1500)/(0.55 × ln(174.86/0.5) + 0.8)PI = 6.9 STB/day/psi.

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Answer:

If you're carrying a load that extends beyond the sides of your vehicle, you don't need to clearly mark it unless it extends more than four feet beyond the rear of the vehicle.

Explanation:

fluid, i. e., water enters the heat exchanger at 20°c and exits at 70°c. assuming the fouling factor on the oil side and water side to be 0.00015 m2 ·k/w and 0.0001 m2 ·k/w, respectively, determine the overall heat transfer coefficient on inner and outer surface of the copper tube.xgjicbb .follow me

Answer:

Increasing following distance to Four-seconds when encountering other motorists who follow too closely  is an example of appropriate implementation of the IPDE defensive driving strategy for the  maintenance of an appropriate Safety Cushion.

Explanation:

Maintaining the required safety cushion by utilizing the IPDE defensive driving strategy to manage the nine to fifteen space driving zones involves continuous scanning.  Therefore, motorists should be able to identify objects and hazards in the driving scene, line of sight, and path of travel.  They should predict points of driving conflicts.  They should determine appropriate and safe driving actions to take, when, and where.  Finally, action is required to ensure that conflicts are avoided.

The dual problem of a linear programming problem can be found by flipping the inequality signs and re-assigning the objective function as a constraint.

Given the following linear programming problem min 4x1 - 3 x2 subject to 3x1 - x2 ≤ 6 5x1 - 4x2 ≥ 8 x1 - 6x2 =5 x1, x2 ≥ 0To find the dual of the problem, the following steps can be taken:

Step 1: Flip the problem The first step in finding the dual problem is to flip the inequality signs of the constraint of the original problem. The constraints of the original problem are as follows:3x1 - x2 ≤ 65x1 - 4x2 ≥ 8x1 - 6x2 = 5Flipping the inequality signs of the above equations results in the following:3x1 - x2 ≥ 65x1 - 4x2 ≤ 8x1 - 6x2 = 5

Step 2: Re-assign the objective The next step is to re-assign the objective function of the original problem as a constraint. That is, the coefficients of the original objective function are used as constraints in the dual problem. Thus, for the given problem,

we have:4x1 - 3x2 = x0Step 3: Formulate the dual problem The dual problem can now be formulated by using the re-assigned objective function and the flipped inequality signs of the original problem. The coefficients of the original problem form the new objective function of the dual problem, while the flipped inequalities form the constraints of the dual problem. Therefore, the dual problem of the given problem is: minimize 6y1 + 8y2 + 5y3, subject to:3y1 + 5y2 + y3 ≥ 4- y1 - 4y2 - 6y3 ≥ -3Where y1, y2 and y3 are the dual variables corresponding to the original constraints. Thus, the dual problem of the given problem has been found.

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