Weight of jenny's book will be 10N.
What is weight?The force exerted on an object by gravity is known as its weight. Weight is the result of multiplying the mass by the acceleration that is acting on it. The pound (lb), which is the most often used unit of weight, is equivalent to 1 kilogram meter per second squared (N), the SI unit of weight. The impact of gravity (or another acceleration) on an object is quantified by its weight. At various points on the Earth, two causes alter weight. Weight reduces as altitude rises. Latitude also affects weight.
Area=200cm²
p=0.05N/cm²
weight=thrust=Force
p=F/A
0.05×200=F
F=10N
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6. Total current in a parallel circuit is equal to ?
Answer:
A Parallel circuit has certain characteristics and basic rules: A parallel circuit has two or more paths for current to flow through. Voltage is the same across each component of the parallel circuit. The sum of the currents through each path is equal to the total current that flows from the source.
Explanation:
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what evidence do you have that the rocket cart is accelerating?yes, it is speeding up but how do you know
As the rocket cart speeds up, the velocity changes with time which causes the rocket cart to accelerate.
Acceleration is the change in velocity per change in time of motion.
When an object accelerates upwards, the velocity of the object is changing with time.
In addition, speed describes the magnitude of the given velocity. If the speed of an object change with direction, then the velocity of the object is changing.
Since the rocket cart is speeding up, the speed is changing with time and the velocity will be changing as well. This will result in increase of the cart's acceleration.
Thus, as the rocket cart speeds up, the velocity changes with time which causes the rocket cart to accelerate.
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Questions:
(a) Why should the amplitude of oscillation be small on a pendulum experiment
As an electron that is placed between the plates below moves toward the positive plate, the force acting on it.
As an electron moves towards the positive plate in a uniform electric field between two parallel plates, the distance between the electron and the positive plate decreases, force causing the electric field between them to increase. Hence, the correct option is (2).
In the given diagram, there is a uniform electric field between two parallel plates, with the positive plate on the left and the negative plate on the right. When an electron is placed between the plates and moves towards the positive plate, it experiences a force due to the electric field. The direction of this force is opposite to the direction of the electric field and is given by F = qE, where F is the force, q is the charge of the electron, and E is the electric field. As the electron moves towards the positive plate, the distance between the electron and the positive plate decreases, which means that the electric field between them increases. Therefore, the force acting on the electron also increases according to F = qE. Hence, the correct option is (2) increases.
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2(a)Find the density of air filled in polythene container with mass of 0.419kg when it is empty. When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times
When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.
The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.
Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:
Mass of air = Mass of filled container - Mass of empty container
= 0.428 kg - 0.419 kg
= 0.009 kg
Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:
Volume of air = Volume of perplex box * Number of times air inside
= 1000 cm³ * 7.2
= 7200 cm³
Convert the volume of air to cubic meters (m³) by dividing by 1000000:
Volume of air = 7200 cm³ / 1000000
= 0.0072 m³
Calculate the density of air using the formula:
Density = Mass / Volume
Density = 0.009 kg / 0.0072 m³
≈ 1.25 kg/m³
Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.
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A parallel circuit has four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. How much current is supplied by the source?
A parallel circuit is an electrical circuit with more than one current path and all circuit components are connected between the same two sets of electrically common points. The current supplied by the source in a parallel circuit is equal to the sum of all branch currents in the circuit.
The sum of the branch currents in a parallel circuit can be calculated by adding up the values of the individual branch currents. In this case, we have four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. Thus, the sum of the branch currents is:120 mA + 380 mA + 250 mA + 2.1 A= 2.85 ATherefore, the current supplied by the source in this parallel circuit is 2.85 A. This is because, in a parallel circuit, the current from the source is split between the different branches of the circuit. Each branch will have a different current, but the sum of all the branch currents will always equal the current supplied by the sourceFor such more question on parallel circuit
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Fill in the blanks using the following words: Solid, Liquids, Gasses, More, Less, Gas, Fluids, Higher, Lower, Sun, Radiation, Conductors
● Radiation transfers heat best through _________ because there is _______ space between the particles.
● Conduction transfers heat best through _______ because there is space between the particles.
● Convection transfers heat best through _______ which includes _______ and ______.
● Heat always moves from _________ temperature to _________ temperature.
● Heat from ______ travels to earth by ___________.
● Solids that transfer heat well ate known as _____________.
Answer:
Blank 1: Gasses
Blank 2: More
Blank 3: Solids
Blank 4: Fluids
Blank 5: Liquid
Blank 6: Gas
Blank 7: Higher
Blank 8: Lower
Blank 9: Sun
Blank 10: Radiation
Blank 11: Conductors
P.S. order of answers does not matter between Blank 5 and 6.
Which of these is a characteristic of the Milky Way galaxy
A. It looks like a faint Bond of clouds in the night sky.
B It has no gas and dust for a new stars
C it is not moving through space
D It has only one star with planets
Answer:
A
Explanation:
Spacecraft instruments measure the radiation from an asteroid, and the data show that the power per unit wavelength peaks at 40 μm. Assuming the asteroid is a blackbody, find its surface temperature.
The surface temperature of the asteroid, assuming it is a blackbody, is approximately 72.45 K, based on the peak wavelength of 40 μm.
To find the surface temperature of the asteroid, we can use Wien's displacement law, which states that the peak wavelength of radiation emitted by a blackbody is inversely proportional to its temperature. Given that the power per unit wavelength peaks at 40 μm, we can calculate the surface temperature of the asteroid.
1. According to Wien's displacement law, the peak wavelength (λ) is related to the temperature (T) by the equation: λ_max = (b / T), where b is Wien's displacement constant equal to 2898 μm·K.
2. We are given that the peak wavelength is 40 μm. Substituting this value into the equation, we have: 40 μm = (2898 μm·K / T).
3. Rearranging the equation, we find: T = (2898 μm·K) / (40 μm).
4. Calculating the values, we get: T = 72.45 K.
Therefore, the surface temperature of the asteroid, assuming it is a blackbody, is approximately 72.45 K.
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Calculate the wave speed (in m/s) for the following waves:
a) A sound wave in steel with a frequency of 500 Hz and a wavelength of 3.0 meters. (2pts)
b) a ripple on a pond with a frequency of 2 Hz and a wavelength of 0.4 meters. (2pts)
Calculate the wavelength (in meters) for the following waves:
A wave on a slinky spring with a frequency of 2 Hz travelling at 3 m/s. (2pts)
An ultrasound wave with a frequency 40,000 Hz travelling at 1450 m/s in fatty tissue. (2pts)
Calculate the frequency (in Hz) for the following waves:
A wave on the sea with a speed of 8 m/s and a wavelength of 20 meters. (2pts)
A microwave of wavelength 0.15 meters travelling through space at 300,000,000 m/s. (2pts)
Answer: A : 250 is the answer
B; The frequency of a wave is the number of complete oscillations (cycles) made by the wave in one second.
Instead, the wavelength is the distance between two consecutive crests (highest position) or 2 troughs (lowest position) of the wave.
In this problem, we are told that the leaf does two full up and down bobs: this means that it completes 2 full cycles in one second. Therefore, its frequency is
where is called Hertz (Hz). So, the correct answer is
Explanation:
#Wavespeed
#1
\(\\ \rm\Rrightarrow v=\nu\lambda=500(3)=1500m/s\)
#2
\(\\ \rm\Rrightarrow v=2(0.4)=0.8m/s\)
#Wavelength
#1
\(\\ \rm\Rrightarrow \lambda=\dfrac{v}{\nu}=\dfrac{3}{2}=1.5m\)
#2
\(\\ \rm\Rrightarrow \lambda= \dfrac{1450}{40000}=0.03625m\)
#Frequency
\(\\ \rm\Rrightarrow \nu=\dfrac{v}{\lambda}=\dfrac{8}{20}=0.4Hz\)
#2
\(\\ \rm\Rrightarrow \nu=\dfrac{3\times 10^8}{15\times 10^{-2}}=0.2\timee 10^{10}=2\times 10^9Hz\)
A force of 6.7 N acts on a 30 kg body initially at rest. Compute the work done by the force in (a) the first, (b) the second, and (c) the third seconds and (d) the instantaneous power due to the force at the end of the third second.
Answer:
(a) 0.748 J
(b) 2.245 J
(c) 3.74 J
(d) 4.482 W
Explanation:
(a) Work done W = Force × distance
W = F×d,
Where d = 1/2(at²)
Therefore,
W =1/2(F×at²)................ Equation 1
Where a = acceleration, t = time.
But,
a = F/m...................... Equation 2
Where m = mass.
Substitute equation 1 into equation 2
W = 1/2(F²t²/m)................. Equation 3
Given: F = 6.7 N, t = 1 s, m = 30 kg
Substitute into equation 3
W₁ = 1/2(6.7²×1²/30)
W = 0.748 J.
(b) Similarly,
The work done in the second seconds is
Where t₂ = 2 s
W₂ = 1/2(F²t₂²/m)- W₁
W = 1/2(6.7²×2²/30)-0.748
W = 2.245 J
(c) The work done in the third seconds is
Where t₃ = 3 s
W₃ = 1/2(F²t₃²/m)-(W₂+W₃)
W = 1/2(6.7²×3²/30)-(2.993)
W = 3.74 J.
(d) P = Fv ............... Equation 4
Where v = velocity.
and,
v = at..................... Equation 5
Substitute equation 5 into equation 4
P = Fat................... Equation 6
Given: F = 6.7 N, a = 6.7/30 = 0.223 m/s², t = 3 s
Substitute into equation 6
P = 6.7×0.223×3
P = 4.482 W.
wire (mass = 50 g, length = 40 cm) is suspended horizontally by two vertical wires which
conduct a current I = 8.0 A, as shown in the figure. The magnetic field in the region is into the
paper and has a magnitude of 60 mT. What is the tension in either wire?
The magnetic field in the region is into the paper and has a magnitude of 60 mT and the tension in either wire is 0.096 N.
To find the tension in either wire, we can apply the equation for the force experienced by a current-carrying wire in a magnetic field.
The force experienced by a current-carrying wire in a magnetic field is given by the equation F = B * I * L * sin(θ), where B is the magnetic field strength, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.
In this case, the wire is suspended horizontally by two vertical wires, and the magnetic field is into the paper. Since the wire is horizontal, the angle between the wire and the magnetic field is 90 degrees, so sin(θ) = 1.
The force experienced by the wire due to the magnetic field is F = B * I * L.
Given:
Current (I) = 8.0 A
Magnetic field (B) = 60 mT = 60 * 10^(-3) T
Length of the wire (L) = 40 cm = 40 * 10^(-2) m
Substituting the given values into the equation, we get:
F = (60 * 10^(-3) T) * (8.0 A) * (40 * 10^(-2) m)
Simplifying the expression, we find:
F = 0.192 N
Since the wire is suspended by two vertical wires, the tension in each wire will be half of the total force. Therefore, the tension in either wire is 0.192 N / 2 = 0.096 N.
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A force of x Newtons is applied at an angle of x degrees above the horizontal to
a mass of x kg which sits on an incline of angle x degrees. The coefficient
of friction between the mass and the incline is x. For a sufficient applied force so
that the mass moves upward , the net force is given by the expression
F_net = F * cos(α + β) - m * g * sin(β) - u * N
Note:
F_net = net force
F = applied force
α = angle of the applied force
β = angle that the mass sits on
m = mass
g = gravity
u = coefficient of friction between the mass and the incline
N = normal force of the object
Determine the expression to find the angle of the applied force (α).
Show all work/steps.
Hello,
I hope you and your family are doing well!
To find the angle of the applied force (α), you can rearrange the equation for the net force to solve for α. The equation for the net force is:
F_net = F * cos(α + β) - m * g * sin(β) - u * N
To solve for α, you can start by isolating the term containing α. You can do this by subtracting the other terms from both sides of the equation, which gives you:
F_net - F * cos(β) + m * g * sin(β) + u * N = F * cos(α + β)
Then, you can divide both sides of the equation by F * cos(β) to get:
[F_net - F * cos(β) + m * g * sin(β) + u * N] / (F * cos(β)) = cos(α + β)
Next, you can use the identity cos(a + b) = cos(a)cos(b) - sin(a)sin(b) to rewrite the right side of the equation:
[F_net - F * cos(β) + m * g * sin(β) + u * N] / (F * cos(β)) = cos(α)cos(β) - sin(α)sin(β)
Finally, you can rearrange this equation to solve for α:
α = atan2(sin(α) * cos(β) + cos(α) * sin(β), cos(α) * cos(β) - sin(α) * sin(β))
This equation gives the angle of the applied force (α) in terms of the other variables in the equation for the net force.
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What was the big bang?
The big bang is how astronomers explain the way the universe began. It is the idea that the universe began as just a single point, then expanded and stretched to grow as large as it is right now—and it is still stretching!
What's This Big Bang All About?
In 1927, an astronomer named Georges Lemaître had a big idea. He said that a very long time ago, the universe started as just a single point. He said the universe stretched and expanded to get as big as it is now, and that it could keep on stretching.
What an Idea!
The universe is a very big place, and it’s been around for a very long time. Thinking about how it all started is hard to imagine.
Some More Information
Just two years later, an astronomer named Edwin Hubble noticed that other galaxies were moving away from us. And that’s not all. The farthest galaxies were moving faster than the ones close to us.
This meant that the universe was still expanding, just like Lemaître thought. If things were moving apart, it meant that long ago, everything had been close together.
Everything we can see in our universe today—stars, planets, comets, asteroids—they weren't there at the beginning. Where did they come from?
A Tiny, Hot Beginning
When the universe began, it was just hot, tiny particles mixed with light and energy. It was nothing like what we see now. As everything expanded and took up more space, it cooled down.
The tiny particles grouped together. They formed atoms. Then those atoms grouped together. Over lots of time, atoms came together to form stars and galaxies.
The first stars created bigger atoms and groups of atoms. That led to more stars being born. At the same time, galaxies were crashing and grouping together. As new stars were being born and dying, then things like asteroids, comets, planets, and black holes formed!
I have multiple voltage sources of different rating like 5V,6V,1V and 20V draw schematic diagram using these sources to power a light of rating 11 volt
Answer:
add molecules
A torque of T= 4Nm is required to rotate the intermediate cylinder at W= 30 rad/min .
Calculate the viscosity of the
oil. All cylinders are 450 mm long. Neglect the end effects.
R=0.15m, t=0.003 m.
Result: 1.258 N.s/m
The viscosity of the oil with a torque 4Nm and a rotational speed is 30 rpm is 0.2003 N.s/m.
From the given,
torque = 4Nm
rotational speed = 30 rpm = (30 × 3.14)/60 = 3.14 rad/sec
radius = 0.15 m
thickness (h) = 0.003 m
To find linear velocity,
V = R×ω
= 0.15×3.14
V =0.471 m/s
The dragging force,
F = 2μA(V/h) (V is linear velocity and h is the thickness )
Area = area of cylinder = 2πRH, R is radius and H is the height of the cylinder.
F = 2μ(2πRH) (V/h)
= 2μ(2×3.14×0.15×0.45) (0.471/0.003)
= 133.10 μ (μ is the viscosity of the oil)
F = 133.1μ
Torque (τ) = Force × radius
4 Nm = 133.1μ × 0.15
μ = 4 / (133.1×0.15)
= 0.2003 N.s/m
The viscosity of the oil is 0.2003 N.s/m.
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A)How much heat does it take to increase the temperature of 2.10 molmol of an ideal gas by 60.0 KK near room temperature if the gas is held at constant volume and is diatomic?
B)What is the answer to the question in part A if the gas is monatomic?
A) It would take 2079 J of heat to increase the temperature of 2.10 mol of a diatomic gas by 60.0 K at a constant volume.
B) It would take 1244 J of heat to increase the temperature of 2.10 mol of a monatomic gas by 60.0 K at a constant volume.
What is the difference between diatomic and monoatomic?The terms "diatomic" and "monoatomic" describe how many atoms make up a molecule or an ion. Diatomic molecules, like O2 or HCl, are made up of two covalently connected atoms of the same element. On the other hand, monoatomic species are made of a single atom, which could be neutral like helium or argon or charged like cations and anions. Diatomic molecules have unique chemical properties and are frequently involved in chemical processes, whereas monoatomic species normally exist as gases under normal conditions and are relatively inert. In the study of chemistry and physics, the contrast between diatomic and monoatomic particles is significant, particularly in understanding the behavior of various elements and their interactions with other substances.
(A) To calculate the amount of heat required to increase the temperature of 2.10 mol of a diatomic gas by 60.0 K at constant volume, we can use the formula: Q = nCvΔT
where Q is the amount of heat, n is the number of moles of the gas, Cv is the molar heat capacity at constant volume, and ΔT is the change in temperature. For a diatomic gas, Cv = (5/2)R, where R is the gas constant.
So, substituting the given values, we get:
Q = (2.10 mol)(5/2)(8.31 J/mol·K)(60.0 K)
Q = 2079 J
Therefore, it would take 2079 J of heat to increase the temperature of 2.10 mol of a diatomic gas by 60.0 K at a constant volume.
B) For a monatomic gas, Cv = (3/2)R. So, using the same formula as above, we get:
Q = (2.10 mol)(3/2)(8.31 J/mol·K)(60.0 K)
Q = 1244 J
Therefore, it would take 1244 J of heat to increase the temperature of 2.10 mol of a monatomic gas by 60.0 K at a constant volume.
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) To calculate the amount of heat required to increase the temperature of 2.10 mol of a diatomic gas by 60.0 K at constant volume, we can use the formula:
Q = nCvΔT
where Q is the amount of heat, n is the number of moles of the gas, Cv is the molar heat capacity at constant volume, and ΔT is the change in temperature. For a diatomic gas, Cv = (5/2)R, where R is the gas constant.
So, substituting the given values, we get:
Q = (2.10 mol)(5/2)(8.31 J/mol·K)(60.0 K)
Q = 2079 J
Therefore, it would take 2079 J of heat to increase the temperature of 2.10 mol of a diatomic gas by 60.0 K at constant volume.
B) For a monatomic gas, Cv = (3/2)R. So, using the same formula as above, we get:
Q = (2.10 mol)(3/2)(8.31 J/mol·K)(60.0 K)
Q = 1244 J
Therefore, it would take 1244 J of heat to increase the temperature of 2.10 mol of a monatomic gas by 60.0 K at constant volume.
A farmer hitches her tractor to a sled loaded with firewood and pulls it a distance
of 20 m along level ground (Figure 3). The total weight of sled and load is 14,700
2
N. The tractor exerts a constant 5000 N force at an of 36.9
◦ angle of above the
horizontal. A 3500 N friction force opposes the sled’s motion. Find the work
done by each force acting on the sled and the total work done by all the forces.
(a) The work done by the force applied by the tractor is 79,968.47 J.
(b) The work done by the frictional force on the tractor is 55,977.93 J.
(c) The total work done by all the forces is 23,990.54 J.
Work done by the applied forceThe work done by the force applied by the tractor is calculated as follows;
W = Fd cosθ
W = (5000 x 20) x cos(36.9)
W = 79,968.47 J
Work done by frictional forceW = Ffd cosθ
W = (3500 x 20) x cos(36.9)
W = 55,977.93 J
Net work done by all the forces on the tractorW(net) = work done by applied force - work done by friction force
W(net) = 79,968.47 J - 55,977.93 J
W(net) = 23,990.54 J
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The rock and meterstick balance at the 25-cm mark, as shown in the sketch. The meterstick has a mass of 1 kg. What must be the mass of the rock? (Show work).
Answer:
1 kgExplanation:
Check the diagram attached below for the diagram.
Let the weight of the rock be W and the mass of the meter stick be M. Note that the mass of the meter stick will be placed at the middle of the meter stick i.e at the 50cm mark
Using the principle of moment to calculate the weight of the rock. It states that the sum of clockwise moments is equal to the sum of anti clockwise moment.
Moment = Force * perpendicular distance
The meterstick acts in the clockwise direction while the rock acys in the anti clockwise direction
Clockwise moment = 1kg * 25 = 25kg/cm
Anticlockwise moment = W * 25cm = 25W kg/cm
Equating both moments of forces
25W = 25
W = 25/23
W = 1 kg
The mass of the rock is also 1 kg
A 175,000 kg space probe is landing on an alien planet with a gravitational acceleration of 8.25. If its fuel is ejected from the rocket motor at 35,000 m/s what must the mass rate of change of the space ship (delta m)/(delta t) be to achieve at upward acceleration of 2.00 m/s^2? Remember to use the generalized form of Newton's Second Law.
answer with correct units
The mass rate of change of the space probe is approximately 28.49 kg/s .
What is the mass rate of the space probe?To solve this problem, we can use the generalized form of Newton's Second Law, which states that the force acting on an object is equal to its mass times its acceleration:
F = ma
In this case, the force acting on the space probe is the thrust force generated by the rocket motor, which is equal to the rate of change of momentum of the ejected fuel:
F = (Δ m /Δt) * v
where;
Δ m /Δt t is the mass rate of change of the space ship, and v is the velocity of the ejected fuel, which is given as 35,000 m/s.Since the space probe is landing on the planet, the net force acting on it should be equal to the force of gravity pulling it down minus the upward thrust force generated by the rocket motor. So we can write:
F_net = m * g - (Δ m /Δt) * v
Plugging in the values and solving for delta m / delta t, we get:
2.00 m/s² = (175,000 kg * 8.25 m/s²) - (Δ m / Δt) * 35,000 m/s
Δ m / Δt = (175,000 kg * 8.25 m/s² - 2.00 m/s² * 35,000 m/s) / 35,000 m/s
Δm / Δt ≈ 28.49 kg/s
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What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
Oarea in contact between the two substances
specific heat of the material that makes up the substances
density of the two substances in contact
Answer:
The characteristics that determine how easily two substances change temperature are:
specific heat of the material that makes up the substancesarea in contact between the two substancesThe volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.
Explanation:
Your physics teacher crumples a piece of paper into a ball and releases it from
rest 1.5 m from the ground. How long does the ball take to hit the ground?
We have that it takes the ball \(t=0.553sec\) to take to hit the ground
\(t=0.553sec\)
From the Question we are told that
Initial height \(s=1.5m\)
Generally the equation for Time is mathematically given as
\(S=ut+1/2at^2\\\\1.5=0.5*9.8\)
\(t=0.553sec\)
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The paper ball will hit the ground from 1.5 m at 0.55 s.
Here we can use the free fall kinematics equations. Let's see that the paper ball falls from the rest, so the initial velocity will be 0.
\(y=y_{i}+v_{i}t-0.5gt^{2}\)
Here:
y is the final heighty(i) is the initial heightv(i) initial velocity (will be 0)g is the gravity (9.81 m/s²)t the timeNow, the initial height will be 1.5 m, putting our reference system zero in the ball. So, the final height will be 0 m, because it hits the ground.
\(0=1.5-0.5(9.81)t^{2}\)
Therefore, we just need to solve it for t.
\(t=\sqrt{\frac{3}{9.81}}\)
\(t=0.55\: s\)
The ball will hit the ground at 0.55 s.
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4. At the top of a hill, a moving 4 kg ball has 15 J of kinetic energy. Towards the
bottom of the hill, the ball has 70 J of kinetic energy and 5 J of potential energy.
How tall is the hill?
The height of the hill is approximately 0.128 meters.
The total energy of the ball at the top of the hill is equal to its kinetic energy:
E_top = K = 15 J
At the bottom of the hill, the total energy of the ball is the sum of its kinetic and potential energies:
E_bottom = K + U = 70 J + 5 J = 75 J
The potential energy of the ball at the top of the hill is zero, since it is at the highest point. Therefore, the potential energy at the bottom of the hill is:
U = E_bottom - K = 75 J - 70 J = 5 J
The potential energy of an object at a height h is given by:
U = mgh
where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s^2), and h is the height. Rearranging this equation gives:
h = U/(mg)
Substituting the values given in the problem, we get:
h = 5 J / (4 kg * 9.8 m/s^2) ≈ 0.128 m
Therefore, the height of the hill is approximately 0.128 meters.
What is kinetic energy?
Kinetic energy is the energy possessed by a moving object due to its motion. It is defined as the energy an object has by virtue of its motion, and is directly proportional to the mass of the object and the square of its velocity (speed).
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Room has a sensible heat gain of 4000 btu per hr is to be maintained at 78F when the outside temp is 93F. The temp of the air entering the room is to be 68F. Determine the number of pounds of fresh air per minute that must be used if 75% of the total air is recirculated.
BTU = Flow Rate In GPM (of water) x (Temperature Leaving Process - Temperature Entering Process) x 500.4*Formula changes with fluids others than straight water.
What is sensible heat?Sensible heat is the type of heat that causes a change in temperature when you heat or cool an object. For instance, when you heat an ice cube, its temperature will start to rise until it reaches 0 °C, at which time it will begin to melt.
Similar to this, when we heat water from room temperature, it gets hotter and hotter until it begins to boil. Sensible heat is the heat that causes a change in temperature. In other words, the sensation you have is heat.
Latent heat, in contrast, is a type of heat that solely affects phase transitions. Use our latent heat calculator to learn more. The equation for sensible heat is:
=Q=mc p (T f −Ti )
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what is fundamental quantity
Answer:
The Fundamental Quantity is a physical quantity that exists independently and cannot be expressed by any other physical quantity.
Explanation:
Examples of these could be : Length, electric current and mass
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write down an example scenario of an object that has acceleration
Answer:
An object which experiences either a change in the magnitude or the direction of the velocity vector can be said to be accelerating. This explains why an object moving in a circle at constant speed can be said to accelerate - the direction of the velocity changes.
if a car turns a corner at constant speed, it is accelerating because its direction is changing. The quicker you turn, the greater the acceleration. So there is an acceleration when velocity changes either in magnitude (an increase or decrease in speed) or in direction, or both.
Explanation:
A pressure cooker contains water and steam in equilibrium at a pressure greater than atmo-spheric pressure. How does this greater pressure increase cooking speed
Answer:
As the pressure inside the pressure cooker increases as it is heated, the temperature also increases.
Explanation:
A pressure cooker contains water and steam in equilibrium at a pressure greater than atmospheric pressure.
According to the ideal gas law, as the pressure increases, the temperature also increases.
As the pressure inside the pressure cooker increases as it is heated, the temperature also increases.
for two vectors A and B, if A×B =6i+2j+5k, A.B=-13, A+B=-2i+j+2k and magnitude of vector A is 3. find the two vectors A anf B
Two vectors are parallel when the angle between them is either 0° (the vectors point in the same direction) or 180° (the vectors point in opposite directions).
What is vectors ?In both mathematics and physics, the term "vector" is used informally to describe certain quantities (also known as "scalars") that cannot be described by a single number or by the constituent parts of some vector spaces.
Historically, vectors were introduced in geometry and physics (usually in mechanics) for things like displacements, forces, and velocity that have both a magnitude and a direction. Similar to how lengths, masses, and time are represented by real numbers, these quantities can be thought of as geometric vectors.
Tuples, which are finite sequences of numbers with a definite length, are also referred to as vectors in some settings.
Tuples and geometric vectors may both be added to and scaled, and the idea of a vector space is a result of these vector operations.
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7. State condition of equilibrium when a borly is acted upon by a number of parallel forces. A uniform metal tube of length 5cm and mass 9 kg is suspended horizontally by two vertical wire attaches at 50cm and 150cm respectively from the ends of the tuber Find the tension in each wire. in tril Solution -
According to the question the tension in each wire is 1.96 N.
What is tension?Tension is a term that describes the psychological and physical state of a person or system in which there is a high degree of stress, uncertainty, and anxiety. It is often associated with conflict and is often experienced when individuals or groups feel threatened or constrained in some way. Tension can be experienced in a variety of different contexts, from interpersonal relationships to the workplace. It can result from a variety of different factors, including a lack of communication, conflicting goals or expectations, and unmet needs.
The body is in equilibrium when the sum of all forces acting on it is equal to zero. In this case, the forces acting on the metal tube are the two wires and the weight of the tube due to gravity.
The tension in each wire is equal to the weight of the tube divided by the length of the tube. This is because the tube is suspended horizontally, so the forces in each wire must be equal in order to keep the tube in equilibrium.
Therefore, the tension in each wire is:
T = (9 kg × 9.8 m/s2) / (5 cm × 0.01 m)
= 1.96 N
Therefore, the tension in each wire is 1.96 N.
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you have water in two buckets of equal height.Your friend asked you which bucket contains the moat water.Now how did you find out .write short answer
To determine which bucket contains more water, I would pour the water from one bucket into the other until they are both at the same level. Then, I would compare the amount of water left in each bucket. The bucket with more water remaining is the one that originally had more water.