Jack travels 80 km in 50 minutes. What is his speed in m/s?
Answers
Answer:
1.6 m/s?
Explanation:
80 ÷ 50 = 1.6 m/s
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Related Questions
When the car comes to a sudden stop, the passenger ________ in motion
Answers
Answer:
If the car comes to a sudden stop, your body tends to keep moving forward.
Explanation:
Obtain information about commonly used gadgets or devices which are based on the principles of newtons laws of motion.
Answers
One such gadget is the airbag, which is designed to protect occupants in vehicles during collisions.
When a vehicle experiences a sudden deceleration, the airbag system uses Newton's first law (inertia) to sense the change in motion and rapidly inflates the airbag to prevent passengers from hitting hard surfaces.
Another example is the rocket, which follows Newton's third law of motion (action and reaction). Rockets work by expelling gases in one direction, causing the rocket to move in the opposite direction. This principle is used in various applications, such as space exploration and fireworks displays.
Additionally, devices like elevators and escalators also rely on Newton's laws of motion. Elevators use Newton's second law (force equals mass times acceleration) to lift or lower passengers. Escalators, on the other hand, utilize Newton's first and second laws to transport people between different levels.
These gadgets and devices demonstrate the practical application of Newton's laws of motion in everyday life, enhancing safety, transportation, and convenience.
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a planet has a mass of 7.70 × 1023 kg and a radius of 2.86 × 106 m. (a) what is the acceleration due to gravity on this planet? (b) how much would a 78.1-kg person weigh on this planet?
Answers
(a) The acceleration due to gravity on the planet is approximately 2.71 m/s².
(b) A 78.1-kg person would weigh approximately 211.51 N on this planet.
(a) To calculate the acceleration due to gravity on the planet, we can use the formula for gravitational acceleration:
g = G * (m / r²),
where g is the acceleration due to gravity, G is the gravitational constant (approximately 6.67 × 10⁻¹¹ N(m/kg)²), m is the mass of the planet, and r is the radius of the planet.
Plugging in the values:
g = (6.67 × 10⁻¹¹ N(m/kg)²) * (7.70 × 10²³ kg) / (2.86 × 10⁶ m)²
g ≈ 2.71 m/s²
Therefore, the acceleration due to gravity on the planet is approximately 2.71 m/s².
(b) To determine how much a 78.1-kg person would weigh on this planet, we can use the formula for weight:
Weight = mass * acceleration due to gravity.
Plugging in the values:
Weight = 78.1 kg * 2.71 m/s²
Weight ≈ 211.51 N
Therefore, a 78.1-kg person would weigh approximately 211.51 N on this planet.
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True or false: if the magnitudes of both the x- and y-component of a vector are doubled, then the magnitude of the vector is also doubled.
Answers
Yes, if the magnitudes of both the x- and y-component of a vector are doubled, then the magnitude of the vector is also doubled. The given statement is true.
In physics, a quantity having both magnitude and direction is called a vector.
A vector is represented by a straight line with an arrow at one end of the line.
Let's say we have a representative vector F.
A representative vector has always its two components Fx and Fy.
A vector can have both magnitude and direction but it has no specific position. It can be drawn in any direction.
There are four vector quantities in physics: force, acceleration, velocity, and displacement.
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It is true that when the magnitude of vectors x and y components are doubled then the magnitude of the vector is also doubled.
For better understanding, lets take an example,
Vector A=5m, 60degrees south of west. So its X-component= 5 x cos60= -4.76
And Y-component= 5 x sin60= -1.52
Now,
doubling the magnitude of vector A will give A=10m , 60degree south of west
Hence X-component= 10 x cos60= -9.52
Now Y-component is 10 x sin60= -3.04
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You push a book across a table. The book moves at a constant speed, but you do not move. Identiffy all the forces on you. Then identify all of the forces on the book
Answers
The forces acting on me are static frictional force and reaction force of the book. The forces acting on the book moving with a constant speed are Applied force and Kinetic frictional force.
Forces acting on me are
Static frictional forceReaction force of the bookThe book at rest, will have a static frictional force. So when I push the book, these forces will act on me. According to Newton's third law of motion, when I apply a certain amount of force on the book, the book will exert the equal amount of force on me.
Forces acting on the book are
Applied forceKinetic frictional forceThe book when moving at constant velocity will have zero net force, because according to Newton's second law of motion, force is directly proportional to acceleration. If the velocity is constant, acceleration will be zero and net force will also be zero. Since the book is moving on a table, a kinetic frictional force will act on the book to resist the movement of the book.
Therefore,
The forces acting on me are Static frictional force and Reaction force of the book.The forces acting on the book are Applied force and Kinetic frictional forceTo know more about Newton's second law of motion
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14.
A student inserts four different objects into a circult to discover which objects will cause a light bulb to light. A table describing the student's results is shown.
Lab Data Table
Material
Object
A
B
C
D
D
Copper
Brass
Glass
Wood
Based on the data in the table, which objects have highly mobile electrons and high conductivity?
AO Objects A and
B. Objects B and D
c.
Objects A and C
Objects C and D
Result
Light
Light
No light
No light
Answers
According to the information in the table, Objects A and B (Copper and Brass) have the highest conductivity and most mobile electrons.
This is clear from the fact that the light bulb turns on when Objects A and B are introduced into the circuit, demonstrating the presence of an electric current.
In addition to having free or extremely mobile electrons inside their atomic structures, copper and brass are both metals renowned for their great electrical conductivity, which enables the effective transmission of electric current.
Thus, when placed into the circuit, cause the lightbulb to turn on.
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A. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.
Answers
The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.
When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.
According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.
According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.
According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.
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A car traveling in a straight line has a velocity of 5.43 m/s at some instant. After 6.2 s, its velocity is 13.8 m/s. What is its average acceleration in this time interval? Answer in units of m/s
Answers
Explanation:
Average acceleration is the change in velocity over change in time.
a = Δv / Δt
a = (13.8 m/s − 5.43 m/s) / 6.2 s
a = 1.35 m/s²
Wil-E-Coyote drops a bowling ball off a cliff to try to catch the Roadrunner. The cliff is 132m high. how far does it fall in the first 3.0 seconds
Answers
Ball A is negatively charged and ball B is electrically neutral. What happens to the charges of both balls when they come into contact with each other if:
(a) they are made of an electrical conductor
describe what will happen
(b) they are made of insulator
describe what will happen
Answers
Answer:
ans for A)
Ball A being negatively charged and Ball B being neutral
when they come into contact.... electrons from the ball A will transfer to ball B and since they are covered by an electrical conductor... their contact will form a joint pathway for electric charge to be transferred to another object.
Answer: i think A
Explanation:
What is isochronism
brainliest for answer
Answers
Answer:
the study of Earth's magnetic field is known as isochronism
Explanation:
isochronism is having a period that is independent of oscillator amplitude in an oscillator. Like, a pendulum or balance.
What's scientific notation
Answers
height 5. An inclined plane is 100 m long and at an angle of 20° to the horizontal. The AMA of the slope is two. Calculate: a) the effort required to push a 7200 N block up the slope b) the ideal mechanical advantage c) the efficiency of the slope.
Answers
(a) The effort required to push the block up the slope is 3600 N.
(b) the ideal mechanical advantage of the slope is 2.92
(c) The efficiency of the slope is 68.5%.
What is the effort required?a) To calculate the effort required to push the block up the slope, we can use the formula:
Effort = Load / AMA
where;
Load is the weight of the block, and AMA is the actual mechanical advantage of the slope.Load = 7200 N
AMA = 2
Effort = 7200 N / 2
Effort = 3600 N
b) The ideal mechanical advantage (IMA) of an inclined plane is given by the formula:
IMA = Length of slope / Height of slope
Length of slope = 100 m
Angle of slope = 20°
We can use trigonometry to find the height of the slope:
Height of slope = Length of slope x sin(angle of slope)
Height of slope = 100 m x sin(20°)
Height of slope = 34.2 m (rounded to one decimal place)
Therefore, the ideal mechanical advantage of the slope is:
IMA = 100 m / 34.2 m
IMA = 2.92 (rounded to two decimal places)
c) The efficiency of the slope is given by the formula:
Efficiency = AMA / IMA x 100%
AMA = 2
IMA = 2.92
Efficiency = 2 / 2.92 x 100%
Efficiency = 68.5% (rounded to one decimal place)
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A battery operating a large flashlight produces a current of 2 amperes in a light bulb that has a resistance of 4 ohms. The voltage of the battery is
a. 0.5 volts.
b. 2 volts.
c. 8 volts.
d. none of the above.
Answers
A battery operating a large flashlight produces a current of 2 amperes in a light bulb that has a resistance of 4 ohms. The voltage of the battery is option c) 8 volts.
To determine the voltage of the battery, we can use Ohm's Law, which states that voltage (V) is equal to the product of current (I) and resistance (R), i.e.,
V = I × R.
In this case, the current is given as 2 amperes and the resistance is given as 4 ohms. Plugging these values into Ohm's Law, we have V = 2 A × 4 \(\Omega\) = 8 volts.
Therefore, the correct answer is c) 8 volts.
The voltage of a battery represents the electric potential difference it provides to the circuit. In this scenario, the battery is operating the flashlight, and the light bulb acts as the resistance in the circuit.
The current flowing through the bulb is determined by the battery's voltage and the resistance. With a current of 2 amperes and a resistance of 4 ohms, the voltage required to sustain this current is 8 volts.
It's important to note that the voltage of the battery is not solely dependent on the current or the resistance. It is the combination of these factors that determines the voltage required to drive the desired current through the circuit.
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What tool is used to cause the frame eyewire to conform to the meniscus curve of the lens bevel?
Answers
The tool that is used to cause the frame eyewire to conform to the meniscus curve of the lens bevel is called a "rimless lens groover."
This groover is specifically designed to create a groove on the eyewire that matches the curvature of the lens bevel. By using this tool, opticians can ensure a precise fit between the lens and the frame, which is essential for rimless or semi-rimless eyewear. The grooving process involves carefully cutting a groove along the eyewire, allowing the lens to be secured in place. This tool helps achieve a seamless and comfortable fit for the wearer, as it allows the lens to sit securely within the frame while maintaining the desired aesthetic. Opticians are trained to use the rimless lens groover effectively and accurately to ensure optimal vision and overall satisfaction for the wearer.
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Particles q1 = -20.5 UC, q2 = -9.30 uC, and q3 = -31.6.0 uC are in a line. Particles q, and q2 are separated by 0.980 m and particles q2 and q3 are separated by 0.750 m. What is the net force on particle q2?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
Answers
The net force on particle q2 can be calculated by finding the net electric force acting on it. The net electric force acting on a particle is the vector sum of the forces exerted by all the other charges on it.
The electric force between two charges q1 and q2 is given by Coulomb's law: F = k * (q1 * q2)/r^2, where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.
The force on particle q2 due to q1 will be:
F1 = k * (q1 * q2) / (0.980m)^2
The force on particle q2 due to q3 will be:
F2 = k * (q2 * q3) / (0.750m)^2
The net force acting on q2 will be the vector sum of F1 and F2.
Keep in mind, q1 and q3 have opposite charges, so they attract each other, while q2 has the same charge as q1, so they repel each other.
Note: The unit of charge is Coulomb (C), but in this problem you are given the charges in microCoulomb (uC) so you need to convert it to Coulomb.
the sun rises and sets; the moon rises and sets. as seen from a location on earth that is arbitrary and in no way special, do all stars also rise and set, or do some stars stay in the sky all the time, or do all stars stay in the same place in the sky and neither rise nor set?
Answers
Some stars rise and set, while others remain in the sky all the time, depending on the observer's location on Earth.
This phenomenon occurs because Earth rotates on its axis, causing the stars to appear to move across the sky.
Stars that rise and set are called "circumpolar stars." These stars are visible above the horizon throughout the entire night, and their positions change due to Earth's rotation. For observers at the Earth's equator, all stars will appear to rise and set because they are equally distributed around the sky.
However, for observers at higher latitudes, some stars will never rise nor set. These stars are called "circumpolar stars." They are visible all year round and seem to circle around the celestial poles (North and South Poles). The closer an observer is to the poles, the larger the number of circumpolar stars.
In summary, whether stars appear to rise and set or remain in the sky depends on the observer's location on Earth. At the equator, all stars will appear to rise and set, while at higher latitudes, some stars will be circumpolar and stay visible in the sky all the time.
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what does weighing less on the moon mean for astronauts on the moon?
Answers
Answer:
Isaac Newton discovered that as an object's mass increases, the gravitational attraction of that object increases. Thus, the gravitational attraction on the Moon is much less than it is here on Earth, and a person weighs less on the Moon.
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Suppose you are sitting in the bleachers at a baseball game 170 m from home plate. How long after the batter hits the ball do you hear the "crack" of the ball and bat?
Answers
Answer:
t = 0.5 s
Explanation:
We know that the distance from the batter to the bleachers is 170 m, and we are trying to find the time it takes for the sound of the ball hitting the bat to travel that distance.
We can use the formula v = d/t, where v is the speed of sound in air (we know that sound in air travels at a speed of 340 m/s), d is the distance the sound travels (170 m in this case), and t is the time it takes for the sound to travel that distance.
Rearranging the formula to solve for t, we get t = d/v. Plugging in the values we know, we get:
t = 170 m / 340 m/s
t = 0.5 s
Therefore, it takes 0.5 seconds for the sound of the ball hitting the bat to travel 170 meters from home plate to the bleachers.
Fighter jets on aircraft carriers are accelerated down a 270 foot "runway" in two seconds when they are taking off. A fully loaded, combat ready F-15 has a maximum take-off weight of 62,000 pounds. To ensure the pilot can reach sufficient velocity within 2 seconds a pneumatic cannon propels the plane down the runway. If this same cannon was used to launch your Toyota Corolla (mass is 2646lbs), how fast in miles per hour would you be going after reaching the end of the runway?
Answers
The speed of the Toyota Corolla would have been 143.9 mph.
What is the acceleration of the F-15?
The acceleration of the F-15 can be calculated as follows:
Acceleration = Velocity Change / Time = (Take-off Speed) / Time
where;
Take-off Speed = √(2dg /t²)
Take-off Speed = √(2 x (270 ft) x 32.2 ft/s² / (2 s)²)
T = √(17496) = 131.6 ft/s
Acceleration = Velocity Change / Time
= (131.6 ft/s) / (2 s) = 65.8 ft/s²
We can use the same acceleration to launch the Toyota Corolla, and calculate its final velocity:
Final Velocity = Initial Velocity + Acceleration x Time
where;
Initial Velocity = 0 (because the car is not moving initially), Time = 2 sFinal Velocity = 0 + (65.8 ft/s²) * (2 s) = 131.6 ft/s
Finally, we can convert the velocity from feet per second to miles per hour:
Velocity (mph) = Velocity (ft/s) x (1 hour/3600 s) x (5280 ft/mile)
= 131.6 ft/s x (1 hour/3600 s) x (5280 ft/mile)
= 143.9 mph
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What is the net force and direction the box will move in ?
Answers
Answer:
5 Newton to right direction
Explanation:
5N to the right will be vanishes with 5N to the left..... then the another 5N to right will be the force that move the box
would this be Newtons 1st, 2nd, or 3rd law
Answers
Answer:
Newton's First Law of Motion.
Explanation:
Newton's First Law of Motion states that a body continues its state of motion untill and unless an external force acts on it. Here, the truck moves forward even after the breaks are applied in order to maintain its State of motion.
How did the apparent motions of planets set those objects apart
from other stars when observed by ancient astronomers?
Answers
Ancient astronomers observed planets exhibiting noticeable movement against the background of fixed stars, distinguishing them as wandering objects in the night sky.
Unlike the fixed stars, which maintained a relatively stable position in the night sky, planets displayed distinct motion over time when observed by ancient astronomers. While stars appeared to maintain their positions relative to each other, planets exhibited a wandering or meandering path against the backdrop of the fixed stars. This irregular motion set planets apart, capturing the attention of ancient astronomers and prompting them to recognize them as distinct celestial entities. The movement of planets was often retrograde, appearing to temporarily reverse their usual eastward motion relative to the stars before resuming their regular path. This unique behavior of planets distinguished them from the fixed stars and piqued the curiosity of early astronomers.
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what do halo stars do differently from disk stars?
Answers
Answer: They orbit the galactic center with many different inclinations, while disk stars all orbit in nearly the same plane. ... They have vertical motions out of the plane, making them appear to bob up and down, but they never get "too far" from the disk.
Explanation:
Con respecto a las magnitudes longitud del péndulo y periodo, ¿por qué la línea de mejor ajuste de los puntos-dato de la distribución indica que sí hay relación entre ambas magnitudes?
Answers
Answer:
Por que existe una relación entre dichas magnitudes.
Para un pendulo perfecto de largo L, sabemos que el periodo esta definido como:
\(T = 2*\pi *\sqrt{L/g}\)
Donde:
pi = 3.14
L = largo del péndulo
g = aceleración gravitatoria = 9.8 m/s^2
Entonces podemos ver que el periodo es proporcional a la raíz cuadrada de la longitud del péndulo.
Esto es por lo que al analizar datos de un experimento se debería observar una relación entre esas magnitudes.
it bins the particles in the nucleus together
Answers
Answer:
Nuclear forces (forces)
Explanation:
An elevator, mass 4750kg, is designed so that the maximum acceleration is 0.50m/s2. What are themaximum and minimum forces the motor exerts on the cable?
Answers
The free body diagram of the elevator can be shown as,
According to free body diagram, the net force acting on the elevator is,
\(F_n=T_{\max }-mg\)According to Newton's law,
\(F_n=ma\)Plug in the known expression,
\(\begin{gathered} ma=T_{\max }-mg \\ T_{\max }=ma+mg \\ =m(a+g) \end{gathered}\)Substitute the known values,
\(\begin{gathered} T_{\max }=(4750kg)(0.50m/s^2+9.8m/s^2) \\ =(4750\text{ kg)(}10.3m/s^2)(\frac{1\text{ N}}{1kgm/s^2}) \\ =48925\text{ N} \end{gathered}\)Thus, the maximum force exerted on the cable is 48925 N.
For minimum, tension the net force can be expressed as,
\(F_n=mg-T_{\min }\)Plug in the known expression,
\(\begin{gathered} ma=mg-T_{\min } \\ T_{\min }=mg-ma \\ =m(g-a) \end{gathered}\)Substitute the known values,
\(\begin{gathered} T_{\min }=(4750kg)(9.8m/s^2-0.5m/s^2) \\ =(4750\text{ kg)(}9.3m/s^2)(\frac{1\text{ N}}{1kgm/s^2}) \\ =44175\text{ N} \end{gathered}\)Thus, the minimum force exerted on the cable is 44175 N.
If I double the amount I stretch a spring, what happens to its EPE
A. Doubles
B. Halves
C. Quadruples
D. Quarters
Answers
40 points!
Fill in the blanks in the following paragraph to correctly describe the behavior of waves.
A wave is a(n) _______________ that carries _______________ through space. Some waves travel through empty space. Other waves must travel through a material, also known as a _______________. Waves transfer energy but not _______________.
d. Match each term to its correct description. (1 point)
A. Refraction
B. Diffraction
C. Reflection
D. Constructive interference
E. Destructive interference
_____ The superimposition of waves to create a wave with a larger amplitude
_____ The superimposition of waves to create a wave with a smaller amplitude
_____ The bending of a wave as it enters a different medium
_____ The bending of a wave around an obstacle
_____ The bouncing of a wave off a surface
Answers
d. Match each term to its correct description.
A. Refraction - The bending of a wave as it enters a different medium
B. Diffraction - The bending of a wave around an obstacle
C. Reflection - The bouncing of a wave off a surface
D. Constructive interference - The superimposition of waves to create a wave with a larger amplitude
E. Destructive interference - The superimposition of waves to create a wave with a smaller amplitude
What is the kinetic energy of a 0.38 kg soccer ball that is traveling at a
speed of 120 m/s?
Answers
Answer:
The answer is 2736 JExplanation:
The kinetic energy (KE) of an object given it's mass and velocity can be found by using the formula
\(KE = \frac{1}{2} m {v}^{2} \)
where
m is the mass of the object
v is the velocity
From the question
m = 0.38 kg
v = 120 m/s
We have
\(KE = \frac{1}{2} \times 0.38 \times {120}^{2} \\ = \frac{1}{2} \times 0.38 \times 14400 \\ = 0.38 \times 7200\)
We have the final answer as
2736 JHope this helps you