it's 11:33 am and i add 30 minutes what time will it be

The base is 16 while the amount is 15 giving a percentage of 93.75%

Percentage is a number or ratio expressed in a fraction of 100. It is represented in percentage sign.

Let x represent the base and y represent the amount.

The base is one greater than the amount. Hence:

The percentage is 93.75%, hence:

y/x = 93.75%

y/x = 0.9375

y = 0.9375x

0.9375x - y = 0  (2)

From equation 1 and 2:

x = 16, y = 15

The base is 16 while the amount is 15.

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There is no solution for the number of dimes and quarters, given that there are 20 nickels, 57 coins in total, and the total value of all the coins is $6.50.

Let the number of dimes and quarters be represented by the variables d and q, respectively.

The total number of coins is given as 57. Thus, we can write:20 + d + q = 57d + q = 37

The value of all the coins is $6.50, and this includes the 20 nickels. Therefore, we can write an equation for the value of the dimes and quarters as:

0.10d + 0.25q = $6.50 - ($0.05 x 20)0.10d + 0.25q = $5.50

Simplifying this equation by multiplying both sides by 10, we get:

d + 2.5q = 55

Dividing both sides by 2.5, we get: d/2.5 + q = 22

If we now substitute the expression we derived for d + q in terms of d (which is d + q = 37), we get:

d/2.5 + 37 = 22d/2.5 = -15

Multiplying both sides by 2.5, we get:

d = -37.5

This is a contradiction since the number of coins cannot be negative.

Therefore, there is no solution for the number of dimes and quarters, given that there are 20 nickels, 57 coins in total, and the total value of all the coins is $6.50.

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the answer is b commutative property

By organizing countless data points into comprehensible ranges or bins, the histogram, which resembles a bar graph in appearance, condenses a data series into an understandable visual. So Histograms based on data on housing, prices and salaries typically are skewed to the right.

A histogram in statistics is a graphic depiction of the data distribution. The histogram is shown as a collection of rectangles that are next to one another, where each bar represents a different type of data.

A branch of mathematics called statistics is used in many different fields. Frequency is the term for how often numbers appear in statistical data; it can be shown as a table and is known as a frequency distribution.

A histogram is a bar graph-like data visualization that groups various class levels into columns along the horizontal x-axis. The numerical count or percentage of occurrences for each column in the data are shown on the vertical y-axis.

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Answer:

396 cm²

Step-by-step explanation:

This may look complex, but it's actually an easy one.

The length of the left hand side is 27 cm, while the length of the right hand side is 9 cm. Subtracting 9 from 27, we have 18 cm

Also, the breadth of the bottom is 24 cm, while the breadth of the top is 10 cm. Subtracting 10 from 24, we have 14 cm.

Now, to find the area, we divide the diagram into 2. Taking the breadth first, we have breadth of 24 cm and it's relatively small height of 9 am.

Area of a rectangle is l * b, = 24 * 9 = 216 cm

Now, we look at the remaining part of the diagram. The length with a height of 18 cm, and a breadth of 10 cm. Area of a rectangle is l * b, = 180 cm

Adding both calculations together, we have 180 + 216 = 396 cm²

Answer:

35

Step-by-step explanation:

if you have 40$ and you want money to have left for the shirt (5$), you subtract 5 from 40 and get 35

Answer:

x=4

Step-by-step explanation:

no because x=4 and you can't have multiple answerd

Consider the initial value problem y' = 3y^2, at the value of y(0) = 1/6 will the solution have a vertical asymptote at t = 2.

The differential equation is y'=3y^2.

We can write this equation as:

dy/dt = 3y^2

dy/y^2 = 3dt

Now integrating on both side

\(\int \frac{dy}{y^2} = \int 3dt\)

After integrating we get,

- 1/y = 3t + c

Multiply by y on both side, we get

(3t + c)y = -1

Divide by (3t + c) on both side, we get

y = -1/(3t + c).................(1)

Since there is vertical asymptote at t = 2

So 3t + c = 0 at t = 2

3(2) + c = 0

6 + c = 0

Subtract 6 on both side, we get

c = -6

Put the value of c in equation 1

y = -1/(3t - 6)

At t = 0

y(0) = -1/(3(0) - 6)

y(0) = 1/6

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The linear functions in this problem are given as follows:

A linear function is modeled by:

y = mx + b

In which:

For function f(x), when x increases from 2 to 3, f(x) decays from 5 to 1, hence the slope is of -4 and:

f(x) = -4x + b.

When x = 2, f(x) = 5, hence the y-intercept is found as follows:

5 = -4(2) + b

b = 13.

Then:

f(x) = -4x + 13.

For function g(x), when x increases from 4 to 7, g(x) increases from 2 to 8, hence the slope is of:

m = (8 - 2)/(7 - 4) = 6/3 = 2.

Hence:

g(x) = 2x + b.

When x = 4, g(x) = 2, hence the y-intercept is found as follows:

2 = 2(4) + b

2 = 8 + b

b = -6.

Then:

g(x) = 2x - 6.

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Answer:

Option B is the best way to write the underlined parts of sentences 2 and 3.

Sentence 2: They have a special finish that helps.

Sentence 3: The finish helps the swimmer glide through the water.

Option B provides a clear and concise way to connect the two sentences and convey the idea that the special finish of the swimsuits helps the swimmer glide through the water. It avoids any ambiguity or redundancy in the language.

At the point (1, 2), y = 16.

To evaluate y at the point (1, 1) for the equation (2x - y)^4 + 2y^3 = 16, we substitute x = 1 and y = 1 into the equation and solve for y.

(2(1) - y)^4 + 2(1)^3 = 16

Simplifying further:

(2 - y)^4 + 2 = 16

Now, we can solve for (2 - y)^4:

(2 - y)^4 = 16 - 2

(2 - y)^4 = 14

Taking the fourth root of both sides:

2 - y = ±√14

Now, isolate y:

y = 2 - √14  or  y = 2 + √14

Therefore, at the point (1, 1), y can have two possible values: y = 2 - √14 or y = 2 + √14.

To evaluate y at the point (1, 2) for the same equation, we substitute x = 1 and y = 2 into the equation:

(2(1) - 2)^4 + 2(2)^3 = 16

Simplifying:

(0)^4 + 2(8) = 16

0 + 16 = 16

Therefore, at the point (1, 2), y = 16.

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hello

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thanks

The area and perimeter of a polygon with vertices (1,-2) , (1,5) , (7,-2)

A=23.27644 units^2

Let

A= (1,-2) ,

B=(1,5) ,

C=(7,-2)

Therefore, the equation for distance is  mathematically given as

d=\sqrt {(x^2-x^1)^2+(y^2-y^1)^2}

Therefore For AB

\(d=\sqrt {(-2-1)^2+(5-1)^2}\)

d=5

For BC

\(d=\sqrt {(5-1)^2+(-2-7)^2}\)

d=9.84

for CA

\(\sqrt {(5-1)^2+(-2-7)^2}\)

9.486

Hence, Perimeter

P=9.486+9.84 +5

P=24.326

In conclusion, the Area of a triangle

A = √s(s−a)(s−b)

Where

s=24.326/2

Therefore

\(A=\sqrt{24.326/2((24.326/2)-5)((24.326/2)-9.486 )((24.326/2)-9.84 )}\)

A=23.27644 units^2

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The best measure of variability for the data, and its value is: D. The range is the best measure of variability, and it equals 9.

In Mathematics and Statistics, a line plot simply refers a type of graph that is used for the graphical representation of data set above a number line, while using crosses, dots, or any other mathematical symbol.

From the data set, we have:

10, 1, 1, 4, 4, 2, 2, 2, 5, 5, 5, 3, 3, 3, 3

For the IQR, we have:

IQR = Third quartile (Q₃) - First quartile (Q₁)

IQR = 5 - 2

IQR = 3

For the range, we have;

Range = maximum - minimum

Range = 10 - 1

Range = 9.

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Answer:

y = -1/2x + 1

Step-by-step explanation:

The y-intercept can be determined since the line touches the y-axis at the point (0,1), making it 1. The slope can be determined since the line is going down negatively, down one half and right one, making it -1/2

There are 5 full square and 6 triangles that are half squares.

      5 + (6)(1/2) = 5 + 3 = 8

You could also break this into smaller shapes (like a big triangle on the top and a smaller triangle and rectangle on the bottom and use area formulas to calculate the area.  But counting works well in this example.

Answer: 8

Step-by-step explanation:

First you split up this shape into two different shapes, a triangle and trapezoid

Put a line through the coordinates (-2,2) to  (-1,2); the top is a triangle and the other is a trapezoid

Area of the trapezoid is A = .5x (base1 + base2) x height

base1 of the trapezoid goes from -4 to -1 which is 3

base2 goes from -2 to -1 which is 1

height is 0 to 2 whcich is 2

A = .5 x (3+1) x 2 = 4

Now area of a triangle is A = .5 x base x height

the base goes from -2 to 2 which is 4

the height goes from 2 to 4 which is 2

A = .5 x (4) x (2) = 4

Area of the Trapezoid + Area of the Triangle = Total Area

4 + 4 = 8

The number of weeks for taking 30 Quizzes will be 10.

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that Ernest took a total of 12 quizzes over the course of 4 weeks. The number of weeks required to take 30quizzes will be calculated as;-

12 quiz = 4 weeks

1 quiz = 4 / 12 weeks

30 quiz = ( 4 x 30 ) / 12 week

30 quiz = 10 week

Therefore, there will be 10 weeks total for taking the 30 quizzes.

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Answer:

So the portion of the loan lent at 4% is 21000(0.5955) = $12,505.5

And the portion of the loan lent at 15% is 21000(0.4045) = $8494.5

Step-by-step explanation:

This problem can be solved in several ways. The way I like is as follows.

Ask yourself at what interest would $ 21,000 yield and interest of $ 2,215 in one year ? The equation to solve is:

21000(P) = 2215

P = 0.1055 or 10.55 %

This number is a weighed average of the 4% yield and the 15% yield so the next equation to solve is

10.55 = 4(1 – X) + 15X

Where X is the proportion of the loan given at the indicated interest. So

10.55 = 4 – 4X + 15X

6.55 = 11X

X = 0.5955

1-X = 0.4045

So the portion of the loan lent at 4% is 21000(0.5955) = $12,505.5

And the portion of the loan lent at 15% is 21000(0.4045) = $8494.5

To obtain the rectangle with the maximum value efficiently, you can use the Kadane's algorithm for the maximum subarray sum with slight modifications.

Here's the algorithm:

1. Initialize variables `max_sum` and `result` to negative infinity.

2. Iterate over all possible pairs of columns `(c1, c2)`:

a. Initialize an array `row_sum` of size n with all elements set to 0.

b. Iterate over all rows i from 1 to n:

c. Apply Kadane's algorithm on the `row_sum` array to obtain the maximum sum subarray. Let `cur_sum` be the current sum and `start` and `end` be the indices of the subarray.

d. If `cur_sum` is greater than `max_sum`:

3. Return `result` as the rectangle with the maximum value.

The algorithm runs in O(n^3) time complexity, which is significantly faster than the naive O(n^4) approach.

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The future value of an annuity of $500 per year for 12 years, with an interest rate of 5%, can be calculated using the future value of an ordinary annuity formula. The future value is approximately $7,005.53.

To calculate the future value of an annuity, we can use the formula:

FV = P * [(1 + r)^n - 1] / r

Where:

FV is the future value of the annuity,

P is the annual payment,

r is the interest rate per compounding period,

n is the number of compounding periods.

In this case, the annual payment is $500, the interest rate is 5% (or 0.05), and the number of years is 12. As the interest is compounded annually, the number of compounding periods is the same as the number of years.

Plugging the values into the formula:

FV = $500 * [(1 + 0.05)^12 - 1] / 0.05

= $500 * [1.05^12 - 1] / 0.05

≈ $500 * (1.795856 - 1) / 0.05

≈ $500 * 0.795856 / 0.05

≈ $399.928 / 0.05

≈ $7,998.56 / 100

≈ $7,005.53

Therefore, the future value of the annuity of $500 per year for 12 years, with a 5% interest rate, is approximately $7,005.53.

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Statement A: The cabinets have the same base area.

To determine if the cabinets have the same base area, we need to compare the dimensions of their bases.

For the oblique rectangular prism, the base dimensions are not provided, so we cannot conclude if the base area is the same as the right rectangular prism.

Statement B: The cabinets may have the same base dimensions.

Based on the given information, we can determine the base dimensions for the right rectangular prism since its height is given as 48 inches. However, the base dimensions for the oblique rectangular prism are not provided.

Therefore, we cannot conclude if the cabinets have the same base area (Statement A) or if they may have the same base dimensions (Statement B) based on the information given.

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The system of equations has infinite solutions, both equations represent the same line.

Here we have the following system of equations:

-3x+6y=12

2y=x+4

And we want to solve this by substitution, first, we can rewrite the first equation as:

-3x + 3*(2y) = 12

Now we can substitute the second equation 2y = x + 4 in the parenthesis, we will get:

-3x + 3*(x + 4) = 12

Now we can solve this for x.

-3x + 3x + 12 = 12

12 = 12

So this is true for any value of x, which means that both equations represent the same line (thus the system has infinite solutions).

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To calculate the cash balance at the end of the period, we need to consider the cash inflows and outflows.

Starting cash balance: $4,520

Cash inflows: $1,654 (receivables collected)

Cash outflows: $1,961 (payments to suppliers) + $500 (cash expenses)

Total cash inflows: $1,654

Total cash outflows: $1,961 + $500 = $2,461

To calculate the cash balance at the end of the period, we subtract the total cash outflows from the starting cash balance and add the total cash inflows:

Cash balance at the end of the period = Starting cash balance + Total cash inflows - Total cash outflows

Cash balance at the end of the period = $4,520 + $1,654 - $2,461

Cash balance at the end of the period = $4,520 - $807

Cash balance at the end of the period = $3,713

Therefore, the cash balance at the end of the period is $3,713.

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To find the first derivative of f(x), we need to integrate the second derivative with respect to x once.

f'(x) = ∫ f''(x) dx = ∫ x(x-a)(x-b)^2 dx

f'(x) = ∫ (x^4 - (a+b)x^3 + (a^2+3ab+b^2)x^2 - ab(a+b)x + ab^2) dx

f'(x) = 1/5 x^5 - 1/4(a+b)x^4 + 1/3(a^2+3ab+b^2)x^3 - 1/2ab(a+b)x^2 + 1/3ab^2x + C

where C is the constant of integration.

To find the second derivative of f(x), we need to differentiate f'(x) with respect to x.

f''(x) = d/dx [1/5 x^5 - 1/4(a+b)x^4 + 1/3(a^2+3ab+b^2)x^3 - 1/2ab(a+b)x^2 + 1/3ab^2x + C]

f''(x) = 1 x^4 - 1(a+b)x^3 + 1(a^2+3ab+b^2)x^2 - 1ab(a+b)x + 1ab^2

f''(x) = x^4 - (a+b)x^3 + (a^2+3ab+b^2)x^2 - ab(a+b)x + ab^2

Therefore, the second derivative of f is given by f''(x) = x^4 - (a+b)x^3 + (a^2+3ab+b^2)x^2 - ab(a+b)x + ab^2.

Answer:

the first one

hope this helps

To solve for x, transpose one to the other side and make it positive. Then simplify of possible.

Divide both sides of the equation by -68 and simplify.

Answer:

Wxndy~~

Statistical significance refers to the likelihood that the association between two variables is not due to chance alone. In other words, it is a measure of the probability that the observed relationship between two variables is real and not just a result of random variation or sampling error.

When analyzing data, researchers often use statistical tests to determine whether there is a significant association between two variables. A p-value is calculated, which represents the probability that the observed relationship between the variables is due to chance. If the p-value is less than a predetermined threshold (usually 0.05), the results are considered statistically significant, and the researchers can conclude that there is a real association between the variables. It's important to note that statistical significance does not necessarily imply practical significance. Just because a relationship is statistically significant does not mean that it is important or meaningful in real-world terms. Additionally, statistical significance only tells us about the strength of the relationship between two variables, not about causation or directionality. Therefore, it is always important to interpret statistical significance in the broader context of the research question and study design.

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Answer:

18

Step-by-step explanation:

The diagonal EG is a line of symmetry for rhombus EFGH

A rhombus is a quadrilateral with equal sides. Because opposite sides of a parallelogram are equal, a rhombus is a type of parallelogram in which all sides are equal.

Given rhombus EFGH

We have to prove that diagonal EG is a line of symmetry for rhombus EFGH

According to the property of the rhombus

Four sides of EFGH are equal

So EF = EH

FG =HG

Meanwhile EG =EG(common side)

So triangle EFG = triangle EHG

The diagonal EG is a line of symmetry for rhombus EFGH

Therefore the diagonal EG is a line of symmetry for rhombus EFGH

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Answer: x = 8

Step-by-step explanation:

Answer:

x=8

Step-by-step explanation:

10= -1/4x+12

move the 12 to the other side

10-12= -1/4x

-2= -1/4x

divide -1/4 by both sides

8=x