It takes Taylor hour to make of a batch of cookies. About how long will it take him to make 8 batches?
B.
3.6 hours
C.
5.4 hours
D.
7.2 hours

Answer: Ann would make $105 for 5 hours of work at the same rate.

Step-by-step explanation:

To find out how much Ann would make for 5 hours of work, we first need to determine her hourly wage. Divide her earnings by the number of hours she worked:

147 ÷ 7 = 21

Ann earns $21 per hour. Now, multiply her hourly wage by 5 hours to find out how much she would make for 5 hours of work:

21 × 5 = 105

Ann would make $105 for 5 hours of work at the same rate.

The solution to the equation \((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2\) is 10.3891

From the question, we have the following parameters that can be used in our computation:

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2\)

Using the following trigonometry ratio

sin²(x) + cos²(x) = 1

We have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = (\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + 1 + e^2\)

The sum to infinity of a geometric series is

S = a/(1 - r)

So, we have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = \frac{1/2}{1 - 1/2} + \frac{9/10}{1 - 1/10} + 1 + e^2\)

So, we have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 1 + 1 + 1 + e^2\)

Evaluate the sum

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 3 + e^2\)

This gives

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 10.3891\)

Hence, the solution to the equation is 10.3891

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Answer:

50x - 99 x =79 + 31 is your answer

Step-by-step explanation:

The change in profit (ΔP) when the number of units (Δx) increases by 5, based on the given marginal profit function, is -18331.50

To find the change in profit (ΔP) when the number of units (Δx) increases by 5.

we need to evaluate the marginal profit function and multiply it by Δx.

The marginal profit function is given by dP/dx = 12.1(60 - 3x).

We are given the value of x as 121, so we can substitute it into the marginal profit function to find the marginal profit at that point.

dP/dx = 12.1(60 - 3(121))

= 12.1(60 - 363)

= 12.1(-303)

= -3666.3

Now, we can calculate the change in profit (ΔP) by multiplying the marginal profit by Δx, which is 5 in this case.

ΔP = dP/dx×Δx

= -3666.3 × 5

= -18331.5

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Answer: I believe the correct answer is the last one but I’m not entirely sure, wait for someone else to answer.

Step-by-step explanation:

Answer:

third one

Step-by-step explanation:

point-slope form is y - y1 = m(x - x1)

plug in values  y -(-5) = 2/3(x - 4)

the double negative cancels out and becomes a positive

therefore y + 5 = 2/3(x - 4)

8x + 7 = -25

=>  8x = -25 - 7 = -32

=> x = -32/8 = -4

Answer:

-4=x

Step-by-step explanation:

8x+7(-7)=-25(-7)

8x(/8)=-32(/8)

-4=x

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

x = 2.4545... → (1)

100x = 245.4545... → (2)

Subtract (1) from (2) eliminating the repeating decimal

99x = 243 ( divide both sides by 99 )

x = \(\frac{243}{99}\)

Answer:

A- the graph of f(x) is shifted 7 units down

Step-by-step explanation:

Answer:y=1/3x+8

Step-by-step explanation:

Plug it into point slope form

y-6=1/3(x+6)

y-6=1/3x+2

+6. +6

y=1/3x+8

The required percent error of the measurement is 0.8%.

Error bar, are the line through a point on a graph, axes, which emphasizes the uncertainty or variation of the corresponding coordinate of the point.

The percent error of Adrian's measurement can be calculated as follows:

(|Measured value - Actual value| / Actual value) * 100

= (|12.8 - 12.7| / 12.7) * 100

= (0.1 / 12.7) * 100

= 0.786%

Rounded to the nearest tenth of a percent, the error is 0.8%.

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Answer:6.6%

Step-by-step explanation:

\(\large\text{Hey there!}\)

\(\large\text{Guide:}\)

\(\large\textsf{Difference = Subtraction/Subtract}\)

\(\large\textsf{Number is unknown until we find it}\)

\(\large\textsf{Product = Multiplication/Multiply}\)

\(\large\textsf{Quotient = Division/Divide}\)

\(\large\textsf{Sum = Addition/Add}\)

\(\large\textsf{Now, that we have that information out the way, we can answer the}\\\large\textsf{question.}\)

\(\large\text{Question reads:}\)

\(\large\textsf{The PRODUCT of a NUMBER z & 12 is 60}\)

\(\large\text{Equation:}\)
\(\mathsf{12 \times z = 60}\)

\(\large\text{Simplify it:}\)

\(\mathsf{12 \times z = 60}\)

\(\mathsf{12z = 60}\)

\(\large\text{DIVIDE 12 to BOTH SIDES:}\)

\(\mathsf{\dfrac{12z}{12} = \dfrac{60}{12}}\)

\(\large\text{CANCEL out:}\) \(\rm{\ \dfrac{12}{12}}\)  \(\large\text{because it gives you 1.}\)

\(\large\text{Keep:}\)  \(\rm{\dfrac{60}{12}\)  \(\large\text{because it gives you the answer of the unknown number.}\)

\(\large\text{New equation:}\)

\(\mathsf{ x = \dfrac{60}{12}}\)

\(\large\textsf{Simplify it:}\)

\(\mathsf{x = 5}\)

\(\large\text{Therefore, your answer should be:}\)

\(\large\boxed{\mathsf{x = \frak{5}}}\large\checkmark\)

\(\large\text{Good luck on your assignment \& enjoy your day!}\)

~\(\frak{Amphitrite1040:)}\)

Answer: 38

Step-by-step explanation:

Subtract 1/8 from 1/2

12 - 18 is 38.

Steps for subtracting fractions

Find the least common denominator or LCM of the two denominators:

LCM of 2 and 8 is 8

Next, find the equivalent fraction of both fractional numbers with denominator 8

For the 1st fraction, since 2 × 4 = 8,

12 = 1 × 42 × 4 = 48

Likewise, for the 2nd fraction, since 8 × 1 = 8,

18 = 1 × 18 × 1 = 18

Subtract the two like fractions:

48 - 18 = 4 - 18 = 38

Answer: 0

Step-by-step explanation:

-4b - 2b = -2b

7a - 5a = -2a

-2b + 2a = 0

Answer:

can you help me in something please? 27362 Is the answer

The example of systematic sampling is option c) in a population of 1000 at a school, every 64th person is chosen.

In systematic sampling, the population is first divided into a sampling frame (for example, a list or a map) and then every kth individual is selected from the list. In this example, every 64th person is chosen from the list of 1000 individuals, which is an example of systematic sampling. In the example given, there is a list of 1000 individuals, and every 64th person is chosen from the list. This means that the sampling interval k is 64, and the first individual is selected randomly from the first 64 individuals in the list. From then on, every 64th individual is selected to be included in the sample. For instance, if the first individual selected is number 8, then the individuals selected for the sample would be 8+64=72, 8+264=136, 8+364=200, and so on.

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The circumference of the outer circle is greater than the circumference of the inner circle by 44/7 feet.

What exactly is a circle?

A circle is a basic closed form made up of all points on a plane that are at a fixed distance from the centre. The radius is the distance between the centre and any point on the circle. A circle is often represented by the mathematical symbol "∘" or the equation (x-a)² + (y-b)² = r², where (a,b) is the center and r is the radius.

Now,

To find the circumference of the outer circle, we need to add the distance between the two circles to the circumference of the inner circle and then calculate the circumference of the resulting larger circle.

Circumference of the inner circle = πd = π*44 = 44π feet

Distance between the circles = 2 ft

Diameter of the larger circle = diameter of inner circle + distance between the circles = 44 ft + 2 ft = 46 ft

Circumference of the larger circle = πd = π(46) = 46π ft

Therefore, the circumference of the outer circle is greater than the circumference of the inner circle

by 46π - 44π

= 2*π feet=

=2*22/7=

=44/7 feet.

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Answer:

i cant see anything

Step-by-step explanation:

Answer:

The general form of a circle is :

x² + y² + 2gx + 2fy + c = 0

Step-by-step explanation:

You can always compare any equation of a circle given to you in that form to get it centre and it radius if needed.

For example: the equation you gave... x² + y² + 8x +22y +37 = 0. It centre is (h,k) (-4,-11).

We have proved that Angle BCD is equal to angle BAD plus angle ABC plus angle ADC, as required.

To prove that angle BCD is equal to angle BAD plus angle ABC plus angle ADC, we can use the following steps:

Step 1: Join points A and C with a line segment. Let's label the point where AC intersects with line segment BD as point E.

Step 2: Since line segment AC is drawn, we can consider triangle ABC and triangle ADC separately.

Step 3: In triangle ABC, we have angle B + angle ABC + angle BCA = 180 degrees (due to the sum of angles in a triangle).

Step 4: In triangle ADC, we have angle D + angle ADC + angle CDA = 180 degrees.

Step 5: From steps 3 and 4, we can deduce that angle B + angle ABC + angle BCA + angle D + angle ADC + angle CDA = 360 degrees (by adding the equations from steps 3 and 4).

Step 6: Consider quadrilateral ABED. The sum of angles in a quadrilateral is 360 degrees.

Step 7: In quadrilateral ABED, we have angle BAD + angle ABC + angle BCD + angle CDA = 360 degrees.

Step 8: Comparing steps 5 and 7, we can conclude that angle B + angle BCD + angle D = angle BAD + angle ABC + angle ADC.

Step 9: Rearranging step 8, we get angle BCD = angle BAD + angle ABC + angle ADC.

Therefore, we have proved that angle BCD is equal to angle BAD plus angle ABC plus angle ADC, as required.

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Given: Quadrilateral \(\displaystyle\sf ABCD\)

To prove: \(\displaystyle\sf \angle BCD = \angle BAD + \angle ABC + \angle ADC\)

Proof:

1. Draw segment \(\displaystyle\sf AC\) and extend it to point \(\displaystyle\sf E\).

2. Consider triangle \(\displaystyle\sf ACD\) and triangle \(\displaystyle\sf BCE\).

3. In triangle \(\displaystyle\sf ACD\):

4. In triangle \(\displaystyle\sf BCE\):

5. Since \(\displaystyle\sf \angle BCE\) and \(\displaystyle\sf \angle BCD\) are corresponding angles formed by transversal \(\displaystyle\sf BE\):

6. Combining the equations from steps 3 and 4:

Therefore, we have proven that in quadrilateral \(\displaystyle\sf ABCD\), \(\displaystyle\sf \angle BCD = \angle BAD + \angle ABC + \angle ADC\).

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Let's calculate the products and check if they indeed have the same value:

Product of 32 and 46:

32 * 46 = 1,472

Reverse the digits of 23 and 64:

23 * 64 = 1,472

As you mentioned, the products are the same. This phenomenon is not unique to this particular pair of numbers. In fact, it occurs with any pair of two-digit numbers whose digits, when reversed, are the same as the product of the original numbers.

To find two other pairs of two-digit numbers that have this property, we can explore a few examples:

Product of 13 and 62:

13 * 62 = 806

Reversed digits: 31 * 26 = 806

Product of 17 and 83:

17 * 83 = 1,411

Reversed digits: 71 * 38 = 1,411

As for determining if a given pair of two-digit numbers will have this property without actually performing the multiplication, there is a simple rule. For any pair of two-digit numbers (AB and CD), if the sum of A and D equals the sum of B and C, then the products of the original and reversed digits will be the same.

For example, let's consider the pair 25 and 79:

A = 2, B = 5, C = 7, D = 9

The sum of A and D is 2 + 9 = 11, and the sum of B and C is 5 + 7 = 12. Since the sums are not equal (11 ≠ 12), we can determine that the products of the original and reversed digits will not be the same for this pair.

Therefore, by checking the sums of the digits in the two-digit numbers, we can determine whether they will have the property of the products being the same when digits are reversed.

The value of the given function `limit as x approaches infinity is the square root of (x^2+1)` is √(x^2 + 1).

We have to find the value of the limit as x approaches infinity for the given function f(x) = sqrt(x^2 + 1).

Let's use the method of substitution.

Replace x with a very large value of positive integer 'n'.

Now, let's solve for f(n) and f(n+1) to check the behavior of the function.f(n) = sqrt(n^2 + 1)f(n+1) = sqrt((n+1)^2 + 1)f(n+1) - f(n) = sqrt((n+1)^2 + 1) - sqrt(n^2 + 1)

Let's multiply the numerator and denominator by the conjugate and simplify:

f(n+1) - f(n) = ((n+1)^2 + 1) - (n^2 + 1))/ [sqrt((n+1)^2 + 1) + sqrt(n^2 + 1)]f(n+1) - f(n) = (n^2 + 2n + 2 - n^2 - 1)/ [sqrt((n+1)^2 + 1) + sqrt(n^2 + 1)]f(n+1) - f(n) = (2n+1)/ [sqrt((n+1)^2 + 1) + sqrt(n^2 + 1)]

Thus, we can see that as n increases, f(n+1) - f(n) approaches to 0. Therefore, the limit of f(x) as x approaches infinity is √(x^2 + 1).

Therefore, the value of the given function `limit as x approaches infinity is the square root of (x^2+1)` is √(x^2 + 1).

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Answer:

Step-by-step explanation:

To show that the function f(x) = x³ for x < 0 and f(x) = x²sin(x) for x > 0 is differentiable, we need to demonstrate that the function has a derivative at every point in its domain.

Let's consider the function f(x) separately for x < 0 and x > 0.

For x < 0

In this case, f(x) = x³. The power rule tells us that the derivative of xⁿ with respect to x is nxⁿ⁻¹. Applying this rule, we find that the derivative of f(x) = x³ is f'(x) = 3x².

For x > 0

In this case, f(x) = x²sin(x). The product rule is used when we have a function that is the product of two other functions. The derivative of f(x) can be calculated as follows

f'(x) = (x²)' sin(x) + x² (sin(x))'

To find the derivative of x² sin(x), we use the product rule again

(f(x)g(x))' = f'(x)g(x) + f(x)g'(x)

Let f(x) = x² and g(x) = sin(x). We have

f'(x) = 2x

g'(x) = cos(x)

Substituting these values back into the product rule equation

f'(x) = (x²)' sin(x) + x² (sin(x))'

= (2x) sin(x) + x^2 cos(x)

Therefore, the derivative of f(x) = x²sin(x) is f'(x) = (2x) sin(x) + x²cos(x).

Now, we have found the derivatives of f(x) for both x < 0 and x > 0. To show that f(x) is differentiable, we need to verify that the derivatives from both cases match at x = 0.

As x approaches 0 from the left side (x < 0), we have

lim(x → 0⁻) f'(x) = lim(x → 0⁻) 3x² = 0

As x approaches 0 from the right side (x > 0), we have

lim(x → 0⁺) f'(x) = lim(x → 0⁺) (2x) sin(x) + x²cos(x) = 0

Since the limits of the derivatives from both cases are equal at x = 0, we can conclude that f(x) = x³ for x < 0 and f(x) = x²sin(x) for x > 0 is differentiable at every point in its domain.

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Answer:

6^2

Step-by-step explanation:

it is a division between two power with the same base, so we have to subtract the exponents

6^(6-4) = 6^2

Answer:

36

Step-by-step explanation:

6^6/ 6^4

46656/1296

36

The left side of the equation is equal to the right side, which confirms that a = 11/10 is the correct solution.

To solve the equation, we need to isolate the variable "a". The equation is given as a - 1/2 = 3/5.
To eliminate the fraction, we can multiply both sides of the equation by the least common denominator (LCD), which is 10. This will clear the fractions and make the equation easier to solve.
Multiplying the left side of the equation by 10, we get:
10(a - 1/2) = 10(3/5)
10a - 5 = 6
Next, we can simplify the equation by adding 5 to both sides:
10a - 5 + 5 = 6 + 5
10a = 11
Finally, we can solve for "a" by dividing both sides of the equation by 10:
(10a)/10 = 11/10
a = 11/10
Therefore, the solution to the equation is a = 11/10 or a = 1 1/10.
To check the solution, substitute a = 11/10 back into the original equation:
11/10 - 1/2 = 3/5
(11/10) - (5/10) = 3/5
6/10 = 3/5
In summary, the solution to the equation a - 1/2 = 3/5 is a = 11/10 or a = 1 1/10. This solution has been checked and is correct.

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The given statement "The this pointer is not automatically passed to static member functions of a class." is false as static member functions can be called without creating an object of the class, and the "this" pointer is used to refer to the current instance of the class. Since no instance is required for static member functions, the "this" pointer is not applicable in this case.

In object-oriented programming, a class is a blueprint for creating objects, and member functions are functions defined within a class that can be called on objects of that class.

Static member functions, also known as class methods, are special member functions that are associated with the class itself rather than any specific object or instance of the class. They are declared using the "static" keyword.

Since static member functions do not operate on specific instances of the class, they do not have access to the "this" pointer. The "this" pointer is a hidden pointer that points to the current object instance, allowing non-static member functions to access the data members and other member functions of the object. However, static member functions do not have this pointer because they are not tied to any specific object.

Static member functions can only access static members of the class, which include static variables and other static member functions. They can be called using the class name itself, without creating an instance of the class. This is because they are not associated with any particular object but rather with the class as a whole.

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The company's profits for each month from March through May were $658.33.

How to find the company profits for the months of March through May?

To solve the problem, we need to use the information given and set up an equation. Let's call the profits for the months of March through May "P" (since they are the same for each month).

The company's total profits for the year can be calculated by adding up the profits for each month:

January profit + February profit + March profit + April profit + May profit = total profit

Plugging in the numbers we know:

-$4,758 + $3,642 + 3P + 3P + 3P = -$1,275

Simplifying the equation:

9P = $5,925

Dividing both sides by 9:

P = $658.33

So the company's profits for each month from March through May were $658.33.

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Answer:

$55.25

Step-by-step explanation:

35% × 85 = 29.75

85 - 29.75

= 55.25

Answer:

B greater than or equal to -12

Answer:

b\(\geq\)-12

Step-by-step explanation:

Step 1- Subtract 10 from both sides of the inequality.

New inequality:

4b\(\geq\)-48

Step 2- Divide by 4 into both sides of the inequality, to get your answer.

Answer:

b\(\geq\)-12

Answer:

\(y = \frac{1}{2}x +4\)

Step-by-step explanation:

Given:

\(R = (0,0)\)

\(S= (8,4)\)

\(T = (-2,3)\)

First, we have that the line is parallel to RS.

This means that the line has the same slope as RS and the slope of RS is calculated as follows:

\(m = \frac{y_2 - y_1}{x_2 - x_1}\)

\(m = \frac{4-0}{8-0}\)

\(m = \frac{4}{8}\)

\(m = \frac{1}{2}\)

So, the line has a slope of \(m = \frac{1}{2}\)

Next, we have that the line passes through \(T = (-2,3)\).

The equation of the line is then calculated using the following formula

\(y - y_1 = m(x - x_1)\)

\(y - 3 = \frac{1}{2}(x - (-2))\)

\(y - 3 = \frac{1}{2}(x +2)\)

Open bracket

\(y - 3 = \frac{1}{2}x +1\)

Make y the subject

\(y = \frac{1}{2}x +1+3\)

\(y = \frac{1}{2}x +4\)