Answers
Given:
Time taken, t = 3 hr and 10 min
Distance covered = 14.32 km
Let's find the speed of the train.
To find the speed of the train, apply the formula:
\(\text{speed}=\frac{\text{distance}}{\text{time}}\)Convert the time to hour.
Where:
1 hour = 60 minutes
Thus, we have:
\(\text{Time = 3}\frac{10}{60}=3\frac{1}{6}=3.17\text{ hours}\)To find the speed, we have:
\(\text{speed}=\frac{14.32\operatorname{km}}{3.17}=4.52\operatorname{km}\text{ /h}\)Therefore, the speed of the train is 4.52 kilometers per hour.
ANSWER:
4.52 km/h
Related Questions
1.00 kg of ice at -24.0°C is placed
in contact with a 1.00 kg block of a
metal at 5.00°C. They come to
equilibrium at -8.88°C. What is
the specific heat of the metal?
Answers
1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C.
We can use the principle of conservation of heat to solve this problem. The heat lost by the metal must equal the heat gained by the ice.
The heat lost by the metal is given by
Q1 = m1c1ΔT1
Where m1 is the mass of the metal, c1 is its specific heat, and ΔT1 is the change in temperature.
The heat gained by the ice is given by
Q2 = m2c2ΔT2
Where m2 is the mass of the ice, c2 is its specific heat, and ΔT2 is the change in temperature.
Since the two objects come to thermal equilibrium, we can set Q1 equal to Q2
m1c1ΔT1 = m2c2ΔT2
Solving for c1, we get
c1 = m2c2ΔT2 / (m1ΔT1)
By putting these values we get
c1 = (1.00 kg)(2.06 kJ/kg·K)(-24.0°C - (-8.88°C)) / [(1.00 kg)(5.00°C - (-8.88°C))]
c1 = 0.902 kJ/kg·K
Hence, the specific heat of the metal is 0.902 kJ/kg·K.
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A 52 kg and a 95 kg skydiver jump from an airplane at an altitude of 4750 m, both falling in the pike position. Assume all values are accurate to three significant digits. (Assume that the density of air is 1.21 kg/m3 and the drag coefficient of a skydiver in a pike position is 0.7.) If each skydiver has a frontal area of 0.14 m2, calculate their terminal velocities (in m/s). 52 kg skydiver m/s 95 kg skydiver m/s How long will it take (in s) for each skydiver to reach the ground (assuming the time to reach terminal velocity is small)
Answers
Answer: 52 kg skydiver: 9.09 m/s and 522.55 s
95 kg skydiver: 12.3 m/s and 386.2 s
Explanation: Drag Force is an opposite force when an object is moving in a fluid.
For skydivers, when falling through the air, the forces acting on it are gravitational and drag forces. At a certain point, drag force equals gravitational force, which is constant on any part of the planet, producing a net force that is zero. Since there is no net force, there is no acceleration and, consequently, velocity is constant. When that happens, the person reached the Terminal Velocity.
Drag Force and Velocity are proportional to the squared speed. So, terminal velocity is given by:
\(F_{G}=F_{D}\)
\(mg=\frac{1}{2}C \rho Av_{T}^{2}\)
\(v_{T}=\sqrt{\frac{2mg}{\rho CA} }\)
where
m is mass in kg
g is acceleration due to gravitational force in m/s²
ρ is density of the fluid in kg/m³
C is drag coefficient
A is area of the object in the fluid in m²
Calculating:
The 52kg skydiver has terminal velocity of:
\(v_{T}=\sqrt{\frac{2(52)(9.8)}{(1.21)(0.7)(0.14)} }\)
\(v_{T}=\) 9.09
The 95kg skydiver's terminal velocity is
\(v_{T}=\sqrt{\frac{2(95)(9.8)}{(1.21)(0.7)(0.14)} }\)
\(v_{T}=\) 12.3
The 52 kg and 95kg skydivers' terminal velocity are 9.09m/s and 12.3m/s, respectively.
The time each one will reach the floor will be:
52 kg at 9.09 m/s:
\(t=\frac{4750}{9.09}\)
t = 522.5
95 kg at 12.3 m/s:
\(t=\frac{4750}{12.3}\)
t = 386.2
The 52 kg and 95kg skydivers' time to reach the floor are 522.5 s and 386.2 s, respectively.
In a DC generator, the generated emf is directly proportional to the
Answers
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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What initiative regarding Native Americans did the government begin in 1954, but stop by 1962?
A. Expanding the role of the federal government in daily governance of reservations
B. Providing additional federal funds for Native American education
C. Allowing Native American reservations to use federal funds as they found fit
D. Abolishing reservations and relocating Native Americans
Answers
The government started allowing reservations for Native Americans to use federal monies in 1954, but stopped by 1962.
What makes them reservations, exactly?The earliest phase of Indian encounters with Europeans is when the word "exclusive" originally appeared. A sizable portion of the Indians' country was "reserved" for their exclusive use through treaties. Indians were intended to live on reserves, which are frequently sparsely populated areas of land.
What use did reservations serve?Displacement to reservations had two purposes for the United States. Native Americans were originally removed from the area to create room for westward territories. Second, it made it possible for the US to carry out a strategy to transform tribal villages into modest farming settlements.
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A train 350 m long is moving on a straight track with a speed of 84.1 km/h. The engineer applies the brakes at a crossing, and later the last car passes the crossing with a speed of 15.8 km/h. Assuming constant acceleration, determine how long the train blocked the crossing. Disregard the width of the crossing.
Answers
Answer:
t = 25.0 s
Explanation:
Assuming that the engineer applies the brakes just over the crossing, the train moves exactly 350 m at a constant acceleration, with a final speed (when the last car of the train leaves the crossing) of 15.8km/h.Since we know the initial and final speeds, and the horizontal distance traveled (the length of the train) we can use the following kinematic equation to get the acceleration:\(v_{f}^{2} - v_{o}^{2} = 2*a* \Delta x (1)\)
Since we need to find the time in seconds, it is advisable to convert vf and vo to m/s first, as follows:\(v_{o} = 84.1 km/h*\frac{1h}{3600s} *\frac{1000m}{1km} = 23.4 m/s (2)\)
\(v_{f} = 15.8 km/h*\frac{1h}{3600s} *\frac{1000m}{1km} = 4.4 m/s (3)\)
Replacing (2) and (3) in (1), since Δx =350m, we can solving for a:\(a = \frac{(4.4m/s)^{2} - (23.4m/s)^{2}}{2*350m} = -0.76 m/s2 (4)\)
In order to get the time, we can simply use the definition of acceleration, and rearrange terms:\(t =\frac{v_{f}-v_{o}}{a} = \frac{(4.4m/s)-(23.4m/s)}{-0.76m/s2} = 25.0 s (5)\)
Frequency= Wavelength = 502 km Speed= 100 m/s
Answers
Answer:
Explanation:
Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.
How much would it cost to cover the entire land area of the U.S. in dollar bills?
How much would it take to cover the entire land area of the U.S. in dollar bills?
The contiguous United States can be approximated as a rectangle that measures 1000 x 3000 miles, while Alaska has about 1/5 of the area of the contiguous U.S. Ignore Hawaii for this calculation. Also note that the dollar bill measures roughly 6.5cm x 15.5cm.
How much would it cost to cover the entire land area of the United States?
*Round your answer to one significant figure*
Answers
Answer:
$900 trillion
Explanation:
If Alaska is 20% of the contiguous US, then the approximate area of interest is ...
1200 miles × 3000 miles = 3.6×10^6 square miles.
The size of a dollar bill is about ...
(6.5 cm)·(15.5 cm) = 100.75 cm^2
One mile is 160,934.4 cm, so 1 square mile is about ...
1 mi^2 = (160,934.4 cm)^2 ≈ 2.59·10^10 cm^2
The number of dollars of interest is then ...
(3.6 · 10^6 mi^2)(2.59 · 10^10 cm^2)/(100.75 cm^2) ≈ 9.3·10^14
≈ 930 × 10^12 . . . dollars
It would cost about 900 trillion dollars to cover the land area of the US in $1 bills.
What is the definition of electrical power?
Answers
Liz rushes down onto a subway platform to find her train already departing. She stops and watches the cars go by. Each car is 8.60 m long. The first moves past her in 1.80 s and the second in 1.61 s. Find the constant acceleration of the train.
Answers
The constant acceleration of the train is 0.33 m/s.
The average velocity can be calculated by using the formula:
velocity = distance/time
For the 1st car, the velocity is calculated as:
v₁ = 8.60 m / 1.80 s = 4.78 m / s
For the second car, velocity can be calculated as:
v₂ = 8.60 m / 1.66 s = 5.34 m / s
Now we can solve for the acceleration using the formula:
v₂² = v₁² + 2 a d
Rewriting in terms of a, we get
a = (v₂² – v₁²) / 2 d
a = (5.34)² – (4.78)² / (2 × 8.6)
a = 0.33 m/s
Therefore, the constant acceleration of the train is 0.33m/s.
what is acceleration explain?
acceleration, fee at which speed modifications with time, in terms of each pace and course. A factor or an object shifting in a directly line is improved if it hastens or slows down. motion on a circle is improved even if the velocity is steady, due to the fact the route is constantly converting
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If the instantaneous voltage at a given moment in the circuit RL is V=VmaxSIN(150), then the instantaneous current at the...... same instant I=Imaxsin
Answers
The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.
1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).
2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.
3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.
4. However, the given equation does not explicitly mention resistance.
5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).
6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.
7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).
8. Therefore, V = VR + VL.
9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.
10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.
The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.
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At Orrington, the Penobscot flows with an average speed of 40cm/s, the average depth of is 3m and width is 40m and the mercury concentration is 0.002mg/l.
What is flux of mercury there in g/min?
Answers
Answer:
The flux of mercury at Orrington is 0.48 g/min. This is calculated by multiplying the average speed (40 cm/s) by the average depth (3 m) by the width (40 m) by the concentration (0.002 mg/l) and then converting to g/min by multiplying by 1000.
Which do solar flares and coronal mass ejections have in common?
Answers
8. A pen fell from a table from the height of 120 cm. (a) Find out how long it will take to reach on the ground. (b) What would be its speed when it hits the ground?
Answers
Answer:
0.49 seconds, 4.8(02)m/s
Explanation:
a) first convert 120cm to metres
that is 1.2m
suvat says that s = ut + ½ at²
let's rearrange that for time
t = -((u ± √(u² + 2as))/a)
u = 0
a = 9.8
s = 1.2
t = -((0 ± √(0 + 2(9.8)(1.2)))/9.8)
t = -((±√23.52)/9.8)
t = either 0.49 or -0.49 seconds.
since it cannot happen in negative time, the answer is 0.49 seconds
b) a = (v - u) / t
rearrange for v
v = u + at
a = 9.8
t = 0.49
u = 0
v = 0 + 9.8(0.49)
v = 4.8
or to be more specific, 4.802 m/s
How many cs are there in 40 mins plane ride?
Answers
The distance is 1600 km, and the plane's average speed is x km/hr. The Ordinary aeroplane speed is 800 km/hr.
How to find the aeroplane speed calculation?The distance is 1600 km, and the plane's average speed is x km/hr. The time it takes the plane to fly 1600 km at its current speed is =
Time consumed by the plane at the increased speed is equal to x+400 /1600 km/hr because all time is measured in hours, which must be converted to minutes using the formula 60 /40 hr= 3 2 hr.
Considering the query,/x/ 1600 − x+400 /1600 = 3 /2
⇒ 1600[ x(x+400) x+400−x ]= 3/ 2
⇒ x(x+400)/ 400 = 3 /2 × 1600/ 1
⇒ x(x+400)= 2400×3×1600
⇒ x 2 +400x=960000 ⇒ x 2 +400x−960000=0
⇒ x2 +1200x−800x−960000=0
⇒ x(x+1200)−800)x+1200)=0
⇒ (x+1200)(x−800)=0
∴ x=−1200 or x=800
Given that speed cannot be negative.
∴ Ordinary aeroplane speed is 800 km/hr.
The Complete Question is aeroplane speed.
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WILL VOTE MOST BRAINLIEST
Which of the following explains why the inner planets are different than the outer planets?
A) Due to the greater inertia of the dust particles, the dust remained close to the sun to form the inner planets leaving gases to form the outer planets.
B) The lighter gases boiled off of the protoplanets closest to the sun, leaving dust and metals behind to form the inner planets.
C) Due to the greater momentum of the gas particles, the gas particles flew farther away from the sun than dust and metals to form the outer planets, leaving dust and metals to form the inner planets.
Answers
Answer:
B) The lighter gases boiled off of the protoplanets closest to the sun, leaving dust and metals behind to form the inner planets.
Explanation:
Inner planets are smaller and rockier than outer gas planets,outer planets are larger,because of their lower gravity they don't attract extreme amounts of gas in their planets.The four outer planets were so far from the Sun that its winds could not blow away their ice and gases
A 215 N sign is supported by two ropes. One rope pulls up and to the right 1=29.5∘ above the horizontal with a tension 1 , and the other rope pulls up and to the left 2=44.5∘ above the horizontal with a tension 2 , as shown in the figure. Find the tensions 1 and 2 .
Answers
The sign is held in equilibrium. Using Newton's second law, we set up the equations of the net forces acting on the sign in the horizontal and vertical directions:
∑ F (horizontal) = T₁ cos(29.5°) - T₂ cos(44.5°) = 0
(right is positive, left is negative)
∑ F (vertical) = T₁ sin(29.5°) + T₂ sin(44.5°) - 215 N = 0
(up is positive, down is negative)
Solve the system of equations. I use elimination here:
• Multiply the first equation by sin(29.5°) and the second by cos(29.5°):
sin(29.5°) (T₁ cos(29.5°) - T₂ cos(44.5°)) = 0
cos(29.5°) (T₁ sin(29.5°) + T₂ sin(44.5°) - 215 N) = 0
T₁ cos(29.5°) sin(29.5°) - T₂ cos(44.5°) sin(29.5°) = 0
T₁ cos(29.5°) sin(29.5°) + T₂ cos(29.5°) sin(44.5°) = (215 N) cos(29.5°)
• Subtract the first equation from the second to eliminate T₁ :
T₂ cos(29.5°) sin(44.5°) - (- T₂ cos(44.5°) sin(29.5°)) = (215 N) cos(29.5°)
• Solve for T₂ :
T₂ (cos(29.5°) sin(44.5°) + cos(44.5°) sin(29.5°)) = (215 N) cos(29.5°)
T₂ sin(74.0°) = (215 N) cos(29.5°)
… … … (using the fact that sin(x + y) = sin(x) cos(y) + cos(y) sin(x))
T₂ = (215 N) cos(29.5°) / sin(74.0°)
T₂ ≈ 195 N
• Solve for T₁ :
T₁ cos(29.5°) - T₂ cos(44.5°) = 0
T₁ cos(29.5°) = T₂ cos(44.5°)
T₁ = T₂ cos(44.5°) / cos(29.5°)
T₁ ≈ 160. N
Vector component practice
Given Ax = 3.5 and Ay = 5.7,
what is the angle of inclination for the resultant vector?
A. 58.47 degrees
B. 1.63 degrees
C. 31.55 degrees
D. 27.35 degrees
Answers
Answer:
Option (C)
Explanation:
Vector A has two components,
Ax = 3.5 and Ay = 5.7
Therefore, from the figure attached,
From triangle ABC,
BC represents the vertical component and AC represents the horizontal component of vector A.
For the angle of inclination,
tanθ = \(\frac{\text{Vertical component}}{\text{Horizontal component}}\)
= \(\frac{3.5}{5.7}\)
θ = \(\text{tan}^{-1}(\frac{35}{57})\)
θ = 31.55 degrees
Therefore, Option (C) will be the correct option.
Which option best describes the average acceleration from 40 to 70 s?
Answers
C. The average acceleration is positive and smaller in magnitude than the initial acceleration.
What is average velocity?Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.
a = Δv/Δt
where;
Δv is change in velocityΔt is change in timea = (250 - 248) / (70 - 40)
a = 0.067 m/s²
Thus, we can conclude that the average acceleration is positive and smaller in magnitude than the initial acceleration.
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An Apple sits on a table which is 0.5 m above the floor. The acceleration due to gravity could be our earths value of g equals 10 m/s^2 or something larger or smaller. In this case the acceleration due to gravity is 1.7* g. The acceleration due to gravity is g= 17.0 m/s^2 What is the speed acquired by the Apple just before it hits the floor? How long does the Apple take to fall through the h meters? What is the initial potential energy in Joules possessed by the Apple if it’s mass is 0.1 kg? What is the kinetic energy that the Apple acquired after it falls through the entire 0.5 meters?
Answers
magnetism/ magnetic field ana magnetic forces
Answers
Answer:
Magnetism is a physical phenomenon that manifests itself in a force acting between magnets or other magnetized or magnetisable objects, and a force acting on moving electric charges, such as in current-carrying cables. The force action takes place by means of a magnetic field, which is generated by the objects themselves or otherwise. There are natural and artificial magnets. All magnets have two poles called the north pole and the south pole. The north pole of one magnet repels the north pole of another magnet and attracts the south pole of another magnet; the same with south poles.
(round to 3 significant figures pls) A block of iron at 415 degrees C is put into a 0.625 kg tub of water at 15.0 degrees C. They come to equilibrium at 100 degrees C, and 0.144 kg of the water boils off to steam. What was the mass of the iron block?
Answers
Temperature of iron (Ti) = 415 °C Temperature of water (Tw) = 15.0 °CTemperature at equilibrium (Te) = 100 °CMass of water (m) = 0.625 kgMass of steam evaporated (ms) = 0.144 kgHeat lost by iron (Q1) = Heat gained by water (Q2) + Heat required to evaporate steam .
Heat lost by iron = (mass of iron (m) x specific heat capacity of iron (c) x change in temperature of iron (ΔT1))Heat gained by water = (mass of water (m) x specific heat capacity of water (c) x change in temperature of water (ΔT2))Heat required to evaporate steam = (mass of steam (ms) x specific latent heat of vaporization of water (L))Now, using the above formula we can calculate the mass of the iron block as:
Q3m x c x ΔT1 = m x c x ΔT2 + ms x L
Let's calculate the value of Q1 first.
Q1 = m x c x ΔT1m = Q1 / (c x ΔT1)
We know that
c = 450 J/kg °C and ΔT1 = Ti - Te = 415 - 100 = 315°CQ1 = m x c x ΔT1= m x 450 J/kg
°C x 315°C= 141750 m Jm = Q1 / (c x ΔT1)= 141750 / (450 x 315)= 1.002 kg
Now, let's calculate the value of Q3.Q3 = ms x L= 0.144 kg x 2.26 x 10^6 J/kg= 325440 J
Now, let's calculate the value of Q2
.Q2 = m x c x ΔT2m = (Q2 + Q3) / (c x ΔT2)
We know that ΔT2 = Te - Tw = 100 - 15 = 85°CQ2 = m x c x ΔT2= 0.625 kg x 4186 J/kg °C x 85°C= 276981.25 JNow, let's calculate the mass of the iron block.m =
(Q2 + Q3) / (c x ΔT2)= (276981.25 + 325440) / (450 x 85)= 1.003 kg
Hence, the mass of the iron block is 1.003 kg rounded off to 3 significant figures.
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A cap 6.000 cm in diameter plugs an opening in a spherical container 1.000 m in diameter at atmospheric pressure. The container is submerged to a depth of 10.00 ft in water. Assume the plug is planar and the pressure over the container is equalized. The force needed to remove the plug is closest to?
Answers
The force needed to remove the plug that is 6.000 cm in diameter which plugs an opening in a spherical container 1.000 m in diameter at atmospheric pressure is 85 N
P = F / A
P = ρ g h
P = Pressure
F = Force
A = Area
ρ = Density
g = Acceleration due to gravity
h = Height
ρ = 1000 kg / m³
g = 9.8 m / s²
h = 10 ft = 3.048 m
A = π r²
d = 6 cm = 0.06 m
r = d / 2 = 0.06 / 2
r = 0.03 m
A = 3.14 * 0.03 * 0.03
A = 0.002826 m²
Equating both formulae of P,
F / A = ρ g h
F = 1000 * 9.8 * 3.048 * 0.002826
F = 85 N
Therefore, the force needed to remove the plug is closest to 85 N
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Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
Answers
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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A 1500-kg car goes around a flat 25-m-radius circular track at 10 m/s (approximately 22 mph). What is the maximum speed this car can go without sliding, in m/s? The coefficients of friction between the tire and the road on a dry day are µs = 1.0 and µk= 0.80. Use g = 10 m/s2.
Answers
The maximum speed that the car can gο arοund the circular track withοut sliding is apprοximately 27.39 m/s.
What is a fοrce?Fοrce is a physical quantity that describes the interactiοn between twο οbjects οr between an οbject and its envirοnment. A fοrce can cause an οbject tο accelerate, change directiοn, οr defοrm. Fοrce is a vectοr quantity, meaning it has bοth magnitude and directiοn. It is measured in units οf Newtοns (N).
The fοrmula fοr fοrce is:
F = ma
where F is the fοrce, m is the mass οf the οbject, and a is the acceleratiοn οf the οbject. This fοrmula is knοwn as Newtοn's Secοnd Law οf Mοtiοn. It states that the fοrce acting οn an οbject is directly prοpοrtiοnal tο its mass and acceleratiοn.
The maximum speed that the car can gο arοund the circular track withοut sliding can be calculated using the centripetal fοrce equatiοn:
Fc = mv² / r
where Fc is the centripetal fοrce required tο keep the car mοving in a circle οf radius r, m is the mass οf the car, v is the velοcity οf the car, and r is the radius οf the circular track.
Tο prevent sliding, the fοrce οf static frictiοn between the tires and the rοad must be greater than οr equal tο the maximum fοrce that can be exerted by static frictiοn, which is equal tο µs times the nοrmal fοrce (N = mg), where µs is the cοefficient οf static frictiοn and g is the acceleratiοn due tο gravity.
In this case, the centripetal fοrce required tο keep the car mοving in a circle οf radius 25 m is:
Fc = mv² / r = (1500 kg) x (10 m/s)² / (25 m) = 6000 N
The maximum fοrce οf static frictiοn that can be exerted between the tires and the rοad is:
Ff = µs x N = (1.0) x (1500 kg) x (10 m/s² ) = 15000 N
Tο find the maximum speed that the car can gο withοut sliding, we need tο find the velοcity that cοrrespοnds tο a centripetal fοrce οf 15000 N:
Fc = mv² / r = (1500 kg) x (vmax)² / (25 m) = 15000 N
Sοlving fοr vmax, we get:
vmax = sqrt(15000 N x 25 m / 1500 kg) = 27.39 m/s
Therefοre, the maximum speed that the car can gο arοund the circular track withοut sliding is apprοximately 27.39 m/s.
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How much impulse is imparted on a 0.14 kg baseball initially traveling at 32 m/s when it is struck by a baseball bat and begins to travel in the opposite direction at 49 m/s
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ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:
Impulse = Change in momentum
The momentum of an object is given by the product of its mass and velocity:
Momentum = mass × velocity
In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.
Therefore, the change in momentum is given by:
Change in momentum = (mass × final velocity) - (mass × initial velocity)
Change in momentum = mass × (final velocity - initial velocity)
Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))
Change in momentum = 0.14 kg × (49 m/s + 32 m/s)
Change in momentum = 0.14 kg × 81 m/s
Change in momentum = 11.34 kg·m/s
So, the impulse imparted on the baseball is 11.34 kg·m/s.
What is gravity?(20 points)
1. A force that pulls objects toward the center of Earth.
2. A force that pushes objects away from the center of Earth.
3. Energy that moves objects away from the center of Earth.
4. Energy that moves objects toward the center of Earth.
Answers
Answer:
The answere is A force that pulls objects toward the center of Earth
Explanation:
Hope this helpe! :)
Answer: It's A because I did this test
Explanation:
ı can't solve this problem. please help
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Cold air rises because it is denser than water, is this true?
Answers
Answer:
true
Explanation:
im not sure please dont attack me
use chebyshev to estimate the number of coin flips you need to take to be 95% sure you know which coin was chosen.
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We may calculate the proportion of data values that are 1.5 standard deviations or more from the mean using Chebyshev's rule in statistics. Alternately, we can calculate the proportion of data values that deviate by 2.5 standard deviations from the mean.
What does a 75% Chebyshev interval mean?
Therefore, Chebyshev's Theorem informs you that at least 75% of the values lie within the range of 100 20, or 80 to 120. In contrast, no more than 25% of cases fall outside of that range. 1.41 standard deviations is an intriguing range.
What does the Chebyshev inequality tell us?
According to Chebyshev's inequality, 75% of values are found within two standard deviations of the mean, and 88.9% are found within three standard deviations of the mean. It is true for.
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A book is at rest on a table identify the correct free body diagram for the situation
Answers
Answer: 3rd one
Explanation:
3rd diagram is the correct free body diagram for the situation.
What is Free body diagram?Free-body diagrams are used to display the relative strength and direction of all forces that are being applied to an item in a certain scenario.
A unique illustration of the vector diagrams that were covered in a previous lesson is the free-body diagram. We will make use of these graphics throughout our study of physics. In a free-body diagram, the size of the arrow indicates the strength of the force.
The force is acting in the direction indicated by the arrow's direction. The exact type of force is labeled next to each force arrow in the diagram. In a free-body diagram, it is common practice to depict the item as a box and to draw the force arrow from the box's center outward in the direction.
Therefore, 3rd diagram is the correct free body diagram for the situation.
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