Is the answer correct? Explain.

Answer:

is there a picture to answer?

Step-by-step explanation:

Based on the graph (see attachment), John's speed on each section of the walk are as follows:

Speed can be defined as the distance covered by a physical object per unit of time. This ultimately implies that, speed can be measured as meter per seconds.

Distance can be defined as the amount of ground covered (travelled) by a physical object over a specific period of time and speed, regardless of its direction, starting point or ending point.

Mathematically, speed can be calculated by using this formula;

Speed = distance/time

Based on the graph (see attachment), John's speed on each section of the walk can be calculated as follows.

For the first interval, we have:

Speed = 6/1.5

Speed = 4 km/h.

For the first interval, we have:

Speed = 6/1.5

Speed = 4 km/h.

For the second interval, we have:

Speed = 6/0

Speed = 0 km/h.

For the third interval, we have:

Speed = 6/4

Speed = 1.5 km/h.

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Answer: 186

you take 15 and multiply it by 12 then add the extra 6

Answer:

no hes not hes a rapper..........Jk the answer is 53700

Step-by-step explanation:

Step-by-step explanation:

1,350 a month

16,200 a year

Answer:

The confidence interval is (657.18, 661.02)

or , CI = 659.1 ± 1.922

Step-by-step explanation:

We have to ind the 95% confidence interval,

Mean = Y = 659.1

Standard Deviation = s(Y) = 19.9

Confidence level = 95%

Alpha value = (1 - 0.95)/2

Alpha value = 0.025

So,

This gives a z value of,

z = - 1.96

Now, there are 412 districts so, n = 412

so,

The upper limit is,

Upper limit =  UL = Y + z(s(Y))/sqrt(n)

\(UL = Upper limit = Y + z(s(Y))/\sqrt{n}\\UL = 659.1 + (1.96)(19.9)/|sqrt(412)\\UL = 661.02\)

Lower limit is,

LL = Y - z(s(Y))/sqrt(n)

\(LL = 659.1 - (1.96)(19.9)/\sqrt{412}\\LL = 657.18\)

Hence the confidence interval is (657.18, 661.02)

The equation to illustrate a word problem regarding the renting of a car is 60 + 3h.

It should be noted that an equation is simply used to illustrate the information given about the variables.

An example of word problem simply that can be illustrated by an equation will be that the initial deposit to rent a car is $50 and there's an hourly rate of $3.

Therefore, based on the above information, the equation to illustrate this will be:

= Initial cost + Hourly rate

Let the number of hours be represented by h.

= 50 + (3 × h)

= 50 + 3h

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3161617

Step-by-step explanation:

Answer:

240= 24x10

960= 96x10

Step-by-step explanation:

doesnt really need an explanation but

96x10=960

24x10=240

good luck on map or any question this is for <3!

The 50 students are an example of a sample population

A sample is a subset of a population that is used to represent the entire population. In this case, the 50 students who received the questionnaire are a sample of the population of students on the university campus. The results of the questionnaire would be used to make inferences about the satisfaction of the entire student population with the financial aid office on campus. The importance of the sample lies in the fact that it allows researchers to make inferences about a larger population based on a smaller, more manageable group of individuals. This is done by selecting a sample that is representative of the population of interest.

By studying a sample, researchers can make predictions about the characteristics of the larger population, such as the percentage of students who are satisfied with the financial aid office on campus. This can be done with a high degree of accuracy if the sample is chosen and analyzed properly. Additionally, studying a sample can also be much more cost-effective and time-efficient than studying the entire population. However, it's important to keep in mind that the sample may not be perfectly representative of the population and it may introduce some errors, called sampling errors, in the inferences made about the population.

So, 50 students as an example of a population sample to fill out the questionnaire.

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Answer:

First option, 4 because 1/6 + 1/6 + 1/6 +1/6 = 4/6

(a) Average velocity over the given time intervals:

i. [2, 2.5]:  To find the average velocity, we need to calculate the change in position (Δy) divided by the change in time (Δt) over the interval [2, 2.5].

\(Δy = y(2.5) - y(2) = (20(2.5) - 2(2.5)^2) - (20(2) - 2(2)^2)\)

\(Δt = 2.5 - 2\)

ii. [2, 2.05]:

\(Δy = y(2.05) - y(2)\)

\(Δt = 2.05 - 2\)

iii. [2, 2.005]:

\(Δy = y(2.005) - y(2)\)

\(Δt = 2.005 - 2\)

iv. [2, 2.0005):

\(Δy = y(2.0005) - y(2)\)

\(Δt = 2.0005 - 2\)

(b) Instantaneous velocity at t = 2:

To estimate the instantaneous velocity at t = 2, we can calculate the derivative of the position function with respect to time and evaluate it at t = 2.

\(v(t) = dy/dt = d(20t - 2t^2)/dt\)

To find v(2), substitute t = 2 into the derivative expression.

Please note that I cannot provide the numerical values of the average velocities or the instantaneous velocity without specific calculations. You can evaluate the expressions provided using the given equation y = 20t - 2t^2 and calculate the values accordingly

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Answer:

x = 9/2, y = 15/4

Step-by-step explanation:

The line intersecting two distinct points on both sides of the triangle are parallel

So the corresponding angles are equal
Also, we have a common angle at point A
So, both the triangles are similar by AAA criteria

Now, the sides will be proportional as the triangles are similar
4/7 = 5/5+y = 6/6+x
Solving this, we get y = 15/4 units
and x = 9/2 units

Answer:

f(x)=-\(\frac{5}{2}\\\)x+9

Step-by-step explanation:

Use the slope formula and slope intercept formula form y=mx + b to find the equation

Answer:

The correct choice is option B. -7 ≤ x < 12

Step-by-step explanation:

The chemicals under considerationm an important quantity is the total proportion Y1 +Y2 found in any sample.V(Y1 + Y2) = Var(Y1) + Var(Y2) + 2Cov(Y1, Y2) = 1/18 + 1/18 + 2(1/144) = 5/72.

To find E(Y1 + Y2), we first find the marginal distribution of Y1 and Y2 by integrating the joint density function over the other variable as follows:

f1(y1) = ∫f(y1,y2)dy2 = ∫2dy2 from 0 to 1-y1 = 2(1-y1) for 0 ≤ y1 ≤ 1

f2(y2) = ∫f(y1,y2)dy1 = ∫2dy1 from 0 to 1-y2 = 2(1-y2) for 0 ≤ y2 ≤ 1

Now we can find E(Y1 + Y2) as follows:

E(Y1 + Y2) = ∫∫(y1 + y2)f(y1,y2)dy1dy2

= ∫∫(y1 + y2)2dy1dy2 over the region 0 ≤ y1 ≤ 1-y2, 0 ≤ y2 ≤ 1

E(Y1 + Y2) = ∫0^1∫0^(1-y1) (y1 + y2)2dy2dy1

= ∫0^1[y1(y1/2 + 2/3) + 1/3]dy1

= 7/12

To find V(Y1 + Y2), we can use the fact that V(Y1 + Y2) = V(Y1) + V(Y2) + 2Cov(Y1, Y2), where Cov(Y1, Y2) is the covariance of Y1 and Y2. First, we need to find the variances of Y1 and Y2:

Var(Y1) = E(Y1^2) - [E(Y1)]^2 = ∫∫y1^22dy1dy2 - [∫∫y1f(y1,y2)dy1dy2]^2

= ∫0^1∫0^(1-y1) y1^22dy2dy1 - [∫0^1(2y1-2y1^2)dy1]^2

= 1/18

Var(Y2) = E(Y2^2) - [E(Y2)]^2 = ∫∫y2^22dy1dy2 - [∫∫y2f(y1,y2)dy1dy2]^2

= ∫0^1∫0^(1-y2) y2^22dy1dy2 - [∫0^1(2y2-2y2^2)dy2]^2

= 1/18

Now we need to find the covariance of Y1 and Y2:

Cov(Y1, Y2) = E(Y1Y2) - E(Y1)E(Y2) = ∫∫y1y2f(y1,y2)dy1dy2 - (∫∫y1f(y1,y2)dy1dy2)(∫∫y2f(y1,y2)dy1dy2)

= ∫0^1∫0^(1-y1) 2y1y2dy2dy1 - (7/12)(7/12)

= 1/144

Therefore, V(Y1 + Y2) = Var(Y1) + Var(Y2) + 2Cov(Y1, Y2) = 1/18 + 1/18 + 2(1/144) = 5/72.

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Answer:

<

Step-by-step explanation:

First, let's find common denominators:

Multiply 3/4 by 2.

Product is 6/8.

Next, let's compare both fractions:

5/8 ? 6/8

5/8 is less than 6/8.

Therefore 5/8 < 6/8.

Answer:

40 min per period

Step-by-step explanation:

When it has 8 periods :

Total time = 45 min per period for 8 period

Total time = 45 × 8 min

When it has 9 periods : let each period be of x min

Total time = x min per period for 9 period

Total time = x × 9 min

As total time remains same,

45 × 8 = x × 9

5 x 8 = x

40 = x

Answer:

2/3

Step-by-step explanation:

By using the definition of continuity and exploiting the fact that f(0) = 1, we were able to prove the existence of an open interval (a, b) containing 0 such that for any real number r within this interval, the function value f(r) is greater than 0.

First, let's recall the definition of continuity at a point. A function f is continuous at a point c if, for any positive number ε, there exists a positive number δ such that whenever x is within δ of c, the value of f(x) will be within ε of f(c).

Now, since f is continuous at 0, we can say that for any positive ε, there exists a positive δ such that if |x - 0| < δ, then |f(x) - f(0)| < ε.

Since f(0) = 1, the above inequality simplifies to |f(x) - 1| < ε.

We want to find an open interval (a, b) containing 0 such that for any r within this interval, f(r) > 0. Let's consider ε = 1 as an arbitrary positive number.

From the definition of continuity at 0, we can find a positive δ such that if |x - 0| < δ, then |f(x) - 1| < 1. This implies -1 < f(x) - 1 < 1, which further simplifies to 0 < f(x) < 2.

Now, consider the interval (a, b) = (-δ, δ). Since δ is positive, it ensures that 0 is within this interval. Also, since f(x) is continuous on this interval, we can conclude that f(r) > 0 for all r within (-δ, δ).

To prove this, let's take any r within (-δ, δ). Since r is within this interval, we have -δ < r < δ, which implies |r - 0| < δ. By the definition of continuity at 0, we know that |f(r) - 1| < 1. Therefore, 0 < f(r) < 2, and we can conclude that f(r) > 0.

Hence, we have shown that there exists an open interval (a, b) containing 0 such that for all r within this interval, f(r) > 0.

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Answer:

You didnt put any answer choices but by applying that scale factor, I got these measurements in the order you put them in. 0.5. 1.25. 1.75. 3.

a. The distribution of individual runner's time (X) is approximately normal (X ~ N).

b. The distribution of the sample mean (ȳ) of 9 runners is also approximately normal (ȳ ~ N).

c. The distribution of the sample mean difference (∆ȳ) is also approximately normal (∆ȳ ~ N).

d. To find the probability of a randomly selected runner's time falling between 19.2 and 20.2 minutes, calculate the corresponding z-scores and find the area under the standard normal curve between those z-scores.

e. The Central Limit Theorem states that the distribution of the sample mean approaches normality for large sample sizes. Therefore, the probability of the average time of 9 runners falling between 19.2 and 20.2 minutes can be calculated using z-scores and the standard normal distribution.

f. To determine the probability of a randomly selected 9-person team having a total time less than 174.6 minutes, calculate the z-score and find the corresponding probability using the standard normal distribution.

g. Yes, the assumption of normality is necessary for parts e) and f) because they rely on the properties of the normal distribution and the Central Limit Theorem.

h. To find the longest total time allowing a relay team to make it to the championship round (top 15%), calculate the z-score corresponding to the 15th percentile and convert it back to the original scale using the population mean (20 minutes) and standard deviation (2.2 minutes).

a. The distribution of X (individual runner's time) is approximately normal (X ~ N).

b. The distribution of the sample mean (average time of 9 runners) is also approximately normal (ȳ ~ N).

c. The distribution of the sample mean difference (∆ȳ) is also approximately normal (∆ȳ ~ N).

d. To find the probability that a randomly selected runner's time will be between 19.2 and 20.2 minutes, we need to calculate the z-scores for these values and then find the area under the standard normal curve between those z-scores.

Using the formula:

z = (x - μ) / σ

For 19.2 minutes:

z1 = (19.2 - 20) / 2.2

For 20.2 minutes:

z2 = (20.2 - 20) / 2.2

Next, we can use a standard normal distribution table or a calculator to find the probabilities corresponding to these z-scores. The probability of the runner's time being between 19.2 and 20.2 minutes is the difference between these probabilities.

e. To find the probability that the average time of the 9 runners is between 19.2 and 20.2 minutes, we can use the Central Limit Theorem. Since the sample size is large enough (n = 9), the distribution of the sample mean approaches a normal distribution, regardless of the shape of the population distribution.

We can calculate the z-scores for the given values and then find the corresponding probabilities using a standard normal distribution table or a calculator.

f. To find the probability that the randomly selected 9-person team will have a total time less than 174.6 minutes, we need to calculate the z-score for this value and then find the corresponding probability using a standard normal distribution table or a calculator.

g. Yes, the assumption of normality is necessary for parts e) and f) because we are using the properties of the normal distribution and the Central Limit Theorem to make inferences about the sample mean and the sample mean difference.

h. To determine the longest total time that a relay team can have and still make it to the championship round (top 15%), we need to find the z-score corresponding to the 15th percentile. This z-score represents the cutoff point for the top 15% of the distribution. We can then convert the z-score back to the original scale using the formula:

x = μ + z * σ

where μ is the population mean (20 minutes) and σ is the population standard deviation (2.2 minutes). This will give us the longest total time that allows the relay team to make it to the championship round.

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Step-by-step explanation:

1. -3x+7x=18

    x(-3+7)=18

      x=\(\frac{18}{(-3+7)}\)

2. 4x+7x=-5

    x(4+7)=-5

     x=\(\frac{-5}{(4+7)}\)

I hope this helped, may be wrong but ive done it my way

The probability that on any given day the office receives exactly 3 calls is 0.0076.

What is probability?

A probability is a numerical representation of the likelihood or chance that a specific event will take place. Both proportions ranging from 0 to 1 and percentages ranging from 0% to 100% can be used to describe probabilities.

Here, we let

Let X be the number of calls received in an office per day.

X≈Poison(λ=10)

P(X = x) = e^(-λ)λˣ/x!; x = 0, 1, 2.....

= 0, otherwise

The probability that on any given day the office receives exactly 3 calls: 0.0076

P(X = 3) = e^(-10)10³/3!

P(X=3) = 0.0076

Hence, the probability that on any given day the office receives exactly 3 calls is 0.0076.

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For this case, the first thing we must do is define variables.

We have then:

n: number of cans that each student must bring

We know that:

The teacher will bring 5 cans

There are 20 students in the class

At least 105 cans must be brought, but no more than 205 cans

Therefore the inequation of the problem is given by:

Answer:

105 < 20n + 5 < 205

the possible numbers n of cans that each student should bring in is:

105 < 20n + 5 < 205

Answer:

D

Step-by-step explanation:

If we use pemdas and simplify the whole equation by each step (parentheses, exponets, muliplation, addition, and subtraction) it will give us our answer I got D

Option D

From the given integer numbers, the states that have temperatures within 10ºC of Delaware are: California, Hawaii and Idaho.

The temperature in Delaware is of 5 ºC, hence for our range, we have that:

Alaska(< -5), Tennessee(>15) and WV(<-5) do not have temperatures in this range, hence the states that have temperatures within 10ºC of Delaware are: California, Hawaii and Idaho.

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In the given question, we found that the values of z that satisfy both the equations f(z) and g(z) are z = 4 or z = -2.

To solve this question, we need to equate f(z) and g(z) since we are looking for the value of z that satisfies both equations. We can do that as follows:

f(z) = g(z)

2z² + 2z = 2z + 16

Next, we will bring all the terms to one side of the equation and factorize it to solve for z:

2z² - 2z - 16

= 02(z² - z - 8)

= 0(z - 4)(z + 2)

= 0

Either (z - 4) = 0 or (z + 2) = 0

Solving for each of these, we get z = 4 or z = -2.

Therefore, the values of z that satisfy both equations f(z) and g(z) are z = 4 or z = -2.

To find the values of the variable z which satisfies the equations f(z) and g(z), we equate both the equations and solve for z as we did above.

We can bring all the terms to one side of the equation to get a quadratic expression and solve it using factorization or quadratic formula.

Once we find the roots, we can check if the roots satisfy both the equations. If the roots satisfy both the equations, we say that those are the values of z that satisfy the given equations.

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f(x+9) = 3x + 26.

Given equation:

f(x)=3x-1

f(x+9) = 3(x+9) - 1

= 3x + 3*9 - 1

= 3x + 27 - 1

= 3x + 26.

Therefore f(x+9) = 3x + 26.

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Answer:

22

Step-by-step explanation:

Use a proportion.

30/15 = 44/x

30x = 15 × 44

2x = 44

x = 22

Answer:

22

Step-by-step explanation:

30 miles/ 15 sessions of tract practice

Per practice Jack is running a total of 2 miles.

So 44 miles/2 miles

22 sessions of track practice

Answer:

-4 :)

Step-by-step explanation:

2(\(\frac{1}{2}\)\()^{3}\) + 3\(\frac{1}{4}\) - 5 = -4